Donna and Dave were participating in a lab on the properties of water. First, they tried to see how many drops of water they could fit on a penny. Then they dropped water and alcohol on waxed paper and observed what happened. Next they made a streak of water and then alcohol on the lab bench. The alcohol streak dried up and disappeared first. Donna and Dave had to write an explanation for everything that happened during the lab. How can they explain the disappearing alcohol? A) Alcohol is flammable. B) Alcohol has a lower boiling point than water. C) Alcohol has a lower melting point than water. D) Alcohol has a higher boiling point than water.

Answers

Answer 1

Answer:

D

Explanation:

D ok ok ok ok bye

Answer 2

The correct statement is that the alcohol has lower boiling point than water. The correct option is B.

What is boiling point?

At the boiling point, the pressure exerted by the surroundings on a liquid equals the pressure exerted by the liquid's vapor, under this condition, adding heat outcomes in the transformation of the liquid into its vapor without raising the temperature.

The boiling point of alcohol is low. Because there is less hydrogen bonding between ethanol molecules than between water molecules.

The ethanol requires less energy to vaporize than water, and water has a higher boiling point than ethanol.

The boiling point of a liquid can be known by utilizing the capillary method, that encompasses placing an inverted capillary in the liquid of interest as well as heating it.

Thus, the correct option is B.

For more details regarding boiling points, visit:

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Related Questions

A spinning disc with a mass of 2.5kg and a radius of 0.80m is rotating with an angular velocity of 1.5 rad/s. A ball of clay with unknown mass is dropped onto the disk and sticks to the very edge causing the angular velocity of the disk to slow to 1.13 rad/s. What is the mass of the ball of clay

Answers

Answer:

M = 1.90 Kg

Explanation:

Given data: mass = 2.5 Kg

radius R = 0.8 m

angular velocity ω = 1.5 rad/s

Angular momentum L =0.5×Iω^2

Where, I  is the moment of inertia of the spinning disc.

I = 0.5MR^2

I = 0.5×2.5×0.8^2

I = 0.8 Kg/m^2

Then L = 0.5×0.8×1.5^2 = 0.8×2.25 = 0.9 Kg-m^2/sec

Let unknown mass be M

New mass of disc = (2.5+M) Kg, R = 0.8 m

New I = 0.5(2.5+M)(0.8)^2

Since, angular momentum is conserved

Angular momentum before = angular momentum after

0.5×0.5(2.5+M)(0.8)^2×(1.13)^2 = 0.9

Solving for M we get

0.204304(2.5+M)=0.9

M = 1.90 Kg

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