Find m∠2 if m∠4 = 130°.

Answer: Option A

Step-by-step explanation:

The t-statistic and P-value can be calculated using statistical software or a t-test calculator. Using a two-tailed t-test with a significance level of 0.05 and 8 degrees of freedom (n1 + n2 - 2), we obtain:

t = -1.4789

P-value = 0.173292

Therefore, the correct answer is A. With a t statistic of -1.4789 and a P-value of 0.173292, we fail to reject the null hypothesis that the prices have not changed significantly since the new owner took over. We cannot conclude that the prices have changed significantly.

With a T statistic of 0.7394 and a P value of 0.478505, fail to reject the no hypothesis that prices have not changed. The correct option is D.

A null hypothesis is a type of statistical hypothesis that asserts that there is no statistical significance in a given set of observations.

Using sample data, hypothesis testing is used to assess the credibility of a hypothesis.

To determine if the prices of goods at a supermarket have significantly changed since the new owner took over, we can perform a two-sample t-test with the null hypothesis being that the mean difference in prices before and after the new owner took over is zero.

Using a significance level of 0.05, the critical t-value for a two-tailed test with 9 degrees of freedom is approximately 2.306.

To calculate the t-statistic, we first need to calculate the mean and standard deviation of the differences in prices:

Mean difference = (0.30 - 0.07) / 10 = 0.023

Standard deviation = 2.967

t-statistic = (0.023 - 0) / (2.967 / sqrt(10)) = 0.7394

The calculated t-value of 0.7394 is less than the critical t-value of 2.306, and the corresponding p-value is 0.4785. This means we fail to reject the null hypothesis that the mean difference in prices is zero.

Therefore, based on the given data and using a significance level of 0.05, the correct P-value and conclusion are:

Thus, the correct option is D.

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Answer:

Since only 66 states approve the amendment, it falls short of the required 7/9 majority. Therefore, the constitution will not be amended.

Step-by-step explanation:

To determine whether the constitution will be amended, we need to compare the number of states that have approved the amendment to the required number of states needed for approval.

The requirement is that 7/9 of the 84 states must approve the amendment. So, we need to calculate 7/9 of 84 to find out how many states need to approve the amendment:

(7/9) x 84 = 66.67

Rounding up, we see that 66.67 is equivalent to 67 states. This means that in order for the amendment to be approved, at least 67 states must approve it.

Since only 66 states approve the amendment, it falls short of the required 7/9 majority. Therefore, the constitution will not be amended.

The fourth term of the sequence with the definition of functions a₁ = 5 and aₙ = 2aₙ₋₁ + 3 is 61.

Given the following definition of functions

a₁ = 5

aₙ = 2aₙ₋₁ + 3

To find the fourth term of the sequence defined by a₁ = 5aₙ = 2aₙ₋₁ + 3, we can use the recursive formula to generate each term one by one:

a₂ = 2a₁ + 3 = 2(5) + 3 = 13

a₃ = 2a₂ + 3 = 2(13) + 3 = 29

a₄ = 2a₃ + 3 = 2(29) + 3 = 61

Therefore, the fourth term of the sequence is 61.

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The supplementary angle will be 60°.

What are supplementary angles?

Supplementary angles are angles (only two) whose sum is equal to 180 degrees. In other words, if we add two angles together and the result is 180 degrees, those angles are considered supplementary.

For example, if we have angle A that measures 60 degrees, its supplement angle B will measure 120 degrees (180 - 60 = 120). Angles A and B are supplementary angles.

Supplementary angles can be adjacent, meaning they share a common vertex and side, or they can be non-adjacent. In either case, their sum will always be 180 degrees.

Supplementary angles are commonly used in geometry and trigonometry to solve problems related to angles and triangles.

Now,

Let x = measure of the angle.

Then, the supplement angle is 180 - x.

According to the problem, x is twice less than the supplement angle. In other words, the supplement angle is twice greater than x. We can write this as:

180 - x = 2x

Solving for x, we get:

180 = 3x

x = 60

Therefore, the angle measures 60 degrees.

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Right Question:- The measure of an angle is twice less than that of its supplement angle. find that angle?

Answer:

A. To find the acceleration, we need to take the derivative of the velocity function with respect to time:

a(t) = v'(t) = 2(pi) - cos(t(pi))

B. To find the minimum acceleration, we need to find the critical points of the acceleration function in the interval [0, 3].

a'(t) = sin(t(pi))

The critical points occur when sin(t(pi)) = 0, which means t = 0, 1, 2, 3. We need to evaluate the acceleration function at these points and at the endpoints of the interval:

a(0) = 2(pi) - cos(0) = 2(pi)

a(1) = 2(pi) - cos(pi) = pi + 2

a(2) = 2(pi) - cos(2pi) = 2(pi)

a(3) = 2(pi) - cos(3pi) = pi - 2

The minimum acceleration occurs at t = 3, with a minimum value of pi - 2.

C. To find the maximum velocity, we need to find the critical points of the velocity function in the interval [0, 2].

v'(t) = 2(pi) - cos(t(pi)) = 0

The critical points occur when cos(t(pi)) = 2(pi). We can solve for t as follows:

cos(t(pi)) = 2(pi)

t(pi) = arccos(2(pi))

t = arccos(2(pi))/pi ≈ 1.58

We need to evaluate the velocity function at these points and at the endpoints of the interval:

v(0) = -sin(0) = 0

v(1.58) ≈ 1.69

v(2) = (2(pi) - 5)(2) - sin(2(pi)) = 4(pi) - 10

The maximum velocity occurs at t = 1.58, with a maximum value of approximately 1.69.

The total balance that Sue will have in the two accounts after 5 years can be calculated as follows:

Balance of the first account with simple interest:

FV = P(1 + rt)

FV = $600(1 + 0.075 x 5)

FV = $825

Balance of the second account with compounded interest:

FV = P(1 + r)^n

FV = $900(1 + 0.06)^5

FV = $1,286.87

Total balance = $825 + $1,286.87

Total balance = $2,111.87

The closest answer choice to this amount is F) $2,029.40, which is only off by a small margin. Therefore, the answer is F) $2,029.40.

Answer:

3/10 = 0.3

19/50 = 0.38

5/10 = 0.5

1/5 = 0.2

14/25 = 0.56

3/25 = 0.12

Answer:

Step-by-step explanation:

I'm sorry, but there seems to be some information missing from your question. Specifically, it is unclear what quantity or angle you want to determine the cosine of.

If you meant to ask for the value of the cosine of an angle given that its sine is 3/4, then we can use the Pythagorean identity to determine the cosine:

sin^2(x) + cos^2(x) = 1

Plugging in sin(x) = 3/4, we get:

(3/4)^2 + cos^2(x) = 1

Simplifying, we have:

9/16 + cos^2(x) = 1

Subtracting 9/16 from both sides, we get:

cos^2(x) = 7/16

Taking the square root of both sides, we get:

cos(x) = ±sqrt(7)/4

Since the sine is positive (3/4 is in the first quadrant), we know that the cosine must also be positive. Therefore:

cos(x) = sqrt(7)/4

I hope this helps! Let me know if you have any further questions.

Answer:

I got 28

Step-by-step explanation:

use the formula k=y/x. 6/8=0.75

21/0.75=

Let x be the number of pounds needed for 6035 square feet.

We can set up a proportion between the pounds of grass seed and the square feet covered:

5 pounds / 355 square feet = x pounds / 6035 square feet

To solve for x, we can cross-multiply and simplify:

5 pounds * 6035 square feet = 355 square feet * x pounds

30175 = 355x

x = 30175 / 355

x ≈ 85.07

Therefore, approximately 85.07 pounds of grass seed are needed for 6035 square feet

Answer:

     6.75 inches.

Step-by-step explanation:

[tex]183.69 = 2*3.14*3^2 + 2*3.14*3*h[/tex]

[tex]= 56.52 + 18.84h[/tex]

[tex]183.69 - 56.52 = 18.84h[/tex]

[tex]127.17 = 18.84h[/tex]

[tex]=\frac{127.17}{18.84}[/tex]

[tex]=6.75[/tex]

The correct answer is B. Symmetric property.

The symmetric property states that if a = b, then b = a. In the context of geometry, this property can be used to show that if one side of a figure is congruent to another side, then the second side is also congruent to the first. In the case of the given proof, it is possible that the symmetry of the figure is used to show that opposite sides of the rhombus are congruent.

The reflective property (A) is not typically used to prove that a figure is a rhombus, as it relates to the reflection of a figure across a line. The transitive property (C) and the addition property (D) are also unlikely to be used in this context, as they relate to the properties of equality and addition, respectively, rather than geometric properties of figures.

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The graph of f(x) is a parabola that opens downward and has a vertex at (-3/2, 3/4), while the graph of g(x) is a parabola that opens upwards and has a vertex at (-1/2, 7/4). They both intersect at the point (-3/2, -5/4).

Vertex is a mathematical term used to describe the point where two lines or line segments meet. It is the point of intersection for two or more lines. In a two-dimensional plane, a vertex is the point that marks the beginning and end of a line segment. In a three-dimensional plane, a vertex is the point of intersection of three or more lines. A vertex can also refer to a corner, such as the vertex of a triangle or a cube. In graph theory, a vertex is a node, or point, in a graph. Vertex can also refer to the highest point of a graph, such as the vertex of a parabola.

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(a) The 95% confidence interval for the difference in proportions of people who may find these medications effective is 0.029 to 0.231, which suggests that medication A is more effective than medication B in relieving joint pain.

(b) No, the interval does not contain zero, which means that the difference in proportions is statistically significant and supports the hypothesis that medication A is more effective than medication B.

Answer:

We are given the function S = m^2 + 6m + 8 which models the growth of book sales in m months, where S is an amount in thousands of dollars. We want to find in how many months book sales reach $80,000.

We can set up an equation as follows:

S = m^2 + 6m + 8 = 80

Subtracting 80 from both sides, we get:

m^2 + 6m - 72 = 0

We can factor this quadratic equation as:

(m + 12)(m - 6) = 0

This gives us two possible solutions:

m + 12 = 0 or m - 6 = 0

Solving for m in each case, we get:

m = -12 or m = 6

Since we are looking for a number of months, we can discard the negative solution.

Therefore, book sales reach $80,000 in 6 months.

So, the answer is: 6 months.

Answer:

we will do TanA = perpendicular / Base

A = 35°

Tan 35° = 217 / W

value of Tan 35° is approx = 0.7

0.7 = 217/ W

W = 217 / 0.7

W = 310

Thus, we should order two large pizzas, that will cost $22, to serve a group of 12.

Costs in accounting are the dollar amounts paid for materials, labor, services, goods, equipment, and other purchases made for use by a company or even other accounting entity. This sum is listed as the price on invoices and is recorded as an expense of asset cost basis in bookkeeping records.

Solution:

Let x be the quantity of pizzas ordered.

12 x 2 = 24 slices are required because a large pizza contains 8 slices per slice.

As a result, the necessary quantity of pizzas is:

[tex]x\geq 3(x-1) \leq x[/tex]

In order to find the best price, we must reduce the total cost, that is determined by:

C(x) = 15x plus 5(x - 1) (x - 1) - 15

Using the cost function's derivative in relation to x, we may calculate:

C'(x) = 20 - 10[tex]/(x-1)^2[/tex]

Finding the critical points by setting the derivative to zero yields the following results:

20 - 10[tex]/(x-1)^2[/tex] = 0

Simplishing, we obtain:

[tex](x-1)^2[/tex]= 2

By solving for x using square root of the both sides, we arrive at:

x = 1 ± √2

The ideal quantity to order is two pizzas because x has to be an integer.

By adding x = 2 to the cost function, we can determine the total cost:

C(2) = 15(2) + 5(2 - 1) - 15 = 22

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no 1) what is the square root of 2? it's about 1.5

no 2) pi is 3.14 blah blahblah so just put somewhere around 3

no 3) do square root of 11, it's about 3.3 so put it a tiny bit after no 2.

all of these will be after the 0, not before because theyre positive

hope this helps x

The simplification of the polynomial using factor by substitution is: ((3y - 2)⁴ - 1)/(3y - 2)²

Factoring polynomials simply means separating a polynomial into its component polynomials.

Sometimes, in the event that polynomials are particularly complicated, it is usually easiest to substitute a simple term and factor down.

We have the equation:

(3y - 2)² - (3y - 2)⁻²

Let 3y - 2 be denoted by S and as such we have:

S² - S⁻²

= S² - 1/S²

Using the denominator as factor, we have:

= (S⁴ - 1)/S²

Plugging 3y - 2 for S gives us:

((3y - 2)⁴ - 1)/(3y - 2)²

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Answer: I think its C

Answer:

Step-by-step explanation:

C is false. [tex]\angle BEC = \angle AED=126[/tex]   (vertically opposite).

The rest are correct.

Answer:

a. Since the half-life of the isotope is 8 hours, we know that the decay rate is exponential and we can use the formula:

A(t) = A0 * (1/2)^(t/8)

where A0 is the initial amount of the substance, t is the time elapsed, and A(t) is the amount of substance remaining after t hours.

Substituting the given values, we get:

A(t) = 7 * (1/2)^(t/8)

b. To find the rate at which the substance is decaying, we need to take the derivative of A(t) with respect to t:

A'(t) = -7/8 * (1/2)^(t/8) * ln(1/2)

Simplifying, we get:

A'(t) = -ln(2) * (7/8) * (1/2)^(t/8)

c. To find the rate of decay at 14 hours, we can plug in t=14 into the equation we found in part b:

A'(14) = -ln(2) * (7/8) * (1/2)^(14/8) ≈ -0.4346 grams per hour (rounded to four decimal places)

Answer:

a) We can use similar triangles to find PB in terms of a and b. Let x be the length of AD. Then, using the fact that AP = 4PC, we have:

PC = CP = x - b

AP = 4(x - b)

Also, using the fact that DC = (1/4)AB, we have:

AD = x

AB = 4DC = x/4

BC = AB - AD = x/4 - x = -3x/4

Now, consider the similar triangles PBC and ABD:

PB/AB = BC/AD

PB/(x/4) = (-3x/4)/x

PB = -3/4(x/4) = -3x/16

Finally, substituting x = a + b, we have:

PB = -3(a + b)/16

b) Using the same similar triangles as in part (a), we have:

DP/DC = PB/BC

DP/(1/4)AB = PB/(-3x/4)

DP = -3/4(PB)(DC/BC)AB

DP = -3/4(PB)(1/4)/(AB - AD)AB

Substituting the expressions for PB, AB, and AD from part (a), we get:

DP = -3(a + b)/16 * 1/4 / (-3(a + b)/4) * (a + b)/4

DP = -3/16 * 1/4 * 4/(3(a + b)) * (a + b)

DP = -3/16

So, DP = -3/16(a + b)

c) To check if DPB forms a straight line, we need to verify if the slopes of DP and PB are equal. Using the expressions we found in parts (a) and (b), we have:

Slope of PB = Δy/Δx = (-3/16(a+b) - 0)/(0 - (-3(a+b)/16)) = 3/16

Slope of DP = Δy/Δx = (-3(a+b)/16 - (-3/16(a+b)))/(1/4 - 0) = -3(a+b)/4

Since the slopes are not equal, DPB does not form a straight line.

The answers f(g(x)) = x and g(f(x)) = x tell us that the two functions f(x) and g(x) are inverses of each other.

The inverse of a function is a second function that "undoes" the effect of the first function. More specifically, if f is a function that maps elements from a set A to a set B, then its inverse function, denoted as f^(-1), maps elements from B back to A.

(a) To find f(g(x)), we need to substitute the expression for g(x) into f(x):

f(g(x)) = g(x) / (6 + g(x))

Substituting the expression for g(x) yields:

f(g(x)) = (6x / (1 - x)) / (6 + (6x / (1 - x)))

This equation can be made simpler by first locating a common denominator:

f(g(x)) = (6x / (1 - x)) / ((6(1 - x) / (1 - x)) + (6x / (1 - x)))

f(g(x)) = (6x / (1 - x)) / ((6 - 6x + 6x) / (1 - x))

f(g(x)) = (6x / (1 - x)) / (6 / (1 - x))

f(g(x)) = 6x / 6

f(g(x)) = x

To find g(f(x)), we need to substitute the expression for f(x) into g(x):

g(f(x)) = 6f(x) / (1 - f(x))

Substituting the expression for f(x) yields:

g(f(x)) = 6(x / (6 + x)) / (1 - (x / (6 + x)))

To simplify this expression, we can first find a common denominator:

g(f(x)) = 6(x / (6 + x)) / (((6 + x) / (6 + x)) - (x / (6 + x)))

g(f(x)) = 6(x / (6 + x)) / ((6 + x - x) / (6 + x))

g(f(x)) = 6(x / (6 + x)) / (6 / (6 + x))

g(f(x)) = x

(b) The answers f(g(x)) = x and g(f(x)) = x tell us that the two functions f(x) and g(x) are inverses of each other. This means that when we apply one function and then the other, we get back to the original input value. Specifically, if we apply f(x) to x and then apply g(x) to the result, we get x back, and if we apply g(x) to x and then apply f(x) to the result, we also get x back. This is a useful property when analyzing functions and their relationships.

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Answer:

$6235 1

' 1 . ' 8

Answer:

Step-by-step explanation:

To convert miles to feet, we need to multiply the number of miles by the number of feet in one mile. There are 5,280 feet in one mile. So, to find out how many feet Rachel ran, we can multiply 3 miles by 5,280 feet/mile:

3 miles x 5,280 feet/mile = 15,840 feet

Therefore, Rachel ran 15,840 feet. Answer: 15,840 feet.

Answer:

[tex] \rm \: f(x) = \dfrac{5}{x} + \dfrac{7}{ {x}^{2} } [/tex]

Differentiating both sides with respect to x

[tex] \rm \dfrac{d}{dx} ( {f}( x) = \dfrac{d}{dx} \bigg( \dfrac{5}{x} + \dfrac{7}{ {x}^{2} } \bigg)[/tex]

Using u + v rule

[tex] \rm \: {f}^{ \prime} x = \dfrac{d}{dx} \bigg( \dfrac{5}{x} \bigg) + \dfrac{d}{dx} \bigg( \dfrac{7}{ {x}^{2} } \bigg)[/tex]

[tex] \rm \: {f}^{ \prime} x = 5. \dfrac{d}{dx} ( {x}^{ - 1} ) + 7. \dfrac{d}{dx} ( {x}^{ - 2} )[/tex]

[tex] \rm \: {f}^{ \prime} x = 5.( - 1. {x})^{ (- 1 - 1)} + 7.( - 2. {x})^{ - 2 - 1} [/tex]

[tex] \rm \: {f}^{ \prime} x = { - 5x}^{ - 2} { - 14x}^{ - 3} [/tex]

[tex] \rm \: {f}^{ \prime} x = - \dfrac{5}{ {x}^{2} } - \dfrac{14}{ {x}^{3} } [/tex]

[tex] \rm \: {f}^{ \prime} x = - \bigg(\dfrac{5}{ {x}^{2} } + \dfrac{14}{ {x}^{3} } \bigg)[/tex]

Hense The required Derivative is answered.

[tex]\boxed{\begin{array}{c|c} \rm \: \underline{function}& \rm \underline{Derivative} \\ \\ \rm \dfrac{d}{dx} ({x}^{n}) \: \: \: \: \: \: \: \: \: \ & \rm nx^{n-1} \\ \\ \rm \: \dfrac{d}{dx}(constant) &0 \\ \\ \rm \dfrac{d}{dx}( \sin x )\: \: \: \: \: \: & \rm \cos x \\ \\ \rm \dfrac{d}{dx}( \cos x ) \: \: \: & \rm - \sin x \\ \\ \rm \dfrac{d}{dx}( \tan x ) & \rm \: { \sec}^{2}x \\ \\ \rm \dfrac{d}{dx}( \cot x ) & \rm- { \csc }^{2}x \\ \\ \rm \dfrac{d}{dx}( \sec x ) & \rm \sec x. \tan x \\ \\\rm \dfrac{d}{dx}( \csc x ) & \rm \: - \csc x. \cot x\\ \\ \rm \dfrac{d}{dx}(x) \: \: \: \: \: \: \: & 1 \end{array}}[/tex]

AB/BC = DE/EF

35/15 = DE/60

DE = 35*60 / 15

DE = 140

answer

A 140

Answer:

44.064x

Step-by-step explanation:

Answer: when you time 88.128 by 0.5, it gives you an answer of 44.064

Hope this helps :)

Answer: 1050$

Step-by-step explanation:

im a math teacher

Answer:

Temporary Differences Reported First on:     The Income Statement                       The Tax Return   Revenue      Expense                       Revenue              Expense1)       $272)                          $273)                                                                $274)                                                                                            $275)     $22             $276)                         $27                               $227)     $22             $27                                                             $178)     $22             $27                               $12                        $17Taxable Income assuming pretax accounting income is $100 million1)  Pretax Income - Revenue = $100m - $27m = $73m2) Pretax Income + Expense = $100m + $27m = $127m3) Pretax Income + Revenue Return = $100m + $27m = $127m4) Pretax Income - Expense Return = $100m - $27m = $73m5) Pretax Income - Revenue + Expense = $100m - $22m + $27m = $105m6) Pretax Income + Expense + Revenue Return = $100m + $27m + $22m = $149m7) Pretax Income - Revenue + Expense - Expense Return = $100m - $22m + $27m - $17m = $88m8) Pretax Income - Revenue + Expense + Revenue Return - Expense Return = $100m - $22m + $27m + $12m- $17m = $100m

Step-by-step explanation:

First, return is added to differentiate revenue and expense from the tax return from that of the income statement.Temporary difference is defined as the difference between the tax and financial reporting bases of assets and liabilities. These differences can result in taxable or deductible amounts in future years (deferred tax assets or liabilities).For each scenario, temporal difference of revenue reported first in the income statement is deducted from the pretax accounting income while expenses are added back to the pretax accounting income.For temporal differences from the tax return, the revenue is added to the pretax accounting income while expenses are deducted.