find the area of the figure below, composed of a rectangle with two semicircles removed.

Find The Area Of The Figure Below, Composed Of A Rectangle With Two Semicircles Removed.

Answers

Answer 1

This is a composite shape composed of a rectangle with two semicircles removed. The area will be calculated by subtracting the area of the two semicircles from the area of the rectangle

The area of a rectangle is given by:

[tex]\begin{gathered} Area(rectangle)=length\cdot width \\ length=12 \\ width=6 \\ Area(rectangle)=12\cdot6=72 \\ Area(rectangle)=72 \end{gathered}[/tex]

The area of the two semicircles is given by:

[tex]\begin{gathered} Area(2semicircles)=2(\frac{1}{2}\pi r^2) \\ Area(2semicircles)=\pi r^2 \\ r=\frac{diameter}{2}=\frac{6}{2}=3 \\ Area\mleft(2semicircles\mright)=\pi\cdot3^2=3.14\cdot9=28.26 \\ Area\mleft(2semicircles\mright)=28.26 \end{gathered}[/tex]

Therefore, the area of the figure is:

[tex]\begin{gathered} Area(figure)=Area(rectangle)-Area(2semicircles) \\ Area(figure)=72-28.26 \\ Area(figure)=43.74\approx43.7 \\ Area(figure)=43.7 \end{gathered}[/tex]


Related Questions

This is Calculus 1 Problem! MUST SHOW ALL THE JUSTIFICATION!!!

Answers

Given: A surveyor standing 50 feet from the base of a large tree measures the angle of elevation to the top of the tree as 75.8 degrees.

Required: To determine how accurately the angle must be measured if the percent error in estimating the tree's height is less than 5%.

Explanation: To estimate the angle, we will use the trigonometric ratio

[tex]tanx=\frac{h}{50}\text{ ...\lparen1\rparen}[/tex]

where h is the tree's height, and x is the angle of elevation to the top of the tree.

Hence we get

[tex]\begin{gathered} h=50\cdot(tan75.8\degree) \\ h=197.59\text{ feet} \end{gathered}[/tex]

Now differentiating equation 1, we get

[tex]sec^2xdx=\frac{1}{50}dh[/tex]

We can write the above equation as:

[tex]sec^2x\cdot\frac{xdx}{x}=\frac{h}{50}\cdot\frac{dh}{h}\text{ ...\lparen2\rparen}[/tex]

Also, it is given that the error in estimating the tree's height is less than 5%.

So

[tex]\frac{dh}{h}=0.05[/tex]

Also, we need to convert the angle x in radians:

[tex]x=1.32296\text{ rad}[/tex]

Putting these values in equation (2) gives:

[tex]\frac{dx}{x}=\frac{197.59}{50}\cdot\frac{cos^2(1.32296)}{1.32296}\cdot0.05[/tex]

Solving the above equation gives:

[tex]\begin{gathered} \frac{dx}{x}=3.9518\cdot0.04548551012\cdot0.05 \\ =0.008987\text{ radians} \end{gathered}[/tex]

Let

[tex]d\theta\text{ be the error in estimating the angle.}[/tex]

Then,

[tex]\lvert{d\theta}\rvert\leq0.008987\text{ radians}[/tex]

Final Answer:

[tex]\lvert{d\theta}\rvert\leq0.008987\text{ radians}[/tex]

Add or subtract. Simplify. Change the answers to mixed numbers, if possible.

Answers

Answer:

[tex]\begin{gathered} \frac{1}{8} \\ \\ \text{LCD = 8} \end{gathered}[/tex]

Explanation:

Here, we start by finding the lowest common denominator

From what we have, the lowest common denominator is the lowest common multiple of both denominators which is equal to 8

We divide the first denominator by this and multiply the result by its numerator. We take the same step for the second denominator

Mathematically, we have it that:

[tex]\frac{11-10}{8}\text{ = }\frac{1}{8}[/tex]

Identify the key features of the graph, including the x - intercepts. Y-intercept, axis of symmetry, and vertex. (3)

Answers

The graph of the given finction is:

Here, the x-intercept is at -1 and -6

The y-intercept is at 6

The axis of symmetry is x=-3.5

The vertex is (-3.5,-6.2)

quien me puede ayudar a resolver estos ejercicios porfa de ecuaciones

Answers

3x^2 -5x +1 =0

Aplica la formula cuadrática:

[tex]\frac{-b\pm\sqrt[]{b^2-4\cdot a\cdot c}}{2\cdot a}[/tex]

Donde:

a = 3

b= -5

c= 1

Reemplazando:

[tex]\frac{-(-5)\pm\sqrt[]{(-5)^2-4\cdot3\cdot1}}{2\cdot3}[/tex][tex]\frac{5\pm\sqrt[]{25-12}}{6}[/tex][tex]\frac{5\pm\sqrt[]{13}}{6}[/tex]

Positivo:

(5+√13) /6 = 1.43

NEgativo:

(5-√13) /6 = 0.23

What is 9207 /10 equivalent to?

Answers

Answer:

9207/10 is equivalent to 920.7

Which of the following expressions is equivalent to 2^4x − 5? the quantity 8 to the power of x end quantity over 10 the quantity 4 to the power of x end quantity over 5 the quantity 16 to the power of x end quantity over 32 the quantity 1 to the power of x end quantity over 32

Answers

The equivalent expression for the given exponent equation is 16^x/32

Given,

The exponent equation; 2^4x - 5

We have to find the expressions which is equivalent to 2^4x - 5

Exponential equations are inverse of logarithmic equations.

This can also be expressed as;

2^(4x-5) = 2^4x/2^5

2^4x-5 =16^x/2^5

2^4x-4 = 16^x/32

Hence the equivalent expression is 16^x/32

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Answer:it's not 4^x/5

Step-by-step explanation:

Find the length of the segment indicated. Round to the nearest tenth if necessary. Note: One segment of each triangle is a tangent line

Answers

Given

A circle with a tangent drawn to it forming one side of a triangle

Required

we need to find the diameter of the circle

Explanation

clearly it is a right angled triangle as radius through point of contact is perpendicular to the tangent. let the lenght of missing side be d

Therefore

[tex]d^2+12^2=20^2[/tex]

or

[tex]d^2=400-144[/tex]

or

[tex]d^2=256[/tex]

or d=16

the table below shows the attendance and revenue at theme parks in the us

Answers

Let

y ------> the year

x ----> revenue

so

Plot the given ordered pairs

see the attached figure

(please wait a minute to plot the points)

In the graph the x-coordinate 0 represent year 1990

Find out the equation of the line

take two points

(1990, 5.7) and (2006, 11.5)

Find the slope m

m=(11.5-5.7)/(2006-1990)

m=5.8/16

m=0.3625

Find the equation of the line in slope intercept form

y=mx+b

we have

m=0.3625

point (1990, 5.7)

substitute and solve for b

5.7=(0.3625)(1990)+b

b=-715.675

therefore

y=0.3625x-715.675

Mrs. Williams estimates that she will spend $65 onschool supplies. She actually spends $73. What is thepercent error? Round to the nearest tenth ifnecessary.

Answers

We can calculate the percent error as the absolute difference between the predicted value ($65) and the actual value ($73) divided by the actual value and multiplied by 100%.

This can be written as:

[tex]e=\frac{|p-a|}{a}\cdot100\%=\frac{|65-73|}{73}\cdot100\%=\frac{8}{73}\cdot100\%\approx11.0\%[/tex]

Answer: the percent error is approximately 11.0%

The table below shows the average annual cost of health insurance for a single individual, from 1999 to 2019, according to the Kaiser Family Foundation.YearCost1999$2,1962000$2,4712001$2,6892002$3,0832003$3,3832004$3,6952005$4,0242006$4,2422007$4,4792008$4,7042009$4,8242010$5,0492011 $5,4292012$5,6152013$5,8842014$6,0252015$6,2512016$6,1962017$6,4352017$6,8962019$7,186(a) Using only the data from the first and last years, build a linear model to describe the cost of individual health insurance from 1999 onward. Use t to represent years after 1999 (treating 1999 as year 0).Pt = (b) Using this linear model, predict the cost of insurance in 2030.$ (c) = According to this model, when do you expect the cost of individual insurance to reach $12,000? Give your answer as a calendar year (ex: 2020)..

Answers

The given data plot will look thus:

a) Building a model using just the 1999 and 2019 years:

[tex]\begin{gathered} 1999\rightarrow0\rightarrow2196 \\ 2019\rightarrow20\rightarrow7186 \\ \text{Havng} \\ x_1=0,y_1=2196 \\ x_2=20,y_2=7186 \\ \frac{y-y_1}{x-x_1}=\frac{y_2-y_1}{x_2-x_1}_{} \\ \text{The model will be:} \\ P_t=249.5t+2196 \end{gathered}[/tex]

b) The cost of insurance in 2030

[tex]\begin{gathered} P_t=249.5t+2196 \\ t=2030-1999=31 \\ \text{The cost of insurance in 2030 therefore will be:} \\ =249.5(31)+2196 \\ =7734.5+2196 \\ =\text{ \$9930.5} \end{gathered}[/tex]

c) When do we expect the cost to reach $12,000

[tex]\begin{gathered} P_t=249.5t+2196 \\ 12,000=249.5t+2196 \\ 12000-2196=249.5t \\ 9804=249.5t \\ \frac{9804}{249.5}=\frac{249.5t}{249.5} \\ 39.2946=t \\ Since\text{ t = year -1999} \\ 39.2946+1999=\text{year} \\ 2038.2946=\text{year} \\ Since\text{ we are to give our answer as an exact year} \\ \text{The year will be }2039. \end{gathered}[/tex]

hello, in the picture you can see a graph and my teacher said that the domain and range would be all real numbers possible. could you please help me because I don't understand why.

Answers

The domain is all the values of the independent variable (in this case, x) for which the function is defined.

In this case, as it is indicated with the arrows in both ends, the function continues for greater and smaller values of x.

As there is no indication that for some value or interval of x the function is not defined (a discontinuity, for example), then it is assumed that the function domain is all the real values.

Example function:

We have the function y=1/(x-2)

We can look if there is some value of x that makes the function not defined.

The only value of x where f(x) is not defined is x=2. When x approximates to 2, the value of the function gets bigger or smaller whether we are approaching from the right or from the left.

Then, the function is not defined for x=2. So, the domain of f(x) is all the real numbers different from x=2.

The domain is, by default, all the real numbers, but we have to exclude all the values of x (or intervals, in some cases like the square roots) for which f(x) is not defined.

20 P1: a For two events, A and B.P(B) -0.5, P(AB) -0.4 andPAB) = 0.4.Calculatei PAB)ii P(A)ili P(AUB)iv P(AB)(8 marks)b Determine, with a reason, whetherevents A and B are independent ornot.(2 marks)probabilityStatistics and

Answers

We have two events A and B.

We know that:

P(B) = 0.5

P(A|B) = 0.4

P(A∩B') = 0.4

i) We have to calculate P(A∩B).

We can relate P(A∩B) with the other probabilities knowing that:

[tex](A\cap B)\cup(A\cap B^{\prime})=A[/tex]

So we can write:

[tex]P(A\cap B)+P(A\cap B^{\prime})=P(A)[/tex]

We know P(A∩B') but we don't know P(A), so this approach is not useful in this case.

We can try with the conditional probability relating P(A∩B) as:

[tex]P(A|B)=\frac{P(A\cap B)}{P(B)}[/tex]

In this case, we can use this to calculate P(A∩B) as:

[tex]\begin{gathered} P(A\cap B)=P(A|B)P(B) \\ P(A\cap B)=0.4*0.5 \\ P(A\cap B)=0.2 \end{gathered}[/tex]

ii) We have to calculate P(A) now.

We can use the first equation we derive to calculate it:

[tex]\begin{gathered} P(A)=P(A\cap B)+P(A\cap B^{\prime}) \\ P(A)=0.2+0.4 \\ P(A)=0.6 \end{gathered}[/tex]

iii) We have to calculate P(A∪B).

We can use the expression:

[tex]\begin{gathered} P(A\cup B)=P(A)+P(B)-P(A\cap B) \\ P(A\cup B)=0.6+0.4-0.2 \\ P(A\cup B)=0.8 \end{gathered}[/tex]

iv. We can now calculate P(A|B') as:

[tex]\begin{gathered} P(A)=P(A|B)+P(A|B^{\prime}) \\ P(A|B^{\prime})=P(A)-P(A|B) \\ P(A|B^{\prime})=0.6-0.4 \\ P(A|B^{\prime})=0.2 \end{gathered}[/tex]

b) We now have to find if A and B are independent events.

To do that we have to verify this conditions:

[tex]\begin{gathered} 1)P(A|B)=P(A) \\ 2)P(B|A)=P(B) \\ 3)P(A\cap B)=P(A)*P(B) \end{gathered}[/tex]

We can check for the first condition, as we already know the value:

[tex]\begin{gathered} P(A|B)=0.4 \\ P(A)=0.6 \\ =>P(A|B)P(A) \end{gathered}[/tex]

Then, the events are not independent.

Answer:

i) P(A∩B) = 0.2

ii) P(A) = 0.6

iii) P(A∪B) = 0.8

iv) P(A|B') = 0.2

b) The events are not independent.

Select the correct choice below and, if necessary, fill in the answer box within your choice

Answers

x² - 20x + 100

Find two numbers, such that its sum gives -20 and its product gives 100

If such numbers exist, this implies that the polynomial is NOT prime

The two numbers are: -10 and -10

Replace the coefficient of x with the two numbers

x² - 10x -10x + 100

x(x-10) - 10(x - 10)

(x-10)(x-10)

(x-10)²

Therefore, the correct option is A.

x² - 20x + 100 = (x-10)²

Find the slope of every line that is parallel to the graph of the equation

Answers

The slope should be - 1/2

F(x) = -3x,x<0 4,x=0 x^2, x>0 given the piece wide functions shown below select all of the statements that are true

Answers

The correct statements regarding the numeric values of the piece-wise function are given as follows:

B. f(3) = 9.

D. f(2) = 4.

How to find the numeric value of a function or of an expression?

To find the numeric value of a function or of an expression, we replace each instance of the variable in the function or in the expression by the value at which we want to find the numeric value.

A piece-wise function means that the definition of the input is different based on the input of the function. In this problem, all the numeric values we are calculating are for positive numbers, hence the definition of the function is given by:

f(x) = x².

Then the numeric values of the function are given as follows:

f(1) = 1² = 1.f(2) = 2² = 4.f(3) = 3² = 9.f(4) = 4² = 16.

Meaning that options B and D are correct.

Missing information

The options are given by the image at the end of the answer.

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This graph shows the solution to which inequality?3.2)(-3,-5)O A. ys fx-2B. vfx-2O c. vfx-2OD. yzfx-2

Answers

First, find the equation of the line, given that the points (3,2) and (-3,-6) belong to that line. To do so, use the slope formula and then substitute the value of the slope and the coordinates of a point on the slope-point formula of a line:

[tex]y=m(x-x_0)+y_0[/tex]

The slope of the line, is:

[tex]\begin{gathered} m=\frac{\Delta y}{\Delta x} \\ =\frac{(2)-(-6)}{(3)-(-3)} \\ =\frac{2+6}{3+3} \\ =\frac{8}{6} \\ =\frac{4}{3} \end{gathered}[/tex]

Therefore, the equation of a line (using the point (3,2)) is:

[tex]\begin{gathered} y=\frac{4}{3}(x-3)+2 \\ =\frac{4}{3}x-\frac{4}{3}\times3+2 \\ =\frac{4}{3}x-4+2 \\ =\frac{4}{3}x-2 \end{gathered}[/tex]

Since the colored region on the coordinate plane is placed above the line

y=(4/3)x-2, then the equation of the inequality is:}

[tex]undefined[/tex]

20. Write the slope-intercept form of the line described in the followingPerpendicular to -2+3y=-15and passing through (2, -8)

Answers

The equation of a line in Slope-Intercept form is:

[tex]y=mx+b[/tex]

Where "m" is the slope and "b" is the y-intercept.

Solve for "y" from the equation given in the exercise in order to write it in Slope-Intercept form:

[tex]\begin{gathered} -2+3y=-15 \\ 3y=-15+2 \\ y=-\frac{13}{2} \end{gathered}[/tex]

You can notice that the equation has this form:

[tex]y=b[/tex]

Where "b" is the y-intercept.

Then, it's a horizontal line, which means that its slope is:

[tex]m=0[/tex]

Since it is a horizontal line, the lines perpendicular to that line is a vertical line, whose slope is undefined and whose equation is:

[tex]x=k[/tex]

Where "k" is the x-intercept.

Knowing that the x-coordinate of any point on a vertical line is always the same, and knowing that this line passes through this point:

[tex]\mleft(2,-8\mright)[/tex]

You can determine that the equation of the line is:

[tex]x=2[/tex]

Which sequence of transformations will map AABC onto AA' B'C'?A- reflection and translationB- rotation and reflectionC- translation and dilation D- dilation and rotation

Answers

For the given problem, we can observe that the image is bigger than the original diagram.

We can also observe that the image is rotated counterclockwise.

Hence, the sequence of transformation that maps triangle ABC onto triangle A'B'C' is a dilation and a rotation.

Answer: Option D

points E,D and H are the midpoints of the sides of TUV, UV=100,TV=126,and HD=100, find HE.

Answers

Since the triangles are similar there exists correspondance in the angles, so in order to solve this you just have to clear the function:

[tex]\begin{gathered} \frac{VD}{VU}=\frac{HD}{TU} \\ \end{gathered}[/tex]

Since D is the midpoint of VU, VD=50

[tex]\begin{gathered} \frac{50}{100}=\frac{100}{TU} \\ 50\times TU=100\times100 \\ TU=200 \end{gathered}[/tex]

then

[tex]\begin{gathered} \frac{HE}{UV}=\frac{HD}{TU} \\ \frac{HE}{100}=\frac{100}{200} \\ HE=\frac{100}{200}\times100 \\ HE=50 \end{gathered}[/tex]

In the picture below, angle 2 = 130 degrees, what is the measurement of angle 8?

Answers

Answer:

130°

Step-by-step explanation:

Alternate interior angles are equal in measure.

What is 120 percent of 118?

Answers

120 percent of 118 is expressed mathematically as;

120% of 118

120/100 * 118

= 12/10 * 118

= 6/5 * 118

= 708/5

= 141.6%

Hence 120 percent of 118 is 141.6%

3. The number line below represents the solution to which inequality of he 0 1 2 3 4 5 6 7 8 9 10

Answers

let x be the money daniel has. So we get that

[tex]x\ge72+15\rightarrow x\ge87[/tex]

Daniel has at least $87

A diesel train left Abuja and traveled west. One hour later a freight train left traveling 50 mph faster in an effort to catch up to it. After three hours of freight train finally caught up. Find the diesel train’s average speed.

Answers

The speed at which diesel train was moving is = 150mph

In the above question, it is given that,

Let the speed of the diesel train which left Abuja be x mph

then, speed of freight train which is moving 50 mph faster than diesel train = (50 + x)mph

Further, the freight train finally caught up the diesel train after three hours

So time taken by freight train = 3 hours

While time taken by diesel train would 1 hour more than freight train as its moving slower = 3 + 1 = 4 hours

Now, it is given that both the trains finally catch up, it means the distance travelled by both the trains would be equal

We know that,

Speed = [tex]\frac{Distance}{Time}[/tex]

Distance = Speed x Time

Distance travelled by Diesel train = distance travelled by Freight train

4x = 3(50 + x)

4x = 150 + 3x

x = 150 mph

Hence, the speed at which diesel train was moving is = 150mph

While, the speed at which freight train was moving is = (150 + x)mph = (150 + 50)= 200mph

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1. Which of the following is NOT a linear function? (1 point ) Oy=* -2 x x Оy - 5 ya 0 2. 3*- y = 4 3.

Answers

hello

to solve this question we need to know or understand the standard form of a linear equation

the standard form of a linear equation is given as

[tex]\begin{gathered} y=mx+c \\ m=\text{slope} \\ c=\text{intercept} \end{gathered}[/tex]

from the options given in the question, only option D does not corresponds with the standard form of a linear equation

[tex]undefined[/tex]

Writing a equation of a circle centers at the origin

Answers

ANSWER

[tex]x^2+y^2=100[/tex]

EXPLANATION

The general equation of a circle is:

[tex](x-h)^2+(y-k)^2=r^2[/tex]

where (h, k) = the center of the circle

r = radius of the circle (i.e. distance from any point on its circumference to the center of the circle)

The center of the circle is the origin, that is:

[tex](h,k)=(0,0)[/tex]

To find the radius, apply the formula for distance between two points:

[tex]r=\sqrt[]{(x_1-h)^2+(y_1-k)^2_{}}[/tex]

where (x1, y1) is the point the circle passes through

Hence, the radius is:

[tex]\begin{gathered} r=\sqrt[]{(0-0)^2+(-10-0)^2}=\sqrt[]{0+(-10)^2} \\ r=\sqrt[]{100} \\ r=10 \end{gathered}[/tex]

Hence, the equation of the circle is:

[tex]\begin{gathered} (x-0)^2+(y-0)^2=(10)^2 \\ \Rightarrow x^2+y^2=100 \end{gathered}[/tex]

A music club charges an initial joining fee of $24.00. The cost per CD is $8.50. The graph shows the cost of belonging to the club as a function of CDs purchased. How will the graph change if the cost per CD goes up by $1.00.? (The new function is shown by the dotted line.)

Answers

Given the function with a graph that shows the cost of belonging to the club as a function of CDs purchased

linear function with the form

[tex]y=x[/tex]

since the new graph has a new cd cost up by $1.00

then the new line is

Correct answer

Option C

Write an equation of a circle with diameter AB.A(1,1), B(11,11)Choose the correct answer below.A. (X-6)2 + (y-6)2 = 11C. (x-6)2 – (y+6)2 = 50E. (X+6)2 + (y-6)2 = 50G. (X+6)2 – (y + 6)2 = 50

Answers

The question asks us to find the equation of a circle with diameter AB with coordinates:

A = (1, 1), B = (11, 11)

In order to solve this, we need to know the general form of the equation of a circle.

The general form of the equation of a circle is given by:

[tex]\begin{gathered} (x-a)^2+(y-b)^2=r^2 \\ \text{where,} \\ (a,b)=\text{ coordinates of the center of the circle} \\ r=\text{radius of the circle} \end{gathered}[/tex]

We have been given the coordinates of the diameter. This means that finding the midpoint of the diameter

will give us the center coordinates of the circle, which is (a, b).

The formula for finding the midpoint of a line is given below:

[tex]\begin{gathered} (x,y)=\frac{x_2+x_1}{2},\frac{y_2+y_1}{2} \\ \text{where,} \\ x_2,y_2=\text{ second coordinate} \\ x_1,y_1=\text{first coordinate} \end{gathered}[/tex]

For better understanding, a sketch is made below:

Therefore, let us find the coordinates of the center of the circle using the midpoint formula given above:

[tex]\begin{gathered} a,b=\frac{x_2+x_1}{2},\frac{y_2+y_1}{2} \\ x_2=11,y_2=11 \\ x_1=1,y_1=1 \\ \\ \therefore(a,b)=\frac{11+1}{2},\frac{11+1}{2} \\ \\ (a,b)=6,6 \\ Thus, \\ a=6,b=6 \end{gathered}[/tex]

Now that we have the coordinates of the center, we now need to find the value of the radius of the circle.

This is done by finding the length from the center of the circle to any side of the diameter.

Let us use from point (6,6) which is the center to the point (11, 11) which is one side of the diameter.

The formula for finding the distance between two points is given by:

[tex]\begin{gathered} |\text{distance}|^2=(y_2-y^{}_1)^2+(x_2-x_1)^2_{} \\ \text{where,} \\ x_2,y_2=\text{second point} \\ x_1,y_1=\text{first point} \end{gathered}[/tex]

hence, we can now find the square of the radius as:

[tex]\begin{gathered} r^2=(y_2-y^{}_1)^2+(x_2-x_1)^2_{} \\ x_2,y_2=11,11_{} \\ x_1,y_1=6,6 \\ \\ \therefore r^2=(11-6)^2+(11-6)^2 \\ r^2=5^2+5^2 \\ r^2=25+25 \\ \therefore r^2=50 \end{gathered}[/tex]

Now that we have the radius, we can now compute the equation of the circle as:

[tex]\begin{gathered} (x-a)^2+(y-b)^2=r^2 \\ a=6,b=6,r^2=50 \\ \\ \therefore(x-6)^2+(y-6)^2=50\text{ (Option B)} \end{gathered}[/tex]

A graph of the circle is given below:

Can you Convert 840 inches to cm. Use unit analysis to convert the rate.

Answers

we know that

1 in=2.54 cm

so

840 in

Applying proportion

1/2.54=840/x

x=(840*2.54)/1

x=2,133.6 cm

answer is

2,133.6 cmApplying unit rate or unit analysis

we have

2.54 cm/in

Multiply by 840 in

2.54*(840)=2,133.6 cm40/

find x..in a right triangle ️ with a height of 10 and hypotenuse of 19

Answers

Since it is a right triangle we can apply the Pythagorean theorem:

c^2 = a^2 + b^2

Where:

c= hypotenuse (the longest side) = 19

a & b = the other 2 legs of the triangle

Replacing:

19^2 = 10^2 + x^2

Solve for x

361 = 100 + x^2

361 - 100 = x^2

261 = x^2

√261 =x

x= 16.16

I need help figuring out if what I got is rigjt

Answers

The figure in the picture shows 3 squares that form a right triangle. Each side of the triangle is determined by one side of the squares.

The only information we know is the area of two of the squares. The area of a square is calculated as the square of one of its sides

[tex]A=a^2[/tex]

So to determine the side lengths of the squares, we can calculate the square root of the given areas:

[tex]\begin{gathered} A=a^2 \\ a=\sqrt[]{A} \end{gathered}[/tex]

For one of the squares, the area is 64m², you can determine the side length as follows:

[tex]\begin{gathered} a=\sqrt[]{64} \\ a=8 \end{gathered}[/tex]

For the square with an area 225m², the side length can be calculated as follows:

[tex]\begin{gathered} a=\sqrt[]{225} \\ a=15 \end{gathered}[/tex]

Now, to determine the third side of the triangle, we have to apply the Pythagorean theorem. This theorem states that the square of the hypothenuse (c) of a right triangle is equal to the sum of the squares of its sides (a and b), it can be expressed as follows:

[tex]c^2=a^2+b^2[/tex]

If we know two sides of the triangle, we can determine the length of the third one. In this case, the missing side is the hypothenuse (c), to calculate it you have to add the squares of the sides and then apply the square root:

[tex]\begin{gathered} c^2=225+64 \\ c=\sqrt[]{225+64} \\ c=\sqrt[]{289} \\ c=17 \end{gathered}[/tex]

So the triangle's sides have the following lengths: 8, 15 and, 17

Now that we know the side lengths we can calculate the perimeter of the triangle. The perimeter of any shape is calculated by adding its sides:

[tex]\begin{gathered} P=8+15+17 \\ P=40m \end{gathered}[/tex]

yes you did get it right
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