Hi there!
II. Linear momentum of the system is zero.
This is an example of a RECOIL collision. With the Law of Conservation of Momentum, momentum remains constant before and after the collision.
Thus, the total momentum would also be equivalent to zero after the collision.
when did humans learn that the earth is not the center of the universe?
Answer:
When did humans learn that the Earth is not the center of the universe?
Answer
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4 Answers
Asked in 3 Spaces


Science - Next Generation
Alexander Somm
, Consultant, Investor Relations at Novelpharm AG (2015-present)
Answered Oct 16
What, it isn’t?!
Sorry, I had to.
As far as I have read and understood, the Sumerians and later the Babylonians both had astronomical calendars that already differentiated planets and stars. Earth was not the center to them, the Sun likely was. That was around 2,200 - 1,600 BC.
After that, Greek philosopher Aristarchus of Samos (310 - 230 BC) was the first (recorded) to have believed the solar system was organized around the Sun, rather than the Earth. His heliocentric model was unpopular during Aristarchus’ lifetime, although it would inspire astronomers centuries later, such as Copernicus and Galileo.
Now, there are numerous archeological findings (cave paintings) and studies, that all suggest an understanding of complex astronomy in prehistoric times dating back as far as 40,000 years. This also explains how early, prehistoric migrants may have navigated the seas.
Explanation:
hope it helps
have a good day
If you were traveling 60 mph and not wearing a seatbelt and collided with a fixed object, how fast would you be traveling when you hit the windshield
Your speed when your car hits a fixed object is 60 mph.
The given parameters:
Your initial speed, v = 60 mphWhat is relative velocity?Relative velocity tells us how fast we are traveling from a fixed point or reference point.
When travel at 60 mph in a car, you are moving at the same rate with the car.If you are not wearing a seat belt, when you hit a fixed object, you will move forward at the same rate as the car's speed.Thus, we can conclude that your speed when your car hits a fixed object is 60 mph.
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A block of mass 1.0 kg rests on a trolley of mass 4.0 kg. The coefficient of dynamic friction between the block and the trolley is 0.30. A horizontal force f = 5.0 n acts on the block. The block slides over the trolley. What is the acceleration of the trolley?
Answer:
the acceleration of the trolley is the acceleration of the trolley is 0.75 m/s^-2
Explanation:
friction force between the block and the trolley
= 1×0.3×9.8
= 2.94 N
(F = ma)
the acceleration of the trolley
= friction force/mass
= 2.94/4
= 0.735 m/s^-2
= 0.75 m/s^-2
The acceleration of the trolley will be 0.75 m/s².Acceleration is the ratio of the force to the mass.
What is the friction force?It is a type of opposition force acting on the surface of the body that tries to oppose the motion of the body. its unit is Newton (N).
Mathematically it is defined as the product of the coefficient of friction and normal reaction.
The friction force between the block and the trolley is found as;
[tex]\rm F_f = \mu N \\\\ \rm F_f = \mu \times mg \\\\ \rm F_f = 0.30 \times 1 \timess 9.81 \\\\ \rm F_f= 2.94 \ N[/tex]
Mechanical force is equal to the product of the mass and the acceleration which is equal to the frictional force;
[tex]\rm F_f =F=ma \\\\ \rm a = \frac{F}{m} \\\\ \rm a = \frac{2.94}{4} \\\\ a=0.735 \ ms^{-2}[/tex]
Hence the acceleration of the trolley will be 0.75 m/s².Acceleration is the ratio of the force to the mass.
To learn more about the friction force refer to the link;
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the breaks on a 15,680 N car exert a stopping force of 640 N.
Recoil is noticeable if you throw a heavy ball while standing on roller skates. If instead you go through the motions of throwing the ball but hold onto it, your net recoil velocity will be
Answer:
Since there is no external force, there is no change (movement) in the center of mass. Internally, the center of mass might change position, but the external result is still zero net velocity.
The net recoil velocity must be zero.
If the forces acting on an object at rest are ______,the object will remain at rest.
Answer:
friction. or gravity both ofbthem .....................
..
. A teacher pushes a desk across the floor for a distance of 5 meters. She exerted a horizontal force of 20N. How much work was done?
Answer:
100 J work was done.
Hope you could get an idea from here.
Doubt clarification - use comment section.
PLEASE HELP!!
5. A 700 kg race car travels
around the track at 65 m/s. The track has a radius of 75 m.
a. What is the centripetal acceleration?
b. What is the centripetal force?
c. Is the net force on the car less than, equal to, or greater than the centripetal force? Why?
Hi there!
a.
The equation for centripetal acceleration is as follows:
[tex]\large\boxed{a_c = \frac{v^2}{r}}}[/tex]
Plug in the given values to solve:
[tex]\large\boxed{a_c = \frac{(65)^2}{75} = 56.33 m/s^2}[/tex]
b.
According to Newton's Second Law:
[tex]\large\boxed{\Sigma F = ma}}[/tex]
The acceleration is v²/r, so the net force is:
[tex]\large\boxed{\Sigma F = m(\frac{v^2}{r})}}[/tex]
Multiply by the given mass:
[tex]\large\boxed{\Sigma F = 700(56.33) = 39433.33 N}}[/tex]
c.
There is NO net force in the vertical direction since the object is NOT accelerating in the vertical direction (normal force and weight cancel).
Thus, the ONLY net force experienced by the object is in the horizontal direction and is EQUAL to the centripetal force.
Describe the direction in which each object will accelerate. If the object won't accelerate, write "no acceleration." Explain what might be happening to each object in terms of its overall motion.
Answer:
No acceleration. All of the forces are acting equally on the paper air plane therfore It isn't going to move any where.
The Earth currently has an orbital period of 1 year and a semi-major
axis length of 1 AU. If the Earth's orbit changed and the semi-major
axis length increased to 1.1 AU, how would the Earth's orbital period change?
A: It would increase by 0.15 years
B: It would increase by 0.032 years
C: It would decrease by 0.15 years
D: It would decrease by 0.032 years
The Earth's orbital period change is A: It would increase by 0.15 years
Using Kepler's third law which states that the square of the orbital period of the planet is directly proportional to the cube of its distance from the sun.
So, T² ∝ R³
T'²/T² = R'³/R³ where
T = orbital period at R = 1 yearR = initial axis length = 1 AUT' = orbital period at R'R' = final axis length = 1.1 AU.So, making T' subject of the formula, we have
T' = [√(R'/R)³]T
T' = [√(1.1 AU/1 AU)³] × 1 year
T' = [√(1.1)³] × 1 year
T' = √1.331 × 1 year
T' = 1.15 × 1 year
T' = 1.15 years.
So, the change in the Earth's orbital period ΔT = T' - T
= 1.15 years - 1 year
= 0.15 years
Since this is positive, the orbital period increases by 0.15 years.
So, the Earth's orbital period change is A: It would increase by 0.15 years
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A 0.24 kg mass with a speed of 0.60 m/s has a head-on collision with a 0.26 kg mass that is traveling in the opposite direction at a speed of 0.20 m/s. Assuming that the collision is perfectly inelastic, what is the final speed of the combined masses?
The final speed of the combined masses is 0.186m/s
According to the law of collision, the sum of the momentum of the bodies before the collision is equal to the momentum after the collision.
Mathematically;
m1u1 - m2u2 = (m1+m1)v
v is the final speed of the combined masses.Substituting the given parameters;
0.24(0.6) - 0.26(0.2) = (0.24+0.26)v
0.144 - 0.052 = 0.5v
0.092 = 0.5v
v = 0.092/0.5
v = 0.184m/s
Hence the final speed of the combined masses is 0.186m/s
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how to find time with acceleration and velocity
anyone to help with this question
Answer:
i can
Explanation:
i know what's the answer
Which action will cause the tennis ball to move the farthest?
You gently hit the tennis ball.
You pull the tennis racket back and up and hit the ball hard as you swing down.
You hit the tennis ball from another side to change its direction.
You tap the tennis ball lightly.
Answer:
2nd option at the most
Explanation:
leave a thanks if helped
If the energy in a mechanical wave increases or decreases, what is also going to increase or decrease? A wavelength B amplitude с frequency d refraction
Answer:
i think wave lengh not 100% sure tho
If the energy of the mechanical wave will increase or decrease, then the wavelength will also change accordingly. Hence, option A is correct.
What is Wavelength?The distance between two identical locations (adjacent crests) in successive cycles is known as the wavelength, and it is used to describe waveform signals that are transmitted over wires or into space. Typically, in wireless systems, this length is specified in meters (m), centimeters (cm), or millimeters (mm). The wavelength is more frequently described in nanometers (nm), which are units of 10⁻⁹ m, or angstroms, which are units of 10⁻¹⁰ m, for infrared (IR), visible light (UV), and gamma radiation.
Frequency, which is defined as the number of wave cycles per second, and wavelength have an inverse relationship. The wavelength of a signal decreases with increasing frequency, or we can say that wavelength and refractive index are inversely proportional to each other.
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1. Which of these is not a spherical mirror?
a) Concave mirror
b) Convex mirror
c) Plane mirror
d) None of these
Answer:
C.Plane mirror this is the answer of this question.
None of the above. That is option D.
A spherical mirror is defined as a mirror that has a surface that reflects curved rays. It is also called a curved mirror.
Types of spherical mirror include:
Concave mirror: This has a reflective surface that is curved inward and away from the light source. It reflects light inward to one focal point.Example of concave mirror are Torch lights and automobile headlights.
Convex mirror: These are the spherical mirror that reflects light outwards and towards the light source.Example of convex mirror is the magnifying glasses and telescopes.
Plane mirrors: This is a type of spherical mirror with a flat surface. Reflection of light occurs in plane mirror but it's center of curvature is infinite because it's flat.Therefore, concave, convex and plane mirrors are all examples of a spherical mirror.
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what is the difference between an asteroid and a meteoroid
Answer:
Asteroids smaller than planets and meteroids are small piece of an asteroid burns up upon enetering Earths atmosphere
what is the meaning of " hi baby girl "
Explanation:
it's mean hI small little cute baby girl ...
Which statement describes the magnetic field inside a bar magnet? It points from north to south. It points from south to north. It forms loops inside the magnet. There is no field within the magnet.
Inside the bar magnet, the magnetic field points from north to south. Statement A is correct.
Magnetic Field:
It is defined as a vector field or the influence of the magnet on the electric current, charges and ferromagnetic substance.
The strength of magnetic field is depends up on the numbers of magnetic field lines per unit area.
Magnetic field lines emerge from the North pole and end in the South pole of a bar magnet. Inside the magnet are also present inside the bar magnet and never intersect at any point.Therefore, inside the bar magnet, the magnetic field points from north to south.
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Answer:b
Explanation:
A water balloon is launched with a speed of 40 m/s at an angle of 60 degrees to the horizontal. What is the vertical component of the velocity?
a 40 m/s
b 34.6 m/s
c 0 m/s
d 20 m/s
Vertical component = 40 m/s x sin(60) = 34.6 m/s
Answer: b. 34.6 m/s
Help it’s multiple choice 11 through 15 please!
1. • Here, force of gravity on the block = 20 N.
• Therefore, the normal force will also be the same, i.e., 20 N [According to Newton's Third Law, on every action, there is an equal and opposite reaction]
• The coefficient
[tex] u_{k} = 0.4[/tex]
• Force of friction =
[tex]u_{k} \times \: normal \: \: \: force \\ = 0.4 \times 20N \\ = 8N[/tex]
• Hence, the force of sliding friction between the block and the ground is 8 N.
• So, it is option c. 8 N
2. The answer is option d. continue in the same direction with no change in speed.
We know, force = mass × acceleration. When force is 0, then acceleration will also be 0 since mass cannot be 0. So, there will be no change in speed.
3. It is option b. force that is required to give a one kilogram object the acceleration of 1 m/s^2.
Newton is the SI unit of force. As mentioned earlier, force = mass × acceleration. The SI unit of mass and acceleration is Kg and m/s^2 respectively.
So, 1 N = 1 Kg × 1 m/s^2.
4. It is d. not zero.
Acceleration is the change in speed. So, if the force is zero, then acceleration will not occur.
5. Force = 2 N
Acceleration of the object A = 2 m/s^2.
Acceleration of the object B = 1 m/s^2.
Therefore, mass of the object A = 2 N ÷ 2 m/s^2 = 1 Kg
And, mass of the object B = 2 N ÷ 1 m/s^2 = 2 Kg
So, the mass of object B is greater than that of object A.
Hence, the answer is option c. Object B has more mass.
Hope you could get an idea from here.
Doubt clarification - use comment section.
Something has a mass of 40 kg and a velocity of 1 m/s
How much kinetic energy does it have?
Part 2: If it doubles its mass, will its KE also double?
[tex]\\ \sf\Rrightarrow K.E=\dfrac{1}{2}mv^2[/tex]
[tex]\\ \sf\Rrightarrow K.E=\dfrac{1}{2}(40)(1)^2[/tex]
[tex]\\ \sf\Rrightarrow K.E=20J[/tex]
Part 2:-m=80kg[tex]\\ \sf\Rrightarrow K.E=\dfrac{1}{2}(80)(1)^2[/tex]
[tex]\\ \sf\Rrightarrow K.E=40J[/tex]
YesA 25 N force acts on a box moving along a plane at a distance of 20 meters. What is the work it does with this force?
Help!!
Answer:
500 J.
Explanation:
Work done = force * distance
= 25 * 20
= 500 Joules.
ignoring air resistance, an object falling toward the surface of the earth has a velocity that is
A 100 g mass of tungsten at 100.0°C is placed in 200 g of water at 20.0°C. The
mixture reaches equilibrium at 21.6°C. Calculate the specific heat of tungsten
The specific heat capacity of tungsten given the data from the question is 0.17 J/gºC
Data obtained from the questionMass of tungsten (M) = 100 g
Temperature of tungsten (T) = 100 °C
Mass of water (Mᵥᵥ) = 200 g
Temperature warm water (Tᵥᵥ) = 20 °C
Specific heat capacity of the water (Cᵥᵥ) = 4.184 J/gºC
Equilibrium temperature (Tₑ) = 21.6 °C
Specific heat capacity of tungsten (C) = ?
How to determine the specific heat capacity of tungstenHeat loss = Heat gain
MC(T – Tₑ) = MᵥᵥCᵥᵥ(Tₑ – Tᵥᵥ)
100 × C × (100 – 21.6) = 200 × 4.184(21.6 – 20)
100 × C × 78.4 = 1338.88
Divide both sides by 100 × 78.4
C = 1338.88 / (100 × 78.4 )
C = 0.17 J/gºC
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Forces are needed to make a car do which of these?
slow down
speed up
stay on the ground
all of the above
Both igneous and sedimentary rock can become metamorphic rock if enough ________________ are applied.
As best you can, describe how we can tell the age of the Earth and rocks found on it.
Answer:
We can determine the age of the Earth and the rocks found on Earth with techniques such as measuring ice cores and digging and analysing fossils.
Explanation:
Hopefully this helped!
Calcula el valor de la velocidad de las ondas sonoras en el agua sabiendo que su
densidad es 1.10 3 kg/m 3 y su módulo de comprensibilidad vale 2,16x10 9 N/m 2 ¿Cuál
es la longitud de onda de las ondas sonoras en el agua si su frecuencia es de 1000hz?
1) Inicialmente, debemos determinar la velocidad de las ondas sonoras a través del agua ([tex]v[/tex]), en metros por segundo:
[tex]v = \sqrt{\frac{K}{\rho} }[/tex] (1)
Donde:
[tex]K[/tex] - Módulo de compresibilidad, en newtons por metro cuadrado.[tex]\rho[/tex] - Densidad del agua, en kilogramos por metro cúbico.Si sabemos que [tex]\rho = 1\times 10^{3}\,\frac{kg}{m^{3}}[/tex] y [tex]K = 2,16\times 10^{9}\,\frac{N}{m^{2}}[/tex], entonces la velocidad de las ondas sonoras es:
[tex]v = \sqrt{\frac{2,16\times 10^{9}\,\frac{N}{m^{2}}}{1\times 10^{3}\,\frac{kg}{m^{3}} } }[/tex]
[tex]v\approx 1469,694\,\frac{m}{s}[/tex]
La velocidad de las ondas sonoras es aproximadamente 1469,694 metros por segundo.
2) Luego, determinamos la longitud de onda ([tex]\lambda[/tex]), en metros, mediante la siguiente fórmula:
[tex]\lambda = \frac{v}{f}[/tex] (2)
Donde [tex]f[/tex] es la frecuencia de las ondas sonoras, en hertz.
Si sabemos que [tex]v\approx 1469,694\,\frac{m}{s}[/tex] y [tex]f = 1000\,hz[/tex], entonces la longitud de onda de las ondas sonoras es:
[tex]\lambda = \frac{1469,694\,\frac{m}{s} }{1000\,hz}[/tex]
[tex]\lambda = 1,470\,m[/tex]
La longitud de onda de las ondas sonoras es 1,470 metros.
Para aprender más sobre las ondas sonoras, invitamos a ver esta pregunta verificada: https://brainly.com/question/1070238
A bike accelerates uniformly from rest to a speed of 7.10 m/s over a distance of 35.4 m. Determine the acceleration of the bike.
So acceleration of the bike which started from rest, reaches at speed of 7.10 m/s by travelling distance 35.4 m will be 0.712 m/ sec^2.