Do two indentical objects become statically charged when you rub them together? Explain why they do or do not.

Answers

Answer 1

Answer:

Yes, they do. When two different materials are rubbed together, there is a transfer of electrons from one material to the other material. This causes one object to become positively charged and the other object to become negatively charged.

Explanation:

hope this helps


Related Questions

If a 35 kg box collides with a stationary 120 kg box with a force of 90 N, what must
be true of the magnitude of the reaction force?

Answers

Answer:

yes , true the magnitude of the reaction force.

How would you explain conduction?

Answers

Answer:

the meaning of conduction is the process by which heat or electricity is directly transmitted through a substance when there is a difference of temperature or of electrical potential between adjoining regions, without movement of the material.

Explanation:

Answer:

the process by which heat or electricity is directly transmitted through a substance when there is a difference of temperature or of electrical potential between adjoining regions, without movement of the material.

Explanation:

The density of air is 1.3 kg/m'. Calculate the mass of air in the room.

Answers

Answer:

The density of air is 1.3 kg/m'. Calculate the mass of air in the room.

These diagrams represent two types of tectonic plate boundaries

Answers

Convergent boundaries are caused by the collision of two plates and can originate volcanoes. Transforming boundaries produce fractures by displacement. The correct option is D. Type A boundaries have fewer volcanoes.

----------------------------------------

The crust -the outermost layer of the earth- is divided into many plates that move over the mantle.

These plates are limited by three types of ridges or borders that differ in the movement they produce.

Boundaries types:

I. Divergent:

This boundary occurs when two plates separate and molten material rises from the mantle creating a new crust.

The hot material creates a new seabed between the separating plates, expanding the sea bottom.

II. Convergent.

Collision area between two plates.

Two oceanic plates might collide, or one oceanic plate with a continental one.

In this last case, the oceanic crust sinks under the continental plate, and magma rises to the surface by crevices.

The thicker and older plate subduces under the other plate.

Collisions create volcanic arches and continental arches.

III. Transforming.

The plates slide laterally with each other, and they are usually called faults.

It is associated, in general, with the oceanic ridge, although it might also occur in the continental plate.

No rocky material is either destroyed or formed.

When the plates move and produce a displacement of one transforming limits from side to side, earthquakes occur.

The movement breaks the crust and originates pronounced fractures.

In the attached images, we can see

image A representing transforming boundaries, image B representing Convergent boundaries.

Image B is the one that can originate volcanoes because transforming boundaries only produce fractures.

So the correct option would be D.

--------------------------------

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Answer:

d

Explanation:

Find the heat energy is required to change 2Kg of ice at 0 C to water at 20 C ( specific latent heat of fusion of water = 336000 J/Kg and specific heat of capacity of water = 4200 J/Kg C

Answers

We want to find the energy that we need to transform 2kg of ice at 0°C to water at 20°C.

We will find that we must give 840,000 Joules.

First, we must change of phase from ice to water.

We use the specific latent heat of fusion to do this, this quantity tells us the amount of energy that we need to transform 1 kg of ice into water.

So we need 336,000 J of energy to transform 1kg of ice into water, and there are 2kg of ice, then we need twice that amount of energy:

2*336,000 J = 672,000 J

Now we have 2kg of water at 0°C, and we need to increase its temperature to 20°C.

Here we use the specific heat, it tell us the amount of energy that we need to increase the temperature per mass of water by 1°C.

We know that:

specific heat of capacity of water = 4200 J/kg°C

This means that we need to give 4,200 Joules of energy to increase the temperature by 1°C of 1kg of water.

Then to increase 1°C of 2kg of water we need twice that amount:

2*4,200 J = 8,400 J

And that is for 1°C, we need to give that amount 20 times (to increase 20°C) this is:

20*8,400 J = 168,000 J

Then the total amount of energy that we must give is:

E = 672,000 J + 168,000 J = 840,000 J

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If the half-life of iodine-131 is 8 days, how much of a 5.00 sample is left after 32 days?

A) 0.31

B) 2.5

C) 1.25

D) 0.62

Answers

Answer:

Option A, 0.31

Explanation:

n = Time taken / half life

n = 32/ 8

= 4

Remaining fraction = 1/2^n

= 1/2⁴

= 1/16

Amount of iodine-131 left = 1/16 × 5

= 0.3125

plz help! ill give brainlyest to whoever gets this correct!
Two carts move directly toward one another on an air track. Cart 1 has a mass of 0.35 kg and a speed of 1.2 m>s. Cart 2 has a mass of 0.61 kg and a speed of 0.85 m>s. What is the total momentum of the system, assuming that cart 1 moves in the positive direction?

Answers

What’s Brainlyest? Can you post a picture of the question or farther explain what (m>s) means?

A water-skier is being pulled by a tow rope attached to a boat. As the driver pushes the throttle forward, the skier accelerates. A 73.5-kg water-skier has an initial speed of 5.2 m/s. Later, the speed increases to 12.2 m/s. Determine the work done by the net external force acting on the skier.

ANSWER FOR BRAINLIEST IF ANSWER IS GOOD

Answers

Ignore my comment, that information is unnecessary.

Assuming no friction between the skis and the water, the total work performed on the skier is due only to the pulling force (T, for tension). By Newton's second law, the net force exerted on the skier is

∑ F = T = ma

where m = 73.5 kg is the mass of the skier, and a is their acceleration.

Under constant acceleration, the skier is pulled a distance x such that

(12.2 m/s)² - (5.2 m/s)² = 2ax

and solving for x gives

x = (60.9 m²/s²) / a

Then the total work performed on the skier is

W = Tx

W = ma • (60.9 m²/s²) / a

W = (73.5 kg) (60.9 m²/s²)

W ≈ 4480 J

In an action-reaction pair
a. action force is exerted first

b. action force and the reaction force are equal in magnitude and act in the same direction.

c. action force and the reaction force are contact forces only.

d. action force and the reaction force act on two different objects.

Answers

In an action-reaction pair, action force and th reaction force act on two different objects.Newton's Third Law of Motion states, "To every action, there is an equal and opposite reaction; action and reaction act on two different bodies."The first option is incorrect because action and reaction forces act simultaneously.The second option is also false because they act in opposite direction.The third option is wrong because for action-reaction force, physical contact is not necessary.

Answer:

d. action force and the reaction force act on two different objects.

Hope you could understand.

If you have any query, feel free to ask.

In an action-reaction pair, action force and the reaction force act on two different objects.

What is Newton's Third Law of Motion?

Newton's Third Law of Motion states that "For every action, there is an equal and opposite reaction, action and reaction act on two different bodies."

It means that equal force are act on reaction force that is it is also known as reciprocal law of motion.

When considering the options,

The first option is incorrect because action and reaction forces act simultaneously.The second option is also false because they act in opposite direction.The third option is wrong because for action-reaction force, physical contact is not necessary.

So, In an action-reaction pair, action force and the reaction force act on two different objects. Thus, Option B is the correct answer.

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19. A beach ball is rolling in a straight line toward you at a speed of 9 m/sec. Its momentum is 3 kg'm/sec.
What is the mass of the beach ball? moss - 0.33
aroto from 10mle to speed of 14 m/s The mass of the bicycle

Answers

The mass of the beach ball is 0.33 kg

From the question,

We are to determine the mass of the beach ball.

Using the formula

ρ = mv

Where ρ is the momentum

m is the mass

and v is the velocity

From the given information,

ρ = 3 kg m/sec

v = 9 m/sec

Putting the parameters into the formula, we get

3 = m × 9

∴ m = 3 ÷ 9

m = 0.33 kg

Hence, the mass of the beach ball is 0.33 kg

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(50 POINTS) please answer each question:

what is the Distance from Earth (light years)

what is the Visual Luminosity in comparison to Sun

what is the Surface Temperature (Kelvin)

stars:

Sun




Alpha Centauri A




Sirius B




Barnard’s Star




Vega




Proxima Centauri

Answers

Answer:

i know the first one.

Explanation:

the distance from earth in light years is 6 trillion miles.

Solve the science problem

Answers

How does this have anything to do with science? (If you explain I’ll try my best to answer)

Mass can be measured with a triple
beam balance in units of
Resources
A. grams
B. Newtons
C. cubic centimeters
D. millimeters

Answers

Answer:

A

Explanation:

A pilot wishes to fly from airport A to airport B. Airport B is located due south from airport A. The pilots aircraft averages a speed of 160 mi/hr. If the pilot is flying in a wind which blows out of the west at a speed of 40 mi/hr, then the pilot should head his plane in the direction of vector ...

Answers

The pilot should head his plane in the direction of vector of 76⁰.

The given parameters;

velocity of the plane due south, a =160 mphvelocity of the wind west, b = 40 mph

Let the direction of the vector = θ

The direction of the vector can be determined by applying the principle of vector addition;

[tex]tan(\theta) = \frac{v_y}{v_x} \\\\\theta = tan^{-1} (\frac{160}{40} )\\\\\theta = 76 \ ^0[/tex]

Thus, the pilot should head his plane in the direction of vector of 76⁰.

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1. Which statement is true about natural
resources?

A. They are only found in living things.
B. They only provide sources of food and
material to humans.
C. They can be man-made or found in nature.
D. They can be a substance, material, object or
source of energy.

2. How do the properties of a substance that is
the result of a chemical reaction compare to the
properties of the starting material?

A. The properties will stay the same.
B. The properties will be different.
C. The properties stayed the same and new
properties will be added.

3. Chlorine is a poisonous gas. Sodium reacts
explosively with water. When chlorine and
sodium react with each other, the product is
the salt we sprinkle on our food. Which
principle does this demonstrate?

A. Reactants are more dangerous than products.
B. Energy is released by some reactions and
absorbed by others.
C. When two reactants form one product, the
reaction is spontaneous.

Answers

Answer:

1. D. They can be a substance, material, object or  source of energy.

2. B. The properties will be different.

3. C. When two reactants form one product, the  reaction is spontaneous.

The magnitude, M, of an earthquake is represented by the equation M=23logEE0 where E is the amount of energy released by the earthquake in joules and E0=104. 4 is the assigned minimal measure released by an earthquake. In scientific notation rounded to the nearest tenth, what is the amount of energy released by an earthquake with a magnitude of 5. 5?.

Answers

An earthquake with a magnitude of 5.5 releases 4.5 × 10¹² J of energy.

What is the magnitude of an earthquake?

The magnitude of an earthquake is a number that characterizes the relative size of an earthquake and is based on the measurement of the maximum motion recorded by a seismograph.

If the magnitude of the earthquake is M = 5.5, we can calculate the amount of energy released (E) using the following expression.

[tex]M = \frac{2}{3} log(\frac{E}{E_0} )\\\\E = E_0 \times 10^{\frac{3}{2}M } = 10^{4.4} \times 10^{\frac{3}{2}(5.5) } = 4.5 \times 10^{12} J[/tex]

where,

E₀ is the assigned minimal measure released by an earthquake.

An earthquake with a magnitude of 5.5 releases 4.5 × 10¹² J of energy.

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please someone help me understand this question ​

Answers

[tex]\\ \sf\longmapsto F=\dfrac{Gm_1m_2}{r^2}[/tex]

m1 and m2 has same units let both be m

[tex]\\ \sf\longmapsto F=\dfrac{Gm^2}{r^2}[/tex]

[tex]\\ \sf\longmapsto G=\dfrac{Fr^2}{m^2}[/tex]

SI units:-

F=Newton (N)r=metre(m)mass=m=kg

[tex]\\ \sf\longmapsto G=\dfrac{Nm^2}{kg^2}[/tex]

Option C is correct

An engine has an energy input of 125 J, and 35 J of that energy is transformed into useful energy. What is the efficiency of the engine? 28% 35% 72% 90%.

Answers

The efficiency of the engine at the given useful energy and input energy is 28%.

The given parameters:

Input energy of the engine, = 125 JUseful energy of the engine, 35 J

The efficiency of the engine is defined as the ratio of the output energy (useful energy) to the input energy and it is calculated as follows;

[tex]efficiency\ = \frac{0ut put \ energy}{1nput \ energy} \times \ 100\%\\\\efficiency\ = \frac{35}{125} \times 100\%\\\\efficiency\ = 28 \ \%[/tex]

Thus, the efficiency of the engine at the given useful energy and input energy is 28%.

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Answer:

ITS A

Explanation:

An astronomical unit (A.U.) is 1 point A) a term for defining the luminosity of a star B) the average distance from the Earth to the sun C) the average distance of any given planet to the sun D) equal to a light year

Answers

Answer:

B) the average distance from the Earth to the Sun

Explanation:

The International Space Station (ISS) orbits Earth at an altitude of 4.08 × 105 m above the surface of the planet. At what velocity must the ISS be moving in order to stay in its orbit?
A) 7.91 × 10^3 m/s
B) 3.12 × 10^4 m/s
C) 7.66 × 10^3 m/s
D) 8.17 × 10^3 m/s

Answers

This question involves the concepts of orbital velocity and orbital radius.

The orbital velocity of ISS must be "7660.25 m/s".

The orbital velocity of the ISS can be given by the following formula:

[tex]v=\sqrt{\frac{GM}{R}}[/tex]

where,

v = orbital velocity = ?

G = Universal Gravitational Constant = 6.67 x 10⁻¹¹ N.m²/kg²

M = Mass of Earth = 5.97 x 10²⁴ kg

R = orbital radius = radius of earth + altitude = 63.78 x 10⁵ m + 4.08 x 10⁵ m

R = 67.86 x 10⁵ m

Therefore,

[tex]v=\sqrt{\frac{(6.67\ x\ 10^{-11}\ N.m^2/kg^2)(5.97\ x\ 10^{24}\ kg)}{67.86\ x\ 10^5\ m}}[/tex]

v = 7660.25 m/s

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Question 4 of 10
When you go along with a group because you don't want to cause trouble, it is
called:
A. informational social influence.
B. normative social influence.
C. attribution
.
D. fundamental social influence.

Answers

Answer:

Normative

Explanation:

It is normal occurance but not unnatural

Calculate the weight of the object of mass
20kg. (g= 10 m/s^2)

Answers

Answer:

mass= 20kg

g=10m/s2

weight is F=mg

F=20×10

F=200N

A 2-year-old child is prescribed cyclosporine. The parent says the child doesn't like taking the liquid medication. Which statement by the nurse is most appropriate

Answers

Given what we know, we can say that the most appropriate response by the nurse is to indicate that the parent should dilute the medicine in chocolate milk in order to make it more palatable.

Why is this an appropriate response?This is an appropriate response given that it offers a possible solution for the problem.The nurse is first showing that the problem presented by the parent is being taken seriously.Then, without criticizing the parent, a healthy and viable solution is offered.

Therefore, we can confirm that since this response is a calm and thought-out response that respects the patient and offers a viable solution, it can be considered the most appropriate statement by the nurse.

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ASAP!!!!!!!! Parts of a Microscope: Use the following word bank to identify the following parts of the microscope.
Body Tube
Ocular Lens ( eye piece)
Revolving Nose piece Arm
Objectives (three of these) Diaphragm
Stage clips
Stage
Light Source
Base
Course Adjustment Knob
Fine Adjustment Knob

Answers

Answer:

1. Body Tube

2.Revolving Nose Piece

3.Low Objective

4.Med Objective

5.High Objective

6.Stage clips

7.Diaphragm

8.Light source

9.Ocular lens

10. Arm

11.Stage

12.Coarse Adjustment knob

13.Fine Adjustment knob

14. base

A Person is carrying 6kg in one hand and 5kg in another.Calculate the resultant force applied by him​

Answers

I think first of all you should convert both masses to weight by
W= mg ( gravity is 9.8m/s^2)

W= (6)(9.8)= 58.8N
W= (5)(9.8)= 49N

Resultant force = 58.8-49= 9.8N

Final answer:
9.8N

I’m really sorry if the answer turned out to be wrong but I tried my best so good luck!!

How long does it take a car traveling at 45km/h to travel 100.0 m?

Answers

Answer:

8 seconds

Explanation:

Since the carspeed is in km/h, we need equal units, so we will make 100.0m 0.1000km.

Then we need to find how long it takes the car to travel 0.1km

We can use the formula distance=speed * time and get

0.1=45 * time

Therefore we get .002222... hours

Multiplying this by 3600 (to get seconds, 60x60), we get 8 seconds

Answer:

8m/s

Explanation:

speed = 45km/h

Distance = 100m

we have to find time = ?

Formula for speed is = Distance/ Time

Here Distance is given in 'm' so we need to convert speed value in 'm'

So to convert km/h in m formula is divide 45km/h by 3.6 then the km/h value gets converted in m so now the value is 12.5 m/s

So now,

speed = Distance/Time

we have to find Time

Then,

Time = Distance/ Speed

= 100/12.5

= 8m/s

If a 75 kg box collides with a stationary 35 kg box with a force of 110 N, what must be true of the magnitude of the reaction force?

Answers

According to Newton third law of motion,  what must be true of the magnitude of the reaction force is that the reaction force will be equal and opposite to the action force of 110 newtons

From Newton third law of motion which state that in every action of force, there will be equal and opposite reaction.

If a 75 kg box collides with a stationary 35 kg box with a force of 110 N, the mass 35 kg will produce a reaction force which is equal and opposite to the action force 110 newton received from mass 75 kg.

Therefore, what must be true of the magnitude of the reaction force from mass 35 kg is that the mass will produce an equal and opposite force equal to 110 Newtons.

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A moving car hits the breaks and starts to slow down. The car was moving 35 m/s when hitting the breaks and slows at a rate of 7 m/s/s. What is the final velocity of the car after 4 seconds?

Answers

7 miles per second.

It would take 5 seconds to stop because 35 divided by 7 = 5.

It would slow 28 miles in 4 seconds because 7 x 4 = 28.

35 - 28 = 7.

Miguel, a single teacher, earns $1,500 every two weeks (biweekly). He claims two allowances. What is his federal income tax withholding for each biweekly paycheck?

Answers

The federal income tax withholding for each biweekly paycheck for the single teacher is $259.9.

The given parameters:

Biweekly amount earned by the single teacher, = $1,500

The federal tax rate for single workers is given as;

amount between $436 and $1,506 = $34.9 plus 15%

The federal income tax withholding for each biweekly paycheck for the single teacher is calculated as follows;

income tax withholding = $34.9  +  0.15($1,500)

income tax withholding = $34.9  +  $225

income tax withholding  = $259.9

Thus, the federal income tax withholding for each biweekly paycheck for the single teacher is $259.9.

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A car drives 84 meters forward. It's displacement and distance would be the same?​

Answers

Answer:

Yes.

Explanation:

Displacement is a vector quantity, meaning it has to be a straight graph jointing from starting point to final point and has a direction as well as magnitude and it can also be negative as well as positive and zero.

Displacement is also changes in position (points) of distance. A distance is scalar quantity meaning it only has magnitude and does not have direction. Since distance is scalar quantity, it cannot be negative. Also graph of distance can be a curve graph or any graph.

So when does displacement equal to distance? If an object is moving in straight path or line in one/fixed direction, both displacement and distance are same.

Because if a distance is a straight path and the displacement is simply a straight line (or ray) jointing from starting point to end point, both distance and displacement are both straight path or rays. Since distance and displacement have same graph, we can conclude that both are same in values.

If we go by calculus, given x = 2t as example of straight graph where x stands for position and t stands for time. We can find the displacement from b to a by using the following formulas:

Displacement

[tex]\displaystyle \large{s=\int\limits^b_a {v} \, dt}[/tex]

Distance

[tex]\displaystyle \large{l=\int\limits^b_a {|v|} \, dt}[/tex]

v stands for velocity which we can find from:

Velocity

[tex]\displaystyle \large{v=\frac{dx}{dt}}[/tex]

If you have learnt calculus, first, differentiate x = 2t with respect to t.

[tex]\displaystyle \large{v=2}[/tex]

Then substitute v = 2 in s and l to find find if both displacement and distance are equal in straight path.

Displacement

[tex]\displaystyle \large{s=\int\limits^b_a {2} \, dt}\\\displaystyle \large{s=[2t]\limits^b_a}\\\displaystyle \large{s=2b-2a = 2(b-a)}[/tex]

Distance

[tex]\displaystyle \large{l=\int\limits^b_a {|2|} \, dt}\\\displaystyle \large{l=\int\limits^b_a {2} \, dt}\\\displaystyle \large{l=[2t]\limits^b_a}\\\displaystyle \large{l=2b-2a=2(b-a)}[/tex]

Since both displacement and distance are equal when integrating on straight graph, we can conclude that an object moving in straight fixed point has same distance and displacement.

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