How do I find the volume?

How Do I Find The Volume?

Answers

Answer 1

Answer:

150m^3

Step-by-step explanation:

The formula for the volume a triangular prism, like the one you have, is 1/2 base x height. For your prism the volume would be 1/2 (30 x 10) which equals 150. Now just add the measurment m (meters) and you're set.


Related Questions

Find the measure of ∠ABC.

Answers

Answer:

170°

Step-by-step explanation:

There is a total of 180° and the angle is 10° less...

So, 180°-10° = 170°

Please 5 stars if correct!!!

I hope this helps!!!

Please help I'll mark brainliest​

Answers

✿————✦————✿————✦————✿————✦————✿

So, to find the mean they added up the scores from 20 seasons and divided by 20, the number of seasons to get an average score of 10.4.

10.4 = (x1 +x2 +x3 ... +x20 )/20

Then;

10.4*(20) = (x1 +x2 +x3 ... +x20 )

208 = sum of the first 20 seasons

We want to add one more number in there, the 21st season with a score of 14. Add the 14 to the sum of the first 20 seasons and then divide by 21, the new number of seasons you're averaging.

Mean = (208+14)/21  

✿————✦————✿————✦————✿————✦————✿

Answer

= 10.6

✿————✦————✿————✦————✿————✦————✿

#carryonlearning

Describe how to find the sale price of an item that has been discounted 15%

Answers

multiply the initial price by the percentage. move the decimal two places to the left

p=price
q=percentage

p x q=total

p - total= answer

30 x 15=450

30 - 4.50= 25.5

sale price= 25.5

Alice is making bracelets to sell. She plans to put 12 beads on each bracelet. Beads are sold in packages of 20.

#1. What is the least number of packages she can buy to make bracelets and have no beads left over?

#2 If each package of beads costs $5.50, how much will the beads cost for her project?


Show and Explain your work
Hint: the “T” Method works well for show and explain. Make sure you have all of the details explained. If someone only read your explanation they should know… what the question is, all of the steps needed to answer the question and what your final answer is.

Answers

Answer:

question 1 is 60 beads and question 2 is 16 dollars and 50 cents.

Step-by-step explanation:

for question 1 the are asking for the lowest common denomonator (60)

for question 2 you devide 60/20 and multiply by 5.50

3 x 5.50 = 16.5$

do this only on number line ​

Answers

#4

-2/8=-1/43/6=1/2

Refer to the attachment

#2

Mid point:-

-2/5+1/2/2-4+5/10/21/10/21/20

Step-by-step explanation:

please mark me as brainlest

The height of a triangle is 4cm more than twice the length of the base.The area of the triangle is 35 square cm.Find the height of the triangle.​

Answers

Answer:

14cm

Step-by-step explanation:

Algebra is the way!

But seriously, let's model this algebraically.

We know the that the area of a triangle is represented by:

[tex]A = \frac{1}{2} base*height[/tex]

we'll use b and h to represent base and height

[tex]A = \frac{1}{2} b*h[/tex]

Okay, so you are given the area of the triangle already. It is [tex]35 cm^2[/tex]. SO you have:

[tex]35 = \frac{1}{2} bh[/tex]

Now here's the tricky bit of the question. You have 2 unknown variables, oh no! How will you solve? The key to this is simple, in a case where you have 2 or more unknown variables, ALWAYS think to yourself, "can I represent this variable in terms of another"?

In this case you can. They tell you what the height of the triangle is, in terms of the length of the base. They tell you, height is 4 cm more than 2 times the base.

So replace h in this equation with 2b + 4.

[tex]35 = \frac{1}{2} (b)(2b+4)\\\\35 = \frac{1}{2}(2b^2 + 4b)\\ 70 = 2b^2 + 4b\\0 = 2b^2 + 4b - 70\\0 = (2)(b^2 + 2b - 35)\\0 = (b +7)(b - 5)\\\\b = 5\\b\ \neq -7[/tex]

Okay, so you know the base of the triangle is 5 cm. The question asks for height, so what you're going to do is refer back to what h is.

We found that [tex]h = 2b + 4[/tex]

sub in 5 into that:

[tex]h = 2(5) + 4 = 14[/tex]

Therefore the height of the triangle is 14cm.

Answer:

Step-by-step explanation:

Givens

Area = 1/2 B* H

B = B

H = 2*B + 4

Area = 35

Solution

35 = 1/2 * B * (2B + 4)                          Multiply both sides by 2

35*2 = 2*(1/2) * B * (2B + 4)                 Combine

70 = B(2B + 4)                                      Remove the Brackets.

70 = 2B^2 + 4B                                    Subtract 70 from both sides.

2B^2 + 4B - 70 = 0                               Divide everything by 2

B^2 + 2B - 35 = 0                                 Factor

(B + 7)(B - 5)

B+7 = 0 will give a minus number. Geometry does not allow minus numbers.

B - 5  = 0

B = 5

But what you want is the height.

h = 2b + 4

h = 2*5 + 4

Answer: h = 14

The giraffes at the Liberia zoo eat 75 pounds of food per day, and 52.5 pounds per day comes from acacia leaves. How much of their diet comes from other types of leaves?

Julia, the zookeeper, used the equation 52.5 + x = 75 to find the answer. Which equation is an equivalent equation that can be used to solve the problem?

Answers

Answer:

Step-by-step explanation:

75-52.5=x

Find the factorization of the polynomial below.

81x^2 - 18x + 1

A. (9x + 1)^2

B. (18x + 1)^2

C. (18x - 1)^2

D. (9x - 1)^2

Answers

Answer:

[tex](9x-1)^2[/tex]

Step by step explanation:

[tex]81x^2-18x+1\\\\=81x^2 - 9x-9x+1\\\\=9x(9x-1)-(9x-1)\\\\=(9x-1)(9x-1)\\\\=(9x-1)^2[/tex]

Find the slope of the line that passes through the two given points:

(-1, 4) and (5, 3)
A line starting in the third quadrant, crossed the x axis twice, and then ending in the first quadrant

Answers

Answer:

[tex] \frac{ - 1}{6} [/tex]

Step-by-step explanation:

[tex]slope \: = \frac{y2 - y2}{x2 - x1} \\ slope = \frac{3 - 4}{5 - - 1} \\ sope = \frac{ - 1}{ \: \: \: 6} [/tex]

44. What three-dimensional figure can be made by folding the net?
ASSESSMENT 1
A rectangular pyramid
B. triangular pyramid
C. triangular prism
D. square pyramid

Answers

You forgot to add a picture of the net!

Answer:

Its B square pyramid

Step-by-step explanation:

Because

Zoe planted a walnut tree. Every week, she measures the tree and records its
growth. On the first week, the tree was 27 1/2 inches tall. On the second week, it was
29 1/4 inches tall. On the third week, it was 31 1/3 inches tall. How much did the tree
grow from the first week until it was measured on the third week? Show your work.

Answers

The tree grew about 3.83 inches between the first and third week.

What is an equation?

An equation is an expression that shows the relationship between two or more numbers and variables.

On the first week, the tree was 27 1/2 inches (27.5) tall. On the second week, it was 29 1/4 inches (29.25) tall. On the third week, it was 31 1/3 inches (31.33) tall.

The length grown = 31.33 - 17.5 = 3.83 inches

The tree grew about 3.83 inches between the first and third week.

Find out more on equation at: https://brainly.com/question/2972832

Can someone please help me with this! Thanks <3

Answers

Answer:

H

Step-by-step explanation:

If you convert these fractions into decimals:
-2 1/2 = -2.5
-2.47 = -2.47
-2/5 = -0.4
5 = 5
21/4 = 5.25
You can see that the order from lest to greatest is answer H

Hope this helps :)

Find the value of X and perimeter.

Answers

Answer:
See below.

Step-by-step explanation:
TQ & UQ are 2 tangents from the same external point 'Q' and touches the same circle with centre 'W'.

Given,
UQ = 14 in

Then,
TQ = UQ = 14 in (tangents from same external points are equal to each other)

•°• TQ
= 14
= 7 × 2
=》x = 7 inch

___________
ST = SV = 17 in

Then,
RV
= RS - SV
= 27 - 17
= 10 in

RU = RV = 10 in

Perimeter:
= RS + RQ + SQ
= 27 + (14 + 10) + (14 + 17)
= 27 + 24 + 31
= 82 in


______
Hope it helps ⚜


Choose the expression that represents 3 less than 7 times a number

Answers

Answer:

7x - 3, x being the number

Step-by-step explanation:

number = x

7x - 3

Answer:

Three less than 7 times a number is 39.

Step-by-step explanation:

3. The object has the shape of a rectangular prism, but part of a face is missing.
Find the surface area of the object and show your work.
a)
Find the surface area of the complete prism.
5 cm
30 cm
20 cm
10 cm
15 cm


I need an answer

Answers

the answer is 15cm i don’t know how but it is

Can someone help me with this question please?

Answers

Answer:

  a) 96 = 3.57√h

  b) h ≈ 723.11 m

Step-by-step explanation:

a)

The equation you want to solve is the model with the given values filled in.

  D(h) = 3.57√h . . . . model

  96 = 3.57√h . . . . . equation for seeing 96 km to the horizon

__

b)

We solve this equation by dividing by the coefficient of the root, then squaring both sides.

  96/3.57 = √h

  h ≈ 26.891² ≈ 723.11 . . . . meters above sea level

Dustin would need to have an elevation of 723.11 meters above sea level to see 96 km to the horizon.

What is the product of 3/4 and -6/7?

Answers

Answer:

-9/14

Step-by-step explanation:

Hey there!

Guide:

• Difference means subtract/subtraction
• Product means multiply/multiplication
• Sum means add/addition
• Quotient means divide/division


• Now that we know what “product” means… we can make the question/equation easier to solve.

3/4 × -6/7

= 3(-6) / 4(7)

= -18 / 28

= -18 ÷ 2 / 28 ÷ 2

= -9 / 14


Therefore, your answer is: -9/14


Good luck on assignment & enjoy your day!


~Amphitrite1040:)

Manu had ₹ 120. He bought one book for ₹ 25.75 and a pen for ₹ 12.50. How much money does he have now?​

Answers

Answer:

₹ 81.75

Step-by-step explanation:

Total =  ₹ 120.

He bought one book for ₹ 25.75 and a pen for ₹ 12.50.

    ₹ 25.75 + ₹ 12.50 =  ₹ 38.25

How much money does he have now?​

     ₹ 120 -  ₹ 38.25 =  ₹ 81.75

₹81.75

you just minus 120 from 25.75 and 12.50

How do you write 7,100 in scientific notation

Answers

Answer:

7.1 x 10³

Step-by-step explanation:

Move your decimal so that it follows your first whole number greater than zero. The number of places you moved the decimal is the same as the exponent. Since the number 7.1 needs to INCREASE to be 7,100, then the exponent is positive.

Answer:

7.1 x 10[tex]^{3}[/tex] (note the 3 is an exponent)

Step-by-step explanation:

1. Count how many places there are to the right of 7

2. There are 3

3. Apply the formula of scientific notation a x 10[tex]^{b}[/tex]

4. 7.1 x 10[tex]^{3}[/tex]  (remove all digits after 7.1  

Hope this helps :)

URGENT I NEED IT NOW PLEASE HELP ME!!!!

Answers

The fourth one because they at minimum need that amount not the most. The answer is option 4 or the last option

Sayeed is buying a crate for his puppy. The crate is 20 inches long, 13 inches wide, and 16 inches high. What is the volume of the crate?​

Answers

V = 20 in X 13 in X 16 in

V = 4,160 cu in

Sorry if this was confusing, this was my first time answering a question, if I got it wrong I apologize, have a nice day/night!

(2)Please help with both questions

Answers

Answer:

See below for answers and explanations

Step-by-step explanation:

Problem 1

Let's think of the boat and wind as vectors:

Boat Vector --> [tex]\langle28cos36^\circ,28sin36^\circ\rangle[/tex]

Wind Vector --> [tex]\langle10cos22^\circ,10sin22^\circ\rangle[/tex]

Now, let's add the vectors:

[tex]\langle28cos36^\circ+10cos22^\circ,28sin36^\circ+10sin22^\circ\rangle[/tex]

Find the magnitude (the true velocity):

[tex]\sqrt{(28cos36^\circ+10cos22^\circ)^2+(28sin36^\circ+10sin22^\circ)}\approx37.78\approx38[/tex]

Find the direction (angle):

[tex]\theta=tan^{-1}(\frac{28sin36^\circ+10sin22^\circ}{28cos36^\circ+10cos22^\circ})\approx32.32^\circ\approx32^\circ[/tex]

Thus, D is the best answer

Problem 2

Recall that the angle between two vectors is [tex]\theta=cos^{-1}(\frac{u\cdot v}{||u||*||v||})[/tex] where [tex]u\cdot v[/tex] is the dot product of the vectors and [tex]||u||*||v||[/tex] is the product of each vector's magnitude:

[tex]\theta=cos^{-1}(\frac{u\cdot v}{||u||*||v||})\\\\\theta=cos^{-1}(\frac{\langle-82,47\rangle\cdot\langle92,80\rangle}{\sqrt{(-82)^2+(47)^2}*\sqrt{(92)^2+(80)^2}})\\\\\theta=cos^{-1}(\frac{(-82)(92)+(47)(80)}{\sqrt{6724+2209}*\sqrt{8464+6400}})\\\\\theta=cos^{-1}(\frac{(-7544)+3760}{\sqrt{8933}*\sqrt{14864}})\\\\\theta=cos^{-1}(\frac{-3784}{\sqrt{132780112}})\\\\\theta\approx109.17^\circ\approx109^\circ[/tex]

Therefore, C is the best answer

Kristy bought some rolls of wrapping paper and 2 bags of bows for less then $10. Each roll of wrapping paper and each bag of bows cost $1.50. Which inequality can be used to find w, the number of rolls of wrapping paper Kristy bought?

Answers

Answer:

[tex]w < 4 \frac{2}{3}[/tex]

Step-by-step explanation:

The inequality symbol for 'less than' is '<'.

Let's relate the cost and the number of each item bought together with an equation.

Total cost

= (number of rolls)(cost of each roll) +(number of bags)(cost per bag of bows)

= w(1.50) +2(1.50)

= 1.5w +3

Now, we can form the inequality.

Since the total cost is less than $10,

1.5w +3< 10

Subtract 3 from both sides:

1.5w < 10 -3

1.5w < 7

Divide both sides by 1.5:

[tex]w < 7 \div \frac{3}{2} [/tex]

[tex]w < 7 \times \frac{2}{3} [/tex]

[tex]w < \frac{14}{3} [/tex]

[tex]\textcolor{red}{w < 4 \frac{2}{3} }[/tex]

Help me out please I don’t understand

Answers

[tex]\\ \sf\Rrightarrow y=-4(x+2)^2-1[/tex]

Compare to the vertex form of parabola

y=a(x-h)^2+k

h=-2k=-1

So vertex should be at (h,k)=(-2,-1)

Graph attached

Adrianna has $20 in her savings account. Each week she will add $5 to it. Which equation represents this situation?

Answers

y is total amount, x is weeks

we would have
y = 5x + 20

Answer:

Let y = the amount in Adrianna's savings account

Let x = the number of weeks passed

y = 5x + 20

A. 140°

B. 90°

C. 70°

D. 50°

Help please

Answers

Answer:

i think the answer is d which is 50°

General solution of: (1-xy)^-2 dx + [y^2 + x^2 (1-xy)^-2]dy = 0


show two solution on your answer

nonsense answer deleted​

Answers

✒️MATHEMATICS

[tex] \Large \bold{SOLUTION\ 1:} [/tex]

[tex] \small \begin{array}{l} \text{First, we need to check if the given differential} \\ \text{equation is exact.} \\ \\ (1-xy)^{-2} dx + \big[y^2 + x^2 (1-xy)^{-2}\big]dy = 0 \\ \\ \dfrac{dx}{(1-xy)^2} + \left[y^2 + \dfrac{x^2}{(1-xy)^2}\right]dy = 0 \\ \\ \quad M(x, y) dx + N(x, y) dy = 0 \end{array} [/tex]

[tex] \small \begin{array}{l l}\tt\: M(x,y) = \dfrac{1}{(1 - xy)^2}, & N(x,y) = y^2 + \dfrac{x^2}{(1-xy)^2}\\ \\\tt \dfrac{\partial M}{\partial y} = \dfrac{-2(-x)}{(1 - xy)^3}, & \dfrac{\partial N}{\partial x} = \dfrac{2x}{(1 - xy)^2} + \dfrac{-2(-y)x^2}{(1 - xy)^3} \\ \\\tt \dfrac{\partial M}{\partial y} = \dfrac{2x}{(1 - xy)^3}, & \dfrac{\partial N}{\partial x} = \dfrac{2x(1 - xy)+2x^2y}{(1 - xy)^3} \\ \\\tt \: & \dfrac{\partial N}{\partial x} = \dfrac{2x}{(1 - xy)^3} \end{array} [/tex]

[tex] \small \begin{array}{l} \tt\dfrac{\partial M}{\partial y} = \dfrac{\partial N}{\partial x} \implies \text{Differential equation is exact.} \\ \\\tt \dfrac{\partial F}{\partial x} = M(x, y) = \dfrac{1}{(1 - xy)^2} \\ \tt\displaystyle F(x, y) = \int \dfrac{1}{(1 - xy)^2} \partial x = -\dfrac{1}{y} \int \dfrac{1}{(1 - xy)^2}(-y)\partial x \\ \\ \tt\:F(x, y) = \dfrac{1}{y(1 - xy)} + h(y) \\ \\ \tt\dfrac{\partial F}{\partial y} = N(x, y) = y^2 + \dfrac{x^2}{(1-xy)^2} \\ \\\tt \dfrac{\partial}{\partial y}\left[\dfrac{1}{y(1 - xy)} + h(y)\right] = y^2 + \dfrac{x^2}{(1-xy)^2} \\ \\ \tt-\dfrac{1 - xy + y(-x)}{y^2(1 - xy)^2} + h'(y) = y^2 + \dfrac{x^2}{(1-xy)^2} \\ \\ \tt-\dfrac{1 - 2xy}{y^2(1 - xy)^2} + h'(y) = y^2 + \dfrac{x^2}{(1-xy)^2} \\ \\ h'(y) = y^2 + \dfrac{x^2}{(1-xy)^2} + \dfrac{1 - 2xy}{y^2(1 - xy)^2} \\ \\ \tt\:h'(y) = y^2 + \dfrac{x^2y^2 - 2xy + 1}{y^2(1-xy)^2} = y^2 + \dfrac{1}{y^2} \\ \\ h(y) = \dfrac{y^3}{3} - \dfrac{1}{y} + C \\ \\ \tt\text{Substituting to }F(x,y),\text{we get} \\ \\ \dfrac{1}{y(1 - xy)} + \dfrac{y^3}{3} - \dfrac{1}{y} = C \\ \\ \quad \quad \text{or} \\ \\ \tt\red{\boxed{\dfrac{x}{1 - xy} + \dfrac{y^3}{3} = C} \Longleftarrow \textit{Answer}} \end{array} [/tex]

[tex] \Large \bold{SOLUTION\ 2:} [/tex]

[tex] \small \begin{array}{l} \tt\text{Since we already know that the equation is exact,} \\ \text{we can then continue solving for the solution by} \\ \text{inspection method or by algebraic manipulation.} \\ \\ \tt(1-xy)^{-2} dx + \big[y^2 + x^2 (1-xy)^{-2}\big]dy = 0 \\ \\ \tt\dfrac{dx}{(1-xy)^2} + \left[y^2 + \dfrac{x^2}{(1-xy)^2}\right]dy = 0 \\ \\ \tt\dfrac{dx}{(1-xy)^2} + y^2 dy + \dfrac{x^2}{(1-xy)^2} dy = 0 \\ \\ \tt\dfrac{dx + x^2dy}{(1-xy)^2} + y^2 dy = 0 \\ \\ \tt\text{Divide both numerator and denominator of the} \\ \tt\text{fraction by }x^2. \end{array} [/tex]

[tex] \small \begin{array}{c}\tt \dfrac{\dfrac{1}{x^2}dx + dy}{\dfrac{(1-xy)^2}{x^2}} + y^2 dy = 0 \\ \tt\\ \tt\dfrac{\dfrac{1}{x^2}dx + dy}{\left(\dfrac{1}{x}-y\right)^2} + y^2 dy = 0 \\ \\ \tt-\dfrac{\left(-\dfrac{1}{x^2}dx - dy\right)}{\left(\dfrac{1}{x}-y\right)^2} + y^2 dy = 0 \\ \\ \tt\displaystyle {\large{\int}} -\frac{d\left(\dfrac{1}{x}-y\right)}{\left(\dfrac{1}{x}-y\right)^2} + \int y^2 dy = \int 0 \\ \\ \tt\implies\tt \dfrac{1}{\dfrac{1}{x}-y} + \dfrac{y^3}{3} = C \\ \\\text{or} \\ \\ \tt\red{\boxed{\dfrac{x}{1 - xy} + \dfrac{y^3}{3} = C} \Longleftarrow \textit{Answer}} \end{array} [/tex]

#CarryOnLearning

#BrainlyMathKnower

a) the cost of. kg oranges is rs 350 how many kg of oranges can be bought for rs 665
b.). A car travel for 50 km.with the help of 5 litres of petrol how many litres of petrol is reauired to travel 120 km​

Answers

A: 1.9 Kilograms of oranges for rs 665.

B: 12 liters of petrol will make a car travel 120 km.

Solve the system of equations:

4x-5y=21
3x+10y= -53

Answers

Step-by-step explanation:

2× (4x-5y) = 21

3x+10y= -53

-------------------------

8x-10y = 42

3x+10y=-53

------------------------

11x= -11

{x=-1}

-----------------

3x+10y=-53

x=-1

3(-1)+10y=-53

-3+10y=-53

10y= -50

{y=5}

Factorize the given expression below.
a. 6x power 2 - 3x


b) x power 2 + 3x - 28


c) 4qu + 24av - 5bu -30bv
please answer and make it clear thank you. ​

Answers

Step-by-step explanation:

a)[tex] \sf \: Factor 6x2−3x \\ \sf {6x}^{2} −3x \\ \sf \: =3x(2x−1) \\ \sf \: Answer:3x(2x−1) \\ [/tex]

b)Let's factor x²+3x−28

⇒x²+3x−28

⇒x² - 4x + 7x - 28

⇒(x² - 4x) + (7x - 28)

⇒x( x - 4) + 7(x - 4)

⇒(x -4) (x + 7)

Answer:

(x−4)(x+7)

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