Calculate the (H3O+) for a solution whose pH is 6.79



Note: blank 1 should have three significant figures



The answer is: Blank 1 X 10^Blank 2

Answers

Answer 1

Answer:

Explanation:

alculate the (H3O+) for a solution whose pH is 6.79

Note: blank 1 should have three significant figures

The answer is: Blank 1 X 10^Blank 2

Answer 2

The pH of a solution is the negative logarithm of H₃O⁺ ion concentration.The concentration of H₃O⁺ ions in a solution with a pH of 6.79 is 1.6 × 10⁻⁷M.

What is pH ?

pH of a solution is the measure of its acidity or basicity. Mathematically it is the negative logarithm of its  H₃O⁺ ion concentration. A solution with a pH of 7 is neutral.

The solution with a pH below 7 is acidic and above 7 is basic. Thus, the higher H+ ion concentration, then the pH will be lower and more acidic the solution.

It is given that the pH of the solution is 6.79. The concentration of  H₃O⁺ ions in the solution is calculated is calculated as follows:

pH   = -log ( H₃O⁺)

6.79 = -log( H₃O⁺

[ H₃O⁺] = antilog (-6.79)

             =  1.6 × 10⁻⁷M

Hence, the  hydronium ion H₃O⁺ ion concentration of the solution of pH 6.79 is  1.6 × 10⁻⁷M.

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Related Questions

When a sodium atom becomes an ion, the size of the atom
A
decreases by losing an electron,
B
decreases by gaining an electron,
с
increases by losing an electron,
D
increases by gaining an electron,

Answers

decreases by losing an electron

Sodium has an electron configuration of 2-8-1. Since sodium is a metal, it loses that one electron and becomes a positive ion. Since it is losing an electron, it is decreasing in size.

0.75 mol hydrogen sulfide (H2S)

Answers

Answer:

• Information and media literacy

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brief evaluation of your work.

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Answer: =378.94000053g

Explanation:

I think that explains it

(Squirrels gather and store acorns for the winter, which is an example of a ___________ adaptation.)

A. Mimicry

B. Behavioral

C. Structural

D. Environmental

Answers

Answer:

C

Explanation:


Why do we have to decide what to do in a day?

Answers

Answer:

otherwise you will be bord and have nothing to do

Explanation:

Because people like to keep busy/have things to do.

Otherwise, we would just be blobs and do nothing.

What does it mean that our solar system is about 25,000 light-years from the center of the Milky Way?(1 point) It took our solar system 25,000 light-years to form. It took our solar system 25,000 light-years to form. It would take about 25,000 years for light to travel from our solar system to the center of the Milky Way. It would take about 25,000 years for light to travel from our solar system to the center of the Milky Way. There are 25,000 stars between our solar system and the center of the Milky Way. There are 25,000 stars between our solar system and the center of the Milky Way. It would take 25,000 years for humans to fly, using a rocket ship, from our solar system to the center of the Milky Way.

Answers

Answer: A light year is a measure of distance, for example, there is a big comet 5 light years away, it takes 5 years for light to get to the comet, and just like the galaxy, it would take 25,000 years for light to reach the center of the galaxy.

write an equation to show the effect of heat on the nitrate of silver​

Answers

Answer:

2AgNO³(l) → 2Ag(s) + O²(g) + 2NO²(g)

Explanation:

I used powers ³,²,²

So change them to be down

What type of molecule is cis-2-pentene?
O A. Alkane
B. Alkyne
C. Branched alkane
D. Alkene

Answers

The given molecule, cis-2-pentene, is an Alkene. The correct option is D. Alkene

Saturated & Unsaturated Hydrocarbons

Alkanes, Alkenes, and Alkynes are examples of simple hydrocarbons.

Alkanes are the simplest organic compounds. They have only single bonds between carbon atoms and are called saturated hydrocarbons. Their nomenclature usually ends in -ane.

Alkenes on the other hand have at least one carbon-carbon double bond. Their nomenclature usually ends in -ene.

Alkynes have one or more carbon-carbon triple bonds.Their nomenclature usually ends in -yne. Alkenes and alkynes are called as unsaturated hydrocarbons.

The given molecule is cis-2-pentene

Since the name of the molecule ends in "ene", the molecule is an Alkene.

Hence, the given molecule, cis-2-pentene, is an Alkene. The correct option is D. Alkene

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Answer: Alkene

Explanation: just took tha test

what is the percent (mass/volume) if 22 g of kcl is added to 75 ml of water to make 83 ml of solution

Answers

Considering the definition of volume percentage, the mass/volume percent in this solution is 26.5%.

Definition of mass/volume percent

Mass/volume percent is a measure of concentration that indicates the number of grams of solute in each 100 mL of solution.

In other words, the volume percent of a component in the solution is defined as the ratio of the mass of solute that is present in a solution, relative to the volume of the solution, as a whole.

The volume percentage of a solution is determined by the following expression:

[tex]mass/volume percent=\frac{mass of solute}{volume of solution}100[/tex]

Mass/volume percent in the solution

In this case, you know:

mass of solute= 22 gvolume of solution= 83 mL

Replacing in the definition of mass/volume percent:

[tex]mass/volume percent=\frac{22 g}{83 mL}100[/tex]

Solving:

mass/volume percent= 26.5 %

Finally, the mass/volume percent in this solution is 26.5%.

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What is molarity of 47.0 g KCl dissolved in enough water to give 375 mL of solution?

Answers

This question provides us –

Weight of [tex] \bf KCl [/tex] is = 47 gVolume, V = 375 mL

__________________________________________

Molar Mass of [tex]\bf KCl [/tex] –

[tex]\qquad[/tex] [tex]\twoheadrightarrow\bf 39.0983 \times 35.453 [/tex]

[tex]\qquad[/tex] [tex]\twoheadrightarrow\bf 74.5513[/tex]

Using formula

[tex]\qquad[/tex] [tex]\purple{\twoheadrightarrow\bf Molarity _{(Solution)} = \dfrac{ W\times 1000}{MV}}[/tex]

[tex]\qquad[/tex] [tex]\twoheadrightarrow\bf Molarity _{(Solution)} = \dfrac{ 47 \times 1000}{74.5513\times 375}[/tex]

[tex]\qquad[/tex] [tex]\twoheadrightarrow\bf Molarity _{(Solution)} = \dfrac{47000}{27956.7375}[/tex]

[tex]\qquad[/tex] [tex]\twoheadrightarrow\bf Molarity _{(Solution)} = \cancel{\dfrac{47000}{27956.7375}}[/tex]

[tex]\qquad[/tex] [tex] \twoheadrightarrow\bf Molarity _{(Solution)} = 1.68117M [/tex]

[tex]\qquad[/tex] [tex]\pink{\twoheadrightarrow\bf Molarity _{(Solution)} = 1.7M} [/tex]

Henceforth, Molarity of the solution is = 1.7M

___________________________________________

how many grams of lead II chloride are produced from the reaction of 15.3 g of NaCl and 60.8 gr of Pb(NO3)2?

Answers

The mass, in grams, of lead that will be produced from the illustrated reaction would be 71.47 grams

Stoichiometric reactions

From the balanced equation of the reaction:

Pb(NO3)2 + 2NaCl ---> PbCl2 + 2NaNo3

Mole ratio of Pb(NO3)2 and NaCl = 1:2

Mole of 15.3 g NaCl = 15.3/58.4

 = 0.257 moles

Mole of 60.8 g PbCl(NO3)2 = 60.8/331.2

  = 0.184 moles

Thus, NaCl is limiting.

Mole ratio of NaCl to PbCl2 = 1:1

Mas of 0.257 moles PbCl2 = 0.257 x 278.1

 = 71.47 grams

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9. Using the balanced equation from Question #8, how many grams of lead will be produced if 2.54 grams of PbS is burned with 1.88 g of O2? Express your answer to the correct number of significant figures and you must show all work in the form of dimensional analysis as shown in Lesson 4. (Hint: be sure to work the problem with both PbS and O2).

Answers

Answer: 2.24 grams of Pb

Explanation:

Step 1

Balanced chemical reaction;

2PbS + 3O2 → 2Pb + 2SO3

Step 2

Moles of both PbS and O2

Moles = mass / molar mass

Moles of PbS = 2.54 g / 239.3 g/mol = 0.0108 moles

Moles of O2 = 1.88 / 32 g/mol = 0.0588 moles

Step 3

Finding the limiting reactant.

Limiting reactant, is that reactant which is completely used in the reaction;

If we assume that PbS is the limiting reactant;

We have 0.0588 moles of O2. This needs ( 0.0588 * 2) / 3 = 0.0392 moles of PbS to fully react. But we have only 0.0108 moles of PbS available. That means that the PbS will be completely consumed hence the limiting reactant

If we assume O2 is the limiting reactant;

We have 0.0108 moles of PbS. That needs ( 0.0108 * 3) / 2 = 0.0162 moles of O2. But we have 0.0588 moles of O2 which is in excess further confirming that PbS is the limiting reactant since it will be depleted in the reaction.

Step 4

Moles of lead

For this step we apply the mole ratios with the limiting reactant;

Mole ratio of PbS : Pb = 2 : 2 = 1 : 1

Therefore;

Moles of Pb = (0.0108 moles  * 1 ) 1

Moles of Pb =0.0108 moles

Step 5

Mass of Pb

Mass = moles * molar mass

Mass of Pb =0.0108 moles * 207.2 g/mol

Mass of Pb = 2.24 grams

Identify the independent /manipulated variable

Answers

Answer:

independent- test variable

manipulated - outcome variable; if needed, there could be changes.

Explanation:

knowledge

Determine which reaction has the highest activation energy.
A. Burning charcoal
B. Melting ice
C. Combusting gasoline
D. Reacting metal and acid

Answers

Answer:

A.

Explanation:

one revolution of the moon around earth takes_______ days.

Answers

Answer:It’s important to know WHY. Great explanations are what makes Brainly awesomeExplain everything. Imagine that the person who was asking, knows nothing at all so you need to start from the very beginningAlways include the steps and/or background required to get to the final answer. Let’s help other people understand and solve future problems on their ownShow all the calculation if it is a numerical question.

Explanation:

73.5 mol of P4O10 contains how many moles of P ? moles of P:

Answers

Answer:

294 moles of P

Explanation:

For every 1 mol of P4O10 contains 4 mol of P

so;

73.5 mol P4O10 × 4 mol P

1 mol P4O10

= 73.5 × 4

= 294 moles of P

73.5 mol of [tex]P_4O_{10}[/tex] contains 294 moles of P. In 1 mole of [tex]P_4O_{10}[/tex], there are 4 moles of P.

The International System of Units (SI) uses the mole (abbreviated as mol) as its basic unit to measure the amount of a substance. It is mostly used in chemistry and is defined as the volume of a substance that contains exactly 12 grammes of pure carbon-12 in terms of atoms (or equivalent amounts of molecules, ions, or particles). The fundamental notion that atoms combine in whole-number ratios to form compounds serves as the foundation for the concept of the mole. It makes it simple for scientists to convert between a substance's mass and the quantity of atoms or molecules it contains.

In 1 mole of [tex]P_4O_{10}[/tex], there are 4 moles of P.

=4 × 73.5 moles of P.

= 294 moles of P

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how do the parts of the liverworts above the soil get the minerals from the soil that are needed for plant processes

Answers

Answer:

I don't know but I'm curious now

What type of reaction is 2NaBr+Cl2-NaCl+Br2

Answers

Answer:

An anionic single replacement reaction.

Explanation:

Hope this helps!!!

Answer:

Substitution or Displacement maybe?

Select the correct answer.
Iron oxide reacts with aluminum to give aluminum oxide and iron. What kind of chemical reaction is this?

Answers

Answer:

Single-replacement reaction

Explanation:

Single-replacement reactions, aka. single-displacement reactions, involve one element/ion in a compound being replaced by another element/ion. In this case, aluminum is replacing the iron in the compound.

If you need help visualizing, the equation looks like this:

FeO + Al³⁺ --> AlO + Fe³⁺

An atom with more electrons than protons has an overall positive charge and is called a
positive ion

Answers

That is correct! It is a positive ion!


If 1.76 g of an ideal gas occupy 1.0 L at standard temperature and pressure (STP), what is the molar mass of the gas?

Answers

Answer:

Explanation:

Whenever you see molar masses in gas law questions, more often than not density will be involved. This question is no different. To solve this, however, we will first need to play with the combined ideal gas equation PV=nRT to make it work for density and molar mass. The derivation is simple but for the sake of time and space, I will skip it. Hence, just take my word for it that you will end up with the equation:M=dRTPM = molar mass (g/mol)d = density (g/L)R = Ideal Gas Constant (≈0.0821atm⋅Lmol⋅K) T = Temperature (In Kelvin) P = Pressure (atm)As an aside, note that because calculations with this equation involve molar mass, this is the only variation of the ideal gas law in which the identity of the gas plays a role in your calculations. Just something to take note of. Back to the problem: Now, looking back at what we're given, we will need to make some unit conversions to ensure everything matches the dimensions required by the equation:T=35oC+273.15= 308.15 KV=300mL⋅1000mL1L= 0.300 LP=789mmHg⋅1atm760mmHg= 1.038 atmSo, we have almost everything we need to simply plug into the equation. The last thing we need is density. How do we find density? Notice we're given the mass of the sample (0.622 g). All we need to do is divide this by volume, and we have density:d=0.622g0.300L= 2.073 g/LNow, we can plug in everything. When you punch the numbers into your calculator, however, make sure you use the stored values you got from the actual conversions, and not the rounded ones. This will help you ensure accuracy.M=dRTP=(2.073)(0.0821)(308.15)1.038= 51 g/molRounded to 2 significant figuresNow if you were asked to identify which element this is based on your calculation, your best bet would probably be Vandium (molar mass 50.94 g/mol). Hope that helped :) 

why are hydrocarbons insoluble in water

Answers

Answer:

Hydrocarbons are insoluble in water because they are non-polar compounds while water is a polar solvent. By principle, like dissolves like. Nonpolar solvents dissolve nonpolar solutes and polar solvents dissolve polar solutes.

Explanation:

please brainliest me

hope it helps

Hydrocarbons are insoluble in water because :-

1)Hydrocarbons are nonpolar whereas water is polar. (like dissolves like).

2) Hydrocarbons and water do not exhibit appropriate solvent-solute interactions. Hydrocarbons only form very weak dispersion forces whereas water produces strong polar hydrogen bonding interactions.

Explanation:

Hope it helps you!!

A buffer was prepared containing 0.50 M formic acid (HCOOH) and 0.50 M sodium formate (NaCOOH). The Ka of formic acid is 1.7 x 10-4. What will be the pH after 0.010 mol of NaOH(s) is added to 100.0 mL of the buffer

Answers

For a buffer that was prepared contain 0.50 M formic acid (HCOOH) and 0.50 M sodium formate (NaCOOH). the pH is mathematically given as

pH=3.95

What is the pH after 0.010 mol of NaOH(s) is added to 100.0 mL of the buffer?

Generally, the equation for the Hendersons equation   is mathematically given as


pH=pKa+log(SALT)/(ACID)

Where

moles of  (NaCOOH)=100*0.05/1000

moles of  (NaCOOH)=0.05moles

and  formic acid

moles of formic acid=100*0.05/1000

moles of  formic acid=0.05moles

Therefore

pKa=-logka

pKa=1.4*10*3.77

pH=3.77+log{0.06/0.04}

pH=3.95

In conclusion, the pH is

pH=3.95

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explain how sound is produced and travel from one place to another.​

Answers

Answer:

vibration of particles...........

A compound is 69.9% Fe and 30.1% O. What is the empirical formula?

Answers

Answer:

Fe2O3

Explanation:

get the ratio for both Fe and O using relative atomic mass and the percent as the mass

A 0.205 g sample of CaCO3 (Mr = 100.1 g/mol) is added to a flask along with 7.50 mL of 2.00 M HCl. CaCO3(aq) + 2HCl(aq) → CaCl2(aq) + H2O(l) + CO2(g)Enough water is then added to make a 125.0 mL solution.

Answers

The volume of the NaOH used is calculated as 14 mL.

What is stoichiometry?

The term stoichiometry has to do with the calculation of the amount of substance in a reaction using mass - mole or mass - volume relationship.

Here;

Number of  moles of CaCO3 = 0.205 g/100.1 = 0.00205 moles

Number of  moles of HCl = 2.00 M * 7/1000 L = 0.014 moles

2 moles of HCl reacts with 1 mole of CaCO3

x moles of HCl reacts with 0.00205 moles of CaCO3

x = 0.00205 moles * 2/1 = 0.0041 moles

Hence HCl is the excess reactant

Amount of excess HCl =  0.014 moles -  0.0041 moles = 0.0099 moles

Concentration of excess HCl reacted = 0.0099 moles/125 * 10^-3 = 0.0792 M

Using;

CAVA/CBVB = NA/NB

CAVANB = CBVBNA

VB = CAVANB/CBNA

VB = 0.0792 M * 10 mL * 1/ 0.058 M

VB = 14 mL

Missing parts;

A 0.205 g sample of caco3 (mr = 100.1 g/mol) is added to a flask along with 7.50 ml of 2.00 m hcl. caco3(aq) + 2hcl(aq) → cacl2(aq) + h2o(l) + co2(g) enough water is then added to make a 125.0 ml solution. a 10.00 ml aliquot of this solution is taken and titrated with 0.058 m naoh. naoh(aq) + hcl(aq) → h2o(l) + nacl(aq) how many ml of naoh are used?

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The volume of a gas is 3.0 L, the pressure is 1.0 atm, and the temperature is 300 K. A chemist changes one factor while keeping another constant so that the new volume is 2.0 L. Which of the following could be the new conditions?

Group of answer choices

The final pressure is 0.5 atm, while temperature is kept constant.

The final temperature is 200 K, while pressure remains constant.

The final pressure is 0.2 atm, while temperature is kept constant.

The final temperature is 350 K, while pressure remains constant.

Answers

Given the data from the question, the final temperature is 200 K, while pressure remains constant.

Basic concepts

To obtain the correct answer to the question, we shall consider two conditions:

Case 1 (temperature is constant) Case 2 (pressure is constant)

Case 1 (Temperature is constant)

We shall determine the new pressure by using the combined gas equation (P₁V₁ / T₁ = P₂V₂ / T₂) as illustrated below:

Initial volume (V₁) = 3 LInitial pressure (P₁) = 1 atmTemperature = constant New Volume (V₂) = 2 L New pressure (P₂) =?

P₁V₁ / T₁ = P₂V₂ / T₂

Since temperature is constant, we have:

P₁V₁ = P₂V₂

3 × 1 = P₂ × 2

3 = P₂ × 2

Divide both side by 2

P₂ = 3 / 2

P₂ = 1.5 atm

Case 2 ( pressure is constant)

We shall determine the new temperature by using the combined gas equation (P₁V₁ / T₁ = P₂V₂ / T₂) as illustrated below:

Initial volume (V₁) = 3 LInitial pressure (T₁) = 300 KPressure = constant New Volume (V₂) = 2 L New pressure (T₂) =?

P₁V₁ / T₁ = P₂V₂ / T₂

Since pressure is constant, we have:

V₁ / T₁ = V₂ / T₂

3 / 300 = 2 / T₂

1 / 100 = 2 / T₂

Cross multiply

T₂ = 100 × 2

T₂ = 200 K

SUMMARY

when the temperature is constant, the new pressure is 1.5 atmWhen the pressure is constant, the new temperature is 200 K

From the calculations made above, we can conclude that the correct answer is:

The final temperature is 200 K, while pressure remains constant.

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Answer:

b

Explanation:

Which of the following mainly drives surface runoff?
A. magnetism
B. gravity
C. electricity
D. thermal energy​

Answers

I think its D. I hope this helped
The answer is Either C or D. Sorry if I’m wrong!

the ability of atoms to attract electrons from surrounding atoms is called

Answers

Answer:

Electronegativity

Explanation:

The ability of an atom to attract itself an electron pair shared with another atom in a chemical bond.

Which would lower the reaction rate?

A. Increasing the concentration of reactants.

B. Increasing the temperature of the system.

C. Raising the value of k.

D. Decreasing the temperature of the system.

Answers

Answer:

D. Decreasing the temperature of the system

Explanation:

Oxidation Number of Carbon in C6H12O6​

Answers

Correct option is C)

C

6

H

12

O

6

6x+12−12=0

C has oxidation number = 0

Sorry if my answers wrong.

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