draw the following vector quantity Using the coordinate system.
a. 190 newton east
b. 120km/hr, 250 north of east
c. 60 meters southwest​

Answers

Answer 1

The given vectors quantities can be described by their properties of both

magnitude and direction.

a. The drawing of the vector extending from point (0, 0) to (190, 0) on the coordinate plane is attached.b. The velocity vector extending from  (0, 0) to (108.76, 50.714) on the coordinate plane is attached.c. The displacement vector extending from (0, 0) to (30·√2, 30·√2) is attached.

Reasons:

a. The magnitude of the vector = 190 N

The direction in which the vector acts = East

Therefore, in vector form, we have;

[tex]\vec{F}[/tex] = 190 × cos(0)·i + 190 × sin(0)·j = 190·i

The vector can be represented by an horizontal line, 190 units long

Coordinate points on the vector = (0, 0) and (190, 0)

The drawing of the vector with the above points using MS Excel is attached.

b. Magnitude of the velocity vector = 120 km/hr. 25° North of east

Solution;

The vector form of the velocity is; [tex]\vec{v}[/tex] = 120 × cos(25)·i + 120×sin(25)·j, which gives;

[tex]\vec{v}[/tex] = 120 × cos(25)·i + 120×sin(25)·j ≈ 108.76·i + 50.714·j

[tex]\vec{v}[/tex] ≈ 108.76·i + 50.714·j

Therefore, points that define the vector are; (0, 0) and (108.76, 50.714)

The drawing of the vector is attached

c. The magnitude of the vector = 60 m

The direction of the vector is southwest = West 45° south

The vector form of the displacement is [tex]\vec{d}[/tex] = 60 × cos(45°)·i + 60 × sin(45°)·j

Which gives;

[tex]\vec{d}[/tex] = 30·√2·i + 30·√2·j

Points on the vector are therefore; (0, 0), and (30·√2, 30·√2)

The drawing of the vector is attached

Learn more about vectors here:

https://brainly.com/question/10409036

Draw The Following Vector Quantity Using The Coordinate System. A. 190 Newton East B. 120km/hr, 250 North
Draw The Following Vector Quantity Using The Coordinate System. A. 190 Newton East B. 120km/hr, 250 North
Draw The Following Vector Quantity Using The Coordinate System. A. 190 Newton East B. 120km/hr, 250 North

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A 30.4-newton force is used to slide a 40.0-newton crate a distance of 6.00 meters at constant speed along an incline to a vertical height of 3.00 meters. Calculate the work done by a friction force on the crate as it slides 6.00 m along the incline.

Answers

Hi there!

Since the crate is being slid at a constant speed, the forces sum to 0 N. In this instance, the following forces occur in the axis of interest:

Wsinθ = downward acceleration along incline due to gravity (N)

Fκ = kinetic friction force along incline (N)

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The acceleration due to gravity and friction force act in the same direction, so:

Wsinθ + Fκ = A

Solve for sinθ using right triangle trigonometry:

sinθ = O/H = 3/6 = 0.5

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Now, recall that:

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Since the box's displacement is in the same axis as the force but OPPOSITE direction, we must use:

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Work done by friction = -Fd = -10.4(6) = -62.4 J

If a category 6 hurricane would exist how fast do you think it would be?

Answers

My Answer:The scale starts with a Category 1, which ranges from 74 to 95 mph (119 to 153 km/h). A Category 5 storm has winds of 156 mph (251 km/h) or stronger. An extrapolation of the scale suggests that if a Category 6 were created, it would be in the range of 176-196 mph.

After the series of powerful storm systems of the 2005 Atlantic hurricane season, as well as after Hurricane Patricia, a few newspaper columnists and scientists brought up the suggestion of introducing Category 6, and they have suggested pegging Category 6 to storms with winds greater than 174 or 180 mph (78 or 80 m/s).

There is no such thing as a Category 6 hurricane. When Hurricane Irma was headed toward the coast of southern Florida in August, it had maximum wind speeds of 185 mph, according to the New York Times. But the Saffir-Simpson scale only goes up to 5.Hope it helps(◠ᴥ◕ʋ)

Express the sum of 2.52 kg + 131 g in kilograms with the correct number of significant
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Answers

Convert second term into kg

131 = 0.131

Term has become:

2.52 + 0.131

The total is:

2.651 kg

Which element forms more com-
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Answers

Answer:

Terms in this set (7) Which element forms more compounds than all the other elements combined? Carbon.

Explanation:

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10.38°
一企一
14.67°
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Answers

Trigonometry allows to find the result for the question about the height of the mountain is:

The height mountain  is:  y = 9674.4 ft

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         [tex]tan \theta = \frac{y}{x}[/tex]  

Where θ is the angle, y the opposite leg (height) and x the adjacent leg (horizontal distance).

In the attachment we can see a diagram of the system. They indicate that for x  distance the angle is 14.67º  

         tan 14.67 = [tex]\frac{y}{x}[/tex]  

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        tan 10.38 = [tex]\frac{y}{x+15860}[/tex]

We look for the horizontal distance (x) with these equations.

        x tan 14.67 = (x + 15860) tan 10.38

        x tan 14.67 / tan 10.38 = x + 15860

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        x 0.429 = 15860

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        x = 36955.3 ft

We calculate for the height.

        y = x tan 14.67

        y = 36955.3 tan 14.67

        y = 9674.4 ft

In conclusion using trigonometry we can find the result for the height of the mountain is:

The height is y = 9674.4 ft

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Abigail runs one complete lap (400m) around the track, while Gabi runs a 50 meter dash in a straight line. Which runner had a greater displacement?

Answers

Answer:

The distance of one lap on this track from the start line to the finish line is 400 meters. Two laps around the track is 800 meters, half a lap is 200 meters, and so on.

    Remember, displacement is the direction from the starting point and the length of a straight line from the starting point to the ending point. If a runner was going to run 400 meters (one lap around the track), they would start and stop at the same place on the track. Therefore, their displacement would be 0.

 

Explanation:

hope this helped

Answer:

[tex]\boxed {\boxed {\sf Gabi \ had \ greater \ displacement}}[/tex]

Explanation:

Displacement is the change in the position of an object.

Abigail runs a complete lap around the track, which is 400 meters. Even though she ran 400 meters, she has no displacement. If she starts and ends at the same spot, there is no change in position.

Gabi runs a 50 meter dash in a straight line. Gabi has 50 meters of displacement. She runs in a straight line and is 50 meters away from where she began.

While Abigail ran the farther distance, Gabi had the greater displacement.

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Answers

Answer:

The mass of the eagle is about 5 Kg

Explanation:

1/2 M= Ke/V^2

120 km/h = 33.3333m/s

1/2 M = 2,800/33.3333^2

1/2 M = 2,800/ 1111.10888889

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(2) 1/2 M = (2) 2.52000504h001

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The Law of Exponents applies here

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The Production Possibilities Curve (PPC) is a model that captures scarcity and the opportunity costs of choices when faced with the possibility of producing two goods or services. Points on the interior of the PPC are inefficient, points on the PPC are efficient, and points beyond the PPC are unattainable.

Explanation:

Suppose you drop a 10-pound weight and a 5-pound weight on the Moon, both from the same height at the same time. What will happen? The 10-pound weight will hit the ground before the 5-pound weight. The 5-pound weight will hit the ground before the 10-pound weight. Both weights will float freely because everything is weightless on the Moon. Both will hit the ground at the same time.

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Answer:

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Answers

Answer:

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Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 284 × 9 = 2556

We have the final answer as

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Answer:

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A pail of water of mass 2000 gm is rotated in a vertical circle of radius 1.00 m. What is the pail’s minimum speed at the top of the circle if no water is to spill out and the tension exerted by the string is 25 N?

Answers

The pail’s minimum speed at the top of the vertical circle is 4.72 m/s.

The given parameters:

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The net force on the pail of water at the top of the vertical circle is calculated as follows;

[tex]T = ma - mg\\\\T = \frac{mv^2}{r} - mg\\\\T + mg = \frac{mv^2}{r} \\\\mv^2 = r(T + mg)\\\\v^2 = \frac{r(T + mg)}{m} \\\\v= \sqrt{\frac{r(T + mg)}{m}} \\\\v = \sqrt{\frac{1 (25\ + \ 2 \times 9.8)}{2}} \\\\v = 4.72 \ m/s[/tex]

Thus, the pail’s minimum speed at the top of the vertical circle is 4.72 m/s.

Learn more about tension on top of vertical circle here: https://brainly.com/question/19904705

The pail’s minimum speed at the top of the circle if no water is to spill out is; v = 4.722 m/s

We are given;

Mass of the pail of water; m = 2000 g = 2kg

Radius of the circle; r = 1 m

Tension exerted by string; T = 25 N

To calculate the net force on the pail of water at the top of the vertical circle, let us take equilibrium of forces to give;

W - T = ma

Where;

W is weight = mg

T is tension on the string

Now, in circular motion, we know that;

Acceleration is; a = v²/r

Thus;

mg - T = m(v²/r)

Making v the subject of the formula gives us;

v = √[(r(T + mg)/m)

Plugging in the relevant values gives;

v = √[(1(25 + (2 * 9.8))/2)

v = 4.722 m/s

Read more about Tension exerted by spring atop a vertical circle at; https://brainly.com/question/19904705


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Answers

Answer:2.86seconds

Explanation:

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t=2h/g

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The fibers of the sweater lose electrons.

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Answer:

The fibers of the sweater lose electrons.

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Answer:

468.42572 Wavelength In Metres

Explanation:

Answer:

[tex]\huge\boxed{\sf Wavelength= 470\ m}[/tex]

Explanation:

Given Data:

Speed of light = c = 3 × 10⁸ m/s (Constant)

Frequency = f = 640 kHz = 6.4 × 10² × 10³ Hz = 6.4 × 10⁵ Hz

Required:

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Formula:

λ = c / f

Solution:

λ = 3 × 10⁸ / 6.4 × 10⁵

λ = 0.47 × 10³

λ = 4.7 × 10² m

λ = 470 m

[tex]\rule[225]{225}{2}[/tex]

Hope this helped!

~AH1807

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