CHEMISTRY QUESTION, PLEASE HELP!!!


Reaction B (attached); The change in enthalpy for the forward reaction is -91kJ/mol. (Energy is a product, flowing from the chemical reaction to the surroundings. )


The forward reaction for Reaction B (attached) is.


- endothermic

- exothermic


If Reaction B (attached) was ta equilibrium and then was heated ______ CH3OH would be present after the reaction adjusts to the new temperature.


- more

- less

- the same amount of


If Reaction B (attached) was at equilibrium and then the pressure in its container was increased, ____ CH3OH would be present after the reaction adjusts to the new pressure.


- more

- less

- the same amount of


If Reaction B (attached) was at equilibrium and then H2 was added, _____ CH3OH would be present after the reaction adjusts.


- more

- less

- the same amount of


If Reaction B (attached) was at equilibrium and then H2 was added, ____ CO would be present after the reaction adjusts.


- more

- less

- the same amount

Answers

Answer 1

The forward reaction for Reaction B is endothermic, as indicated by the negative change in enthalpy (-91 kJ/mol) for the forward reaction.

If Reaction B was at equilibrium and then was heated, the amount of CH₃OH would be less after the reaction adjusts to the new temperature. This is because the forward reaction is endothermic, meaning that an increase in temperature would shift the equilibrium towards the reactants side to counteract the increase in temperature.

If the pressure in the container of Reaction B was increased, the amount of CH₃OH would be more after the reaction adjusts to the new pressure. This is because the forward reaction produces fewer moles of gas than the reverse reaction, so increasing the pressure would shift the equilibrium towards the side with fewer moles of gas (the products side) to counteract the increase in pressure.

If H₂ was added to Reaction B at equilibrium, the amount of CH₃OH would be more after the reaction adjusts. This is because H₂ is a reactant in the reverse reaction, so adding more H₂ would shift the equilibrium towards the products side to counteract the increase in H₂.

If H₂ was added to Reaction B at equilibrium, the amount of CO would be less after the reaction adjusts. This is because CO is a product in the forward reaction, so adding more H₂ would shift the equilibrium towards the products side to counteract the increase in H₂, resulting in a decrease in CO.

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Related Questions

What is the percent abundance (in units of percent) of zinc in a sample whose density is 7. 537 g/ml and the only other component is copper? the density for pure copper is 8. 96 g/cm3 and the density of pure zinc is 7. 13 g/cm3. Report your answer to one decimal place

Answers

The percentage of abundance of zinc is 20.16 % whose density is 7.13 g/cm3.

Density of the mixture is 7.039 g/ml.

Density of Cu is 8.96 g/ cm3.

Density of Zn is 7.13 g/cm3.

The fractional abundance of copper is 0.946.  

Density is defined as the substance's mass per unit of volume. The symbol of density is ρ. Mass is defined as the quantity of matter while volume is the measure of space occupied by the object. The ratio of the mass and volume of the matter is known as density.

Mass of the mixture is equals to the mass of the copper and the mass of the zinc.

Mass of mixture = Mass of copper + mass of Zinc

We know that, Density = Mass * Volume

Putting the values in this we can find the percentage of abundance of zinc.

Volume of zinc / volume of mixture = 0.20156

Percentage abundance is defined as the quantitative measurement of the percentage of a specific isotope present on earth. This gives the abundance of that particular isotope.

So percentage of abundance of zinc in the mixture is,

                = 0.20156 * 100 %

                = 20.16 %

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The question is incomplete.

What is the percent abundance (in units of percent) of zinc in a sample whose density is 7.039 g/mL and the only other component is copper with a fractional abundance of 0.946? The density for pure copper is 8.96 g/cm3 and the density of pure zinc is 7.13 g/cm3. Report your answer to one decimal place.

buffer solution is made by mixing 375 ml of 0.25 m hf and 225 ml of 0.50 m naf. calculate the ph of the following: a. the original buffer solution b. the solution after adding 0.018 mol of koh to the original buffer solution c. the solution after adding 12.5 ml of 1.25 m hi to the original buffer solution

Answers

A buffer solution is made by mixing 375 ml of 0.25 m hf and 225 ml of 0.50 m naf. The ph of:

the original buffer solution is: 3.24,

the solution after adding 0.018 mol of KOH to the original buffer solution is: 9.85,

the solution after adding 12.5 ml of 1.25 m HI to the original buffer solution is 0.88.

A buffer solution is created by combining a weak acid and its conjugate base, which together maintain a relatively constant pH despite the addition of small amounts of acid or base. In this question, 375 mL of 0.25 M HF and 225 mL of 0.50 M NaF are mixed together to form the buffer solution.

The pH of the original buffer solution can be calculated using the Henderson-Hasselbalch equation, which states that [tex]pH = pKa + log([A-]/[HA]).[/tex]

In this case, [A-] is the concentration of the conjugate base (NaF) and [HA] is the concentration of the weak acid (HF). Plugging in the values given, the pH of the original buffer solution is 3.24.

After adding 0.018 moles of KOH to the original buffer solution, the pH can be calculated using the same Henderson-Hasselbalch equation. Since KOH is a strong base, the concentration of the conjugate base (NaF) increases and the concentration of the weak acid (HF) decreases. Plugging in the values, the pH of the solution after the addition of KOH is 9.85.

After adding 12.5 mL of 1.25 M HI to the original buffer solution, the pH can be calculated using the Henderson-Hasselbalch equation. Since HI is a strong acid, the concentration of the conjugate base (NaF) decreases and the concentration of the weak acid (HF) increases. Plugging in the values, the pH of the solution after the addition of HI is 0.88.

In conclusion, the original buffer solution had a pH of 3.24, the solution after the addition of 0.018 moles of KOH had a pH of 9.85, and the solution after the addition of 12.5 mL of 1.25 M HI had a pH of 0.88.

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The formation of hydrazine (N2H4) from its elements takes place by the following reaction equation.


N2 (g) + 2 H2 (g) → N2H4 (g)


What are the volumes of N2 gas and H2 gas required to form 28. 5 grams of N2H4 at 30oC and 1. 50 atm?

Answers

The volumes of N₂ gas and H₂ gas required to form 28.5 grams of N₂H₄ at 30oC and 1.50 atm are 14.3 L and 28.6 L, respectively.

To determine the volumes of N₂ gas and H₂ gas required to form 28.5 grams of N₂H₄ at 30oC and 1.50 atm, we need to use the ideal gas law to calculate the number of moles of each gas needed, and then use the balanced chemical equation to determine the volume of each gas.

Calculate the number of moles of N₂H₄

The molar mass of N₂H₄ is:

Molar mass N₂H₄ = 2 x molar mass N + 4 x molar mass H

Molar mass N₂H₄ = 2 x 14.01 g/mol + 4 x 1.01 g/mol

Molar mass N₂H₄ = 32.05 g/mol

The number of moles of N₂H₄ can be calculated as follows:

n(N₂H₄) = mass / molar mass

n(N₂H₄) = 28.5 g / 32.05 g/mol

n(N₂H₄) = 0.890 mol

Determine the number of moles of N₂ and H₂ required

From the balanced chemical equation, we see that 1 mole of N₂ reacts with 2 moles of H₂ to produce 1 mole of N₂H₄. Therefore, the number of moles of N₂ and H₂ required can be calculated as follows:

n(N₂) = n(N₂H₄) = 0.890 mol

n(H₂) = 2 x n(N₂H₄) = 1.780 mol

Use the ideal gas law to calculate the volumes of N2 and H2

The ideal gas law is given by:

PV = nRT

where P is the pressure, V is the volume, n is the number of moles, R is the gas constant (0.0821 L atm/mol K), and T is the temperature in Kelvin.

We are given P = 1.50 atm and T = 30oC = 303 K.

For N₂ gas:

n(N₂) = 0.890 mol

R = 0.0821 L atm/mol K

T = 303 K

P = 1.50 atm

Solving for V, we get:

V(N₂) = n(N₂)RT/P

V(N₂) = 0.890 mol x 0.0821 L atm/mol K x 303 K / 1.50 atm

V(N₂) = 14.3 L

For H₂ gas:

n(H₂) = 1.780 mol

R = 0.0821 L atm/mol K

T = 303 K

P = 1.50 atm

Solving for V, we get:

V(H₂) = n(H₂)RT/P

V(H₂) = 1.780 mol x 0.0821 L atm/mol K x 303 K / 1.50 atm

V(H₂) = 28.6 L

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At each station, work with a partner to use claim, evidence, and reasoning to determine what the fossil type is at that station. Write your responses on the following lines.

Station 1

Station 2

Station 3

Station 4

Station 5

Choose the station you are most confident about and write your CER for it below. Make sure you separate and label your claim, evidence, and reasoning.

Answers

According to the meaning of a fossil, a fossil is a once-living organism's remains that have been kept by nature

What is a simple definition of a fossil?

A fossil is any conserved remnants, imprint, or evidence of any once-living object from a previous geological era (from the Classical Latin fossilis, lit. "obtained by excavating"). Examples include exoskeletons, bones, shells, animal or microbe impressions in stone, items kept in amber, hair, petrified wood, and Genetic traces. The sum of fossils is known as the fossil record.

The study of fossils, including their age, creation process, and evolutionary importance, is known as palaeontology. If a specimen is more than 10,000 years old, it is typically regarded as a relic.

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A biologist examines a tree in an orchard. Name three structures the biologist can examine to indicate that it is a tree. Name two characteristics the biologist can examine to indicate it is an apple tree

Tree- made of bark, have annual rings, have trunk, produce oxygen

Answers

Two characteristics that will indicate that it is a tree would be the presence of a trunk and roots.

Two characteristics that will indicate it is an apple tree would be the presence of flowers and apple fruits.

Characteristics of trees

Structures to indicate that it is a tree:

Leaves: Trees typically have a branched network of leaves, which are often broad and flat and grow directly from the branches.Roots: Trees have a well-developed root system, which anchors the tree in the ground and absorbs water and nutrients from the soil.Height: Trees are generally tall and have a single main trunk that supports the branches and leaves.

Characteristics to indicate it is an apple tree:

Fruit: Apple trees produce apples, which are round, red or green, and typically have a sweet or sour taste.Flowers: In the spring, apple trees produce white or pink flowers, which bloom in clusters and have a distinctive fragrance.

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What is the pH of water?

A. 7

O

B. 1 x 107

O

C. -7

D. 1 x 107

Answers

Answer: a= 7  

Explanation:

2... The table below shows the results of tests carried out on a salt D. Copy and complete the table. Test (a) (i) D + 10 cm³ of distilled water (ii) Solution D tested with litmus paper (b) (i) D (aq) + NaOH(aq) in drops, then in excess (ii) D (aq) + dil. NH3 solution in drops, then in excess (c) D (aq) + dil. HNO3 + AgNO3(aq) + NH3(aq) (d) Write the formula of the salt. Observation D dissolved to give a colourless solution White gelatinous precipitate Precipitate dissolved No visible reaction.. White precipitate Precipitate dissolved Inference Solution is acidic Zn²+ present​

Answers

The question deals with the process of qualitative analysis and the salt we are to identify is D which is ZnCl2.

What is qualitative analysis of metal ions in chemistry?

Qualitative analysis of metal ions in chemistry is the process of identifying the presence or absence of various metal ions in a given sample through the use of chemical tests. Qualitative analysis is important because it helps to identify the chemical composition of a substance.

We can see that the time that the NaOH(aq) in drops, then in excess was added, there was the appearance of a ppt which is Zn(OH)2. This is going to dissolve in excess.

Addition of  dil. HNO3 + AgNO3(aq) + NH3(aq) would confirm the presence of the chloride anion.

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A pair of students are assigned a project. They are to design a container to put an egg in that will keep the egg from

breaking when dropped from a height of 10 feet. Before they gather materials for their project, describe the steps in the scientific design process that they should perform

Answers

In the egg drop project, Students will apply the principles of momentum and impulse to build housing for an egg survive being dropped from the maximum height possible to solve for momentum and force.

In the egg drop project, there will be several drops from various heights.  The egg must survive lower heights to progress to the highest. Student will try a few smaller heights. Only those who survive that is not leaking the smaller drops may proceed to the higher levels. From this egg drop theory a cracked egg is defined as one that is visibly leaking its contents. After each drop, student must be able to quickly open the container to show the egg. Grade will drop if not able to open quickly and may occur error. The container must be constructed with a hatch or a door so that the egg can be inserted or withdrawn too quickly. From this the momentum and the impulse can be determined.

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what kind of intermolecular forces act between a chloroacetylene molecule and a dichloroethylene molecule?

Answers

The kind of intermolecular forces that act between a chloroacetylene molecule and a dichloroethylene molecule is dipole-dipole and London dispersion forces.

Let's understand this in detail:

1. Intermolecular forces are the forces of attraction or repulsion between molecules. Different types of intermolecular forces exist, such as dipole-dipole forces, London dispersion forces, and hydrogen bonding. These forces play a significant role in determining the physical properties of a substance, such as melting point, boiling point, and vapor pressure.

2. The chloroacetylene molecule and a dichloroethylene molecule are polar molecules with positive and negative ends. The positive and negative ends of the molecules attract each other by a dipole-dipole force.

3. Dipole-dipole forces are the forces of attraction between polar molecules. The strength of these forces depends on the magnitude of the molecule's dipole moment. The larger the dipole moment of the molecule, the stronger the dipole-dipole force.

4. London dispersion forces occur between nonpolar molecules such as dichloroethylene. The molecule's electrons are constantly in motion, and they may be distributed unevenly at any instant. The temporary distribution of electrons creates an instantaneous dipole that attracts neighboring molecules. The instantaneous dipoles fluctuate with time, leading to temporary dipoles in neighboring molecules. The temporary dipoles result in attractive forces between the molecules.

5. In conclusion, the type of intermolecular forces that act between a chloroacetylene molecule and a dichloroethylene molecule is dipole-dipole and London dispersion forces.

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2 C4H10 + 13 O2 ---> 8 CO2 + 10 H2O 5. You have 68.75 g of C4H10 what is the theoretical yield in grams of water?

Answers

The theoretical yield of H2O from 68.75 g of C4H10 is 106.6 g.

What is the molecular theoretical yield of CO2?

We now know that the theoretical yield of CO2 C O 2 is 2.56 mol since the limiting reactant dictates it.

For the combustion of C4H10, the balanced equation is:

2C4H10 + 13O2 → 8CO2 + 10H2O

First, let's calculate the number of moles of C4H10:

molar mass of C4H10 = 4(12.01) + 10(1.01) = 58.12 g/mol

C4H10 mass is equal to its molar mass in C4H10 moles.

moles of C4H10 = 68.75 g / 58.12 g/mol

moles of C4H10 = 1.183 mol

According to the balanced equation, 2 moles of C4H10 produce 10 moles of H2O. As a result, the amount of water generated is:

moles of H2O = (moles of C4H10) x (10 moles H2O / 2 moles C4H10)

moles of H2O = 1.183 mol x 5

moles of H2O = 5.915 mol

The amount of moles of water can finally be converted to grams:

molar mass of H2O = moles of H2O x

mass of H2O = 5.915 mol x 18.02 g/mol

mass of H2O = 106.6 g.

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Help please 25 points !!!

Answers

Overall order of reaction is 2

What is the order of reaction?

The order of a chemical reaction is the relationship between the rate of the reaction and the concentration of the reactants. It is determined experimentally and can be used to predict the rate of a reaction under different conditions.

We know that for A;

4 * 10^-3/2 * 10^-3 = (0.1/0.5)

2= (2^-1)^n

1 = -n

n = -1

For B;

8 * 10^-3/1 * 10^-3 = 0.1/0.05

8 = 2^n

2^3 = 2^n

n = 3

The overall order of the reaction is -1 + 3 = 2

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there are two main reasons that radiocarbon (14c based) age is offset from calendar (true) age. one is that the standard half life adopted is slightly shorter than the correct half life for 14c. what is the other main reason?

Answers

The other main reason that radiocarbon (14C based) age is offset from calendar (true) age is because of variations in the concentration of 14C in the atmosphere over time.

Radiocarbon dating is a technique for determining the age of an object by measuring the quantity of the radioactive isotopes of carbon contained within it. It relies on a specific natural decay process of the radioactive isotope carbon-14 (14C) into stable carbon isotopes.

Carbon-14 (14C) is a radioactive isotope that is created in the Earth's upper atmosphere when cosmic rays collide with nitrogen atoms. This is followed by the decay of 14C into stable nitrogen, with a half-life of 5,700 years.

As a result, living organisms absorb 14C as they consume carbon-containing food. When an organism dies, it no longer consumes carbon, and the 14C in its tissues starts to decay.

By measuring the ratio of 14C to stable carbon isotopes in the remains, scientists can determine the age of the organism or object.

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In which of the following reactions is mass and/or
charge not conserved?
A) H₂O → H+ + OH-
B) CIO2 + 2 H2O + 4e → Cl- + 4 OH-
C) H2SO4 + NaOH → Na2SO4 + H+ + 2 OH-
D) ZnCl + H₂O → ZnOH + H+ + Cl−
E) none of the above

Answers

Answer:

The answer is E) none of the above.

In all of the given reactions, mass and charge are conserved. The law of conservation of mass states that the mass of reactants must be equal to the mass of the products in a chemical reaction. The law of conservation of charge states that the total charge of the reactants must be equal to the total charge of the products.

In reaction A, the water molecule dissociates into a hydrogen ion (H+) and a hydroxide ion (OH-), but the total mass and charge are still conserved.

In reaction B, the reduction of CIO2 to Cl- is balanced by the oxidation of water to form OH-. The electrons and charge are conserved.

In reaction C, H2SO4 reacts with NaOH to form Na2SO4, H+ and OH-. The mass and charge are conserved.

In reaction D, ZnCl reacts with water to form ZnOH, H+ and Cl-. The mass and charge are also conserved.

Please Help
1. Convert 1.65 moles of magnesium chloride to grams
2. how many moles are in 100 grams of methane (CH4) ​

Answers

Answer:

157 grams magnesium chloride

Explanation:

1.  We must first find the molar mass (g/mole) of magnesium chloride.  The molecular formula is MgCl2.

Add the elemental atromic weights for one molecule of the material:

1 Mg = 24.3

2 Cl = 2*(35.45) = 70.9

Total = 95.2 grams/mole

We can use this as a conversion factor by multiplying it times the moles we are asked to convert:  (1.65 moles MgCl2)*(95.2 grams/mole MgCl2).

The moles cancel, leaving us with 157 grams of magnesium chloride.

In a calorimeter, 30 g of ice absorbs heat with an enthalpy of fusion of 334 J/g.


What is the heat absorbed in kJ?


Convert your answer to kJ and round to two decimal places.


Enter the number only; no units

Answers

The heat absorbed by 30 g of ice absorbs heat with an enthalpy of fusion of 334 J/g in a calorimeter is 10.02kJ.

Given the mass of ice (m) = 30g

The enthalpy of fusion (L) = 334J/g

Let the heat absorbed = Q

We know that in calorimetry, the heat absorbed is equal to the product of mass of substance and its enthalpy of fusion.

According to the above given details,

Q = m * L

Q = 30 * 334 = 10,020J = 10.02kJ

Enthalpy of fusion is the amount of energy required to convert a substance from its solid state to its liquid state at a constant pressure.

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An element has two stable isotopes. One
has a mass of 106.91 amu and is
51.839% abundant. The second has a
mass of 108.90 amu and is 48.161%
abundant.
What is the identity of this element?
1. Silver 2. Sodium
3. Oxygen 4. Fluoride
Enter the answer choice number.

Answers

Answer:

The identity of the element can be determined by comparing the atomic masses of the known isotopes with the atomic masses of the elements listed in the answer choices.

The weighted average atomic mass of the element can be calculated as follows:

(0.51839 × 106.91 amu) + (0.48161 × 108.90 amu) = 107.87 amu

The closest match to this atomic mass is option 1, Silver. The atomic number of silver is 47, which means it has 47 protons in its nucleus. The two stable isotopes of silver are ^107Ag and ^109Ag, which have atomic masses of 106.905 amu and 108.905 amu, respectively. The given atomic masses of the isotopes in the question are not exact matches to the known isotopes of silver, but they are close enough to identify the element as silver.

Therefore, the answer is 1. Silver.

This unit was about forces and motion. We also have connected FORCES AND MOTION to car crashes. In your own words explain how CAR CRASHES are related to BALANCED FORCES AND UNBALANCED FORCES. Your answer needs to include vocabulary like Balanced forces, unbalanced forces, mass, acceleration, speed, and any other important vocabulary you learned during this unit that will help you explain.

Answers

Car crashes are related to balanced and unbalanced forces because the forces acting on a car determine its motion.

Explain balanced forces and unbalanced forces in a car crash?

Balanced forces are those that cancel each other out, resulting in no change in motion, while unbalanced forces cause a change in motion. In the case of a car crash, the forces involved are unbalanced, resulting in a change in motion.

The mass of the car also plays a crucial role in determining the outcome of a car crash. The greater the mass of the car, the more force it will experience during a crash, and the greater the potential for damage. Additionally, the acceleration of the car can impact the severity of the crash. The faster the car is traveling, the greater the force it will experience upon impact, resulting in a more severe crash.

Speed is another important factor that affects car crashes. When a car is traveling at a high speed, it has more kinetic energy, which means it has more potential for causing damage upon impact. The energy of the car is transferred to the object it collides with, which can result in injury or damage.

Overall, car crashes are a result of unbalanced forces acting on a car, which can be influenced by factors such as mass, acceleration, and speed. Understanding these concepts can help us better understand the physics behind car crashes and ultimately lead to safer driving practices.

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4. 35 L of a gas is at 1. 16 atm. What will be its

volume at 1 atm?

k

0 0. 267 L

0 0. 198 L

0. 0185 L

5. 05 L

3. 75 L

Answers

The volume of the gas at 1 atm will be 5.05 L. Option D is correct.

To solve this problem, we can use the combined gas law, which relates the pressure, volume, and temperature of a gas:

P₁V₁/T₁ = P₂V₂/T₂

where P₁, V₁, and T₁ are the initial pressure, volume, and temperature, respectively, and P₂ and V₂ are the final pressure and volume, respectively.

Assuming the temperature is constant, we can rearrange the equation to solve for V₂:

V₂ = (P₁/P₂) × V₁

Plugging in the given values, we get:

V₂ = (1.16 atm/1 atm) × 4.35 L = 5.046 L

Therefore, the volume of the gas at 1 atm will be approximately 5.05 L (rounded to three significant figures).

Hence, D. 5. 05 L is the correct option.

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--The given question is incomplete, the complete question is

"4. 35 L of a gas is at 1. 16 atm. What will be its volume at 1 atm? k A) 0 0. 267 L B) 0 0. 198 L C) 0. 0185 L D) 5. 05 L E) 3. 75 L"--

30 POINTS!!!

describe an electron cloud the name and explain a particular atomic model that use the concept of the electron cloud

written question

Answers

Answer:

Explanation:

Electron clouds are the portion that is found around the nucleus where the probability of electrons getting found is the most. The theory that describes about the electron cloud is quantum mechanical model (Schrodinger atomic model). Schrodinger suggested that the electrons are observed around the nucleus.

Which condition is sufficient to show ABC~QPR?

Answers

For AABC AQPR to be true, the measures of angles A, C, and D must all be equal; in this case, they must all be equal to 81°. Therefore, conditions A, C, and D are sufficient to show that AABC AQPR.

What is angles ?

Angles are points in a plane that are formed when two lines intersect. They can also be formed when one line rotates around a fixed point. Angles are measured in degrees and can be equal to, greater than, or less than a right angle (90°). The four main types of angles are acute (less than 90°), right (90°), obtuse (greater than 90°), and straight (180°). Angles can also be classified as complementary, supplementary, vertical, alternate, and adjacent.

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A chemist produced 26. 75 moles of potassium oxide in the lab. How many particles of potassium ocide is this ?

Answers

In the lab, a chemist created 26.75 moles of potassium oxide. particles of potassium oxide produced by the chemist is 1.610 x

[tex] {10}^{25} [/tex]

To determine the number of particles of potassium oxide, we need to know the Avogadro's number which is 6.022 x

[tex] {10}^{23} [/tex]

particles per mole.

So, we can calculate the number of particles of potassium oxide as follows:

Number of particles = number of moles x Avogadro's number

Number of particles = 26.75 moles x 6.022 x

[tex] {10}^{23} [/tex]

particles/mole

Number of particles = 1.610 x

[tex] {10}^{25} [/tex]

particles

Therefore, there are 1.610 x

[tex] {10}^{25} [/tex]

particles of potassium oxide produced by the chemist.

Avogadro's number is a fundamental constant in chemistry and physics that represents the number of atoms, molecules, or other particles in one mole of a substance.

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Describe how a sample of cobalt chloride crystals, could be made from cobalt oxide and dilute hydrochloric acid.​

Answers

Answer:

To make a sample of cobalt chloride crystals from cobalt oxide and dilute hydrochloric acid, follow the steps below:

Add cobalt oxide to dilute hydrochloric acid in a beaker or flask. Stir the mixture to ensure the cobalt oxide is well distributed in the acid.

Heat the mixture gently, stirring constantly, until all of the cobalt oxide has dissolved in the acid.

Filter the solution to remove any impurities.

Slowly add hot distilled water to the solution, stirring continuously, until the solution is saturated (i.e., no more cobalt chloride can dissolve in the solution).

Set the solution aside to cool. As the solution cools, cobalt chloride crystals will begin to form.

Once the solution has cooled completely, remove the cobalt chloride crystals from the solution using a filter or other method.

Rinse the crystals with distilled water to remove any remaining impurities.

Dry the cobalt chloride crystals thoroughly by placing them on a paper towel or in an oven at low temperature.

Explanation:

4) SiO2 + CSIC + CO Find the theoretical yield of silicon carbide if 50.0 grams of silicon dioxide reacts with 79.1 grams of Carbon.​

Answers

The mass of the Silicon Carbide is  33.3 g using the data that has been presented in the question before us.

What is the stoichiometry?

In a balanced chemical equation, the coefficients in front of the chemical formulas represent the number of moles of each substance that participate in the reaction.

We can see that;

Number of moles of silicon dioxide =  50.0 grams/60 g/mol

= 0.833 moles

Number of moles of Carbon = 79.1 g/12 g/mol = 6.6 moles

Now silicon dioxide is the limiting reactant.

Thus;

The theoretical yield of the silicon carbide is;

0.833 moles * 40 g/mol

= 33.3 g

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How many elements are present in each of the following
(a)HF and HF(b)Co and CO(c)Si and SiO2(d)PoCI2 and POCI3

Answers

There are two elements present in each of the following:

(a) HF and HF = Hydrogen and Fluorine
(b) Co and CO = Cobalt and Carbon Monoxide
(c) Si and SiO2 = Silicon and Silicon Dioxide
(d) PoCI2 and POCI3 = Phosphorus Chloride and Phosphorus Chloride Iodide

(a) HF is the chemical formula for hydrogen fluoride, a colorless gas or a colorless fuming liquid with a pungent odor. It contains one atom of hydrogen and one atom of fluorine, making it a binary compound.

(b) Co is the chemical symbol for cobalt, a hard, lustrous, silver-gray metal. CO is the chemical formula for carbon monoxide, a colorless, odorless gas that is highly toxic. CO contains one atom of carbon and one atom of oxygen, making it a binary compound.

(c) Si is the chemical symbol for silicon, a hard, brittle, crystalline solid with a blue-gray metallic luster. SiO2 is the chemical formula for silicon dioxide, also known as silica, a white or colorless crystalline compound found in many minerals. SiO2 contains one atom of silicon and two atoms of oxygen, making it a ternary compound.

(d) PoCl2 is the chemical formula for polonium dichloride, a yellow solid with a melting point of 60 °C. It contains one atom of polonium and two atoms of chlorine, making it a binary compound. PCl3 is the chemical formula for phosphorus trichloride, a colorless or yellow liquid with a pungent odor. It contains one atom of phosphorus, three atoms of chlorine, and no oxygen, making it a ternary compound. However, the compound POCI3 (phosphoryl chloride) contains one atom of phosphorus, one atom of oxygen, and three atoms of chlorine, making it another ternary compound.

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using an equation, explain how sulphur(iv)oxide reacts with each of the following:
I) potasiumhydroxide solution
II) concentrated trioxonitrate(v) acid​

Answers

I) Sulphur dioxide gas reacts with potassium hydroxide solution in the following equation:

SO2(g) + 2KOH(aq) → K2SO3(aq) + H2O(l)

In this reaction, the sulphur dioxide reacts with the potassium hydroxide to form potassium sulphite and water. The reaction is a neutralization reaction, as the potassium hydroxide is a base and the sulphur dioxide is an acidic oxide.

II) Sulphur dioxide gas reacts with concentrated trioxonitrate(V) acid in the following equation:

SO2(g) + HNO3(l) → H2SO4(l) + NO2(g)

In this reaction, the sulphur dioxide reacts with the concentrated trioxonitrate(V) acid to form sulphuric acid and nitrogen dioxide gas. This is an oxidation-reduction reaction, as the sulphur dioxide is oxidized to sulphuric acid, while the trioxonitrate(V) acid is reduced to nitrogen dioxide gas. The reaction is also exothermic, meaning it releases heat.

Name the product(s) in the reaction. A scientist has 4 pieces of copper. Each piece is a different shape and size (samples A through D). The scientist imagines what a very small piece of sample A would look like if she could see its atoms. She includes 20 copper atoms in the model she draws of this very small piece of sample A. If you were to draw a model of the atoms in a very small piece of sample B, that was the same size as the very small piece from sample A and at the same temperature; which of the following features would be the same in the model of samples A and B.

Answers

Answer:

A answer is write answer

If lon X has a charge of 1+ and lon Y has a charge of 3-, the chemical formula of the
ionic compound they form is

Answers

The name of the ionic compound formed by Ion X and Ion Y would be written as Ion X₃Y.

What is the name of ionic compound they form?

Ion X with a charge of 1+ means that it has lost one electron, while Ion Y with a charge of 3- means that it has gained three electrons.

To form an ionic compound, the ions must combine in such a way that the overall charge of the compound is neutral. This is achieved by combining one Ion X ion with three Ion Y ions, since 1+ charge of Ion X can be balanced by the combined 3- charge of three Ion Y ions.

The chemical formula of the ionic compound formed by Ion X and Ion Y would be written as X⁺¹(Y)³⁻

where;

X represents the Ion X ion and Y represents the Ion Y ion.

So, the name of the ionic compound formed by Ion X and Ion Y would be written as Ion X₃Y.

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An electron in an unknown energy level of a hydrogen atom transitions to the n=2 level and emits a photon with wavelength 410 nm in the process. What was the initial energy level? Use R[infinity]=2. 179×10−18J for the hydrogen atom Rydberg constant. Use h=6. 626×10−34 Js for Planck's constant. Use c=2. 998×108ms for the speed of light. Your answer should be a whole number

Answers

The electron's starting energy level was 1.73.

We can use the energy formula E=hc/λ, where E is the energy of the photon, h is Planck's constant, c is the speed of light, and λ is the wavelength of the photon.

First, let's convert the given wavelength to meters:

λ = 410 nm = 410 × 10⁻⁹ m

Next, we can substitute the given values into the energy formula to find the energy of the emitted photon:

E = (6.626×10⁻³⁴ J s) × (2.998×10⁸ m/s) / (410×10⁻⁹ m) = 4.846×10⁻¹⁹ J

The energy of the emitted photon corresponds to the difference in energy levels between the initial and final states of the electron in the hydrogen atom. We can use the formula for the energy levels of a hydrogen atom: E = -R[infinity] / n², where R[infinity] is the Rydberg constant for hydrogen and n is the principal quantum number.

If the electron transitioned from an initial energy level with principal quantum number n1 to a final energy level with n2 = 2, then we can set up an equation to solve for n1:

E = -R[infinity] × (1/n₂² - 1/n₁²)

Substituting the given values into the equation and solving for n1, we get:

n₁² = (R[infinity] × (1/n₂² - E / R[infinity]))⁻¹ = 3.00

Therefore, the initial energy level of the electron was n1 = √(3) ≈ 1.73 (rounded to the nearest whole number).

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What is the mass of 7.93 * 10 ^ 32 molecules of NH3G (g) at STP?​

Answers

Answer:

This assumes that NH3G is supposed to be NH3.

1.31x10^9 grams of NH3  [Note comment in the Explanation section.]

Explanation:

1)  Determine the molar mass of NH3:  17.0 g/mole

2)  Determine the moles of NH3:

1 mole NH3 = 6.02x10^23 molecules NH3  Use this as a conversion factor.

  (7.93x10^32 molecules NH3)*((1 mole NH3)/(6.02x10^23 molecules NH3)

The molecules NH3 cancel and we're left with moles.

 This is equal to 1.31x10^9 moles!  [Was the exponent for the mass supposed to be 10^23 instead of 10^32?]

3)  Determine the mass of 1.31x10^9 moles of NH3

   (1.31x10^9 moles)*(17.0 g/mole) = 1.31x10^9 grams of NH3

[That is 2,888,055 pounds]

PLEASE HELP

- Share at least one example of each element of conductivity

- Please include key points (about 3) and very briefly share your experience about this activity.

Answers

The ability of a material to carry electricity is referred to as conductivity. Below are some illustrations of various conductivity components:

Excellent conductors: The capacity of free electrons to readily travel through metal makes metals like copper, silver, gold, and aluminum good conductors of electricity.Weak conductors: Insulators such as rubber, glass, plastic, and air are unable to conduct electricity properly because they lack free electrons.Semiconductors: Materials with a medium electrical conductivity, such as silicon, germanium, and gallium arsenide, are utilised in electronic components including transistors and solar cells.MRI machines, particle accelerators, and other devices require superconductors because they can conduct electricity with no resistance at very low temperatures.

ConductivityThe capacity of a material to carry heat or electricity is known as conductivity. High electrical conductivity is a characteristic of electrically good conductors, whereas low electrical conductivity is a characteristic of insulators.For many materials, conductivity is a crucial characteristic since it can impact how well they function in different applications.Due to the existence of free electrons that can easily pass through the metal lattice, metals are normally good conductors of electricity. Because of their ability to transport electrical energy effectively, metals are perfect materials for use in electrical wiring.Insulators, on the other hand, are used to stop the passage of electricity. Examples include electrical insulation materials and protective coatings for electrical lines.

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