copper has two stable isotopes,and , with masses of 62.939598 amu and 64.927793 amu, respectively. calculate the percent abundances of these isotopes of copper.

Answers

Answer 1

Considering the definition of atomic mass, isotopes and atomic mass of an element,  the isotope with masses of 62.939598 amu and 64.927793 amu have percent abundances of 69.80% and 30.20% respectively.

Definition of atomic mass

The atomic mass (A) is obtained by adding the number of protons and neutrons in a given nucleus of a chemical element.

Definition of isotope

The same chemical element can have the same atomic numbers, but the number of neutrons is different. These atoms are called isotopes of the element.

Definition of atomic mass

The atomic mass of an element is the weighted average mass of its natural isotopes, taking into account the relative abundance of each of them.

Atomic mass of the element in this case

In this case, you know:

The first isotope has an atomic mass of 62.939598 amu and a percent natural abundance of x%. The second isotope has an atomic mass of 64.927793 amu and a percent natural abundance of (100 -x)%.Average mass of copper is 63.54 amu.

The percent abundance can be calculated as:

62.939598 amu× (x%÷100%) + 64.927793 amu× [(100-x)%÷100%]= 63.54 amu

Solving:

62.939598 amu× x+ 64.927793 amu× (1-x)= 63.54 amu

62.939598 amu× x+ 64.927793 amu× 1- 64.927793 amu× x= 63.54 amu

62.939598 amu× x- 64.927793 amu× x= 63.54 amu - 64.927793 amu× 1

-1.988195 amu× x= -1.387793 amu

x= (-1.387793 amu)÷ (-1.988195 amu)

x= 0.6980= 69.80%

Then, (100-x)%= (100 -69.80)%= 30.2%

Finally, the isotope with mass of 62.939598 amu has a percent abundance of 69.80% and the isotope with mass of 64.927793 amu has a percent abundance of 30.20%.

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Related Questions

Identify the element symbol
1s22s22p63s23p64s23d104p65s24d5

Answers

Answer:

Tc

Explanation:

You just have to follow the rows with the exponents. Just remember that when we get to d, the number in the front is a period lower. Hope this helps!

Which two elements do not have a second energy level at all?

Answers

The two elements that do not have a second energy levels are Hydrogen (H) and Helium (He)

Energy levels are nothing but the 3-D spaces around the nucleus of an atom. The electrons revolve around the nucleus in their respective energy levels. Each energy levels can accommodate only a particular number of electrons.

For example, first energy level can accommodate only a maximum of 2 electrons whereas second energy level can accommodate 8 electrons.

Hydrogen has 1 electron and helium has 2 electrons around their respective nucleus. In both hydrogen and helium, electrons are accommodated in the first energy level.

Hence, the two elements that do not have a second energy levels are Hydrogen (H) and Helium (He)

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What type of force would put the soccer ball in motion?
balanced
unbalanced
input
output

Answers

Type of force would put the soccer ball in motion is unbalanced force.

Unbalanced force is  defined as when the net force acting on the object is not equal to zero. The unbalanced force brings an object in motion. while balanced force acting on any object does not change the state of rest or uniform motion. The soccer ball moves from one place to another because unbalanced forces are acting on the soccer ball. this means the resultant force acting on soccer ball is not equal to zero.

Thus, Type of force would put the soccer ball in motion is unbalanced force.

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Answer:

b) Unbalanced force

Explanation:

Unbalanced force is the type of force which puts the soccer ball in motion while kicking it. Hence, option (b) is the correct answer.

What is the mass of 5.36 mol of ammonia
vapor (NH3)?
Answer in units of g.

Answers

Answer:

91.12 gram

Explanation:

Number of moles of Ammonia = 5.36

Molecular Mass of Ammonia = 14 + 3 × 1 = 17 gram/mol

Mass = Number of moles × Molecular mass

Mass = 5.36 mol × 17 gram/mol = 91.12 gram

Put the following elements in order, with the element having the most valence electrons at the top of your list and the element with the fewest valence electrons at the bottom.swap_vertAstatine (At)swap_vertArsenic (As)swap_vertCalcium (Ca)swap_vertSodium (Na)swap_vertOxygen (O)swap_vertSilicon (Si)swap_vertAluminum (Al)

Answers

answer

1. Neon

2. Astatine

3. oxygen

4. Arsenic

5. Silicone

6. Aluminium

7. Calcium

8. Sodium

what are some shared properties of both transition metals and alkali metals.

Answers

Both transition metals and alkali metals are good conductors of heat and electricity, react with water, and are easily oxidized.

What are alkali metals and transition metals?

The alkali metals are elements of group 1 which are lithium (Li), sodium (Na), potassium (K), rubidium (Rb), caesium (Cs), and francium (Fr).  They are also known as the s-block elements because they have their outermost electron in an s-orbital.

The alkali metals are shiny, soft, highly reactive metals and readily lose their outermost electron to create cations with charge +1. They can tarnish rapidly in the air due to oxidation by atmospheric moisture and oxygen.

Transition elements or transition metals are elements that have partially filled d-orbitals. An element having a d-subshell that is partially filled with electrons or can form stable cations with an incompletely filled d orbital.

Any element present in the d-block of the modern periodic table which consists of groups 3 to 12, is considered to be a transition element. For example, the mercury in the +2 oxidation state, corresponds to an electronic configuration of (n-1)d¹⁰. Many paramagnetic compounds are formed by transition metals because they have unpaired electrons in the d orbital.

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a reaction involving acetic acid has an enthalpy change of 55.7 kj/mol. what is the concentration of 27.90-ml of this acetic acid solution if the reaction it is involved in evolves 716.12-j of heat?

Answers

not gon find it here cuh

Explanation:

The concentration of the acetic acid solution is approximately 0.0128 mol/L, given the information provided.

To determine the concentration of the acetic acid solution, we need to use the given enthalpy change and the heat evolved in the reaction.

The enthalpy change (ΔH) is given as 55.7 kJ/mol, which represents the heat released or absorbed per mole of acetic acid involved in the reaction.

The heat evolved in the reaction is given as 716.12 J. However, we need to convert it to kilojoules to match the unit of the enthalpy change. There are 1000 J in 1 kJ, so 716.12 J is equal to 0.71612 kJ.

Now, we can set up a proportion to find the concentration of the acetic acid solution. The heat evolved is directly proportional to the moles of acetic acid involved in the reaction, which is in turn proportional to the concentration of the solution.

Let's assume the concentration of the acetic acid solution is c mol/L.

The proportion can be set up as:

ΔH (kJ/mol) / Heat evolved (kJ) = 1 mol / c L

Substituting the values we have:

55.7 kJ/mol / 0.71612 kJ = 1 mol / c L

Simplifying:

c = 1 mol / (55.7 kJ/0.71612 kJ)

c ≈ 0.0128 mol/L

Therefore, the concentration of the acetic acid solution is approximately 0.0128 mol/L, given the information provided.

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