draw and label the diagram of parts of the battery and illustrate the flow of electric current.

Answer:

Explanation:

The total number of atoms in the reactants can be determined by counting the atoms on each side of the equation.

On the left side, there are:

6 carbon atoms (C)

12 hydrogen atoms (H)

6 oxygen atoms (O)

On the right side, there are:

6 carbon atoms (C)

12 hydrogen atoms (H)

18 oxygen atoms (O)

Therefore, the reactants contain a total of:

6 + 12 + 6 = 24 atoms (of carbon, hydrogen, and oxygen)

Answer: 24 atoms

According to a first-order rate law with a rate constant of 0.0058 min1, the reaction requires a concentration of iodide of about 4.83 mM before the color changes after 12 minutes.

The demonstration in the movie shows that larger iodide ion concentrations accelerate the first reaction, hastening the depletion of thiosulfate. Because of this, the reaction's end-signaling color shift happens faster.

rate = k[I-]

[I-] = rate / k

Plugging in the given rate (0.028 mM/12 min), we get:

[I-] = (0.028 mM/12 min) / k

[I-] = (0.028 mM/12 min) / (0.0058 min⁻¹)

[I-] ≈ 4.83 mM

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One potential source of error could be a measurement error, either in the volume of water added or in the temperature of the water. Another potential source of error could be a problem with the calibration of the thermometer used to measure the temperature of the water.

However, one of the most likely sources of error in this case is the presence of air bubbles in the erlenmeyer flask during the experiment. Air bubbles can act as an insulator, trapping heat and preventing the water from reaching the same temperature as the rest of the water in the flask. This can result in an inaccurate measurement of the water's temperature and ultimately affect the calculation of the experimental data.

To reduce the impact of air bubbles in future experiments, it is recommended to ensure that the erlenmeyer flask is thoroughly cleaned and free of any debris or contaminants that may trap air bubbles. Additionally, carefully swirling the flask during the heating process can help to dislodge any trapped air bubbles and ensure that the water is evenly heated.

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The molarity of the acetic acid, when it is titrated with 0.50M NaOH, and 15.6 ml of it is required to reach the equivalence point, is 0.78 M.

The molarity of the acetic acid can be calculated using the following formula:
Molarity (M) = (Moles of Acid) / (Volume of Acid)

First, the moles of acetic acid must be determined. To do this, the moles of sodium hydroxide (NaOH) used to titrate the acetic acid must be determined.

Moles of NaOH = (Molarity of NaOH) x (Volume of NaOH)
Moles of NaOH = (0.50 mol/L) x (0.0156 L)
Moles of NaOH = 0.0078 mol

Since one mole of NaOH is needed to neutralize one mole of acetic acid, the moles of acetic acid are equal to the moles of NaOH, or 0.0078 mol.

Next, the volume of the acetic acid must be determined. Since 10.0 mL of vinegar was used, the volume of acetic acid is also 10.0 mL.

Now that the moles of acetic acid and the volume of acetic acid have been determined, the molarity of the acetic acid can be calculated.

Molarity (M) = (Moles of Acid) / (Volume of Acid)
Molarity (M) = (0.0078 mol) / (0.010 L)
Molarity (M) = 0.78 mol/L

Therefore, the molarity of the acetic acid is 0.78 mol/L.

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The experiment would produce 102.18 g of ammonia. The answer is closest to 102 g NH₃.

The balanced chemical equation for the reaction is:

N₂(g) + 3H₂(g) → 2NH₃(g)

In this equation, the stoichiometric ratio of nitrogen gas to ammonia gas is 1:2. Accordingly, 2 moles of ammonia gas are created for every 1 mole of nitrogen gas that reacts.

As a result of using 3 moles of nitrogen gas, Brett will generate 2 x 3 = 6 moles of ammonia gas.

From the equation, we can see that for every 1 mole of nitrogen gas (N₂) used, 2 moles of ammonia (NH₃) will be produced. Therefore, if 3 moles of N₂ is used, the number of moles of NH₃ produced will be:

moles of NH₃ = (3 moles N₂) x (2 moles NH₃ / 1 mole N₂) = 6 moles NH₃

To calculate the mass of NH₃ produced, we need to use its molar mass, which is 17.03 g/mol. Therefore:

mass of NH₃ = (6 moles NH₃) x (17.03 g/mol) = 102.18 g NH₃

So, the experiment would produce 102.18 g of ammonia. The answer is closest to 102 g NH₃.

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Gasoline can have potential energy because it is stored in a container, chemical energy because of the energy stored in its molecular bonds, and thermal energy because of the heat produced when it is burned.

Gasoline is a fuel that contains potential, chemical, and thermal energy.

Potential energy is the energy that an object has due to its position or configuration. In the case of gasoline, it has potential energy because it is stored in a tank or container and has the potential to be used as fuel for a car or other combustion engine.

Chemical energy is the energy that is stored in the bonds between atoms and molecules. Gasoline has chemical energy because it is made up of molecules that contain stored energy in the form of chemical bonds. When gasoline is burned in an engine, the chemical energy is released and converted into thermal energy.

Thermal energy is the energy that is related to the temperature of a substance. When gasoline is burned in an engine, it produces thermal energy as a result of the chemical reactions that take place. This thermal energy is then converted into mechanical energy that powers the car's engine.

In summary, gasoline can have potential energy because it is stored in a container, chemical energy because of the energy stored in its molecular bonds, and thermal energy because of the heat produced when it is burned. These three forms of energy are all interrelated and can be converted from one form to another.

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Momentum-

[tex] \:\:\:\:\:\:\:\:\:\:\:\:\star\sf \underline {P = mv}\\[/tex]

Where-

As per question, we are given -

Convert 20 minutes to hour-

Therefore, 20 minutes = 20/60 = 1/3 hour

[tex] \:\:\:\:\:\:\longrightarrow \sf\underline{Speed _{(car)} = \dfrac{Distance }{ time}}\\[/tex]

[tex] \:\:\:\:\:\:\longrightarrow \sf Speed_{(car)} = \dfrac{12}{\dfrac{1}{3}}\\[/tex]

[tex] \:\:\:\:\:\:\longrightarrow \sf Speed_{(car)}=12 \times 3 \\[/tex]

[tex] \:\:\:\:\:\:\longrightarrow \sf Speed_{(car)}= 36 km/h \\[/tex]

[tex] \:\:\:\:\:\:\longrightarrow \sf Speed_{(car)}= \dfrac{36 \times 1000}{3600}\\[/tex]

[tex] \:\:\:\:\:\:\longrightarrow \sf Speed_{(car)}= \dfrac{\cancel{36} \times 10\cancel{0}\cancel{0}}{\cancel{36}\:\cancel{0}\cancel{0}}\\[/tex]

[tex] \:\:\:\:\:\:\longrightarrow \sf \underline{Speed_{(car)} = 10 m/s }\\[/tex]

No that we have obtained the velocity of the car is 10 m/s and the mass of the car is 30 kg,so we can put all the values and find for momentum of car -

[tex] \:\:\:\:\:\:\longrightarrow \sf \underline{Momentum_{(car)} = mv}\\[/tex]

[tex] \:\:\:\:\:\:\longrightarrow \sf Momentum_{(car)} = 30 \times 10\\[/tex]

[tex] \:\:\:\:\:\:\longrightarrow \sf\underline{ Momentum_{(car)} =300 kgms^{-1}}\\[/tex]

In order to create 2,4-dinitrobenzene and 2,6-dinitrobenzene, respectively, nitrobenzene can be nitrated in either the ortho or para positions.

A nitro group (-NO2) is substituted for a hydrogen atom (-H) on the benzene ring during the nitration process. The nitrobenzene resonance structures demonstrate that the electrons are distributed between the nitro group and the benzene ring. Due to the partial negative charge they have as a result of the nitro group's electron-withdrawing effect, the ortho and para positions are more vulnerable to electrophilic attack as a result of this delocalization.

The following diagram depicts the resonance structures for the ortho and para nitration products:

Ortho nitrification

      H                             H

      |                             |

  H---C---NO2        H---C---NO2

      |                             |

      H                             NO2

Para nitration:

      H                             H

      |                             |

  H---C---NO2        NO2---C---H

      |                             |

     NO2                            H

The nitro group is situated on the 2 and 4 positions of the benzene ring in the ortho nitration product, whereas it is situated on the 2 and 6 positions in the para nitration product.

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Dimethylglyoxime is a chemical that is present in this kit (in solution). KIT The solution will turn pink when used to clean a metal object with such a cotton swab when nickel is present in the Penelope's 14k white gold ring.

White gold was first created to mimic platinum (a white metal). White gold is typically an alloy containing around 75% gold or around 25% nickel and zinc. It would be approximately 75% pure gold if it had an 18 karat stamp.

The question:

Joe, a friend of Penelope's, presents her with a 14k white gold ring on Valentine's Day. Daksha, a friend of Penelope's, believes it is truly made of nickel. Penelope may use the following procedure or experiment to determine this for sure:

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If you have 3.45 mol sample of iron, how many grams of Fe₂O₃ will there be after the iron has rusted completely is 193.2 g Fe₂O₃.

Rust is a multi-paradigm, general-purpose programming language developed by Mozilla Research. It is designed to be a safe, concurrent, practical language that supports functional and procedural programming. Rust is syntactically similar to C++, but its memory safety features make it safer and more secure. It also provides better performance than many other languages. Rust provides memory safety by using a type system and a borrowing system to ensure that memory is only accessed when it is valid.

The balanced equation for the rusting of iron is:
Fe + O₂ -> Fe₂O₃
To calculate the grams of Fe2O₃ produced, we must first convert 3.45 mol Fe to grams.
Molar mass of Fe = 56.0 g/mol
Therefore, 3.45 mol Fe x 56.0 g/mol = 193.2 g Fe
Now, according to the balanced equation, 1 mol Fe produces 1 mol Fe₂O₃.
So, 193.2 g Fe will produce 193.2 g Fe₂O₃.
Therefore, the answer is 193.2 g Fe₂O₃.

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The  colour change when nitric acid is added to the mixture of universal indicator and water can range from yellow/orange to red/dark red.

When nitric acid is added to a mixture of water and universal indicator, the color change depends on the concentration of the acid.

At low concentrations of nitric acid, the universal indicator will turn yellow or orange, indicating a slightly acidic solution. As the concentration of nitric acid increases, the color will shift towards red, indicating a more acidic solution. At very high concentrations, the solution may turn dark red, indicating a strongly acidic solution.

The reason for this color change is that universal indicator is a pH indicator that contains a mixture of dyes that change color depending on the pH of the solution. Nitric acid is a strong acid that dissociates completely in water, producing H+ ions that lower the pH of the solution. As the pH decreases, the color of the universal indicator changes from green to yellow to orange to red.

Therefore, the color change when nitric acid is added to a mixture of water and universal indicator depends on the concentration of the acid and can range from yellow/orange to red/dark red.

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The energy released when 1 kg of water vapor condenses into 1 kg of liquid water is known as the heat of condensation, and it has a value of 2,260 kJ/kg. This means that for every kilogram of water vapor that condenses, 2,260 kJ of energy is released as heat.

How to calcalculate total amount of heat?

To calculate the total amount of heat released by the condensing water from Hurricane Isabel, we first need to know the total amount of water that was present in the hurricane. Once we have this value, we can multiply it by the heat of condensation (2,260 kJ/kg) to find the total amount of heat released.

For example, if the total amount of water from Hurricane Isabel was 1,000 kg, then the total amount of heat released would be:

Total heat released = 2,260 kJ/kg x 1,000 kg = 2,260,000 kJ

Therefore, the total amount of heat released by the condensing water from Hurricane Isabel depends on the amount of water that was present in the hurricane, and we need this information to make a specific calculation.

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The molarity of the solution is 1.253 M.  To find the molarity of the solution, we first need to calculate the number of moles of CuSO4 in the solution.

The molar mass of CuSO4 is

63.55 + 32.07  + (4 x 16.00 ) g/mol  = 159.62 g/mol.

Next, we can use the equation moles = mass / molar mass to find the number of moles of CuSO4 in the solution.  

Moles of CuSO4 = 40.00 g / 159.62 g/mol = 0.2506 mol

Finally, we can use the equation molarity = moles / volume to find the molarity of the solution.

The volume of the solution is 200.0 mL, or 0.2000 L.

Molarity = 0.2506 mol / 0.2000 L = 1.253 M

Therefore, the molarity of the solution is 1.253 M.

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The possible values of the quantum numbers are:

Orbital shape quantum number l: 0, 1, 2, 3, 4, or 5.

Magnetic quantum number m: -l to +l.

Spin quantum number, s: +1/2 or -1/2.

For the principal quantum number n = 6, the possible values of the azimuthal (orbital shape) quantum number l are 0, 1, 2, 3, 4, and 5.

The magnetic quantum number m can have values ranging from -l to +l, inclusive.

The spin quantum number, s can be either +1/2 or -1/2.

So, the valence electrons in an atom with principal quantum number n = 6 can have the following quantum numbers:

Azimuthal quantum number, l can be 0, 1, 2, 3, 4, or 5.

Magnetic quantum number, m can range from -l to +l, inclusive.

Spin quantum number, s can be either +1/2 or -1/2.

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The mistake is made in step 1.

2C4H10 + 13 O2 → 8 CO2 + 10 H2O

From the equation, we see that 2 mole of butane reacts with 13 moles of oxygen to produce 10 moles of water.

First, we need to convert the given mass of water to moles:

1500 g H2O ÷ 18.015 g/mol H2O = 83.284 mol H2O

Next, we can use stoichiometry to calculate the moles of butane required to produce this amount of water:

83.284 mol H2O × 2 mol C4H10 ÷ 10 mol H2O = 16.657 mol C4H10

Finally, we can convert moles of butane to grams:

16.657 mol C4H10 × 58.12 g/mol C4H10 = 967.79 g C4H10

Thus, the mistake in the calculation was made in the first step where the given mass of water is to be converted to moles.

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The aluminum bar is cooling through an exothermic process, which means that heat is being released from the bar and being transported to the surroundings. This is indicated by the negative sign of the heat change.

The aluminum bar is cooling through an exothermic process, which means that heat is being released from the bar and being transported to the surroundings. This is indicated by the negative sign of the heat change (-14.2 kJ). This is due to the metal bar losing heat as it cooled down because the ultimate temperature (25.0°C) is lower than the initial temperature (70.0°C).

we can use the formula:

Q = m * c * ΔT

where Q = heat change, m = mass of the aluminum bar, c = specific heat capacity of aluminum, and ΔT = change in temperature.

The specific heat capacity of aluminum is 0.903 J/g·°C.

So, plugging in the values, we get:

Q = (350.0 g) * (0.903 J/g·°C) * (25.0°C - 70.0°C)

Q = -14,175 J

The negative sign indicates that heat is being lost by the aluminum bar,

To convert -14,175 J to kJ, we divide by 1000:

-14,175 J = -14.175 kJ

Rounding to one decimal place, we get:

-14.175 J ≈ -14.2 kJ

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Answer: 86.68 grams KOH or 86.7 g KOH to correct sig figs

Explanation:

M= moles/L

moles = MXL

moles = 2.84 X 0.545 = 1.55 moles now multiply by the molar mass of KOH

which is 56 (from the periodic table) =

If you had [tex]9.65 * 10^{26[/tex] atoms of Ag, you would have [tex]1.603 * 10^3[/tex] moles of Ag.

To find the number of moles of Ag atoms you have, you need to use Avogadro's number, which is 6.022 x 10^23. This number represents the number of atoms in one mole of any substance.
To find the number of moles, you need to divide the number of atoms you have by Avogadro's number:
Number of moles = Number of atoms / Avogadro's number
Plug in the given values:
Number of moles = 9.65 x 10^26 atoms / 6.022 x 10^23 atoms/mole
Simplify:
Number of moles = 1.603 x 10^3 moles
So, if you had 9.65 x 10^26 atoms of Ag, you would have 1.603 x 10^3 moles of Ag.

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Answer:

Filtration

Explanation:

Sand can be separated by filtration. Then, salt can be separated by evaporating the salt solution in water. Water can be recovered by condensation.

pls mrk me brainliest

Answer:

decantation and evaporation

Explanation:

If you want a solution that is less than saturated, the amount of HCl needed is less - in this case, 27.5g.

Saturated refers to a state of being filled to capacity or having reached its maximum level. In chemistry, it is used to describe a molecule or compound that has all its available bonds filled with either single or multiple bonds. It is a state of maximum solubility, meaning that no more of a substance can dissolve in a given solvent. In physical science, it can also refer to the highest temperature where a substance can exist in the liquid state without boiling.

The amount of HCl required to make a solution with 100g of water saturated at 60 degrees C depends on the concentration of the HCl solution you are trying to make. If you want to make a saturated solution, the maximum amount of HCl that can be dissolved in 100g of water at 60 degrees C is 55g. If you want a solution that is less than saturated, the amount of HCl needed is less - in this case, 27.5g.

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cjcjckdkxhdkdkxbxjskagsjsoss

Answer:

The PH is 2.66 of the titration solution after 2.19 ml of the naoh was added if the ka of acetic acid is 1.8 x 10-5

Explanation:

The batter was then transferred to a baking dish and placed in the oven for the required baking time.

What is Carbon dioxide?

Carbon dioxide (CO2) is a colorless, odorless gas that is naturally present in the Earth's atmosphere. It is composed of one carbon atom bonded to two oxygen atoms, and is a byproduct of respiration, combustion, and other chemical reactions. CO2 is important for plant growth and is also a greenhouse gas, contributing to the warming of the Earth's atmosphere.

To prepare the cake batter, two eggs were cracked into a mixing bowl and beaten thoroughly. Next, a suitable amount of oil and water were added to the mixture. The cake mix was then slowly added and stirred until it formed a homogeneous mixture.

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Answer:

c) Put it in a bag and properly label it with the chain of custody information.

Step by step explanation:-

Tasting it might kill the investigator.

Drug test would not be appropriate during the crime scene.

Having the knowledge to identify the drug by smelling is quite rare in people.

Mass of rock = 5004.16kg. The mass of the elements present in the compound determines the percentage composition.

Given that the [tex]Fe_{2} O_{3}[/tex] is 80 % by mass.

It means that 80 kg of is present in 100 kg of rock

To find the mass of rock which contains 2800 kg of iron

2800 kg = 2800*1000 g

2 moles of iron are present in 1 mole of

Molar mass of iron = 55.845 g/mol

Mass of 2 moles = 55.845 * 2 = 111.69 g/mol

159.69 g/mol Molar mass of [tex]Fe_{2} O_{3}[/tex]

It implies,

In 159.69 g of iron, there are 111.69 g.

The amount of iron in 159.69/111.69 g of

There are 2800*1000 g in (159.69/111.69) *2800*1000 g of material.

Mass of [tex]Fe_{2} O_{3}[/tex] = 4003.33kg

Thus,

100 kg of rock contains 80 kg.

One kilogram of rock makes up 100/80 kg.

(100/80) *4003.33 kg of rock contains 4003.33 kg.

Mass of rock = 5004.16kg

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Answer:

Here are the names of the esters and the corresponding alcohols and carboxylic acids that were used to make them:

1. Ethyl acetate, made from ethanol and acetic acid

2. Methyl propanoate, made from methanol and propanoic acid

3. Butyl butyrate, made from butanol and butyric acid

4. Octyl formate, made from octanol and formic acid

5. Ethyl benzoate, made from ethanol and benzoic acid

6. Ethyl propionate, made from ethanol and propanoic acid

7. Methyl butyrate, made from methanol and butyric acid

8. Ethyl butyrate, made from ethanol and butyric acid

9. Propyl formate, made from propanol and formic acid

10. Butyl propionate, made from butanol and propanoic acid.

The pH of the resulting solution is 8.57. In terms of moles/liter, pH is the negative logarithm of the concentration of hydrogen ions. pH expresses the nature of the solution (acidic, alkaline or neutral).

Number of HCN moles equals molarity * volume in L.

                                 = 0.337(0.15) = 0.05055 moles

Number of NaCN moles = molarity * volume in L.

                                   = 0.344(0.15)   =0.0516 moles

HCN's Pka is 9.31.

PH   = Pka + log [NaCN]/[HCN]

        = 9.31 + log0.0516/0.05055

        = 9.31 + 0.00893    = 9.319

After adding 0.0359 moles of HCL, the number of moles of HCN is equal to 0.05055 + 0.0359, = 0.08645 moles.

After adding 0.0359 moles of HCl, the number of moles of NaCN is equal to 0.0516-0.0359 moles, = 0.0157 moles.

PH = PKa + log [NaCN]/[HCN] = 9.31 + log [0.0157/0.08645] = 9.31 -0.74086 = 8.57

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While the circular portion of this solar eclipse is not visible in Quito, a partial solar eclipse can be seen there.

A partial eclipse happens when the Sun and Moon are only partly blocked from Earth's view by the Moon. Typically, a sizable portion of the planet's surface outside of an annular or complete eclipse can observe this occurrence.

However, because the umbra travels above the polar areas of the Earth and never touches the Earth's surface, some eclipses can only be seen as partial eclipses. Since it requires well over 90% coverage to observe any dimming of the Sun's brightness, partial eclipses are essentially undetectable. It wouldn't be any dimmer than civil dusk even at 99%.

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