Given :
[tex]f(x)=3x+12[/tex]WE need to find the value of f(-2)
So, substitute with x = -2
[tex]f(-2)=3\cdot-2+12=-6+12=6[/tex]So, the value of f(-2) = 6
Do 9 and 10 keep it 9th grade if you can Question 9-10
Given the formula for the volume of a cylinder:
[tex]V=\pi r^2h[/tex]You know that "r" is the radius of the cylinder and "h" is the height.
a. In order to solve the formula for "h", you can divide both sides of the formula by:
[tex]\pi r^2[/tex]As follows:
[tex]\frac{V}{\pi r^2}=\frac{\pi r^2h}{\pi r^2}[/tex][tex]h=\frac{V}{\pi r^2}[/tex]b. Having a cylindrical swimming pool, you know that:
[tex]\begin{gathered} r=12\text{ }ft \\ V=1810\text{ }ft^3 \end{gathered}[/tex]And, for this case:
[tex]\pi\approx3.14[/tex]Therefore, you can substitute values into the formula for the height of a cylinder found in Part "a" and evaluate:
[tex]\frac{V}{\pi r^2}=\frac{\pi r^2h}{\pi r^2}[/tex][tex]h=\frac{1810\text{ }ft^3}{(3.14)(12\text{ }ft)^2}[/tex][tex]h=\frac{1810\text{ }ft^3}{452.16\text{ }ft^2}[/tex][tex]h\approx4\text{ }ft[/tex]Hence, the answers are:
a.
[tex]h=\frac{V}{\pi r^2}[/tex]b.
[tex]h\approx4\text{ }ft[/tex]Please help me this is so confusing .which of the following, names a ray in the drawing?
From the given figure, let's select the rays given in the option.
A ray can be said to be a straight line which starts from a point and goes to infinity at the other end.
From the given figure, the rays are:
• NK
,• NJ
,• NL
,• NM
Therefore, from the list the, the ray is NK.
ANSWER:
NK
simplify 12 times y to the 6th power times z to the 4th power divided by 6 times y times z to the 6th power
The simplified expression of the given expression is 2y^5 z^{-2}
What is expression?
A mathematical expression is a phrase that includes at least two numbers or variables, at least one arithmetic operation, and the expression itself. Any one of the following mathematical operations can be used.
Given expression, [tex]\frac{12y^6 z^4}{6 yz^6}[/tex]
Simplifying and we get
[tex]\frac{12y^6 z^4}{6 yz^6}\\=2y^{6-1} z^{4-6}\\=2y^5 z^{-2}[/tex]
Therefore, the simplified expression of the given expression is 2y^5 z^{-2}
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Equation of line passing thru point -6,-3 and perpindicular to JK -2,7 and 6,5
Equation of the line passing through the point (-6,-3) and perpendicular to the line passing through (-2,7) and (6,5) is y = 4x -19.
First we will find the slope of the line passing through (-2,7) and (6,5).
Slope of the line = (5-7)/(6-(-2)) = -2/8 = -1/4.
We know that,
Product of the slopes of two perpendicular lines = -1.
Let the equation of the line we have to find be y = mx + c.
Slope will be m.
Hence, we can write,
m*(-1/4) = -1
m = -1*(-4/1)
m = 4
Putting (6,5) and m = 4 in y = mx + c , we get
5 = 4*(6) + c
5 = 24 + c
c = 5 - 24 = -19
Hence, the equation of the line is:-
y = 4x -19
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leon wrote an expression that is equivalent to (30+6)÷12 witch expression could be the one leon wrote
ANSWER
(3 · 3 · 2 · 2) ÷ (3 · 2 · 2)
EXPLANATION
The given expression is also equivalent to 36 ÷ 12 - because 30 + 6 = 36.
In the equivalent expression we have:
[tex]\begin{gathered} 3\cdot3\cdot2\cdot2=36 \\ 3\cdot2\cdot2=12 \end{gathered}[/tex]Therefore it's 36 ÷ 12 too
Which of the equations or inequalities below are true?O A. 7-26O B. 7-224O C. 7-23 5O D. 7 - 2 = -5
Given,
The equation orr inequalities are,
[tex]\begin{gathered} A)7-2\ge6 \\ B)7-2\ne4 \\ C)7-2\leq5 \\ D)7-2=-5 \end{gathered}[/tex]A) In the expression,
7 - 2 = 5
Hence, 7-2 =6 is incorrect.
B) In the expression,
7 - 2 = 5,
Hence,
[tex]7-2\ne4[/tex]Option B is correct.
C) In the expression,
7 - 2 = 5
7 - 2 < 5 is incorrect
Hence, 7 - 2 =< 5 is incorrect.
D)In the expression,
7 - 2 = 5
Hence, 7 - 2 =< -5 is incorrect.
Hence, option B is correct.
Line segment AB is on square ABCD. Segment EF on equilateral triangle EFG is 12 units longer than AB. Square ABCD and triangle EFG have equal perimeters. What is the length of AB?
The length of segment AB as required in the task content is; 36.
What is the length of segment AB?It follows from the task content that the length of the line segment AB which is a side of the square ABCD is to be determined.
Since the perimeters of triangle EFG and square ABCD are equal as given;
Let the length of segment AB = x.
Therefore, EF = x + 12.
Therefore, the perimeter of the equilateral triangle = 3(x +12).
While the perimeter of square ABCD is; 4x.
Therefore, since the perimeters are equal;
3(x + 12) = 4x
3x + 36 = 4x
36 = x.
On this note, thee Length of line segment AB is; 36.
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Cut a 10-foot (ft.) long piece of wood into two pieces so that one piece is 2 ft longer than the other. Which of the following equations depicts the given situation?A. x/2 = 10B. x + 2 = 10C. 2x + 2 = 10D. None of the choices
Given:
Cut a 10-foot (ft.) long piece of wood into two pieces so that one piece is 2 ft longer than the other.
Required:
Which of the following equations depicts the given situation?
Explanation:
Let 10 feet long piece of wood cut into two pieces of length x(smaller piece) and
x+2 larger piece.
So, the equation will be
x + x + 2 =10
2x + 2=10
Answer:
Option C is correct.
a bottle of ketchup holds 0.95 liters how maney milliliters does it hold?
Explanation:
The relation between liters and milliliters is:
[tex]1\text{ liter}=1000\text{ milliliters}[/tex]we have to multiply the liters by 1000
Answer:
The answer is 950 milliliters
Mrs. Smith has 12 times as many markers as colored pencils. The total number of markers and colored pencils is 78. How many markers does Mrs. Smith have?ok...answers given so far are not helpful in explaining process.
Let:
x = Colored markers
y =
I don't understand this. Proving and applying ASA and Salad congruence
Given two triangles, we can say that they are congruent by the SAS postulate (Side Angle Side) if both triangles have two congruent sides and the angle that they form is also congruent
In this case, we have that triangle IHG and DFE have already two congruent sides, then, to make them congruent, the angle that they each form (angle IHG and angle DEF) must be congruent so we can use the SAS postulate
what is the slope of a line parallel to the line whose equation is 18 x - 3 y equals -45
The equation of the line in Slope-Intercept form is:
[tex]y=mx+b[/tex]Where "m" is the slope and "b" is the y-intercept.
Let's solve for "y" from the equation of the line given in the exercise, in order to express it in Slope-Intercept form:
[tex]\begin{gathered} 18x-3y=-45 \\ -3y=-18x-45 \\ y=\frac{-18x-45}{-3} \\ y=6x+15 \end{gathered}[/tex]You can identify that:
[tex]\begin{gathered} m=6 \\ b=15 \end{gathered}[/tex]By definition, the slopes of parallel lines are equal. Therefore, the slope of the line parallel to line given in the exercise, is:
[tex]m=6[/tex]Compute the sums below. (Assume that the terms in the first sum are consecutive terms of an arithmetic sequence.) 9 + 4 + (-1) + ... + (-536)
SOLUTION
The terms below make an A.P. Now we are told to find the sum of the AP.
Sum of an AP is given by
[tex]S\text{ = }\frac{n}{2}\lbrack2a\text{ + (n-1)d\rbrack}[/tex]Where S = sum of the AP, a = first term = 9, d = -5, n= ?
So we have to find n first before we can find the sum. The nth term which is the last term = -536. So we will use it to find the number of terms "n"
[tex]\begin{gathered} \text{From T}_{n\text{ }}=\text{ a +(n-1)d where T}_{n\text{ }}=\text{ -536} \\ -536\text{ = 9+(n-1)-5} \\ -536\text{ = 9-5n+5} \\ -536\text{ = 14-5n} \\ -5n\text{ = -536-14} \\ -5n\text{ = -550} \\ n\text{ = 110} \end{gathered}[/tex]Now let's find the sum
[tex]\begin{gathered} S\text{ = }\frac{n}{2}\lbrack2a\text{ + (n-1)d\rbrack} \\ S\text{ = }\frac{110}{2}\lbrack2\times9\text{ + (110-1)-5\rbrack} \\ S\text{ = 55\lbrack{}18+(119)-5\rbrack} \\ S\text{ = 55\lbrack{}18 - 595\rbrack} \\ S\text{ = 55}\times-577 \\ S\text{ = -31735} \end{gathered}[/tex]Therefore, the sum = -31735
Hello. I think I have the right answer. These types of questions have been giving me problems
EXPLANATION
Using a composite figure to approximate the area of the figure will give us the needed surface,
The area of the composite is approximately the area of the squares:
Area of square:
A= base * height = 1.0*1.0 = 1 cm^2
Since we have approximately 22 squares inside the figure, the approximate area will be as follows:
[tex]Area_{composite\text{ figure}}=22*1cm^2=22cm^2[/tex]Therefore, the solution is approximately 22 square units.
The Neckware association of America reported that 3% of ties sold in the United States are bow ties. If 4 customers who purchased a tie randomly selected,find the probability that at least 1 purchased a bow tie
Pr (people with bow ties) = 3% = 0.03
p = 0.03
Pr (people without bow tie) = 1 - 0.03 = 0.97
q = 0.97
n = 4 customers
[tex]Pr(at\text{ least 1 purchased a bow tie) = 1 - Pr(none purchased a bow tie)}[/tex]To find the probability that at least 1 purchased a bow tie, we will use a binomial probability formula:
[tex]p(x=^{}X)=^nC_xp^xq^{n\text{ - x}}[/tex][tex]\begin{gathered} \text{Pr(none purchased a bow tie) = p(x = 0)} \\ \text{p(x = 0) = }^4C_0\times p^0\times q^{4\text{ - }0} \\ \text{p(x = 0) = 1 }\times\text{ 1}\times q^4=(0.97)^4 \\ \text{p(x = 0) = }0.8853 \\ \\ \text{Pr(none purchased a bow tie) = }0.8853 \end{gathered}[/tex][tex]\begin{gathered} Pr(at\text{ least 1 purchased a bow tie) = 1 - 0.8853} \\ Pr(at\text{ least 1 purchased a bow tie) = 0.1147} \end{gathered}[/tex]a coral reef grows 0.15 m every week. how much does it grow in 13 weeks? in centimeters
Given:
A coral reef grows 0.15 m every week.
Coral reefs grow 13 times 0.15m for 13 weeks.
[tex]=13\times0.15m[/tex][tex]=1.95\text{ m}[/tex]We need to convert m into cm.
[tex]1m=100cm[/tex]Multiply 1.95m by 100, we get
[tex]1.95\times100=195cm[/tex]Hence a coral reef grows 195cm in 13 weeks.
The measures of the angles of a triangle are shown in the figure below. Solve for x. (2x+6)° 42°
A triangle is a shape that has a total angle of 180°.
How to solve the triangle?It's important to note that a triangle is a shape that has three sides and the total sum is equal to 180°.
In this case, we have 2x + 6 and 42°. The other angle isn't given and this can't be solved further
The sides will have been illustrated as:
= a + b + c = 180
The expression given will then be allocated for each side to solve it further.
Note that an overview was given as the information is incomplete.
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Kala the trainer had two solo workout plans that she offers her clients. PlanA and plan B. Each client does either one or the other (not both) on Friday there were 3 clients who did plan A and 5 who did plan B. On Saturday there were 9 clients who did plan A and 7 who did plan B. Kala trained her Friday clients for a total of 6 hours and her Saturday clients for a total of 12 hours. How long does each of the workout plans last?
Answer:
Each of the workouts plans lasts 45 minutes.
Explanation:
Let the duration for Plan A workout = x
Let the duration for Plan B workout = y
Friday
• Plan A --> 3 clients
,• Plan B --> 5 clients
,• Kala trained her Friday clients for a total of 6 hours
[tex]3x+5y=6[/tex]Saturday
• Plan A --> 9 clients
,• Plan B --> 7 clients
,• Kala trained her Saturday clients for a total of 12 hours
[tex]9x+7y=12[/tex]The system of equations is solved simultaneously.
[tex]\begin{gathered} 3x+5y=6\cdots(1) \\ 9x+7y=12\cdots(2) \end{gathered}[/tex]Multiply equation (1) by 3 in order to eliminate x.
[tex]\begin{gathered} 9x+15y=18\cdots(1a) \\ 9x+7y=12\cdots(2) \end{gathered}[/tex]Subtract.
[tex]\begin{gathered} 8y=6 \\ y=\frac{6}{8}=0.75\text{ hours} \\ 0.75\times60=45\text{ minutes} \end{gathered}[/tex]Substitute y=0.75 into equation (2) to solve for x.
[tex]\begin{gathered} 9x+7y=12 \\ 9x+7(0.75)=12 \\ 9x+5.25=12 \\ 9x=12-5.25=6.75 \\ x=\frac{6.75}{9} \\ x=0.75 \end{gathered}[/tex]x=y=0.75 hours = 45 minutes,
Each of the workouts plans lasts 45 minutes.
Linear Programming WorksheetGraph each feasible region. maximize or minimize each objective
Given:
x+2y = 8
x=2, y=0
Substitute x=2 then find value of x as,
2+2y=8
2y=6
y=3
(x,y) = (0,3)
Now, substitute y=0 then find value of y as,
x+2(0)=8
x=8
(x,y) = (8,0)
It is given that P = x+3y
(x,y) = (0,3) then P= 0+3x3
P=9
The maximum valu P=9 and vertiex (0,3)
(x,y) = (8,0) then P=8+0= 8
The mininmum val
In an office building, 54 office are currently being rented, this represent 30% of the total units. how many offices are in the building
given that,
54 offices are currently rented
and it represent 30% of the total unit
to get the total offices in the building
let the total offices be x
30% of x = 54
30/100 X x = 54
cross multiply
30x = 5400
dividing both sides by 30
30x/30 = 5400/30
x = 5400/30
x = 180
therefore the total offices in the building is 180
Point B is located at -2. Points C and D are each 8 units away from point B. Where are C and D located?
They are located 8 units away, so one has to be away in the left direction and the other one in the right direction
[tex]\begin{gathered} \text{ - 2 - 8 = -10 } \\ \text{ - 2 + 8 = 6} \end{gathered}[/tex]So, C and D are located at -10 and 6
help video S-(x – 6)² +7 for 2 2 +3 x = 3 for Find f(3)
Explanation:
This is a function defined by parts. When x is not 3, the function has the equation on top, but when x is 3, the function has one value: 2.
Answer:
f(3) = 2
In the diagram below, if the measure of < C = 45 °, and side AB = 6.8, then side BC = _____.
Solution
Since
[tex]\begin{gathered} \tan45=\frac{6.8}{BC} \\ \\ \Rightarrow BC=\frac{6.8}{\tan45}=6.8\text{ since}\tan45=1 \end{gathered}[/tex]The correct option is A.
3.
How much greater is the surface area of the rectangular prism than the surface area of the cube?
6 cm
(1 point)
3 cm
2 cm
O 36 cm²
O 33 cm²
O 18 cm²
O 45 cm²
3 cm
The dimensions of the rectangular prism of 6 cm by 3 cm by 2 cm and the dimension of the cube of 3 cm gives the amount the surface area of the prism is greater than the cube as 18 cm²
What is a rectangular prism?A rectangular prism is a six faced solid hexahedron.
The given dimension of the rectangular prism are:
Length = 6 cm
Height = 3 cm
Width = 2 cm
The side length of the cube = 3cm
The surface area of the rectangular prism is therefore:
[tex]A_p[/tex] = 6 × 3 × 2 + 6 × 2 × 2 + 3 × 2 × 2 = 72
The surface area of the rectangular prism is 72 cm²
The surface area of the cube: [tex]A_c[/tex] = 6 × 3² = 54
The surface area of the cube, [tex]A_c[/tex] = 54 cm²
The amount by which area of the rectangular prism is greater than the area of the cube is therefore: [tex]A_p[/tex] - [tex]A_c[/tex] = 72 cm² - 54 cm² = 18 cm²
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I need help answering this if you can show your work to the be good
Let:
x = Number of sodas purchased
y = Number of hamburgers purchased
The food truck charges $3 for sodas, so the total cost for sodas will be:
3*x=3x
also, it charges $8 for each hamburger, hence, the total cost for hamburgers will be:
8*y = 8y
Since Jack wants to spend no more than $30, the total cost must be less or equal than $30:
[tex]\begin{gathered} \text{Total cost }\leq\text{ 30} \\ \text{Total cost = total cost for sodas+total cost for hamburgers} \\ 3x+8y\le30 \end{gathered}[/tex]Issac says that T' will be located at (4,20)Isabella says that T' will be located at (4,12(who is correct and why?
In the given triangle :
The coordinate of T is ( 2, 10 )
Triangle TUV will be dilated by a scale factor of 2
Thus, multiply the coordinates of TUV by 2
T' = 2 x T
T' = 2 x ( 2, 10 )
T' = ( 2x2, 2x10)
T' = ( 4, 20 )
So, T' will be located at ( 4, 20 )
Issac says that T' will be located at (4,20)
Answer : Issac says that T' will be located at (4,20)
oblem 9If 8 x 17 = 136, then 17 isI % of 136if 44 x 8 = 352, then 44 is% of 352
Let 'x' represents the missing number
a) x % of 136 = 17
[tex]\begin{gathered} \text{where, }x\text{ \% =}\frac{\text{x}}{100} \\ \frac{x}{100}of136=17 \\ \frac{x}{100}\times136=17 \\ \frac{136x}{100}=17 \\ 1.36x=17 \end{gathered}[/tex]Divide both sides by 1.36
[tex]\begin{gathered} \frac{1.36x}{1.36}=\frac{17}{1.36} \\ x=\frac{25}{2}=12.5 \\ \therefore x=12.5 \end{gathered}[/tex]Hence, 17 is 12.5% of 136.
b) x% of 352 = 44
[tex]\begin{gathered} \text{where, x\%=}\frac{\text{x}}{100} \\ \frac{x}{100}\times352=44 \\ \frac{352x}{100}=44 \\ 3.52x=44 \end{gathered}[/tex]Divide both sides by 3.52
[tex]\begin{gathered} \frac{3.52x}{3.52}=\frac{44}{3.52} \\ x=12.5 \\ \therefore x=12.5 \end{gathered}[/tex]Hence, 44 is 12.5% of 352.
1. P(video games and kid is 10 to 12 years old)2. P(basketball/kid is 13 to 15 years old)3. P(kid is 13 to 15 years old/basketball)4. P(darts/kid is 10 to 15 years old)5. P(basketball and darts)6. P(basketball and kid is 13 to 18 years old)Answer the following problems about two way frequency tables make sure to reduce your fraction.
1. P(video games and kid is 10 to 12 years old)
[tex]\begin{gathered} P(video\text{ games and kid i 10 to 12 years old)} \\ =\text{ }\frac{number\text{ of kids 10 - 12 years old playing video games}}{total\text{ number of students}} \\ =\text{ }\frac{17}{143} \end{gathered}[/tex]Therefore,
The P(video games and kid is 10 to 12 years old) = 17/143
2. P(basketball/kid is 13 to 15 years old)
[tex]\begin{gathered} P\mleft(basketball/kid\text{ is 13 to 15 years old}\mright)\text{ } \\ =\text{ }\frac{number\text{ of kids 13 - 15 years old playing basketball}}{number\text{ of kids of age 13 to 15 years old}} \\ =\text{ }\frac{14}{45} \end{gathered}[/tex]P(basketball/kid is 13 to 15 years old) = 14/45
3. P(kid is 13 to 15 years old/basketball)
[tex]\begin{gathered} P(\text{kid is 13 to 15 years old / basket ball)} \\ =\text{ }\frac{number\text{ of kids aged 13 to 15 years old }}{number\text{ of kids playing basketball}} \\ =\text{ }\frac{14}{54} \\ =\text{ }\frac{7}{27} \end{gathered}[/tex]P(kid is 13 to 15 years old/basketball) = 7/27
4. P(darts/kid is 10 to 15 years old)
[tex]\begin{gathered} P(\text{darts / kid is 10 to 15 years old)} \\ =\text{ }\frac{number\text{ of kids age 10 to 15 playing darts}}{\text{number of kids age 10 to 15}} \\ =\text{ }\frac{kids\text{ age 10 to 12 + age 13 to 15 playing darts}}{\text{kids age 10 to 12 + age 13 to 15}} \\ =\text{ }\frac{12\text{ + 15}}{34\text{ + 45}} \\ =\text{ }\frac{27}{79} \end{gathered}[/tex]P(darts/kid is 10 to 15 years old) = 27/79
5. P(basketball and darts)
[tex]\begin{gathered} P(basketball\text{ and darts)} \\ \sin ce\text{ there are no kids playing basketball and darts at the } \\ \text{same time} \\ \text{then,} \\ P(basketball\text{ and darts) = 0} \end{gathered}[/tex]P(basketball and darts) = 0
6. P(basketball and kid is 13 to 18 years old)
[tex]\begin{gathered} P(\text{basketball and kid is 13 to 18 years old)} \\ =\text{ }\frac{number\text{ of kids 13 to 18 years playing basket}}{nu\text{mber of kid 13 to 18 years }} \\ =\text{ }\frac{\text{kids 13 to 15 years + 16 - 18 years playing basketball}}{\text{kids 13 to 15years + 16 to 18 years}} \\ =\text{ }\frac{14\text{ + 18}}{45\text{ + 35}} \\ =\text{ }\frac{32}{80} \\ =\frac{2}{5} \end{gathered}[/tex]P(basketball and kid is 13 to 18 years old) = 2/5
Given AFGH ~ ALMN, which must be true? Select all that apply.A.FGLMFHLNB. FH ~ LNC.mZFmZLmZGmZMD. GHMNE. mZH ^mZN
Jan plans to tell two people each day and will ask that person to tell two other people each day through the day of the opening, and so on. Assume that each new person who hears about the soft opening is also asked to tell two other people each day through the day of the opening and that each one starts the process of telling their friends on the day after he or she first hears. When should Jan begin telling others about the soft opening in order to have at least 700 people know about it by the day it occurs?
Explanation:
From the given question, we can sketch the pattern observed
The figure above helps show how the number of people increases
Initially, Jan tells 2 more people, then the two people tell two more people, then they also tell two more people
Thus
we can see that the model is given by
[tex]\begin{gathered} (2)^n \\ where\text{ n is the number of days} \end{gathered}[/tex]In order to have at least 700 (it also means a minimum of 700), we will have the equation
[tex]2^n\ge700[/tex]We then solve for n
Taking the log of both sides
[tex]n\text{ }log2\ge log700[/tex][tex]n\ge\frac{log700}{log2}[/tex]So that
[tex]\begin{gathered} n\ge\frac{2.845}{0.301} \\ \\ n\ge9.451 \end{gathered}[/tex]So, the number of days will be at least 10 days (Rounded to the nearest whole day )