differentiate the following with respect to x
irrelevant answers will be reported
Answers
Answer:
[tex]\displaystyle y' = - \frac{e^{x^2 + 7} \sqrt{\csc 5x} \Bigg[ \bigg[ 5 \cot (5x) - 4x \bigg] \sin (3x + 4) - 6 \cos (3x + 4) \Bigg] }{2}[/tex]
General Formulas and Concepts:
Calculus
Differentiation
DerivativesDerivative NotationDerivative Property [Multiplied Constant]:
[tex]\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)[/tex]
Derivative Property [Addition/Subtraction]:
[tex]\displaystyle \frac{d}{dx}[f(x) + g(x)] = \frac{d}{dx}[f(x)] + \frac{d}{dx}[g(x)][/tex]
Derivative Rule [Basic Power Rule]:
f(x) = cxⁿf’(x) = c·nxⁿ⁻¹Derivative Rule [Product Rule]:
[tex]\displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)[/tex]
Derivative Rule [Chain Rule]:
[tex]\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)[/tex]
Step-by-step explanation:
Step 1: Define
Identify.
[tex]\displaystyle y = e^{x^2 + 7} \sin (3x + 4) \sqrt{\csc (5x)}[/tex]
Step 2: Differentiate
Apply Derivative Rule [Product Rule]:[tex]\displaystyle y' = \big[ e^{x^2 + 7} \big]' \sin (3x + 4) \sqrt{\csc (5x)} + e^{x^2 + 7} \big[ \sin (3x + 4) \big]' \sqrt{\csc (5x)} + e^{x^2 + 7} \sin (3x + 4) \big[ \sqrt{\csc (5x)} \big]'[/tex]Apply Exponential Differentiation [Derivative Rule - Chain Rule]:
[tex]\displaystyle y' = e^{x^2 + 7} (x^2 + 7)' \sin (3x + 4) \sqrt{\csc (5x)} + e^{x^2 + 7} \big[ \sin (3x + 4) \big]' \sqrt{\csc (5x)} + e^{x^2 + 7} \sin (3x + 4) \big[ \sqrt{\csc (5x)} \big]'[/tex]Apply Derivative Rules and Properties [Basic Power Rule + Addition/Subtraction]:
[tex]\displaystyle y' = 2xe^{x^2 + 7} \sin (3x + 4) \sqrt{\csc (5x)} + e^{x^2 + 7} \big[ \sin (3x + 4) \big]' \sqrt{\csc (5x)} + e^{x^2 + 7} \sin (3x + 4) \big[ \sqrt{\csc (5x)} \big]'[/tex]Apply Trigonometric Differentiation [Derivative Rule - Chain Rule]:
[tex]\displaystyle y' = 2xe^{x^2 + 7} \sin (3x + 4) \sqrt{\csc (5x)} + e^{x^2 + 7} \cos (3x + 4) (3x + 4)' \sqrt{\csc (5x)} + e^{x^2 + 7} \sin (3x + 4) \big[ \sqrt{\csc (5x)} \big]'[/tex]Apply Derivative Rules and Properties [Basic Power Rule + Addition/Subtraction]:
[tex]\displaystyle y' = 2xe^{x^2 + 7} \sin (3x + 4) \sqrt{\csc (5x)} + 3e^{x^2 + 7} \cos (3x + 4) \sqrt{\csc (5x)} + e^{x^2 + 7} \sin (3x + 4) \big[ \sqrt{\csc (5x)} \big]'[/tex]Apply Derivative Rules [Basic Power Rule + Chain Rule]:
[tex]\displaystyle y' = 2xe^{x^2 + 7} \sin (3x + 4) \sqrt{\csc (5x)} + 3e^{x^2 + 7} \cos (3x + 4) \sqrt{\csc (5x)} + e^{x^2 + 7} \sin (3x + 4) \frac{\big[ \csc (5x) \big] '}{2\sqrt{\csc (5x)}}[/tex]Apply Trigonometric Differentiation [Derivative Rule - Chain Rule]:
[tex]\displaystyle y' = 2xe^{x^2 + 7} \sin (3x + 4) \sqrt{\csc (5x)} + 3e^{x^2 + 7} \cos (3x + 4) \sqrt{\csc (5x)} + e^{x^2 + 7} \sin (3x + 4) \frac{- \csc (5x) \cot (5x) (5x)'}{2\sqrt{\csc (5x)}}[/tex]Apply Derivative Rules and Properties [Basic Power Rule + Multiplied Constant]:
[tex]\displaystyle y' = 2xe^{x^2 + 7} \sin (3x + 4) \sqrt{\csc (5x)} + 3e^{x^2 + 7} \cos (3x + 4) \sqrt{\csc (5x)} + e^{x^2 + 7} \sin (3x + 4) \frac{-5 \csc (5x) \cot (5x)}{2\sqrt{\csc (5x)}}[/tex]Rewrite:
[tex]\displaystyle y' = - \frac{e^{x^2 + 7} \sqrt{\csc 5x} \Bigg[ \bigg[ 5 \cot (5x) - 4x \bigg] \sin (3x + 4) - 6 \cos (3x + 4) \Bigg] }{2}[/tex]
∴ we have found the derivative of the function.
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Topic: AP Calculus AB/BC (Calculus I/I + II)
Unit: Differentiation
To find the derivative of the function [tex]\displaystyle\sf\:y=e^{x^{2}+7}\sin(3x+4)\sqrt{\csc(5x)}}[/tex] with respect to [tex]\displaystyle\sf x[/tex], we'll use the chain rule and product rule.
Let's break down the function into its individual parts:
[tex]\displaystyle\sf u= e^{x^{2}+7}[/tex]
[tex]\displaystyle\sf v= \sin(3x+4)[/tex]
[tex]\displaystyle\sf w= \sqrt{\csc(5x)}}[/tex]
Now, let's differentiate each part separately:
Using the chain rule, the derivative of [tex]\displaystyle\sf u= e^{x^{2}+7}[/tex] is:
[tex]\displaystyle\sf \dfrac{du}{dx}= (2x)e^{x^{2}+7}[/tex]
Using the chain rule, the derivative of [tex]\displaystyle\sf v= \sin(3x+4)[/tex] is:
[tex]\displaystyle\sf \dfrac{dv}{dx}= 3\cos(3x+4)[/tex]
To differentiate [tex]\displaystyle\sf w= \sqrt{\csc(5x)}}[/tex], we can rewrite it as [tex]\displaystyle\sf w= (\csc(5x))^{1/2}[/tex]. Using the chain rule, the derivative of [tex]\displaystyle\sf w[/tex] is:
[tex]\displaystyle\sf \dfrac{dw}{dx}= \dfrac{1}{2}(\csc(5x))^{-1/2}(-\cot(5x))(5)[/tex]
Simplifying the derivative [tex]\displaystyle\sf \dfrac{dw}{dx}[/tex]:
[tex]\displaystyle\sf \dfrac{dw}{dx}= -\dfrac{5\cot(5x)}{2\sqrt{\csc(5x)}}[/tex]
Now, using the product rule, the derivative of [tex]\displaystyle\sf y[/tex] with respect to [tex]\displaystyle\sf x[/tex] can be calculated as follows:
[tex]\displaystyle\sf \dfrac{dy}{dx}= \dfrac{du}{dx} \cdot v \cdot w + u \cdot \dfrac{dv}{dx} \cdot w + u \cdot v \cdot \dfrac{dw}{dx}[/tex]
Substituting the values of [tex]\displaystyle\sf \dfrac{du}{dx}[/tex], [tex]\displaystyle\sf \dfrac{dv}{dx}[/tex], and [tex]\displaystyle\sf \dfrac{dw}{dx}[/tex]:
[tex]\displaystyle\sf \dfrac{dy}{dx}= \left((2x)e^{x^{2}+7}\right) \cdot \sin(3x+4) \cdot \sqrt{\csc(5x)} + e^{x^{2}+7} \cdot \left(3\cos(3x+4)\right) \cdot \sqrt{\csc(5x)} - e^{x^{2}+7} \cdot \sin(3x+4) \cdot \dfrac{5\cot(5x)}{2\sqrt{\csc(5x)}}[/tex]
Simplifying further:
[tex]\displaystyle\sf \dfrac{dy}{dx}= \left(2xe^{x^{2}+7}\right) \sin(3x+4) \sqrt{\csc(5x)} + 3e^{x^{2}+7}\cos(3x+4) \sqrt{\csc(5x)} - \dfrac{5e^{x^{2}+7} \sin(3x+4) \cot(5x)}{2\sqrt{\csc(5x)}}[/tex]
Therefore, the derivative of [tex]\displaystyle\sf y[/tex] with respect to [tex]\displaystyle\sf x[/tex] is:
[tex]\displaystyle\sf y' = -2e^{x^{2}+7}\csc(5x)[5\cot(5x)-4x]\sin(3x+4) - 3e^{x^{2}+7}\sqrt{\csc(5x)}\cos(3x+4) - \dfrac{5e^{x^{2}+7}\sin(3x+4)\cot(5x)}{2\sqrt{\csc(5x)}}[/tex]
Simplifying further, we have:
[tex]\displaystyle\sf y' = -2e^{x^{2}+7}\csc(5x)[5\cot(5x)-4x \sin(3x+4) - 6e^{x^{2}+7}\cos(3x+4)\sqrt{\csc(5x)}[/tex]
Therefore, the derivative of [tex]\displaystyle\sf y[/tex] with respect to [tex]\displaystyle\sf x[/tex] is:
[tex]\displaystyle\sf y' = -2e^{x^{2}+7}\csc(5x)[5\cot(5x)-4x]\sin(3x+4) - 6e^{x^{2}+7}\cos(3x+4)\sqrt{\csc(5x)}[/tex]
[tex]\huge{\mathfrak{\colorbox{black}{\textcolor{lime}{I\:hope\:this\:helps\:!\:\:}}}}[/tex]
♥️ [tex]\large{\underline{\textcolor{red}{\mathcal{SUMIT\:\:ROY\:\:(:\:\:}}}}[/tex]
Related Questions
Help me please. Don't mind that I answered it, I put whatever so that I can move on to the next page. Show how you did the work!
Answers
Answer:
true false false
Step-by-step explanation:
3,4,5 is a common triangle (proof sqrt(3^2+4^2) = 5)
5,6,7 cant exist sqrt(5^2+6^2) doesnt equal 7
5,5,10 cant exist sqrt(5^2+5^2) doesnt equal 10
Camden invested $1400 in an account that pays 4.5% interest compounded annually Assuming no deposits or withdrawals are made, find how much money Camden would have in the account 12 years after his initial investment. Round to the nearest tenth ( if necessary)
Answers
The amount of money Camden would have in his account after 12 years is equal to $2,374.3.
How to calculate compound interest.To calculate how much money Camden would have in his account after 12 years, we would use the formula for compound interest.
Mathematically, compound interest is given by this formula:
[tex]A=P(1+r)^t[/tex]
Where:
A is the balance.P is the principal or starting amount.R is the interest rate.T is the time measured in years.Given the following data:
Principal = $1400.
Interest rate = 4.5% = 0.045.
Time = 12 year.
Substituting the given parameters into the formula, we have;
[tex]A=1400(1+0.045)^{12}\\\\A=1400(1.6959)[/tex]
A = $2,374.3.
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64, –48, 36, –27, ... which formula can be used to describe the sequence? f(x 1) = three-fourthsf(x) f(x 1) = negative three-fourthsf(x) f(x) = three-fourthsf(x 1) f(x) = negative three-fourthsf(x 1)
Answers
The formula which can be used to describe the sequence of provided series is f(x+1) =-(3/4) × f(x).
What is geometric sequence?Geometric sequence is the sequence in which the next term is obtained by multiplying the previous term with the same number for the whole series.
The relation formula can be used to describe such sequence are,
[tex]f(x+1)=r\times f(x)[/tex]
Here, r is the common ratio.
The given sequence is,
[tex]64, -48, 36, -27, ...[/tex]
In the above sequence, the next term has opposite sign to its previous term. The common ratio between the two terms is,
[tex]r=\dfrac{-48}{64}=-\dfrac{3}{4}\\r=\dfrac{36}{-48}=-\dfrac{3}{4}\\r=\dfrac{-27}{36}=-\dfrac{3}{4}[/tex]
The common ratio of the sequence is -3/4. Put this value in the above formula as,
[tex]f(x+1)=-\dfrac{3}{4}\times f(x)[/tex]
Hence, the formula which can be used to describe the sequence of provided series is f(x+1) =-(3/4) × f(x).
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Answer:
B
Step-by-step explanation:
edge
M is the midpoint of AB. If the coordinates of A are (-1,5), and the coordinates of M are (3,3), what are the coordinates of B?
I need the answer asap!
Answers
Answer:
B = (5, 1).
Step-by-step explanation:
From the formula for the midpoint of a line :-
(-1 + x)/2 , (5 + y)/2 = (6/2, 6/2) where x and y are the coordinates of B.
so (-1 + x)/2 = 6/2
-1 + x = 6
x = 5.
and (5 + y)/2 = 6/2
5 + y = 6
y = 1.
what is x (its a parralleligram)
Answers
Check the picture below.
everyone please answer one of these my birthday tuesday but i might be in trouble if i fail this :(
Answers
Answer:
11. b
10.d
9.c
7.b
1.d
the rest I can't see clearly
please give brainiest
Step-by-step explanation:
11.
3/x-4=7/x
*cross multiply
3x=7 (x-4)
3x=7x-28
28=7x-3x
28=4x
x=7
10.
SOHCAHTOA
Cos☆=11/14
cos^-1 (11/14)
☆=38.21 degrees
9.
MLN CONGRUENT TO WBN
ML/WB=LN/BN=MN/WN
LN/BN=10/6
ML/WB
24/x=10/6
24x6=10x
144÷10
=14.4
6^2+14.4^2
=243.36
squareroot
=15.6
The depth in feet, D. of a scuba diver can be modeled by the function D(x) = -x + 12x + 4. where x is the number of seconds spent diving.
What is the number of seconds spent diving when the scuba diver reaches their maximum depth?
Respond in the space provided
Answers
Considering the vertex of the quadratic equation, it is found that the scuba diver reaches maximum depth after 6 seconds.
What is the vertex of a quadratic equation?A quadratic equation is modeled by:
[tex]y = ax^2 + bx + c[/tex]
The vertex is given by:
[tex](x_v, y_v)[/tex]
In which:
[tex]x_v = -\frac{b}{2a}[/tex]
[tex]y_v = -\frac{b^2 - 4ac}{4a}[/tex]
Considering the coefficient a, we have that:
If a < 0, the vertex is a maximum point.If a > 0, the vertex is a minimum point.In this problem, the depth is given by:
D(x) = -x² + 12x + 4.
Which means that the coefficients are a = -1, b = 12, c = 4, hence:
[tex]x_v = -\frac{b}{2a} = -\frac{12}{-2} = 6[/tex]
The scuba diver reaches maximum depth after 6 seconds.
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Which choices are in the solution set of the equation below? Check all that
apply.
4x = 30
A. 8
B. 7.5
C. 8.5
D. 7
E.6.5
Answers
4x = 30
4x/4 = 30/4
x = 7.5
What is 3(b+8) in Distributive Property
Answers
Answer:
3b + 24
Step-by-step explanation:
3*b=3b
3*8=24
therefore the answer is 3b+24
Hope this helps:)...if not then sorry for wasting your time and may God bless you:)
A cylindrical water tank has a diameter of 9 feet and a height of 16 feet. Each can of paint covers 50 square feet. What is the minimum number of cans of paint needed to cover the outside of the tank
Answers
Answer:
12 cans
Step-by-step explanation:
The area of the outside of the tank:
radio = half diameter = 4.5 ft.
base: [tex]A_{b} =\pi r^{2} =\pi (4.5)^{2} =20.25\pi[/tex]
Top: = base [tex]=20.25\pi[/tex]
cylinder: [tex]2\pi rh=2\pi (4.5)(16)=144\pi[/tex]
Total area to paint: [tex]144\pi +2(20.25\pi) =184.5\pi =579.6sq.ft.[/tex]
Number of cans of paint:
[tex]c=\frac{579.6}{50} =11.59=12[/tex]
Hope this helps
What is the result when the number 39 is decreased by 3%?
Answers
result = 39 - 39 x 3% = 39 x 0,97 = 37,83
The question is below:
Answers
QUESTION -> {WHICH EQUATION DESCRIBES A LINEAR FUNCTION }.
?ANSWER :
B .
y =(1 — 6 ) ×
or.
C .
y = (2) ×
HOPE IT HELPS .
THANK ME LATER THANKS.
Which is the solution to the inequality?
y + 15 less-than 3
Answers
Hey there!
"less than" is "<"
y+15<3
Solve it:
y<3-15
y<-12
Hope everything is clear.
Let me know if you have any questions!
Always remember: Knowledge is power!
Answer:
y < -12
Step-by-step explanation:
Edge
Ron started the day with a score of +12.
He lost 4 points, gained 3 points, and then
lost 15 points. What was his score then?
Answers
+ 12 - 4 + 3 - 15
= 12 + 3 - 4 - 15
= 15 - 19
= - 4
Answer:
He has -4 points. if I'm not mistaken
Step-by-step explanation:
12 - 4 + 3 - 15 = -4
I apologize if I am incorrect
Josiaanswer this is it josia the question
Answers
Answer:
6? i am soooo confused
Step-by-step explanation:
Find the exact volume of the radius is 7 inches and the height is 18 inches.
Answers
Answer: 882pi square inches
Step-by-step explanation:
The measures of the angles of a triangle are shown in the figure below. Solve for x.
Answers
Answer: x = 54°
Step-by-step explanation:
The sum of these three inter angles is equal to 180°.
36° + 90° + x° = 180
126 + x = 180
x = 54°
Step-by-step explanation:
36° +90°+ x = 180° ( sum of all angle of triangle is 180°)
126° + x = 180°
x = 180° - 126°
x = 54°
Find the sum of each of the following series:
(a) 2 + 7 + 12 + ...... +92
Answers
where u(n) is the nth term (any term).
u⁰ is out first term (2)
d is the common difference (5)
u(n)=u⁰+nd92 =2 +5n5n =90n =18This sequence admits 19 terms since we start counting from 0 till 18.SummationS= number of terms/2 ×(u¹⁸+u⁰)[tex]s = \frac{19}{2} \times (92 + 2)[/tex][tex]s = 9.5(94)[/tex]
[tex]s = 893[/tex]
That's ur answer :)Determine
the rotation around the origin that was performed to transform the preimage on the left to its image on the right.
Answers
Answer:
-90 degrees counter clock wise
Step-by-step explanation:
it goes the opposite of a clock so it would be called -90 degrees counter clockwise, you could also say 270 degrees clockwise if the other isnt an option.
I’ll give Brainly but can somebody help me with this?
Answers
Answer:
give me 2 minutes and I will
Carlos has a 12300 millimeters long piece of wook. he wants to cut it into 3 equal lengths. how long will each piece be in meters?
Answers
Answer:
4.1 meters each
1000 milileters go into 1 meter
Step-by-step explanation:
Answer:
Step-by-step explanation:
12300/3= 4100 1 meter = 1000 millimeters
4100/1000=4.1 meters
In which quadrant does θ lie given that sinθ < 0 and cosθ < 0? Thank You!
Quadrant I
Quadrant II
Quadrant III
Quadrant IV
Answers
Answer:
Quadrant III yw :3
Step-by-step explanation:
work out the total length of the wire two wire shapes make an earring. the shapes are a circle with radius 21mm and a quarter circle 6mm. work out the total length of the wire in the earring. give your answer in the form a pie +b where a and b are integers.
Answers
Answer:
45n+12mm
Step-by-step explanation:
I hope this is right if it is right pls mark me as brainliest and learn well
the value of a and b will be 45 and 0 for the given expression.
What is proportionality?the property of having suitable proportions in terms of size, number, degree, harshness, etc.: If a defensive action against an unfair attack results in the destruction that contravenes the proportionality criterion, it may even go far beyond a justifiable defense.
Given, the shapes are a circle with a radius of 21mm and a quarter circle of 6mm.
Since Radius = 21 cm
the radius of the circle/ radius of the quarter circle = 7/2
Total length = Sum of the circumference of both the circle
Since the formula for the circumference of a circle:
C = 2 * pi * radius
Total length = 2* pi* r + 1/4 * (2 * pi * r')
Total length = 2 *pi * 21 + pi * 3
Total length = π(42 + 3)
total length = 45π + 0
therefore, the value of a and b will be 45 and 0 for the given expression.
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#SPJ2
e + 3.1 = 5
this is hard.
Answers
AnswerAnswer:E=1.9
Step-by-step explanation:
ssorry bit i conta speak englessh
What are the missing operations?
A. 48 ? (-8) = (-6)
B. (-40) ? 8 =( -5)
C. 12 ? (-2) = 14
D. 18 ? (-12) = 6
E. 18 ? (-20) = -2
F. 22 ? (-0.5) = -11
Answers
48 / -8 = -6
-40 / 8 = -5
12 - (-2) = 14
18 - (-12) = 6
18 - (-20) = -2
22 x (-0.5) = 11
Good evening! Can someone please answer this, ill give you brainliest and your earning 50 points. Would be very appreciated.
Answers
Answer:
( 6(x)² + 12(x) - 90 ) ft³
Explanation:
deep end water: 2(x)² + 12(x) + 10shallow end water: 4(x)² - 100addition problem: 2(x)² + 12(x) + 10 + 4(x)² - 100
total volume of water:
2(x)² + 12(x) + 10 + 4(x)² - 1002(x)² + 4(x)² + 12(x) + 10 - 1006(x)² + 12(x) - 90Answer:
a) [tex]\sf total \ volume \ of \ pool= (2x^2+12x+10)+(4x^2-100) \ ft^3[/tex]
b) [tex]\sf total \ volume \ of \ pool =(6x^2+12x-90) \ ft^3[/tex]
Step-by-step explanation:
Given:
volume of water in the deep end: [tex]\sf (2x^2+12x+10) \ ft^3[/tex]volume of water in the shallow end: [tex]\sf (4x^2-100) \ ft^3[/tex]a) Total volume of water = deep end volume + shallow end volume
[tex]\implies \sf total= (2x^2+12x+10)+(4x^2-100)[/tex]
b) Simplify:
[tex]\sf \implies 2x^2+12x+10+4x^2-100[/tex]
Collect like terms:
[tex]\sf \implies 2x^2+4x^2+12x+10-100[/tex]
Combine like terms:
[tex]\sf \implies 6x^2+12x-90[/tex]
What are the solutions of the equation (x 2)2 – 2(x 2) – 15 = 0? use u substitution to solve. x = –7 and x = 1 x = –5 and x = 3 x = –3 and x = 5 x = –1 and x = 7
Answers
The solutions to the equation [tex]\rm (x + 2)^{2} - 2(x + 2) - 15 = 0[/tex] are 3 and -5.
What is the solution to the equation?To solve any equation is to find the solution of the given equation which satisfied the equation.
The given expression is [tex]\rm (x + 2)^{2} - 2(x + 2) - 15 = 0[/tex]
let u = (x +2)
then the equation becomes
[tex]\rm u^{2} - 2u - 15 = 0[/tex]
by factorizing, we get
(u + 3)(u - 5) = 0
u + 3 = 0, u = -3
u - 5 = 0, u = 5
Since, u = x + 2
So, x + 2 = 5, x = 3
x + 2 = -3, x = -5
Therefore, the solutions to the equation are 3 and -5.
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A watch company is developing packaging for its new watch. the designer uses hexagons with a base area of 25 in2 and rectangles with a length of 10 in to create a prototype for the new package. what is the volume of the prototype? 150 in3 200 in3 250 in3 300 in3
Answers
Answer:
The answer should be C. 250 in^3
Answer:
C. 250 in^3
Step-by-step explanation:
MATH
NATION
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Suppose h(t) = -0.2t2 + 2t models the height, in feet, of a ball that is kicked into the air where t is
given as time, in seconds.
After how many seconds does the ball reach its maximum?
Answers
Step-by-step explanation:
the point of extreme value we get a the zero dilution of the first derivative of the function.
h(t) = -0.2t² + 2t
h'(t) = -0.4t + 2
so,
-0.4t + 2 = 0
2 = 0.4t
t = 2/0.4 = 5 seconds
so, after 5 seconds the ball reaches its maximum height.
FYI : that height is then h(5).
-0.2×5² + 2×5 = -5 + 10 = 5 ft
so, all in all, a very weak kick in very low gravity ...
What are the factors of 2x2 3x – 54? Select two options. 2x – 9 2x – 6 2x 6 x – 6 x 6.
Answers
The factors of expression [tex]2x^{2} +3x-54[/tex] are (x+6) and (2x-9).
The given expression is: [tex]2x^{2} +3x-54[/tex]
What is a factor?A factor is a number that divides another number leaving no remainder.
We can rewrite the given expression as:
[tex]2x^{2} +12x-9x-54[/tex] (middle term has been splitted)
Take 2 as common from first two terms while take -9 as common from last two terms.
[tex]2x(x+6)-9(x+6)[/tex]
Take (x+6) as common
[tex](x+6) (2x-9)[/tex]
So, we got the factors (x+6) and (2x-9)
Therefore, The factors of expression [tex]2x^{2} +3x-54[/tex] are (x+6) and (2x-9).
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