Combine the terms that can be combined. Indicate the others in descending powers of x or a.

21. 720 + 40-60-120 + 15 =

24. 3x² - 2xy + 4x²-3xy + y² =

22. 25ab +6a²-3b² +6=

25. 2x + x + 25y-y-4=

23. 3a+2b-3a + 1-3 =

Answer: A. ; [tex]2x-3=7[/tex]

Step-by-step explanation: We are solving for when the value of x is equal to five. Here is proving that the answer to the first question is correct.

[tex]2x-3=7[/tex]

Add 3 to both sides

[tex]2x=10[/tex]

Divide both sides by 2

[tex]x=5[/tex]

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Answer: A

Step-by-step explanation:

When an equation has a solution for x = some number n, that means the equation is true when you substitute for x=n. In this case, n=5, so we substitute x=5 in all 4 equations. We can notice that A yields 2*5-3=7 -> 10-3=7, which is true. Therefore, A yields a solution for x=5. We can also put in x=5 for the other 3 equations and we can spot that the equation does not hold for x=5 for any of them.

As in the given circle, the measure of the value of ∠X is 115°.

Now, let's look at point X. This point is on the same line as point B and is also on the circle. Since the angle subtended by an arc at the center of a circle is twice the angle subtended by the same arc at any point on the circle, we can find the measure of ∠AXB by first finding the measure of arc ACB. Since arc ACB is subtended by ∠AOC, which measures 90°, we can find the measure of arc ACB by subtracting 40° (the measure of ∠ABC) from 90°. Therefore, arc ACB measures 50°. This means that ∠AXB is half the measure of arc ACB, so ∠AXB measures 25°.

Therefore, the measure of ∠X is 180° minus the sum of ∠AXB and ∠ABC, which gives us:

∠X = 180° - (25° + 40°) = 115°.

So, the measure of ∠X is 115°.

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Complete Question:

If O is the center of the circle of the figure and the ∠ABC = 40°, then the measure of ∠X

a) We have f−1(7) = 2.Thus, the value of f-1(7) is 2.

b) We can conclude that f( f−1(−3) ) = f(5) = −3.Thus, the value of f(5) is -3.

(a) Determine f-1(7)Given that f be a one-to-one function and f(2)=7.Since f is one-to-one, there exists a unique inverse function f−1. We have f(2) = 7, hence 2 = f−1(7). Therefore, we have f−1(7) = 2.Thus, the value of f-1(7) is 2.(b) Determine f(5)Given that f be a one-to-one function and f−1(−3) = 5.Since f is one-to-one, there exists a unique inverse function f−1. Hence, f( f−1(x) ) = x and f−1( f(x) ) = x for all x in the domain of f. Also, f(2) = 7, thus f−1(7) = 2. Therefore, we can conclude that f( f−1(−3) ) = f(5) = −3.Thus, the value of f(5) is -3.

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Answer:

124= 100

2,311= 2,300

48= 0

Step-by-step explanation:

Answer:

u=4

Step-by-step explanation:

u+6/12 = 4+6/12 = 10/12 ÷ 2/2 = 5/6

Answer: u = 4

Step-by-step explanation:

Answer:

68

Step-by-step explanation:

The transformation from f(x) to g(x) involves a horizontal shift and a change in the slope of the graph.The function g(x) is obtained from the function f(x) by a vertical shift of 3 units to the left.

Specifically, the denominator of g(x), x+3, represents a horizontal shift of 3 units to the left compared to the denominator of f(x), x. As a result, g(x) is shifted to the left relative to f(x). Furthermore, the shift causes the graph of g(x) to be steeper than that of f(x) at x=0. This is because, for small values of x, the difference between (1)/(x) and (1)/(x+3) becomes larger as x gets smaller. Therefore, the transformation from f(x) to g(x) involves a horizontal shift and a change in the slope of the graph.

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The elevation at point B is 740 ft. So, option B is correct.

The elevation is the height above or below a specified reference point, most frequently a reference geoid, which is a mathematical representation of the Earth's sea level as an equipotential gravitational surface, determines a location's elevation.

There are Four points that are displayed on the given map whose range are from A to D.  There are few additional lines in between these four places. The height between these points and lines is indicated on the map in feet, and from point A onwards there is an elevation difference of 20 feet. Point A is at the 700 ft and there is one more line between A and B, and the elevation difference in between one line is 20. So the elevation difference at point B is = 700 + 20 +20= 740 ft. So, option answer is B.

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The constraint 2X - Y = 0 states that the difference between variable X and twice variable Y must be equal to 0, meaning that X must be exactly twice the value of Y.The correct answer is C. 2X - Y = 0.

This constraint states that the difference between variable X and twice variable Y must be equal to 0. In other words, the value of variable X must be exactly twice the value of variable Y. This can be mathematically represented as 2X - Y = 0, meaning that 2 multiplied by X minus Y must equal 0. To illustrate this, let us assume that the value of variable X is 10 and the value of variable Y is 5. This means that 2X is equal to 20 and Y is equal to 5. When we subtract Y from 2X, we get 20 - 5 = 15. However, since the constraint states that the difference between X and twice Y must equal 0, the value 15 does not satisfy the condition. Therefore, the values of X and Y must be adjusted until the difference between X and twice Y equals 0. To satisfy the constraint, the value of X must be equal to 20 and the value of Y must be equal to 10. This means that X is exactly twice the value of Y, which satisfies the condition set by the constraint 2X - Y = 0.

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The probability that among 10 such cars tested, 3 will average less than 28 miles per gallon, 6 will average from 28 to 32 miles per gallon, and 1 will average more than 32 miles per gallon is given by 0.0020125

Let X be the number of cars among ten that averages less than 28 miles per gallon. Let Y be the number of cars among ten that average from 28 to 32 miles per gallon. Let Z be the number of cars among ten that average more than 32 miles per gallon. We are to find P(X = 3, Y = 6, Z = 1).

Firstly, let us find the probability of getting 3 cars among 10 cars that will average less than 28 miles per gallon.

The probability of getting exactly 3 cars among 10 cars that will average less than 28 miles per gallon is given by the probability mass function:

P(X = 3) = (10C3) (0.4)³ (0.6)⁷
= (10 x 9 x 8 / 3 x 2 x 1) (0.064) (0.096)
= 0.23 (approximately)

Similarly, the probability of getting 6 cars among 10 cars that will average from 28 to 32 miles per gallon is given by the probability mass function:

P(Y = 6) = (10C6) (0.5)⁶ (0.5)⁴
= (10 x 9 x 8 x 7 x 6 x 5 / 6 x 5 x 4 x 3 x 2 x 1) (0.156) (0.063)
= 0.25 (approximately)

Finally, the probability of getting 1 car among 10 cars that will average more than 32 miles per gallon is given by the probability mass function:
P(Z = 1) = (10C1) (0.1)¹ (0.9)⁹
= (10) (0.1) (0.348)
= 0.035

Therefore, the answer is:
P(X = 3, Y = 6, Z = 1) = P(X = 3) P(Y = 6) P(Z = 1)
= 0.23 x 0.25 x 0.035
= 0.0020125 (approximately)

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a. The utility of going to Western is 6.4/10

b. The utility of going to York would also be 5.15/10

Decision theory is a branch of mathematics that deals with decision making in the face of uncertainty.

a. If Martha accepts the early admission offer from Western, her utility would be 5/10, since that is the utility of going to Queens.

If Martha waits and gets admitted to Queens, her utility would be 5/10 as well, since that is the utility of going to Queens.

If Martha waits and gets admitted to UTM, her utility would be 9/10.

The probability of getting admitted to Queens is 1, since she is guaranteed admission. The probability of getting admitted to UTM is 6/10. The probability of accepting the early admission offer from Western is 4/10, since it is the complement of the probability of getting admitted to UTM.

Therefore, the expected utility of waiting is ⇒ (1 * 5/10) + (6/10 * 9/10) = 8.4/10. The expected utility of accepting the early admission offer is

⇒ (4/10 * 5/10) = 2/10.

Since Martha is indifferent between the two options, the utility of going to Western is 8.4/10 - 2/10 = 6.4/10

b. If Martha is indifferent between accepting an early-admissions offer from York and gambling on a 3/4 chance at going to Western vs. a 1/4 chance of having to go to Queens, then the utility of going to York must be the same as the expected utility of gambling.

If Martha gambles, her expected utility would be (3/4 * 6.4/10) + (1/4 * 5/10) = 5.15/10.

Therefore, the utility of going to York would also be 5.15/10.

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According the question given above the area of ABK is  100 square cm.

a) ACD = 50 square cm

b)AMCN = 225 square cm

c)ABK = 100 square cm

a) Tο calculate ACD, we need tο use the fοrmula fοr the area οf a trapezοid, which is:

Area = (base1 + base2) × height ÷ 2

Since CD is twice the length οf AB, we can let AB = x and CD = 2x. Let's alsο call the height οf the trapezοid h.

Then we have:

450 = (AB + CD) × h ÷ 2

450 = (x + 2x) × h ÷ 2

450 = 3xh ÷ 2

300 = 3xh

100 = xh

Nοw, we can use the fact that MA = MB tο find the area οf triangle ACD:

ACD = AB × h ÷ 2

ACD = xh ÷ 2

ACD = 100 ÷ 2

ACD = 50 square cm

b) Tο calculate AMCN, we need tο first find the length οf MN. Since MA = MB and NC = ND, we can use the fact that οppοsite sides οf a trapezοid are parallel tο find that AMCN is a parallelοgram. Therefοre, MN is equal tο AB.

Using the fοrmula fοr the area οf a parallelοgram, which is base × height, we have:

AMCN = AB × CD

AMCN = x × 2x

[tex]AMCN = 2x^2[/tex]

AMCN = 900 ÷ 2

AMCN = 225 square cm

c) Tο find the area οf triangle ABK, we need tο find the length οf BK. Since AB = x and CD = 2x, we knοw that AK and KC are alsο equal tο x. Therefοre, BK is equal tο DA, which is 2x.

Using the fοrmula fοr the area οf a triangle, which is base × height ÷ 2, we have:

ABK = AB × BK ÷ 2

ABK = x × 2x ÷ 2

[tex]ABK = x^2[/tex]

ABK = 100 square cm

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From the given data, the test statistic is -2.052 and the p-value is 0.0461. The correct answer is option 5.

To perform a two independent samples t-test, we can use the following formula to calculate the test statistic:

t = (x₁ - x₂) / (s_p × √(1/n₁ + 1/n₂))

where x₁ and x₂ are the sample means, n₁ and n₂ are the sample sizes, s_p is the pooled standard deviation, calculated as:

s_p = √(((n₁ - 1) × s₁² + (n₂ - 1) × s₂²) / (n₁ + n₁ - 2))

Let's calculate the test statistic:

x₁ = 60.345, s₁ = 10.8968, n₁ = 25

x₂ = 67.635, s₂ = 12.936, n₂ = 20

s_p = √(((25 - 1) × 10.8968² + (20 - 1) × 12.936²) / (25 + 20 - 2)) = 11.8074

t = (60.345 - 67.635) / (11.8074 × √(1/25 + 1/20)) = -2.052

The degrees of freedom for the t-distribution can be calculated as:

df = n₁ + n₂ - 2 = 43

Using a two-tailed t-test at a significance level of 0.05, the critical t-value is ±2.016.

The p-value for the test is the probability of obtaining a t-value as extreme or more extreme than the calculated t-value, assuming the null hypothesis is true. Since the calculated t-value is outside the critical region (|t| > 2.016), the p-value is less than 0.05 and we can reject the null hypothesis in favor of the alternative hypothesis.

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Answer:

210°

Step-by-step explanation:

Measure of unknown arc = Measure of full circle - Measure of given arc

= 360° - 150°

= 210° --- Option D

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Thanks.

Answer:

Let's assume Karl rents the bike for x hours. Then the cost of renting the bike can be expressed as:

Cost = 7x + 9.5

We know that the maximum cost Karl can afford is $55. So we can set up an equation:

7x + 9.5 ≤ 55

Subtracting 9.5 from both sides:

7x ≤ 45.5

Dividing both sides by 7:

x ≤ 6.5

Since Karl can only rent the bike for whole hours, the maximum number of hours he can rent the bike is 6 hours (which costs $49 plus the $9.5 flat fee, for a total of $58.5). If he rented it for 7 hours, it would cost $60.5, which is over his budget.

After calculating, Bert will move 720 meters when paddling across the lake at one-third of his top speed for 8 minutes.

Considering that Bert's maximum speed is 270 meters per minute, then his speed when he is paddling at one-third of his top speed is:

270 m/min * (1/3) = 90 m/min

If he is paddling at this speed for 8 minutes, then the distance that he covers is:

distance = speed * time = 90 m/min * 8 min = 720 meters

Therefore, Bert will move 720 meters when paddling across the lake at one-third of his top speed for 8 minutes.

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As a result, the arithmetic progression's first term is 22 and its first fifteen terms add up to 735. The AP's initial term is 22 and its first fifteen terms add up to 735.

The total of the first seven terms is seventy-five.

The formulae for the nth term and the sum of an arithmetic progression can be used to solve the issue.

We have the following using the nth term formula:

a + 5d = 37\s(6/2)(2a + 5d) = 147

3a + 15d = 147\sa + 5d = 49

We may find a by substituting d into either equation and finding:

a + 5(-3) = 37\sa = 22

Hence, the first term of the arithmetic progression is 22 and the formula for the total of the first fifteen terms is (15/2)(2a + 14d) = 735.

(15/2)(2(22) + 14(-3)) = 735

If we simplify, we get:

15 terms added together is 735

As a result, the AP's first term is 22 and its first fifteen terms add up to 735.

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The probability of the fifth job being the first one that is forced to wait for a second quantum is 0.0266.

Probability is the measure of the likelihood of an event occurring. It is expressed as a number between 0 and 1, where 0 indicates impossibility and 1 indicates certainty. Probability is calculated by taking all possible outcomes into consideration and then dividing the number of favourable outcomes by the total number of possible outcomes.

The probability that an arriving job is forced to wait for a second quantum is the probability of that job requiring more than 100ms of CPU time. This probability can be calculated by taking the cumulative distribution function of the exponential distribution and subtracting the probability of the job requiring 100ms or less of CPU time. The probability of the job requiring more than 100ms of CPU time is 0.6853.

This probability can be calculated by taking the probability of the first four jobs requiring less than 100ms of CPU time and multiplying it by the probability of the fifth job requiring more than 100ms of CPU time.

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Answer:

B.) x(x+2)

Step-by-step explanation:

Hope this helps! :)

Answer: The radius of a circle is half of its diameter. Therefore, if the diameter of the circle is 3 cm, then the radius is 1.5 cm.

To set a pair of compasses to draw a circle with diameter 3 cm, open the compasses to a distance of 1.5 cm (which is the radius of the circle). The correct diagram in the link provided shows the compasses set to the correct radius.

So its A

The radius of the circle is 1.5cm.

A circle's diameter is divided in half by its radius. Thus, if the circle's diameter is 3 cm, the radius is:

radius = diameter/2 = 3cm/2 = 1.5cm

Any circular object's radius is the measurement from the centre to its outermost border or boundary. A radius is a dimension that applies to spheres, semispheres, cones with circular bases, and cylinders with circular bases in addition to circles.

It is possible to define a circle as the locus of a point travelling on a plane while maintaining a constant distance from a fixed point. The radius of a circle is the distance from any point on the circle to its centre. The fixed point is referred to as the centre of the circle.

The distance along a line drawn between two points on a circle and through the centre of the circle is the diameter of the circle. It is equivalent to double the circle's radius. It is typically indicated with a d or a D.

Diameter = 2 x Radius

Or

Radius = diameter / 2.

The circle's longest chord equals its diameter.

Moreover, we may relate a circle's area and circumference to its diameter.

Circle circumference equals (Diameter)

Circle area equals /4 (Diameter[tex])^2.[/tex]

from the question;

A circle's diameter is divided in half by its radius. Thus, if the circle's diameter is 3 cm, the radius is:

radius = diameter/2 = 3cm/2 = 1.5cm

Therefore, the radius of the circle is 1.5cm.

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The speed at which the driver travelled the 175 miles in 5 hours is  35 miles/hour.

The speed can be calculated by dividing the distance travelled (175 miles) by the amount of time taken (5 hours).

Formula: Speed = Distance/Time

Speed = 175/5 = 35 miles/hour

Therefore, my speed was 35 miles/hour.

To calculate the speed, the formula mentioned above is used. The formula states that speed is equal to the distance travelled divided by the amount of time taken. In this case, the distance travelled was 175 miles, and the time taken was 5 hours. When the distance travelled is divided by the time taken, the result is 35 miles/hour. This is the speed at which the driver travelled the 175 miles in 5 hours.

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Answer:

103

Step-by-step explanation:

157-54= 103

Answer: 103

Step-by-step explanation:

subtract 54 from 157

Answer:

Step-by-step explanation:

You can do 6x+the number of the amount of squares. Then find find the units of the square unit.

Step-by-step explanation:

(a + 1/a)³ = a³ + 3a + 3/a + 1/a³

We are given that a + 1/a = 4, so we can substitute that into the identity and simplify:

(a + 1/a)³ = (4)³ = 64

a³ + 3a + 3/a + 1/a³ = 64

a³ + 1/a³ + 3(a + 1/a) = 64

a³ + 1/a³ + 3(4) = 64

a³ + 1/a³ = 52

Therefore, we have proved that a³ + 1/a³ = 52 when a + 1/a = 4.

Therefore, it will take about 11 years for the account value to reach 5100 dollars.

Percent is a way of expressing a quantity as a fraction of 100. The symbol "%" is used to represent percent. For example, if we say that an interest rate is 5%, it means that the interest is 5/100 or 0.05 as a decimal. Percentages are commonly used in finance, economics, and everyday life to express rates, proportions, and changes in quantities.

Here,

We can use the formula for compound interest to solve this problem:

A = P(1 + r/n)ⁿˣ

where A is the amount of money in the account after x years, P is the principal amount (initial deposit), r is the annual interest rate (as a decimal), n is the number of times the interest is compounded per year, and x is the time (in years).

We are given that P = 2100, r = 0.05, and we want to find the value of x when A = 5100. Let's assume that the interest is compounded annually (n = 1). Substituting the given values into the formula, we get:

5100 = 2100(1 + 0.05)ˣ

Dividing both sides by 2100, we get:

(1 + 0.05)ˣ = 5100/2100

Simplifying the right-hand side, we get:

(1 + 0.05)ˣ = 2.42857

Taking the natural logarithm of both sides, we get:

ln(1 + 0.05)ˣ = ln 2.42857

Using the power rule of logarithms, we can simplify the left-hand side:

x ln(1 + 0.05) = ln 2.42857

Dividing both sides by ln(1 + 0.05), we get:

x= ln 2.42857 / ln(1 + 0.05)

Using a calculator, we get:

x≈ 11.4

Rounding this to the nearest year, we get:

x ≈ 11 years

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Answer:

plot the point at -3

Step-by-step explanation:

-3 is 6 points away from t and 4 away from s. thus 3/5

The pοpulatiοn οf the bacteria after 5 days is 96.

An expοnential functiοn is a mathematical functiοn οf the fοrm f(x) = ab^x, where a and b are cοnstants, and x is a variable. The base, b, is a pοsitive number, typically greater than 1, that determines hοw quickly the functiοn grοws οr decays. The expοnent, x, is the independent variable, and represents the pοwer tο which the base is raised.

Tο find the pοpulatiοn οf the bacteria after 5 days, we need tο substitute t = 5 intο the given functiοn:

p(5) = 3(2)⁵

Simplifying the expressiοn, we get:

p(5) = 3(32)

p(5) = 96

Therefοre, the pοpulatiοn οf the bacteria after 5 days is 96.

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1.   If the first envelοpe cοntains the largest amοunt, then yοu take it and stοp. The prοbability οf this happening is 1/4.

Prοbability is the study οf the chances οf οccurrence οf a result, which are οbtained by the ratiο between favοrable cases and pοssible cases.

a) If yοu take the first envelοpe, the prοbability that it cοntains the largest amοunt is 1/4.

b) If yοu οpen the first envelοpe, nοte that it cοntains the amοunt x, and take the next amοunt which is larger than x (if nο such amοunt shοws up, yοu must take the last envelοpe), the prοbability that yοu get the largest amοunt is 1/3.

Tο see why, cοnsider the fοllοwing cases:

2.   If the first envelοpe dοes nοt cοntain the largest amοunt, but the secοnd envelοpe dοes, then yοu discard the first envelοpe and take the secοnd οne. The prοbability οf this happening is (3/4) x (1/3) = 1/4.

3.   If the first twο envelοpes dο nοt cοntain the largest amοunt, but the third οne dοes, then yοu discard the first twο envelοpes and take the third οne. The prοbability οf this happening is (3/4) x (2/3) x (1/2) = 1/4.

4.   If the first three envelοpes dο nοt cοntain the largest amοunt, then yοu must take the last envelοpe, which has the largest amοunt with prοbability 1/4.

c) If yοu οpen the first twο envelοpes, call the amοunts x and y, and discard bοth and take the next amοunt that is larger than bοth x and y, the prοbability that yοu get the largest amοunt is 1/2.

Tο see why, cοnsider the fοllοwing cases:

1.   If the largest amοunt is in the first twο envelοpes, then yοu must take the last twο envelοpes, and the prοbability οf getting the largest amοunt is 1/2.

2.   If the largest amοunt is nοt in the first twο envelοpes, then yοu must take the third οr fοurth envelοpe, and the prοbability οf getting the largest amοunt is 1/2.

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The maximum profit of $3330 can be obtained by manufacturing 80 model A motors and 70 model B motors.

Let A and B denote the number of model A and model B motors to be manufactured, respectively. The goal is to maximize the total profit, which is given by the expression 22A + 15B

The given constraints imply that [tex]$3A + 2B \le 240$, $2A + B \le 210$, and $1.5A + 0.5B \le 120$.[/tex]

We can solve this problem using linear programming. Let P = 22A + 15B denote the total profit. Then, the optimization problem can be written as follows:

Maximize P = 22A + 15B

Subject to [tex]$3A + 2B \le 240$, $2A + B \le 210$, and $1.5A + 0.5B \le 120$.[/tex]

Using the Simplex Method, we obtain the optimal solution: A = 80, B = 70, and P = 2280 + 1050 = 3330$. This implies that the maximum profit is 3330, which is obtained by manufacturing 80 model A motors and 70 model B motors.

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