calculate grxn for the reaction at -73 c under the following standard conditions at equilibrium at ph2

Answer:

Na (s) + Cl2 (g) → NaCl (s)

Explanation:

A reaction of sodium with chlorine to produce sodium chloride is an example of a combination reaction. 2 Na + Cl 2 → 2 NaCl.

CH4 is an example of a covalent molecule.

Covalent molecules are formed when atoms share electrons between them to form a bond. In CH4, or methane, there is a single carbon atom that shares four electrons with four hydrogen atoms, resulting in a tetrahedral shape. Covalent molecules typically have low melting and boiling points, do not conduct electricity, and tend to have lower solubility in water compared to ionic compounds.

In contrast, ionic compounds, such as NaCl, CuSO4, and LiF, are formed from the transfer of electrons from one atom to another, resulting in the formation of positively and negatively charged ions. Ionic compounds typically have high melting and boiling points, are good conductors of electricity when dissolved in water, and have higher solubility in water compared to covalent molecules.

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I would argue against Tony's claim that the temperature of a solid cannot be measured, just because solids do not have a lot of thermal expansion.

Thermal expansion is the tendency of materials to change in size, shape, or volume in response to changes in temperature.

There are several ways to measure the temperature of solids. One common method is to use a thermometer, which can be inserted into the solid to measure its temperature. Another method is to use an infrared thermometer, which measures the temperature of a solid by detecting the amount of infrared radiation it emits.

Second, while it is true that solids have a lower coefficient of thermal expansion than liquids or gases, they still expand and contract with changes in temperature. This is evident in Valdez's example of the wooden door, which becomes difficult to open in the summer when the temperature is higher, and easier to open in the winter when the temperature is lower. This change in the size of the door is due to thermal expansion and contraction of the wood.

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When looking down the C2-C3 bond of pentane, the staggered conformations have the same representation (show the same orientation) there are three staggered conformations

Isomers are molecules with the same formula but a different spatial orientation of the atoms, meaning they have different shapes. Conformations refer to the different spatial arrangements that a molecule can take on by rotating around single bonds, such as those in pentane. The staggered conformations, which occur when the two largest substituents are 60 degrees apart, are the most thermodynamically stable of the conformations for pentane.

Therefore, when looking down the C2-C3 bond of pentane, there are three staggered conformations that have the same representation (show the same orientation).

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Universal waste is a category of hazardous waste that includes certain widely generated electronic devices, batteries, lamps, and other devices that contain hazardous materials.

The handling, storage, transportation, and disposal of universal waste is subject to regulations by the United States Environmental Protection Agency (EPA) under the Universal Waste Rule.

One of the requirements of the Universal Waste Rule is that records of universal waste shipments must be retained for a minimum of three years. This applies to any person who generates, collects, transports, or receives universal waste. The records must include the following information:

Retention of these records helps to ensure compliance with the regulations and enables tracking of the movement and disposition of universal waste. The records must be made available for inspection by authorized EPA officials upon request.

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Answer:

74g.

Explanation:

The volume won't increase by the volume of salt you added, though. This is for many different reasons among them the fact that salt is in grains (with lots of air in between) and the salt dissolving in the water and kind of squeezing in the spaces between water molecules. But the mass should increase by exactly the 19g you added.

Chlorofluorocarbon (CFC) is not an example of a naturally occurring greenhouse gas.

CFCs are human-made gases that are not naturally found in the atmosphere. These gases trap heat in the atmosphere, contributing to the greenhouse effect, but are not naturally produced.

On the other hand, methane, nitrous oxide, and water vapor are all naturally occurring greenhouse gases.

Methane is produced by microbial processes in the environment, while nitrous oxide and water vapor come from naturally occurring processes like volcanoes and evaporation.

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To distinguish between cyclohexane and 2-hexene, you can carry out the bromine water test. Chemical equation for the reaction is 2-hexene + Br2 (aq) -> 2,3-dibromohexane

This test is based on the fact that cyclohexane is an alkane and 2-hexene is an alkene. Alkenes readily react with bromine water due to the presence of a double bond, while alkanes do not react.

Add a few drops of bromine water to separate test tubes containing cyclohexane and 2-hexene.

Observe the color change in the test tubes.

Chemical equation for the reaction:

2-hexene + Br2 (aq) -> 2,3-dibromohexane

Upon reaction, the bromine water loses its color in the presence of 2-hexene, while it remains the same in the presence of cyclohexane.

This difference in color change will help you distinguish between the two compounds.

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Diffusion, nucleation, and crystal growth are the physical processes by which atoms rearrange during phase transformations in the solid state.

Phase transformations in the solid state refer to a type of reaction that happens to the solid state of matter, which results in different properties of the substance.

It is important to note that the process of phase transformation happens through different physical processes that include evaporation, melting, sublimation, and condensation, among others.

During phase transformation in the solid state, atoms undergo a rearrangement process that changes the physical properties of the solid into a different phase. This process usually happens in a few ways, such as:

- Diffusion: This is the movement of atoms from one place to another due to the application of heat or pressure, which allows the atoms to shift positions within the solid. The diffusion process enables the atoms to break and form new bonds, resulting in phase transformation.
- Nucleation: This is a process that happens when the solid phase undergoes a change, which causes the formation of new atoms or molecules. This process typically occurs in areas where there is a higher concentration of atoms, and it takes place due to the application of heat or pressure.
- Crystal Growth: This is a process that happens when the atoms of a solid phase come together to form a new crystal structure. The crystal structure has a different arrangement of atoms, which results in different physical properties.

These processes change the physical properties of the solid into a different phase, resulting in different properties.

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There are 1.49 × 10²³ formula units of potassium nitrate in a 25 g sample.

One formula unit is defined as the simplest formula of a substance, which indicates the relative amounts of the elements in the molecule. As a result, the number of formula units in a sample can be calculated by dividing the sample's mass by the substance's molar mass.

The molecular formula of potassium nitrate is KNO3. It contains one potassium atom (K), one nitrogen atom (N), and three oxygen atoms (O). The atomic masses of the elements can be used to calculate the molar mass of the compound.

One potassium atom has a molar mass of 39.1 g/mol, one nitrogen atom has a molar mass of 14.0 g/mol, and three oxygen atoms have a combined molar mass of 48.0 g/mol.

The molar mass of KNO3 = (1 × 39.1 g/mol) + (1 × 14.0 g/mol) + (3 × 16.0 g/mol) = 101.1 g/mol.

Now, on dividing the sample's mass (25 g) by the molar mass of potassium nitrate (101.1 g/mol), a value of 0.247 mol is obtained. The Avogadro constant can be used to convert moles into formula units. The Avogadro constant, 6.022 × 10²³ formula units per mole, represents the number of formula units in one mole of a substance.

The number of formula units = (0.247 mol) × (6.022 × 10²³ formula units/mol) = 1.49 × 10²³ formula units.

Therefore, there are 1.49 × 10²³ formula units of potassium nitrate in a 25 g sample.

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The samples that  has the most moles of the compound is option B which is 75.0g

To determine which sample has the most moles of the compound, we need to calculate the number of moles of each compound using its molar mass.

a) Fe2O3:

Molar mass of Fe2O3 = 2(55.85 g/mol of Fe) + 3(16.00 g/mol of O) = 159.70 g/mol

Number of moles of Fe2O3 = 163.0 g / 159.70 g/mol = 1.02 mol

b) CaS:

Molar mass of CaS = 40.08 g/mol of Ca + 32.06 g/mol of S = 72.14 g/mol

Number of moles of CaS = 75.0 g / 72.14 g/mol = 1.04 mol

Therefore, sample b) (75.0 g of CaS) has the most moles of the compound, with 1.04 moles. Sample a) (163.0 g of Fe2O3) has 1.02 moles and sample c) (150.0 g of BaO) has 0.98 moles.

So, the correct answer is b.

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The molar mass of the solute x is 85.32 g/mol.

The mass of the unknown, non-volatile, non-electrolyte solute = 12.0 g

Mass of the solvent = 100 g

The vapor pressure of the solvent before adding the solute = 100 torr

The vapor pressure of the solvent after adding the solute = 91.4 torr

Temperature = 299 K

Raoult's law can be written as:

P₂ = X₂ * P₁

Where:

P₁ = the vapor pressure of the pure solvent

P₂ = the vapor pressure of the solution

X₂ = the mole fraction of the solute

Solving for

X₂;X₂ = P₂/P₁ = 91.4/100

    X₂ = 0.914

Calculate the moles of benzene;

n = 100g / 78.11 g/mol = 1.28 moles

X₂ = moles of solute / (moles of solute + moles of benzene)

Substituting the value of X₂ and moles of benzene;

n = 0.1406 moles

Now we need to calculate the moles of the solute;

Mass of solute = 12.0 g

Now, we will use the following formula to calculate the molar mass of the solute;

Molar mass = Mass of solute / Moles of solute

Molar mass = 12.0 g / 0.1406 moles

Molar mass of the solute is 85.32 g/mol.

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Evaporites form as ions (minerals) precipitate out of an evaporating solution. The correct option is B.

Evaporites are minerals that are created as a result of the evaporation of water. The minerals are usually found in salt pans or salt lakes. Salt pans are shallow pans that are usually found in hot and dry regions of the world. In most cases, salt pans are usually found in places where water sources are limited. Evaporites form as ions (minerals) precipitate out of an evaporating solution.

As the water evaporates, it leaves behind salt crystals. Over time, these salt crystals can build up and form a layer of salt. The process of evaporation and deposition can repeat itself many times over the years, resulting in the formation of thick layers of salt.

There are different types of evaporites, and they are classified based on the minerals that are formed. Some of the most common types of evaporites include halite, gypsum, and anhydrite. Halite is the most common type of evaporite, and it is usually found in salt pans and salt lakes. Gypsum and anhydrite are usually found in areas that have been submerged in water for long periods of time.

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The ground state electron configuration of an atom of the element identified in the mass spectrometer results is  1s²2s²2p⁶3s².

The sample of the pure element that is analyzed using a mass spectrometer shows the following results:

Bar one: amu 24 and percent abundance just below 80.

Bar 2: amu 25 and percent abundance 10

Bar 3: amu 26 and percent abundance just above 10.

The ground-state electron configuration of an atom of the element that is identified in part c is as follows:

The mass number of the element is the weighted average of the isotopic masses, and it is calculated by adding the product of each isotope's atomic mass and its percent abundance. The calculation for the above-given values is shown below:

(24 amu × 0.79) + (25 amu × 0.10) + (26 amu × 0.11) = 24.33 amu

Since the mass number of the element is closer to 24 than to 25, it is reasonable to believe that the element is magnesium (Mg). The atomic number of magnesium is 12. Therefore, its electron configuration in the ground state is 1s²2s²2p⁶3s².

Hence, the ground-state electron configuration of an atom of the element that you identified in part c is 1s²2s²2p⁶3s².

Complete answer:

A sample of a pure element is anylazed using a mass spectrometer. The results are shown below.

Bar one: amu 24 and percent abundance just below 80.

Bar 2: amu 25 and percent abundance 10

Bar 3: amu 26 and percent abundance just above 10.

Write the ground-state electron configuration of an atom of the element that you identified in part c.

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Answer: The amount of heat energy required to melt 649.2 g of HBr is 12.99 kJ, given that the molar heat of fusion of HBr is 2.41 kJ/mol.

Molar heat of fusion is the amount of heat required to melt one mole of a substance. The molar heat of fusion for HBr is 2.41 kJ/mol.

To find the amount of heat energy required to melt 649.2 g of HBr, the following steps should be followed:

Step 1: Determine the number of moles of HBr in 649.2 g of HBr:mass of HBr = 649.2 gMolar mass of HBr = 80.91 g/molNumber of moles of HBr = mass/molar mass= 649.2 g/80.91 g/mol= 8.01 mol

Step 2: Calculate the amount of heat required to melt 1 mol of HBr:Given molar heat of fusion of HBr is 2.41 kJ/molHeat required to melt 1 mol of HBr = 2.41 kJ/mol

Step 3: Calculate the amount of heat required to melt 8.01 mol of HBr:Heat required to melt 8.01 mol of HBr = Heat required to melt 1 mol of HBr × Number of moles of HBrHeat required to melt 8.01 mol of HBr = 2.41 kJ/mol × 8.01 molHeat required to melt 8.01 mol of HBr = 19.301 kJ

Step 4: Convert the heat in kJ to J by multiplying it with 1000: Heat required to melt 8.01 mol of HBr = 19.301 kJ = 19,301J. Finally, we get the result: The amount of heat energy required to melt 649.2 g of HBr is 12.99 kJ.

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The first and second ionization of a diprotic acid cannot be treated as completely separate reactions when the reaction is taking place in an environment with a fixed pH.

The second ionization of the acid is dependent on the concentration of the ions produced from the first ionization.

If the pH is fixed, then the concentration of the first ionization is also fixed, so the second ionization will not occur completely independently.

For example, a diprotic acid such as oxalic acid can be completely ionized in two steps. In the first ionization, the hydrogen ions of the oxalic acid are replaced with hydroxide ions, forming the oxalate ion:

H2C2O4 + 2H2O → H3O+ + HC2O4–

In the second ionization, the oxalate ion is further dissociated, forming two separate anions and hydronium ions:

HC2O4– + H2O → H3O+ + C2O4–2

However, in an environment with a fixed pH, the second ionization will not take place as the concentration of oxalate ions from the first ionization is fixed.

Therefore, the two ionizations must be treated together in order to accurately predict the final concentrations of the products.

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Answer:

The first ionization constant is greater than the second ionization constant by only a factor of 10.

Explanation:

The two ionization constants must differ by a factor of at least 20 in order to treat the first and second ionizations as chemically (and mathematically) distinct.

a. The parentheses indicate that the elements within are grouped together, i.e., they are part of the same unit.

Tribarium Phosphate,Tribarium is the chemical symbol for Barium and the name reflects the fact that it is composed of three atoms of Barium and two atoms of Phosphate.It is an inorganic salt that is insoluble in water and has a variety of uses in industrial and medical applications.

b. The subscript 4 indicates that there are four [tex]PO_4\ molecules[/tex] in the compound.

c.The subscript 2 implies that there are two [tex]Ba_3[/tex] molecules in the compound.

d. The coefficient indicates the number of molecules of each element in the compound. In this case, there is one [tex]Ba_3[/tex] molecule, four [tex]PO_4[/tex] molecules, and three Ca molecules.

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As temperature increases, vapor pressure of substance also increases due to an increase in  kinetic energy of the molecules. The correct answers are options: 1, 2, 3, 4.

As temperature increases, vapor pressure of a substance also increases due to an increase in  kinetic energy of molecules Substances with stronger intermolecular forces will have lower vapor pressure because it requires more energy to break bonds between molecules and transition into  gas phase. An increase in external pressure will decrease  vapor pressure. Molecular size and shape of a substance can affect intermolecular forces and therefore its vapor pressure. For example, larger molecules tend to have stronger intermolecular forces, which result in lower vapor pressures. Options are 1, 2, 3, 4  correct .

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--The complete Question is, which of the following will affect the vapor pressure of a pure molecular substance?

select all that apply.

1. the external pressure

2. the structure of the substance

3. the strength of the intermolecular forces

4. the temperature

5. the weather conditions--

When carbonates (CO3^2-) or bicarbonates (HCO3^-) are reacted with an acid in an acid-base reaction, the resulting product is carbonic acid (H2CO3).

This reaction follows the general pattern of an acid-base reaction, where the base (CO3^2- or HCO3^-) and acid (H+) combine to form the conjugate acid (H2CO3) and conjugate base (OH-).
The general equation for this reaction is:
Acid + Base ⇋ Conjugate Acid + Conjugate Base
In the case of carbonates and bicarbonates, the equation is:
H+ + CO3^2- (or HCO3^-) ⇋ H2CO3 + OH-
The reaction between carbonates and bicarbonates with an acid is called a "carbonate hydrolysis" reaction. This is because the hydroxide ions (OH-) from the reaction can hydrolyze the carbonate ion (CO3^2-) and bicarbonate ion (HCO3^-), breaking them down into carbonic acid (H2CO3).
In addition to the carbonate hydrolysis reaction, there is also a "bicarbonate hydrolysis" reaction that occurs when bicarbonate ions are reacted with an acid. The general equation for this reaction is:
H+ + HCO3^- ⇋ H2CO3 + H2O
In this reaction, the hydroxide ions are replaced with water, and the resulting product is still carbonic acid (H2CO3).

To sum up, when carbonates (CO3^2-) or bicarbonates (HCO3^-) are reacted with an acid in an acid-base reaction, the resulting product is carbonic acid (H2CO3). This reaction follows the general pattern of an acid-base reaction, where the base and acid combine to form the conjugate acid and conjugate base. The reaction between carbonates and bicarbonates with an acid is called a "carbonate hydrolysis" reaction, and for bicarbonates it is called a "bicarbonate hydrolysis" reaction.

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By plugging in the values for each of the parameters and solving for t, the time required for 99.9% of the 2-chloro-2-methylpropane to hydrolyze can be determined.

The time required for 99.9% of the 2-chloro-2-methylpropane to hydrolyze at room temperature depends on the specific conditions of the reaction. Generally, it will take several hours for this reaction to occur.

To calculate the exact time required, we can use the Arrhenius equation, which is given as:

   k = A*e(-Ea/RT)

Where:

   k = rate constant for the reaction

   A = pre-exponential factor

   Ea = activation energy

   R = gas constant

   T = temperature

The values for each of the parameters and solving for t in the equation, the time required for 99.9% of the 2-chloro-2-methylpropane to hydrolyze can be determined.

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To prepare a 35% alcohol solution containing 15.0 ml of alcohol, you will need 27.9 ml of water and 15 ml of alcohol.

To calculate this, you can use the equation C1V1 = C2V2, where C1 is the concentration of the alcohol (in this case, 35%), V1 is the volume of alcohol you need (15 ml), C2 is the desired concentration of the solution (35%), and V2 is the total volume of the solution (25 ml).

To prepare a 35% alcohol solution containing 15.0 ml alcohol, you will require 27.9 ml of water. The amount of alcohol and water required to prepare a 35% alcohol solution containing 15.0 ml alcohol is given below:

Given data:

Let us find the amount of water required.

Using the above formula, Volume of solution = 15 + Volume of water

Let us find the percentage of water in the solution.

35% alcohol solution implies that the solution contains 35 ml of alcohol in 100 ml of solution. Therefore, the amount of solution that contains 1 ml of alcohol is:

Therefore, the amount of solution required to prepare 15 ml of alcohol is:

Using the formula for volume of solution, 42.9 ml of solution = 15 ml of alcohol + Volume of water.

Therefore, you will require 15 ml of alcohol and 27.9 ml of water to prepare a 35% alcohol solution containing 15 ml of alcohol.

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If 0.0200 m fe3 is initially mixed with 1.00 m oxalate ion, then concentration of Fe3+ ion at equilibrium is 0 M.

The balanced chemical equation for the reaction of Fe3+ ion and oxalate ion is:

Fe3+ + 3C2O42- -> Fe(C2O4)33-

The reaction quotient, Qc, for the above reaction is given by the expression:

Qc = [Fe(C2O4)33-]/[Fe3+][C2O42-]

Here, the initial concentration of Fe3+ ion

= 0.0200 m

And, the initial concentration of oxalate ion is 1.00 m . According to the stoichiometry of the balanced equation, 1 mole of Fe3+ ion reacts with 3 moles of C2O42- ions to form 1 mole of Fe(C2O4)33- complex ion. Hence, the concentration of C2O42- ion that reacts with the given initial concentration of Fe3+ ion is given by the expression: [C2O42-] = 3[Fe3+] = 3 x 0.0200 m = 0.0600 m. After the reaction comes to equilibrium, let the concentration of Fe3+ ion be x M.Now, [Fe(C2O4)33-] = 0 M (as the entire Fe3+ ion is converted into Fe(C2O4)33- complex ion)Substituting the given and calculated values in the expression for Qc, we get:

Kc = [Fe(C2O4)33-]/[Fe3+][C2O42-]

=> 0/[x][0.0600]

=> 0x

=> 0 M

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The volume of 0.150 M HNO3 that can be prepared from 0.350 L of 1.98 M HNO3 is 0.07112 L, or approximately 71.12 mL (since 1 L = 1000 mL).

The given equation is used to calculate the volume (V1) of a desired concentration of a solution (0.150 M HNO3) that can be prepared from a given volume (V2) of a known concentration solution (1.98 M HNO3), using the ratios of their concentrations (C1 and C2).

Let's break down the calculation step by step using the given values:

V2 (given volume) = 0.350 L

C1 (desired concentration) = 0.150 M

C2 (known concentration) = 1.98 M

Plugging these values into the equation, we get:

V1 (0.150 M HNO3) = V2 (1.98 M HNO3) x (C1 (0.150 M) / C2 (1.98 M))

V1 = 0.350 L x (0.150 M / 1.98 M)

V1 = 0.350 L x 0.0758

V1 = 0.07112 L

Therefore, the volume of 0.150 M HNO3 that can be prepared from 0.350 L of 1.98 M HNO3 is 0.07112 L, or approximately 71.12 mL (since 1 L = 1000 mL).

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The combination that will produce an insoluble salt is b) MnSO4 Pb(NO2)2.

A salt is a chemical compound made up of cations (positively charged ions) and anions (negatively charged ions) (negatively charged ions). The ions must be combined in such a way that the sum of the charges is zero. NaCl is the most well-known saltand it is made up of sodium cations (Na+) and chloride anions (Cl-).MnSO4 Pb(NO2)2 is the answer since both of these elements are soluble. MnSO4 is a soluble substance that is sometimes used in the production of ceramics.

MnSO4 is often used as a nutritional supplement for animals since it is a good source of manganese. Pb(NO2)2 is a powder that is bright yellow, it has a molar mass of 325.2 g/mol. It is made up of two NO2 anions (negatively charged ions) and one Pb2+ cation (positively charged ion).The formation of insoluble salts can occur when the cations and anions in a reaction solution bind to create a new solid. Since the newly formed solid is insoluble, it settles to the bottom of the solution and can be separated from the liquid through filtration. The insoluble salt that is formed is a white or colorless substance that appears as a powder.

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The excess reagent is FeCl₃ and 0.33 moles of FeCl₃ remains unreacted after igniting 3.00 moles of FeCl₃ with 2.00 moles of O₂ gas.

The balanced chemical equation for the reaction between FeCl₃ and O₂ is:

4 FeCl₃ + 3 O₂ → 2 Fe₂O₃ + 6 Cl₂

From the balanced equation, we can see that for every 4 moles of FeCl₃, we need 3 moles of O₂.

To determine what is the excess reagent and how much of it is left over, we need to calculate the amount of each reagent required for complete reaction:

3.00 moles FeCl₃ × (3 moles O₂/4 moles FeCl₃) = 2.25 moles O₂ required

2.00 moles O₂ × (4 moles FeCl₃/3 moles O₂) = 2.67 moles FeCl₃ required

Since we only have 2.00 moles of O₂ available, this is the limiting reagent and there is not enough O₂ to react completely with all 3.00 moles of FeCl₃. Therefore, FeCl₃ is the excess reagent.

The amount of excess reagent remaining can be calculated by subtracting the amount required for complete reaction from the amount initially present:

Excess FeCl₃ = 3.00 moles - 2.67 moles = 0.33 moles

Therefore, there is an excess of 0.33 moles of FeCl₃ remaining unreacted. There is no excess of O₂ remaining, as we started with less than the amount required for complete reaction.

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Yes, a solid Cu(OH)2 will form when 0.075 g KOH is dissolved in 1.0 L of 1.0 x 10^-3 M Cu(NO3)2.  0.107 g of solid Cu(OH)2 will form.

First, we need to determine the amount of Cu2+ ions present in the solution:
1.0 x 10^-3 M Cu(NO3)2 means that there are 1.0 x 10^-3 moles of Cu2+ ions per liter of solution.
Next, we can use stoichiometry to determine the amount of OH- ions that will react with the Cu2+ ions to form Cu(OH)2. The balanced chemical equation for this reaction is:
Cu2+ (aq) + 2OH- (aq) → Cu(OH)2 (s)
For every 1 mole of Cu2+ ions, we need 2 moles of OH- ions. Therefore, the total amount of OH- ions needed to react with all of the Cu2+ ions in the solution is:
2 x 1.0 x 10^-3 mol = 2.0 x 10^-3 mol
Now we can use the Ksp of Cu(OH)2 to calculate the concentration of Cu2+ and OH- ions in the solution. The Ksp expression for Cu(OH)2 is:
Ksp = [Cu2+][OH-]^2
Since we know the Ksp value for Cu(OH)2, we can solve for either [Cu2+] or [OH-]. Let's solve for [OH-]:
Ksp = [Cu2+][OH-]^2
4.8 x 10^-20 = (1.0 x 10^-3 M)[OH-]^2
[OH-]^2 = 4.8 x 10^-17
[OH-] = 2.2 x 10^-9 M
Therefore, the concentration of OH- ions in the solution is 2.2 x 10^-9 M. Since we need 2 moles of OH- ions for every mole of Cu2+ ions, we know that the concentration of Cu2+ ions is half of the concentration of OH- ions:
[Cu2+] = 1.1 x 10^-9 M
Finally, we can use the molar mass of Cu(OH)2 to determine the mass of solid that will form:
Molar mass of Cu(OH)2 = 97.56 g/mol
1 mole of Cu(OH)2 is formed for every mole of Cu2+ ions, so the mass of Cu(OH)2 that will form is:
0.0011 mol x 97.56 g/mol = 0.107 g
Therefore, 0.107 g of solid Cu(OH)2 will form when 0.075 g KOH is dissolved in 1.0 L of 1.0 x 10^-3 M Cu(NO3)2.

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A desulfurization reaction is a type of hydrogenation reaction, where sulfur atoms in a compound are replaced by hydrogen atoms. In a desulfurization reaction, a thioacetal is treated with Raney nickel, resulting in the conversion of the thioacetal to an alkane.

Desulfurization reactions are a type of chemical reaction that involves the conversion of a thioacetal to an alkane by treating the thioacetal with raney nickel. During the reaction, the sulfur atoms of the thioacetal are replaced by hydrogen atoms.

Desulfurization is the process of converting sulfur-containing chemicals into non-sulfur containing substances by means of a chemical reaction. It is applied in refineries and in the petrochemical industry to lower sulfur emissions. Sulfur emissions contribute to acid rain and other environmental problems.

Therefore, desulfurization is an essential process for reducing pollution caused by sulfur dioxide emissions. In conclusion, desulfurization reactions are a type of chemical reaction that involves the replacement of sulfur atoms with hydrogen atoms. They are used in the petrochemical industry to reduce sulfur emissions and prevent environmental pollution caused by acid rain and other environmental problems.

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The equilibrium constant for the new reaction at 752 K is approximately 0.29 and at 719 K is approximately 0.42.

Step wise explanation:

1) For the first reaction, the equilibrium constant (Kc) is given as 11.8 at 752 K for the reaction:

[tex]2NH_{3}[/tex](g) ⇌ [tex]N_{2}[/tex](g) + [tex]3H_{2}[/tex](g)

You are asked to calculate Kc for the following reaction:

[tex]1/2N_{2} + 3/2H_{2}[/tex] ⇌ [tex]NH_{3}[/tex](g)

To find Kc for the new reaction, note that it is the reverse of the original reaction with all coefficients divided by 2. To calculate the equilibrium constant for the reverse reaction, take the reciprocal of the original Kc, and then raise it to the power of the coefficients ratio (1/2):

Kc (new) =[tex]\sqrt{ (1 / Kc (original))}[/tex] = [tex]\sqrt{(1 / 11.8)}[/tex] ≈ 0.29

So, the equilibrium constant for the new reaction at 752 K is approximately 0.29.

2) For the second reaction, the equilibrium constant (Kc) is given as 5.70 at 719 K for the reaction:

[tex]2NH_{3}[/tex](g) ⇌ [tex]N_{2}[/tex](g) + [tex]3H_{2}[/tex](g)

You are asked to calculate Kc for the following reaction:

[tex]NH_{3}[/tex](g) ⇌ [tex]1/2N_{2}[/tex](g) + [tex]3/2H_{2}[/tex](g)

This new reaction is the reverse of the original reaction with all coefficients divided by 2. Similar to the first case, take the reciprocal of the original Kc and then raise it to the power of the coefficients ratio (1/2):

Kc (new) = [tex]\sqrt{(1 / Kc (original))}[/tex] = [tex]\sqrt{(1 / 5.70)}[/tex] ≈ 0.42

So, the equilibrium constant for the new reaction at 719 K is approximately 0.42.

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Answer:

Explanation:

I think 'The heat from Earth's core causes material in the area under the crust to become denser and rinse, while less dense material sinks.

To calculate the mass of sodium benzoate needed to obtain a buffer with a pH of 4.20, use the Henderson-Hasselbalch equation.

The Henderson-Hasselbalch equation states that the pH of a buffer is equal to the pKa of the acid plus the logarithm of the ratio of the concentrations of the conjugate base and acid.

Using this equation, we can calculate the mass of sodium benzoate needed as follows: first, we need to calculate the ratio of the concentrations of the conjugate base (sodium benzoate) and the acid (benzoic acid). This ratio is equal to the concentration of the conjugate base divided by the concentration of the acid.

For the given solution, the concentration of the acid is 0.15 M and the concentration of the conjugate base is equal to the desired pH of 4.20 (as the pKa of benzoic acid is 4.20). Therefore, the ratio of the concentrations is 4.20/0.15.

Next, we use the Henderson-Hasselbalch equation to calculate the mass of sodium benzoate needed. The equation states that the pH of a buffer is equal to the pKa of the acid (4.20) plus the logarithm of the ratio of the concentrations of the conjugate base and acid.

As the ratio of the concentrations is 4.20/0.15, the logarithm of this ratio is 1.862. Therefore, the pH of the buffer is equal to 4.20 + 1.862, or 6.062.

Finally, we can calculate the mass of sodium benzoate needed by multiplying the molarity of the solution (142.0 mL) by the concentration of the conjugate base needed for a pH of 6.062. This yields a mass of sodium benzoate of 8.68 grams.

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