Consider a car of mass m moving with an initial speed Vo on a straight, flat road. At time t=0, the driver fully applies the breaks to avoid colliding with debris in the road in front of the car. The car’s wheels lock, causing the car to slide on the roadway until the car stops, before running over the debris. The distance that the car slides is D. The coefficient of kinetic friction between the car’s tires and the roadway is a constant value of Uk.

A) Sketch a free body diagram for the car sliding to rest and write Fnet equations

A) does the value D increase or decrease with increasing initial speed?

B) does the value D increase or decrease with increasing the coefficient of friction?

C) derive an equation for the acceleration of the car in terms of Uk and physical consonants

Answer:

vector quantity have both magnitude and direction but scalar quantities have only magnitude

Answer:

The acceleration of the car with the mass of 1200kg and a force of 11 × 10³N is 9.17m/s²

Explanation:

Answer:

water pushes against the squid

Answer:

its B hope you have a good Day

[tex]\\ \sf\Rrightarrow s=ut+\dfrac{1}{2}at^2[/tex]

[tex]\\ \sf\Rrightarrow s=0(19)+\dfrac{1}{2}a(19)^2[/tex]

[tex]\\ \sf\Rrightarrow 475=\dfrac{361a}{2}[/tex]

[tex]\\ \sf\Rrightarrow 950=361a[/tex]

[tex]\\ \sf\Rrightarrow a\approx 2.3m/s^2[/tex]

Answer:

B,A,A

Explanation:

Answer:

Other guy is correct b,a,a

Explanation:

1. Frequency

2. Reflected

3. Absorbed

4. Black

Answer:

0/10

Explanation:

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Answer:

No. -infinity/10

Explanation:

Ew. Just why, like no.

Answer:

0.23N for the speed

at the bottom of the circle

Explanation:

For this problem, use the first law of thermodynamics. The change in energy equals the increase in heat energy minus the work done.

ΔU=Q−W

We are not given a value for work, but we can solve for it using the force and distance. Work is the product of force and displacement.

W=FΔx

W=3N×2m

W=6J

Now that we have the value of work done and the value for heat added, we can solve for the total change in energy.

ΔU=Q−W

ΔU=10J−6J

ΔU=4J

Answer is 4J

i think this may help you very much

The impulse of the boxers punch is 28 kgm/s.

The given parameters;

The impulse of the boxers punch is calculated as follows;

[tex]J = Ft[/tex]

where;

The magnitude of the impulse is calculated as follows;

[tex]J = 1400 \times 0.02 \\\\J = 28 \ kg m/s[/tex]

Thus, the impulse of the boxers punch is 28 kgm/s.

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Answer:

a. 2.5 m/s

Explanation:

50 / 20 = 2.5 m/s

Answer:

Explanation:

Volume = Length x width x height

Multiply the length, width and, height to get the volume of the question.

Answer:

Momentum is directly proportional to the object's mass and also its velocity.

Explanation:

Thus the greater an object's mass or the greater its velocity, the greater its momentum. Momentum p is a vector having the same direction as the velocity v.

Answer:

Letter A

Explanation:

Manganese dioxide- Mn02

Nitrogen Dioxide- n02

Strontium bromide- SrBr

During chemical reactions, bonds between atoms break and form Electrical fields of charged particles interact, bonding those with opposite charges.

During chemical reactions, bonds between atoms break and form Electrical fields of charged particles interact, bonding those with opposite charges.

Since we know that every element have electrons in their atoms and every atom have vacant shells.

So during chemical reactions the elements fulfill their vacant shells and form bonds between each other it can be ionic or it can be covalent bond.

But when atoms breaks the bond their will be the positively or negatively charged electrons left in the atoms.

Hence During chemical reactions, bonds between atoms break and form Electrical fields of charged particles interact, bonding those with opposite charges.

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Answer:

it will float up cause its has gravity

When Jacob cuts some holes in the disk and immerses it again in a vessel of water it will now float at the top. Thus, the correct option for this question is A.

An object floats when the weight force on the object is balanced by the upward push of the water on the object. The upwards push of the water increases with the volume of the object that is underwater. It is not affected by the depth of the water or the amount of water.

According to the context of this question, when a disk does not have holes in it, it will definitely sink to the bottom of the water because it has high density, but when the hole is made in the disk, the water is passed out from them and now, the upward force is minimized that cause less density as compared to previous.

Therefore, when Jacob cuts some holes in the disk and immerses it again in a vessel of water it will now float at the top. Thus, the correct option for this question is A.

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#SPJ2

The final speed of the car at the given conditions is 30.1 m/s.

The given parameters:

The change in the energy applied to the car is calculated as;

[tex]\Delta E = E_1 - E_2\\\\\Delta E = 22,000 \ J \ - \ 3,666.67 \ J\\\\\Delta E = 18,333.33 \ J[/tex]

The final speed of the car is calculated as follows;

[tex]\Delta E = \frac{1}{2} m(v_f^2 - v_0^2)\\\\v_f^2 - v_0^2 = \frac{2\Delta E}{m} \\\\v_f^2 = \frac{2\Delta E}{m} + v_0^2\\\\v_f = \sqrt{ \frac{2\Delta E}{m} + v_0^2} \\\\v_f = \sqrt{ \frac{2\times 18,333.4}{1700} + (21)^2} \\\\v_f = 30.1 \ m/s[/tex]

Thus, the final speed of the car at the given conditions is 30.1 m/s.

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73.9m/s (1dp)

1) list everything that you are given using suvat, where s is distance, u is initial velocity(speed), v is final velocity(speed), a is acceleration and t is time

s = 430m

u = 27 m/s

v = ? (we need to work out)

a = 5.5m/s^2

t = (we are not given this value)

2) use an equation that doesn't involve the time

[tex] {v}^{2} = u {}^{2} + 2as[/tex]

3) input the values that we have

[tex] {v}^{2} = ( {27})^{2} + 2(5.5)(430)[/tex]

[tex]v {}^{2} = 5459[/tex]

[tex]v = \sqrt{5459} = 73.9[/tex]

so the answer is 73.9m/s to 1dp

When a log of wood is put over the freshwater, the log start to float. Option B is correct.

Density:

It can be defined as the amount of substance per unit volume. It is usually denoted by D. It is measured in the [tex]\bold { kg/m^3}[/tex].

The less dense object always floats over the more dense substance.

For example- Here, The density of the log is 0.8 [tex]\bold{ cm^3}[/tex] and the density of the of water is 1.0 [tex]\bold{ cm^3}[/tex] .

Since, the density of the log is lesser than the density of the water.

Therefore, when a log of wood is put over the freshwater, the log start to float.

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Answer:

Static= 600/(130*9.8)=0.47

Kinetic=475/(130*9.8)=0.37

Answer:

Explanation:

The speed of the wave given only it's frequency and wavelength can be found by using the formula

[tex]c = f \times \lambda[/tex]

where

c is the velocity of the wave in m/s

[tex] \lambda[/tex] is the wavelength in m

f is the frequency in Hz

From the question we have

c = 8 × 24 = 192

We have the final answer as

Hope this helps you

Answer:

2.1 seconds

Explanation:

let D represent the height in meters

let g represent gravity in meters per second squared

let t represent time in seconds

D= -42 meters (negative because it falls down)

g= -9.8m/s^2

t= [tex]\frac{-42 meters}{9.8 m/s^2}[/tex]

this gives t= 4.2857 s^2

the meter units cancel out in the division

now we must simplify the units to singular seconds so...

[tex]\sqrt{4.3 s^{2} }[/tex] which simplifies to [tex]\sqrt{4.3}[/tex] x [tex]\sqrt{s^{2} }[/tex]

this equals 2.1 seconds

Answer:

Please translate this into Spanish! Sorry I can't :(

Explanation:

Disadvantages of Friction:

Friction produces unnecessary heat leading to the wastage of energy.

The force of friction acts in the opposite direction of motion, so friction slows down the motion of moving objects.

Forest fires are caused due to the friction between tree branches.

Without friction, the car cannot stop...

Newton's second equation of motion :-

S=ut+1/2at^2 [where, u is the initial velocity, a is the acceleration and t is the time interval]

This Equation simply finds a relation between distance travelled by a particle (classically) under uniform acceleration.

So let's see what pieces of information (bundles of equations) do we have with us, initially.

We have, a very primary equation with us,

dS/dt = v… (I)

(Considering motion in a straight line only)

And we also have the equation

dv/dt = a…(II)

Simply replacing the v in eqn (II) by eqn (I), we find

d2S/dt^2 = a…(III)

This is what we need to solve. It's easy.

You know,

d2S/dt^2 = d/dt(dS/dt) = a

⟹ dS/dt = ∫adt = at+c1

Since, dS/dt is the velocity of the particle,

Therefore, at t = 0, dS/dt|t = 0 = u

⟹ u = a∗0 + c1 = c1

⟹ c1 = u

Therefore, dS/dt = u + at

Thus, S = ∫(udt + atdt)

⟹ S = ut + 1/2at^2 +c^2

If say, the particle is already having a displacement S0 the moment you start measuring it's motion. Then, at t = 0, S = S0

This makes S = S0 +ut + 1/2at^2

Since, in most of the practical cases, we start measuring a motion when the particle starts displacing (i.e., when S0=0 ),

We get

S = ut + 1/2at^2

Hope it helps :)

Answer:

Every gas is made up of very small particles called molecules. Molecules of a gas are separated from each other by large distances so that volume is negligible as compared to total volume of gas. The force of gravitation on the molecules is also negligible.

Hope that helps. x

:

Answer:

The golf ball would be revolving around the baseball while the baseball would be revolving around the basketball.

Explanation:

The basketball would be represented as the Sun, the baseball would be represented as the Earth and the golf ball would be represented as the moon. Since the Moon revolves around the Earth and the Earth revolving around the Sun makes a perfect explaination for this question.

Answer:

Water is more dense than air. When water goes through a denser thing, the light is "bent" more towards the "normal" which is a straight, vertical line.

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