Create a new Java class called AverageWeight. Create two arrays: an array to hold 3 different names and an array to hold their weights. Use Scanner to prompt for their name and weight and store in correct array. Compute and print the average of the weights entered using printf command. Use a loop to traverse and print the elements of each array or use Arrays class method to print. Submit your code.

//import the Scanner class

import java.util.Scanner;

//begin class definition

public class AverageWeight{

       //declare the main method

    public static void main(String []args){

       //declare the names array

       String [] names = new String [3];

       //declare the weights array

       double [] weights = new double [3];

       //Create an object of the Scanner class

       Scanner input = new Scanner(System.in);

       //create a loop to ask for the names and weights.

       for(int i = 0; i< names.length; i++){

           System.out.println("Enter name " + (i+1));

           names[i] = input.next();

           System.out.println("Enter weight " + (i+1));

           weights[i] = input.nextDouble();

       }

       //find the sum of the weights

       double sum = 0.0;

       for(int j = 0; j< weights.length; j++){

           sum += weights[j];

       }

       //find the average

       double average = sum / weights.length;

       //print out the average of the weights

       System.out.printf("%s%f \n", "The average of the weights is ", average);

       //print out the elements of the names array

       System.out.println("Names : ");

       System.out.print("{ ");

       for(int i = 0; i< names.length; i++){

           System.out.print(names[i] + " ");

       }

       System.out.print(" }");

       //print out the elements of the weights array

       System.out.println();

       System.out.println();

       System.out.println("Weights : ");

       System.out.print("{ ");

       for(int i = 0; i< weights.length; i++){

           System.out.print(weights[i] + " ");

       }

       System.out.print(" }");

    } //end of main method

} //end of class definition

>> Enter name 1

Peter

>> Enter weight 1

12.0

>> Enter name 2

Joe

>> Enter weight 2

23.4

>> Enter name 3

Paul

>> Enter weight 3

23.9

The average of the weights is 19.766667  

Names :  

{ Peter Joe Paul  }

Weights :  

{ 12.0 23.4 23.9  }

The code contains comments explaining important lines.

The source code file has been attached to this response.

A sample output has also been provided.

A pharmaceutical company is going to issue new ID codes to its employees. Each code will have three letters followed by one digit. The letters and and the digits , , , and will not be used. So, there are letters and digits that will be used. Assume that the letters can be repeated. How many employee ID codes can be generated

Please answer it’s timed

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Write a program second.cpp that takes in a sequence of integers, and prints the second largest number and the second smallest number. Note that in the case of repeated numbers, we really mean the second largest and smallest out of the distinct numbers (as seen in the examples below). You may only use the headers: and . Please have the output formatted exactly like the following examples: (the red is user input)

Popular periodicals might include newspapers

True or false?

Write functions to compute a subset, find member, union, and intersection of sets. Follow the steps below:

1. Read two integers from the user.
2. Suppose one of the integers is 2311062158. The binary equivalent of this integer stored in a register will be 1000 1001 1100 0000 0000 0010 1000 1110. This data should be regarded as bit strings representing subsets of the set {1, 2, … 32}. If the bit string has a 1 in position i, then element i is included in the subset. Therefore, the string: 1000 1001 1100 0000 0000 0010 1000 1110 corresponds to the set: {2, 3, 4, 8, 10, 23, 24, 25, 28, 32}.
3. Print out members of the set from smaller to larger. You can do a loop from 1 to 32. Load a masking bit pattern that corresponded to the position number of the loop counter (0x00000001 for 1). Isolate the bit in the operand by using the AND operation. If the result of the AND is not 0 then the loop counter is in the set and should be displayed. Increment the counter and shift the masking bit pattern to the left.
4. Read a number from the user. Determine if that element is a member of the given sets.
5. Determine the union of two sets.
6. Determine the intersection of two sets.
7. Implement a loop back to the main function. See the prompts below: "Enter the first number:" "Enter the second number:" "Members of Set 1:" "Members of Set 2:" "Enter an element to find:" "It is a member/ not a member of set 1" "It is a member/ not a member of set 2" "Union of the sets:" "Intersection of the sets:" "Do you want to compute set functions again?"
8. Test the program using the following data:

Enter the first number: 99999
Enter the second number: 111445
Members of set 1: 1 2 3 4 5 8 10 11 16 17
Members of set 2: 1 3 5 7 9 10 13 14 16 17
Enter an element to find: 7
It is not a member of set 1
It is a member of set 2
Union of the sets: 1 2 3 4 5 7 8 9 10 11 13 14 16 17
Intersection of the sets: 1 3 5 10 16 17

Which of the following describes a characteristic of organic light-emitting diodes (OLEDs) used in clothing?

uniform

flexible

transparent

sizeable

1. A bank customer invested $24 in a bank with 5 percent simple interest per year, write a program the construct a table showing how much money the bank customer would have at the end of each 20- year period starting in 2021 to 2041.

2. A programmer starts with salary of $65,000 and expect to receive $1500 raise each year. Write a program to compute and print the programmer's salary for each of the first 10 years and total amount of money the programmer would receive over the 10- year period.

Code a Python program that uses a graphical user interface (GUI) to address a real-world problem. Within reason, you may choose to address any real-world problem that you would like; however, please only choose a real-world problem that is both safe and legal.

In Python what are the values passed into functions as input called?

Given positive integer n, write a for loop that outputs the even numbers from n down to 0. If n is odd, start with the next lower even number.

Populations are effected by the birth and death rate, as well as the number of people who move in and out each year. The birth rate is the percentage increase of the population due to births and the death rate is the percentage decrease of the population due to deaths. Write a program that displays the size of a population for any number of years. The program should ask for the following data:
• The starting size of a population
• The annual birth rate
• The annual death rate
• The number of years to display
Write a function that calculates the size of the population for a year. The formula is
N = P + BP − DP
where N is the new population size, P is the previous population size, B is the birth rate, and D is the death rate.
Input Validation: Do not accept numbers less than 2 for the starting size. Do not accept negative numbers for birth rate or death rate. Do not accept numbers less than 1 for the number of years.
#include
using namespace std;
double calcOfPopulation(double, double, double);
double inputValidate(double, int);
int main()
{
double P, // population size
B, // birth rate %
D, // death rate %
num_years;
cout << "Starting size of population: ";
P = inputValidate(P, 2);
cout << "Annual birth rate: %";
B = inputValidate(B, 0);
cout << "Annual death rate: %";
D = inputValidate(D, 0);
cout << "Number of years to display: ";
num_years = inputValidate(num_years, 1);
cout << "Population size for "
<< num_years << " years "
<< " = "
<< (calcOfPopulation(P, B, D) * num_years)
<< endl;
return 0;
} // END int main()
double inputValidate(double number, int limit)
{
while(!(cin >> number) || number < limit)
{
cout << "Error. Number must not be "
<< " 0 or greater:";
cin.clear();
cin.ignore(numeric_limits::max(), '\n');
}
return number;
}
double calcOfPopulation(double P, double B, double D)
{
B *= .01; // 3.33% = .0333
D *= .01; // 4.44% = .0444
return P + (B * P) - (D * P);

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