Consider these functions:
х
g(x)
h(x)
0
0 0
NO
6
What is the value of x when gh(x)) = 4?
O A 0
OB. 2
OC. 4
OD 5
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Related Questions
Anyone know this? please help and Thank you very much!!!
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[tex](9+7i)(6+3i)\\\\=54+27i + 42i + 21i^2\\\\=54+69i -21~~~;[i^2 =-1]\\\\=33+69i[/tex]
Write the equation for f(x)=x3
after being translated to the left
8 units and up 3 units.
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Using translation concepts, the equation will be given by:
[tex]g(x) = (x + 8)^3 + 3[/tex]
The parent function is:
[tex]f(x) = x^3[/tex]
Shifting a function left 8 units means that [tex]g(x) = f(x + 8)[/tex], hence:
[tex]g(x) = f(x + 8) = (x + 8)^3[/tex]
Shifting a function up 3 units means that 3 is added to the function, that is, [tex]g(x) = f(x + 8) + 3[/tex], hence:
[tex]g(x) = f(x + 8) + 3 = (x + 8)^3 + 3[/tex]
Which is the desired equation.
You can learn more about translation concepts at https://brainly.com/question/4521517
i cant decide if its b or d please help for brainlist !!!!!!!!!!!!!
Answers
This is right answer because option d only shows that y are multiples in sequence but this answer shows the correct sequence
A is correct! Our base number is 9 since it's at x = 0. The number gets smaller as x increases, so it will be 1/3 instead of 3.
Hope this helps :)
150 in product of primes in index form
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Answer:
Step-by-step explanation:
The prime factor representation of 150 is 2 x 3 x 5^2
help pls will mark brainliest if it is correct, its not 72.
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Answer:
52
Step-by-step explanation:
Answer:
52
Step-by-step explanation:
The top has 6 faces, so 6 x 2 = 12
The bottom has the same, 12
The left side has 3, 3 x 2 = 6
The front and inside has 6, x 2 = 12
The right side has 2 x 2 = 4
The back has 3 x 2 = 6
12 + 12 + 6 + 12 + 4 + 6 = 52
1. What is the next number in the pattern below?
0, 5, 11, 18, _____
can someone pls help me with this? Thank you!
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0 to 5 = +5
5 to 11 = +6
11 to 18 = +7
18 to ? = +8
? = 26
write f(2)=3 in coordinate
form (x,y)
Answers
Answer:
Coordinate form is [tex](x,y)=(2,3)[/tex]
Step-by-step explanation:
Usually the form is
[tex]f(x)=y[/tex]
Here
We have [tex]f(2)=3[/tex]
Hence [tex](x,y)=(2,3)[/tex]
Eva is working two summer jobs, making $16 per hour tutoring and $8 per hour clearing tables. Last week Eva worked 3 times as many hours clearing tables as she worked hours tutoring hours and earned a total of $80. Graphically solve a system of equations in order to determine the number of hours Eva worked tutoring last week, x,x, and the number of hours Eva worked clearing tables last week, yy.
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Answer:
48 and 32 6 hours clearing tables and 2 hours tutoring
Step-by-step explanation:
we can rewrite this as a fraction. we will use 1/10s because 80 can be divided by 8 which is in the problem. we then have to find out what two numbers add up to 8 but one is 3 times the other. 6 and 2 fit into this problem so we plug it into the equation and we write it as this 6x+4x=80 where x is 8. we get 48 and 32.
graph -1,-1 on this graph
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Answer:
UP THE DOWN THAT WHAT I GOT
Step-by-step explanation:
A small cup holds 75% as much as a large cup. If the small cup holds 36 units, how much does the large cup hold?
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Answer:
48
Step-by-step explanation:
75/100 = 36/x
x = 48
please help ! 20 pts please
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The given ratios expresses the number of time a value is larger or smaller
than another value.
The correct responses are;
3. (B) 12 and 244. (D) 6, 9, 215. [tex]\underline{(E) \ \displaystyle \frac{11}{2}}[/tex]6. [tex]\underline{(E) \ \displaystyle \frac{5}{14}}[/tex]7. (B) [tex]\overline{EF}[/tex] = 6, [tex]\overline{AC}[/tex] = 9·√58. (C) The values are equal9. (A) The value in column A is greaterReasons:
3. Given that the perimeter of the rectangle = 72
The ratio of the lengths of the sides = 1:2
Let a and b represent the sides, we have;
2·a + 2·b = 72
[tex]\displaystyle \frac{a}{b} = \mathbf{\frac{1}{2}}[/tex]
Which gives;
2·a = b
2·a + 2·(2·a) = 72
6·a = 72
a = 72 ÷ 6 = 12
b = 2·a = 2 × 12 = 24
The lengths of the sides are; (B) 12 and 24
4. Extended ratio = 2:3:7
The perimeter = 36
The lengths of the sides are;
[tex]\displaystyle \frac{2}{2 + 3 + 7} \times 36 = \mathbf{6}[/tex]
[tex]\displaystyle \frac{3}{2 + 3 + 7} \times 36 = \mathbf{9}[/tex]
[tex]\displaystyle \frac{7}{2 + 3 + 7} \times 36 = \mathbf{21}[/tex]
The lengths are; (D) 6, 9, 21
5. The given equation is presented as follows;
[tex]\displaystyle \frac{5}{x + 7} = \mathbf{\frac{3}{x + 2}}[/tex]
5 × (x + 2) = 3 × (x + 7)
5·x + 10 = 3·x + 21
5·x - 3·x = 21 - 10
2·x = 11
[tex]\displaystyle x = \mathbf{ \frac{11}{2}}[/tex]
The correct option is; [tex]\displaystyle \underline{(E) \ \frac{11}{2}}[/tex]
6. The width to length ratio is [tex]\displaystyle \mathbf{\frac{2.5}{7.0}}[/tex]
The simplified ratio is therefore;
[tex]\displaystyle \frac{2.5}{7.0} = \frac{2 \times 2.5}{2 \times 7.0} = \mathbf{\frac{5}{14}}[/tex]
The correct option is (E) [tex]\displaystyle \underline{(E) \ \frac{5}{14}}[/tex]
7. The given ratio of the lengths is 3:1
Therefore;
[tex]\overline{BC}[/tex]:[tex]\overline{EF}[/tex] = 3:1
Which gives;
[tex]\displaystyle \mathbf{\frac{\overline{BC}}{\overline{EF}}} = \frac{3}{1}[/tex]
[tex]\overline{BC}[/tex] = 18
Therefore;
[tex]\displaystyle \frac{18}{\overline{EF}} = \frac{3}{1}[/tex]
18 × 1 = 3 × [tex]\overline{EF}[/tex]
[tex]\displaystyle \overline{EF} = \frac{18 \times 1}{3} = 6[/tex]
[tex]\overline{EF}[/tex] = 6
By Pythagorean theorem, we have;
[tex]\overline{DF}[/tex]² = [tex]\mathbf{\overline{DE}}[/tex]² + [tex]\mathbf{\overline{EF}}[/tex]²
Which gives;
[tex]\overline{DF}[/tex]² = 3² + 6² = 45
[tex]\overline{DF}[/tex] = √(45) = 3·√5
Using the given ratio, we have;
[tex]\overline{AC}[/tex] = 3 × [tex]\mathbf{\overline{DF}}[/tex]
Which gives;
[tex]\overline{AC}[/tex] = 3 × 3·√5 = 9·√5
[tex]\overline{AC}[/tex] = 9·√5
The correct option is; (B) [tex]\overline{EF}[/tex] = 6, [tex]\overline{AC}[/tex] = 9·√5
8. EF = 1, AB = 2
CD = 2, CE = 4
Therefore;
[tex]\displaystyle \mathbf{\frac{EF}{AB}} =\frac{1}{2}[/tex]
[tex]\displaystyle \mathbf{\frac{CD}{CE}} =\frac{2}{4} = \frac{1}{2}[/tex]
Which gives;
[tex]\displaystyle \frac{EF}{AB} =\displaystyle \mathbf{\frac{CD}{CE}}[/tex]
(C) The values are equal
9. AC = 6, BE = 8
DF = 3, BD = 6
Column A
[tex]\displaystyle \frac{AC}{BE} =\displaystyle \mathbf{\frac{6}{8}} = \frac{3}{4}[/tex]
Column B
[tex]\displaystyle \frac{DF}{BD} =\displaystyle \mathbf{\frac{3}{6}} = \frac{1}{2}[/tex]
[tex]\displaystyle \frac{3}{4} > \mathbf{\frac{1}{2}}[/tex]
Therefore;
Column A is greater than column B
(A) The value in column A is greater
Learn more about ratios here:
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HAS ANYONE EVER DONE MARKET DAY AT SCHOOL IT IS SO STRESSFUL HELPPPPP
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Kind of, Market day as in make stuff and then sell it or Market day as in Sell food, I remember this in elementary school 2 Different Kind of Market day :)
solve the system of equations
y =2x -9
y = x - 4
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y=x-4
x-4=2x-9
+9 each side=
x+5=2x
-x each side=
5=x
flip for the final answer of x=5
Shania bought a $1455 drum set on the installment plan. The installment agreement included a 15% down payment and 18 monthly payments of $80.78 each.
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Answer:
A
Step-by-step explanation:
nicole sold half of her comic books then bought 12 more . She now has 25 books. How many did she begin with.
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Find the slope of the line that passes through (-2, -44) and (-1, -70).
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Let m = slope of the line.
m = delta y/delta x
m = (-70 -(-44)/(-1 -(-2)
m = (-70 + 44)/(-1 + 2)
m = -26/1
m = -26
Understand?
What is the Distance formula of (-6, -12) and (4,8)
Distance formula is in picture
Answers
Answer:
The distance formula is 22.360679775
if you round it to the nearest tenth, then the answer is 22.4
Step-by-step explanation:
(-6, -12) and (4,8)
(x2 - x1)² + (y2 - y1)²
Place the x and y values
(4 - - 6)² + (8 - - 12)²
= 10² + 20²
= 100 + 400 = 500
√500 = 22.360679775
Round it to the nearest tenth and you will get 22.4
Hope this helps!
please mark me as the brainliest
The formula in finding the distance between two points is given below:
[tex] \sf{d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}}[/tex]where:
[tex] \sf{(x_1, y_1) = (-6, -12)}[/tex][tex] \sf{(x_2, y_2) = (4, 8)}[/tex]Substitute the given values into the distance formula and solve for d:
[tex] \sf{d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}}[/tex][tex] \sf{d = \sqrt{[4 - ( - 6)]^2 + [8 - ( - 12)]^2}}[/tex][tex] \sf{d = \sqrt{(10)^2 + (20)^2}}[/tex][tex] \sf{d = \sqrt{100 + 400}}[/tex][tex] \sf{d = \sqrt{500}}[/tex][tex] \bold{d = 22.4 \: units}[/tex]Therefore, the distance between the two points is 22.4 units (nearest tenth).
Cheers!
Solve for b.
r=5(b + a)
help timed
Answers
Answer:
b=(r/5)-a
Step-by-step explanation:
To solve, you do the mathematics.
r=5(b+a)
r=5b+5a
5b=r-5a
b=(r/5)-a
if p(q) = q^2 + 4q − 12,then what is p(−1)?
Answers
Step-by-step:
Plug -1 into the equation in place of q.
p(-1) = (-1)^2 + 4(-1) - 12
p(-1) = (-1)^2 - 4 - 12
p(-1) = (-1)^2 -16
p(-1) = 1 - 16
p(-1) = -15
Step by step solution :
STEP
1
:
Trying to factor by splitting the middle term
1.1 Factoring q2-4q-12
The first term is, q2 its coefficient is 1 .
The middle term is, -4q its coefficient is -4 .
The last term, "the constant", is -12
Step-1 : Multiply the coefficient of the first term by the constant 1 • -12 = -12
Step-2 : Find two factors of -12 whose sum equals the coefficient of the middle term, which is -4 .
-12 + 1 = -11
-6 + 2 = -4 That's it
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -6 and 2
q2 - 6q + 2q - 12
Step-4 : Add up the first 2 terms, pulling out like factors :
q • (q-6)
Add up the last 2 terms, pulling out common factors :
2 • (q-6)
Step-5 : Add up the four terms of step 4 :
(q+2) • (q-6)
Which is the desired factorization
Equation at the end of step
1
:
(q + 2) • (q - 6) = 0
STEP
2
:
Theory - Roots of a product
2.1 A product of several terms equals zero.
When a product of two or more terms equals zero, then at least one of the terms must be zero.
We shall now solve each term = 0 separately
In other words, we are going to solve as many equations as there are terms in the product
Any solution of term = 0 solves product = 0 as well.
Solving a Single Variable Equation:
2.2 Solve : q+2 = 0
Subtract 2 from both sides of the equation :
q = -2
Solving a Single Variable Equation:
2.3 Solve : q-6 = 0
Add 6 to both sides of the equation :
q = 6
Supplement : Solving Quadratic Equation Directly
Solving q2-4q-12 = 0 directly
You roll one die 8 times. What is the probability of rolling exactly six fours
Please convert the fraction into a decimal
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Answer:
4/8 = 1/2 = 0.5 is your answer
Are two similar triangles necessarily congruent? Why?
Answers
if their corresponding angles are congruent and the corresponding sides are in proportion ...so it will be similar triangle
Which of the following expressions are equivalent to 40x+30y choose all that apply
Answers
Answer:
1,390 I think that's the answer
Step-by-step explanation:
hope that helps
The expression equivalent to 40x + 30y are 5(8x + 6y), 10(4x + 3y) and 2(20x + 15y).
What are Expressions?Expressions are mathematical statements which consist of two or more terms and terms are connected to each other using mathematical operators like addition, multiplication, subtraction and so on.
Given are some expressions in the options.
Distributive rule says that,
a ( b + c ) = (a b) + (a c), where a, b and c are any numbers.
5x(8 + 6) = 5x(14) = 70x
5(8x + 6y) = 40x + 30y
10(40x + 30y) = 400x + 300y
10(4x + 3y) = 40x + 30y
2y(20x + 15) = 40xy + 30y
2(20x + 15y) = 40x + 30y
Hence the expressions which are equivalent to 40x + 30y are 5(8x + 6y), 10(4x + 3y) and 2(20x + 15y).
Learn more about Expressions here :
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The complete question is :
Which of the following expressions are equivalent to 40x+30y. Choose all that apply.
5x(8 + 6)
5(8x + 6y)
10(40x + 30y)
10(4x + 3y)
2y(20x + 15)
2(20x + 15y)
answer this please
as percentages
Answers
According to the National Institute of Health, about 37% of high school seniors have vaped in the past year. Suppose that a survey contacts an SRS of 400 high school seniors and calculates the sample proportion, , in this sample who have vaped in the past year. What is the mean of the sampling distribution of ?
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Using the Central Limit Theorem, it is found that the mean of the sampling distribution of sample proportions is 0.37.
The Central Limit Theorem establishes that, for a proportion p in a sample of size n, the sampling distribution of sample proportions has:
Mean [tex]\mu = p[/tex].Standard error [tex]s = \sqrt{\frac{p(1 - p)}{n}}[/tex]For this problem, about 37% of high school seniors have vaped in the past year, hence [tex]p = 0.37[/tex].
Then, the mean of the sampling distribution of sample proportions is 0.37.For more on the Central Limit Theorem, you can check https://brainly.com/question/4086221
Solve using the Quadratic Formula:
a) -7x^2 + 7x + 1 = -8
b) -6x - 1 + 5x^2 = 8x^2
Show your work.
Answers
A. - 7x² + 7x + 1 + 8 = 0
- 7x² + 7x + 9 = 0
x = - b ± √b² - 4ac / 2a
= - 7 ± √7² - 4 (-7) (9) / 2 (-7)
= - 7 ± √49 + 252 / - 14
= - 7 ± √ 301 / - 14
x = - 7 + 17.349 / - 14 x = - 7 - 17.349 / - 14
= 10.349 / - 14 = - 24.349 / - 14
= - 0.739 = - 1.739
B. 8x² - 5x² + 6x + 1 = 0
3x² + 6x + 1 = 0
x = - b ± √b² - 4ac / 2a
= - (-5) ± √-5² - 4 (3) (1) / 2 (3)
= 5 ± √25 - 12 / 6
= 5 ± √ 13 / 6
x = 5 + 3.606 /6 x = - 5 - 3.606 / 6
= 8.606/6 = - 8.606/6
= 1.434. = - 1.434
please re-check the answers hope this helps
A car dealer starts the month with 120 cars. The dealer sells 3 cars each day. The number of cars remaining on any day can by modeled by the function f(x) = 120 - 3x. What should the domain of the function be if you want to know the number of cars remaining on any day during the month? What are the maximum and minimum values during the month?
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The domain of the function to know the number of cars remaining on any day during the month is [0, 40]. The maximum and minimum values are 120 and 0 respectively.
The domain is the all inputted value for which the function is defined. All the x values are domain of a function.
Now, finding the domain of the function,
We know that, the number of cars cannot be negative, so
[tex]f(x)\geq0\\120-3x\geq0\\3x\leq120\\x\leq40[/tex]
The number of cars should be greater than 0, so x > 0.
So, the domain will be [0, 40].
The maximum value is given by putting x = 0,
[tex]f(0)=120-3(0)\\=120[/tex]
The minimum value is given by putting x = 40,
[tex]f(40)=120-3\times40\\=120-120\\=0[/tex]
Therefore, the domain of the function f(x)=120-3x to know the number of cars remaining on any day during the month is [0, 40]. The maximum and minimum values are 120 and 0 respectively.
To learn more about the Domain of Functions visit here:
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trinomios de 6x 2 + 13 x + 5
Answers
Answer:
77
Step-by-step explanation:
6x2 = 12
13x5 = 65
65+12 = 77
The answer is 77.
Xavier's pet turtle laid eggs! So far, only 2 eggs have hatched for every 5 that are unhatched. If Xavier's turtle laid 35 eggs in all, how many eggs have hatched?
Answers
hopefully this helps!
Answer: 21
Step-by-step explanation:
(test question) If you're good at geometry please help me
Answers
Step-by-step explanation:
this is a rectangle. so, all things are symmetric.
EI = IG = FI = IH
IGF = IFG = IEH = IHE
therefore, since EI = FI
2x + 8 = 6x - 20
28 = 4x
x = 7
now,
EG = EI + IG = 2×EI = 2×(2×7 + 8) = 2×22 = 44
IFE is a complementary angle to IFG (together they have 90°).
and because IFG = IGF = 30°
IFE = 90 - 30 = 60°
If f(x) = x2 + x - 8, find f(-3).
Answers
Answer:
-17
Step-by-step explanation:
it's telling you to replace x with -3.
You have to replace all the x's with -3.
(-3)2 + (-3) - 8 = -17