Consider a 2D plate with surface area A = 100 cm2
that we charge with a certain
charge Q. How large does Q need to be for the field of the plate to levitate a load of m = 100 kg
that has charge q = 25 µC?

R = R1 + R2 + R3

This is the formula for resistance in a series circuit.

Answer:

There are 640 acres in 1 square mile I think

These mudflows are called Lahar.

A quickly moving mixture of rock debris and water that begins on a volcano's slopes is referred to as a lahar in Indonesian. Other names for lahars are volcanic mudflows and debris floods. The size, pace, and volume of material transported by a moving lahar can constantly alter as it rushes downstream. It resembles a swirling slurry of wet concrete.

The melting of snow and ice as well as the ingestion of river or lake water by the moving slurry may both add to its water consumption. A lahar's starting flow may be quite tiny, but as it entrains and integrates everything in its path, including rocks, dirt, vegetation, even structures like houses and bridges, it may increase in volume.

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The number of electrons that must be removed from object A and placed on object B is 1.24 * [tex]10^{19}[/tex]

We know that,

E = k [tex]q_{1}[/tex] [tex]q_{2}[/tex] / r²

where,

E = Electrostatic force

k = Coulomb's constant

[tex]q_{1}[/tex], [tex]q_{2}[/tex] = Point charges

r = Distance between two charges

Given that,

[tex]q_{1}[/tex] = 2 + ne C

[tex]q_{2}[/tex] = - 2 - ne C

r = 3 cm

k = 9 * [tex]10^{9}[/tex] N m² / C²

E = - 68 N ( Since it is attractive )

- 68 = 9 * [tex]10^{9}[/tex] ( 2 - ne ) ( - 2 + ne ) / ( 3 * [tex]10^{-2}[/tex] )²

68 * [tex]10^{-4}[/tex] / 3 * [tex]10^{9}[/tex] = ( 2 - ne )²

2.27 * [tex]10^{-12}[/tex] = ( 2 - ne )²

1.5 * [tex]10^{-6}[/tex] = 2 - ne

ne = 1.98

n = 1.98 / 1.6 * [tex]10^{-19}[/tex] = 1.24 * [tex]10^{19}[/tex]

The given problem is an electrostatic attractive force because the two point charges are unlike charges. If the charges are like, then the electrostatic force will be repulsive.

Therefore, the number of electrons that must be removed from object A and placed on object B is 1.24 * [tex]10^{19}[/tex]

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Answer: The world population increased from 1 billion in 1800 to around 8 billion today. The world population growth rate declined from around 2% per year 50

Explanation:

Baseball will  hit the wall due to less height from the The Green Monster  wall.

from the data, we have in

velocity of x direction is 25 m/s

velocity of y direction is 20.5 m/s

now, the horizontally:

velocity=distance/time

time=distance/velocity

time=94.5/25

t=3.76sec

now for vertically: we will apply kinematics equation

s=ut+[tex]\frac{at^2}{2}[/tex]

now putting the values,

s=77.08-69.27

s=7.80m

now,

the initial height from baseball hit=0.9m

now, total height=0.9+7.80

s=8.7

8.7 m is less than wall height

so it will hit the wall

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If the voltage of the power supply is increased by a factor of 3 and the resistance was held constant, the new current will be 0.008 A or 8 mA

Power is the rate at which work is done. Electrical power is measured in Watt.

Given that a circuit is wired with a power supply, a resistor and an ammeter (for measuring current). The ammeter reads a current of 24 mA Determine the new current if the voltage of the power supply was increased by a factor of 3 and the resistance was held constant

Let the

From the power formula, power will always be constant. That is, initial power will be the same with new power

Since P = IV

24/1000 V = I × 3V

0.024V = 3IV

V cancels out

3I = 0.024

I = 0.024/3

I = 0.008 A

Therefore, the new current will be 0.008 A.

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Answer:

(a) The electric potential at a point midway between the charges is 160 V.

(b) The potential energy of the pair of charges is -2.4x10⁻⁷ J.

What is electrical potential energy?

The effort necessary to assemble a system of point charges by bringing them close together, as in the system from an infinite distance, is defined as the electric potential energy of the system. Alternatively, the electric potential energy of any given charge or system of charges is defined as the total work performed by an external agent in moving the charge or system of charges from infinity to the current configuration without acceleration.

Explanation:

The electric potential at a point between two point charges Q₁ = +6.00nC and Q₂ = -2.00 nC separated by 45.0 cm is found to be 160 V and the potential energy of the pair of charges is -2.4 x 10⁻⁷ J.

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That would be the proportion between the difference and the total of the two amplitudes (when they are in phase, or as they say, "add coherently") (when they are out of phase or "add destructively").

The amplitude of a wave is the maximum displacement of a particle on the medium from its rest point. The distance between the rest and the crest can be thought of as the amplitude. Measuring the amplitude from the rest position to the trough position is another method of determining it.

The height between the center line and the peak is known as the amplitude (or to the trough). Alternatively, we might multiply the height from highest to lowest places by 2.

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Answer: a place in space where gravity pulls so much that even light can not get out.

Answer:

black holes are holes that can suck this world with its high gravity

Answer:

There are a few ways that traffic lights can sense the presence of a car. One way is by using inductive loops that are installed on the road. These loops detect changes in the magnetic field caused by a car passing over them. Another way is by using infrared sensors that detect the heat signature of a car.

Explanation:

Hope this helps!

The final speed of the race car, given the data is 49 m/s (Option C)

The acceleration of an object is defined as the rate of change of velocity which time. It is expressed as

a = (v – u) / t

Where

With the above formula, we can determine the final velocity of the car. Details below:

a = (v – u) / t

0.8 = (v – 33) / 20

Cross multiply

v – 33 = 0.8 × 20

v – 33 = 16

Collect like terms

v = 16 + 33

v = 49 m/s

Thus, the final velocity of the car is 49 m/s (Option C)

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Answer:

The speed of the boat, in m/s, with respect to Earth, is vBE = 7.52 m/s.

Explanation:

vBE = vBW + vWE

vBE = 7.18 m/s + 2.29 m/s

vBE = 7.52 m/s

The skateboarder will travel a distance of 9.19 m

We know that,

a = ( v - u ) / t

Δv = ( v + u ) / 2 ( If acceleration is constant )

Δv = d / t

where,

a = Acceleration

v= Final velocity

u = Initial velocity

t = Time taken

d = Displacement

Δv = Average velocity

Given that,

u = 1.8 m / s

a = 1.5 m / s²

t = 2.5 s

a = ( v - u ) / t

1.5 = ( v - 1.8 ) / 2.5

v = 3.75 + 1.8

v = 5.55 m / s

Δv = ( 5.55 + 1.8 ) / 2

Δv  = 3.675 m / s

d = Δv * t = 3.675 * 2.5

d = 9.19 m

If the initial and final velocity is known, average velocity can be calculated by taking the average value of initial and final velocity, if the acceleration is constant.

Therefore, the skateboarder will travel a distance of 9.19 m

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The resultant displacement is 32.4 m due west of south.

The term displacement has to do with the change in the position of a body in a particular direction. Displacement is a vector quantity. We have to find the resultant displacement algebraically;

Hence;

Resultant displacement = √((26.5)^2 + 18.7)^2

Resultant displacement = 32.4 m due west of south

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Answer:

ok

Explanation:

je cuene8snw72me8rntirn3ue 2 eje eue due rbd

There are many reasons. The easiest solution is because the rain that we remember acidic has a low pH; it has a better amount of hydrogen ions.

Acid rain manipulation implies three adjustments a notably extra complicated and cumbersome regulatory program beneath the Clean Air Act, new emission manipulation prices for initial rollback requirements and next offsets, and on account of these, new impediments to utility and commercial plant creation, expansion, and modernization.

The Acid Rain application (ARP) has brought widespread discounts in sulfur dioxide (SO2) and nitrogen oxide (NOX) emissions from fossil fuel-fired strength flora, full-size environmental and human fitness blessings, and a ways lower-than-anticipated prices.

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The force exerted at the bottom of the swimming pool is 6.42 × 10⁶ N.m².

The length of the swimming pool is l = 28.5 m.

The breadth of the swimming pool is b = 10 m.

Then the area of the swimming pool is:

A = l × b

A = 28.5 m × 10 m

A = 285 m²

The depth of the pool is h = 2.30 m

The pressure exerted at the bottom of the pool is equal to the density of water.

P = ρ × g × h

P = 1000 kg/m³ × 9.8 m/s² × 2.30 m

P = 22540 N

Therefore, the force exerted by the water at the bottom of the swimming pool is:

F = P × A

F = 22540 × 285

F = 6.42 × 10⁶ N.m²

Hence, the force exerted on the bottom is 6.42 × 10⁶ N.m².

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The horizontal distance d in meters between the waiter and the diner at the time the cork reaches where the diner had previously been sitting is 9.7 m

The term distance refers to the quantity of length between two points. it is usually measured in meters but has other units.

Given data

u = 15.6

∅ = 78.5 deg

g = 9.81

t = 2 * u * sin ∅ / g

t = 2 * 15.6 * sin 78.5 / 9.81

t = 30.57 / 9.81

t = 3.12 s

d = u * co ∅ * t

d = 15.6 * cos 78.5 * 3.12

d = 9.7 m

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complete question

The cork from a champagne bottle slips through the hands of a waiter opening it, moving with an initial velocity v0 = 15.6 m/s at an angle θ = 78.5° above horizontal. A diner is sitting a horizontal distance d away when this happens. Assume the cork leaves the waiter’s hands at the same vertical level as the diner and that the cork falls back to this vertical level when it reaches the diner. Use a Cartesian coordinate system with the origin at the cork's initial position.

Calculate the time, td in seconds, for the cork to reach the diner.

Reacting quickly to avoid being struck, the diner moves 2.00 m horizontally directly toward the waiter opening the champagne bottle. Determine the horizontal distance, d in meters, between the waiter and the diner at the time the cork reaches where the diner had previously been sitting.

Distance is the overall motion of an object with no regard to its path. we can define distance as how much floor an item has included no matter it's beginning or ending point.

Given,

Distance = 100km

             =100000

Speed =100m/sec

Distance=speed × time

Time= [tex]\frac{distance}{speed}[/tex]

Time =100000/100

time =1000 sec

Distance is a numerical or on occasion qualitative size of how far apart items or factors are. In physics or regular usage, the space might also check with a physical length or an estimation primarily based on other standards.

Displacement is described because of the alternate the function of an item. it's miles a vector amount and has a course and value. it's miles represented as an arrow that points from the beginning role to the very last function. as an example- If an item moves from A role to B, then the item's function modifications.

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Answer:An antenna is an array of conductors, that is connected to the receiver or transmitter.

It transmits and receives radio waves in the horizontal directions or in a particular direction.

It may include a parasitic elements, and reflectors that can serve to direct the radio waves into a beam like pattern or some other patter.

Explanation:

It will not capture modulated radio waves.

(a) The position-time equations for fishing boat is x = 3.4t + 40.8

(b) The time taken for the speedboat to catch up with the fishing boat is 7.1 seconds.

The position-time equations for fishing boat will be obtained by applying the principle of relative velocity as follows;

Let the time when the speedboat catches up = t

let the total time spent by fishing boat = t + 12

x = 3.4(t + 12)

x = 3.4t + 40.8

fishing boat is moving at a constant speed = 3.4 m/s

speed boat started moving 12 seconds later,

distance between the boats = 3.4 m/s  x 12 s = 40.8 m

v = u + at

v = 2.8 + 1.7t

set up the following equation to determine the time when the two boats meet.

vt - x = 40.8

t(2.8 + 1.7t) -  (3.4t + 40.8) = 40.8

2.8t + 1.7t² - 3.4t - 40.8 = 40.8

1.7t² - 0.6t  - 81.6 = 0

solve the quadratic equation using formula method as shown below;

a = 1.7, b = -0.6, c = -81.6

t = 7.1 seconds

Thus, the time taken for the speedboat to catch up with the fishing boat is 7.1 seconds.

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The distance traveled by the object from its initial position is 384 cm.

Distance is the sum of an object's movements, regardless of direction. Without respect to the object's starting or finishing positions, distance can be defined as the amount of space it has traveled.

An object is moving in a straight path.

The speed of the object from its initial position is 12.8 cm/s.

The object is moving for 05 minutes.

Then, t = 0.5 min = 0.5 × 60 = 30 seconds.

Now, the speed of an object is the distance of the object per unit time.

Therefore,

s = d / t

d = s × t

d = ( 12.8 cm/s ) × ( 30 s )

d = 384 cm

Hence, the object's position from its initial position is 384 cm.

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Based on the data attached, the option of the conclusion that could be made from this data is option B. It snows less in Green Bay than in Kalamazoo on average.

.

The term snows is known to be a kind of a small white crystals of ice that is known to be formed as a result of  direct water vapor of the air.

It is known to be a measure or a mass of snowflakes that is said to have  fallen to earth.

Therefore, from the data, one can see that the snow fell a lot in Buffalo and from it one can also see that Kalamazoo has almost times 2 of the snow in Green Bay.

Therefore, Based on the data attached, the option of the conclusion that could be made from this data is option B. It snows less in Green Bay than in Kalamazoo on average.

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Answer: gravity of earth = 9.8 n/s , new weight of the body on other planet = mg = 1.913 ×6×9.8=112..5

Explanation:

The ratio of their amplitudes is 3.

The relation between energy and amplitude is as follows:

[tex]E_{1} = \frac{1}{2} KA_{1} ^{2}[/tex]

[tex]E_{2} =\frac{1}{2} KA_{2} ^{2}[/tex]

As, we know , one oscillation has 3.0 times the energy of a second one of equal frequency and mass i.e.,

[tex]E_{1} = 3E_{2}[/tex]

So, [tex]\frac{1}{2} KA_{1} ^{2} = 3(\frac{1}{2}KA_{2} ^{2} )[/tex]

[tex]A_{1} ^{2} = 3A_{2} ^{2}[/tex]

[tex]\frac{A_{1}^{2} }{A_{2}^{2} } = 3[/tex]

Therefore,  the ratio of their amplitudes is 3.

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Answer:

the magnitude of b 3A

Explanation:

2b 1 a

Answer:

Velocity is distance + direction / time

so your answer is

75 km north / 1.5 hours

75/1.5  km north/ hours =

50 km / hours north

The bike is travelling at 22.5 m/s after 2.5 s

This is defined as the rate of change of velocity which time. It is expressed as

a = (v – u) / t

Where

a = (v – u) / t

a = (15 – 0) / 5

a = 3 m/s²

a = (v – u) / t

3 = (v – 15) / 2.5

Cross multiply

v – 15 = 3 × 2.5

v – 15 = 7.5

Collect like terms

v = 7.5 + 15

v = 22.5 m/s

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