Answer: The largest cube has volume of 64 cubic units, and the sides are 4 units long.
Step-by-step explanation:
Elena has 80 unit cubes and she has to build the largest cube using the unit cubes she has
Unit cube has a dimension of 1 unit on each side (Cube has all sides equal)
To make the largest cube, she needs to calculate the maximum volume which is near 80 units of cubes
Therefore,
We have a cube with each side 4 units whose volume is 64 and a cube with each side 5 units whose volume is 125
Elena has only 80 unit cubes to build the maximum-sized cube
Therefore she will be able to build a cube with each side as 4 units with a volume of 64 units with 16 spare cubes
Question HelpMultiple Representations A vehicle ses 7 gallons of gasoline to travel 147 miles. The vehicle uses gasoline at a steady rate. Use pencil and paper to draw a picture that models the situation Write a table of equivalent ratiosThen use the table to find the number of gallons of gasoline the vehicle uses to travel 63 milesComplete the tableGallons Miles1231411421
We know a vehicle uses 7 gallons of gasoline to travel 147 miles.
This gives us a ratio: 147/7 = 21
The vehicle travels 21 miles per gallon of gasoline
The situation can be modeled as a line with a constant slope of 21 miles/gallon
If we use the horizontal axis for the number of gallons and the vertical axis for the miles traveled, we can draw an approximate graph
Let's give the gallons (g) some values to fill up the table:
For g=1, miles = 21
For g=2, miles = 42
For g=3, miles = 63
For g=7, miles = 147
For g=14, miles = 294
For g=21, miles = 441
The graph is shown below
The system of equations may be solved by hand calculation or by using the crossing-graphs method.Solve the following system using the crossing-graphs method.2x - y = 04x + 2y = 48(x, y) = (_____,_____)
The first thing you can do is graph each of the equations. To do this, you can write the equations following the form
[tex]y=mx+b[/tex]Where m is the slope of the line and b the intersection point with the y axis. Then
[tex]\begin{gathered} 2x-y=0 \\ 2x=y \\ y=2x \\ \text{ And the other equation} \\ 4x+2y=48\text{ } \\ \text{To simplify the equation, you can divide by 2 both sides of the equation} \\ 2x+y=24 \\ y=-2x+24 \end{gathered}[/tex]Graphing you have
The solution of the system of equations will be the point at which both lines intersect. Therefore, the solution is (6,2).
Find the derivativef(x) = 1 / (x - 2)
ANSWER
[tex]\frac{df}{dx}=-\frac{1}{(x-2)^2}[/tex]EXPLANATION
We want to find the derivative of the given function:
[tex]f(x)=\frac{1}{x-2}[/tex]First, we have to rewrite the function as follows:
[tex]f(x)=(x-2)^{-1}[/tex]Next, make the following substitution:
[tex]a=x-2[/tex]The function now becomes:
[tex]f(x)=a^{-1}[/tex]Apply the chain rule of differentiation:
[tex]\frac{df}{dx}=\frac{df}{da}\cdot\frac{da}{dx}[/tex]Therefore, we have that:
[tex]\frac{df}{da}=-1\cdot a^{-1-1}=-a^{-2}[/tex]and:
[tex]\frac{da}{dx}=1[/tex]Therefore, the differentiation of the function is:
[tex]\begin{gathered} \frac{df}{dx}=-a^{-2}\cdot1 \\ \Rightarrow\frac{df}{dx}=-(x-2)^{-2}\cdot1 \\ \frac{df}{dx}=-\frac{1}{(x-2)^2} \end{gathered}[/tex]On its website a tv station displays temperature data for each hour during the past 24 hours. The data are displayed as using two different functions on a line graph. One function shows the current temperature and the other function shows the historical average. Which quantities are represented by the y-values on the line graph
, Given the question, we are asked to find which of the quantities are represented by the y-values on the line graph .
Explanation
In the question, we are told that the tv station displays temperature data using two different functions on a line graph. One of the functions shows the current temperature and the other function shows the historical average.
A function, by definition, can only have one output value(y) for any input value. In this case the input values are the time the temperature which we result in the output value of the historical average and temperature.
Therefore,
Answer
Option D
Identify the side lengths that form a right triangle.a. 12, 13, 16b. 15, 20, 21c. 9, 40, 42d. 10, 24, 26Identify the side lengths that form a right triangle.a. 3, 4, 8b. 30, 40, 45c. 5, 12, 13d. 6, 12, 133. do the side lengths of 8, 10, and 13 form a right triangle? 4. Determine if ▼ABC is a right triangle if AB=36, AC=48 and BC=60
Answer:
d. 10, 24, 26
Explanation:
To identify the side lengths that form a right triangle, we check if it satisfies the Pythagorean theorem.
By the theorem:
[tex]\begin{gathered} a^2=b^2+c^2 \\ a\text{ is the hypotenuse, the longest side.} \end{gathered}[/tex]a. 12, 13, 16
[tex]\begin{gathered} 16^2=12^2+13^2 \\ 256=144+169 \\ 256\neq313 \end{gathered}[/tex]These side lengths do not form a right triangle.
b. 15, 20, 21
[tex]\begin{gathered} 21^2=15^2+20^2 \\ 441=225+400 \\ 441\neq625 \end{gathered}[/tex]These side lengths do not form a right triangle.
c. 9,40,42
[tex]\begin{gathered} 42^2=9^2+40^2 \\ 1764=81+1600 \\ 1764\neq1681 \end{gathered}[/tex]These side lengths do not form a right triangle.
d. 10, 24, 26
[tex]\begin{gathered} 26^2=10^2+24^2 \\ 676=100+576 \\ 676=676 \end{gathered}[/tex]These side lengths form a right triangle since both sides of the equation are the same.
What is the difference between chemical and physical change
Answer:
Step-by-step explanation:
In a physical change the appearance or form of the matter changes but the kind of matter in the substance does not. However in a chemical change, the kind of matter changes and at least one new substance with new properties is formed.
Identify the type of polar graph for the equation: r = 2+2cos θ aLimacon with inner loop bCardioid cDimpled limacon dConvex limacon eRose Curve fCircle gLemniscate
is choice a
iner loop Limacon
Ben, Claire and Devon are training for a triathalon. Today, they are practicing their swimming by swimming one mile. Ben swam 0.77 of the mile before stopping. Claire swam 3/5 of the mile and Devon swam 82% of the mile before stopping. Who swam the farthest distance? Who swam the shortest distance?
Given:
Ben, Claire, and Devon are swimming one mile.
Ben swam 0.77 of the mile before stopping.
So, the distance Ben swam = 0.77 x 1 = 0.77 mile
Claire swam 3/5 of the mile.
So, the distance Claire swam = 3/5 x 1 = 3/5 = 0.6 miles
Devon swam 82% of the mile before stopping.
So, the distance Devon swam = 82% of 1 mile = 0.82 x 1 = 0.82 miles
Arrange the distances in order from the largest to the least:
0.82, 0.77, 0.6
So, the answer will be:
The farthest distance is for Devon = 0.82 miles
The shortest distance is for Claire = 0.6 miles
Your psychology class has 45 students. You want to ask an SRS of four students from your class whether they prefer taking online or face-to-face courses. You label the students 01, 02, . . . , 45. You enter the table of random digits at this line:
78314 96529 67532 98144 28944 26687 49634 88274 20361
Your SRS contains the students labeled
A. 14, 32, 42, 44.
B. 31, 29, 44, 28.
C. 31, 29, 29, 44.
D. 31, 49, 29, 44.
E. 78, 31, 49, 65.
Answer:
Step-by-step explanation:
The answer is c! :)
Answer:
The answer is B. 31, 29, 44, 28.
Step-by-step explanation:
(blank)+(7x+24)=180
7x + (blank)+ = 180
7x =
x =
Answer:
first blank: 72°
2nd blank: 96
next line: 84
last: 12
Step-by-step explanation:
The two marked angles are called same-side interior angles or consecutive angles.
They add up to 180°
Thats how you know how to set up the equation.
72° + 7x + 24 = 180
Add the plain numbers (the 72 and 24)
7x + 96 = 180
subtract 96 from both sides.
7x = 84
Divide both sides by 7.
x = 12
1 3/8 × 3 2/3=answer must be in simplest fraction form
EXPLANATION
Given the fractions 1 3/8 and 3 2/3
First we need to turn both fractions into improper ones
[tex]1\frac{3}{8}=\frac{11}{8}[/tex][tex]3\frac{2}{3}=\frac{11}{3}[/tex]Now, multiplying both fractions:
[tex]\frac{11}{8}\cdot\frac{11}{3}=\frac{121}{24}[/tex]The answer is 121/24
How to solve 11 3/7 × 7/10 =
Given:
The objective is to solve the given equation.
The given equation can be solved by,
[tex]\begin{gathered} =11(\frac{3}{7})\cdot\frac{7}{10} \\ =\frac{11\cdot3}{10} \\ =\frac{33}{10} \\ =3.3 \end{gathered}[/tex]Hence, the value of the equation is 3.3
Which of the following pairs of numbers do not have a geometric mean of 12? A 11 and 13 B 20 and 7.2 C 3 and 48 D 5 and 28.8
Answer
Option A contains two numbers that do not have a geometric mean of 12.
11 and 13 do not have a geometric mean of 12.
Explanation
The geometric mean of two numbers, a and b, is given as
Geometric mean = √(a × b)
So, we want to find which two numbers will have a geometric mean of 12
12 = √(a × b)
Taking the square of both sides, we see that
144 = (a × b)
So, whichever two numbers give a product of 144 is our answer.
Option A
11 × 13 = 143
Option B
20 × 7.2 = 144
Option C
3 × 48 = 144
Option D
5 × 28.8 = 144
Hope this Helps!!!
Hey could someone help me out with this thank you
Karen will run more than 28
Miguel has 225 base ball cards. He plans to keep 75 cards and give the rest to his friends.Can Miguel give an equal number of cards to 6 friends? Explain.
We know what Miguel has 225 baseball cards, and he plans on keeping 75, while giving them the rest of them to his friends. We want to know if he can give an equal number to 6 of his friends.
For this objective, we know what he will have to give to his friends an amount of:
[tex]undefined[/tex]ABC is dilated by a factor of 5 produce A'B'C.What is A'C, the length of AC after the dilation? What is the measure of angle A?
We have that the scale factor is 5, then, the dilation is an enlargement.
Then, the new lengths are:
[tex]\begin{gathered} A^{\prime}C^{\prime}=5AC=5\cdot5=25 \\ A^{\prime}B^{\prime}=5AB=5\cdot4=20 \\ B^{\prime}C^{\prime}=5BC=5\cdot3=15 \end{gathered}[/tex]therefore, A'C' =25.
Finally, the dilations don't affect the angles, therefore, angle A remains with the measure of 37°
What’s negative 5 + 1 fourth equal
Answer:
-4 3/4
Step-by-step explanation:
-5 x 4/4 + 1/4
-19/4 = -4 3/4
Mikayla and Courtney both leave the internet cafe at the same time, but in opposite directions. If Courtneytravels 7 mph faster than Mikayla and after 6 hours they are 162 miles apart, how fast is each traveling?
Courtney travels at 17mph and Mikayla at 10mph
1) In this question, we need to set equations for that.
Courtney Mikayla
v +7 v speed
2) Note that we have to use this relation:
[tex]Speed\, {\times time=distance}[/tex]So, we can write out the following:
[tex]\begin{gathered} v6+(v+7)6=162 \\ v6+6v+42=162 \\ 12v+42-42=162-42 \\ 12v=120 \\ v=10 \end{gathered}[/tex]So we can now plug into Mikayla's speed and Courtney
Mikayla travels at 17mph and Courtney at 10mph
a gate that is 5 ft tall casts a shadow 9 ft long the house behind the gate cast a shadow of 54 ft how about how many feet tall is the house
In this case, we'll have to carry out several steps to find the solution.
Step 01:
Data
gate:
hg = 5 ft
shadow = 9ft
house
hh = ?
shadow = 54 ft
Step 02:
We must apply the theorem of thales.
[tex]\frac{hg}{hh}=\frac{shadow\text{ gate}}{\text{shadow house}}[/tex][tex]\frac{5ft}{hh}=\frac{9ft}{54\text{ ft}}[/tex]hh * 9 ft = 5 ft * 54 ft
hh = (5 ft * 54 ft ) / 9 ft
hh = 270 ft ² / 9 ft = 30 ft
The answer is:
The house is 30ft tall.
HELP PLS (question in image)
Answer:
[tex]106-19\sqrt{x} 10[/tex]
Step-by-step explanation:
the table shows the number of jeans sold at a store at different prices
To make a plot of the data you first must choose your axis. In this case we've chosen the X axis to be the average cost of the jeans and the Y axis to be the number of copies sold. To graph the data we match the information we're given in the table as shown in the drawing.
Given f(x) = 2x - 1 h(x) = x^2 + 1Find f[h(7)]
Answer:
[tex]f\lbrack h(7)\rbrack\text{ = 99}[/tex]Explanation:
Given the functions:
[tex]\begin{gathered} f(x)=2x-1 \\ h(x)=x^2+1 \end{gathered}[/tex]We want to find:
[tex]f\lbrack h(7)\rbrack[/tex]First of all, we need to find:
[tex]f\lbrack h(x)\rbrack[/tex]This is done by inserting the value of h(x) into f(x)
So, we have:
[tex]\begin{gathered} f\lbrack h(x)\rbrack=2(x^2+1)-1 \\ =2x^2+2-1 \\ =2x^2+1 \end{gathered}[/tex]Substituting 7 for x in f[h(x)], we have f[h(7)]
[tex]\begin{gathered} f\lbrack h(7)\rbrack=2(7^2)+1 \\ =2(49)+1 \\ =98+1 \\ =99 \end{gathered}[/tex]Which is what we are looking for.
Consider functions h and k. Every x value has a relationship in k of x. What is the value of (h o k)(1)? A. 28 B. 4 C. 1 D. 0
Recall that:
[tex](f\circ g)(x)=f(g(x)).[/tex]Therefore:
[tex](h\circ k)(1)=h(k(1)).[/tex]From the given diagram we get that:
[tex]k(1)=3.[/tex]Then:
[tex]h(k(1))=h(3).[/tex]Now, from the given table we get that:
[tex]h(3)=28.[/tex]Therefore:
[tex](h\circ k)(1)=28.[/tex]Answer: Option A
REI pays $330.30 for a 6-person tent and the markup is 35% of cost. Find the markup.
First convert 35% into decimal
35% → 0.35
To find 35% of $330.30, multiply it to its decimal
$330.30 ˣ 0.35 = $115.605
Rounding off to the nearest cent.
The markup of the tent is $115.61
What is lim (2x² - x + 3)/(3x² + 5) as x approaches + ∞?
Given:
lim (2x² - x + 3)/(3x² + 5)
We are to
Derrick's football team needs to raise at least $1,000 for new uniforms they have collected 480 so far which inequality represents the amount of money,m, the team still needs to raise A. m>$480 B. m<$480 C.m<$520 D.m>$520
The inequality representing the amount of money, m. Derrick's football team needs to raise is D. m>$520
What is inequality?In mathematics, Inequality is part of equations solved with the use of the some special type of equality signs. The signs used inequality calculations are
greater thanless thangreater than or equal toless than or equal toGiven that:
Derrick's football team needs to raise at least $1,000
The team collected 480
To solve the given problem we have the inequality in the form
at least $1,000 ≡ greater than or equal to 1000
m > $1000
having collected $480 so far. The amount collected is subtracted from the $1000
m > $1000 - $480
m > $520
Read more on inequality here: https://brainly.com/question/25275758
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I need help with graph inequalityx < 1 on number lines
Answer:
The graph for the inequality x < 1 is shown below
Explanation:
The graph is marked on the number line, from the point 1 to the left, 1 is not included in this set, so the point is not shaded
find the value of. abe, bec, and the minor arc ec
Answer
Angle ABE = 64°
Angle BEC = 48°
Minor arc EC = 134°
Explanation
The key to solving this is to take a look at this image below
According to the tangent-chord theorem, we know that
Tangent Chord angle ABE = (Intercepted arc BE)/2
Angle ABE = (128°/2)
Angle ABE = 64°
Tangent chord angle CED = (Intercepted arc EC)/2
68° = (Minor arc EC/2)
Multiply both sides by 2
136° = Minor arc EC
To find the Angle BEC, we need to first obtain the arc BC
The total angle around a circle is 360°
Arc BE + Arc BC + Arc EC = 360°
128° + Arc BC + 136° = 360°
Arc BC = 360° - 128° - 136°
Arc BC = 96°
Then to find the Angle BEC, the image attached below guides us
So, we can easily say that
Angle BEC = ½ (Arc BC)
Angle BEC = ½ (96°)
Angle BEC = 48°
Hope this Helps!!!
how do I use a right triangle to write the following expression as an algebraic expression?
So, we want to express the following:
[tex]\sec (\sin ^{-1}(\frac{x}{\sqrt[]{x^2+81}}))[/tex]As an algebraic expression.
If:
[tex]\begin{gathered} \sin ^{-1}(\frac{x}{\sqrt[]{x^2+81}})=\theta \\ \text{Then,} \\ \sin (\theta)=\frac{x}{\sqrt[]{x^2+81}} \end{gathered}[/tex]We could draw the following triangle:
Remember that the secant function relations the hypotenuse of the triangle and the adjacent side of the triangle. So first, we should find the adjacent side using the pythagorean theorem:
[tex]\begin{gathered} a^2=(\sqrt[]{x^2+81})^2-x^2 \\ a^2=x^2+81-x^2 \\ a^2=81\to a=9 \end{gathered}[/tex]Therefore, the adjacent side is 81. And, the value of:
[tex]\sec (\sin ^{-1}(\frac{x}{\sqrt[]{x^2+81}}))[/tex]Is:
[tex]\sec (\sin ^{-1}(\frac{x}{\sqrt[]{x^2+81}}))=\frac{\sqrt[]{x^2+81}}{9}[/tex]O GRAPHS AND FUNCTIONSDomain of a rational function: Excluded values
Recall that the domain of a rational function consists of all the real numbers x except those for which the denominator is 0.
The denominator of the given rational function is:
[tex]d(x)=x^2+11x-18.[/tex]Notice that:
[tex]\begin{gathered} x^2+11x+18=x^2+2x+9x+9*2 \\ =x(x+2)+9(x+2)=(x+9)(x+2). \end{gathered}[/tex]Therefore d(x)=0 at x=-9 and x=-2, then those values are not in the domain of g.
Answer:
[tex]x=-9,-2.[/tex]