carmen went on a trip of 120 miles, traveling at an average of x miles per hour. several days later she returned over the same route at a rate that was 5 miles per hour faster than her previous rate. if the time for the return trip was one-third of an hour less than the time for the outgoing trip, which equation can be used to find the value of x?

Using translation concepts, it is found that graph D represents the function f(x) = tan(x + 1).

A translation is represented by a change in the function graph, according to operations such as multiplication or sum/subtraction in it's definition.

The function f(x) = tan(x + 1) is a translation of one unit to the left of g(x) = tan(x), which has g(0) = 0, hence at the translated function g(-1) = 0, which means that graph D represents the function f(x).

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Answer:

Step-by-step explanation:

You want q and the probability of 3 successes in 8 trials if the probability of success is 0.45.

The value designated q is the complement of p, the probability of success.

  q = 1 -p

  q = 1 -0.45

  q = 0.55

The probability of 3 successes is ...

  P(3 of 8) = 8C3·p^3·q^(8-3) = 56·0.45^3·0.55^5

  P(3 of 8) ≈ 56°0.091125·0.050328 ≈ 0.256826

The probability of exactly 3 successes in 8 trials is about 0.2568.

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The sampling distribution of p is the distribution of all possible values of p that could be obtained from all possible samples of size n = 200i from the population with size N = 25 and population proportion p = 0.2.

To determine whether the sampling distribution of p is approximately normal, we need to check the conditions n <= 0.05N and [tex]np(1 - p)\geq 10[/tex].

Here, n = 200i and N = 25, so [tex]n\leq 0.05N[/tex] holds if and only if [tex]i\leq 0625[/tex].

Since i is a positive integer, the largest value that i can take is 1. Therefore, n = 200 is the maximum sample size that we can have.

Next, we need to check whether [tex]np(1 - p)\geq 10[/tex]. Substituting n = 200 and p = 0.2, we get np(1 - p) = 32, which is greater than or equal to 10. Therefore, this condition is also satisfied.

Hence, we can conclude that the sampling distribution of p is approximately normal because [tex]n\leq0.05N[/tex] and [tex]np(1 - p)\geq 10[/tex].

Therefore, the correct answer is option A: Approximately normal because and [tex]n\leq0.05N[/tex] and [tex]n_{D} (1 - p)\geq 10.[/tex].

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The probability that the randomly selected point is in the bullseye is 0.75, or 75%.

The area of the bullseye is the difference between the areas of the larger and smaller circles:

[tex]A = \pi r_1^2 - \pi r_2^2[/tex]

where [tex]r_1[/tex] is the radius of the larger circle (8 cm) and [tex]r_2[/tex] is the radius of the smaller circle (4 cm).

[tex]A = \pi(8^2 - 4^2)A = \pi(64 - 16)A = 48\pi[/tex]

The area of the entire target (both circles) is:

[tex]A = \pi r_1^2[/tex]

A = 64π

Therefore, the probability of selecting a point in the bullseye is:

P(bullseye) = A(bullseye) / A(target)

P(bullseye) = (48π) / (64π)

P(bullseye) = 3/4 or 0.75

So the probability that the randomly selected point is in the bullseye is 0.75, or 75%.

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A manufacturer of soap bubble liquid tests a new formula with a sample of 700 parisons. With a significance level of 0.05, the test results in a p-value of 0.206, leading to the conclusion that the new formula can be approved since the proportion of defective parisons does not exceed 7%. So, the correct option is A).

Let p be the true proportion of defective parisons in the population.

The null hypothesis is that the proportion of defective parisons is equal to or less than 7%, i.e., H0: p <= 0.07

The alternative hypothesis is that the proportion of defective parisons is greater than 7%, i.e., Ha: p > 0.07

Calculate the sample proportion and standard error

We are given that the sample size n = 700 and the number of defective parisons x = 55.

The sample proportion is P = x/n = 55/700 = 0.0786

The standard error of the sample proportion is

SE = √[(P(1-P))/n] = sqrt[(0.0786*0.9214)/700] = 0.0166

Calculate the test statistic

The test statistic for a one-tailed z-test is

z = (P - p) / SE

Here, we want to test if the proportion of defective parisons is greater than 7%, so we use the alternative hypothesis to calculate the z-value

z = (0.0786 - 0.07) / 0.0166 = 0.516

The p-value is the probability of getting a test statistic as extreme or more extreme than the observed value, assuming the null hypothesis is true. Since this is a one-tailed test, we need to find the area under the standard normal distribution curve to the right of z = 0.516.

Using a standard normal table or calculator, we find that the area to the right of z = 0.516 is 0.206.

The p-value of the test is 0.206, which is greater than the significance level of 0.05. Therefore, we fail to reject the null hypothesis and conclude that there is not enough evidence to suggest that the proportion of defective parisons is greater than 7%.

In other words, the new soap bubble liquid formula can be approved since the proportion of produced parisons with contents that do not allow bubbles to inflate does not exceed 7%. So, the correct answer is A).

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Therefore, we have the recurrence relation: |P(S_k)| = 2 * |P(S_{k-1})|
with the initial condition |P(S_0)| = 1 (since the empty set is the only subset of the empty set).

Sure! To count the number of subsets of a set with k elements, we can use the fact that each element can either be in a subset or not. This gives us two options for each element, so there are 2^k total subsets.

To set up a recurrence relation for this, let S_k denote the set with k elements and P(S_k) denote its power set (the set of all subsets of S_k). Then, we can relate P(S_k) to P(S_{k-1}) by considering whether or not to include the kth element in each subset.

If we don't include the kth element, then each subset of S_{k-1} is also a subset of S_k, so there are |P(S_{k-1})| subsets that don't include the kth element.

If we do include the kth element, then each subset of S_{k-1} can be extended by including the kth element, giving us |P(S_{k-1})| more subsets.

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The solution of the given system of equations by substitution is (-2, -3).

Given a system of equations,

9y - 7x = -13 [Equation 1]

-9x + y = 15 [Equation 2]

We have to find the solution of the given system of equations.

From [Equation 2],

y = 15 + 9x [Equation 3]

Substitute [Equation 3] in [Equation 1].

9 (15 + 9x) - 7x = -13

135 + 81x - 7x = -13

74x = -148

x = -2

y = 15 + (-18) = -3

Hence the solution of the given system of equations is (-2, -3).

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The expression for the perimeter of the wood deck, obtained from the formula for finding the perimeter of a rectangle is; 84 + 8·c + 8·w

The perimeter of a rectangle is found from the sum of twice the length and twice the width of the rectangle.

The dimensions of the rectangular swimming pool are;

Length = 26 feet

Width = 16 feet

The width of the concrete walkway = c

The width of the wooden deck = w

Therefore;

The length of the perimeter of the wooden deck = 26 + 2·c + 2·w

The width of the perimeter of the wooden deck = 16 + 2·c + 2·w

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The distance between the points (-21,-29) and (0,0) is approximately 35.80 units.

To find the distance between two points in a coordinate plane, we can use the distance formula. The distance formula is based on the Pythagorean theorem and can be written as follows:

d = √((x₂ - x₁)² + (y₂ - y₁)²)

Where d is the distance between the two points, and (x₁, y₁) and (x₂, y₂) are the coordinates of the two points.

Using this formula, we can find the distance between the points (-21,-29) and (0,0) as follows:

d = √((0 - (-21))² + (0 - (-29))²)

= √(21² + 29²)

= √(441 + 841)

= √1282

≈ 35.80

This distance represents the length of a straight line segment connecting the two points in the coordinate plane.

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The value of a in the expression will be 3750.

The value of b, rounded to 2 decimal places will be (75/23)^1/4

The value of n is 450.

An expression consists of one or more numbers or variables along with one more operation.

The value of a in the expression will be:

= 4200 - 450

= 3750.

The number of French words a student remembers never decreases below a certain number of words, n which is 450.

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Using the system of equations, we get that the drama club is charging $21 for a regular gift basket and $39 or a deluxe gift basket.

Given that,

The drama club is selling gift baskets to raise money for new costumes.

Let x be cost of the regular gift baskets and y be the cost of the deluxe gift baskets.

During the fall play, they sold a combined 15 regular gift baskets and 17 deluxe gift baskets, earning a total of $978.

15x + 17y = 978

During the spring musical, they sold 27 regular gift baskets and 17 deluxe gift baskets, earning a total of $1,230.

27x + 17y = 1230

From both equations,

978 - 15x = 1230 - 27x

12x = 252

x = 21

Cost of regular gift basket = $21

Cost of deluxe gift basket = y = (978 - 15 (21)) / 17 = $39

Hence the cost two kinds of baskets are $21 and $39.

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If the sum of squares for error (SSE) is 40 and the sum of squares due to the model (SSM) is 60, therefore, the answer is (c) 0.60.

Based on your question,  the coefficient of determination (R²) for a simple linear regression, given the sum of squares for error (SSE) is 40 and the sum of squares due to the model (SSM) is 60.

To calculate R², follow these steps:

1. Calculate the total sum of squares (SST): SST = SSE + SSM
2. Divide SSM by SST: R² = SSM / SST

Now, let's apply the values from your question:
To calculate, we use the formula:
= SSM / SSM + SSE)

Plugging in the given values, we get:
= 60 / (60 + 40) = 0.6
SST = SSE + SSM = 40 + 60 = 100
R² = SSM / SST = 60 / 100 = 0.60

So, the coefficient of determination (R²) is 0.60, which corresponds to option (c).

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The experimental probability of landing on a number greater than 4 is 18/60

The experimental probability will be given by the number of times that the outcome was greater than 4 (so a 5 or a 6) over the total number of trials.

We can see that the total number of trials is 60, and we have:

The outcome 5 a total of 10 times.

The outomce 6 a total of 8 times.

Adding these values we will get 10 + 8 = 18

Then the experimental probability of a number greater than 4 is:

E = 18/60

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Answer:

1/2

Step-by-step explanation:

The probability of a random card being red is 1/2 since half the cards are red and half are black

The probability of selecting a red card or a king from a deck of 52 cards is 28/52, which can be simplified to 7/13.

To find the probability of selecting a red card or a king from a deck of 52 cards, follow these steps:

1. Determine the total number of red cards in the deck. There are 26 red cards, as there are 13 cards of each red suit (hearts and diamonds).
2. Determine the total number of kings in the deck. There are 4 kings, one from each suit.
3. Determine the overlap between red cards and kings. There are 2 red kings (king of hearts and king of diamonds).
4. Use the principle of inclusion-exclusion to account for the overlap. This means we'll add the probabilities of the two individual events and subtract the probability of their intersection (overlap).
5. Calculate the probability of each event and their intersection:
  - Probability of a red card: 26/52 (number of red cards / total cards)
  - Probability of a king: 4/52 (number of kings / total cards)
  - Probability of a red king: 2/52 (number of red kings / total cards)
6. Apply the inclusion-exclusion principle:
  - Probability of a red card or a king = (Probability of a red card) + (Probability of a king) - (Probability of a red king)
  - Probability = (26/52) + (4/52) - (2/52) = 28/52

So, the probability of selecting a red card or a king from a deck of 52 cards is 28/52, which can be simplified to 7/13.

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We may draw a scatterplot of the data and compute the correlation coefficient to see whether there is a relationship between Nadeem's visits to the library and the number of books he checks out. Linear Equation = Y =mx+c. Option A is Correct.

The degree and direction of the linear link between two variables are measured by the correlation coefficient. If the correlation is positive, it suggests that if one variable rises, the other variable rises as well.

If there is a correlation, linear regression may be used to describe the data with a linear equation.

Y= mx+c

Based on how frequently Nadeem visits the library, we may use this equation to anticipate how many books he will borrow. Correlation does not always indicate cause, though. Option A is Correct.

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Correct Question:

Each month, Nadeem keeps track of the number of times he visits the library and the number of books he checks out Is there a correlation. you model his data with a linear equation? Is there a causal relationship?

A. There is a positive correlation and no causal relationship.

B. There is a negative correlation and no casual relationship.

C. There is a casual relationship but no positive correlation.

D. There is neither a correlation nor a casual relationship.

The correlation coefficient of 0.88 reveals that there is an intense linear connection between the two variables.

It should be noted that to ascertain the correlation coefficient, we can utilize the formula:

r = (nΣxy - ΣxΣy) / sqrt[(nΣx^2 - (Σx)^2)(nΣy^2 - (Σy)^2)]

Retaining the same numeric values from before, we can compute:

r = (9(976) - (36)(605)) / sqrt[(9(182) - (36)^2)(9(11681) - (605)^2)] ≈ 0.88

Therefore, the correlation coefficient is fairly close to 0.88.

The correlation coefficient implies a strong positive relationship between hours expended studying and test outcomes. As the quantity of hours committed to studying increases, the test scores will tend to keep up accordingly. A correlation coefficient of 0.88 reveals that there is an intense linear connection between the two variables, and the line of best fit serves as a desirable standard representation of the data.

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Answer:

Step-by-step explanation:

It appears there is an error in the table. The correct table is:

[tex]\begin{array}{|l|c|c|c|c|c|c|c|c|c|c|c|}\cline{1-11}\vphantom{\dfrac12}\textsf{Hours spent studying $(x)$}&0&1&2&4&4&4&6&6&7&8\\\cline{1-11}\vphantom{\dfrac12}\textsf{Test score $(y)$}&35&40&46&65&67&70&82&88&82&95\\\cline{1-11}\end{array}[/tex]

The simplest method to find the linear regression equation and the correlation coefficient for this data set is to use a statistical calculator.

After entering the data into a statistical calculator we get:

The regression line of y on x is y = a + bx.

Therefore, substitute the found values of a and b into the formula to write the linear regression equation for the given data set:

[tex]\boxed{y=34.27+7.79x}[/tex]

The correlation coefficient is the value of r, so r = 0.98 to the nearest hundredth.

The correlation coefficient, r, measures the strength of the linear correlation between two variables. |t is always between +1 and -1.

As r = 0.98, there is a very strong positive correlation.

In context, this suggests that the more hours of studying for a test a student does, the higher their test score.

Answer:

x^3 + 5x^2 + 2x - 8.

Step-by-step explanation:

To find the equation of a polynomial function, we need to know the roots and the degree of the function. We are given the roots -4, -2, and 1.

Since these are the roots, we know that the factors of the polynomial are (x + 4), (x + 2), and (x - 1). We can find the equation by multiplying these factors together:

(x + 4)(x + 2)(x - 1)

To simplify this expression, we can use FOIL (First, Outer, Inner, Last) method:

(x + 4)(x + 2)(x - 1) = (x^2 + 2x + 4x + 8)(x - 1) = (x^2 + 6x + 8)(x - 1)

Expanding further, we get:

(x^2 + 6x + 8)(x - 1) = x^3 + 6x^2 + 8x - x^2 - 6x - 8 = x^3 + 5x^2 + 2x - 8

Therefore, the equation is:

x^3 + 5x^2 + 2x - 8.

The metal in the frame weighs 70.5 kg in total. If a rectangular frame measuring 5 metres in length and 12 metres in width is constructed from five straight pieces of metal.

Get the diagonal

d² = 52 + 122

d² = 25+ 144

d² = 169

d = 13m

Get the perimeter of the rectangular frame:

Perimeter of the frame = 2(5+12) + 13

Perimeter of the frame = 2(17) + 13

Perimeter of the frame = 34 + 13

Perimeter of the frame = 47m

If the weight of the metal is 1.5 kg per metre, the total weight will be expressed as:

Total weight = 47×1.5

Total weight = 70.5kg

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The complete question is

This rectangular frame is made from 5 straight pieces of metal.

5 m

12 m

The weight of the metal is 1.5 kg per metre.

Work out the total weight of the metal in the frame.

In a case whereby Sami wants to find the measurements of the sides and angles of the parallelogram shown the tools she can use to find these measurements are;

The protractor serves as one of the tools that can be used in making the parallelogram whih which be used in the mearement of the angles of the paralleolgram.

The ruler is also useful in the creation of the parallelogram because it can be used to meausre the lenght of the fiqure, hence the first as well as the third option is right

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a. At the 0.05 level of​ significance, there is evidence of a linear relationship between the plate gap of the​ bag-sealing machine and the tear rating of a bag of​ coffee.

b. A​ 95% confidence interval estimate of the population​ slope, betaβ1 is (0.5590, 0.8606).

a. To test for the linear relationship between plate gap and tear rating, we can use the null and alternative hypotheses:

H0: β1 = 0 (there is no linear relationship)
Ha: β1 ≠ 0 (there is a linear relationship)

We can use the t-test to test this hypothesis. The test statistic is calculated as:

t = b1 / (S1 / [tex]\sqrt(n)[/tex])

where b1 is the sample slope, S1 is the standard error of the slope, and n is the sample size. Substituting the values given in the question, we get:

t = 0.7098 / (0.2146 / sqrt(30)) = 5.05

Using a t-distribution with n-2 = 28 degrees of freedom and a significance level of 0.05, we can find the critical values as ±2.048. Since the calculated t-value of 5.05 is greater than the critical value of 2.048, we reject the null hypothesis and conclude that there is evidence of a linear relationship between plate gap and tear rating at the 0.05 level of significance.

b. To construct a 95% confidence interval estimate of the population slope β1, we can use the formula:

b1 ± tα/2(S1 / [tex]\sqrt(n)[/tex])

where tα/2 is the critical value from the t-distribution with n-2 degrees of freedom and a confidence level of 95%. Substituting the values given in the question, we get:

b1 ± 2.048(0.2146 / [tex]\sqrt(30)[/tex]) = 0.7098 ± 0.1508

Therefore, the 95% confidence interval for the population slope β1 is (0.5590, 0.8606).

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Answer:

The z-score is calculated as follows:

z = (x - μ) / σ

where x is the value of interest, μ is the mean, and σ is the standard deviation.

Plugging in the values given, we get:

z = (86 - 62) / 12 = 2

Therefore, the z-score for a value of 86 is 2.

The answer is (C) 2.

Step-by-step explanation:

Answer:

2a - 1/a^2 +5

The first three terms of the sequence a_n = 2n-1/n²+5 are 1/6, 1/3, and 5/14.

In mathematics, a sequence is an enumerated collection of objects in which repetitions are allowed and order matters. Like a set, it contains members. The number of elements is called the length of the sequence.

A sequence is an ordered list of numbers. The three dots mean to continue forward in the pattern established. Each number in the sequence is called a term.

The first three terms of the sequence a_n = 2n-1/n²+5 are:

1. For n=1, a_1 = (2(1)-1)/(1²+5) = 1/6
2. For n=2, a_2 = (2(2)-1)/(2²+5) = 3/9 = 1/3
3. For n=3, a_3 = (2(3)-1)/(3²+5) = 5/14

So, the first three terms of the sequence are 1/6, 1/3, and 5/14.

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As we see, p-value is less than the significance level, so null hypothesis rejected and there is no evidence to support the claim that population mean is 22 degree C.

The population mean can be calculated by the sum of all values in the given data/population divided by a total number of values. We have various temperature measurements are recorded at different times for a particular city.

Sample Mean, [tex]\bar X [/tex] = 20°C

Standard deviations,[tex]\sigma [/tex]= 1.5° C

Level of significance, = 0.05

We have to test that population mean is 22 degree C. Consider the hypothesis testing, the null and alternative hypothesis are [tex]H_0 : \mu = 22 [/tex].

[tex]H_a : \mu ≠ 22 [/tex].

Consider the test statistic, z test for mean formula, [tex]z = \frac{\bar x - \mu }{\frac{\sigma}{\sqrt{n}}}[/tex].

=> [tex]z = \frac{20 - 22}{\frac {1.5}{\sqrt{60}}}[/tex].

= - 10.32

Now, using distribution table, the p-value for z = - 10.32 is less than to 0.001. So,

p-value < 0.05, so null hypothesis is rejected.

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It is true that When the central bank raises the discount rate, commercial banks are likely to reduce their borrowing of reserves from the Fed.

The discount rate is the interest rate at which commercial banks can borrow reserves from the central bank, such as the Federal Reserve in the United States. An increase in the discount rate makes borrowing from the Fed more expensive for commercial banks.

As a result, commercial banks may choose to call in loans to replace the reserves they would have otherwise borrowed from the central bank. Calling in loans refers to the process of demanding the repayment of outstanding loans from borrowers, which allows the bank to obtain funds to maintain their required reserve levels. By calling in loans, banks can avoid the higher cost of borrowing from the Fed due to the increased discount rate.

Overall, a higher discount rate can encourage commercial banks to reduce their borrowing of reserves from the central bank and instead call in loans to maintain their reserve requirements. This can lead to tighter credit conditions in the economy, as banks may be less willing to extend new loans to borrowers, potentially slowing down economic growth.

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The goal of an optimization problem is to find the maximum or minimum value of an objective function given certain constraints. In this case, the goal of a business owner is often to maximum profit.

The objective function is a method for maximising (or decreasing) something. This something has a monetary value. In the real world, it could be the cost of a project, the quantity of goods produced, the profit value, or even the materials saved as a result of a streamlined process. The objective function is used to try to achieve a target for output, profit, resource use, and so on. We must examine the connections between constraints and any limitations within the business itself. These can include production capacity constraints, resource availability, and even technological limitations.

For instance, from the values of maximum and minimum speed of a train, an engineer will be able to decide on the materials required to withstand the speed, to manufacture brakes for the train to run smoothly. The maximum and minimum value of thyroid in the bloodstream enables the doctor to prescribe the appropriate medicine for the patients to bring down the thyroid levels.

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A graph of the transformed function y = f(-x) is shown in the image attached below.

In Mathematics and Geometry, a reflection over or across the y-axis or line x = 0 is represented and modeled by this transformation rule (x, y) → (-x, y).

This ultimately implies that, a reflection over or across the y-axis would maintain the same y-coordinate (y-axis) while the sign of the x-coordinate (x-axis) would change from positive to negative or negative to positive.

In this context, we can reasonably infer and logically deduce that the graph of the absolute value function y = f(-x) can be created by reflecting the parent absolute value function y = f(x) over or across the y-axis;

f(x) = |x - 4|

g(x) = y = f(-x) = |-x - 4|

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Answer:

(x+10)² + (y+5)² = 125

Step-by-step explanation:

We are given that a circle has a center (-10,-5), and passes through the point (-5,5).

We want to write the equation of this circle in the standard equation. The standard equation is (x-h)² + (y-k)² = r² where (h,k) is the center and r is the radius.

As we are already given the center point, we can substitute its values into the equation.

Reminder: the equation uses negative values, and we have negative numbers.

(x--10)² + (y--5)² = r²

This can be simplified to:

(x+10)² + (y+5)² = r²

Now, we need to find r².

As the point passes through (-5,5), we can use its values to solve for r².

Substitute -5 as x and 5 as y.

(-5+10)² + (5+5)² = r²

(5)² + (10)² = r²

25 + 100 = r²

125=r²

The radius is 125

Substitute 125 as r².

(x+10)² + (y+5)² = 125

The researcher needs a sample of at least 46 days.

We have,

To estimate the true mean water temperature within 4 with 90% confidence, given that the variance is 27%, we need to use the formula for sample size in a confidence interval estimation:
n = (Z² x σ²) / E²
where n is the required sample size, Z is the Z-score corresponding to the desired confidence level (90%), σ^2 is the variance (27%), and E is the margin of error (4).

We can find the Z-score for a 90% confidence level using a standard normal table, which is 1.645.
Now we can plug the values into the formula:
n = (1.645² x 0.27) / 4²
n = (2.706025 x 0.27) / 16
n = 0.729625 / 16
n = 0.0456015625

Since we cannot have a fraction of a day, we need to round up to the nearest whole number to ensure the desired accuracy.

Therefore, the researcher needs a sample of at least 46 days to estimate the true mean water temperature within 4 with 90% confidence.

Thus,

The researcher needs a sample of at least 46 days.

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The experimental probability of drawing a diamond is 0.20

From the question, we have the following parameters that can be used in our computation:

Outcome Frequency

Heart 7

Spade 3

Club 6

Diamond 4

For diamond, we have

P(Diamond) = Diamond/Total

So, we have

P(Diamond) = 4/20

Evaluate

P(Diamond) = 0.20

Hence, the value is 0.20

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The solutions to the equation 12x²-22x-5=-5x using the quadratic formula are x = 5/4 and x = -1/3.

The given equation is a quadratic equation in standard form, ax² + bx + c = 0, where a = 12, b = -22, and c = -5 + 5 = 0. We can use the quadratic formula to solve for x:

x = (-b ± √(b² - 4ac)) / 2a

Substituting the values of a, b, and c, we get:

x = (22 ± √(22² - 4(12)(0))) / 2(12)

Simplifying under the square root, we get:

x = (22 ± √484) / 24

x = (22 ± 22) / 24

Simplifying further, we get:

x = 44/24 or x = 0/24

Reducing the first fraction, we get:

x = 11/6 or x = 0

However, we need to check if x = 0 satisfies the given equation or not. Substituting x = 0, we get:

12(0)² - 22(0) - 5 = -5(0)

-5 = 0

This is not true, so x = 0 is an extraneous solution and should be discarded. Therefore, the solutions to the given equation are:

x = 5/4 and x = -1/3.

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