The frequency of the light that has a wavelength of 16.23 × 10⁻⁹ meter would be 1.84 × 10¹⁶ Hz , as the frequency and the wavelength are inversely proportional to each other.
What is Wavelength?It can be understood in terms of the distance between any two similar successive points across any wave for example wavelength can be calculated by measuring the distance between any two successive crests.
C = λν
As given in the problem we have to calculate the frequency of the light if the wavelength of light is 16.23 × 10⁻⁹ meter.
The frequency of the light = 3 × 10⁸ / 16.23 × 10⁻⁹
= 1.84 × 10¹⁶ Hz
Thus, the frequency of the light would be 1.84 × 10¹⁶ Hz.
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Sodium hydroxide is extremely soluble in water. At a certain temperature, a saturated solution contains 573 g NaOH(s) per liter of solution. Calculate the molarity of this saturated NaOH(aq) solution.Concentration: ____________ M
Remember: solution = NaOH + water
Volumen here = 1 L
Molecular mass NaOH = 39.99 g/mol
[tex]M\text{ = }\frac{573\text{ g}}{39.99\text{ }\frac{g}{\text{mol}}x\text{ 1 L}}=\text{ 14.32 }\frac{mol}{L}[/tex]Answer: Contration = 14.32 M
What volume of carbon dioxide (in L) will 2.00 g of antacid made of calcium carbonate produce at 37.0 °C and 1.00 atm in the stomach according to the following reaction?
CaCO₃ (s) + 2 HCl (aq) → CaCl₂ (aq) + H₂O (l) + CO₂ (g)
The volume of carbon dioxide (in L) that can be made from the 2.00 g of the antacid is 5.09 L
How to determine the volume of CO₂We'll beging by obtaining the mole of CO₂ produced. This can be obtained as follow:
Mass of CaCO₃ = 2 gMolar mass of CaCO₃ = 100 g/mole Mole of CaCO₃ = 2 / 100 = 0.02 moleCaCO₃ (s) + 2 HCl (aq) → CaCl₂ (aq) + H₂O (l) + CO₂ (g)
From the balanced equation above,
1 mole CaCO₃ reacted to produce 1 mole of CO₂.
Therefore,
0.02 mole CaCO₃ will also react to produce 0.02 mole of CO₂.
Finally, we shall determine the volume of the CO₂ produced. Details below.
Number of mole (n) = 0.02 moles Pressure (P) = 1 atm Temperature (T) = 37 °C = 37 + 273 = 310 KGas constant (R) = 0.0821 atm.L/Kmol Volume (V) =?PV = nRT
1 × V = 0.02 × 0.0821 × 310
V = 5.09 L
Thus, the volume obtained is 5.09 L
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Given the following, find the number of grams 0.3672 moles SmO
Answer:
61.09 grams SmO
Explanation:
To find the number of grams SmO, you need to multiply the moles by the molar mass of SmO. The molar mass is a ratio which represents the mass of SmO per every 1 mole. It is important to arrange the ratio in a way that allows for the cancellation of units (moles should be in the denominator). The final answer should have 4 sig figs like the given value (0.3672 = 4 sig figs).
Atomic Mass (Sm): 150.36 g/mol
Atomic Mass (O): 15.999 g/mol
Molar Mass (SmO): 150.36 g/mol + 15.999 g/mol
Molar Mass (SmO): 166.359 g/mol
0.3672 moles SmO 166.359 grams
-------------------------------- x -------------------------- = 61.09 grams SmO
1 mole
Which choice is an element?
carbon dioxide
carbon
water
air
Answer:
Explanation:
Carbon is the only element listed. Carbon Dioxide consists of Carbon AND Oxygen x2 so this is a compound. As stated earlier, air is a mixture of compounds. Water is another compound consisting of Hydrogen x2 and Oxygen.
For the following equations you will be given the names of reactants and products. In the space below each reaction provide theformulas of each reactant and product along with coefficients.
Explanation:
First, let's write the formulas:
Potassium chlorate: KClO3
Oxygen: O2
Potassium chloride: KCl
So the reaction will be:
KClO3 -> O2 + KCl
Now let's balance it.
To balance the equation it is necessary to have the same number of atoms of each element on both sides of the equation (reactant side and product side). Let's count the number of atoms of each element for the unbalanced equation: KClO3 -> O2 + KCl
Reactant side:
K - 1
Cl - 1
O - 3
Product side:
O - 2
K - 1
Cl - 1
As you can see, oxygen number of atoms is not equal on both sides of the equation. Let's balance it by changing the stoichiometric coefficient.
2KClO3 → 2KCl + 3O2
Let's count the number of atoms of each element for the balanced equation.
Reactant side:
K - 2
Cl - 2
O - 6
Product side:
K - 2
Cl - 2
O - 6
Now the equation is balanced.
Answer: 2KClO3 → 2KCl + 3O2
Coefficients are: 2, 2 and 3.
How many moles of atoms are in 7 g of 13C
Answer:
Explanation:
molar mass of 13c = 13 grams
number of moles = mass / molar mass
therefore,
number of moles = 7 / 13
To know the number of atoms in 7/13 moles, we simply multiply the number of moles by Avogadro's number as follows:
number of atoms = (7/13) x 6.022 x 10^23 = 3.2426 x 10^23 atoms
_Ca +_AlCl3 --> _CaCl2 + _AIWhen the reaction is balanced, what is the coefficient in front of the Al? Answer options 2, 4, 1, 3
To balance the given equation remember to start by the elements that are different from oxygen and hydrogen, in this case, let's start by chlorine:
As chlorine in AlCl3 is 3 times and in CaCl2 is 2 times, we have to write a 2 in AlCl3 and a 3 in CaCl2, with this coefficients we will have 6 chlorines in total at each side of the equation.
Then, as we put that 2 in front of AlCl3, we will also have 2 aluminium. After the reaction we have only one aluminium, it means that we need to write 2 in front of Al to balance the number of aluminium in the equation.
The correct option is 2.
Place these Types of Decay in Order from the LOWEST Energy to the HIGHEST energy.
Answer:
[tex]\begin{gathered} Alpha\text{ Decay} \\ Beta\text{ Decay} \\ Gamma\text{ Decay} \end{gathered}[/tex]Explanation:
Here, we want to order the radiations in terms of energy
There is a proportional relationship between the mass and the energy
It is established that the radiation with a higher mass would have the lesser energy
Alpha decay has the highest mass and thus, the lowest energy. This is followed by beta decay, and finally, gamma decay
What is the pH of a solution in which 15 mL of 0.10 M NaOH is added to 25 mL of 0.10 M HCl?
Answer:
The pH of the solution is 1.60.
Explanation:
1st) It is necessary to write and balance the chemical reaction:
[tex]NaOH+HCl\rightarrow NaCl+H_2O[/tex]Now we can see that 1 mole of NaOH reacts with 1 mole of HCl.
2nd) We have to calculate the moles contained in 15mL of 0.10M NaOH solution and the moles contained in 25mL of 0.10M HCl solution:
• Moles contained in NaOH solution:
[tex]\begin{gathered} 1000mL-0.10moles \\ 15mL-x=\frac{15mL*0.10moles}{1000mL} \\ x=1.5*10^{-3}moles \end{gathered}[/tex]• Moles contained in HCl solution:
[tex]\begin{gathered} 1000mL-0.10moles \\ 25mL-x=\frac{25mL*0.10moles}{1000mL} \\ x=2.5x10^{-3}moles \end{gathered}[/tex]Now we know that there are 1.5x10^-3 moles of NaOH and 2.5x10^-3 moles of HCl.
3rd) According to the stoichiometry of the reaction, 1 mole of NaOH reacts with 1 mole of HCl, so in this case, 1.5x10^-3 moles of NaOH will react with 1.5x10^-3 moles of HCl, because NaOH will be the limiting reactant and HCl will be the excess reactant.
So, now we have to calculate the excess of HCl:
2.5x10^-3moles - 1.5x10^-3moles = 1x10^-3moles
Now we know that there are 1x10^-3 moles of HCl left.
4th) Excess HCl will remain dissociated into H+ and Cl-, according to the following equation:
[tex]HCl\rightarrow H^++Cl^-[/tex]That means that for every mole of HCl, 1H+ dissociates. So, in this case, there are 1x10^-3 moles of H+.
Remember that these moles are contained in 40mL, so the molarity of H+ is 0.025M:
[tex]\begin{gathered} 40mL-1x10^{-3}moles \\ 1000mL-x=\frac{1000mL*1x10^{-3}moles}{40mL} \\ x=0.025moles \end{gathered}[/tex]5th) Finally, we can calculate the pH of the solution, by replacing the H+ concentration in the pH formula:
[tex]\begin{gathered} pH=-log\lbrack H^+\rbrack \\ pH=-log\lbrack0.025\rbrack \\ pH=1.60 \end{gathered}[/tex]So, the pH of the solution is 1.60.
Some hydrogen and iodine are mixed at 229 degrees Celsius in a 1.00L container. When equilibrium is established, the following concentrations are present: [HI] = 0.490 M, [H2] = 0.080 M, [I2] = 0.060 M. If an additional 0.300 mol of HI is then added, what concentration will be present when the new equilibrium is established?
The concertation of the HI that would be present in the new equilibrium position is 0.15 M.
What is the new equilibrium position?We have to first obtain the equilibrium constant that we have under the initial conditions and then we have; H2 + I2 ------> 2HI
K = [HI]^2/[H2] [I2]
K = (0.490)^2/(0.080) (0.060)
K = 0.2401/(0.080) (0.060)
K = 50
Again;
H2 + I2 ------> 2HI
Initial 0.080 0.060 0.060
concentration +x +x -2x
Equilibrium 0.080 + x 0.060 + x 0.490 - 2x
50 = (0.490 - 2x)^2/( 0.080 + x) (0.060 + x)
Working through the quadratic we have;
46x^2 + 10.2 x - 0.38 = 0
x = 0.32 M
In each case we now have;
H2 = 0.080 + 0.32 = 0.4 M
[I2] = 0.060 + 0.32 = 0.38 M
[HI] = 0.790 - 2( 0.32 ) = 0.15 M
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Limestone is a sedimentary rock composed largely of the mineral calcite, (calcium carbonate) CaCO3. To test the purity of the calcium carbonate, a sample of the mineral is reacted with hydrochloric acid to produce calcium chloride, carbon dioxide and water If a 15.70 g sample of calcite is reacted with excess hydrochloric acid and 16.89 g of calcium chloride are produced, what is the percent by mass of the calcium carbonate in the limestone? A) 69.4% B)93.0 % C) 96.94% D)98,22 %
Answer:
[tex]C\text{ : 96.94 \%}[/tex]Explanation:
Here, we want to get the percentage by mass of calcium carbonate in the limestone
We start by writing an equation of chemical reaction
The reaction involves calcium carbonate reacting with hydrochloric acid to give calcium chloride, carbon dioxide and water
We have the equation as follows:
[tex]\text{CaCO}_{3(s)\text{ }}+2HCl_{(aq)}\rightarrow CaCl_{2(aq)\text{ }}+CO_{2(g)\text{ }}+H_2O_{(l)}[/tex]Now, let us work with the extra information
16.89 g of calcium chloride are produced
Let us get the number of moles of calcium chloride produced
We can get that by dividing the mass by the molar mass of calcium chloride
The molar mass of calcium chloride is 111 g/mol
So, the number of moles will be:
[tex]\frac{16.89}{111}\text{ = 0.1522 mole}[/tex]From the equation,
1 mole of calcite gave 1 mole of calcium chloride, then 0.1522 mole of calcium chloride was produced by 0.1522 mole of calcite
To get the mass of calcite that produced this, we have to multipply the number of moles by the molar mass of calcite
The molar mass of calcite is 100 g/mol
That means the mass of calcite that produced the calcium chloride will be:
[tex]0.1522\text{ }\times\text{ 100 = 15.22 g}[/tex]What this mean is that 15.22 g of calcite produced the given mass of calcium chloride
The percentage by mass of calcite in the limestone will be:
[tex]\frac{15.22}{15.70}\times\text{ 100\% = 96.94 \%}[/tex]How many pounds in 16.1lbmol of pure HCl
Answer:
586.846 lbs
Explanation:
the molar mass of HCl is 1 + 35.45 = 36.45
this means you can do 16.1 lbmol * 36.45 lb/lbmol = 586.845
using a graduated cylinder and a becker write the detailed steps to measure the volume of a piece of rock
The detailed steps to measure the volume of a piece of rock using a graduated cylinder and beaker are based on Archimedes' Principle, which states that an object that is displacing fluid has a weight equal to that of the object it is displacing.
Step 1: In order to calculate a stone's volume, we first add water to the graduated cylinder until the stone is fully submerged. Step 2: Following the insertion of the stone into the cylinder, the initial reading, or baseline reading, must now be recorded. Step 3: The last reading of the cylinder needs to be recorded after the stone has been fully immersed. Step 4: We can calculate the stone's millilitre capacity by comparing the cylinder's results. If necessary, this value can be changed to another unit of measurement.The submersion or dunking method is another name for the displacement method.
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explain the process of photosynthesis with these
Words:
Photosynthesis,
light,
water,
energy,
Carbon Dioxide,
Oxygen,
xylem,
stomata,
Sugar(Glucose),
phloem,
chloroplasts,
leaves,
roots
Be legible and neat please and thank you
The process of photosynthesis used by plant in which they produce sugar ( glucose ).
Photosynthesis is the process in which plants produced sugar by using sun - light , water and carbon dioxide. In the process of photosynthesis plants use carbon dioxide ( CO₂ ) and water H₂O from the air and the soil then this carbon dioxide and water transforms to oxygen and sugar (glucose). the oxygen produced by plant back into the air and the sugar produces stores by the plant as the form of energy.
sunlight
carbon dioxide + water --------------> glucose + oxygen
In the leaf cell a part called chloroplast in it energy in sunlight used to break oxygen and hydrogen. T he water required in the process of photosynthesis taken by the roots from soil and then it transport with the help of xylem cell to the different parts of plant. phloem takes sugar from leaves to different parts of plant. The stomata is for the transpiration exchange that means it takes carbon dioxide and the release oxygen back to air after the photosynthesis end.
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According to the label on a soft drink, one serving provides 185 kcal. If all of this energy is used to lift 1.0-kg blocks, how many blocks can be lifted 7.0 meters? Note: 1 J is approximately equal to the energy required to raise a 1-kg block a distance of 10 cm against Earth’s gravity.
The number of blocks that can be lifted through this height is 11563 blocks.
How many blocks can be lifted?We know that we define the term energy as the ability to do work, Now we have to consider the fact that we are told that one serving provides 185 kcal. Then we are told that all of this energy is used to lift 1.0-kg blocks through a distance of 7.0 meters.
Given that the energy exerted in lifting each block is;
mgh
m = mass of the block
g = acceleration due to gravity
h = height lifted through
E = 1.0-kg * 9.8 m/s^2 * 7.0 meters = 68.6 J or 0.016 kcal
The number of blocks that can be lifted = 185 kcal/ 0.016 kcal
= 11563 blocks
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NaCl + _Cal2 → Nal + CaCI2
Answer
2NaCl + Cal₂ → 2Nal + CaCI₂
Explanation
Given unbalanced equation;
NaCl + _Cal₂ → Nal + CaCI₂
Step 1: Balance the Cl atom on both the reactant and product sides of the equation by putting 2 as the coefficient of NaCl in the reactant side.
2NaCl + _Cal₂ → Nal + CaCI₂
Step 2: Balance the Na atom on both the reactant and product sides of the equation by putting 2 as the coefficient of NaI in the product side.
2NaCl + Cal₂ → 2Nal + CaCI₂
Therefore, the balanced equation is: 2NaCl + Cal₂ → 2Nal + CaCI₂
What are the products of the neutralization reaction between HNO3 andCa(OH)2?OA. CaO, NO₂, and H₂OB. Ca3N₂ and H₂OOC. Ca(NO3)2 and H₂OOD. CaNO3 and H30+
Ca(NO3)2 and H₂O. Option C is correct
Explanations:What is a neutralization reaction?The combination of acid and base to form salt and water at the product is known as a neutralization reaction.
Hence the products of the neutralization reaction between HNO3 and Ca(OH)2 must be salt and water
From the given option, the equivalent product that are salt and water is Ca(NO3)2 and H₂O which gives the required product.
For an aqueous solution with a H+ concentration of 1.0 × 10−12 M, calculate the concentration of OH−.
Taking into account the definition of pH and pOH, the concentration of OH⁻ is 1×10⁻² M.
Definition of pHpH is a measure of acidity or alkalinity that indicates the amount of hydrogen ions present in a solution or substance.
The pH is defined as the negative base 10 logarithm of the activity of hydrogen ions:
pH= - log [H⁺]
Definition of pOHSimilarly, pOH is a measure of hydroxyl ions in a solution and is expressed as the logarithm of the concentration of OH⁻ ions, with the sign changed:
pOH= - log [OH⁻]
Relationship between pH and pOHThe following relationship can be established between pH and pOH:
pOH + pH= 14
Concentration of OH⁻Being [H⁺]=1.0×10⁻¹² M, the pH is calculated as:
pH= - log (1.0×10⁻¹² M)
Solving:
pH= 12
Being pH= 4.85, and considering the relationship between pH and pOH, pOH is calculated as:
pOH + 12= 14
pOH= 14 - 12
pOH= 2
Replacing in the definition of pOH the concentration of OH⁻ ions is obtained:
- log [OH⁻]= 2
Solving
[OH⁻]= 10⁻²
[OH⁻]= 1×10⁻² M
In summary, the [OH⁻] is 1×10⁻² M.
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PLEASE HELP, IT’S DUE TODAY!
Isotopes of certain ___ elements that spontaneously emit ____ and ____ from the _____.
Isotopes of certain __radioactive__ elements that spontaneously emit __radiation__ and _rays___ from the __nuclei____
What causes isotopes to emit radiation ?Any of multiple species of the same chemical element with differing masses whose nuclei are unstable and spontaneously produce radiation in the form of alpha, beta, and gamma rays are known as radioactive isotopes, also known as radioisotopes, radionuclides, or radioactive nuclides.
Isotopes are identical elemental atoms with differing quantities of neutrons. Numerous elements have one or more radioactive isotopes. Due to the instability of their nuclei, they decay and release radiation.Many of the radioisotopes in the uranium, thorium, and actinium natural radiation decay series, as well as the naturally occurring radioisotopes potassium-40 and carbon-14, generate gamma radiation.Learn more about Isotopes here:
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500 ml of an unknown concentration of KOH solution and 250 ml of 0.01 ml were mixed KOH solution.
The pH of the resulting solution is 12.7. Calculate the concentration of the first KOH solution.
Answer:
262
Explanation:
Calculate the number of photons having a wavelength of 16.0 um required to produce 2.3KJ of energy (Note => 16.0 um = 16.0 * 10^6 m & 2.3KJ = 2300 J)
The number of photons having a wavelength of 16.0 um required to produce 2.3KJ of energy is 1.85 x 10¹⁹
What are photons?Photons are defined as a basic particle that is both the force carrier for the electromagnetic force and a quantum of the electromagnetic field, which includes electromagnetic radiation like light and radio waves.
It can also be defined as a discrete bundle of electromagnetic energy is what is known as a light particle.
Energy = 2.3 KJ
Wavelength = 16.0 x 10⁶ m
Energy = hc / ∧
= 6.63 x 10²⁴ x 3 x 10³ / 16.0 x 10⁶
= 1.24 x 10¹⁹ J
Number of photons used = 2.3 KJ / 1.24 x10¹⁹
= 1.85 x 10¹⁹
Thus, the number of photons having a wavelength of 16.0 um required to produce 2.3KJ of energy is 1.85 x 10¹⁹
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Using 0.082 as your R value, what mass of NaN3 is required to produce 10L of N2 gas, at 273K and 1.5atm. Show all your work completely.Use the following formula to guide your work: 2NaN3 -> 2Na + 3 N2
To solve this question, we need to use the Clapeyron formula.
Clapeyron's formula is a mathematical expression that relates quantities such as pressure (P), volume (V), temperature (T) and the number of particles (n) that make up an ideal gas.
The formula is: PV = nRT
First, let's discover the number in moles of N2. We have:
P = 1.5 atm
V = 10 L
n = ???
R = 0.082 atm.L/mol.k
T = 273 K
1.5 x 10 = n x 0.082 x 273
15 = n x 22.386
n = 15/22.386
n = 0.67 moles
As we can see in the chemical reaction equation, the ratio between NaN3 and N2 is 2:3.
So:
2 mol of NaN3 --- 3 mol of N2
x mol of NaN2 --- 0.67 moles
3x = 2 x 0.67
x = 0.45 moles of NaN3
Now we transform this value into grams, using NaN3 formula mass, which is 65 g/mol:
65 g ---- 1 mol
x g ---- 0.45 mol
x = 29 g
Answer: 29 g of NaN3
A 25.0 mL solution of HNO₃ is neutralized with 31.4 mL of 0.250 M Ba(OH)₂. What is the concentration of the original HNO₃ solution?
The concentration of the 25ml of original HNO₃ solution that was neutralized with 31.4 mL of 0.250 M Ba(OH)₂ is 0.628 M HNO3
The neutralization reaction involved with HNO₃ and Ba(OH)2 is
Ba(OH)₂ + 2HNO₃---> Ba(NO₃) + 2H₂O.
From the balanced equation of the reaction, we can say that to neutralize barium hydroxide (Ba(OH)₂) we would require 2 moles of Nitric acid (HNO₃)
By multiplying concentration of barium hydroxide by volume its volume, and then multiplying by 2 as twice is required we would get the moles of HNO3 that is equivalent to 2 moles based on the values
Moles of HNO₃ = 2 (0.0314 * 0.250) = 0.0157 moles
Concentration of the original HNO₃ solution = 0.0157 moles / 0.025 L = 0.628 M HNO₃
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2.65 moles of an ideal gas at 36.9oC and 40,205Pa occupy 54.7mL. Additional gas is added to this container such that the temperature and pressure change to 113.7oC and 131,874Pa, with the volume remaining the same. How many moles of this gas were added?
The moles of gas added could not be determined because of an apparent error in the data provided for the volume of the container.
What is the number of moles of gas in the container?The moles of gas in the container is calculated from the ideal gas equation as follows;
PV = nRTn = PV / RTData given:
P = 131,874 Pa or 131.874 kPa
V = 54.7 mL = 0.0547 L
T = 113.7 °C or (113.7 + 273) K
T = 386.7 K
R, molar gas constant = 8.314 L⋅kPa.K/mol
n = (131.874 * 0.0547 L) / (8.314 * 386.7 )
n = 0.000224 moles
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how many grams of CO2 are in 5.67 moles of CO2
The International System of Units uses the mole (symbol: mol) as the unit of substance amount.
In 5.67 moles of CO2 there exists 249.48 grams of CO2.
How to calculate grams in moles?Start by dividing the number of atoms by the atomic weight of each component of the compound to convert grams to moles. After that, tally up all of your responses to determine the compound's molar mass. The final step is to calculate the number of moles by dividing the number of grams of the compound by its molar mass.
The International System of Units uses the mole (symbol: mol) as the unit of substance amount. How many elementary entities of a particular substance are present in an object or sample is determined by the quantity of that substance.
Let the equation be
Mass = relative atomic mass × mole number
substitute the values in the above equation, we get
= 5.67 × (12 + 16 + 16)
= 249.48 g
Therefore, there exists 249.48 grams of CO2 are in 5.67 moles of CO2.
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# 19. Write the molecular, ionic and net ionic equation, with the phases of matter for the reaction between Barium acetate + Sodium phosphate --> Barium phosphate + Sodium acetate.
(a) Write the correct formulas for the molecular equation (b) balance the equation (c) identify the spectator ions (d) Write the ionic equation and (e) Write the net ionic equation.
The general molecular equation is; [tex]Ba(CH3COO)_{2} (aq) + Na_{3} PO_{4} ------ > Ba_{3} (PO_{4})_{2} (s)+ Na(CH3COO)_{2} (aq)[/tex] while the net ionic equation is; [tex]2PO_{4} }^{3-} (aq) + 3Ba^{2+ } (aq) ------- > Ba_{3} (PO_{4})_{2} (s)[/tex]
What is a reaction?We can define the term reaction as the interaction that occurs between the reactants and helps us to be able to get a product as shown. Now we have a case in which we are asked to write the molecular, ionic and net ionic equation, with the phases of matter for the reaction between Barium acetate + Sodium phosphate --> Barium phosphate + Sodium acetate.
The task now is to make use of the ideas that we have from the question to be able to determine both the molecular reaction equation as well as the net ionic equation as required.
Let us no take the reaction individually. We can write the molecular reaction as;
[tex]Ba(CH3COO)_{2} (aq) + Na_{3} PO_{4} ------ > Ba_{3} (PO_{4})_{2} (s)+ Na(CH3COO)_{2} (aq)[/tex]
After we have written the molecular reaction equation, then we can identify the spectator ions as acetate ion and the sodium ion as we can see from the balanced reaction equation.
The net ionic equation therefore is;
[tex]2PO_{4} }^{3-} (aq) + 3Ba^{2+ } (aq) ------- > Ba_{3} (PO_{4})_{2} (s)[/tex]
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How do you solve the decomposition of aluminum oxide?
Aluminum Oxide decomposes to Aluminum metal and Oxygen gas.
- First, write down each compound:
[tex]Al_2O_3\longrightarrow Al+O_2[/tex]- Second, write the number of moles of each compound, so that we have the same amount of reactants as products. Here, it is important not to change the subscript of compound elements.
For example, let's start by adding a number 2 in front of the aluminum metal to balance:
[tex]Al_2O_3\text{ }\rightarrow2Al+O_2[/tex]So far, the amount of aluminum has been balanced but the amount of oxygen is unbalanced, so let's add a number 3 for the oxygen gas.
[tex]Al_2O_3\text{ }\rightarrow2Al+3O_2\text{ }[/tex]Now, to have the same amount of moles of oxygen on both sides, let's put a number 2 in the aluminum oxide:
[tex]2Al_2O_3\text{ }\rightarrow2Al+3O_2[/tex]Here, the amount of aluminum moles is unbalanced, so we add a number 4 for the aluminum metal to balance:
[tex]2Al_2O_3\text{ }\rightarrow4Al+3O_2[/tex]- This is the final balanced equation of decomposition of aluminum oxide:
[tex]\begin{gathered} 2Al_2O_3\text{ }\rightarrow4Al+3O_2 \\ \end{gathered}[/tex]How is percent composition related to alkene stability?
The stability of alkene can be determined by measuring the amount of energy that is associated with the hydrogenation of the molecule.
What is alkene stability?Because those branched alkanes are more stable than their linear isomers (Figure 1), the origins of this stability are unclear. For each branch in an alkane, the measured heat of formation is lower than expected by about 2 kcal mol−1 in comparison to the linear isomer. The fullness structures in which all atoms have complete valence shells are more stable. The structures with the least number of ritual charges are more stable. The structures with a negative charge on the further electronegative atom will be more stable. The three main factors determining the relative stability of alkenes are i) the number of substituents attached to the double-bond carbon atoms, ii) hyperconjugation, and iii) the stereochemistry of the double bond.
So we can conclude that the more electron-donating alkyl groups are the more stable the alkene
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Which two types of information are written in an element's box in the periodic
table?
A. Atomic mass
B. Number of electron shells
C. Nuclear composition
D. Chemical symbol
Answer:
b d my good mannnnnnnnnnnn
Light below the necessary critical frequency doesn't eject electrons from metal because
Light below the necessary critical frequency doesn't eject electrons from metal because no electrons will be emitted when the light shines on the metal.
What is Frequency?This is a term in physics which is used to describe the number of occurrences of a repeating event per unit of time.
The amount of energy which is present in each photon in the beam is determined by and proportional to the frequency of the beam. This therefore means that if there is light which is below the threshold frequency, there will be no electrons emitted when light shines on the metal thereby making it the correct choice.
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