Answer: 300 m/s
Explanation:
So If it moves 200 metres in 20 seconds and then another 100 metres this is changing the total distance travelled to 300 metres. Also, it moves this distance extra distance in 10 seconds therefore the total time is 30 seconds.
speed = distance / time
speed = 300 / 30
speed = 10 m/s
After travelling a total of 300 metres and spending a total of 30 seconds in motion, the school bus travels at an average speed of 10 metres per second (m/s).
To figure out how fast the school bus was going on average, we need to know how far it went and how long it took to get there.
First, we add up the two lengths the school bus travelled: 200 metres plus 100 metres equals 300 metres.
Next, we add up how long it took to go both distances: 20 seconds plus 10 seconds equals 30 seconds.
Here's how to figure out the average speed:
Average Speed = Total Distance Travelled / Total Time Spent
Putting the numbers in:
Average Speed = 300 metres in 30 seconds
10 metres per second (m/s) is the average speed.
So, the school bus's usual speed is 10 m/s.
Average speed is the general rate of movement over a certain amount of time, no matter how it changes during the trip. In this case, the bus went 300 metres in 30 seconds, which means it went 10 m/s on average.
It's important to know that instantaneous speed is not the same as usual speed. Instantaneous speed is the speed of the bus at any given time during its trip. This speed could change as the bus speeds up, slows down, or stays at the same speed.
Calculating the average speed is helpful for figuring out how well something works generally, figuring out how efficient it is, and comparing different trips or types of transportation. But it might not take into account all the details of a given trip, such as different speeds or stops along the way. For a full picture of how the bus moves, it may be necessary to think about other things.
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Predict what will happen when the bicep muscle exerts force on the lower arm bone.
Answer:
the soft drink will be elevated by the lower arm
Explanation:
firstly, muscles can only pull on bones to cause movement so if the bicep applies force on the lower arm bone, it will pull it up.a flat coil of wire consisting of 17 turns, each with an area of 50 cm2, is positioned perpendicularly to a uniform magnetic field that increases its magnitude at a constant rate from 3 t to 6 t in 2.0 s. what is the magnitude of the emf (in volts) induced in the coil? your answer should be a number with two decimal places, do not include the unit.
The magnitude of electromotive force is 0.13 volt.
We need to know about the electromotive force of induction to solve this problem. The emf induction appears when there is any change in magnetic flux. The magnitude of emf can be determined by
ε = N dΦ / dt
where N is coil turns, ε is electromotive force, dΦ is change in magnetic flux and dt is time interval.
From the question above, the parameters given are
B1 = 3T
B2 = 6T
dt = 2 s
N = 17
A = 50 cm² = 5 x 10¯³ m²
Find the change in magnetic flux
dΦ = (Φ2 - Φ1)
dΦ = (B2 . A - B1 . A)
dΦ = A (B2 - B1)
dΦ = 5 x 10¯³(6 - 3)
dΦ = 15 x 10¯³ Tm²
By substituting the given parameters, we can calculate electromotive force
ε = N . dΦ / dt
ε = 17 . 15 x 10¯³ / 2
ε = 0.13 volt
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A 4 coulombs charged particle experiences an electric force of 200 N when placed at point P in an electric field. The magnitude of the electric field at point P is :
a) 5 N/C
b) 800 N/C
c) 0.02 N/C
d) 50 N/C
(d) 50N/C
The magnitude of the electric field at point 'P' is 50N/C.
It is derived from the basic concepts of Electrostatics. Coulomb's Law is the basis of relations in Electrostatics. It resembles Newton's Law of Gravitation.
Using the relation between Electric force, charge, and Electric field:
F = qE
F = 200N; q = 4C200 = (4)E
E = 50N/C
It is widely used in the calculation of Electric Force and Electric Field. The S.I. Unit of the Electric Force is Newton. The S.I. Unit of the Electric Field is N/C. The S.I. Unit of charge is Coulomb.
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a pellet gun fires ten 3.0 g pellets per second with a speed of 400 m/s. the pellets are stopped by a rigid wall. what is the magnitude of the average force on the wall from the stream of pellets?
two power lines, each 300 m in length, run parallel to each other with a separation of 23 cm . part a if the lines carry parallel currents of 130 a , what is the magnitude of the magnetic force each exerts on the other? express your answer using two significant figures.
The magnitude of the magnetic force each exerts on the other is 4.41 N.
The magnitude of the magnetic force depends on the current through the wire, the length of the wire, and the radius of separation. It can be written as
F = μ₀ . I1 . I2 . L / (2π . a)
where F is a magnetic force, μ₀ is vacuum permeability (4π x 10¯⁷ H/m), I1 and I2 is current through the wire, L is the length of the wire and a is the radius of the wire.
From the question above, the given parameters are
L = 300 m
a = 23 cm = 0.23 m
I1 = I2 = 130 A
By substituting the parameters, we can calculate the magnetic force
F = μ₀ . I1 . I2 . L / (2π . a)
F = 4π x 10¯⁷ . 130 . 130 . 300 / (2π . 0.23)
F = 4.41 N
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A particle’s position along the x-axis is described by the functionx(t) = A t + B t2,where t is in seconds, x is in meters, and the constants A and B are given below.Randomized VariablesA = -4.9 m/sB = 6.9 m/s2q. Enter expression interms of A,B, t for the velocity of the particle as a function of time? What time will the velocity be zero?
Given,
The position function is, x(t)=At+bt²
A=-4.9 m/s
B=6.9 m/s²
The velocity is described as the rate of change if the displacement with time.
That is, the velocity is the time derivative of the displacement.
Therefore on differentiating the given function with respect to the time, we get the expression for the velocity.
i.e.,
[tex]\begin{gathered} v(t)=\frac{d(At+Bt^2)}{dt} \\ =A+2Bt \end{gathered}[/tex]Therefore the expression for the velocity is A+2Bt
To know at what time the velocity will be zero,
[tex]A+Bt=0[/tex]On simplifying the above equation,
[tex]t=\frac{-A}{B}[/tex]On substituting the known values in the above equation,
[tex]t=\frac{-(-4.9\text{ )}}{6.9}=0.71\text{ s}[/tex]Therefore the velocity will be zero at 0.71 s
an old chrysler with mass 2050 kg is moving along a straight stretch of road at 75 km/h. it is followed by a ford with mass 1300 kg moving at 40 km/h. how fast is the center of mass of the two cars moving?
the center of mass of the two cars moving is with a speed of 61.41m/s
What is center of mass ?
A position established in relation to an object or set of objects is the center of mass. It represents the system's average location as weighted by each component's mass. The centre of mass for straightforward stiff objects with homogeneous density is found at the centroid.
The center of mass also functions as a location at which inertial forces, such as centrifugal force, and gravitational force are applied. There are a number of direct and indirect techniques for locating the center of mass.
Let mc be the mass of the Chrysler and νc be its velocity .
Let mf be the mass of the Ford and νf be its velocity . Then the velocity of the center of mass is
ν com = (mc v c + mf v f) /m c+ m f = [tex](2050*75 + 1300*40)/(2050+1300)[/tex]
= 61.41 km/h
We note that the two velocities are in the same direction, so the two terms in the numerator have the same sign.
the center of mass of the two cars moving is with a speed of 61.41m/s
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Whoever answers asap gets marked Brainliest! A hockey puck with a mass of 0.12 kg is traveling across the ice at a velocity of 150 m/s downfield. What is the momentum of the hockey puck?
P = 18 N
P = 18 kg * m/s
P = 8 * 10 - 4 kg * m/s
M = 18 kg * m/s
Answer:
Explanation:
Momentum = m * v = .12 * 150 = 18 kg m/s
In the diagram below, two of the three rays used to find the image position are shown. Which of the following best describes the third (missing) ray?A.A ray incident parallel to the axis refracts outward, as if it came from the focus on the left hand side.B.A ray incident through the vertex continues through the lens without refracting.C.A ray incident parallel to the axis refracts so that it passes through the focus on the right hand side.D.A ray incident on a path that would take it through the right focus refracts parallel to the axis.
Answer:
C. A ray incident parallel to the axis refracts so that it passes through the focus on the right hand side
Explanation:
The third ray is the blue ray in the following figure
Therefore, the third ray is a ray parallel to the axis that refracts and passes through the focus of the right side.
So, the answer is:
C. A ray incident parallel to the axis refracts so that it passes through the focus on the right hand side
what is the velocity (in m/s) of a 925 kg car initially moving at 29.5 m/s, just after it hits a 145 kg deer initially running at 12.5 m/s in the same direction? assume the deer remains on the car. (enter the magnitude.)
The velocity after the collision is 27.19 m/s
What is the law of conservation of momentum?For a collision between Object 1 and Object 2 in an isolated system, the total momentum of the two objects before collision equals the total momentum of the two objects after collision. That is, the momentum lost from object 1 is equal to the momentum gained from object 2 (a constant or unchanging value). It can be stated by following equation:
Pₙ = mₙvₙ
mₙvₙ = m₁v₁ + m₂v₂
Where, Pₙ = final momentum
mₙ = total mass of the system
vₙ = final velocity of the system
For the given case,
Since, mₙvₙ = m₁v₁ + m₂v₂
(m₁ + m₂)vₙ = m₁v₁ + m₂v₂
(925 + 145)vₙ = (925 × 29.5) + (145 × 12.5)
1070 vₙ = 27287.5 + 1812.5
1070 vₙ = 29100
vₙ = [tex]\frac{29100}{1070}[/tex]
vₙ = 27.19 m/s
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a 2.6 m diameter penstock carries water at a velocity of 7m/s to an 80% efficient hydroelectricity generation facility in west virginia that produces 12 mw. another 2.275 m diameter penstock carries water at a velocity of 3 m/s to a 74% efficient hydroelectric generation facility in arkansas that produces 9 mw. what is the ratio of the heads of arkansas' reservoir to west virginia's reservoir?
The ratio of the heads of arkansas' reservoir to west virginia's reservoir is 1813 : 1120
Consider the West virginia reservoir,
To calculate the head of the virginia reservoir, we will use
φ = P / nρgh ...(1)
where φ is the flow rate, P is the power generated, n is efficiency, ρ is the density of water, g is the acceleration due to gravity and h is the head.
Given that flow rate is 7 m/s, power generated is 12 mw, 80% is the efficiency.
We know that density of water is 1000 [tex]kg/m^{3}[/tex] and acceleration due to gravity is 9.8 [tex]m/s^{2}[/tex]
By using equation (1)
h = P / φnρg
h = [tex]\frac{12}{7 * \frac{80}{100} * 1000*9.8 }[/tex]
h = 13440
Similarly, the head of the arkansas reservoir will be
Given that flow rate is 3 m/s, power generated is 9 mw, 74% is the efficiency.
h = P / φnρg
h = [tex]\frac{9}{3 * \frac{74}{100} * 1000*9.8 }[/tex]
h = 21756
Now, the ratio of the heads of arkansas' reservoir to west virginia's reservoir is
= (heads of arkansas) / (head of the virginia)
= 21756 / 13440
= 1813 : 1120
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8. Considering frictional forces, which force would you expect to be greater: the
hanging mass or the resulting total mass times acceleration? Did the results of this
experiment consistently show that one was larger than the other?
I expect the
9. What happens to an object's acceleration if the net force applied to the object is
constant but the total mass increases?
10. What happens to the objects acceleration if the net force was increase and the
mass was kept constant?
9. The object's acceleration will decrease if the net force applied to the object is constant but the total mass increases. 10. The objects acceleration will increase if the net force was increase and the mass was kept constant
F = m a
F = Force
m = Mass
a = Acceleration
a ∝ F
a ∝ 1 / m
9 ) Since Force is constant and mass increases, the acceleration will decrease.
10 ) Similarly if the net force increases while the mass is kept constant, the acceleration will increase.
According to Newton's second law of motion, force is equal to the rate of change of momentum. For a constant mass force equals mass of the object times acceleration of the object.
Therefore,
9. The object's acceleration will decrease if the net force applied to the object is constant but the total mass increases.
10. The objects acceleration will increase if the net force was increase and the mass was kept constant
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How is the amplitude of a
longitudinal wave measured?
A. the distance between two rarefactions
B. the distance between two compressions
C. It is measured by how close together or spread
apart the compressions and rarefactions are.
A man is pulling on a rope with a force of 44 N
directed at an angle of 63◦
to the horizontal.
What is the x-component of this force?
Answer in units of N.
Answer:
20 N
Explanation:
Vertical component will be 44 sin 63
HORIZONTAL component is 44 cos 63 N = 19.97 =~ 20 N
complete the table=x =0 2 3 4 6 8 y=30 27 24
Answer: (x=1 y=30) (x=2 y=27) (x=3 y=24) (x=4 y=21) (x=5 y=18) (x=6 y=15) (x=7 y=12) (x=8 y=9) (x=9 y=6) (x=10 y=3) etc its going down by 3 so 30-3=27 27-3=24 24-3=21 etc
hope i helped
Explanation:
now assume that a satellite of mass mmm is orbiting the earth at a distance rrr from the center of the earth with speed vevev e . a satellite of mass 2m2m2m is orbiting mars, also at a distance rrr from the center of mars, with a speed vmvmv m . what is the ratio tmte
The ratio between centripetal force of satellite b and satellite a is 2vm²/ ve².
We need to know about centripetal force to solve this problem. When an object moves in a circular motion, the object is experiencing centripetal force. The magnitude of centripetal force is
Fc = m . v²/R
where Fc is the centripetal force, m is mass, v is velocity and R is the radius.
From the question, we know that
ma = m
mb = 2m
va = ve
vb = vm
ra = rb = r
Find the centripetal force ratio
Fcb / Fca = (mb . vb²/Rb) / (ma . va²/Ra)
Fcb / Fca = (2m . vm²/r) / (m . ve²/r)
Fcb / Fca = 2 . vm²/ ve²
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Use this diagram to calculate the magnitude of the block's acceleration.
A. 0.50 m/s2
B. 2.0 m/s2
C. 9.8 m/s2
D. 32 m/s2
The mass of the block is 4 kg and the force applied on the block is 8 N. So, the acceleration of the block will be 2 m/s².
What is acceleration?The rate at which an object's velocity varies with respect to time is referred to as acceleration in mechanics. accelerations' magnitude as a vector. Depending on which way the net force is pulling on an object, it will accelerate in that direction.
Acceleration has a magnitude and a direction, making it a vector quantity. Vessel quantities include velocity as well. The definition of acceleration is the change in the vector of velocity over a time interval divided by the time interval.
According to the question, the given values are :
Block mass, m = 4 kg
Force applied on the block, f = 8 N
[tex]Force = mass *acceleration[/tex]
a = 8/4
a = 2m/s².
Hence, the acceleration of the block will be 2m/s².
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if the velocity of a pitched ball has a magnitude of 43.5 m/sm/s and the batted ball's velocity is 56.0 m/sm/s in the opposite direction, find the magnitude of the change in momentum of the ball and of the impulse applied to it by the bat.
1.82 kgm/s and 1.82 s^-1 is momentum of the ball and of the impulse respectively applied to it by the bat.
ball mass, m = 0.145 kg
velocity of the pitched ball, v₁ = 43.5 m/s
velocity of the batted ball, v₂ = 56.0 m/s
change in the momentum is
[tex]\Delta P=mv_1-mv_2[/tex]
ΔP=6.30-8.12
ΔP=-1.82 kgm/s
The ball's change in momentum is equal to the impulse it experiences.
[tex]J=\Delta P= 1.82/s[/tex]
A moving particle's change in dynamical state can be estimated using the physical quantity known as impulse. It is the change in momentum that a body experiences when it is briefly impacted by a force. It is a vector quantity, and the letter J is used to denote it.
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A hiker walks 5.00 kilometers due north and then 7.00 kilometers due east.
What is the magnitude of her resultant displacement?
Answer:
8.6 km
Explanation:
Use Pythagorean theorem
D^2 = 5^2 + 7^2
= 25 + 49
D = sqrt (74) = 8.6 km
A tennis ball moves 22 meters southward, then 12 meters northward, then 16 meters southward, and finally 34 meters northward
The resultant displacement of the tennis ball is 8 m northward.
What is displacement?
The displacement of an object is the change in the position of the object. The displacement of an object describes the shortest point between the final and initial position of an object.
The displacement of the tennis ball is calculated as follows;
d = (12 m north + 34 m north) - (22 m south + 16 m south)
d = (46 m north) - (38 m south)
d = 8 m northward
Thus, the resultant displacement of the tennis ball for the given motion is 8 m northward.
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The compete question is below:
A tennis ball moves 22 meters southward, then 12 meters northward, then 16 meters southward, and finally 34 meters northward. find the resultant displacement of the tennis ball.
After every movement in north and south direction multiple times, the displacement of the tennis ball is 8 meters in north direction.
What is displacement?The definition of displacement is the modification of an object's position. It has a direction and magnitude and is a vector quantity. It is shown as an arrow that travels from the initial location to the conclusion.
According to the question, the tennis ball moves 22 meters in south direction then it moves towards north and travels for 12 meters again it turns to south and covers 16 meters and at last it covers 34 meters in the north direction.
d = (12 m + 34 m ) north direction - (22 m + 16 m ) south direction
d = 8 meters in north direction.
Hence, the total displacement done by the tennis ball is 8 meters in the north direction.
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A cosmic-ray electron moves at 7. 5 × 10^6 m/s perpendicular to earth’s magnetic field at an altitude where the field strength is 1. 0 × 10 ^―5t. What is the radius of the circular path the electron follows?.
The separation between an orbit's center and its course is known as its radius. This separation is constant in all directions for an orbit that is entirely circular.
How does radius affect centripetal force?A particle travelling uniformly in a circle experiences a centripetal force, F, which is dependent on the mass (m), velocity (v), and radius (r) of the circle. the F formula using the dimensions method.
Where a, b, and c are the respective powers of m, v, and r and k is the dimensionless constant of proportionality.
Electric field
According to the query, the speed of an electron is 7.50 106 m/s.
1 105 T magnetic field, B
mass of an electron. m = 9.11 × 10⁻³¹
Electron charge, q = 1.6 1019
The relationship between radius of curvature,
r =( 9.11 × 10)-31 × 7.50 × (10)6/ 11.6 × (10) -19 ×1× (10) -5
= 4.266 m.
Therefore, the circular path's radius is 4.266 meters.
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A truck is traveling at a constant velocity of 30 m/s. How long will it take to travel 1000 meters?
A truck is traveling at a constant velocity of 30 m/s. It will take the time to travel 1000 meters is (t)=33.33 S.
What is velocity?The velocity means the ratio of distance and time. Mathematically it means the distance divided by time. It can be measured in m/s and cm/s.
How can we calculate the time?To calculate the time we are using thee formula here is,
S=vt
Or, t=S/v
Here we are given,
S = The covered distance of the car = 1000 m
v= The velocity of the car. = 30 m/s.
We have to calculate the time taken by truck = t
Now we put the values in the above equation, we get
t=S/v
Or, t=1000/30
Or, t=33.33 S
From the calculation we can say that, It will take the time to travel 1000 meters is (t)=33.33 S.
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Select the correct answer from each drop-down menu. earth's rotation causes the cycle of . if earth began to spin a little bit faster .
A hiker, of mass 80kg, walks up a mountain, 700m above sea level, to spend the night at the top in the first overnight hut. The second day she walks to the second overnight hut, 400m above sea level. The third day she returns to her starting point, 200m above sea level. What is the potential energy of the hiker at the first hut (relative to sea level)?
The potential energy of the hiker at the first hut is mathematically given as
v = 548800J
What is the potential energy of the hiker at the first hut?Generally, the equation for potential energy is mathematically given as
v = mgh
where,
m = 80kg, g = 9.8, h = 700
therefore
v = 80 x 9.8 x 700
In conclusion, the potential energy of the hiker at the first hut
v = 548800J
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A heavy vehicle of mass 200 tonnes has a maximum speed of 20m/s up a hill inclined at 1.15 degree to horizontal when the engine is working at 800 kilowatts. determine the resistance to motion of the truck
A heavy vehicle of mass 200 tones has a maximum speed of 20m/s up a hill inclined at 1.15 degree to horizontal when the engine is working at 800 kilowatts. The resistance to motion of the truck will be 800 N
We can define power as the rate of doing work, it is the work done in unit time. The SI unit of power is Watt (W) which is joules per second (J/s).
since , Power = Force * velocity
Force = power / velocity
= 800 * [tex]10^{3}[/tex]/ 20 = 4 * [tex]10^{4}[/tex] N
F net = 0
F - friction force - mg(sin (theta)) = 0
4 * [tex]10^{4}[/tex] - fr - 2 * [tex]10^{5}[/tex] * 9.8 * sin(1.15) =0
fr = resistive force = 4 * [tex]10^{4}[/tex] - 2 * [tex]10^{5}[/tex] * 9.8 * sin(1.15)
fr = 800 N
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Now assume that a satellite of mass m is orbiting the earth at a distance r from the center of the earth with speed ve. A satellite of mass 2m is orbiting mars, also at a distance r from the center of mars, with a speed vm. What is the ratio tmte , the time it takes the satellite circling mars to make one revolution divided by the time it takes the satellite orbiting the earth to make one revolution? the mass of the earth is me and the mass of mars is mm.
The ratio of the time it takes the satellite circling mars to make one revolution divided by the time it takes the satellite orbiting the earth to make one revolution is (Rm/Re)^3/2.(Me/Mm)^1/2
The orbital velocity of the satellite is given by,
V = √(GM/R)
Where,
V is orbital velocity,
G is gravitational constant,
M is the mass of planet,
R is the distance from the centre of the planet to the satellite.
According to given condition,
Ve = √(GMe/Re)
Ve it the orbital velocity of earth,
Me is mass of the earth,
Re is the radius of the earth.
Also,
Vm = √(GMm/Rm)
Vm it the orbital velocity of mars,
Mm is mass of the mars,
Rm is the radius of the mars.
We know, time period of revolution,
T = distance/velocity
Time period od revolution of satelite of earth,
Te = 2πRe/√(GMe/Re)
Time period of revolution of satelite of mars,
Tm = 2πRm/√(GMm/Rm)
Now, dividing the time time period of revolution of mars by time period of revolution of earth,
Te/Tm = [2πRe/√(GMe/Re)]/[2πRm/√(GMm/Rm)]
Te/Tm = (Rm/Re)^3/2.(Me/Mm)^1/2
So the final ratio of both the time periods is (Rm/Re)^3/2.(Me/Mm)^1/2.
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if the speed of a car is increased by 65%, by what factor will its minimum braking distance be increased, assuming all else is the same? ignore the driver's reaction time.
If the speed of the car is increased by 65%, the stopping distance of the car will be increased by 272.25%.
Let us say, the car is moving with velocity U, the stopping time of the car is T and the stopping distance of the block is d,
Now, we should use the equation of motion,
U²-V² =2aD
Where,
U is initial velocity,
V is final velocity,
D is the stopping distance,
a is the acceleration.
We know, at the final velocity will be zero,
So,
U² = 2aD
U =√(2aD)
Now, if the speed is increased by 65%, let us say the stopping distance becomes D'.
So,
U+65%U = √(2aD')
165U/100 = √(2aD')
Now, putting U = √(2aD),
165√(2aD)/100 = √(2aD')
(1.65)²D = D'
D' = 2.7225D
Now,
∆D = D' - D/D × 100
∆D = 2.7225 × 100
∆D = 272.25%
So, the stopping distance increased by 272.25%.
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after driving a portion of the route, the taptap is fully loaded with a total of 27 people including the driver, with an average mass of 70 kgkg per person. in addition, there are three 15- kgkg goats, five 3- kgkg chickens, and a total of 25 kgkg of bananas on their way to the market. assume that the springs have somehow not yet compressed to their maximum amount. how much are the springs compressed? enter the compression numerically in meters using two significant figures. view available hint(s)
When something, like a spring, is stretched, the added length is referred to as its extension.According to Hooke's law, as long as the limit of proportionality is not crossed, a spring's extension is directly proportionate to the force exerted.
Solve the problem ?
The ends of an extension spring connect to two devices.The hooks and loops on the extension springs store and compress energy.An extension spring delivers return force to connected mechanisms via hooks or loops.The no-load position is where tightly wrapped extension springs normally rest. Total mass refers to the combined weight of the shell, its structural and support equipment, and the heaviest load that may be conveyed.The spring's compression at the specified weight is 0.80cm.
"Your inquiry is incomplete because it appears to be lacking the information below,"
The taptap's spring has a k value of 2.4 104 N/m.
the settings provided;
Each of the 27 people weighs 69 kg.
Each of the three goats weighs 15 kg.
Each of the five hens weighs 3 kg.
The weight of the bananas is 25 kg
The taptap's total mass, which includes every passenger, is computed as;
the people's combined mass is 27 x 70 or 1960 kg.
The goats' combined mass is 3 x 15 =45 kg.
The birds' combined mass is equal to 5 x 3 = 15 kg.
The bananas weigh a total of 25 kilograms
The extension of the spring
= 1960×9.8/2.4×104
= 19208/24000
= 0.80 cm
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wake turbulence is near maximum behind a jet transport just after takeoff because a. of the high angle of attack and high gross weight. b. the engines are at maximum thrust output at slow airspeed. c. the gear and flap configuration increases the turbulence to maximum.
Wake turbulence is near maximum behind a jet transport just after take off because of the high angle of attack and high gross weight.
Explanation:
Every aircraft generates wake turbulence while in flight. Wake turbulence is a function of an aircraft producing lift, resulting in the formation of two counter-rotating vortices trailing behind the aircraft.
Wake turbulence from the generating aircraft can affect encountering aircraft due to the strength, duration, and direction of the vortices. Wake turbulence can impose rolling moments exceeding the roll-control authority of encountering aircraft, causing possible injury to occupants and damage to aircraft. Pilots should always be aware of the possibility of a wake turbulence encounter when flying through the wake of another aircraft, and adjust the flight path accordingly.
Wake turbulence is near maximum behind a jet transport just after take off because of the high angle of attack and high gross weight.
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9. a supply plane needs to drop a package of food to scientists working on a glacier inalaska. the plane flies 100 m above the glacier at a speed of 150 m/s. how far short of the target should it drop the package?
[tex]X=150m/s * 4.518s =677.63m[/tex] far short of the target it will drop the package.
How far short of the target should it drop the package?First we can find the total time in order to reach the ground using the following kinematic formula:
[tex]y_{f} =y_{i}+v_{iy}+ \frac{1}{2} gt^{2}[/tex]
And replacing we have:
[tex]-100 =0+0- \frac{1}{2} (9.8)t^{2}[/tex]
And solving for t we got:
[tex]t=\sqrt{ \frac{2* (-100)}{-9.8} }=4.518 s[/tex]
And now we can find the final distance on the x axis using the formula:
[tex]D = Vxt[/tex]
The velocity on x not changes and is the same plane speed [tex]Vx=150m/s[/tex] , if we replace we got:
[tex]X=150m/s * 4.518s =677.63m[/tex]
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