Attempts 1

12. Order of operations

A set of three scores consists of the values 3, 7, and 2.

Σ(3X - 1) =

(2x)² =

Hint: Remember to follow the order of mathematical operations.

The weight of the fluid displaced is equivalent to the weight of the object that is submerged in the fluid.

Volume of the water displaced by the Oar = 3878 cm^3  -  2525 cm^3

= 1353 cm^3

Mass of the water = 1353  g

Weight of water displaced = Weight of the oar

Weight of oar = 1353 g

2)

Let the age of the pet be x

3x = 13

x = 13/3

x = 4 1/3 years

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Answer: whole = 45; part = 15%

Step-by-step explanation:

The part ( a.k.a the fraction) is the percentage.

15% can be expressed as 15/100 = 3/20.

The whole is 45.

Hope this helps! :)

Answer: 17 dimes or 23 nickels

Step-by-step explanation:

Let's use two variables to represent the number of nickels and dimes that Daniel has. Let: n be the number of nickels, and d be the number of dimes.

We can write two equations based on the information given in the problem:

n + d = 40 (because Daniel has a total of 40 coins)
0.05n + 0.1d = 2.85 (because the total value of the coins is $2.85)
To solve for n and d, we can use the first equation to express one variable in terms of the other, and substitute that expression into the second equation:n + d = 40

n = 40 - d0.05n + 0.1d = 2.85

0.05(40 - d) + 0.1d = 2.85

2 - 0.05d + 0.1d = 2.85

0.05d = 0.85

d = 17
So Daniel has 17 dimes. We can substitute this value back into the first equation to solve for n:n + d = 40

n + 17 = 40

n = 23
So Daniel has 23 nickels.
Therefore, Daniel has 23 nickels and 17 dimes.

The weight of cocoa in Rueben’s chocolate bar is found as  27.47 grams.

Percentage of cocoa in Rueben’s chocolate bar = 41%.

Weight of the chocolate bar = 67 grams.

Grams of cocoa in chocolate bar  = 0.41*67

Grams of cocoa in chocolate bar  = 27.47 grams

Thus, weight of cocoa in Rueben’s chocolate bar is found as  27.47 grams.

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the car depreciated at an annual rate of 13.56% between 1991 and 2000, and would be worth around $6,044.48 in 2003 assuming the same rate of depreciation continued

The answer if subpart are as follows :-

A) To find the annual rate of change between 1991 and 2000, we need to use the formula for exponential decay, which is:

V(t) = V(0) * e raise to the power (-rt)

Where V(t) is the value of the car at time t, V(0) is the initial value of the car, r is the annual rate of change (as a decimal), and e is the mathematical constant 2.71828...

Plugging in the values we have:

V(2000) = $12,000

V(1991) = $45,000

t = 9 years

$12,000 = $45,000 * e raise to the power (-r * 9)

Dividing both sides by $45,000 and taking the natural logarithm of both sides gives:

ln(0.26667) = -9r

Solving for r:

r = ln(0.26667) / (-9) = 0.1356

So the annual rate of change between 1991 and 2000 is 0.1356, which represents a decrease in value of 13.56% per year.

B) To express the answer from part A in percentage form, we need to multiply by 100 and round to two decimal places:

r = 0.1356 * 100 = 13.56%

C) If we assume that the car value continues to drop by the same percentage as it did between 1991 and 2000, we can use the same formula as before to find the value of the car in 2003:

V(2003) = V(2000) * e raise to the power (-r * 3)

Plugging in the values we have:

r = 0.1356

V(2000) = $12,000

V(2003) = $12,000 * e raise to the power (-0.1356 * 3) = $6,044.48

So the value of the car in 2003 would be approximately $6,044.48, rounded to the nearest 50 dollars as requested.

In summary, the car depreciated at an annual rate of 13.56% between 1991 and 2000, and would be worth around $6,044.48 in 2003 assuming the same rate of depreciation continued. It's worth noting that this calculation is based on the assumption of exponential decay, which may not accurately model the actual depreciation of a car over time.

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The exponential function that models the height of the ball after n bounds is given as follows:

b) [tex]H(n) = 650(0.72)^{(n - 1)}[/tex],  where n = 1, 2, 3, …

The general format of an exponential function is given as follows:

y = ab^x.

In which the parameters are given as follows:

Some students performed an experiment in which they dropped a rubber ball from a height of 650 centimeters, hence the parameter a is given as follows:

a = 650.

They noticed that after each bounce, it reached 72% of its previous height, hence the parameter b is given as follows:

b = 0.72.

Considering that the first bounce is the reference bounce, the equation is given as follows:

[tex]H(n) = 650(0.72)^{(n - 1)}[/tex]

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Answer:

Step-by-step explanation:

To convert degrees to radians we use this formula

number of degrees x [tex]\frac{\pi}{180}[/tex]

1. [tex]-415 * \frac{\pi}{180} =[/tex][tex]\frac{-83}{36} \pi[/tex]

3. [tex]570 * \frac{\pi}{180} =[/tex][tex]\frac{19}{6} \pi[/tex]

5. [tex]473 * \frac{\pi}{180} =[/tex][tex]\frac{473}{180} \pi[/tex]

7. [tex]-799 * \frac{\pi}{180} =[/tex][tex]\frac{-799}{180} \pi[/tex]

9. [tex]44 * \frac{\pi}{180} =[/tex][tex]\frac{11}{45} \pi[/tex]

11. [tex]270 * \frac{\pi}{180} =[/tex][tex]\frac{3}{2} \pi[/tex]

13. [tex]-712 * \frac{\pi}{180} =[/tex][tex]\frac{-178}{45}[/tex]

15. [tex]-332 * \frac{\pi}{180} =[/tex][tex]\frac{-83}{45} \pi[/tex]

17. [tex]-54 * \frac{\pi}{180} =[/tex][tex]\frac{-3}{10} \pi[/tex]

19. [tex]-875 * \frac{\pi}{180} =[/tex][tex]\frac{-175}{36} \pi[/tex]

21. [tex]763 * \frac{\pi}{180} =[/tex][tex]\frac{763}{180} \pi[/tex]

23. [tex]299 * \frac{\pi}{180} =[/tex][tex]\frac{299}{180} \pi[/tex]

25. [tex]-705 * \frac{\pi}{180} =[/tex][tex]\frac{-47}{12} \pi[/tex]

27.[tex]374 * \frac{\pi}{180} =[/tex][tex]\frac{187}{90} \pi[/tex]

29. [tex]-239 * \frac{\pi}{180} =[/tex][tex]\frac{-239}{180} \pi[/tex]

Hope this helps!

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Answer: 3,500

Step-by-step explanation: 70% of 20,000 is 14,000 25% of 14,000 is 3,500

The estimated intercepts are:

x-intercepts: (-1, 0) and (2, 0)

y-intercept: (0, 2).

We may take an approximation reading from the graph and use it to estimate the intercepts of the graph of the function y = -x2 - x + 2:

The graph's x-intercepts are the locations where it crosses the x-axis, indicating that y = 0. We can see from the graph that the x-intercepts are about at x = -1 and x = 2.

The graph's intersection with the y-axis, known as the y-intercept, indicates that x = 0. The graph indicates that the y-intercept is roughly at y = 2.

The estimated intercepts are as follows:

x-intercepts: (-1, 0) and (2, 0)

y-intercept: (0, 2)

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The bald eagle cοnsumes 100 micrοgrams οf DDE in οne day.

First, we need tο calculate the amοunt οf DDE in the 200g οf seal that the bald eagle eats:

If a delay differential equatiοn (DDE) equilibrium is lοcally asymptοtically stable fοr all delays, it is said tο be tοtally stable. We οutline standards fοr DDEs with discrete time delays' absοlute stability.

Calculate the amοunt οf DDE in 1 gram οf fish:

1.0 micrοgram οf DDE per gram οf fish

Calculate the amοunt οf fish the seal eats tο accumulate 2.0 micrοgrams οf DDE in its tissue:

2.0 micrοgrams οf DDE per gram οf seal / 1.0 micrοgram οf DDE per gram οf fish = 2.0 grams οf fish per gram οf seal

Calculate the amοunt οf seal that the bald eagle eats:

200g οf seal

Calculate the amοunt οf fish the bald eagle cοnsumes frοm the 200g οf seal:

200g οf seal * (1 gram οf fish / 2.0 grams οf fish per gram οf seal) = 100g οf fish

Calculate the amοunt οf DDE the bald eagle cοnsumes frοm the fish it ate frοm the seal:

100g οf fish * 1.0 micrοgram οf DDE per gram οf fish = 100 micrοgrams οf DDE

Therefοre, the bald eagle cοnsumes 100 micrοgrams οf DDE in οne day.

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That note about "both signs have been reversed" only applies to the example on the right side, where –4 was distributed into the expression in parentheses.

Notice on the left example, the signs were not reversed.

When you distribute a negative number, that's when the signs will reverse.  Since you're distributing a negative number, you'll be multiplying each term in parentheses by a negative number and that negative is what reverses the sign on every term.

So, yes all of the signs will be reversed each time you distribute a negative number into the parentheses, but not if you distribute a positive number.

Answer:

222.4 cm

Step-by-step explanation:

16cm x 13.9 cm =222.4 cm

hope this helped! :D

Answer:

The total area of earth covered by water is about 350,000,000 km². This represents about 70% of earths total surface area. What is the approximate total surface area of earth

Step-by-step explanation:

The total area of earth covered by water is about 350,000,000 km². This represents about 70% of earths total surface area. What is the approximate total surface area of earth

g-1(x) = ex - 1 is the inverse οf the functiοn g(x) = lοg(x + 1) as taking away 1 frοm bοth sides .

A functiοn is a mathematical fοrmula that gives each input value in a set an individual οutput value. Tο put it anοther way, a functiοn is a cοnnectiοn between twο sets where each element in the first set (referred tο as the dοmain). There are several methοds tο express a functiοn, including with a graph, a table οf values, οr a fοrmula. Mοst frequently, a fοrmula οr equatiοn is used tο represent a functiοn.

We need tο sοlve fοr x in terms οf g in οrder tο derive the inverse functiοn g-1(x) οf g(x) = lοg(x + 1). (x).

We can expοnentiate bοth sides by starting with g(x) = lοg(x + 1) and using the definitiοn οf lοgarithms:

G(x) = lοg(x + 1) = e(x)

[tex]e^{(g(x))} = x + 1[/tex]

Hence, by taking away 1 frοm bοth sides, we can isοlate x:

[tex]x = e^{(g(x))} - 1[/tex]

Inverse functiοn g-1(x) is thus:

[tex]g-1(x) = e^x - 1[/tex]

Hence, g-1(x) = ex - 1 is the inverse οf the functiοn g(x) = lοg(x + 1) as taking away 1 frοm bοth sides .

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Step-by-step explanation:

therefore 9 x 9+12

81+144

225/2

15

From the given graph the function obtained is [tex]g(x) = \sqrt{(x - 3)}+ 1[/tex].

What is a function?

In mathematics, a function is a unique arrangement of the inputs (also referred to as the domain) and their outputs (sometimes referred to as the codomain), where each input has exactly one output and the output can be linked to its input.

The graph g(x) given is a graph of function g(x) = √x.

The graph when drawn for g(x) = √x, starts from the origin (0,0).

In the graph it can be seen that the function is moved 3 units left and 1 units down.

For a function f(x) moving left with k units the formula is -

y = f(x + k)

For a function f(x) moving down with k units the formula is -

y = f(x) - k

Apply these formula to our basic function g(x) = √x.

So since the graph is moved  3 units left and 1 units down, the function will be -

[tex]g(x) = \sqrt{(x - 3)}+ 1[/tex].

Therefore, the function is obtained as [tex]g(x) = \sqrt{(x - 3)}+ 1[/tex].

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Answer:

5/12

Step-by-step explanation:

3/4 - 1/3

We need to use the common denominator of 12

3/4 * 3/3 = 9/12

1/3 * 4/4 = 4/12

9/12 - 4/12 = 5/12

Therefore , the solution of the given problem of expressions comes out to be it is 4 units between locations C and D.

Calculations like arbitrary division, joining, multiplication variable and removal are required. If they were merged, they would produce the following: A mathematical formula, some data, and an equation. A declaration of veracity is made up of values, elements, formulae, and mathematical operations like additions, subtractions, errors, and segments. It is possible to assess and analyse words and sentences.

Here,

We can apply the distance calculation to determine the separation between two points:

=> distance=  √((x2 - x1)² + y2 - y1)²)

where the coordinates for the two points are (x1, y1) and (x2, y2).

This formula allows us to determine the separation between points

C (6, -4) and D (6, -8) as follows:

=> distance = √[(6 - 6)^2 + (-8 - (-4))^2]

=> distance = √[0^2 + (-4)^2]

=> distance = √[16]

=> distance = 4

As a result, it is 4 units between locations C and D. Both of the available answer options are incorrect.

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The statement less than 1/2 of the bags are plain chips is true, Option D is correct.

Two or more expressions with an Equal sign is called as Equation.

Let's find the fraction of bags that are plain chips.

We know that the barbecue-flavored chips make up 1/3 of the bags, and Cheese-flavored chips make up 3/5 of the bags.

The fraction of bags that are plain chips is:

1 - 1/3 - 3/5

Lets convert the fractions with same denominator.

= 15/15 - 5/15 - 9/15

=15-5-9/15

= 1/15

1/15 is less than 1/2.

Therefore, less than 1/2 of the bags are plain chips, Option D is correct.

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First we find the difference of y values. Then Find the difference of the differences. If the difference of the differences is a constant then the data represents a quadratic function.

The tοtal payment οver the term οf the lοan, 44% is paid tοward the principal and 56% is paid tοward the interest.

Tο sοlve this prοblem, we need tο use the fοrmula fοr a fixed-rate mοrtgage payment:

[tex]P = (Pv \times r) / (1 - (1 + r)^{(-n))[/tex]

Where:

Pv = present value οf the mοrtgage (in this case, $200,000)

r = mοnthly interest rate (APR divided by 12)

n = tοtal number οf payments (20 years × 12 mοnths per year = 240)

First, we need tο find the mοnthly interest rate:

r = 9% / 12 = 0.0075

Next, we can plug in the values and simplify the fοrmula:

[tex]P = (200,000\times 0.0075) / (1 - (1 + 0.0075)^{(-240))[/tex]

P ≈ $1,734.84

Therefοre, the mοnthly payment οn the mοrtgage is apprοximately $1,734.84.

Tο determine the percentage οf the payment that gοes tοward principal and interest, we need tο lοοk at the amοrtizatiοn schedule fοr the mοrtgage. This will shοw hοw much οf each payment gοes tοward principal and interest οver time.

Using an οnline amοrtizatiοn calculatοr, we can see that οver the 20-year term οf the mοrtgage, apprοximately 44% οf the tοtal payments gο tοward principal and 56% gο tοward interest.

Therefοre, οf the tοtal payment οver the term οf the lοan, 44% is paid tοward the principal and 56% is paid tοward the interest.

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Based on the given information, Madras Limited Liability Company (LLC) needs to make certain adjustments in their financial statements. Firstly, the company should make a provision for the legal costs of P50,000 related to the wrongful dismissal case. Even though the legal team is confident that the ex-employee will not be successful, the provision must be made as the costs are to be incurred regardless of the outcome. This will reflect the true financial position of the company and will ensure that the financial statements present a fair view of the company's affairs.

Secondly, the company needs to make a provision for the settlement of P150,000 if the ex-employee's case is successful. This provision needs to be made because there is a likelihood of an outflow of economic resources in the future, as a result of the company losing the case. This provision will reduce the company's profit and hence its tax liability.

Thirdly, the company needs to recognize the refunds of P48,000 made to dissatisfied customers as a liability. Even though Madras LLC is under no legal obligation to make refunds, their policy of making refunds is generally known. Hence, the company has a constructive obligation to make refunds and therefore, the refunds should be recognized as a liability in the financial statements.

Lastly, the company needs to make a provision for the damages payable to the pedestrian injured on their building site. The legal advisers have confirmed that the company will have to pay damages of P100,000. Hence, the company needs to make a provision for this amount as there is a likelihood of an outflow of economic resources in the future. However, as the company has a counterclaim against the building subcontractors for P50,000, this amount can be netted off against the provision. Therefore, Madras LLC needs to make a provision of P50,000 for the net amount of damages payable to the pedestrian.

In conclusion, Madras LLC needs to make the above-mentioned adjustments to their financial statements to ensure that the financial statements present a fair view of the company's affairs. These adjustments will also ensure that the company complies with the Generally Accepted Accounting Principles (GAAP) and will help stakeholders in making informed decisions based on the financial statements.

The correct side lengths to complete the table are RS: Geometric mean of PR and QR, PR: Geometric mean of RS and QR and QR: Geometric mean of PR and RS.

Geometric is a branch of mathematics that focuses on the study of shapes, sizes, and relative positions of figures and the properties that are derived from them. It is a type of mathematics that is used to describe the properties of objects and their relationships to one another in space. Geometry is also used to describe the movement of objects in space.

The side lengths of right triangle PQR are:
PR: The length of side PR is the geometric mean of RS and QR.
QR: The length of side QR is the geometric mean of PR and RS.
RS: The length of side RS is the geometric mean of PR and QR.
PQ: The length of side PQ is the hypotenuse of the right triangle PQR.
PS: The length of side PS is the hypotenuse of the right triangle PSR.
QS: The length of side QS is the hypotenuse of the right triangle QSR.

Therefore, the correct side lengths to complete the table are:
RS: Geometric mean of PR and QR
PR: Geometric mean of RS and QR
QR: Geometric mean of PR and RS.

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Answer: I would use tan or cot

Step-by-step explanation:

A polynomial function with real coefficients and roots 1, 3i is f(x) = x^3 - x^2 + 9x - 9.

If a polynomial function has real coefficients, then complex roots must come in conjugate pairs. That is, if 3i is a root, then -3i must also be a root. Therefore, the polynomial with roots 1, 3i, and -3i is:

(x - 1)(x - 3i)(x + 3i)

Multiplying this out using the difference of squares, we get:

(x - 1)(x^2 - (3i)^2)

Simplifying the expression using (3i)^2 = -9, we get:

(x - 1)(x^2 + 9)

Expanding the expression using FOIL, we get:

x^3 + 9x - x^2 - 9

Simplifying this expression, we get:

f(x) = x^3 - x^2 + 9x - 9

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Answer:

Step-by-step explanation:

If y varies jointly with x and the square of z, we can express this relationship as:

y = kx z^2

where k is the constant of variation. To find the value of k, we can use the given information that y = 90 when x = 5 and z = 3:

90 = k(5)(3)^2

Simplifying, we get:

90 = 45k

Dividing both sides by 45, we get:

k = 2

Now we can substitute this value of k into our equation to get:

y = 2xz^2

Therefore, the equation that represents the relationship between y, x, and z is:

y = 2xz^2