Write the ratio of the first number to the second.
[tex]\begin{gathered} 32\colon44 \\ \text{Ratio}=\frac{32}{44} \\ \text{Ratio}=\frac{8}{11} \\ \text{The ratio therefore is 8}\colon11 \end{gathered}[/tex]2. Luis hizo una excursión de 20 km 75 hm 75 dam 250 m en tres etapas. En la primera recorrió 5 km 5 hm, y en la segunda 1 km 50 dam más que en la anterior. ¿Cuánto recorrió en la tercera etapa? Expresa el resultado de forma compleja
The function h (t) = -4.9t² + 19t + 1.5 describes the height in meters of a basketball t secondsafter it has been thrown vertically into the air. What is the maximum height of the basketball?Round your answer to the nearest tenth.1.9 metersO 19.9 meters16.9 metersO 1.5 meters
Since the function describing the height is a quadratic function with negative leading coefficient this means that this is a parabola that opens down. This also means that the maximum height will be given as the y component of the vertex of the parabola, then if we want to find the maximum height, we need to write the function in vertex form so let's do that:
[tex]\begin{gathered} h(t)=-4.9t^2+19t+1.5 \\ =-4.9(t^2+\frac{19}{4.9}t)+1.5 \\ =-4.9(t^2+\frac{19}{4.9}t+(\frac{19}{9.8})^2)+1.5+4.9(\frac{19}{9.8})^2 \\ =-4.9(t+\frac{19}{9.8})^2+19.9 \end{gathered}[/tex]Hence the function can be written as:
[tex]h(t)=-4.9(t+1.9)^2+19.9[/tex]and its vertex is at (1.9,19.9) which means that the maximum height of the ball is 19.9 m
what times what equals 38
1 4/5 + (2 3/20 + 3/5) use mental math and properties to solve write your answer in simpleist form
Given data:
The given expression is 1 4/5 + (2 3/20 + 3/5).
The given expression can be written as,
[tex]\begin{gathered} 1\frac{4}{5}+(2\frac{3}{20}+\frac{3}{5}_{})=\frac{9}{5}+(\frac{43}{20}+\frac{3}{5}) \\ =\frac{9}{5}+\frac{43+12}{20} \\ =\frac{9}{5}+\frac{55}{20} \\ =\frac{36+55}{20} \\ =\frac{91}{20} \end{gathered}[/tex]Thus, the value of the given expression is 91/20.
factoring out: 25m + 10
Answer:
5(5m + 2)
Explanation:
To factor out the expression, we first need to find the greatest common factor between 25m and 10, so the factors if these terms are:
25m: 1, 5, m, 5m, 25m
10: 1, 2, 5, 10
Then, the common factors are 1 and 5. So, the greatest common factor is 5.
Now, we need to divide each term by the greatest common factor 5 as:
25m/5 = 5m
10/5 = 2
So, the factorization of the expression is:
25m + 10 = 5(5m + 2)
Use the distance formula to find the distance between the points given.(-9,3), (7, -6)
Given the points:
[tex](-9,3),(7,-6)[/tex]You need to use the formula for calculating the distance between two points:
[tex]d=\sqrt{(x_2-x_1)^2+(y_2-y_1^})^2[/tex]Where the points are:
[tex]\begin{gathered} (x_1,y_1) \\ (x_2,y_2) \end{gathered}[/tex]In this case, you can set up that:
[tex]\begin{gathered} x_2=7 \\ x_1=-9 \\ y_2=-6 \\ y_1=3 \end{gathered}[/tex]Then, you can substitute values into the formula and evaluate:
[tex]d=\sqrt{(7-(-9))^2+(-6-3)^2}[/tex][tex]d=\sqrt{(7+9)^2+(-9)^2}[/tex][tex]d=\sqrt{(16)^2+(-9)^2}[/tex][tex]d=\sqrt{256+81}[/tex][tex]d=\sqrt{337}[/tex][tex]d\approx18.36[/tex]Hence, the answer is:
[tex]d\approx18.36[/tex]triangle HXI can be mapped onto troangle PSL by a reflection If m angle H = 157 find m angle S
From the information provided, the triangle HXI can be mapped onto triangle PSL. This means the vertices of the reflected image would now have the following as same measure angles;
[tex]\begin{gathered} \angle H\cong\angle P \\ \angle X\cong\angle S \\ \angle I\cong\angle L \end{gathered}[/tex]Measure of angle S cannot be determined from the information provided because there is insufficient information given to determine the measure of angle X, hence the angle congruent to it (angle S) likewise cannot be determined.
f(x) = x2 + 4 and g(x) = -x + 2Step 2 of 4: Find g(d) - f(d). Simplify your answer.Answer8(d) - f(d) =
Answer:
[tex]\begin{equation*} g(d)-f(d)=-d^2-d-2 \end{equation*}[/tex]Explanation:
Given:
[tex]\begin{gathered} f(x)=x^2+4 \\ g(x)=-x+2 \end{gathered}[/tex]To find:
[tex]g(d)-f(d)[/tex]We can find g(d) by substituting x in g(x) with d, so we'll have;
[tex]g(d)=-d+2[/tex]We can find f(d) by substituting x in f(x) with d, so we'll have;
[tex]f(d)=d^2+4[/tex]We can now go ahead and subtract f(d) from g(d) and simplify as seen below;
[tex]\begin{gathered} g(d)-f(d)=(-d+2)-(d^2+4)=-d+2-d^2-4=-d^2-d+2-4 \\ =-d^2-d-2 \\ \therefore g(d)-f(d)=-d^2-d-2 \end{gathered}[/tex]Therefore, g(d) - f(d) = -d^2 - d -2
A chemist has 30% and 60% solutions of acid available. How many liters of each solution should be mixed to obtain 570 liters of 31% acid solution? Work area number of liters | acid strength | Amount of acid 30% acid solution 60% acid solution 31% acid solution liters of 30% acid liters of 60% acid
Let the amount of 30% acid solution be a
Let the amount of 60% acid solution be b
Given, "a" and "b" mixed together gives 570 liters of 31% acid. We can write:
[tex]0.3a+0.6b=0.31(570)[/tex]Also, we know 30% acid and 60% acid amounts to 570 liters, thus:
[tex]a+b=570[/tex]The first equation becomes:
[tex]0.3a+0.6b=176.7[/tex]We can solve the second equation for a:
[tex]\begin{gathered} a+b=570 \\ a=570-b \end{gathered}[/tex]Putting this into the first equation, we can solve for b. The steps are shown below:
[tex]\begin{gathered} 0.3a+0.6b=176.7 \\ 0.3(570-b)+0.6b=176.7 \\ 171-0.3b+0.6b=176.7 \\ 0.3b=176.7-171 \\ 0.3b=5.7 \\ b=\frac{5.7}{0.3} \\ b=19 \end{gathered}[/tex]So, a will be:
a = 570 - b
a = 570 - 19
a = 551
Thus,
551 Liters of 30% acid solution and 19 Liters of 60% acid solution need to be mixed.
12 + 24 =__(__+__)
Find the GCF. The first distributing number should be your GCF
A group of numbers' greatest common factor (GCF) is the biggest factor that all the numbers have in common. For instance, the numbers 12, 20, and 24 share the components 2 and 4.
Therefore, 12 and 24 have the most things in common. Figure 2: LCM = 24 and GCF = 12 for two numbers.
Find the other number if one is 12, then. What does 12 and 24's GCF stand for?
Example of an image for 12 + 24 = ( + ) Locate the GCF. You should distribute your GCF as the first number.
12 is the GCF of 12 and 24. We must factor each number individually in order to determine the highest common factor of 12 and 24 (factors of 12 = 1, 2, 3, 4, 6, 12; factors of 24 = 1, 2, 3,.
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Which function has the greatest average rate of change on the interval [1,5]
Answer:
Explanation:
Given: interval [1,5]
Based on the given functions, we start by computing the function values at each endpoint of the interval.
For:
[tex]\begin{gathered} y=4x^2 \\ f(1)=4(1)^2 \\ =4 \\ f(5)=4(5)^2 \\ =100 \\ \end{gathered}[/tex]Now we compute the average rate of change.
[tex]\begin{gathered} \text{Average rate of change = }\frac{f(5)-f(1)}{5-1} \\ =\frac{100-4}{5-1} \\ \text{Calculate} \\ =24 \end{gathered}[/tex]For:
[tex]\begin{gathered} y=4x^3 \\ f(1)=4(1)^3 \\ =4 \\ f(5)=4(5)^3 \\ =500 \end{gathered}[/tex][tex]\begin{gathered} \text{Average rate of change = }\frac{f(5)-f(1)}{5-1} \\ =\frac{500-4}{5-1} \\ =124 \end{gathered}[/tex]For:
[tex]\begin{gathered} y=4^x \\ f(1)=4^1 \\ =4 \\ f(5)=4^5 \\ =1024 \end{gathered}[/tex][tex]\begin{gathered} \text{Average rate of change = }\frac{f(5)-f(1)}{5-1} \\ =\frac{1024-4}{5-1} \\ =255 \end{gathered}[/tex]For:
[tex]\begin{gathered} y=4\sqrt[]{x} \\ f(1)=4\sqrt[]{1} \\ =4 \\ f(5)\text{ = 4}\sqrt[]{5} \\ \end{gathered}[/tex][tex]\begin{gathered} \text{Average rate of change = }\frac{f(5)-f(1)}{5-1} \\ =\frac{(4\sqrt[]{5\text{ }})\text{ -4}}{5-1}\text{ } \\ =1.24 \end{gathered}[/tex]Therefore, the function that has the greatest average rate is
[tex]y=4^x[/tex]Select the correct answer from each drop-down menu.
Given: Kite ABDC with diagonals AD and BC intersecting at E
Prove: AD L BC
A
C
E
LU
D
B
Determine the missing reasons in the proof.
The missing reasons are
ΔCDA ≅ ΔBDA by SSS [side side side]
ΔCED ≅ ΔBED by SAS [side angle side]
What is Kite?
A kite is a quadrilateral having reflection symmetry across a diagonal in Euclidean geometry. A kite has two equal angles and two pairs of adjacent equal-length sides as a result of its symmetry.
Given,
ABCD is a kite, with the diagonal AD and BC
We have,
AC = AB
and
CD = BD [Property of Kite]
In ΔACD and ΔABD
AC = AB
and
CD = BD [Property of Kite]
AD = AD [Common]
By rule SSS Criteria [Side Side Side ]
ΔACD ≅ ΔABD
∴ ∠CDA = ∠BDA [CPCT]
Now,
In ΔCDE and ΔBDA
CD = BD
∠CDE = ∠BDE
DE = DE [Common]
By rule SAS Criteria [Side Angle Side]
ΔCDE ≅ ΔBDA
∴ CE = BE [CPCT]
Hence, AD bisects BC into equal parts
The missing reasons are
ΔCDA ≅ ΔBDA by SSS [side side side]
ΔCED ≅ ΔBED by SAS [side angle side]
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The number of algae in a tub in a labratory increases by 10% each hour. The initial population, i.e. the population at t = 0, is 500 algae.(a) Determine a function f(t), which describes the number of algae at a given time t, t in hours.(b) What is the population at t = 2 hours?(c) What is the population at t = 4 hours?
a) Let's say initial population is po and p = p(t) is the function that describes that population at time t. If it increases 10% each hour then we can write:
t = 0
p = po
t = 1
p = po + 0.1 . po
p = (1.1)¹ . po
t = 2
p = 1.1 . (1.1 . po)
p = (1.1)² . po
t = 3
p = (1.1)³ . po
and so on
So it has an exponential growth and we can write the function as follows:
p(t) = po . (1.1)^t
p(t) = 500 . (1.1)^t
Answer: p(t) = 500 . (1.1)^t
b)
We want the population for t = 2 hours, then:
p(t) = 500 . (1.1)^t
p(2) = 500 . (1.1)^2
p(2) = 500 . (1.21)
p(2) = 605
Answer: the population at t = 2 hours is 605 algae.
c)
Let's plug t = 4 in our function again:
p(t) = 500 . (1.1)^t
p(4) = 500 . (1.1)^4
p(4) = 500 . (1.1)² . (1.1)²
p(4) = 500 . (1.21) . (1.21)
p(4) = 500 . (1.21)²
p(4) = 732.05
Answer: the population at t = 4 hours is 732 algae.
4) What is perimeter of this shape? * 4 cm 2 cm
the perimeter is the sum of the outside sides. So in this case is 4+4+2+2+2+2=16
so the answer is 16cm
I'm attempting to solve and linear equation out of ordered pairs in slopes attached
We know that the equation of a line is given by
y = mx + b,
where m and b are numbers: m is its slope (shows its inclination) and b is its y-intercept.
In order to find the equation we must find m and b.
In all cases, m is given, so we must find b.
We use the equation to find b:
y = mx + b,
↓ taking mx to the left side
y - mx = b
We use this equation to find b.
1We have that the line passes through
(x, y) = (-10, 8)
and m = -1/2
Using this information we replace in the equation we found:
y - mx = b
↓ replacing x = -10, y = 8 and m = -1/2
[tex]\begin{gathered} 8-(-\frac{1}{2})\mleft(-10\mright)=b \\ \downarrow(-\frac{1}{2})(-10)=5 \\ 8-5=b \\ 3=b \end{gathered}[/tex]Then, the equation of this line is:
y = mx + b,
↓
y = -1/2x + 3
Equation 1: y = -1/2x + 3
2Similarly as before, we have that the line passes through
(x, y) = (-1, -10)
and m = 0
we replace in the equation for b,
y - mx = b
↓ replacing x = -1, y = -10 and m = 0
-10 - 0 · (-1) = b
↓ 0 · (-1) = 0
-10 - 0 = b
-10 = b
Then, the equation of this line is:
y = mx + b,
↓
y = 0x - 10
y = -10
Equation 2: y = -10
3Similarly as before, we have that the line passes through
(x, y) = (-6, -9)
and m = 7/6
we replace in the equation for b,
y - mx = b
↓ replacing x = -6, y = -9 and m = 7/6
[tex]\begin{gathered} -9-\frac{7}{6}(-6)=b \\ \downarrow\frac{7}{6}(-6)=-7 \\ -9-(-7)=b \\ -9+7=b \\ -2=b \end{gathered}[/tex]Then, the equation of this line is:
y = mx + b,
↓
y = 7/6x - 2
Equation 3: y = 7/6x - 2
4The line passes through
(x, y) = (6, -4)
and m = does not exist
When m does not exist it means that the line is vertical, and the equation looks like:
x = c
In this case
(x, y) = (6, -4)
then x = 6
Then
Equation 4: x = 6
5The line passes through
(x, y) = (6, -6)
and m = 1/6
we replace in the equation for b,
y - mx = b
↓ replacing x = 6, y = -6 and m = 1/6
[tex]\begin{gathered} -6-\frac{1}{6}(6)=b \\ \downarrow\frac{1}{6}(6)=1 \\ -6-(1)=b \\ -7=b \end{gathered}[/tex]Then, the equation of this line is:
y = mx + b,
↓
y = 1/6x - 7
Equation 5: y = 1/6x - 7
The width of a rectangle measures (5v-w)(5v−w) centimeters, and its length measures (6v+8w)(6v+8w) centimeters. Which expression represents the perimeter, in centimeters, of the rectangle?
The most appropriate choice for perimeter of rectangle will be given by -
Perimeter of rectangle = (22v + 14w) cm
What is perimeter of rectangle?
At first it is important to know about rectangle.
Rectangle is a parallelogram in which every angle of the parallelogram is 90°.
Perimeter of rectangle is the length of the boundary of the rectangle.
If l is the length of the rectangle and b is the breadth of the rectangle, then perimeter of the rectangle is given by
Perimeter of rectangle = [tex]2(l + b)[/tex]
Length of rectangle = (5v - w) cm
Breadth of rectangle = (6v + 8w) cm
Perimeter of rectangle = 2[(5v - w) + (6v + 8w)]
= 2(11v + 7w)
= (22v + 14w) cm
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Complete Question
The width of a rectangle measures (5v−w) centimeters, and its length measures(6v+8w) centimeters. Which expression represents the perimeter, in centimeters, of the rectangle?
If b is a positive real number and m and n are positive integers, then.A.TrueB.False
we have that
[tex](\sqrt[n]{b})^m=(b^{\frac{1}{n}})^m=b^{\frac{m}{n}}[/tex]therefore
If b is a positive real number
then
The answer is truewhat is 12 + 0.2 + 0.006 as a decimal and word form
twelve and two hundred six thousandths
The data for numbers of times per week 20 students at Stackamole High eat vegetables are shown below. A dotplot shows 4 points above 1, 4 points above 3, 5 points above 2, 3 points above 4, 3 points above 5, and 1 point above 9.
Considering the given dot plot for the distribution, it is found that:
a) The distribution is right skewed.
b) There is an outlier at 9.
c) Since there is an outlier, the best measure of center is the median.
Dot plotA dot plot shows the number of times that each measure appears in the data-set, hence the data-set is given as follows:
1, 1, 1, 1, 2, 2, 2, 2, 2 3, 3, 3, 3, 4, 4, 4, 5, 5, 5, 9.
To find the skewness of the data-set, we need to find the mean and the median.
The mean is the sum of all values divided by the number of values of 20, hence:
Mean = (4 x 1 + 5 x 2 + 4 x 3 + 3 x 4 + 3 x 5 + 9)/20 = 3.1.
The median is the mean of the 9th and the 10th elements(even cardinality) of the data-set, hence:
Median = (2 + 3)/2 = 2.5.
The mean is greater than the median, hence the distribution is right skewed.
To identity outliers, we need to look at the quartiles, as follows:
First quartile: 0.25 x 20 = 5th element = 2.Third quartile: 0.75 x 20 = 15th element = 4.The interquartile range is:
IQR = 4 - 2 = 2.
Outliers are more than IQR from the quartiles, hence:
4 + 1.5 x 2 = 4 + 3 = 7 < 9, hence 9 is an outlier in the data-set, and hence the median will be the best measure of center.
Missing information
The questions are as follows:
Part A: Describe the dotplot. (4 points)
Part B: What, if any, are the outliers in these data? Show your work. (3 points)
Part C: What is the best measure of center for these data? Explain your reasoning. (3 points) (10 points)
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Simplify 17(z-4x)+2(x+3z)
Answer:
23z-66x
Step-by-step explanation:
Look at the attachment please :D
А ВC D0 2 4 68 10 12Which point best represents V15?-0,1)A)point AB)point Bpoint CD)point D
We have to select a point that is the best representative of the square root of 15.
We can calculate the square root of 15 with a calculator, but we can aproximate with the following reasoning.
We know that 15 is the product of 3 and 5. If we average them, we have 4.
If we multiply 4 by 4, we get 16, that is a little higher than 15.
If we go to the previous number (3) and calculate 3 by 3 we get 9, that is far from 15 than 16.
So we can conclude that the square root of 15 is a number a little less than 4.
In the graph, the point B is the one that satisfy our conclusion, as it is a point in the scale that is between 3 and 4, and closer to 4.
The answer is Point B
What is the solution set of x over 4 less than or equal to 9 over x?
we have
[tex]\frac{x}{4}\leq\text{ }\frac{9}{x}[/tex]Multiply in cross
[tex]x^2\leq36[/tex]square root both sides
[tex](\pm)x\leq6[/tex]see the attached figure to better understand the problem
the solution is the interval {-6,6}
the solution in the number line is the shaded area at right of x=-6 (close circle) and the shaded area at left of x=6 (close circle)
Help me please Circle describe and correct each error -2=-3+x/4-2(4)-3+x/4•48=-3+x+3X=11
Answer
The error in the solution is circled (red) in the picture below.
The equation can be solved correctly as follows
[tex]\begin{gathered} -2=\frac{-3+x}{4} \\ \\ Multiply\text{ }both\text{ }sides\text{ }by\text{ }4 \\ \\ -2(4)=\frac{-3+x}{4}\cdot4 \\ \\ -8=-3+x \\ \\ Add\text{ }3\text{ }to\text{ }both\text{ }sides \\ \\ -8+3=-3+x+3 \\ \\ x=-5 \end{gathered}[/tex]Percents build on one another in strange ways. It would seem that if you increased a number by 5% and thenincreased its result by 5% more, the overall increase would be 10%.7. Let's do exactly this with the easiest number to handle in percents.(a) Increase 100 by 5%(b) Increase your result form (a) by 5%.(C) What was the overall percent increase of the number 100? Why is it not 10%?
Answer:
a) 105
b) 110.25
c) Increase of 10.25%. It is not 100% because the second increase of 5% is over the first increased value, not over the initial value.
Step-by-step explanation:
Increase and multipliers:
Suppose we have a value of a, and want a increse of x%. The multiplier of a increase of x% is given by 1 + (x/100). So the increased value is (1 + (x/100))a.
(a) Increase 100 by 5%
The multiplier is 1 + (5/100) = 1 + 0.05 = 1.05
1.05*100 = 105
(b) Increase your result form (a) by 5%.
1.05*105 = 110.25
(C) What was the overall percent increase of the number 100? Why is it not 10%?
110.25/100 = 1.1025
1.1025 - 1 = 0.1025
Increase of 10.25%. It is not 100% because the second increase of 5% is over the first increased value, not over the initial value.
Identify the vertex of the function below.f(x) - 4= (x + 1)2-onSelect one:O a. (-4,1)O b.(1,-4)O c. (-1,-4)O d.(-1,4)
The standard equation of a vertex is given by:
[tex]f(x)=a(x-h)^2+k[/tex]where (h,k) is the vertex.
Comparing with the given equation after re-arranging:
[tex]f(x)=(x+1)^2+4[/tex]The vertex of the function is (-1, 4)
If the given is -3x+20=8 What should the subtraction property of equality be?
Given the equation
[tex]-3x+20=8[/tex]To apply the subtraction property of equality, we subtract 20 from both sides.
[tex]-3x+20-20=8-20[/tex]The beginning mean weekly wage in a certain industry is $789.35. If the mean weekly wage grows by 5.125%, what is the new mean annual wage? (1 point)O $829.80O $1,659.60O $41,046.20$43,149.82
Given:
The initial mean weekly wage is $ 789.35.
The growth rate is 5.125 %.
Aim:
We need to find a new annual wage.
Explanation:
Consider the equation
[tex]A=PT(1+R)[/tex]Let A be the new annual wage.
Here R is the growth rate and P is the initial mean weekly wage and T is the number of weeks in a year.
The number of weeks in a year = 52 weeks.
Substitute P=789.35 , R =5.125 % =0.05125 and T =52 in the equation.
[tex]A=789.35\times52(1+0.05125)[/tex][tex]A=43149.817[/tex][tex]A=43149.82[/tex]The new mean annual wage is $ 43,149.82.
Final answer:
The new mean annual wage is $ 43,149.82.
Rearrange the formula 5w-3y +7=0 to make w the subject.
According to projections through the year 2030, the population y of the given state in year x is approximated byState A: - 5x + y = 11,700State B: - 144x + y = 9,000where x = 0 corresponds to the year 2000 and y is in thousands. In what year do the two states have the same population?The two states will have the same population in the year
The x variable represents the year in question. The year 2000 is represented by x = 0, 2001 would be repreented by x = 1, and so on.
The year in which both states would have the same population can be determined by the value of x which satisfies both equations.
We would now solve these system of equations as follows;
[tex]\begin{gathered} -5x+y=11700---(1) \\ -144x+y=9000---(2) \\ \text{Subtract equation (2) from equation (1);} \\ -5x-\lbrack-144x\rbrack=11700-9000 \\ -5x+144x=2700 \\ 139x=2700 \\ \text{Divide both sides by 139} \\ x=19.4244 \\ x\approx19\text{ (rounded to the nearest whole number)} \end{gathered}[/tex]Note that x = 19 represents the year 2019
ANSWER:
The two states will have the same population in the year 2019
Question 34: Find the polar coordinates that do NOT describe the point on the graph. (Lesson 9.1)
Notice that the polar coordinates of the point on the simplest form are (2,30). Then, the only option that does not match a proper transformation of coordinates is the point (-2,30)