At the movie theatre , child admission is $ 6.40 and adult admission is $ 9.60 . On Monday , 153 tickets were sold for a total sales of $ 1270.40 . How many adult tickets were sold that day ?

Answer:

387-141=246

Step-by-step explanation:

    387

   - 141

-------------

     246

Answer: -43010000.

Step-by-step explanation: 3.99 million is 3,990,000. From there, you subtract 47,000,000 from 3,990,000. The answer is -43010000.

Have a great day! :)

Answer:

The total compound interest is $1,047,130.76.

Step-by-step explanation:

The amount of the money received after 1 year is $31384283.7672.

Compound interest is the interest on savings calculated on both the initial principal and the accumulated interest from previous periods.

The formula used to find the compound interest = [tex]A=P(1+\frac{r}{100})^{nt}[/tex].

Given that, principal = $10,000,000, rate of interest =10% and time period = 1 year

Here, A=10,000,000(1+10/100)¹²

= 10,000,000(1.1)¹²

= $31384283.7672

Therefore, the amount of the money received after 1 year is $31384283.7672.

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Using proportions, we have that:

A proportion is a fraction of a total amount, and the measures are related using a rule of three.

The scale is of 1 inch = 8 feet. What is the height for 2.5 inches? The rule of three is given by:

1 inch - 8 feet.

2.5 inches - x feet

Applying cross multiplication, the height in feet of the final building is given by:

x = 8 x 2.5 = 20 feet.

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The height of the building is calculated by representing 1 inch as 8 feet. The final building has a height of 20 feet.

Scaling is the increase or decrease in the height of an object by a scale factor k.

Given that the scale used is:

1 inch = 8 feet. Hence:

Since the height of the building is 2.5 in, hence:

Height of the final building = 2.5 in * 8 ft per 1 in = 20 feet

The height of the final building is 20 feet.

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Answer:

x = 3

Step-by-step explanation:

These angles are actually equal to each other

This is because when two lines intersect, the two opposite angles are the same.

Since they are the same, you can set them equal to each other

Like so:

6x - 7 = 4x - 1

Then solve:

6x - 7 = 4x - 1

6x = 4x +6

2x = 6

x = 3

Answer:

C

Step-by-step explanation:

Answer:

142 meters.

Step-by-step explanation:

Area can be found by multiplying length*width.  This means that if you have an area, but no width, you can divide the area by the length, or vice versa.  To get the answer, you divide 852/6 to get 142.

Answer:

0.65 is a number greater than 0.6 but less than 0.7

Step-by-step explanation:

width is 6 units

P=2(l+w)

p=2(l+6)

l+6=p/2

l= (p/2)-6

The length of the reactangle with a width of 6 units and perimeter p units is (P/2)-6 units.

A perimeter is a closed route that surrounds, outlines, or embraces a rectangle. The perimeter of a rectangle is given by the formula,

[tex]\rm Perimeter= 2(Length +width)[/tex]

As it is given that the width of the rectangle is 6 units, while the perimeter of the rectangle is P. Now if we write about the perimeter of the rectangle, it can be written as,

[tex]\rm Perimeter= 2(Length +width)[/tex]

[tex]P = 2(l+6)\\\\\dfrac{P}{2} = (l+6)\\\\l = \dfrac{P}{2}-6[/tex]

Hence, the length of the reactangle with a width of 6 units and perimeter p units is (P/2)-6 units.

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The inequality that represent the number of students in the class is x ≤ 24. They could be 20 students

An inequality is an expression that shows the non equal comparison of two or more numbers and variables.

Let x represent the number of students in the class, hence:

x ≤ 6(4)

x ≤ 24

If each team has at least 2 students:

x ≥ 6(2)

x ≥ 12 and x ≤ 24

The inequality that represent the number of students in the class is x ≤ 24. They could be 20 students

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Answer:

Given:

[tex] \\ {\tt{A = \left [ \: \begin{array}{ c c c} \: \: \: \: 2 & -3 & - 5 \\ - 1 & \: \: \: 4 & \: \: \: \: 5 \\ \: \: \: \: 1& - 3 & - 4\end{array} \: \: \: \right] \: and \: B = \left[\begin{array}{c c c} \: \: \: \: 2 & - 2 & - 4 \\ - 1 & \: \: \: \: 3 & \: \: \: \: 4 \\ \: \: \: \: 1 & - 2 & - 3\end{array} \right]}}[/tex]

Matrix A is of order 3 × 3 and Matrix B is of order 3 × 3

To Show:

Formula Used:

[tex]\\ { \rm{ \left[ \begin{array}{c c c} a_{11} & a_{12} & a_{13} \\ a_{21} & a_{22} & a_{23} \\ a_{31} & a_{32} & a_{33}\end{array} \right] \times \left[ \begin{array}{c c c} b_{11} & b_{12} & b_{13} \\ b_{21} & b_{22} & b_{23} \\ b_{31} & b_{32} & b_{33} \end{array} \right] = \: \left[ \begin{array}{c c c} \: \: a_{11}b_{11} + a_{12}b_{21} + a_{13}b_{31} & a_{11}b_{12} + a_{12}b_{22} + a_{13}b_{32} & a_{11}b_{13} + a_{12}b_{23} + a_{13}b_{33} \\ \: \: a_{21}b_{11} + a_{22}b_{21} + a_{23}b_{31} & a_{21}b_{12} + a_{22}b_{22} + a_{23}b_{32}&a_{21}b_{13} + a_{22}b_{23} + a_{23}b_{33} \\ \: \: a_{31}b_{11} + a_{32}b_{21} + a_{33}b_{31}&a_{31}b_{12} + a_{32}b_{22} + a_{33}b_{32} & a_{31}b_{13} + a_{32}b_{23} + a_{33}b_{33}\end{array} \right]}}[/tex]

If A is a matrix of order a×b and B is a matrix of order c×d , then matrix AB exits and is of order a×d , if and only if b = c.

[tex] \: \: [/tex]

If A is a matrix of order a×b and B is a matrix of order c×d , then matrix BA exits and is of order c×b , if and only if d = a.

[tex] \: \: [/tex]

For Matrix AB, a = 3, b = c = 3, d = 3 , thus Matrix AB is of order 3×3

[tex]\\ { \rm{Matrix \: AB = \left[ \begin{array}{c c c} \: \: \: \: 2 & -3 & -5 \\ -1 & \: \: \: 4 & \: \: \: \: 5 \\ \: \: \: \: 1 & -3 & -4 \end{array} \right] \times \left[ \begin{array}{c c c} \: \: \: \: 2 & -2 & -4 \\ -1 & \: \: \: \: 3 & \: \: \: \: 4 \\ \: \: \: \: 1 & -2 & -3 \end{array} \right] = \left[\begin{array}{c c c} \: \: \: \: 2(2)-3(-1)-5(1) & \: \: \: \: 2(-2)-3(3)-5(-2) & \: \: \: \: 2(-4)-3(4)-5(-3) \\ -1(2)+4(-1)+5(1) & -1(-2)+4(3)+5(-2) & -1(-4)+4(4)+5(-3)\\ \: \: \: \: 1(2)-3(-1)-4(1) & \: \: \: \: 1(-2)-3(3)-4(-2) & \: \: \: \: 1(-4)-3(4)-4(-3) \end{array} \right]}}[/tex]

[tex]\\ {\rm{Matrix \: AB = \left[ \begin{array}{c c c} \: \: \: \: 4 + 3 - 5 & \: \: \: -4 -9 + 10 & \: \: -8 - 12 + 15 \\ -2 - 4 + 5 & \: \: \: \: \: \: + 2 + 12 - 10 & \: \: \: \: \: 4 + 16 - 15 \\ \: \: \: \: \: 2 + 3 - 4 & \: \: -2 - 9 + 8 & -4 - 12 + 12 \end{array} \right] = \left[ \begin{array}{c c c} \: \: \: \: 2 & -3 & -5 \\ -1 & \: \: \: \: 4 & \: \: \: 5 \\ \: \: \: \: 1 & -3 & -4 \end{array} \right]}}[/tex]

[tex]\\ {\rm{Matrix \: AB = \left[ \begin{array}{c c c} \: \: \: \: 2 & -3 & -5 \\ -1 & \: \: \: \: 4 & \: \: \: 5 \\ \: \: \: \: 1 & -3 & -4 \end{array} \right] = Matrix \: A}}[/tex]

For Matrix BA, a = 3, b = c = 3, d = 3 , thus Matrix BA is of order 3 × 3

[tex]\\ {\rm{Matrix \: BA = \left[ \begin{array}{c c c} \: \: \: \: 2 & -2 & -4 \\ -1 & \: \: \: \: 3 & \: \: \: \: 4 \\ \: \: \: \: 1 & -2 & -3 \end{array} \right] \times \left[ \begin{array}{c c c} \: \: \: \: 2 & -3 & -5 \\ -1 & \: \: \: \: 4 & \: \: \: \: 5 \\ \: \: \: \: \: 1 & -3 & -4 \end{array} \right]}}= \left[ \begin{array}{c c c} \: \: \: \: \: 2(2) -2(-1) -4(1) & \: \: \: \: 2(-3) -2(4) -4(-3) & \: \: \: \: 2(-5) -2(5) -4(-4) \\ \: -1(2) + 3(-1) + 4(1) & -1(-3) + 3(4) +4(-3) & -1(-5) + 3(5) + 4(-4) \\ \: \: \: \: \: 1(2) -2(-1) -3(1) & \: \: \: \: 1(-3) -2(4) -3(-3) & \: \: \: \: 1(-5) -2(5) -3(-4) \end{array} \right][/tex]

[tex]\\{ \rm{Matrix \: BA = \left[ \begin{array}{c c c} \: \: \: \: 4 + 2 - 4 & \: \: \: -6 -8 + 12 & \: \: -10 - 10 + 16 \\ -2 - 3 + 4 & \: \: \: \: \: \: +3 + 12 - 12 & \: \: \: \: \: + 5 + 15 - 16 \\ \: \: \: \: \: 2 + 2 - 3 & \: -3 -8 +9 & \: \: \: \: \: -5 -10 + 12 \end{array} \right] = \left[ \begin{array}{c c c} \: \: \: \: 2 & -2 & -4 \\ -1 & \: \: \: \: 3 & \: \: \: \: 4 \\ \: \: \: \: 1 & -2 & -3 \end{array} \right]}}[/tex]

[tex]\\{ \rm{Matrix \: BA = \left[ \begin{array}{c c c} \: \: \: \: 2 & -2 & -4 \\ -1 & \: \: \: \: 3 & \: \: \: \: 4 \\ \: \: \: \: 1 & -2 & -3 \end{array} \right] = Matrix \: B}}[/tex]

Using the normal distribution and the central limit theorem, we have that:

a) The sampling distribution is approximately normal, with mean 0.22 and standard error 0.0338.

b) There is a 0.1867 = 18.67% probability that in a random sample of 150 couples more than 25% met online.

c) There is a 0.2584 = 25.84% probability that in a random sample of 150 couples between 15% and 20% met online.

In a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

In this problem:

Item a:

The mean and the standard error are given by:

[tex]\mu = p = 0.22[/tex]

[tex]s = \sqrt{\frac{p(1 - p)}{n}} = \sqrt{\frac{0.22(0.78)}{150}} = 0.0338[/tex]

The sampling distribution is approximately normal, with mean 0.22 and standard error 0.0338.

Item b:

The probability is one subtracted by the p-value of Z when X = 0.25, hence:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem:

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{0.25 - 0.22}{0.0338}[/tex]

Z = 0.89

Z = 0.89 has a p-value of 0.8133.

1 - 0.8133 = 0.1867.

There is a 0.1867 = 18.67% probability that in a random sample of 150 couples more than 25% met online.

Item c:

The probability is the p-value of Z when X = 0.2 subtracted by the p-value of Z when X = 0.15, hence:

X = 0.2:

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{0.2 - 0.22}{0.0338}[/tex]

Z = -0.59

Z = -0.59 has a p-value of 0.2776.

X = 0.15:

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{0.15 - 0.22}{0.0338}[/tex]

Z = -2.07

Z = -2.07 has a p-value of 0.0192.

0.2776 - 0.0192 = 0.2584.

There is a 0.2584 = 25.84% probability that in a random sample of 150 couples between 15% and 20% met online.

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The probability that Shayla will select two red marbles from the bag is 1/16.

Probability determines the odds that an event would happen. The probability the event occurs is 1 and the probability that the event does not occur is 0.

The probability that Shayla will select two red marbles  = (number of red marbles / total number of marbles) x (number of red marbles / total number of marbles)

5/20 x 5/20 = 1/16

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Using the Central Limit Theorem, it is found that the values of the population standard deviation [tex]\sigma[/tex] needed are given by:

a) [tex]\sigma = 32[/tex]

b) [tex]\sigma = 16[/tex]

c) [tex]\sigma = 4[/tex]

By the Central Limit Theorem, the sampling distribution of sample means of size n has standard error [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

In this problem, we have that n = 16.

Item a:

s = 8, hence:

[tex]s = \frac{\sigma}{\sqrt{n}}[/tex]

[tex]8 = \frac{\sigma}{\sqrt{16}}[/tex]

[tex]\sigma = 32[/tex]

Item b:

s = 4, hence:

[tex]s = \frac{\sigma}{\sqrt{n}}[/tex]

[tex]4 = \frac{\sigma}{\sqrt{16}}[/tex]

[tex]\sigma = 16[/tex]

Item c:

s = 1, hence:

[tex]s = \frac{\sigma}{\sqrt{n}}[/tex]

[tex]1 = \frac{\sigma}{\sqrt{16}}[/tex]

[tex]\sigma = 4[/tex]

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Answer:

B

Step-by-step explanation:

-6x + 6 = 2x - 9

-6x + 15 = 2x

15 = 8x

x = 15/8

given ,

a circle of radius 12 inches

and [tex]\theta[/tex] = 45°

now we know that ,

[tex]\\{Area \: of \: sector = \frac{\theta}{360\degree} \times \pi \: r {}^{2} } \\ \\ [/tex]

let's now plug in the values of radius and theta as 12 inches and 45° respectively ,

[tex]\\\dashrightarrow \: \frac{45}{360} \times \frac{22}{7} \times 12 \times 12 \\ \\ \dashrightarrow \: \frac{1}{8} \times \frac{22 \times 12 \times 12}{7} \\ \\ \dashrightarrow \: \frac{22 \times 12 \times 12}{56} \\ \\ \dashrightarrow \: \frac{3168}{56} \\ \\ \dashrightarrow \: 56.57 \: inches {}^{2} (approx.)[/tex]

hope helpful :D

19.99 + 15= 34.99

40-34.99 = 12.51

Jenny received $5.01 change.

Answer:

$600,000

Step-by-step explanation:

GIven;

Alex had $750,000 he lost 80%

To Find;

How many dollars did he lose ​

Solve;

$750,000 * 80% = 600,000

Hence, Alex lost $600,000.

~Learn with Lenvy~

Answer:75,000

Step-by-step explanation:he has 750,000 but he loses 80% so he has 75,000 about.

Answer:

tkm

Step-by-step explanation:

First T the middle k and at last m

Answer: Its 1,110

Step-by-step explanation:

Answer:

144

Step-by-step explanation:

[tex]x^2+24x +144\\\\=x^2 + 2\cdot 12x +12^2\\\\=(x+12)^2[/tex]

Answer:

-1/2 or -5/2

Step-by-step explanation:

| | means the absolute value (distance from 0), so there is going to be a positive case and a negative case (distance from the negatives and distance from the positives).

POSITIVE CASE

[tex]2x+3=2\\2x=-1\\x=-\frac{1}{2}[/tex]

NEGATIVE CASE

[tex]-(2x+3)=2\\-2x-3=2\\-2x=5\\x=-\frac{5}{2}[/tex]

So, your answer would be -1/2 or -5/2.

Step-by-step explanation:

after 4x^2+12x+5

do sum and product but I solved it directly through calculator

hope it helps

Answer:

D. Two hours exercising and eight hours cleaning

Step-by-step explanation:

Rob works part time at the Fallbrook Riding Stable. He makes $5 an hour exercising horses and $10 an hour cleaning stalls. Because Rob is a full-time student, he can work no more than 12 hours per week. However, he must make at least $60 per week.

x = hrs. exercising horses

y = hrs. cleaning stalls

Equations:

Hours he can work per week:

x + y ≤ 12

Amount of money he can make per week:

5x + 10y ≥ 60

Now, graph your equations into desmos.

As you can see in the graph, the correct answer is D (2, 8)

Check your answer by hand:

x + y ≤ 12

2 + 8 ≤ 12

10 ≤ 12

This statement is correct

5x + 10y ≥ 60

5(2) + 10(8) ≥ 60

10 + 80 ≥ 60

90 ≥ 60

This statement is correct

Therefore, the correct answer is D

Hope this helps!

Answer: (-6x - 5) • (2x + 3)

Step-by-step explanation:

((0 -  (22•3x2)) -  28x) -  15

Pull out like factors :

-12x2 - 28x - 15  =   -1 • (12x2 + 28x + 15)

Trying to factor by splitting the middle term

3.2     Factoring  12x2 + 28x + 15

The first term is,  12x2  its coefficient is  12 .

The middle term is,  +28x  its coefficient is  28 .

The last term, "the constant", is  +15

Step-1 : Multiply the coefficient of the first term by the constant   12 • 15 = 180

Step-2 : Find two factors of  180  whose sum equals the coefficient of the middle term, which is   28 .

     -180    +    -1    =    -181

     -90    +    -2    =    -92

     -60    +    -3    =    -63

     -45    +    -4    =    -49

     -36    +    -5    =    -41

     -30    +    -6    =    -36

     -20    +    -9    =    -29

     -18    +    -10    =    -28

     -15    +    -12    =    -27

     -12    +    -15    =    -27

     -10    +    -18    =    -28

     -9    +    -20    =    -29

     -6    +    -30    =    -36

     -5    +    -36    =    -41

     -4    +    -45    =    -49

     -3    +    -60    =    -63

     -2    +    -90    =    -92

     -1    +    -180    =    -181

     1    +    180    =    181

     2    +    90    =    92

     3    +    60    =    63

     4    +    45    =    49

     5    +    36    =    41

     6    +    30    =    36

     9    +    20    =    29

     10    +    18    =    28    That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above,  10  and  18

                    12x2 + 10x + 18x + 15

Step-4 : Add up the first 2 terms, pulling out like factors :

                   2x • (6x+5)

             Add up the last 2 terms, pulling out common factors :

                   3 • (6x+5)

Step-5 : Add up the four terms of step 4 :

                   (2x+3)  •  (6x+5)

            Which is the desired factorization

Answer: (-6x - 5) • (2x + 3)

The total cost of producing Q units of a given product is given by TC = 500+ 4Q2-12Q. Compute Marginal cost and average cost

Step-by-step explanation:

Answer:

3x>18

Step-by-step explanation:

Three times the number x will be called 3x. If an expression is more or greater than a number, we use the greater symbol: >

So, we can write,

3x>18

Answer:

[tex]y = \dfrac{3}{2} x + 9[/tex]

Step-by-step explanation:

We would like to write the given equation in slope intercept form of the line .

[tex]\longrightarrow 6x - 4y = -36 [/tex]

The slope intercept form of the line is [tex] y = mx + c [/tex] , where

we can rewrite the given equation as ,

[tex]\longrightarrow 6x - 4y = -36 \\ [/tex]

[tex]\longrightarrow -4y = -36 -6x \\ [/tex]

[tex]\longrightarrow -4y = -6( x + 6)\\[/tex]

[tex]\longrightarrow y =\dfrac{-6}{-4}(x + 6)\\[/tex]

[tex]\longrightarrow y = \dfrac{3}{2}(x+6)\\ [/tex]

[tex]\longrightarrow y = \dfrac{3}{2}x +\dfrac{3}{2}\times 6\\[/tex]

[tex]\longrightarrow \underline{\underline{\pmb{ y =\dfrac{3}{2}x +9}}}{}[/tex]

This is the required equation of line in slope intercept form , with ;

Answer:

Refer to the attachment

Answer:

-9

Step-by-step explanation:

225 ÷ -25 = -9

Answer:

C

Step-by-step explanation:Only one that makes sence just look at the graph