Answer:
[tex]15\%[/tex].
Explanation:
The efficiency of a machine is the percentage of energy input that was turned into useful energy.
The power rating of this lamp is [tex]40\; \rm W[/tex] (same as [tex]40\; \rm J \cdot s^{-1}[/tex],) meaning that [tex]40\; \rm J[/tex] of energy is supplied to this lamp every second.
The question states that [tex]34\; \rm J[/tex] out of that [tex]40\; \rm J[/tex] of energy input would be turned into heat, which is not useful energy output in this scenario. Assuming that all other forms of energy loss is negligible. The rest of the [tex](40\; \rm J - 34\; \rm J) = 6\; \rm J[/tex] of energy supplied to this lamp would be turned into useful energy output.
Thus, every second, this lamp would receive [tex]40\; \rm J[/tex] of energy input and would outputs [tex]6\; \rm J[/tex] of useful work. The efficiency of this lamp would be:
[tex]\begin{aligned}& \text{Efficiency} \\ =\; & \frac{\text{Useful energy out}}{\text{Total energy in}} \times 100\% \\ =\; & \frac{6\; \rm J}{40\; \rm J} \times 100\%\\ =\; &15\% \end{aligned}[/tex].
PE:
Write T in the blank if the statement is true and E if it is false.
_____1. A basketball game starts with a jump ball.
_____2. Basketball is a cardiovascular work-out.
_____3. The middle of the basketball court is called the sideline.
_____4. Unlimited substitutions are allowed during a regular basketball game.
_____5. If the ball crosses the sideline, it is considered out of bounds and goes to the other team.
_____6. A turnover is any loss of the ball without a shot being taken.
_____7. A player may intentionally kick the ball for the team's benefit.
_____8. When dribbling a ball, a basketball you want to keep the ball below your waist and off to the side of your body.
_____9. If your opponent shoots at the wrong hoop your team receives the points.
_____10. After a player stops dribbling the ball in basketball, he or she is allowed 4 steps to pass or shoot.
Answer:
The answers are:
T, T, F, F, T, T, F, F, T, T, F
Good luck!
1) A blinking light of constant period is situated on a lab cart. Which diagram best represents a photograph of
the light as the cart moves with constant velocity?
How do I solve this?
Option C with uniform displacement at each time interval represents the photograph of light as the cart moves with constant velocity.
At constant velocity, the change in displacement with time is uniform. The displacement of the given object in motion increases at equal rate.
At constant velocity, the initial velocity is equal to the final velocity.
v₁ = v₂
The acceleration of the object at constant velocity is zero, because the change in velocity with time will be zero.
[tex]a = \frac{\Delta v}{\Delta t} \\\\a = \frac{v_2- v_1}{t} \\\\v_2 = v_1\\\\a = \frac{v_1 - v_1}{t} \\\\a = 0[/tex]
Thus, from the given options we can conclude that option C with uniform displacement at each time interval represents the photograph of light as the cart moves with constant velocity.
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Which of the following is "NOT" a theory of the formation of the universe?
A. Steady State Theory
B. Doppler Theory
C. Oscillating Theory
D. Big Bang Theory
Answer:
Doppler Theory
Explanation:
it's a theory regarding the change in wave frequency during the relative motion between a wave source and its observer.
Which of the following is the goal of physical fitness test? *
a. to determine the level of fitness.
b. to identify the area of development/improvement.
c. all of the above
d. to identify strengths and weaknesses.
Answer
C
hope this helps!!
*please mark brainliest if correct!! Trying to level up!!
For the equation BaCl2 + Na2SO4 → BaSO4 + 2NaCl, how many chlorine atoms are on the reactants side and on the products side?
Answer:2 reactants 2 products.
this is a balanced chemical equation. That means the number of chlorine before the arrow will be the same after the arrow
Explanation: i think this answer will help you very much
An open train car rolls along a track while it is being filled with sand. There is negligible friction. As a result of
the accumulating sand, what happens to the speed of the train car? (Assume negligible friction and the cart is
just rolling along, not receiving any additional force to regulate its speed.)
Answer:
Explanation:
that`s a the train car, that you asked the meaning, of that if the train car rolls it`s doing it`s speed, and it`s not ganna fall off the the trail of the train, car.An open train car rolls along a track while it is being filled with sand. There is negligible friction. The speed of the train car will be slowed down.
What is friction?Between two surfaces that are sliding or attempting to slide over one another, there is a force called friction. For instance, friction makes it challenging to push a book down the floor.
Friction always moves an object in a direction that is counter to the direction that it is traveling or attempting to move.
Speed indicates the rate of movement of something or someone. If you know how far something has traveled and how long it took to get there, you can calculate its average speed. Speed is calculated as follows: speed = distance x time.
Therefore, an open railway car is packed with sand and is rolling along a track. Very little friction exists. The railway car's speed will be slowed down.
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23 and 24 only please help!
Answer:
23: Acceleration 24:1m/s^2
Explanation:
[tex]a = (v_f - v_i) /delta(t)\\a=(16-10)/6\\a=6/6\\a=1m/s^2[/tex]
A bicycle accelerates from rest to 6m/s in a distance of 50m, calculate the acceleration
The acceleration of the bicycle is 0.12 m/[tex]s^{2}[/tex].
We know that acceleration is the change in velocity divided by the change in time. In this case, the bicycle is accelerating from rest to a velocity of 6 m/s. The change in time is the time it takes the bicycle to travel 50 m.
We can use the following equation to find the acceleration:
a = (v2 - v1) / t
where:
a is the acceleration
v2 is the final velocity (6 m/s)
v1 is the initial velocity (0 m/s)
t is the time
Plugging in the values from the problem, we get:
a = (6 m/s - 0 m/s) / 50 s
= 0.12 m/[tex]s^{2}[/tex].
Therefore, the acceleration of the bicycle is 0.12 m/[tex]s^{2}[/tex].
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In a game of pool, a cue ball rolls without slipping toward the stationary eight ball with a momentum of 0.23 kg. After the two balls collide, the final momentum of the cue ball is 0.01 kg. what is the magnitude of the final momentum of the eight ball
This question involves the concepts of the law of conservation of momentum.
The magnitude of the final momentum of the eight ball is "0.22 N.s".
According to the law of conservation of momentum:
[tex]P_{i1}+P_{i2}=P_{f1}+P_{f2}[/tex]
where,
[tex]P_{i1}[/tex] = initial momentum of the cue ball = 0.23 N.s
[tex]P_{i2}[/tex] = initial momentum of the eight ball = 0 N.s (since ball is initially at rest)
[tex]P_{f1}[/tex] = final momentum of the cue ball = 0.01 N.s
[tex]P_{f2}[/tex] = final momentum of the eight ball = ?
Therefore,
[tex]0.23\ N.s + 0\N.s = 0.01\ N.s+P_{f2}\\\\P_{f2} = 0.22\ N.s[/tex]
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what is the capacitance of capacitor
Answer:
The capacitance C of a capacitor is defined as the ratio of the maximum charge Q that can be stored in a capacitor to the applied voltage V across its plates. In other words, capacitance is the largest amount of charge per volt that can be stored on the device: C = Q V . 1 F = 1 C 1 V .
Explanation:
A capacitor's capacity to hold an electric charge when a potential difference (voltage) is applied across its plates is measured by the capacitance of the device.
It can be calculated using the formula C = Q/V,
where Q is the electric charge stored on the capacitor in coulombs (C), C is the capacitance in farads (F), and V is the voltage across the capacitor in volts (V). The capacitor's physical properties, such as the area of the plates, the space between them (dielectric separation), and the substance between the plates (dielectric constant), all affect capacitance. A better charge storage capability is indicated by a higher capacitance value.
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in the bohr model, what is the ratio of its kinetic energy to its potential energy?
The centrifugal force C = mv^2/r = kq^2/r^2 = P centripetal force. m is the electron mass, q are the proton and electron charges (opposites), and r is the Bohr radius.
Thus 1/2 mv^2/r = 1/2 kq^2/r^2 and KE = 1/2 mv^2 = 1/2 kq^2/r = 1/2 PE
Therefore KE/PE = 1/2, no matter what state the electron is in.
Iron, Nickel, Copper, Zinc... These are all what kind of metals?
Answer:
there very old
Explanation:
Solve the science problem
Answer:
ybuTouch and hold a clip to pin it. Unpinned clips will be deleted after 1 hour.Touch and hold a clip to pin it. Unpinned clips will be deleted after 1 hour.Touch and hold a clip to pin it. Unpinned clips will be deleted after 1 hour.Touch and hold a clip to pin it. Unpinned clips will be deleted after 1 hour.Touch and hold a clip to pin it. Unpinned clips will be deleted after 1 hour.
Which car will experience a greater KE, a car traveling at 16 m/s or a half as massive car traveling at 32 m/s
Answer:
The car that is hald as massive
Explanation:
We can use the eqation for kinetic energy to solve this problem
KE = 1/2mv^2 (where m is mass and v is velocity/speed)
Lets give the original car a mass of 100kg and use the equation
KE = 1/2(100kg)(16m/s)^2 = 12800J
and now lets find kinetic energy of the half as massive car
KE2 = 1/2(50kg)(32m/s)^2 = 25600J
From this, we find that the hald as massive car will experience a greater kinetic energy while travling at double the velocity
Why would poor clusters of galaxies be more likely to have irregular shapes then rich
clusters
These Milky Way companion galaxies are easily visible from dark locations in the Southern Hemisphere. Prime examples of erratic galaxies are the Large and Small Magellanic clouds (left and right, respectively).
What clusters of galaxies likely to have irregular shapes?In comparison to a rich cluster, the poor cluster typically has a slightly more erratic shape. A number of smaller galaxies orbit each major spiral. The Small and Large Magellanic clouds are the two most well-known examples of atypical galaxies.
When two galaxies collide, irregular galaxies frequently result. This unusual Cartwheel Galaxy was created when a tiny galaxy slid through the centre of a massive spiral galaxy.
Therefore, Rich clusters are other clusters that include hundreds to thousands of galaxies. A weak cluster can't cling to its members strongly because of its low bulk.
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pls answer this question is due today
=============================================
Explanation:
To compute the speed, we divide the distance traveled over the time duration.
For instance, if a car goes 100 km in 5 hours, then its speed is 100/5 = 20 km per hour.
-----------------
For section A, the car travels 30 km over the course of 2 hours (since 11:00-9:00 = 2:00)
speed = distance/time = (30 km)/(2 hrs) = 15 km/hr
-----------------
We don't need to do any computations for section B. It's a flat horizontal line, so the speed is zero. There's no change in distance, so the car is stationary for this 1 hour period.
You could say speed = distance/time = 0/1 = 0 km/hr if you wanted.
-----------------
For section C, its change in distance is 60-30 = 30 km and the change in time is 0.5 hour (because it spans from 12:00 to 12:30)
So, speed = distance/time = (30 km)/(0.5 hr) = 60 km/hr
The steeper slope of section C, compared to section A, means the car is going faster.
-----------------
Section D spans from 12:30 to 14:00. This is a time period of 14:00-12:30 = 1:30 = 1.5 hours. The change in distance is 60 km
(60 km)/(1.5 hrs) = 40 km/hr
The speed of the car during section D is 40 km per hour.
Side note: if you were talking about velocities instead of speeds, then section D would have a negative velocity of -40 km/hr to indicate the car is going the opposite direction (compared to sections A and C). However, speed is always nonnegative.
An object of length 3.00 cm is inside a plastic block with index of refraction 1.40. If the object is viewed from directly above, what is the length of its image?
Given,
length of object, [tex]h_o = 3 cm[/tex]
We know, for flat refracting surface,
Image distance = object distance
So,
magnification is = [tex]-1[/tex]
length of the image,
[tex]h_i = magnification * h_o\\\\h_i = -1 * 3 \\\\h_i = -3cm[/tex]
Here, negative sign means inverted image.
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Two billiard balls having the same mass and speed roll directly toward each other. What is their combined momentum after they meet
Their combined momentum after they meet is 0.
What is law of conservation of momentum?According to the law of conservation of momentum, absent an external force, the combined momentum of two or more bodies operating upon one another in an isolated system remains constant. As a result, momentum cannot be gained or lost.
Let the mass of each billiard balls = m.
If the initial velocity of first ball is u; according to the question, the initial velocity of the second ball be -u.
Hence, initial momentum of the first ball is: P₁ = mu
initial momentum of the second ball is: P₂ = -mu
Hence, total initial momentum of the two balls = P₁ + P₂ = mu + ( -mu) = 0.
So, according to law of conservation of momentum:
Their combined momentum after they meet is = 0.
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The combined momentum of the two billiard balls after they meet is zero.
When two pool balls of the same size and speed roll directly at each other and collide, their momentum will increase.
Let us denote the speed of the first ball as [tex]\rm p_1[/tex] and the speed of the second ball as [tex]\rm p_2[/tex]. The momentum of the balls are equal in magnitude but opposite in direction because they have the same mass and velocity.
[tex]\rm p_1= -p_2[/tex]
When the balls collide, their momentum increases:
Total momentum after the collision= [tex]\rm p_1+ p_2[/tex]
Substituting the relationship
[tex]\rm p_1= -p_2[/tex]
Total momentum after the collision
[tex]\rm p_1- p_1= 0[/tex]
Therefore, the combined momentum of the two billiard balls after they meet is zero.
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A go cart with a mass of 60 kg is moving at a rate of 10 m/s. How much Kinetic Energy does the go cart have?
Answer:
3000 JExplanation:
The kinetic energy of an object can be found by using the formula
[tex]k = \frac{1}{2} m {v}^{2} \\ [/tex]
m is the mass in kg
v is the velocity in m/s
From the question
m = 60 kg
v = 10 m/s
We have
[tex]k = \frac{1}{2} \times 60 \times {10}^{2} \\ = 30 \times 100 \\ = 3000[/tex]
We have the final answer as
3000 JHope this helps you
Answer:
[tex]\boxed {\boxed {\sf 3000 \ J}}[/tex]
Explanation:
Kinetic energy is the energy an object has due to motion. It is calculated using the following formula:
[tex]KE=\frac{1}{2} mv^2[/tex]
The mass of the go-cart is 60 kilograms and the velocity is 10 meters per second.
m= 60 kg v= 10 m/sSubstitute the values into the formula.
[tex]KE= \frac{1}{2} (60 \ kg)(10 \ m/s)^2[/tex]
Solve the exponent.
(10 m/s)² = 10 m/s * 10 m/s = 100 m²/s²[tex]KE = \frac{ 1}{2} (60 \ kg)(100 \ m^2/s^2)[/tex]
Multiply the numbers together.
[tex]KE= 30 \ kg * 100 \ m^2/s^2[/tex]
[tex]KE= 3000 \ kg*m^2/s^2[/tex]
Convert the units. 1 kilogram meter squared per second squared is equal to 1 Joule, so our answer of 3000 kg*m²/s² equals 3000 Joules.
[tex]KE= 3000 \ J[/tex]
The go-cart has 3000 Joules of kinetic energy.
The solar mass of the Sun is 1. The orbital period of Jupiter is 11. 9 Earth years. What is the distance between Jupiter and the Sun? 5. 2 AU 41 AU 52 AU 410 AU.
The distance between Jupiter and the sun is 5.2 AU.
According to Kepler's third law, the square of the period of revolution of planets is proportional to the cube of their mean distances from the sun. From this; T^2 = r^3.
Now, we are told that the orbital period (T) is 11. 9 Earth years. We have to make the distance the subject of the formula.
r =T^2/3
r = (11.9)^2/3
r = 5.2 AU
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Answer:
The answer is A. 5.2 AU
Explanation:
in jus dat ni ni fr
Calculate the force of gravity of a 25kg block resting on the earth (M=5.97x10^24kg). The radius of the earth is 6.38x10^6m.
I already know...
[tex](6.67*10^{-11})(25)(5.97*10^{24} )/(6.38*10^6)^2[/tex]
But I don't understand what steps I have to take to solve that equation
From Newton's law of gravity, the force of gravity is 245 Newtons
To calculate the force of gravity of a 25kg block resting on the earth of mass M = 5.97x10^24kg with the radius r of the earth is 6.38x10^6m, let us first list out all the given parameters
Mass m = 25 kg
Mass of the earth M = 5.97x10^24kg
Radius r = 6.38x10^6m
Force F = ?
The formula to calculate the force of gravity is
F = (GMm)/[tex]r^{2}[/tex]
Where G = 6.67 x [tex]10^{-11}[/tex]
Substitute all the parameters
F = (6.67 x [tex]10^{-11}[/tex] x 5.97x10^24 x 25) / (6.38x10^6)^2
F = 9.9 x [tex]10^{15}[/tex] / 4.07 x [tex]10^{13}[/tex]
F = 244.56 N
F = 245 Newtons (approximately)
Therefore, the force of gravity is 245 Newtons
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Read this statement: Biotechnology uses primary clarifiers for biological nutrient removal.
Which part of the statement is not true?
Biological nutrients are found in wastewater.
Primary clarifiers remove biological nutrients.
Biological nutrients are part of biotechnology processes.
Biological nutrient removal is part of wastewater management.
Primary clarifiers removing biological nutrients is not true. Primary clarifiers
involves the use of processes such as sedimentation in order to remove
particles floating or other inorganic solids from the waste water.
Biological nutrients such as nitrogen and phosphorus are found in waste
water and removal of these important nutrients for other uses is a part of
waste water management.
The secondary clarifiers are the ones responsible for the removal of
biological nutrients in the waste water through biofiltration etc.
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Two parents are having a child The father has freckles which are a dominant trait The mother does not have trecktes Find the possibility of the chad having tracks.
Answer:
2:3
Explanation:
mathqway
Determine the percent composition of chromium (III) flouride CrF3
(Show your solution)
Answer:
Molar mass of CrF3, Chromium(III) Fluoride is 108.9913096 g/mol
51.9961+18.9984032·3
Mass percentage of the elements in the composition
Element Symbol Atomic Mass Number of Atoms Mass Percent
Chromium Cr 51.9961 1 47.707%
Fluorum F 18.9984032 3 52.294%
Notes on using the Molar Mass Calculator
Chemical formulas are case-sensitive.
Enter subscripts as simple numbers.
The converter uses a simple dot instead of using a midpoint typographic dot (·) in formulas for adduct molecules, such as water of hydration.
Example: type CuSO4.5H2O instead of CuSO₄·5H₂O.
Explanation:
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What is the surface temperature of Sirius B in Kelvins?
Answer: The surface temperature of Sirius B is 25,200 Kelvins(K).
Explanation: You would think Sirius would have a surface temperature of 9,940 Fahrenheit. That is somewhat correct, but Sirius is a binary star consisting of a main-sequence star of spectral type A0 or A1, termed Sirius A, and a faint white dwarf companion of spectral type DA2, termed Sirius B. Sirius, Sirius A, and Sirius B, are all different stars. Sirius A has a temperature of 9,940 Kelvins, but Sirius B has a temperature of 25,200 Kelvins(K).
That would be 9,940 kelvins (K)
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Explain briefly about viscous force
The viscous force refers to the resistance of a fluid to flow. It is measured in Newton-second per square meter.
The viscous force can be defined as the resistance that a fluid has to flow in a given space. Viscous force is proportional to the fluid velocity, while this constant is called viscosity.The viscous force can be measured in Newton-second per square meter (abbreviated as N s/m2).Learn more about viscous force here:
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astronomers have determined the surface temperature of stars by studying their colors. what color emission represents stars with the hottest temperatures?
Answer:
Blue
Explanation:
Did the question already
How does the temp of water change when it is heated on a stove top and it begins to boil.
Answer:
The temperature will no longer rise with the heat because the energy. When the water is boiled on the steam, the temperature rises when heat is given
Explanation:
An external force of 25 N acts on a system for 10 s. What is the impulse delivered to the system?
Answer:
I = 250N*s
Explanation:
I = F*t
I = impulse or momentum
F = Force
t = time
I = 25N*10s
I = 250N*s
An object is moving with a constant velocity of 311 m/s. How long will it take it to travel 9000 m?
[tex]\text{Given that,}\\\\\text{Velocity, v= 311 m s}^{-1}\\\\\text{Displacement, s = 9000 m}\\\\\text{Since velocity is constant,}\\\\s=vt\\\\\implies t =\dfrac{s}v = \dfrac{9000}{311} = 28.94 ~ \text{sec}.[/tex]