Figure 5 shows a ray of light in an optical fibre.
Figure 5
Inside of optical fibre
What is the name given to the dotted line on Figure 5?
[1 mark]

θ = 0.0090 degree is the angle does the water surface make with the horizontal

At a radius of 12.5 cm from the center, or r = 13.5 cm, a tiny container of water is positioned on a rotating carousel within a microwave oven.

Time for every rotation is 7.15 seconds.

Fc=mrω^2

Fc=mr(2 π/T^2)^2

Fc=m12.5x10^-2(2 π/7.45)^2.....(1)

Gravitational force is caused by:

Fg=mg

Fg=mx9.8........(2)

Letθ is the angle between the water's surface and the horizontal be. Equations (1) and (2) can be used to compute it as follows:

tanθ=Fc/Fg

tanθ=m12.5x10^-2(2 π/7.45)^2/mx9.8

tanθ=0.0090

θ=0.0090 degree

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Answer: The angle between the water's surface and the horizontal is = 0.0090 degrees.

Explanation: The angle between the water's surface and the horizontal is = 0.0090 degrees.

A little container of water is placed on a revolving carousel within a microwave oven at a radius of 12.5 cm from the center, or r = 13.5 cm.

7.15 seconds pass throughout each revolution.

Fc=mrω^2

Fc=mr(2 π/T^2)^2

Fc=m12.5x10^-2(2 π/7.45)^2....(1) (1)

There is a gravitational force because of:

Fg=mg

Fg=mx9.8........(2)

Take as an example the angle formed by the water's surface and the horizontal. It can be calculated using Equations (1) and (2) as follows:

tanθ=Fc/Fg

tan = (m12.5x10-2(2 /7.45)/mx9.8)

tanθ=0.0090

0.09 degrees.

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Answer:

false

Explanation:

the time period is for a whole cycle of the wave, so peak-to-peak on an oscilloscope trace.

The gauge pressure at the depth of 210 m will be 2.11974 x 10^{6} Pa .

What is gauge pressure ?

The amount of pressure measured in relation to the applied atmospheric pressure is known as gauge pressure. A diaphragm sensor can be used to measure gauge pressure, with one side of the diaphragm exposed to the pressure medium that has to be measured and the other exposed to the surrounding atmospheric pressure.

The pressure from the weight of the atmosphere is included in gauge pressure readings because gauge pressure is zero-referenced against ambient air (or atmospheric) pressure. This indicates that gauge pressure varies in response to both weather and height above sea level. Gauge pressure measurement is adequate for the majority of industrial applications because every operation in a refinery or manufacturing facility operates at the same air pressure.

The gauge pressure is ;

P = density x g x depth

where , density is of sea water .

Calculate the gauge pressure as -:

P = density x g x depth

  = (1030 kg/m^{3})(9.8 m/s^{2})(210 m)

  = 2.11974 x 10^{6} Pa .

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Coefficient 2  should be placed in front of HCl to balance  the given chemical equation.

Chemical equation is a symbolic representation of a chemical reaction which is written in the form of symbols and chemical formulas.The reactants are present on the left hand side while the products are present on the right hand side.

A plus sign is present between reactants and products if they are more than one in any case and an arrow is present pointing towards the product side which indicates the direction of the reaction .There are coefficients present next to the chemical symbols and formulas .

The first chemical equation was put forth by Jean Beguin in 1615.By making use of chemical equations the direction of reaction ,state of reactants and products can be stated. In the chemical equations even the temperature to be maintained and catalyst can be mentioned.

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When inflating a balloon, the expansion of the balloon represents an equal but opposite force acting on the balloon; option D.

Forces are agents which cause a change in the motion of an object moving in a straight line or an object at rest to change its position.

According to the third law of motion, reaction and action are equal and opposite forces.

This law is seen in the inflation of balloons.

When a balloon is being inflated, the force applied in inflating the balloon pushes against the wall of the balloon. The balloon acts in an equal opposite direction by forcing the air molecules together, thus increasing the pressure of the air inside the balloon.

Therefore, an equal and opposite force is exerted by the air molecules o the air molecules.

When the balloon is released, the air is forcefully forced out in the opposite direction.

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Answer:

its D

Explanation:

the person above is correct too

We can use the formula of the capacitance

where C is the capacitance, Q is the charge and V is the voltage.

In our case

Q=480 C

V= 110 V

The value of the capacitor is 4.36 F

ANSWER B) 4.36F

The mass of the rock with a kinetic energy of 113J and a speed of 6.2m/s is approximately 5.88 kilograms.

Kinetic energy is simply the energy a body possesses due to its motion;

It is expressed as;

K.E = 1/2 × m × v²

Given the data in the question;

To determine the mass of the rock, plug the given values into the Kinetic energy formular and solve for m.

K.E = 1/2 × m × v²

113kgm²/s² = 1/2 × m × ( 6.2m/s )²

113kgm²/s² = 1/2 × m × 38.44m²/s²

113kgm²/s² = m × 19.22m²/s²

m = 113kgm²/s² / 19.22m²/s²

m = 5.88kg

Therefore, the mass of the rock is 5.88 kilograms.

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The ratio u/u0 : 1/2

As the distance is doubled and the battery is connected, we know that Capacitance is given by:   [tex]C= \frac{\epsilon_0 A}{d}[/tex]

As the distance between the plate is doubled, C will become: [tex]C= \frac{\epsilon_0 A}{2d} = \frac{C}{2}[/tex]

Now, as the battery is connected, Voltage will remain constant, therefore Charge Q will become:   [tex]Q=\frac{CV}{2}[/tex]

The energy before doubling the distance between the plates was, U0 :

[tex]U_0 = \frac{1}{2}QV = \frac{1}{2}CV^2[/tex]

After doubling the distance, the Energy will become U:

[tex]U = \frac{1}{2}QV = \frac{1}{4}CV^2[/tex]

Therefore, the ratio will be:

                           [tex]\frac{U}{U_0} = \frac{\frac{1}{2}CV^2}{\frac{1}{4}CV^2} = \frac{1}{2}[/tex]

A capacitor is a bipolar electrical device that can store energy in the form of an electrical charge. It consists of two electrical conductors  separated by a distance. The space between the conductors can be filled with a vacuum or  an insulating material known as a dielectric. The ability of a capacitor to store charges is called capacitance. Capacitors store energy by keeping opposite charges away from each other. The simplest model of a capacitor is a parallel plate, which consists of two metal plates with a gap between them. However, different types of capacitors are manufactured in different shapes, styles, lengths, circumferences and materials.

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It is necessary to collimate the light source before using the prisim to  disperse the light so that the light rays entering the prisim are parallel series.

What is colimate?

collimator is a tool for converting a point source's divergent radiation into a parallel beam. To perform specific measurements in spectroscopy, geometrical optics, and physical optics, the light must be collimated.

An optical collimator is made up of a tube with a convex lens at one end and a variable aperture at the other end that is located in the lens' focal plane. To examine the image without parallax, radiation entering the aperture exits the collimator as a parallel beam.

Therefore collimation is needed for the light rays entering the prism to be parallel .

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110.53m/s  is the minimum initial speed or initial velocity needed for such a shot.

The lowest speed at which a particular range is attained is determined. It is stated the distance that the pumpkins were hurled. By inserting the range of the pumpkin and the acceleration owing to gravity, the minimal velocity at which they were launched to go this distance was determined.

[tex]R=u_m^2/g[/tex]

[tex]1245.41m=(u_m^2/9.80m/s^2[/tex]

[tex]u_m^2=12217.47[/tex]

[tex]u_m=110.53m/s[/tex]

Any object susceptible to forces will move more quickly. This acceleration causes a change in the object's velocity. The speed of the item prior to the change brought on by acceleration is therefore known as the initial velocity. The speed will be the final speed once the object has been accelerating for some time.

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Answer:

1: a measuring instruments the students should use for time is a stopwatch

2: a measuring instruments the students should use for distance is a measuring tape

Explanation:

pls mark brainliest

It is 24 pi fast area of oil sick increasing when the radius is 60m.

This question we are given the rate of change is the radius T. R. D. T. Is equal to two m per minute. And we know that the area since we're talking about the radius theory of the seco which is pi R squared. And our D A t. R. Would be the first derivative of A. That will be two pi R. And our D A D. T. Would be equal to T. A. T. R. Multiplied by the era T. T. And already we can plug in our numbers. Here we have two pi R. A. Multiplied by two and we get four pi hi and this season meters squared per minute.

Now we want to find the value of our rate of change of area with time At R. A. is equal to 56. And therefore our D. A. T. T. At our escort 56 is equal to four pi my play by 56. And here we get 224 pi square meters per minute. This is our answer to part A no for part B. We are giving that At time is equal to zero is equal to zero. And our rate of change of radius the time is still equal to two meters per minute and Therefore from 0 to 3 we have a tiara Is equal to two d. T. And we integrate Both sides from 0 to 3. So on the left hand side we have our era on the right hand side we have to t From 0 to 3 and here we get six So our radius is six m.

Therefore our D a t t will be a quarter full pie. Sarah it R is equal to six and Plugging. In our 6th year. We have four pay And our era is six. We get 24 pi in this season square meters per minute. That's it. We had them.

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Answer:

The speed and direction of motion can be changed by applying force on an object and thus a force can bring a change in the state of motion of an object.

Answer:5110.2 joule

Explanation:Weight of the crate:- 8.35 x 102 N

Height to which the forklift lift the crate:- 6.0 M

Work done by the forklift=F.d

F=Gravitational Force =m.g

d=height=h

Work w=m.g.h

m.g=8.35 x 102 N

h=6.0 M

w=8.35x102N x 6.0M

w=5110.2NM

w=5110.2joule

The mass of the large star based on orbital period is 6912 x 10³⁰ kg.

We need to know about the orbital period to solve this problem. The orbital period depends on the semi-major axis, gravitational constant, and the mass of the massive object. It can be written as

T² = 4π².a³ / GM

where T is the orbital period, a is the semi-major axis, G is the gravitational constant and M is the mass.

From the question above, the given parameters are

a = 24 au = 24 . ³√(G.Msun yr²/ 4π²)

T = 2 years

Msun = 2 x 10³⁰ kg

By substituting the given parameters, we get

T² = 4π².a³ / GM

2² = 4π². (24 . ³√(G.Msun yr²/ 4π²))³ / GM

4 = 13824 Msun / M

M = 6912 x 10³⁰ kg

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Overdriving is driving at a speed making the stopping distance longer than the distance illuminated by headlights.

Typically, one can utilize their headlights to schedule stops in dimly lit or low visibility locations. Typically, one can measure their stopping distance using the visible light cone in the headlights. Exceeding the stopping distance that the headlights highlight is overdriving. Thus, driving too fast and leaving little room to stop in an emergency is known as overdriving the headlights.

When the lights are far enough ahead of a person to illuminate the road, one should often stop so that they can see any approaching impediments. When one is traveling at a rate of speed that prevents them from stopping in that lit region, that rate of speed is taken into account.

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4.266 m is the radius of the circular path the electron follows

Electron's speed = 7.50 × 10⁶ m/s

Magnetic field, B = 1 × 10⁻⁵ T

Electron's mass. m = 9.11 × 10⁻³¹

Charge of electron, q = 1.6 × 10⁻¹⁹

We know the relation of radius of curvature, = 4.266 m

Every point on a circle has a curvature that is equal to the reciprocal of the radius; for other curves (and straight lines, which can be thought of as circles of infinite radius), the curvature is equal to the reciprocal of the radius of the circle that at that point most closely approximates the curve.

The curvature's reciprocal, R, is the radius of curvature in differential geometry. It is equal to the radius of the circular arc that, at that moment, most closely resembles the curve for a curve. The radius of curvature for surfaces is the diameter of a circle that, individually or in combination, best fits a normal section.

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In order to calculate the object's position, we can use the formula below:

Where f is the focal length, do is the object's position and di is the image's position.

Using f = 0.5 m and di = -0.19 m (we use a negative value because the image is virtual), we have:

Therefore the object is at 0.14 meters from the mirror.

The force needed to be applied by each person is 5.150×10^3 N.

The required acceleration is 3.4 m/s2 and the mass of the car is 2,159 kg.

According to Newton's second law:

F = ma

F =  2,159 × 3.4.

F = 7340.6 N

Adding the force of friction into it

F = 7340 + 310

F = 7650.6 N

Since two people need to apply the force

F = 7650 N / 2

F = 3,825.3 N

or

F = 3.825×10^3 N

The force applied by each person to push the car is 3.825×10^3 N.

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Answer:

oxygen 16 has 8 protons and 8 neutrons, oxygen 17 has 8 protons and 9 neutrons

Explanation:

isotope's number is equal to the sum of its protons and neutrons

Answer:Oxygen 16 is number 16 while oxygen 17 is number 17 and oxygen 16 is also oxygen like oxygen 17.

Explanation:  Common Knowledge in my brain....

We will have the following:

1. In the first case, we will calculate the normal force:

Then, we will have that the fricion coefficient will be:

So the magnitude of the friccional force when applied horizontally will be of 30.0N.

2. And the magnitude when applied horizontal but the block is on an inclined surface of 60°, we will have that:

So, the friction force when the force is applied, is 15N.

The mass is 20.038 Kg.

Mass is the amount of count in a physical body. it's also a degree of the frame's inertia, the resistance to acceleration while a net pressure is carried out. An item's mass additionally determines the power of its gravitational attraction to different bodies. The SI base unit of mass is the kilogram.

F = mg

Displacement of weight = h

                                          = 0.7 m

work done by weight lifter W = F × h  

W = (mgh)

     = 0.7mg

work done in 3.2 seconds

power P = W/Δt = 0.7 mg/3.2

Given,

P = 43 W = 43 J/s

⇒ 0.7 mg/3.2 = 43 j/s

⇒ M = (43 × 3.2)/(0.7 × 9.8)

M = 20.038 Kg ans.

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First, let's calculate the particle acceleration, using the formula below:

Now, to find the force applied, let's use the second law of Newton:

Therefore the value of F is 0.08 N.

The phenomenon that occurs here is known as the snell's window, and the cone angle is 98 degrees.

To calculate the cone angle,

The cone angle is equal to two times the critical angle which is say, Ф

To calculate the critical angle Ф take the equation sinФ = n1÷n2 where

n1 is the refractive index of air, and n2 is the refractive index of water.

The refractive index of air, n1 = 1,

The refractive index of water, n2 = 1.33,

Substituting these values in the equation sinФ = n1÷n2, the equation becomes

sinФ = 1÷1.33

solving for Ф

Ф = [tex]sin^{-1}[/tex](1÷1.33)

Ф = 49°

Cone angle = 2×Ф

Cone angle = 2×49

Cone angle = 98°.

The phenomenon taking place here is known as snell's window. In this phenomenon, the person under the water sees everything above the surface through a cone of light whose width is about 96°-98°. Whatever is outside this cone appears dark to the person who is under the water. This is caused due to the refraction of light in different mediums.

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Do = 2f means that object distance is 2 x focal length.

2 x focal length = radius of curvature

When an object is placed at the radius of curvature, a real, inverted image is formed at the other radius of curvature. The sizes of the image and the object are the same. The sketch is shown below

Answer:

Explanation:

A. Their acceleration will be the same.    F=ma, a = F/m.  If F and m are the same, acceleration will be the same.

B. Their acceleration will be different.

C. Their acceleration will depend on their net force, which is not provided.

D. Their acceleration will depend on their weight, which is not provided.

======

A force of 30 N to the right is applied to an object. An opposite force of 20 N to the left is applied to the same object. What is the net force applied to the object?

A. 10 N to the left

B. 50 N to the right

C. 50 N to the left

D. 10 N to the right

Add the two vectors:  30R = +30, 20L = -20 Sum = +10 or 10R

The force acting on two bodies will be the same if they have same mass and same acceleration. But the acceleration is dependant on the net force of the body and thus option C is correct. The net force of the body is 10 N to the right.

Force is an external agent or factor which change an object from its state of rest or motion. The force to be applied depends on the mass and acceleration of the body by the equation F = ma.

Acceleration of a moving body is dependant on the direction and thus the direction of force and net force. Thus the two objects having the same mass and same force f applied to them, the acceleration may not be the same. Thus option C is correct.

The two force acting on a body in opposite direction will cancel each other in magnitude. Thus 20N of force to the right will be cancel by 20 N to the left. Remaining 10N will be there to the right direction. Hence, option D is correct.

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Answer:

i think it's a

Explanation:

Answer:

Potential energy

Explanation: Potential energy is represented as a stored energy.

His shadow is shortening at a rate of dy/dt = 0.6m/s at the time.

The triangle's three angles add up to a total of 180 degrees

The individual is standing at point D and has his head at point E at the time indicated in the problem.

At that moment, his shadow is visible on the wall at y = BC.

The two right triangles ABC and ADE both contain similar triangles. The ratios on their respective sides in the similar triangles are equal:

AD/AB = DE/BC

8/12 = 2/y

y = 3

If we suppose that the man is x distance from the building, then the distance from the spotlight to the man is 12 x.

12-x/12 = 2/y

1-1/12x = 2 1/y

Let's take derivatives of both sides:

-1/12dx = -2 .1/y²dy

Divide both sides by dt as follows.

-1/12.dx/dt = 2/y²dy/dt

At the time specified:

dx/dy = 1.6m/s

y = 3

Let's connect them

- 1/2 (1.6) = -2.9 dy/dt

dy/dt = 1.6/12×9/2 = 0.6m/s.

At the time in question, this is the pace at which his shadow's length is shortening.

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The complete question is:

"A spotlight on the ground shines on a wall 12 m away. If a man 2 m tall walks from the spotlight toward the building at a speed of 1.6 m/s, how fast is the length of his shadow on the building decreasing when he is 4 m from the building?"

a) The motion of the motorcyclist is a uniform motion

b) The distance is 600 m

c) The speed is 20 m/s.

We now that motion has to do with the change in the position of an object with time. In this case, we have the graph that described the motion of the motorcyclist . It is clear that the distance is increasing in equal amounts, in equal time intervals thus this is a uniform motion.

Looking at the graph, we can see that the motorcyclist covers 600 meters of distance within 30 seconds.

We can obtain the speed as the ratio of the distance to the time or the slope of the graph. Hence the speed is obtained from;

Speed = distance / time

Using the slope concept;

[tex]y_{2} - y_{1} /x_{2} - x_{1}[/tex]

= 600 - 0/30 - 0

= 20 m/s

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