eometry Part 4 - Lesson 1 Assessment - EDCP.MA004.D
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What is the area of a sector of a circle with a central angle of measure 180° and whose radius is 5
cm? Leave your answer in terms of I.

o
ле?
o com
35
O 2 cm

Answers

Answer 1

Answer: it would be 34

Step-by-step explanation:


Related Questions

What length is X
3.0000
4.0000

Answers

kinda confused not sure if we have an equation or other numbers to help answer

A city has a population of 380,000 people. Suppose that each year the population grows by 6.5%. What will the population be after 10 years?
Round your answer to the nearest whole number.

Answers

The growth formula is:

y = a•(1+x)^(t/p)

y is the end result

a is the initial amount

x is the percent growth as a decimal

t is the total amount of time

p is how often the growth occurred

Note that t and p both need to be the same units, whether that be seconds or days or months or years etc.

So,

y = 380000 • (1.065)^(10/1)

y = 380000 • 1.87713746527

y = 713312.236802

y = 713312

What is the outlier for the data set?
Heart Rate
5 0 7
6 3 5 6 8 8
7 0 2
8
9 0
5 0 = 50 beats per minute
40
50
68
90

Answers

Answer:

6 3 5 6 8 8

Step-by-step explanation:

farthest apart than any other number

Answer:

Your correct answer is 90 :)

Step-by-step explanation:

90 is the biggest number in the number set so therefore it is an outlier. 

Have an amazing day!!

Please rate and mark brainliest!!

Select ALL the expressions that have the same value as the expression 0.5 ÷ 0.25
A. 1,200 ÷ 60
B. 1.2 ÷ 0.6
C. 0.012 ÷ 0.06
D. 2.5 ÷ 2.25
E. 0.05 ÷0.025

Answers

Answer:

B and E

Step-by-step explanation:

0.5 ÷ 0.25 = 2

A. NO because it's 20

B. Yes

C. NO because it's 0.2

D. NO because it's 1.1 repeating

E. Yes

find the midpiont between y and 31 is -5 find y

Answers

Answer:

y=-41

Step-by-step explanation:

[tex]\frac{y+31}{2} =-5\\y+31=-5 \times 2\\y+31=-10\\y=-10-31\\y=-41[/tex]

can someone help me please​

Answers

Answer:

y=x-5

Step-by-step explanation:

try that my good sir

A T.V. se was bought for Rs. 13950, when 10% discount is given. , calculate the marked price of the T.V.

Answers

Answer:

15500

Step-by-step explanation:

Solution

here

price of tv after discount: 13950

discount : 10%

now,

price of tv without discount= 13950÷90×100price of tv without discount= Rs15500

The area of a square slice of cheese is 25 square inches. The perimeter of the slice of cheese is
Choose...
inches.

Answers

Answer:

As Per Provided Information

Area of given square slice of cheese is 25 square inches .

We have been asked to determine the perimeter of the slice of cheese .

First we will find the side of square slice of cheese .

Let us assume the side of square slice of cheese be s .

Now Let's Solve

[tex] \boxed{\bf \:Area_{(Square)} = {Side}^{2}}[/tex]

Substituting the value and we obtain

[tex] \sf \longrightarrow \: 25 = {s}^{2} \\ \\ \\ \sf \longrightarrow \: \sqrt{25} = s \\ \\ \\ \sf \longrightarrow \: s \: = 5 \: inch[/tex]

So, the side of square slice cheese is 5 inch

Now let's calculate the Perimeter of cheese

[tex] \boxed{\bf \: Perimeter_{(Square)} = 4 \times side}[/tex]

Substituting the value we obtain

[tex] \longrightarrow \sf \: Perimeter_{(Square)} = 4 \times 5 \\ \\ \\ \longrightarrow \sf \: Perimeter_{(Square)} =20 \: inches[/tex]

Therefore,

Perimeter of square slice of cheese is 20 inches .

"The sum of a number and 20 is multiplied by 6 and the result is 26."

Answers

[tex]\qquad\qquad\huge\underline{{\sf Answer}}♨[/tex]

Consider the number as x

let's solve ~

[tex]\qquad \sf  \dashrightarrow \:6(x + 20) = 26[/tex]

[tex]\qquad \sf  \dashrightarrow \:6x + 120 = 26[/tex]

[tex]\qquad \sf  \dashrightarrow \:6x = - 120 + 26[/tex]

[tex]\qquad \sf  \dashrightarrow \:6x = -94[/tex]

[tex]\qquad \sf  \dashrightarrow \:x = - 94 \div 6[/tex]

[tex]\qquad \sf  \dashrightarrow \:x = \dfrac{ - 47}{3} [/tex]

・ .━━━━━━━†━━━━━━━━━.・

Answer:

[tex](x + 20) 6 = 26[/tex]

[tex]6x + 120 = 26[/tex]

[tex]6x = 26 - 120[/tex]

[tex]6x = - 94[/tex]

[tex] \displaystyle \: x = \frac{ - 94}{6} [/tex]

[tex] \displaystyle{x = \frac{ - 47}{3} }[/tex]

[tex]\red {\rule{35pt}{2pt}} \green{ \rule{35pt}{2pt}}\orange{ \rule{35pt}{2pt}}\pink{ \rule{35pt}{2pt}}\blue{ \rule{35pt}{2pt}}\purple{ \rule{35pt}{2pt}}\red{ \rule{35pt}{2pt}}[/tex]

[tex] \bold{ \displaystyle{x = - \frac{47}{3} }}[/tex]

20 POINTS!!!
If A varies directly as B and inversely as C and when A = 6, B = 10 and C = 15. Calculate C when A = 92 and B= 107

Answers

Answer:

C = [tex]\frac{963}{92}[/tex]

Step-by-step explanation:

given A varies directly as B and inversely as C then the equation relating them is

A = [tex]\frac{kB}{C}[/tex] ← k is the constant of variation

to find k use the condition A = 6 , B = 10 , C = 15 , then

6 = [tex]\frac{x10k}{15}[/tex] ( multiply both sides by 15 )

90 = 10k ( divide both sides by 10 )

9 = k

A = [tex]\frac{9B}{C}[/tex] ← equation of variation

when A = 92 and B = 107 , then

92 = [tex]\frac{9(107)}{C}[/tex] ( multiply both sides by C )

92C = 963 ( divide both sides by 92 )

C = [tex]\frac{963}{92}[/tex]

Answer:

C = 963/92

Step-by-step explanation:

Given :

A ∝ BA ∝ 1/C

Finding the constant of variation, k

A = kB/C6 = k(10)/(15) [Given in 1st part of question]6 = 2k/3 2k = 18k = 9

Finding C

Using the same equation, and new values of A and B, we can find CA = kB/CC = kB/AC = 9 x 107 / 92C = 963/92


Can someone solve this question to me.i will mark brainliest. :)

Answers

Answer:

Parent Function:  [tex]y=\sqrt{x}[/tex]Horizontal shift: right 3 unitsVertical shift: up 3 unitsReflection about the x-axis: noneVertical strech: streched

Step-by-step explanation:

assume that [tex]y=\sqrt{x}[/tex] is [tex]f(x)=\sqrt{x}[/tex] and [tex]y=\sqrt{-2x+6}+3[/tex] is

[tex]g(x)=\sqrt{-2x+6}+3\\ f(x)=\sqrt{x} \\g(x)=\sqrt{-2x+6}+3[/tex]

The transformation from the first equation to the second equation can be found by finding a,h and k for each equation.

[tex]y=a\sqrt{x-h}+k[/tex]

factor a 1 out of the absolute value to make the coefficient of x equal to 1

[tex]y=\sqrt{x}[/tex]

factor a 2 out of the absolute value to make the coefficient of x equal to 1

[tex]y=\sqrt{2}\sqrt{x-3}+3[/tex]

find a, h and k for [tex]y=\sqrt{2}\sqrt{x-3}+3[/tex]

[tex]a=1.41421356\\ h=3\\k=3[/tex]

the horizontal shift depends on the value of h when [tex]h > 0[/tex], the horizontal shift is described as:

[tex]g(x)=f(x+h)[/tex] - the graph is shifted to the left h units

[tex]g(x)=f(x-h)\\[/tex] - the graph is shifted to the right h units

the vertical shift depends on the value of k

Using the digits 2, 4, and 6, write a number with a 4 in
the hundred thousands place and a 2 in the hundreds
place.

Answers

Answer:

624

Step-by-step explanation:

THINK SMARTER + Julianna is lining the inside of a basket with fabric.
The basket is in the shape of a rectangular prism that is 29 cm long,
19 cm wide, and 10 cm high. How much fabric is needed to line the
inside of the basket if the basket does not have a top? Explain your
strategy
2

Answers

Answer:

1,511 cm²

Step-by-step explanation:

      We will find the surface area, but not include the top.

      This means we will have five sides to calculate for, see attached.     Please note that the area of a rectangle can be found with A = L * W

[1] 19 cm * 10 cm = 190 cm²

[2] 19 cm * 10 cm = 190 cm²

[3] 29 cm * 10 cm = 290 cm²

[4] 29 cm * 10 cm = 290 cm²

[5] 19 cm * 29 cm = 551 cm²

    Add them all together:

190 cm² + 190 cm² + 290 cm² + 290 cm² + 551 cm² = 1,511 cm²

1. Suppose you pay back $680 on a $650 loan you had for 75 days. What was your simple annual interest rate?

Answers

well, let's assume a year has 365 days, so 75 days is simply 75/365 of a year.  We also know that your loan was $650 and you paid back $680 or namely 30 bucks extra, so the interest on those $650 is really 30 bucks.

[tex]~~~~~~ \textit{Simple Interest Earned} \\\\ I = Prt\qquad \begin{cases} I=\textit{interest earned}\dotfill &\$30\\ P=\textit{original amount deposited}\dotfill & \$650\\ r=rate\to r\%\to \frac{r}{100}\\ t=years\to \frac{75}{365}\dotfill &\frac{15}{73} \end{cases} \\\\\\ 30 = (650)(\frac{r}{100})(\frac{15}{73})\implies 30=\cfrac{9750r}{7300}\implies 30=\cfrac{195r}{146}\implies 4380=195r \\\\\\ \cfrac{4380}{195}=r\implies \stackrel{\%}{22.46}\approx r[/tex]

Need Help Please!!

Determining the price for a product can be tricky! Companies often have to juggle several variables in order to find the price that maximizes their revenue. Currently, the price of a product is set at $100. The company is getting about 20 customers per week at this rate. The company has done some research and found that they lose two customers for every $5 they increase their price.

Let the variable ”x” represent the number of times the company increases the price by $5. What is the price of the product when x= 3?

Answers

Check the picture below.


Use the Pythagorean Theorem to find the missing length and then round the
result to the nearest tenth.

Answers

Answer:2 squared +3 squared and the square root of that number

Step-by-step explanation:

What is the area of this trapezoid? units 2

Answers

area of trapezoid: 153 units²

Here given information:

height : 9side 1 : 10side 2 : 7 + 10 + 7 = 24

trapezium area = [tex]\sf \frac{1}{2}[/tex] * ( side 1 + side 2 ) * height

[tex]\hookrightarrow \sf \dfrac{1}{2} * ( 10 + 24) * 9[/tex]

[tex]\hookrightarrow \sf 153 \ units^2[/tex]

you’d work out the area of the triangles first so you’d half the base and multiply by the height of it. then multiply that by 2 as there are 2 identical triangles. which gives you 63. then you work out the area of the rectangle which is 90. you then do 90+63 to get 153

[tex] \rm \sum_{n = 1}^{ \infty } \frac{( - {1)}^{n + 1} }{n \binom{2n}{n} } \\ [/tex]​

Answers

Recall the well-known series

[tex]\displaystyle 2 \arcsin^2(x) = \sum_{n=1}^\infty \frac{(2x)^{2n}}{n^2 \binom{2n}n}[/tex]

Replace x with √x :

[tex]\displaystyle 2 \arcsin^2(\sqrt x) = \sum_{n=1}^\infty \frac{(4x)^n}{n^2 \binom{2n}n}[/tex]

Differentiate both sides:

[tex]\displaystyle -\frac{\arcsin(\sqrt x)}{2\sqrt{x-x^2}} = \sum_{n=1}^\infty \frac{(4x)^n}{n \binom{2n}n}[/tex]

Multiply by 4x :

[tex]\displaystyle -\frac{4x \arcsin(\sqrt x)}{2\sqrt{x-x^2}} = \sum_{n=1}^\infty \frac{(4x)^{n+1}}{n \binom{2n}n}[/tex]

All the series I've mentioned converge for |x| < 1, so we can take x = -1/4 to find the value of the sum we want.

[tex]\displaystyle \sum_{n=1}^\infty \frac{(-1)^{n+1}}{n \binom{2n}n} = -\frac{4 \times \left(-\frac14\right) \arcsin\left(\sqrt{-\frac14}\right)}{2\sqrt{-\frac14-\left(-\frac14\right)^2}} = -\frac{\arcsin\left(\frac i2\right)}{\frac{\sqrt5\,i}2}} = \boxed{\frac2{\sqrt5} \mathrm{arsinh}\left(\frac12\right)}[/tex]

where

[tex]\arcsin\left(\frac i2\right) = z \iff 2\sin(z) = -2i\sinh(iz) = i \implies z = i \, \mathrm{arsinh}\left(\frac12\right)[/tex]

Solve by completing the square:
x2 + 2x-8= 0
-8
a.
x = -4 or 2
b. X= 4 or 2
-
=
c.
x= -4 or - 2
d. X= 4 or - 2
x

Answers

The answer is 4 trust me bro

If the volume of a cuboid is 120 cm' and it has a length of 10cm, a height of 4cm, the width of the cuboid is ?
cm,​

Answers

Answer:

3cm

Step-by-step explanation:

V = L * W * H

V = 10 * W * 4

10 * 4 = 40

120 / 40 = 3

W = 3

If you have 100 feet of fencing and want to enclose a rectangular area up against a long, straight wall, what is the largest area you can enclose

Answers

Answer: 1250 square feet!

Step-by-step explanation:

A (25)=25•(100-2•25)=25•50=1250 Sq Ft

If you have 100 feet of fencing and want to enclose a rectangular area up against a long, straight wall, The largest area you can enclose will be 1250 sq Ft.

What is a rectangle?

It is defined as two-dimensional geometry in which the angle between the adjacent sides is 90 degrees. It is a type of quadrilateral. The area occupied by the rectangle in two-dimensional planner geometry.

The area of a rectangle can be calculated using the following formula:

Rectangle area = length x width

It is given that if you have 100 feet of fencing and want to enclose a rectangular area up against a long, straight wall.

Any rectangle's length and width differences must be as small as possible for the area to be maximized.

The largest area you can enclose

A =25×(100-2•25)

A=25•50

A=1250 Sq Ft

Thus, if you have 100 feet of fencing and want to enclose a rectangular area up against a long, straight wall, The largest area you can enclose will be 1250 sq Ft.

Learn more about the rectangle here:

https://brainly.com/question/15019502

#SPJ5

Add. Simplify the answer and write the answer as a mixed number if appropriate 3/8+2/3

Answers

First we need common denominators so we could multiply 3/8 by 3 and 2/3 by 8 which would give us 9/24 + 16/24 which would be 25/24. 25 goes into 24 only 1 time so we would be left with 1 now. The answer would be 1 and 1/24

Gizmo eats 3 crickets per day. If there are 15 crickets in a container, what is the maximum number of days Ms. Evans can go before buying replacement crickets.

Answers

5 days!
3 times 5 is 15

For a ride on a rental scooter, Goran paid a $3 fee to start the scooter plus 11 cents per minute of the ride. The total bill for Goran's ride was $23.79. For how many minutes did Goran ride the scooter?

Answers

Answer:

Step-by-step explanation:

he paid a 3 dollar fee so we can remove that 23.79-3 = 20,79

now we devide 20,79 by 11 or 189 minutes.

Rotate the given triangle 180° counter-clockwise about the origin. [ 0 -3 5 ] [0 1 2]​

Answers

Answer:

  [tex]\left[\begin{array}{ccc}0&3&-5\\0&-1&-2\end{array}\right][/tex]

Step-by-step explanation:

Rotation 180° (in either direction) about the origin causes each coordinate to have its sign changed. Effectively, the coordinate matrix is multiplied by -1.

__

Additional comment

This is equivalent to reflection across the origin.

The answers are : (alike the box order)
3 - 5
-1 -2

The length of a rectangle is triple the width. If the area of the rectangle is 75 square inches, then find the length and width

Answers

Answer:

W = 5

L = 15

Step-by-step explanation:

Formula for Area of Rectangle is L × W

Since stated triple;

L = 3W

Area = L×W = 3W² = 75

It'll be:

3W² = 75

Divide both sides with 3:

3W² = 75

3 3

W² = 25

Then square root both sides:

w = 5

Again stated that length is triple the width:

L = 5 × 3

L = 15

Therefore;

W = 5

L = 15

How do I solve for X?

Answers

The value of x in the special right triangle is 39.60 ft.

Right angle triangle

Right angle triangle has one of its angles as 90 degrees. The side and angles can be found using trigonometric ratios.

Therefore, let's find the base of the triangle with 30 degrees.

sin 30° = opposite / hypotenuse

1 / 2 = 7 / b

b = 14 ft

Let's use the value(14 ft) to find the height of the biggest triangle.

sin 30 = opposite / hypotenuse

sin 30 = 14 / h

0.5h = 14

h = 14 / 0.5

h = 28 ft

Therefore, let's find the value of x .

sin 45° = 28 / x

x = 28 / 0.70710678118

x = 39.5979797464

x = 39.60 ft

learn more on right triangle here: https://brainly.com/question/10412877

I’m trying to find the absolute Max and min, I can’t figure out how to do the derivative, thanks

Answers

Step-by-step explanation:

Step 1: Take the First Derivative This means only differentiate once.

Disclaimer: Since absolute value only take positve outputs and quadratics only take positve outputs, we can get rid of the absolute value signs so we now have

[tex]e {}^{ {x}^{2} - 1 } [/tex]

We have the function x^2-1 composed into the function e^x.

So we use chain rule

Which states the derivative of a function composed is the

derivative of the main function times the derivative of the inside function.

So the derivative of the main function is

[tex] \frac{d}{dx} (e {}^{x} ) = e {}^{x} [/tex]

Then we replace x with x^2-1

[tex]e {}^{ {x}^{2} - 1} [/tex]

Then we take the derivative of the second function which is 2x so qe multiply them

[tex]e { }^{ {x}^{2} - 1 } 2x[/tex]

Step 2: Set the equation equal to zero.

[tex]e {}^{x {}^{2} - 1} 2x = 0[/tex]

Since e doesn't reach zero. We can just set 2x=0.

[tex]2x = 0 = x = 0[/tex]

So the critical point is 0.

Since e^x will never reach zero

Since 0 is the only critical point, this where the max or min will occur at.

Next we pick any numbergreater than zero, and plug them in the derivative function which gives us a positve number.

Any pick less than zero will give us a negative number.

Since the function is decreasing then increasing, we have a minimum.

Since 0 is the only critical point, we have a absolute minimum at 0.

To find the y coordinate, plug 0 in the orginal function.

Which gives us

[tex]e {}^{ {0}^{2} - 1 } = e {}^{ - 1} = \frac{1}{e} [/tex]

So the minimum occurs at

(0,1/e).

Points P and Q are respectively 4m North and 3m East of point R. Calculate the distance between point P and Q​

Answers

PR=4mQR=3m

Apply Pythagorean theorem

PQ²=QR²+PR²PQ²=4²+3²PQ²=5²PQ=5m

Answer:

Distance between point P and Q = 5m

Step-by-step explanation:

Given

Point P is 4m north (↑) of Point RPoint Q is 3m east (→) of Point R

Using Pythagorean Theorem (applicable for only right triangles)

PQ = √4² + 3²PQ = √25PQ = 5 m

Hope it helped~

The cards below have a mean of 25. What is the missing number?: ? 19, 22, 31

Answers

Answer: Its 28.

Step-by-step explanation:

The missing number in the card s 28

How to determine the missing number?

Represent the missing number with x.

So, we have:

x, 19, 22 and 31

The mean of a dataset is:

Mean = Sum/Count

So, we have:

25 = (x + 19 + 22 + 31)/4

Multiply both sides by 4

100 = x + 19 + 22 + 31

Evaluate the sum

100 = x + 72

Subtract 72 from both sides

x = 28

Hence, the missing number is 28

Read more about mean at:

https://brainly.com/question/14532771

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