Conner plans to plow a field in one day. Before lunch he plows 15 acres, which is 30% of the field. Howmany acres will he have to plow after lunch in order to finish the field?

Answers

Answer 1

Solution:

Let the total field to plow be 100 %

According to the question,

The field plowed before lunch is shown below:

15 acres field = 30%

30 % field = 15 acres

1 % field = 15/30 acres

The field plow after lunch is 70%.

[tex]\begin{gathered} 70\text{ \% of field = }\frac{15}{30}\times70 \\ =35\text{ acres} \end{gathered}[/tex]

Final Answer:

Therefore, the field to plow after lunch in order to finish the field is 35 acres.


Related Questions

what is the nessecary information you need to know about a cube?

Answers

Answer: the width, length and height

Step-by-step explanation: multiply the width length and height of a cube and you get the area

Suppose that the future price p(t) of a certain item is given by the following exponential function. In this function, p(t) is measured in dollars and t is the number of years from today. p(t) = 3000 * (1.019) ^ t

Answers

Explanation

The growth or decay of an original quantity C that increases or decreases in a p% per year after t years is given by the following equation:

[tex]p(t)=C\cdot(1\pm\frac{p}{100})^t[/tex]

If the quantity increases (i.e. it growths) we use the + symbol inside the parenthesis. If the quantity decreases we use the - symbol. This implies that for a growth the term that is raised to t is greater than 1 and for a decay that term is smaller than 1.

Now let's compare that generic equation with the function given by the question:

[tex]3000\cdot(1.019)^t=C\cdot(1\pm\frac{p}{100})^t[/tex]

One of the first things you can notice is that C=3000 which means that the initial price was $3000. Just to be sure that this is correct we can evaluate p(t) at t=0:

[tex]p(0)=3000\cdot(1.019)^0=3000[/tex]

So the initial price was $3000.

Now let's compare the terms inside parenthesis that are raised to t:

[tex]1.019=1\pm\frac{p}{100}[/tex]

As I stated before, if the term raised to t is greater than 1 then we are talking about a growth. 1.019 is greater than 1 so this function represents a growth. What's more, in the right side of the equation we must use the + symbol. This way we have an equation for the yearly percentage of change of the price:

[tex]1.019=1+\frac{p}{100}[/tex]

We can substract 1 from both sides of this equation:

[tex]\begin{gathered} 1.019-1=1+\frac{p}{100}-1 \\ 0.019=\frac{p}{100} \end{gathered}[/tex]

And we multiply both sides by 100:

[tex]\begin{gathered} 100\cdot0.019=\frac{p}{100}\cdot100 \\ 1.9=p \end{gathered}[/tex]

So each year the price increases in a 1.9%.

Answer

Then the answers in order are:

$3000

growth

1.9%

14#An ecologist randomly samples 12 plants of a specific species and measures their heights. He finds that this sample has a mean of 14 cm and a standard deviation of 4 cm. If we assume that the height measurements are normally distributed, find a 95% confidence interval for the mean height of all plants of this species. Give the lower limit and upper limit of the 95% confidence interval. Carry your intermediate computations to at least three decimal places. Round your answers to one decimal place. (If necessary, consult a list of formulas.)Lower limit:Upper limit:

Answers

Answer:

Lower limit: 11.7 cm

Upper limit: 16.263

Explanation:

The formula to find the lower and upper limits of the confidence interval (given the data is normally distributed) is :

[tex]CI=\mu\pm Z^*\frac{\sigma}{\sqrt{n}}[/tex]

Where:

• μ = sample mean

,

• σ = sample standard deviation

,

• Z* = critical value of the z-distribution

,

• n = is the sample size

In this case:

• μ = 14cm

• σ = 4cm

,

• n = 12

The critical value of the z-distribution for a confidence interval of 95% is Z* = 1.96

Now, we can use the formula above to find the upper and lower limit:

[tex]CI=14\pm1.96\cdot\frac{4}{\sqrt{12}}=14\pm\frac{98\sqrt{3}}{75}=\frac{1050\pm98\sqrt{3}}{75}[/tex]

Thus:

[tex]Lower\text{ }limit=\frac{1050-98\sqrt{3}}{75}\approx11.736cm[/tex][tex]Upper\text{ }limit=\frac{1050-98\sqrt{3}}{75}\approx16.263cm[/tex]

Rounded to one decimal:

Lower limit: 11.7cm

Upper limit: 16.3cm

Question 5 of 10 Solve the proportion below. 23 A 6 B. 8 C. 9 D.

Answers

[tex]\frac{x}{12.6}=\frac{45}{63}[/tex]

solve for x

[tex]\begin{gathered} 12.6\times\frac{x}{12.6}=\frac{5}{7}\times12.6 \\ x=\frac{63}{7}=9 \end{gathered}[/tex]

answer: C. 9

7(x+2)=

4(x+4)=

9(x+6)=

Answers

Answer:

Step-by-step explanation:

7(x+2) = 7x+14

7(x+2)=7x+7 times 2

4(x+4)= 4x+16

4 times x = 4x

4 times 4 = 16

= 4x+16

9(x+6) = 9x+54

9 times x = 9x

9 times 6 = 54

= 9x+54

Find the mean for this set of data. Write your answer as a decimal roundedto the nearest TENTH.32, 23, 34, 29, 15, 17, 23

Answers

Given:

The set of data is given as

[tex]32,23,34,29,15,17,23[/tex]

Required:

To find the mean.

Formula:

[tex]\text{Mean(}\bar{\text{X}})=\frac{\Sigma x}{n}[/tex]

Explanation:

Mean is the ratio of the sum of the values and the number of values.

No of values in the given data is 7.

[tex]n=7[/tex][tex]\begin{gathered} \text{Mean}=\frac{32+23+34+29+15+17+23}{7} \\ =\frac{173}{7} \\ =24.7 \end{gathered}[/tex]

Final Answer:

[tex]\text{Mean}=24.7[/tex]

A square pyramid has a volume of 108 cubic feet and a height of 4 feet.What is the length of each side of the base of the pyramid?A 4 ftOLOB. 9 ftC. 18 ftD. 27 ftO E. 81 ftHelp please very hard

Answers

okay so the answer is 9ft so option B

now we can take a look at how we arrived to that answer

do you know the formula for the volume?

Vincent turned his head 30° to the side. Which of the following shows the angle that he turned his head?

Answers

Given data:

Vincent turned his head 30° to the side.

The figure in the option b is the angle that he turned his head.

Lindsay gets paid $15 per hour at her job. If we let s be her salary and h be the number of hours she has worked, write an equation that represents the direct variation.

Answers

A linear function or a direct variation function is represented by:

[tex]y=kx[/tex]

where k is the constant rate of chante, in this case $15 per hour.

s=y= salary of Lindsay

h=x= hours she has worked

Then, the equation that represents the situation would be:

[tex]s=15h[/tex]

2)Find the missing coordinate (5, 7) and (8,y); m= 4/3​

Answers

Answer:

y = 11

Step-by-step explanation:

Hello!

We can utilize the slope formula to create the equation for y:

[tex]\frac{y - 7}{8 - 5} = \frac{4}{3}[/tex]

Solve for y[tex]\frac{y - 7}{8 - 5} = \frac{4}{3}[/tex][tex]\frac{y - 7}{3} = \frac{4}{3}[/tex]               => Simplifyy - 7 = 4              => Multiply both sides by 3y = 11                   => Add 7 to both sides

The value of y is 11.

write an expression such that if you apply the distributive property to your expression it would give the same result presented. 8x + 12

Answers

Solution:

Let's find a expression such that if you apply the distributive property to your expression it would give the same result presented:

• 8x + 12 = 2 (4x + 6)

,

• 8x + 12 = 4 (2x + 3)

,

• 8x + 12 = 8 (x + 1.5)

Any of these expressions could be the solution to the question.

I need help solving
This problem

Answers

Weight required to destroy a bridge cable (in ponds) The type of variable is Nominal Categorical

A frequently used category variable is gender. Categorical variables can either be ordinal or numeric.

The closing price (in dollars) of the stock is a quantitative variable, and since the price involves an absolute zero, the scale of measurement is a ratio scale

Pounds is what type of variable?

Weight is a prime example of a ratio variable (e.g., in pounds). With certainty, we may state that 20 pounds weigh twice as much as 10 pounds. Ratio variables also have an important zero-point (e.g., exactly 0 pounds means the object has no weight)..

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What is the distance between (-5, 5) and (1, -2)

Answers

Answer:

[tex]\displaystyle d=\sqrt{85}\text{, or about 9.22 units}[/tex]

Step-by-step explanation:

          We will use the distance formula to solve.

[tex]\displaystyle d=\sqrt{(x_{2}-x_{1})^2 +(y_{2}-y_{1})^2}[/tex]

[tex]\displaystyle d=\sqrt{(1--5)^2 +(-2-5)^2}[/tex]

[tex]\displaystyle d=\sqrt{(6)^2 +(-7)^2}[/tex]

[tex]\displaystyle d=\sqrt{36+49}[/tex]

[tex]\displaystyle d=\sqrt{85}\text{, or about 9.22 units}[/tex]

Read more about using the distance formula here: https://brainly.com/question/15691280

6. Refer to the graph in question 5A) graph -f(x)B) graph f(x) -2

Answers

Given the graph of f(x):

Where the points A, B, and C have the coordinates:

[tex]\begin{gathered} A=(0,-2) \\ B=(3,2) \\ C=(5,2) \end{gathered}[/tex]

Now, the transformation -f(x) is just a reflection about the x-axis. This is equivalent to a change of sign on the y-coordinate. The new points A', B', and C' are:

[tex]\begin{gathered} A^{\prime}=(0,2) \\ B^{\prime}=(3,-2) \\ C^{\prime}=(5,-2) \end{gathered}[/tex]

And the graph looks like this:

Now, for the f(x) - 2 transformation, we see that this is just a shift of 2 units down. Then:

Where:

[tex]\begin{gathered} A^{\prime}^{\prime}=(0,-4) \\ B^{\prime}^{\prime}=(3,0) \\ C^{\prime}^{\prime}=(5,0) \end{gathered}[/tex]

Translate into a number sentence7. Four less than seven is greater than zero

Answers

In order to translate the words into a number sentence, first let's translate each word or expression separately:

Four less than seven: "7 - 4"

Is greater than: ">"

Zero: "0"

Therefore the number sentence will be:

[tex]7-4>0[/tex]

7.2. I have a question about advanced trig equations that I really need help with picture included

Answers

[tex]\theta=\frac{\pi}{6},\: \theta=\frac{11\pi}{6}[/tex]

1) Let's start out isolating the cosine by dividing both sides by 2

[tex]\begin{gathered} 2\cos \mleft(\theta\mright)=\sqrt{3} \\ \frac{2\cos\left(θ\right)}{2}=\frac{\sqrt{3}}{2} \\ \cos \mleft(\theta\mright)=\frac{\sqrt{3}}{2} \\ \end{gathered}[/tex]

2) From that we can find two general solutions in which the cosine of theta yields the square root of 3 over two:

[tex]\begin{gathered} \cos (30^{\circ})or\cos (\frac{\pi}{6})\text{ and }cos(330^{\circ}or\frac{11}{6}\pi)=\frac{\sqrt[]{3}}{2} \\ \theta=\frac{\pi}{6}+2\pi n,\: \theta=\frac{11\pi}{6}+2\pi n \end{gathered}[/tex]

But not that there is a restraint, so we can write out the solution as:

[tex]\theta=\frac{\pi}{6},\: \theta=\frac{11\pi}{6}[/tex]

60 cars to 24 cars The percent of change is

Answers

We can calculate the percent of change by means of the following formula:

[tex]change=\frac{x2-x1}{x1}\times100[/tex]

Where x2 is the new value and x1 is the original value.

In this case, we go from 60 to 24, then the original value (x1) was 60 and the new value (x2) is 24, by replacing these values into the above equation, we get:

[tex]change=\frac{24-60}{60}\times100=-60[/tex]

Then, the percent of change equals -60%

A whole pizza is cut into twelfths. If Dexter eats 1/2 of the pizza and Landry eats 1/3 of the pizza, then 3 what fraction of the pizza remains?

Answers

Explanation

Step 1

Let

A whole pizza = 1 pizza

Dexter eats 1/2

Landry eats 1/3

x= fraction of the pizza remains

Step 2

the r

0 1 2 3 4 5 6 7 8 9 100 1 2 3 4 5 6 7 8 9 100 1 2 3 4 5 6 7 8 9 10401234 5 6 7 8 9 10OB.C.OD. +Reset Selection

Answers

Okay, here we have this:

Considering the provided inequation, we are going to identify how can be represented on a number line, so we obtain the following:

So the first thing we will do is factor to find the solution intervals, we have:

[tex]\begin{gathered} 3x^2-27x\leq0 \\ x(x-9)\leq0 \\ 0\leq x\leq9 \end{gathered}[/tex]

According to this, we finally obtain that the solution interval is option D, because it satisfies the found interval and its endpoints are closed.

Add.

47+13

Enter your answer as a fraction in simplest form by filling in the boxes.

Answers

Answer: 47+13 =60

60 as a fraction should be 3/5 in simplest form.

Step-by-step explanation:

True or False? Every rectangle is a parallelogram. Every rhombus is a parallelogram. Every quadrilateral is a square. Every rectangle with four congruent sides is a square. X S True O False True O False O True False O True O False ?

Answers

Given: Different statement relating different quadrilateral

To Determine: If true or false statement

Solution

The image below summarizes the properties of a quadrilateral

From the above, we can conclude that

What is the low end value, high end value, and does it have an outlier

Answers

Solution;

Given the results:

From the above data:

A) The low-end value is

[tex]0[/tex]

B) The high end value is

[tex]95[/tex]

C) Does this data set have outlier?

[tex]Yes[/tex]

D) Outlier:

[tex]95[/tex]

Write the nth rule for the following geometric sequence. Then find the fifth term. (you are given the first term and the common ratio)1-

Answers

The formula for determining the nth term of a geometric sequence is expressed as

Tn = ar^(n - 1)

Where

a represents the first term

r represents the common ratio.

n represents the number of terms

From the information given,

a = 2, r = 3

Thus, the rule for the nth term of the geometric sequence is

Tn = 2 x 3^(n - 1)

To determine the fifth term, we would substitute n = 5 into the equation. It becomes

T5 = 2 x 3^(5 - 1)

T5 = 2 x 3^4

T5 = 162

The fifth term is 162

In Abc,AB=5 feet and BC=3 feet.Which inequality represents all possible values for the length of AC,in feet?

Answers

The smallest value of length AC would be 5 ft - 3 ft = 2 ft while the largest length would be 5 ft + 3 ft = 8ft. The answer will be

2 < Ac < 8

DATE IN OUT IN OUT HOURS TEMPORARY EMPLOYEE TIME CARD NAME: Eugene Mueller 8/8 7:00 4:10 8/9 6:50 11:00 DEPT Sales 8/10 8/11 12:00 4:35 Note: No overtime rate. 10:55 3:25 EMPLOYEE SIGNATURE RATE per hour: $8.50 TOTAL HOURS:

Answers

[tex]\begin{gathered} we\text{ have to count how many hours Eugene worked during his morning's shifts and during afternoon shifts} \\ \text{morning shifts:} \\ 4h\text{ and 15 minutes} \\ 4h\text{ and 10 minutes} \\ 4h\text{ and 36 min} \\ 4h \\ 3h\text{ and 50 min} \\ \text{So we have that during morning shifts he worked} \\ 4h+4h+4h+4h+3h\text{ =21h} \\ 15\min +10\min +36\min +50\min =111\min =\text{ 1h and 51 min } \\ so\text{ in the morning shifts 22h and 51 min } \\ \text{afternoon shifts } \\ 4h \\ 4h\text{ and 10 min} \\ 3h\text{ 24 min} \\ 4h\text{ and 35 min} \\ 3h\text{ and 44 min} \\ so\text{ in total } \\ 4h+4h+3h+4h+3h=18h \\ 10\min \text{ + 24min+35min+44min=113min=1h +53 min} \\ so\text{ in the afternoon shifts he worked 19h and 53 min } \\ so\text{ in total} \\ 22h+19h=41h \\ 51\min \text{ + 53 min =104 min =1h 44min} \\ he\text{ worked 42h and 44 min and that is 42.75 h} \end{gathered}[/tex]

Solve the inequality -30 10-40x and write the solution using:
Inequality Notation:

Answers

Answer:

Step-by-step explanation:

If a red and a blue fair six sided die are rolled what is the probability the result is 8 or divisible by 3?

Answers

SOLUTION:

Step 1:

In this question, we are given that;

If a red and a blue fair six-sided die are rolled.

What is the probability the result is 8 or divisible by 3?

Step 2:

The table for the two dice rolled together is as shown below:

Green 1 2 3 4 5 6

Red

1 2 3 4 5 6 7

2 3 4 5 6 7 8

3 4 5 6 7 8 9

4 5 6 7 8 9 10

5 6 7 8 9 10 11

6 7 8 9 10 11 12

Step 3:

The probability that the result is 8 =

[tex]\begin{gathered} =\text{ }\frac{\nu mber\text{ of 8}}{\text{Total number }} \\ =\text{ }\frac{5}{36} \end{gathered}[/tex]

Next,

The probability that the result is divisible by 3

=

[tex]\frac{12}{36}[/tex]

Finally, the probability that the result is 8 or divisible by 3, we have that:

[tex]\frac{5}{36}+\frac{12}{36}\text{ =}\frac{17}{36}[/tex]



A major record label has seen its annual profit decrease in recent years. In 2011, the label's profit was $128 million. By 2015, the label's profit had decreased by 30%.What was the record label company's profit in 2015? million dollars   Suppose the record label wants to increase its profit to $128 million by 2017. By what percent must the label's profit increase from its 2015 value to reach $128 million within the next two years? %

Answers

the company's profit in 2015 was $89,600,000 (89.6 million dollars)

43%

Explanation:

Profit in 2011 = $128 million

Profit in 2015 decreased by 30%

% decrease = (old price - new price)/old price

old price = Profit in 2011 , new price = Profit in 2015

30% = (128,000,000 - new price)/128000000

[tex]\begin{gathered} 30percent=\text{ }\frac{128,000,000 -newprice}{128000000} \\ 0.30\text{ = }\frac{128,000,000-newprice}{128000000} \\ \text{cross multiply:} \\ 0.3(128,000,000)\text{ = }128,000,000-newprice \end{gathered}[/tex][tex]\begin{gathered} 38400000\text{ = }128,000,000-newprice \\ \text{subtract }38400000\text{ from both sides:} \\ 38400000-\text{ }38400000\text{ = }128,000,000-38400000-newprice \\ \text{0 = 89600000 }-newprice \\ newprice\text{ = 89600000 } \end{gathered}[/tex]

Hence, the company's profit in 2015 was $89,600,000 (89.6 million dollars)

Percentage increase = (new price - old price)/old price

new price = 128million dollars , old price = 89.6 million dollars

% increase = [(128 - 89.6)in millions/(89.6) in millions] × 100

% increase = 38.4/89.6 × 100

% increase = 0.43 × 100

% increase = 43%

Hence, the label's profit must increase by 43% from its 2015 value to reach $128 million within the next two years

Fifth grade > Y.5 Compare and convert Which is more, 1/2 of a pound or 6 ounces? of a pound 2. 6 ounces neither; they are equal Submit

Answers

We should know that :

1 pound = 16 ounces

The question is :

Which is more, 1/2 of a pound or 6 ounces?

so,

1/2 of a pound = 1/2 x 16 = 8 ounces

So,

8 ounces > 6 ounces

so, the answer is option 1

The more is 1/2 of a pound

Write an equation of the line with the given slope and y-intercept.
Slope
1
6
, y−intercept (0, −2)

Answers

The equation of line is [tex]6y=6x$-$12[/tex].

The given slope is [tex]\frac{1}{6}[/tex].

The [tex]y $-$[/tex]intercept is [tex](0, $-$2)[/tex].

We have to write the equation of line using the given slope and [tex]y $-$[/tex]intercept.

The equation of line with the slope m and [tex]y $-$[/tex]intercept of [tex](0,a)[/tex] is [tex]y=mx+a[/tex].

From the question,

The value of  [tex]m=\frac{1}{6}[/tex]

The value of [tex]a= $-$2[/tex]

Now putting the value of [tex]m[/tex] and [tex]a[/tex] in the equation of line.

[tex]y=\frac{1}{6}x+( $-$2)\\y=\frac{1}{6}x$-$2[/tex]

Multiply by [tex]6[/tex] on both side

[tex]y\times6=6\times(\frac{1}{6}x$-$2)\\6y=6\times\frac{1}{6}x$-$6\times2\\6y=6x$-$12[/tex]

The equation of line is [tex]6y=6x$-$12[/tex].

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