During Taylor's experiment, which piece of data would be qualitative?

mass of the cars

degree of the ramp incline

time in seconds

none are qualitative

Answer: 139.2 g

Explanation:

2.9 mol KClO3 (3 mol O2 / 2 mol KClO3) (32 g / 1 mol O2) = 139.2 grams :)

Taking into account the definition of calorimetry, the temperature change of A will be one sixth of the temperature change of B.

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

Sensible heat is defined as the amount of heat that a body absorbs or releases without any changes in its physical state (phase change).

So, the equation that allows to calculate heat exchanges is:

Q = c× m× ΔT

where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.

In this case, for object A:

QA = cA× mA× (ΔT)A

and for object B:

QB = cB× mB× (ΔT)B

You know:

Object A has double the specific heat of object B. ⇒ cA= 2× cB

Object A has triple the mass of object B. ⇒ mA= 3× mB

If the same amount of heat is applied to both objects ⇒ QA= QB

Then:

cA× mA× (ΔT)A= QB = cB× mB× (ΔT)B

2× cB × 3× mB× (ΔT)A=  cB× mB× (ΔT)B

Solving:

6× cB × mB× (ΔT)A= cB× mB× (ΔT)B

(ΔT)A= (cB× mB× (ΔT)B) ÷ (6× cB × mB)

(ΔT)A=[tex]\frac{1}{6}[/tex] (ΔT)B

Finally, the temperature change of A will be one sixth of the temperature change of B.

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The answers to your questions are as follows

A) The number of aluminium ions present = 1.62 * 10²³ ions

B) The number of chloride ions present = 9.86 * 10²³  ions

C) The mass of one unit of aluminium chloride = 133.34 grams

Given data :

mass of aluminium chloride = 37.2 g

molar mass of aluminium chloride = 133.34 g/mol

note : I mole of a molecule has 6 * 10²³ molecules  

Number of moles = mass / molar mass = 0.27 moles

A) aluminium ions present

moles of AlCl₃ * 6 * 10²³

= 0.27 * 6 * 10²³   = 1.62 * 10²³ ions

B) Chloride ions present

moles of AlCl₃ * 6 * 10²³  * 3

= 0.27 * 6 * 10²³ * 3

= 4.86 * 10²³ ions

C) The mass of one formula unit of aluminium chloride = 133.34 grams

Hence we can conclude that the answers to your question are as listed above.

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Answer:

9   I believe

Explanation:

Answer:

7. H

8. F

9. G.

10. D

11. A

12. E

13. B

14. C

The buret should be conditioned before loading it with the titrant.

This is defined as laboratory apparatus which is used in quantitative chemical analysis to measure the volume of a liquid or a gas.

It should be conditioned with the titrant solution to prevent dilution from occurring as a result of cleaning it with water.

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C. Walking on wet floors shows that Friction is undesirable

The solute in the scenario where a chemist adds 36.0 g of sodium chloride to 200 g of water at STP and all of the sodium chloride is sodium chloride.

A solute is a substance that forms a solution with another substance called solvent in a process called solubility.

According to this question, a chemist adds 36.0 g of sodium chloride to 200 g of water at STP and all of the sodium chloride dissolves in the water.

This shows that the sodium chloride is the solute added to the water (solvent).

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Answer:

According to the kinetic theory of gases, in an ideal gas between two successive collisions, a gas molecule travels in a straight line.

Answer:

These clouds extend through the lower and mid-layers of the troposphere bringing rain to the surface below.

Explanation:

The bases of clouds in the middle level of the troposphere, given the prefix “alto,”

Answer:

Mendeleev left some gaps in his periodic table because he believed that in future more elements will be discovered.

Explanation:

"Mendeleev left gaps in his table to place elements not known at the time. By looking at the chemical properties and physical properties of the elements next to a gap, he could also predict the properties of these undiscovered elements."

Answer:

you are not posted question

75% dominant and 25% resistive

The extraction of metal usually makes use of the method of precipitation in which a reagent is added which is able to precipitate the required metal in its pure form without impurities.

The process of extraction has to do with the removal of a substance from another. It is usually the way that pure substances are obtained in chemistry. The question is incomplete but I will try to give a general idea.

The extraction of metal usually makes use of the method of precipitation in which a reagent is added which is able to precipitate the required metal in its pure form without impurities. We can not make numerica;l calculatiosn as the values are missing.

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Answer:

Polyester

Explanation:

For an unknown using the retention times 1. 6 min for ch4, 12. 8 min for octane, 15. 4 min for the unknown, and 19. 6 min for nonane, the kovats retention index is mathematically given as

I = 807.857

Generally, the equation for the Kovats index(i)  is mathematically given as

[tex]I= \frac{100[n + (N - n) x (Log tr (unknown) - logtr (n))}{ logtr(N) - logtr(n))]}[/tex]

Therefore

[tex]I= \frac{100[ 1+8*(log(14.7) -log (1.5)}{log (19.8) - log (1.5)) 0]}[/tex]

I = 100[ 1+8*(0.991/1.12)]

I = 807.857

In conclusion, Kovats retention index

I = 807.857

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Kovats retention index is a system that converts the retention time into the independent constants of the system. The Kovats retention index for the unknown is 807.857.

The Kovats retention index (I) is the system used in analytical techniques like gas chromatography for the conversion of the retention time.  It is given mathematically as:

[tex]\rm I = \rm \dfrac{100[n+(N-n)x(Logtr(unknown)-logtr(n))}{Logtr(N)-Logtr(n)]}[/tex]

Substituting values and solving further,

[tex]\begin{aligned} \rm I &= \rm \dfrac{100[1+8 \times (Log(14.7) - log (1.5))}{(log (19.8) - log (1.5))0}\\\\&= 100 [ 1 + 8 (\dfrac{0.991}{1.12})]\\\\&= 807.857\end{aligned}[/tex]

Therefore, the Kovats retention index for an unknown is 807.857.

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#SPJ4

Answer:

Arsenic (33As) has 33 known isotopes and at least 10 isomers.

The partial stress of H2 is 737.47 mmHg Let's observe the Ideal Gas Law to find out the whole mols.

We count on that the closed vessel has 1L of volume

These are the whole moles. Now we are able to know the moles of water vapor, to discover the molar fraction of it.

Mole fraction is a unit of concentration, described to be identical to the variety of moles of an issue divided through the whole variety of moles of a solution. Because it's miles a ratio, mole fraction is a unitless expression.

Thus it is clear that the partial pressure of H2 is 737,47 mmHg.

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Answer:

isobars

Explanation:

How?

So they are isobars

The number of moles of air present is 0.056 mole

The ideal gas is one in which molecules do not attract or repel each other.Many gases like oxygen,nitrogen, carbon di oxide can be treated as the ideal gases as particular temperature and pressure.The real gases at high temperature and lower pressure can be treated as ideal gases.

The given data in the question is

Volume = 1.35 L

Pressure (P) = 750 torr

Temperature (T) = 17 °C = 17 + 273 = 290 K

Gas constant (R) = 62.396 L•torr/mol•K

The number of moles (n) =?

How to determine the number of moles:

The number of moles present can be obtained by using the ideal gas equation as illustrated below:

[tex]PV=nRT[/tex]

Divide both sides by RT

[tex]n=\dfrac{PV}{RT}[/tex]

[tex]n=\dfrac{(750\times 1.350}{62.396\times 290)}[/tex]

[tex]n=0.056\ moles[/tex]

Hence, the number of moles of air present is 0.056 mole

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Answer:

answer in picture

Explanation:

Moles are an estimation of the smallest unit of the molecules and the atoms in a sample. The moles of ammonium nitrate in a sample are 0.5010 moles.

Moles are calculated by dividing the mass of the substance in gm by that of the molar mass in gram per mole.  

Given.

Mass of ammonium nitrate = 40.10 gm

The molar mass of ammonium nitrate = 80. 0432 g/mol

Moles of ammonium nitrate are calculated as:

[tex]\begin{aligned}\rm moles &= \rm \dfrac{mass}{molar\; mass}\\\\&= \dfrac{40.10}{80.0432}\\\\&= 0.5010 \;\rm mol\end{aligned}[/tex]

Therefore, moles of ammonium nitrate present is option d. 0.5010 moles.

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The final pressure or the air pressure on the top of the mountain is 0.818.

Air pressure is the pressure exerted by air in the atmosphere of the earth.

By the Gas law

[tex]\dfrac{P_1V_1}{ T1} =\dfrac{ P_2V_2 }{T_2}[/tex]

Given, the pressure of the valley floor is 1 atm. = P1

The temperature is 25° C = T1

The volume of the bag is 0.985 L. = V1

The temperature at the top of the mountain is ° C = T2

Now, the volume of the bag is 1. 030 L = V2

To find P2

Put the values in the formula

[tex]\dfrac{1 atm \times0.985 L}{ 25} =\dfrac{ P_2 \times 1. 030 L }{22}\\\\0.03832 = 0.0468 \times P_2\\\\P_2= 0.818[/tex]

Thus, the final pressure is 0.818.

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Considering the ideal gas law,  there are 279.42 moles of acetylene in the tank.

Ideal gases are a simplification of real gases that is done to study them more easily. It is considered to be formed by point particles, do not interact with each other and move randomly. It is also considered that the molecules of an ideal gas, in themselves, do not occupy any volume.

An ideal gas is characterized by three state variables: absolute pressure (P), volume (V), and absolute temperature (T). The relationship between them constitutes the ideal gas law, an equation that relates the three variables if the amount of substance, number of moles n, remains constant and where R is the molar constant of gases:

P×V = n×R×T

In this case, you know:

Replacing in the ideal gas law:

17.4192 atm× 390 L = n×0.082 [tex]\frac{atmL}{molK}[/tex]× 296.5 K

Solving:

[tex]n=\frac{17.4192 atmx 390 L}{0.082 \frac{atmL}{molK}x296.5 L}[/tex]

n= 279.42 moles

Finally, there are 279.42 moles of acetylene in the tank.

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Answer:

B . Water molecules can collide with other particles more than neon atoms can.

When Lead reacted with nitric acid, lead(II) nitrate, nitrogen oxide and water are produced.

What products are produced when lead reacts with nitric acid?

Lead(II) nitrate, nitrogen oxide and water are the products which are produced by reacting lead and nitric acid with each other. The nitrogen attach with the lead molecule as well as oxygen which produces Lead(II) nitrate and nitrogen oxide.

So we can conclude that when Lead reacted with nitric acid, lead(II) nitrate, nitrogen oxide and water are produced.

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The new volume of the gas in the balloon when the pressure is doubled is determined as 11.2 L.

The new volume of the balloon is determined by applying general gas equation as shown below

P₁V₁/T₁ = P₂V₂/T₂

Where;

[tex]\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2} \\\\V_2 = \frac{P_1V_1T_2}{T_1P_2} \\\\V_2 = \frac{1 \times 22.4 \times 273}{273 \times 2} \\\\V_2 = 11.2 \ L[/tex]

Thus, the new volume of the gas in the balloon when the pressure is doubled is determined as 11.2 L.

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Since K3 is greater than 1, the reaction is thermodynamically favorable.

Data;

This states that the heat change in a given chemical reaction is the same irrespective of the number of process in which the reaction is effected.

Using Hess Law;

[tex]rxn_3 = rxn_1 * 2rxn_2\\k_3 = k_1 * k_2^2\\k_3 = 2*10^-^6 * (1*10^3)^2\\k_3 = 2[/tex]

substituting this using Gibbs law,

[tex]\delta G^0_3 = -RT\ln K_3\\\delta G^0_3 < 0[/tex]

Since K3 is greater than 1, the reaction is thermodynamically favorable.

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The reaction which shows the bronsted-lowry acid reacting is HCl + H₂O → H₃O⁺ + Cl⁻.

According to the Bronsted-Lowry theory, the species which donates H⁺ ion to the solution is known as Bronsted-Lowry acid and which accepts H⁺ ion is known as Bronsted-Lowry base.

Among the given reactions, only the reaction which is showing Bronsted-Lowry acid is:

HCl + H₂O → H₃O⁺ + Cl⁻

Here HCl is a Bronsted-Lowry acid as it gives H⁺ ion in the aqueous solution.

Hence, option (3) is correct.

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