Determine the volume (L) of nitrogen monoxide gas that is created at STP when 32.2 g

of solid copper reacts with excess nitric acid.

3Cu(s) + 8HNO3(aq) — 3Cu(NO3)2 (aq) + 4H2O(1) + 2NO(g)

Answers

Answer 1

Taking into account the reaction stoichiometry and STP conditions, the volume of nitrogen monoxide gas that is created at STP when 32.2 g of solid copper reacts with excess nitric acid is 7.5677 L.

Reaction stoichiometry

The balanced reaction is:

3 Cu(s) + 8 HNO₃(aq) → 3 Cu(NO₃)₂ (aq) + 4 H₂O(l) + 2 NO(g)

By reaction stoichiometry, the following amounts of moles of each compound participate in the reaction:

Cu: 3 molesHNO₃: 8 molesCu(NO₃)₂: 3 molesH₂O: 4 moles NO: 2 moles

The molar mass of the compounds is:

Cu: 63.54 g/moleHNO₃: 63 g/moleCu(NO₃)₂: 187.54 g/moleH₂O: 18 g/moleNO: 30 g/mole

By reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

Cu: 3 moles× 63.54 g/mole= 190.62 gramsHNO₃: 8 moles× 63 g/mole= 504 gramsCu(NO₃)₂: 3 moles ×187.54 g/mole= 562.62 gramsH₂O: 4 moles ×18 g/mole= 72 gramsNO: 2 moles ×30 g/mole= 60 grams

STP conditions

The STP conditions refer to the standard temperature and pressure, which values are 0 °C and 1 atmosphere and are reference values for gases. In these conditions 1 mole of any gas occupies an approximate volume of 22.4 liters.

Moles of NO formed

The following rule of three can be applied: if by reaction stoichiometry 190.62 grams of Cu form 2 moles of NO, 32.2 grams of Cu form how many moles of NO?

moles of NO= (32.2 grams of Cu× 2 moles of NO)÷ 190.62 grams of Cu

moles of NO= 0.3378 moles

Then, 0.3378 moles of NO are formed.

Volume of NO created

Now, you can apply the following rule of three: if by definition of STP conditions 1 mole of NO occupies a volume of 22.4 liters, 0.3378 moles occupies how much volume?

volume= (0.3378 moles× 22.4 L)÷ 1 mole

volume= 7.5677 L

Finally, the volume of NO created is 7.5677 L.

Learn more about the reaction stoichiometry:

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The Story Behind The Snowy Sour
As the air gets cooler and winter creeps in, I’m looking forward to the first snowfall of the season. This cocktail is all you will need to help you through. I took a classic sour cocktail and elevated it with a winter-citrus-infused simple syrup, made by combining clementine, orange, and honey with sugar and water. All the flavors came together really well, and the gin and fresh lemon juice amalgamate beautifully.

Ingredients In The Snowy Sour:

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Shake hard again to create a silky consistency.
Finely strain into your cocktail glass.
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Winter Citrus Simple Syrup Ingredients:
2 ounces clementine juice
2 ounces orange juice
2 ounces honey
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Winter Citrus Simple Syrup Directions:
Combine all ingredients into a small saucepan.
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A compound has the following percentage composition: 40.0% carbon, 6.72% hydrogen, 53.28% oxygen. What is the amount of carbon moles in 200g of the compound?

Answers

Answer:

So we're trying to find the number of carbon moles in the compound. We know that we have 200g of the compound and that 40% of it is Carbon. and 40% of 200 is 80g (change 40% into a decimal and multiply it by 200 and you get 80g)

So 80g of the compound is carbon. In order to find the moles of Carbon, I have to divide the mass by the molar mass of the element.

We know from our periodic table that the molar mass for carbon is 12g/mol

[tex]\frac{80}{12} = 6.67\ mol[/tex]

Therefore we have 6.67 moles of carbon in the compound

Answer:

6.67 moles of carbon in compound

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Which branch of Earth science focuses more specifically on Earth's atmosphere?

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Answer:

Meteorology

Explanation:

Meteorology focuses on Earth's atmosphere and, especially, how changes in the atmosphere affect weather and climate on Earth's surface.

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Answer:

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Which of the following is a completely elastic collision? A. a ball rebounds against a wall, reversing its direction, but at only half the speed. B. Two balls collide, stick to each other, and move together after the collision. C. Two balls collide and move at a right angle to each other after the collision at a reduced speed. D. Two balls collide head on, each reversing its direction and traveling at half the speed. E. A ball with velocity v collides with a ball at rest; after the collision the first ball is at rest and the second ball has velocity v. I will mark brainliest​

Answers

Answer:

Answer E.

For a collision to be completely elastic, there must be NO LOSS in kinetic energy.

We can go through each answer choice:

A. Since the ball rebounds at half the initial speed, there is a loss in kinetic energy. This is NOT an elastic collision.

B. A collision involving sticking is an example of a perfectly INELASTIC collision. This is NOT an elastic collision.

C. A reduced speed indicates that there is a loss of kinetic energy. This is NOT elastic.

D. The balls traveling at half the speed after the collision indicates a loss of kinetic energy, making this collision NOT elastic.

E. This collision indicates an exchange of velocities, characteristic of an elastic collision. We can prove this:

Let:

m = mass of each ball

v = velocity

We have the initial kinetic energy as:

KE = \frac{1}{2}mv^2 + 0 = \frac{1}{2}mv^2KE=21mv2+0=21mv2

And the final as:

KE = 0 + \frac{1}{2}mv^2 = \frac{1}{2}mv^2KE=0+21mv2=21mv2

Answer:

E

Explanation:

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Answer:

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Let's consider the decomposition of ethanol on an alumina surface.

C₂H₅OH(g) ⇒ C₂H₄(g) + H₂O(g)

The plot of [A] vs time (t) resulted in a straight line, which indicates that the reaction follows zero-order kinetics.

The slope, 24.00 × 10²⁵ M/s, represents the rate constant, k.

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The integrated rate law for zero-order kinetics is:

[C₂H₅OH]t = [C₂H₅OH]₀ - 24.00 × 10²⁵ M/s × t

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Is the time for the amount of substance to decrease by half.

If the initial concentration of C₂H₅OH was 1.25 × 10²² M, we can calculate the half-life [t(1/2)] using the following formula.

t(1/2) = [C₂H₅OH]₀ / 2 × k

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We can calculate the time required for all the 1.25 × 10²² M C₂H₅OH to decompose using the integrated rate law.

[C₂H₅OH]t = [C₂H₅OH]₀ - 24.00 × 10²⁵ M/s × t

0 M = 1.25 × 10²² M - 24.00 × 10²⁵ M/s × t

t = 5.21 × 10⁻⁵ s

The rate constant for the decomposition of ethanol on an alumina surface is 24.00 × 10²⁵ M.

The rate law is: rate = 24.00 × 10²⁵ M/s

The integrated rate law is: [C₂H₅OH]t = [C₂H₅OH]₀ - 24.00 × 10²⁵ M/s × t

If the initial concentration of C₂H₅OH was 1.25 × 10²² M, the half-life is 2.60 × 10⁻⁵ s.

The time required for all the 1.25 × 10²² M C₂H₅OH to decompose is 5.21 × 10⁻⁵ s.

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Learn more:

https://brainly.com/question/10535983https://brainly.com/question/21089350

Answer:

Ok I seen the answers on here talk about over complicated lol

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then is born CH2O aka formaldehyde : )

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Answers

Answer:

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HELP ME ?
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Answer:

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