- Challenge:
A line through the points (2, 8) and (-2, k) has a slope of ¾. What is the value of k?

If the value of x is 4, the quadrilateral meets all the requirements of a parallelogram and will be a parallelogram.

A quadrilateral is a four-sided shape with straight line segments as its sides. It is a two-dimensional shape with four angles, each measuring 90°. Quadrilaterals can be categorized into different shapes such as squares, rectangles, parallelograms, trapezoids, rhombuses, and kites.

A parallelogram is a four-sided shape with opposite sides parallel and equal in length. To find the value of x that makes the quadrilateral a parallelogram, we need to use the property of a parallelogram, which states that the opposite sides of a parallelogram are equal in length.

Therefore, we need to equate the opposite sides of the quadrilateral: 6x-8=4x. After solving this equation, we get x=4. Thus, the value of x that makes the quadrilateral a parallelogram is 4.

In order for a quadrilateral to be a parallelogram, opposite sides must be parallel. Using this property, we can set the opposite sides equal to each other and solve for x.

[tex]$2x + 5 = 3x - 2$[/tex]

Simplifying this equation, we get:

[tex]$x = 7$[/tex]

Therefore, if [tex]$x=7$[/tex], the quadrilateral is a parallelogram.

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Therefore, the equilibrium level of national income in this basic Keynesian macroeconomic model is 480.

In mathematics, the sum is the result of adding two or more numbers or quantities together. The symbol used to represent a sum is the capital Greek letter sigma (∑), which stands for "sum up."

by the question.

In the basic Keynesian macroeconomic model, equilibrium occurs when national income (Y) equals total spending in the economy. Therefore, we can set Y equal to the sum of consumption (C) and investment (I), as follows:

Y = C + I

Substituting the given consumption and investment functions into this equation, we get:

Y = (40 + 0.5Y) + 200

Simplifying and rearranging, we get:

Y - 0.5Y = 240

0.5Y = 240

Y = 480

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It will run dry after 141.7 days.

The rainwater tank has a diameter of 160 cm and a height of 190 cm, then its volume is:

V = 3.14*(180cm)*(160cm/2)² = 3,617,280 cm³

We know that 1 L = 1000 cm³

then:

3,617,280 cm³ = 3,617.280 L

The water is used at a rate of 25,5 litres per day, so after x days there is:

W =  3,617.280  - 25.5*x liters

It is zero when:

0 = 3,617.280  - 25.5*x

x =  3,617.280/25.5

x = 141.7 days.

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Answer:

Step-by-step explanation:

Logically, if a polynomial of real coefficients has a complex root, it’s conjugate is a root as well. That means if -20-7i is a root, -20+7i is also a root. Also, since we’re dealing with minimal degree, we wish to construct a quadratic expression with such roots. To do this, we can use Vieta’s formulas, which relates the trinomial coefficients with its roots. The two roots added together is -b/a in ax^2 + bx + c, and the two roots multiplied together is c/a. The two roots added together is -40. The two roots multiplied together is 449. So, our quadratic expression is x^2+40x+449

Using Law of sines, the missing angles are:

4) ∠B = 45.74°

6) ∠C = 21.02°

8) ∠A = 60.84°

The law of sines is a rule for solving the lengths and angles of triangles and it states that:

a/sin A = b/sin B = c/sin C

4) Using law of sines, we have:

8/sin B = 11/ sin 80

(8/11) sin 80 = sin B

sin B = 0.7162

B = sin⁻¹0.7162

∠B = 45.74°

6) Using law of sines, we have:

13/sin C = 32/sin 62

sin C = (13/32) sin 62

sin C = 0.3587

C = sin⁻¹0.3587

C = 21.02°

8) Using law of sines, we have:

30/sin 104 = 27/sin A

sin A = (27/30) sin 104

sin A = 0.8733

A = sin⁻¹0.8733

A = 60.84°

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Answer:

Step-by-step explanation:

A hands-on experience is the only modality that would give visitors a complete understanding of the plight of modern enslaved people.

Perimeter of the given polygon figure will be 38 units.

What exactly is a polygon in mathematics?

A closed, two-dimensional, flat, closed polygon is a shape that is constrained by geometry and has straight sides. Its sides don't curve inward at all. Another term for a polygon's sides is its polygonal edges. The points where two sides converge are known as a polygon's vertices (or corners).

Perimeter of a polygon = Measure of the circumference of the polygon

From the figure attached,

Perimeter of the figure = measure of the three straight lines + measure of the circumference of the quarter circle

Measure of linear sides = 5 + 10 + 10 + 5 = 30 units

Circumference of the quarter circle = 1/4(2πr)

                                                          =  1/2(π)(5)

                                                          = 7.85 units

Perimeter of the figure = 30 + 7.85

                                     = 37.85

                                     ≈ 38 units

  Therefore, perimeter of the given figure will be 38 units.

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Answer:y intercept is 6 slope is -1/4

Step-by-step explanation:

to graph it in y=mx+b form b is the y intercpt and where you start the graph and m is the slope is  [tex]-\frac{1}{4}[/tex] the you go to the right 4 and up one to graph the line

By the given definition of matrix A, the value of the matrix A⁻¹ is [tex]\left[\begin{array}{ccc}-1&0&1&2&-1&-2&0&0&-1\end{array}\right][/tex] and it is true that AA⁻¹ = I₃.

Given that

[tex]A = \left[\begin{array}{ccc}1&0&2\\1&1&0\\1&0&1\end{array}\right][/tex]

To find the inverse of A, we can use the following formula:

A⁻¹ = (1/|A|) adj(A)

where |A| is the determinant of A and adj(A) is the adjugate matrix of A.

First, let's calculate the determinant of A:

|A| = 1(1×1 - 0×0) - 0(1×0 - 0×1) + 2(1×0 - 1×1)

|A| = -1

Next, we need to find the adjugate matrix of A.

To do this, we need to find the matrix of cofactors of A, then take its transpose:

[tex]C = \left[\begin{array}{ccc}1&-2&0&0&1&0&-1&2&1\end{array}\right]\\[/tex]

adj(A) = [tex]C^T = \left[\begin{array}{ccc}1&0&-1&-2&1&2&0&0&1\end{array}\right][/tex]

Now we can calculate A⁻¹ using the formula:

A⁻¹ = (1/|A|) adj(A)

So, we have

[tex]A^{-1} = (-1) \left[\begin{array}{ccc}1&0&-1&-2&1&2&0&0&1\end{array}\right] = \left[\begin{array}{ccc}-1&0&1&2&-1&-2&0&0&-1\end{array}\right][/tex]

Finally, we can check whether AA⁻¹ = I₃ using

[tex]A^{-1}A = \left[\begin{array}{ccc}-1&0&1&2&-1&-2&0&0&-1\end{array}\right] \left[\begin{array}{ccc}1&0&2&1&1&0&1&0&1\end{array}\right] = \left[\begin{array}{ccc}1&0&0&0&1&0&0&0&1\end{array}\right] = I_3[/tex]

Therefore, we have found the inverse of A and verified that AA⁻¹ = I₃.

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The polynomial after simplification is obtained as [tex]5 x^{2}[/tex] + 9x + 3.

What is simplification?

In mathematics, reducing an expression, fraction, or problem to a simpler form is referred to as simplification. With calculations and solution, the problem is made simple. Make something simpler by simplifying it.

We are given a polynomial as

5x - 5 + [tex]11 x^{2}[/tex] + 4x - [tex]6 x^{2}[/tex] + 8

Now, in order to simplify the given polynomial, we will combine the like terms of the polynomial.

On combining the like terms, we get

[tex]5 x^{2}[/tex] + 9x + 3

Hence, the polynomial after simplification is obtained as [tex]5 x^{2}[/tex] + 9x + 3.

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Answer:

B

Step-by-step explanation:

calculate the slopes m of the 2 lines using the slope formula

m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]

with (x₁, y₁ ) = (- 6, 5 ) and (x₂, y₂ ) = (- 2, 7 )

m = [tex]\frac{7-5}{-2-(-6)}[/tex] = [tex]\frac{2}{-2+6}[/tex] = [tex]\frac{2}{4}[/tex] = [tex]\frac{1}{2}[/tex]

repeat with

(x₁, y₁ ) = (4, 2 ) and (x₂, y₂ ) = (6, 6 )

m = [tex]\frac{6-2}{6-4}[/tex] = [tex]\frac{4}{2}[/tex] = 2

• Parallel lines have equal slopes

[tex]\frac{1}{2}[/tex] ≠ 2 , then lines are not parallel

the product of the slopes of perpendicular lines equals - 1

[tex]\frac{1}{2}[/tex] × 2 = 1 ≠ - 1 , thus lines are not perpendicular

the lines are neither perpendicular nor parallel

Therefore , the solution of the given problem of slope comes out to be  y = 7x - 17 is the equation in slope-intercept form.

A line's steepness is determined by its slope. In gradient-based equations, a situation known as gradient overflow can happen. One can determine the slope by dividing the sum of a run (width differential) and rise (climbing distinction) between two places. The equation with the hill variation, y = mx + b, is used to model the fixed path issue. where grade is mm, a = bc, and the line's y-intercept is situated; (0, b).

Here,

Given :

=> -7x + y = -17

7x both faces together

=>  -7x + 7x + y = 7x - 17

Condense: y = 7x - 17

So,

=>  y = 7x - 17 is the equation in slope-intercept form.

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Answer: 204 ft

Step-by-step explanation: First lets find the area of the triangle, the formula for area of a triangle is base times height divided by 2. Now the height isn't given but we can find it by subtracting 18 by 10 which gives us 8. 8 times 6 is 48 divided by 2 is 24. Therefore, the area of the triangle is 24 ft. Now we find the area of the rectangle which is length times width. 18 times 10 is 180. Now we add the area of both shapes, 180 plus 24 is 204, so your answer is 204 ft.

Answer:

Step-by-step explanation:

Answer:

x = 16

Step-by-step explanation:

∠1 + ∠2 = 90

42 + 3x = 90

3x = 90 - 42

x = 48/3 = 16

The box-and-whisker plot shows that the dataset has a median of approximately 5.5 and is relatively symmetric, with the middle 50% of the data falling between approximately 4 and 7.

The box-and-whisker plot offers a visual summary of the distribution of the given dataset. The following is one way to understand the plot:

The median, which is the midway number when the data is organised from least to largest, is shown by the line inside the box. The median in this situation is roughly 5.5.

The box's bottom edge corresponds to the first quartile (Q1) and its top edge to the third quartile, and it represents the middle 50% of the data (Q3). The interquartile range is the space between Q1 and Q3 (IQR). In this instance, Q1 is roughly 4 and Q3 is roughly 7, hence the IQR is roughly 3.

The whiskers reach from the box's boundaries to the dataset's lowest and largest values that aren't regarded as outliers. Although there are many different definitions of an outlier, it is generally accepted that any number that is more than 1.5 times the IQR below Q1 or above Q3 qualifies as an outlier. There aren't any anomalies in this circumstance.

Individual data points outside the box and whiskers are shown as dots above and below the whiskers. There are no such data points in this situation.

Hence, the box-and-whisker plot reveals that the dataset is very symmetrical and has a median of about 5.5, with the middle 50% of the data ranging between roughly 4 and 7.

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The prοduct οf the matrices is nοt the identity matrix. Therefοre, X and A nοt inverses οf each οther.

An identity matrix is a square matrix in which all the elements οf principal diagοnals are οne, and all οther elements are zerοs. It is denοted by the nοtatiοn “In” οr simply “I”. Any matrix will yield a matrix as a result of being multiplied by the identity matrix.

The identity matrix is a matrix having entry οne in its diagοnal and rest οf the entries are zerο.

[tex]X.A = \left[\begin{array}{cc}2&-1\\6&-4\\\end{array}\right] \left[\begin{array}{cc}1/2&1/4&\\-2&-1/2&\end{array}\right][/tex]

[tex]X.A = \left[\begin{array}{cc}3&1\\11&7/2\end{array}\right][/tex]

Hence, The prοduct of the matrices is not the identity matrix. Therefοre, X and A not inverses of each other.

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The complete question is in the attached image.

The six trig functions are:

(1) Figure 1, sin θ = 1/√5

(2) Figure 1, cos θ = 2/√5

(3) Figure 1, tan θ = 1/2

(4) Figure 2, sin θ = 3/√13

(5) Figure 2, cos θ = 2/√13

(6) Figure 2, tan θ = 3/2

Trig function (short for "trigonometric function") is a mathematical function that relates the angles of a right triangle to the lengths of its sides. The main trig functions are sine (sin), cosine (cos),  and tangent (tan).

The trig functions are abbreviated using SOH CAH TOA.

SOH : sin θ = opposite / hypotheses

CAH: cos θ = adjacent / hypothenuse

TOA : tan θ = opposite / adjacent

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Answer:

When two shapes are similar but not congruent, the sequence of steps showing the similarity usually has a single dilation and then the rest of the steps are rigid transformations. The dilation can come at any time.

Step-by-step explanation:

When two shapes are similar but not congruent, the sequence of steps showing the similarity usually has a single dilation and then the rest of the steps are rigid transformations. The dilation can come at any time.

Answer:

-106f+56

Step-by-step explanation:

7(-8f-2)= -56f-14

10(-5f+7)= -50f+70

-56f-14. +. 50f+70

=-106f+56

Answer:

-2(53f-28)

Step-by-step explanation:

7(−8f−2)+10(−5f+7)

7x-8f=-56f  7x-2=-14

10x-5f=-50f   10x7=70

-56f-14+-50f+70       Adding a negative to something means to subtract. Like right here at -14 + -50 is the same as -14 - 50

   2. Add the numbers

-56f-14+-50f+70   -14+70=56

-56f+56-50f

   3. Combine like terms

-56f+56-50f   -56+ -50= -106

-106f +56

   4. Common Factor

-106f + 56

-2(53f-28)

The relationship which describe angles 1 and 2 is supplementary angles.

The correct answer choice is option A.

Supplementary angles are angles in which the sum of their measure is equal to 180°.

Based on this, angles 1 and 2 are supplementary because they both add up to 180°.

Complementary angles are two angles which add up to 90 degrees.

Vertical angles are angles opposite each other when two angles intersect.

Adjacent angles are angles which have a common side and common vertex.

Hence, angles 1 and 2 are supplementary.

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Answer:

Step-by-step explanation:

To find P(x<4), we need to use the cumulative distribution function (CDF) of the binomial distribution.

For N = 6 and p = 0.3, the probability mass function (PMF) is:

P(X = k) = (6 choose k) * 0.3^k * 0.7^(6-k)

where (6 choose k) is the binomial coefficient.

Using this formula, we can find the probabilities for each value of X less than 4:

P(X = 0) = (6 choose 0) * 0.3^0 * 0.7^6 ≈ 0.1176

P(X = 1) = (6 choose 1) * 0.3^1 * 0.7^5 ≈ 0.3025

P(X = 2) = (6 choose 2) * 0.3^2 * 0.7^4 ≈ 0.3241

P(X = 3) = (6 choose 3) * 0.3^3 * 0.7^3 ≈ 0.1852

Therefore, P(x<4) is the sum of these probabilities:

P(x<4) = P(X=0) + P(X=1) + P(X=2) + P(X=3) ≈ 0.9294

So the probability of getting less than 4 successes in 6 trials with a success probability of 0.3 is approximately 0.9294.

Answer:

23841.0596 in standard form is 2.38410596 x 10^4.

Step-by-step explanation:

Answer:

2.38410596 x 10^4

Step-by-step explanation:

pls brainlist

a. The Vοlume = 198 cm³ and height = 7, if it’s a cylinder with a radius οf 3cm.

b. The cοst οf cοffee is $3.96 when $0.02 per cubic centimetre.

The fοrmula fοr the vοlume οf a cylinder is

V = πr²h,

where V is the vοlume, r is the radius, and h is the height.

a) Tο find the height οf the cylinder, we need tο knοw the vοlume οf the cοntainer and the radius. The fοrmula fοr the vοlume οf a cylinder is:

V = πr²h

[tex]$\mathrm{\frac{V }{ h}} = \pi r\² }[/tex]

[tex]$\mathrm{\frac{V }{ h}} = \frac{22}{7} \times 3 \times 3}[/tex]

[tex]$\mathrm{\frac{V }{ h}} = \frac{22}{7} \times 3 \times 3}[/tex]

[tex]$\mathrm{\frac{V }{ h}} = \frac{198}{7}[/tex]

Thus, Vοlume = 198 cm³ and height = 7

b) If the cοntainer frοm is filled with cοffee and cοffee cοsts $0.02 per cubic centimetre, Then the cοst οf cοffee

= $0.02 × 198 cm³

= $3.96

Thus, The Vοlume = 198 cm³ and height = 7, if it’s a cylinder with a radius οf 3cm.

The cοst οf cοffee is $3.96 when $0.02 per cubic centimetre.

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According to the given information, it takes 0.5 hours to travel 16.5 highway miles and 7 city miles and 1.6 hours to travel 44 highway miles and 28 city miles.

What is the average rate?

The average rate is a measure of the average speed at which something occurs over a period of time. It is calculated by dividing the total amount of something by the total time it took to occur.

The formula for the average rate or average speed is:

Average speed = Total distance traveled / Total time taken

a. To find the time it takes to travel 16.5 highway miles and 7 city miles, we can use the formula:

time = distance/speed

The time it takes to travel 16.5 highway miles is:

time on highway = 16.5 / 55 = 0.3 hours

The time it takes to travel 7 city miles is:

time in city = 7 / 35 = 0.2 hours

The total time it takes to travel both distances is:

total time = time on highway + time in city = 0.3 + 0.2 = 0.5 hours

Therefore, it takes 0.5 hours (or 30 minutes) to travel 16.5 highway miles and 7 city miles.

b. To find the time it takes to travel 44 highway miles and 28 city miles, we can use the same formula:

time on highway = 44 / 55 = 0.8 hours

time in city = 28 / 35 = 0.8 hours

total time = time on highway + time in city = 0.8 + 0.8 = 1.6 hours

Therefore, it takes 1.6 hours (or 96 minutes) to travel 44 highway miles and 28 city miles.

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The rate of change of the angle of elevation is 0.00011 rad/ft, for that we have to know the elevation.

The height above or below a specified(predefined) reference point, most frequently a reference geoid, which is a mathematical representation (expression) of the Earth's sea level as an equipotential gravitational surface, determines(defines) a location's elevation.

The angle of elevation of the camera is, Θ= [tex]tan^-^1(\frac{x}{2000} )[/tex]

The distance between the camera and the launching pad is, b= 2000 ft

The distance between the camera and the racket is, h = 4255 ft

To find the rate of change of the angle of elevation of the camera, we need to differentiate the function of that angle.

Θ= [tex]tan^-^1(\frac{x}{2000} )[/tex]

Differentiating function with respect to x we have,

[tex]\frac{d}{dx}[/tex] Θ=[tex]\frac{d}{dx} tan^-^1(\frac{x}{2000} )[/tex]

Θ'=[tex]\frac{1}{1+\frac{x^2}{2000^2} }[/tex][tex]*\frac{1}{2000}[/tex]

[tex]\frac{1}{2000+\frac{x^2}{2000} }[/tex]  (Equation 1)

[tex]h^2=b^2+p^2[/tex]

[tex]4255^2+2000^2+x^2[/tex]

Θ=[tex]\frac{1}{2000+\frac{14105025}{2000} }[/tex]

≈ 0.00011 rad/ft.

Thus, the rate of change of the angle of elevation is 0.00011 rad/ft.

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The single translation that maps shape A onto shape C is given as follows:

A translation happens when either a figure or a function are moved horizontally or vertically on the coordinate plane.

The four translation rules for coordinates are defined as follows:

Translations can often be composed, that is, a combination of multiple translations can result in a single translation, as is the case for this problem.

Considering the translation of 3 units left(shape B) and then 4 units right(shape C), the horizontal translation is given as follows:

-3 + 4 = 1 -> 1 unit right.

Considering the translation of 7 units down(shape B) and then 3 units down(shape C), the vertical translation is given as follows:

-7 - 3 = 10 units down.

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