x = 8, y = 21
Explanations:The given equation is:
y = 4x - 11 = x + 13
This can be splitted into two equations as:
y = 4x - 11..........(1)
y = x + 13..........(2)
Substitute equation (1) into equation (2)
4x - 11 = x + 13
4x - x = 13 + 11
3x = 24
x = 24/3
x = 8
Substitute the value of x into equation (1)
y = 4x - 11
y = 4(8) - 11
y = 32 - 11
y = 21
x = 8, y = 21
event a is the event that randomly selected students from your school is make event b is the event that randomly selected students from your school owns a bicycle which of the following do we know for certain correctly represents the probability of selecting a male students or selecting a student who owns a bicycle
The or probability in the context of this problem is represented as follows:
P(A U B).
Or probabilityThe or probability between two events A and B is the probability that at least one of the events happen.
The symbol of the or probability is given as follows:
U
In the context of this problem, the events are given as follows:
Event A: a randomly selected student is male.Event B: a randomly selected student owns a bike.Hence the probability of selecting a male students or selecting a student who owns a bicycle is represented as follows:
P(A or B) = P(A U B).
The other options are as follows:
P(A ∩ B): both male and own bike, representing the intersection operation of the events.P(A): male.P(B): own bike.Missing informationThe complete problem is given by the image at the end of the answer.
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Find an equation in standard form of the parabola passing through the points. (2,-20),(-2,-4), (0, -8)
The equation of a parabola in standard form is
[tex]y\text{ }=ax^2\text{ + bx + c}[/tex]So, we have the following equations,
For ( 2, -20) , -20 = a(2)^2 + b (2) + c,
For (-2, -4), -4 = a( -2)^2 + b (-2) + c,
For (0.-8), -8 = a (0) + b (0) + c
Then solving,
4a + 2b + c = -20 .............. equ 1
4a - 2b + c = -4 ................... equ 2
c= -8
put c= -8 in equ 1,
we have
4a + 2b -8 = -20 = 4a + 2b = -12 ------equ 3
put c= -8 in equ 2,
4a - 2b -8 = -4 = 4a - 2b = 4................... equ 4
Solving equ 3 and equ 4, a= -1 , b= -4
so a =-1, b= -4, c= -8
Then substituting the values in
[tex]y=ax^2\text{ + bx + c}[/tex][tex]y=-1(x^2)\text{ + -4(x) + }(-8)[/tex]
So, y= -x^2 -4x-8
Translate to system Grandpa and Grandma are treating their family to the movies. Matineetickets cost $4 per child and $4 per adult. Evening tickets cost $6 per childand $8 per adult. They plan on spending no more than $80 on the matineetickets and no more than $100 on the evening tickets.
Answer:
4x + 4y ≤ 80
6x + 8y ≤ 100
Explanation:
Let's define x as the number of children and y as the number of adults.
For Matinee tickets, they spend $4 per child and $4 per adult, so if the total is no more than 80, we get:
4x + 4y ≤ 80
In the same way, they spend $6 per child and $8 per adult on the evening tickets, so
6x + 8y ≤ 100
Therefore, the system is
4x + 4y ≤ 80
6x + 8y ≤ 100
How is this wrong can someone explain, and what is the correct answer
Answer:
Step-by-step explanation:
find and classify the global extrema of the following function
f(x)=(x-2)^2+5
compute the critical points of (x-2)^2+5
to find all critical points, first compute f(x)
f(x)=2(x-2)
solving 2(x-2)=0 yields x=2
x=2
f(x) exists everyhere
2(x-2) exists everyhere
the only critical point of (x-2)^2+5 is at x=2
x=2
the domain of (x-2)^2+ 5 is R
the endpints of R are x = -∞ and ∞
Evalute (x-2)^2+5 at x = -∞, 2 and ∞
the open endpoints of the domain are marked in gray
x () f(x)
-∞ ∞
2 5
∞ ∞
the largest value corresponds to a global maximum, and the smallest value corresponds to a global minimum:
the open endpoints of the domain are marked in gray
x () f(x) extrema type
-∞ ∞ global max
2 5 global min
∞ ∞ global max
remove the points x = -∞ and ∞ from the table
These cannot be global extrema, as the value of f(x) here is never achieved
x () f(x) () extrema type
2 5 global min
f(x) = (x-2)^2+5 has one global minimum
Answer:
f(x) has a global minimum at x = 2
Answer:
Step-by-step explanation:
What is the coordinate point location of the y-intercept of the graph below?
The y-intercept is located at the coordinate (0, 4) as shown below. Y-intercept is the point where a line or a graph crosses the y-axis.
Which of the following systems of equations is an example of one where elimination is the best method?A) {y=27x+11 {3x−4y=−24 B) {4x+5y=20 {−4x+6y=24 C) {y=13x+15 {2x−2y=18 D) {x = 11 {y = -8
Answer:
Explanation:
When solving a system of equations, the elimination method is best used when the system is given in such a way that the coefficients of one variable can be eliminated by addition or subtraction.
Of the given system of equations, the example of where elimination is the best method is:
[tex]\begin{gathered} 4x+5y=20 \\ -4x+6y=24 \end{gathered}[/tex]In this example, we see that the variable 'x' can be directly eliminated by adding the two equations.
The correct option is B.
May you hello me and why did yall start making people pay?
Answer:
53.76
Explanation:
The volume of the triangular prism is given by
[tex]V=\frac{1}{2}\cdot h\cdot b\cdot l[/tex]where h is the height, b is the base, and l is the length of the prism.
Now in our case h = 3.2 m, b = 4.8 m, and l = 7m; therefore, the above equation gives
[tex]V=\frac{1}{2}\cdot3.2\cdot4.8\cdot7[/tex][tex]V=53.76\: m^3[/tex]which is our answer!
Hence, the volume of the triangular prism is 53.76 cubic meters.
if AC equals x + 3 and DB equals 3x - 19 find a CFA E equals 3x + 3 + E C equals 5x - 15 find a c d equals 50x - 7 + 80 equals 4x + 9 find DB
2) If DB = 27 the we can replace that:
[tex]27=3x-19[/tex]and we can solve for x
[tex]\begin{gathered} 3x=27-19 \\ 3x=8 \\ x=\frac{8}{3} \end{gathered}[/tex]now we can replace x in the equation for AC:
[tex]\begin{gathered} AC=x+3 \\ AC=\frac{8}{3}+3 \\ AC=\frac{8}{3}+\frac{9}{3} \\ AC=\frac{17}{3} \end{gathered}[/tex]3) we have that:
[tex]\begin{gathered} AE=3x+3 \\ EC=5x-15 \end{gathered}[/tex]So the segment AC will be the sum of the segments:
[tex]\begin{gathered} AC=AE+EC \\ AC=3x+3+5x-15 \\ AC=8x-12 \end{gathered}[/tex]and we also know that
[tex]\begin{gathered} x=\frac{8}{3} \\ \text{then} \\ AC=\frac{64}{3}-\frac{36}{3} \\ AC=\frac{28}{3} \end{gathered}[/tex]3) we have that:
[tex]\begin{gathered} DE=6x-7 \\ AE=4x+6 \end{gathered}[/tex]Break apart ones to add 18+5=
Answer: 23
Step-by-step explanation:
You have 1 ten and 8 ones + 5 ones. First, add the ones to get 13 ones. Then, split the ones into tens and ones to get 2 tens and 3 ones which is 23.
Find the x - and y -intercepts of the graph of the linear equation -6x + 9y = -18
Someone else got x=(3,0) y=(0,-2) but it was wrong
Answer:
x-intercept = 3y-intercept = -2Step-by-step explanation:
You want the intercepts of the equation -6x +9y = -18.
InterceptsThere are several ways to find the intercepts. In each case, the x-intercept is the value of x that satisfies the equation when y=0, and vice versa.
For y = 0, we find the x-intercept to be ...
-6x + 0 = -18
x = -18/-6 = 3
The x-intercept is 3; the point at that intercept is (3, 0).
For x = 0, we find the y-intercept to be ...
0 +9y = -18
y = -18/9 = -2
The y-intercept is -2; the point at that intercept is (0, -2).
Intercept formThe intercept form of the equation for a line is ...
x/a +y/b = 1
where 'a' is the x-intercept, and 'b' is the y-intercept.
We can get this form by dividing the original equation by -18.
-6x/-18 +9y/-18 = 1
x/3 +y/(-2) = 1
The x-intercept is 3; the y-intercept is -2.
__
Additional comment
When asked for the intercepts, it is sometimes not clear whether you are being asked for the value where the curve crosses the axis, or whether you are being asked for the coordinates of the point there.
Your previous "wrong" answer was given as point coordinates. Apparently, just the value at the axis crossing is required.
You have to have some understanding of your answer-entry and answer-checking software to tell the required form of the answer (or you can ask your teacher).
<95141404393>
Help I have use the calculator in degree mode for this problem
SOLUTION
The figure above consists of a triangle and a semi-circle.
Area of the figure = Area the of triangle + Area of the semi-circle
[tex]\begin{gathered} \text{Area of triangle = }\frac{1}{2}\times base\text{ }\times height\text{ } \\ \text{base of the triagle = 15 ft} \\ \text{height = }15\text{ ft } \\ \text{Area of triangle = }\frac{1}{2}\times15\text{ }\times15 \\ \text{Area of triangle = 112.5 ft}^2 \end{gathered}[/tex][tex]\begin{gathered} \text{Area of the semi circle = }\frac{1}{2}\times\pi r^2 \\ r,\text{ radius = }\frac{diameter}{2}\text{ = }\frac{15}{2}\text{ = 7.5} \\ \text{Area of semi-circle = }\frac{1}{2}\times3.14\times7.5^2 \\ \text{Area of semi-circle = }\frac{1}{2}\text{ }\times3.14\times56.25\text{ = 88.3125} \end{gathered}[/tex]Area of composite figure = 112.5 + 88.3125 = 200.8125
Therefore the Area of the figure = 200.81 squared feet to the nearest hundredth
WHAT IS THE CHEAPEST UNIT RATE??? 10 donuts for 13.00 or 1 dozen donuts for 12.00
Step 1: Let's review the information provided to us to answer the question correctly:
• Option 1: 10 donuts for 13.00
,• Option 2: 1 dozen donuts for 12.00
Step 2: Let's calculate the price of a donut in each option, as follows:
• One donut Option 1 = 13/10 = 1.30, this means the price of an individual donut is $ 1.30
,• One donut Option 2 = 12/12 = 1, this means the price of an individual donut is $ 1
Step 3: Twitch Beast 8 will decide what is the cheapest unit rate based on the calculations we did on Step 2
what is 503472 rounded to the nearest thousend
Answer: 503,000
Step-by-step explanation:
The best way to understand the concept is to look at a round to the nearest thousand example: what is 52437 rounded to the nearest thousand?
As the hundredth digit is 4, which is less than 5, the number should be rounded down to 52000. As for 52678, as the hundredth digit is 6, which is larger than 4, it will be rounded up to 53000.
Determine the period
I hate acellus
Answer:
my answer i got is y=2x+9
Answer:
5
Step-by-step explanation:
They are asking for the Period. The Period goes from one peak to the next (or from any point to the next matching point). To me it looks like that value is 5 for this graph.
A washer and a dryer cost $765 combined. The washer costs $85 less than the dryer. What is the cost of the dryer?
The equation is formed and solved below
What is an equation?
Algebra is concerned with two types of equations: polynomial equations and the particular case of linear equations. Polynomial equations have the form P(x) = 0, where P is a polynomial, while linear equations have the form ax + b = 0, where a and b are parameters, when there is only one variable. To solve equations from either family, algorithmic or geometric approaches derived from linear algebra or mathematical analysis are used. Algebra also investigates Diophantine equations with integer coefficients and solutions. The approaches employed are unique and derive from number theory. In general, these equations are complex; one frequently searches just for the existence or lack of a solution, and, if they exist, the number of solutions.
Let the price of washer = $x
The cost of dryer = $x+85
The equation is formed as
x + x + 85 = 765
or, 2x = 765 - 85
or, x = 680/2 = 340
Price of dryer = $(340+85) = $425
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This problem is related to the linear equation and the required cost of the dryer is $425.
What is a linear equation?
If a variable's maximum power is always 1, an equation is said to be a linear equation. As a one-degree equation, it also goes by that name.
Let a washer costs be [tex]w[/tex] and a dryer costs be [tex]d[/tex].
Since the total cost of a washer and a dryer is $765, it follows:
[tex]w+d=765[/tex] ... (1)
Further, it is given that the washer costs $85 less than the dryer, it means that:
[tex]w=d-85[/tex] ... (2)
Using the two linear equations (1) and (2), it follows:
[tex]d-85+d=765\\2d-85=765\\2d=765+85\\2d=850\\d=\frac{850}{2}=425[/tex]
Therefore, the cost of a dryer is $425.
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I survey found that 43 people like chocolate 39 people like peanut butter and 29 people like both draw an empty van diagram with intersections find how many people like only chocolate only peanut butter and both show your work fill in the V diagram according your numbers Calculate how many people are in the survey
Given:
There are 43 people who like chocolate 39 people like peanut butter and 29 people like both.
To draw: The ven diagram
Explanation:
Since 29 people like both chocolate and peanut butter.
Therefore,
The number of people who like chocolate only is,
[tex]43-29=14[/tex]The number of people who like peanut butter only is,
[tex]39-29=10[/tex]So, the total number of persons is,
[tex]14+29+10=53[/tex]The ven diagram is,
Where C represents the chocolate likers, B represents the peanut butter likers and U represents the total number of persons.
Final answer:
• The number of people who like chocolate only is 14.
,• The number of people who like peanut butter only is 10.
,• The total number of people is 53.
what digit is in the
Let:
Mp = Marked price = $310
r = Rate of discount = 20% = 0.2
D = Discount
Sp = Sale price
The discount will be given by:
[tex]\begin{gathered} D=r\cdot Mp \\ D=0.2\cdot310 \\ D=62 \end{gathered}[/tex]And the sale price will be:
[tex]\begin{gathered} Sp=Mp-D \\ Sp=310-62 \\ Sp=248 \end{gathered}[/tex][tex]4(2 \times - 1) \ \textless \ (4 \times - 3)[/tex]That is the Math problem
How many radians are equal to 360 degrees 2 2pi 1 Pi
Answer:
2pi
Explanation:
By definition, 360 degrees are equal to 2π radians.
This follows from the fact that the circumference of a circle is 2π times the radius. Therefore, if radius = 1, then
circumference = 2π
Since the circumference is the distance around a circle, and degrees are the "angular distance " around the circle, these two quantities can be related.
So if you think of the circle in terms of the circumference, a circle measures 2π. If you think in terms of degrees, a circle measures 360 degrees.
Therefore, we say
360 degrees = 2π (radians)
The composition of functions
Answer: g(f(5)) = 352
Step-by-step explanation:
The question being asked is the same as finding g(f(5)).
What this means is to find f(5), and then plug that value into g(x) as x and solve.
f(5) = 4(5) + 1 = 20 + 1 = 21
g(f(5)) = g(21) = 21^2 - 4(21) - 5 = 441 - 84 - 5 = 357 - 5 = 352
Note: You could also find g(f(x)), and then plug 5 in as x and solve.
Start by plugging f(x) into g(x) such that you get g(x = f(x))
g(f(x)) = (4x + 1)^2 - 4(4x + 1) - 5
Now, replace x with 5 and solve to get g(f(5)).
g(f(5)) = (4(5) + 1)^2 - 4(4(5) + 1) - 5 = 352
1 What is the volume of a triangular pyramid with thesame base and height dimensions of the prism below?5.5 in.13 in.7 in.
volume of a triangular pyramid = 1/3 * base area (triangle) *height
triange area= 1/2 base * height
triegle area= 1/7 in * 5.5 in = 38.5 in^2
Volume = 1/3 * 38.5 in^2 * 3 in
Volume = 38.5 in^3
___________________
Answer
choice b)
Determine the x-intercept for 3x + 2y = 14.A) (7,0) B) (0,7) C) (14/3,0) D) (0,14/3)
By definition, when the line intersects the x-axis, the value of "y" is:
[tex]y=0[/tex]Knowing this, you can substitute that value of "y" into ithe equation given in the exercise:
[tex]\begin{gathered} 3x+2y=14 \\ 3x+2(0)=14 \end{gathered}[/tex]Now you must solve for the variable "x" in order to find the x-intercept. This is:
[tex]\begin{gathered} 3x+0=14 \\ 3x=14 \\ x=\frac{14}{3} \end{gathered}[/tex]Then, you get this point:
[tex](\frac{14}{3},0)[/tex]The answer is: Option C.
Triangle CHE Is drawn below. What is the measure of y in the diagram?* I 2 meters 3 meters O 12 meters 6 meters None of the above
The given triangles are similar to each other, this means that we can get the length of the sides of the larger triangle by multiplying the corresponding lengths of the smaller one by a scale factor.
We can get the scale factor by dividing the length of one of the sides of the larger triangle by the length of the corresponding side in the smaller triangle, like this:
By taking the left sides
[tex]s=\frac{8}{4}[/tex]Then, in order to get the length of the base of the larger triangle (6), we just have to multiply the length of the base of the smaller triangle (y) by the scale factor (2), like this:
6 = 2×y
From this equation, we can solve for y to get:
2y = 6
2y/2 = 6/2
y = 3
Then, y equals 3 meters
I need an quadratic equation with -3 and 6 for this assignment
If a quadratic equation has solutions
[tex]x=a,x=b[/tex]Then
[tex]x-a=0\text{ and x-b=0}[/tex]Furthermore, the quadratic can be written as
[tex]\begin{gathered} y=(x-a)(x-b) \\ where,y=0 \end{gathered}[/tex]Therefore,
[tex](x-a)(x-b)=0[/tex]Given:
[tex]a=-3,b=6[/tex]Hence,
[tex]\begin{gathered} (x--3)(x-6)=0 \\ (x+3)(x-6)=0 \end{gathered}[/tex]Simplify
[tex]\begin{gathered} x(x-6)+3(x-6)=0 \\ x^2-6x+3x-18=0 \\ x^2-3x-18=0 \end{gathered}[/tex]Hence, the quadratic equation is
[tex]x^{2}-3x-18=0[/tex]choose the correct letter ( this is not being graded it is review )
we have the points
(-2,6) and (-3,-7)
step 1
Find out the slope
m=(-7-6)/(-3+2)
m=-13/-1
m=13
step 2
Find out the equation in slope-intercept form
y=mx+b
we have
m=13
point (-2,6)
substitute and solve for b
6=13(-2)+b
6=-26+b
b=32
therefore
y=13x+32
step 3
Convert to standard form
AX+By=C
y=13x+32
13x-y=-32 -------> is equivalent to -13x+y=32
therefore
the answer is option DWhich choices are equivalent to the quotient below check all that apply. square root of 16 over square root of 8
To solve the quotient below;
[tex]\frac{\sqrt[]{16}}{\sqrt[]{4}}[/tex]We simply both the numerator and the denominator as follows;
[tex]undefined[/tex]In 2011 Staci invested $13,000 in a savings account for her newborn son. The account pays 3.6% interest each year. Determine the accrued value of the account in the year 2029, when her son will go to college. Round your answer the nearest cent.In the year 2029, the accrued value will be $
To solve this problem, we can use the compound interest formula
[tex]A=P(1+\frac{r}{n})^{nt}[/tex]Where A represents the accrued value, P represents the invested value, r represents the interest(in decimals), n represents the amount of times the interest is compounded per unit 't' and t represents the time.
Since the unit of the time 't' is years, and the interest is compounded yearly, n = 1.
To write a percentage as a decimal, we just have to divide the percentage value by 100.
[tex]3.6\%=0.036[/tex]To find the amount of time t, we just have to subtract the year the money was invested from the year we want to know the money accrued.
[tex]t=2029-2011=18[/tex]Then, using those values on the formula, we have
[tex]\begin{gathered} A=13,000(1+0.036)^6 \\ A=16073.1828298\ldots\approx16073.18 \end{gathered}[/tex]The accrued value in the year 2029 will be $16,073.18.
Find all real and imaginary solutions to the equation. Please help me tyy
Real solutions = 4/5 and 3
Imaginary solutions = 3i
Define real and imaginary solutions.The quadratic equation x² + 1 = 0 has a solution in the imaginary unit or unit imaginary number I Although there isn't a real number associated with this attribute, addition and multiplication can be employed to expand real numbers to so-called complex numbers. A real number is the real root of an equation. A complex root is a fictitious root that is represented by complex numbers in an equation. Imaginary numbers are "real" in the sense that they exist and are used in mathematics, even though they are not real numbers because they cannot be defined on a number line. Complex numbers, often known as imaginary numbers, are used in quadratic equations and in real-world applications like electricity.
Given,
Equation
4x³ + 5x² + 36x + 45 = 0
x²(4x + 5) + 9( 4x + 5) = 0
x² + 9 + (4x +5) = 0
(x - 3 ) (x +3) + (4x+5) = 0
x = 3i
x = [tex]\frac{4}{5}[/tex] and 3
Real solutions = 4/5 and 3
Imaginary solutions = 3i
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please help :(Find the coordinates of the midpoint of HXH(4 1/2, -4 1/4) , X(2 3/4, -2 1/4)
To find the coordinates of the midpoint of HX, we would apply the midpoint formula which is expressed as
[tex]\text{Midpoint = }\lbrack\frac{(x1\text{ + x2)}}{2},\text{ }\frac{(y1\text{ + y2)}}{2}\rbrack[/tex]From the information given,
[tex]\begin{gathered} x1\text{ = 4}\frac{1}{2}\text{ = 4.5, x2 = 2}\frac{3}{4}=\text{ 2.75} \\ y1\text{ = -4}\frac{1}{2}=-4.5,\text{ }y2=-2\frac{1}{4}=\text{ - 2.25} \\ \text{Midpoint = }\lbrack\frac{(4.5\text{ + 2.75)}}{2},\text{ }\frac{(-4.5\text{ - 2.25)}}{2}\rbrack \\ \text{Midpoint = (3.625, - 3.375)} \end{gathered}[/tex]Select the table of values that contains ordered pairs that, when plotted, provide the best representation of the curve of the function
As given by the question
There are given that the equation:
[tex]y=-2(x+3)^2+4[/tex]Now,
Put the value of x into the given equation and find the value of y from all the tables one-by-one and match their value of x and y are equal or not.
Then,
Form the option third,
Put x = -2 to find the value of y, then match the value of y with the given value of y in the table.
So,
[tex]\begin{gathered} y=-2(x+3)^2+4 \\ y=-2(-2+3)^2+4 \\ y=-2(1)^2+4 \\ y=-2+4 \\ y=2 \end{gathered}[/tex]Now,
Put x = -1, then:
[tex]\begin{gathered} y=-2(x+3)^2+4 \\ y=-2(-1+3)^2+4 \\ y=-2(2)^2+4 \\ y=-2(4)+4 \\ y=-8+4 \\ y=-4 \end{gathered}[/tex]Then,
Put x = 0, then:
[tex]\begin{gathered} y=-2(x+3)^2+4 \\ y=-2(0+3)^2+4 \\ y=-2(3)^2+4 \\ y=-2(9)+4 \\ y=-18+4 \\ y=-14 \end{gathered}[/tex]Then,
Put 1 into the given equation instead of x:
So,
[tex]\begin{gathered} y=-2(x+3)^2+4 \\ y=-2(1+3)^2+4 \\ y=-2(4)^2+4 \\ y=-2(16)+4 \\ y=-32+4 \\ y=-28 \end{gathered}[/tex]And,
Put x = 2, so:
[tex]\begin{gathered} y=-2(2+3)^2+4 \\ y=-2(5)^2+4 \\ y=-2(25)+4 \\ y=-50+4 \\ y=-46 \end{gathered}[/tex]Now,
From option d, all values of x and y are matched also but curve representation is matched in option D.
Hence, the correct option is D.