Find the lateral surface area of thiscylinder. Round to the nearest tenth.8ft4ftLSA = [ ? ] ft2—

Find The Lateral Surface Area Of Thiscylinder. Round To The Nearest Tenth.8ft4ftLSA = [ ? ] Ft2

Answers

Answer 1

Solution

Step 1:

Write the lateral surface area or curved surface area of a cylinder:

[tex]Lateral\text{ surface area = 2}\pi rh[/tex]

Step 2:

Write the given data

Height h = 8ft

Radius r = 4 ft

Step 3:

Substitute in the formula to find the lateral surface area.

[tex]\begin{gathered} Lateral\text{ surface area = 2}\pi rh \\ =\text{ 2 }\times\text{ 3.142 }\times\text{ 4 }\times\text{ 8} \\ =\text{ 201.1 ft}^2 \end{gathered}[/tex]

Final answer

201.1


Related Questions

2.3 I can apply the Pythagorean Theorem and Triangle Inequality.Which of the following could be lengths for a triangle?Show your work on a separate piece of paper.(Select all that apply.)5, 6, 9D 4,8, 127, 8, 17Are any of the selected triangles above right triangles?How do you know?Suami

Answers

For the triangle with sides 5, 6 and 9, you have:

5 + 6 > 9

5 + 9 > 6

9 + 6 > 9

9² ≠ 5² + 6²

≠ 25 + 36

≠ 61

Then, it is not a right triangle

For the triangle with sides 4, 8 and 12:

4 + 8 ≥ 12

in this case the triangle inequality is not present

12² ≠ 4² + 8²

Then, it is not a right triangle

For the triangle with sides 7, 8 and 17:

7 + 8 < 17

in this case the triangle inequality is not present

17² ≠ 8² + 7²

Then, it is not a right triangle

Okay so I’m doing this assignment and got stuck ont his question can someone help me out please

Answers

ANSWER

[tex]B.\text{ }\frac{256}{3}[/tex]

EXPLANATION

We want to find the value of the function for F(4):

[tex]F(x)=\frac{1}{3}*4^x[/tex]

To do this, substitute the value of x for 4 in the function and simplify:

[tex]\begin{gathered} F(4)=\frac{1}{3}*4^4 \\ F(4)=\frac{1}{3}*256 \\ F(4)=\frac{256}{3} \end{gathered}[/tex]

Therefore, the answer is option B.

the hypotenuse of a right triangle is 5 ft long. the shorter leg is 1 ft shorter than the longer leg. find the side lengths of the triangle

Answers

the hypotenuse of the right angle triangle is h = 5 ft

it is given that

the shorter leg is 1 ft shorter than the longer leg.

let the shorter leg is a and longer leg is b

the

b - a = 1

b = 1 + a

in the traingle using Pythagoras theorem,

[tex]a^2+b^2=h^2[/tex]

put he values,

[tex]a^2+(1+a)^2=5^2[/tex][tex]\begin{gathered} a^2+1+a^2+2a=25 \\ 2a^2+2a-24=0 \\ a^2+a-12=0 \end{gathered}[/tex][tex]\begin{gathered} a^2+4a-3a-12=0_{} \\ a(a+4)-3(a+4)=0 \\ (a+4)(a-3)=0 \end{gathered}[/tex]

a + 4 = 0

a = - 4

and

a - 3 = 0

a = 3

so, the longer leg is b = a + 1 = 3 + 1 = 4

thus, the answer is

shorter leg = 3 ft

longer length = 4 ft

hypotenuse = 5 ft

3. Identify the solution to the system of equations by graphing:(2x+3y=12y=1/3 x+1)

Answers

Given equations are

[tex]2x+3y=12[/tex][tex]y=\frac{1}{3}x+1[/tex]

The graph of the equations is

Red line represents the equation 2x=3y=12 and the blue line represents the equation y=1/3 x=1.

A cylinder truck all paint cans to be inches across the top diameter in about 10 inches high. How many cubic inches of pink it all to the nearest hundredth?

Answers

Given:

A cylinder truck all paint cans to be inches across the top diameter in about 10 inches high.

[tex]\begin{gathered} r=1.5in \\ h=10in \end{gathered}[/tex]

Required:

To find the volume of the cylinder.

Explanation:

The volume of the cylinder is,

[tex]V=\pi r^2h[/tex]

Therefore,

[tex]\begin{gathered} V=3.14\times1.5^2\times10 \\ \\ =3.14\times2.25\times10 \\ \\ =70.65in^3 \end{gathered}[/tex]

Final Answer:

70.65 cubic inches of paint it hold.

(0,1), (2,4), (4,7) (9.1)}Domain:Range:

Answers

The domain of an ordered pair are its first elements and its range are all the second elements of the ordered pair.

So, the domain ={0,2,4,9}

Range={1,4,7,1}

The coordinates of three vertices of a rectangle are (3,7), (-3,5), and (0,-4). What are the coordinates of the fourth vertex?A. (6,-2)B. (-2,6)C. (6,2)D. (-2,-6)

Answers

ANSWER

A. (6, -2)

EXPLANATION

Let's graph these three vertices,

The fourth vertex must be at the same distance from (0, -4) as vertex (3, 7) is from (-3, 5),

Note that the horizontal distance between these two points is 6 units and the vertical distance is 2 units. The fourth vertex is,

[tex](0+6,-4+2)=(6,-2)[/tex]

Hence, the fourth vertex is (6, -2)

Elisa purchased a concert ticket on a website. The original price of the ticket was $95. She used a coupon code to receive a 10% discount. The website applied a 10% service fee to the discounted price. Elisa's ticket was less than the original by what percent?

Answers

The price of the ticket after the cupon is:

[tex]95\cdot0.9=85.5[/tex]

To this price we have to add 10%, then:

[tex]85.5\cdot1.1=94.05[/tex]

Hence the final cost of the ticket is $94.05.

To find out how less is this from the orginal price we use the rule of three:

[tex]\begin{gathered} 95\rightarrow100 \\ 94.05\rightarrow x \end{gathered}[/tex]

then this represents:

[tex]x=\frac{94.05\cdot100}{95}=99[/tex]

Therefore, Elisas's ticket was 1% less than the orginal price.

3 2 — · — = _____ 8 5 2 9· — = _____ 3 7 8 — · — = _____ 8 7 x — · y = _____ y a b —— · — = _____ 2b c m n2 —- · —— = _____ 3n mGive the product in simplest form: 1 2 · 2— = _____ 2Give the product in simplest form: 1 2 — · 3 = _____ 4 Give the product in simplest form: 1 1 1— · 1— = _____ 2 2 Give the product in simplest form: 1 2 3— · 2— = _____ 4 3

Answers

Given:

[tex]\frac{3}{8}\cdot\frac{2}{5}[/tex]

Required:

We need to multiply the given rational numbers.

Explanation:

Cancel out the common terms.

[tex]\frac{3}{8}\cdot\frac{2}{5}=\frac{3}{4}\cdot\frac{1}{5}[/tex][tex]Use\text{ }\frac{a}{b}\cdot\frac{c}{d}=\frac{a\cdot c}{b\cdot d}.[/tex][tex]\frac{3}{8}\cdot\frac{2}{5}=\frac{3}{20}[/tex]

Consider the number.

[tex]\frac{7}{8}\cdot\frac{8}{7}=\frac{1}{1}\cdot\frac{1}{1}[/tex]

Cancel out the common multiples

[tex]9\cdot\frac{2}{3}[/tex][tex]9\cdot\frac{2}{3}=3\cdot2=6[/tex]

Consider the number

[tex]\frac{7}{8}\cdot\frac{8}{7}[/tex]

Cancel out the common multiples.

[tex]\frac{7}{8}\cdot\frac{8}{7}=\frac{1}{1}\cdot\frac{1}{1}[/tex][tex]\frac{7}{8}\cdot\frac{8}{7}=1[/tex]

Consider the number

[tex]\frac{x}{y}\cdot y=x[/tex][tex]\frac{a}{2b}\cdot\frac{b}{c}=\frac{a}{2}\cdot\frac{1}{c}=\frac{a}{2c}[/tex][tex]\frac{m}{3n}\cdot\frac{n^2}{m}=\frac{1}{3}\cdot\frac{n}{m}=\frac{n}{3m}[/tex]

Final answer:

[tex]\frac{3}{8}\cdot\frac{2}{5}=\frac{3}{20}[/tex][tex]9\cdot\frac{2}{3}=6[/tex][tex]\frac{7}{8}\cdot\frac{8}{7}=1[/tex][tex]\frac{x}{y}\cdot y=x[/tex]

[tex]\frac{a}{2b}\cdot\frac{b}{c}=\frac{a}{2c}[/tex][tex]\frac{m}{3n}\cdot\frac{n^2}{m}=\frac{n}{3m}[/tex]

An outdoor equipment store surveyed 300 customers about their favorite outdoor activities. The circle graph below shows that 135 customers like fishing best, 75 customers like camping best, and 90 customers like hiking best.

Answers

it is given that,

total customer surveyed is 300 customers

also, it is given that,

135 customers like fishing best, 75 customers like camping best, and 90 customers like hiking best.​

the total 300 customers representing the whole circle and circle has a complete angle of 360 degrees

so, 300 customers = 360 degrees,

1 customer = 360/300

= 6/5 degrees,

so, for fishing

135 customer = 135 x 6/5 degrees

= 27 x 6

= 162 degrees,

so, for camping

75 x 6/5 = 90 degrees,

for hiking

90 x 6/5 = 108 degrees,

A length of 48 ft. gave Malama an area
of 96 sq. ft. What other length would
give her the same area (96 sq. ft.)?
4

Answers

I would say the answer is either 48 or 2. Whatever is on the multiple choice

My explanation:


Easy explanation ⬇️

Given length: 48ft

Total area is 96sq. ft

48 + 48 = 96


Second explanation:

Formula to find missing length ⬇️

Area = length x width

96 sq. ft = 48ft x w

96 sq. ft = 48ft x 2



(2 x 48 = 96)



So 2 (probably 48) should be your answer!

A psychologist has designed a questionnaire to measure individuals' aggressiveness. Suppose that the scores on the questionnaire are normally distributed with
a standard deviation of 90. Suppose also that exactly 10% of the scores exceed 700. Find the mean of the distribution of scores. Carry your intermediate
computations to at least four decimal places. Round your answer to at least one decimal place.

Answers

μ =  782.02 is the mean of the distribution of scores by standard deviation.

What is standard deviation in math?

A statistical measurement called standard deviation examines how far away from the mean a set of statistics is. Standard deviation, to put it simply, gauges the degree of dispersion between numbers in a data collection. The variance's square root is used to generate this metric.

we have from standard normal table that

P(Z > 1.282) = 0.1

Therefore the given Z score of a score of 700 is given thus 1.282.

the z score is given:

x - μ / α = 1.282

700 - μ / 90 = 1.282

Therefore μ = (700 - 90)*1.282 = 782.02

So we have that μ =  782.02

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Find the measure of the indicated angle to the nearest degree.A. 63B. 25C. 31D. 27

Answers

The point of the problem is to remember the cosine relation. It says, in this case, that

[tex]\cos (?)=\frac{\text{adjacent side}}{Hypotenuse}\Rightarrow\begin{cases}\text{adjacent side}=6 \\ \text{Hypotenuse}=13\end{cases}\Rightarrow\cos (?)=\frac{6}{13}[/tex]

Converting the last equation by the inverse function, we get

[tex]?=\cos ^{-1}(\frac{6}{13})\approx62.5[/tex]

For the first decimal place (5) equals 5, and by the rounding rule to the nearest degree, we get 63. The answer is A.

Write the sequence {15, 31, 47, 63...} as a function A. A(n) = 16(n-1)B. A(n) = 15 + 16nC. A(n) = 15 + 16(n-1)D. 16n

Answers

To find the answer, we need to prove for every sequence as:

Answer A.

If n=1 then:

A(1) = 16(1-1) = 16*0 = 0

Since 0 is not in the sequence so, this is not the answer

Answer B.

If n=1 then:

A(1) = 15 + 16*1 = 31

Since 31 is not the first number of the sequence, this is not the answer

Answer D.

If n=1 then:

16n = 16*1 = 16

Since 16 is not in the sequence so, this is not the answer

Answer C.

If n = 1 then:

A(1) = 15 + 16(1-1) = 15

A(2) = 15 + 16(2-1) = 31

A(3) = 15 + 16(3-1) = 47

A(4) = 15 + 16(4-1) = 63

So, the answer is C

Answer: C. A(n) = 15 + 16(n-1)

1. How much less is the area of a rectangular field 60 by 20
meters than that of a square field with the same perimeter?

Answers

The area of the rectangular field is 400m² less than the area of the square field.

How to find the area of a rectangle and square?

A rectangle is a quadrilateral that has opposite sides equal to each other. Opposite side are also parallel to each other.

A square is a quadrilateral that has all sides equal to each other.

Therefore,

area of the rectangular field = lw

where

l = lengthw = width

Therefore,

area of the rectangular field = 60 × 20

area of the rectangular field = 1200 m²

The square field have the same perimeter with the rectangular field.

Hence,

perimeter of the rectangular field = 2(60 + 20)

perimeter of the rectangular field =  2(80)

perimeter of the rectangular field = 160 meters

Therefore,

perimeter of the square field = 4l

160 = 4l

l = 160 / 4

l = 40

Hence,

area of the square field  = 40²

area of the square field  = 1600 m²

Difference in area = 1600 - 1200

Difference in area = 400 m²

Therefore, the area of the square field is 400 metre square greater than the rectangular field.

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Function f is defined by f(x) = 2x – 7 and g is defined by g(x) = 5*

Answers

Answer

f(3) = -1, f(2) = -3, f(1) = -5, f(0) = -7, f(-1) = -9

g(3) = 125, g(2) = 25, g(1) = 5, g(0) = 1, g(-1) = 0.2

Step-by-step explanation:

Given the following functions

f(x) =2x - 7

g(x) = 5^x

find f(3), f(2), f(1), f(0), and f(-1)

for the first function

f(x) = 2x - 7

f(3) means substitute x = 3 into the function

f(3) = 2(3) - 7

f(3) = 6 - 7

f(3) =-1

f(2), let x = 2

f(2) = 2(2) - 7

f(2) = 4 - 7

f(2) =-3

f(1) = 2(1) - 7

f(1) = 2 - 7

f(1) =-5

f(0) = 2(0) - 7

f(0) =0 - 7

f(0) = -7

f(-1) = 2(-1) - 7

f(-1) = -2 - 7

f(-1) = -9

g(x) = 5^x

find g(3), g(2), g(1), g(0), and g(-1)

g(3), substitute x = 3

g(3) = 5^3

g(3) = 5 x 5 x 5

g(3) = 125

g(2) = 5^2

g(2) = 5 x 5

g(2) = 25

g(1) = 5^1

g(1) = 5

g(0) = 5^0

any number raised to the power of zero = 1

g(0) = 1

g(-1) = 5^-1

g(-1) = 1/5

g(-1) = 0.2

Janelle is conducting an experiment to determine whether a new medication is effective in reducing sneezing. She finds 1,000 volunteers with sneezing issues and divides them into two groups. The control group does not receive any medication; the treatment group receives the medication. The patients in the treatment group show reduced signs of sneezing. What can Janelle conclude from this experiment?

Answers

Answer:

Step-by-step explanation:

WhichIs 9.56556555... a rational or irrationalnumber? Highlight the correct answer below.181a)Whicha) Rational numberb) Irrational numberthat ap

Answers

Answer

Option B is correct.

9.56556555... is an irrational number.

Step-by-step Explanation

Rational numbers are numbers that can be expressed as a clear fraction consisting of the numerator and the denominator both being integers.

The decimal form or decimal expansion of a rational number terminates after a particular/finite number of digits (e.g., 0.25, 0.762 etc.) or begins to repeat/recur the same sequence over and over again (e.g., 0.333..., 0.267267... etc)

Anything other than these two rules, the number is regarded as an irrational number.

The number given is 9.56556555...

The dots indicate thst the numbers after the decimal point conbtinue till eternity.

Observing the numbers after the decimal point for the given number, one can see that 565 repeats once and then the number after the second 565 is 55, indicating that the 565 doesn't recur till infinity.

Since the numbers after the decimal point doesnt contain a finite number of digits and the numbers don't recur till infinity, we can conclude that 9.56556555... isn't a rational number.

Hope this Helps!!!

Hello! Is it possible to get help on this question?

Answers

To determine the graph that corresponds to the given inequality, first, let's write the inequality for y:

[tex]2x\le5y-3[/tex]

Add 3 to both sides of the expression

[tex]\begin{gathered} 2x+3\le5y-3+3 \\ 2x+3\le5y \end{gathered}[/tex]

Divide both sides by 5

[tex]\begin{gathered} \frac{2}{5}x+\frac{3}{5}\le\frac{5}{5}y \\ \frac{2}{5}x+\frac{3}{5}\le y \end{gathered}[/tex]

The inequality is for the values of y greater than or equal to 2/5x+3/5, which means that in the graph the shaded area will be above the line determined by the equation.

Determine two points of the line to graph it:

-The y-intercept is (0,3/5)

- Use x=5 to determine a second point

[tex]\begin{gathered} \frac{2}{5}x+\frac{3}{5}\le y \\ \frac{2}{5}\cdot5+\frac{3}{5}\le y \\ 2+\frac{3}{5}\le y \\ \frac{13}{5}\le y \end{gathered}[/tex]

The second point is (5,13/5)

Plot both points to graph the line. Then shade the area above the line.

The graph that corresponds to the given inequality is the second one.

Put the following equation of a line into slope-intercept form, simplifying all fractions. 3x+9y=63

Answers

Answer: y = 63x - 180

Step-by-step explanation: y = mx + b ------(i)

Step one: y = 9, x = 3

9 = 63 (3) + b

9 = 189 + b

-180 = b

b = -180 

y = 63x - 180

Answer is
y = -1/3x-6

f(x) = log 2(x+3) and g(x) = log 2(3x + 1).(a) Solve f(x) = 4. What point is on the graph of f?(b) Solve g(x) = 4. What point is on the graph of g?(c) Solve f(x) = g(x). Do the graphs off and g intersect? If so, where?(d) Solve (f+g)(x) = 7.(e) Solve (f-g)(x) = 3.

Answers

Given

[tex]\begin{gathered} f(x)=log_2(x+3) \\ and \\ g(x)=log_2(3x+1) \end{gathered}[/tex]

a)

[tex]\begin{gathered} f(x)=4 \\ \Rightarrow log_2(x+3)=4 \\ \Leftrightarrow x+3=2^4 \\ \Rightarrow x+3=16 \\ \Rightarrow x=13 \end{gathered}[/tex]

The answer to part a) is x=13. The point on the graph is (13,4)

b)

[tex]\begin{gathered} g(x)=4 \\ \Rightarrow log_2(3x+1)=4 \\ \Leftrightarrow3x+1=2^4 \\ \Rightarrow3x+1=16 \\ \Rightarrow3x=15 \\ \Rightarrow x=5 \end{gathered}[/tex]

The answer to part b) is x=5, and the point on the graph is (5,4).

c)

[tex]\begin{gathered} f(x)=g(x) \\ \Rightarrow log_2(x+3)=log_2(3x+1) \\ \Rightarrow\frac{ln(x+3)}{ln(2)}=\frac{ln(3x+1)}{ln(2)}] \\ \Rightarrow ln(x+3)=ln(3x+1) \\ \Rightarrow x+3=3x+1 \\ \Rightarrow2x=2 \\ \Rightarrow x=1 \\ and \\ log_2(1+3)=log_2(4)=2 \end{gathered}[/tex]

The answer to part c) is x=1 and graphs intersect at (1,2).

d)

[tex]\begin{gathered} (f+g)(x)=7 \\ \Rightarrow log_2(x+3)+log_2(3x+1)=7 \\ \Rightarrow log_2((x+3)(3x+1))=7 \\ \Leftrightarrow(x+3)(3x+1)=2^7 \\ \Rightarrow3x^2+10x+3=128 \\ \Rightarrow3x^2+10x-125=0 \end{gathered}[/tex]

Solving the quadratic equation using the quadratic formula,

[tex]\begin{gathered} \Rightarrow x=\frac{-10\pm\sqrt{10^2-4*3*-125}}{3*2} \\ \Rightarrow x=-\frac{25}{3},5 \end{gathered}[/tex]

However, notice that if x=-25/3,

[tex]log_2(x+3)=log_2(-\frac{25}{3}+3)=log_2(-\frac{16}{3})\rightarrow\text{ not a real number}[/tex]

Therefore, x=-25/3 is not a valid answer.

The answer to part d) is x=5.

e)

[tex]\begin{gathered} log_2(x+3)-log_2(3x+1)=3 \\ log_2(\frac{x+3}{3x+1})=3 \\ \Leftrightarrow\frac{x+3}{3x+1}=2^3=8 \\ \Rightarrow x+3=24x+8 \\ \Rightarrow23x=-5 \\ \Rightarrow x=-\frac{5}{23} \end{gathered}[/tex]

The answer to part e) is x=-5/23

Khalil has 2 1/2 hours to finish 3 assignments if he divides his time evenly , how many hours can he give to each

Answers

In order to determine the time Khalil can give to each assignment, just divide the total time 2 1/2 between 3 as follow:

Write the mixed number as a fraction:

[tex]2\frac{1}{2}=\frac{4+1}{2}=\frac{5}{2}[/tex]

Next, divide the previous result by 3:

[tex]\frac{\frac{5}{2}}{\frac{3}{1}}=\frac{5\cdot1}{2\cdot3}=\frac{5}{6}[/tex]

Hence, the time Khalil can give to each assignment is 5/6 of an hour.

Let f(x) = 8x^3 - 3x^2Then f(x) has a relative minimum atx=

Answers

[tex]\begin{gathered} \mathrm{Minimum}(\frac{1}{4},\: -\frac{1}{16}) \\ \mathrm{Maximum}(0,\: 0) \\ Inflection\: Point\colon(\frac{1}{8},-\frac{1}{32}) \end{gathered}[/tex]

1) To find the relative maxima of a function, we need to perform the first derivative test. It tells us whether the function has a local maximum, minimum r neither.

[tex]\begin{gathered} f^{\prime}(x)=\frac{d}{dx}\mleft(8x^3-3x^2\mright) \\ f^{\prime}(x)=\frac{d}{dx}\mleft(8x^3\mright)-\frac{d}{dx}\mleft(3x^2\mright) \\ f^{\prime}(x)=24x^2-6x \end{gathered}[/tex]

2) Let's find the points equating the first derivative to zero and solving it for x:

[tex]\begin{gathered} 24x^2-6x=0 \\ x_{}=\frac{-\left(-6\right)\pm\:6}{2\cdot\:24},\Rightarrow x_1=\frac{1}{4},x_2=0 \\ f^{\prime}(x)>0 \\ 24x^2-6x>0 \\ \frac{24x^2}{6}-\frac{6x}{6}>\frac{0}{6} \\ 4x^2-x>0 \\ x\mleft(4x-1\mright)>0 \\ x<0\quad \mathrm{or}\quad \: x>\frac{1}{4} \\ f^{\prime}(x)<0 \\ 24x^2-6x<0 \\ 4x^2-x<0 \\ x\mleft(4x-1\mright)<0 \\ 0Now, we can write out the intervals, and combine them with the domain of this function since it is a polynomial one that has no discontinuities:[tex]\mathrm{Increasing}\colon-\infty\: 3) Finally, we need to plug the x-values we've just found into the original function to get their corresponding y-values:[tex]\begin{gathered} f(x)=8x^3-3x^2 \\ f(0)=8(0)^3-3(0)^2 \\ f(0)=0 \\ \mathrm{Maximum}\mleft(0,0\mright) \\ x=\frac{1}{4} \\ f(\frac{1}{4})=8\mleft(\frac{1}{4}\mright)^3-3\mleft(\frac{1}{4}\mright)^2 \\ \mathrm{Minimum}\mleft(\frac{1}{4},-\frac{1}{16}\mright) \end{gathered}[/tex]

4) Finally, for the inflection points. We need to perform the 2nd derivative test:

[tex]\begin{gathered} f^{\doubleprime}(x)=\frac{d^2}{dx^2}\mleft(8x^3-3x^2\mright) \\ f\: ^{\prime\prime}\mleft(x\mright)=\frac{d}{dx}\mleft(24x^2-6x\mright) \\ f\: ^{\prime\prime}(x)=48x-6 \\ 48x-6=0 \\ 48x=6 \\ x=\frac{6}{48}=\frac{1}{8} \end{gathered}[/tex]

Now, let's plug this x value into the original function to get the y-corresponding value:

[tex]\begin{gathered} f(x)=8x^3-3x^2 \\ f(\frac{1}{8})=8(\frac{1}{8})^3-3(\frac{1}{8})^2 \\ f(\frac{1}{8})=-\frac{1}{32} \\ Inflection\: Point\colon(\frac{1}{8},-\frac{1}{32}) \end{gathered}[/tex]

Macky Pangan invested ₱2,500 at the end of every 3-month period for 5 years, at 8% interest compounded quarterly. How much is Macky’s investment worth after 5 years?

Answers

Compound interest with addition formula:

[tex]A=P(1+\frac{r}{n})^{nt}+\frac{PMT(1+\frac{r}{n})^{nt}-1}{\frac{r}{n}}[/tex]

where,

A = final amount

P = initial principal balance

r = interest rate

n = number of times interest applied per time period

t = number of time periods elapsed

PMT = Regular contributions (additional money added to investment)

in this example

P = 2500

r = 8% = 0.08

n = 4

t = 5 years

PMT = 2500

[tex]A=2500(1+\frac{0.08}{4})^{4\cdot5}+\frac{2500\cdot(1+\frac{0.08}{4})^{4\cdot5}-1}{\frac{0.08}{4}}[/tex]

solving for A:

[tex]A=189408.29[/tex]

Therefore, his investment after 5 years will be

$189,408.29

What is the standard form of the complex number that point A represents?

Answers

Answer

-3 + 4i

Explanation

The standard form for a complex number is given by:

[tex]\begin{gathered} Z=a+bi \\ \text{Where:} \\ a\text{ is the real part,} \\ b\text{ is the imaginary part} \end{gathered}[/tex]

From the graph, the coordinates of A corresponding to the real axis and imaginary axis is traced in blue color in the graph below:

Hence, the standard form of the complex number that a represents is: -3 + 4i

State all integer values of X in the interval that satisfy the following inequality.

Answers

Solve the inequality

-5x - 5 < 8

for all integer values of x in the interval [-4,2]

We solve the inequality

Adding 5:

-5x - 5 +5 < 8 +5

Operating:

-5x < 13

We need to divide by -5, but we must be careful to flip the inequality sign. It must be done when multiplying or dividing by negative values

Dividing by -5 and flipping the sign:

x > -13 / 5

Or, equivalently:

x > -2.6

I am here, I'm correcting the answer. the interval was [-4,2] I misread the question. do you read me now?

Any number greater than -2.6 will solve the inequality, but we must use only those integers in the interval [-4,2]

Those possible integers are -4, -3, -2, -1, 0, 1, 2

The integers that are greater than -2.6 are

-2, -1, 0, 1, 2

This is the answer.

which of the following describes the two spheres A congruentB similarC both congruent and similarD neither congruent nor similar

Answers

The two spheres are similar since they have a proportion of their radius. This proportion is 9/6 (3/2) or 6/9 (2/3).

They are not congruent. They do not have the same radius.

Therefore, the spheres are similar.

Need help with this.. tutors have been a great help

Answers

Given the table in I which represents function I.

x y

0 5

1 10

2 15

3 20

4 25

• Graph II shows Item II which represents the second function.

Let's determine the increasing and decreasing function.

For Item I, we can see that as the values of x increase, the values of y also increase. Since one variable increases as the other increases, the function in item I is increasing.

For the graph which shows item II, as the values of x increase, the values of y decrease, Since one variable decreases as the other variable decreases, the function in item I is decreasing.

Therefore, the function in item I is increasing, and the function in item II is decreasing.

ANSWER:

A. The function in item I is increasing, and the function in item II is decreasing.

Instructions: Factor 2x2 + 252 + 50. Rewrite the trinomial with the c-term expanded, using the two factors. Answer: 24 50

Answers

Given the polynomial:

[tex]undefined[/tex]

Miscavage Corporation has two divisions: the Beta Division and the Alpha Division.

The Beta Division has:

sales of $320,000,
variable expenses of $158,100,
and traceable fixed expenses of $72,300.
The Alpha Division has:

sales of $630,000,
variable expenses of $343,800,
and traceable fixed expenses of $135,100.
The total amount of common fixed expenses not traceable to the individual divisions is $137,200.

What is the total company's net operating income?

Answers

The total net operating income (NOI) of both divisions is $1,03,500.

What is net operating income?Real estate professionals use the formula known as Net Operating Income, or NOI, to quickly determine the profitability of a specific investment. After deducting required operating costs, NOI calculates the revenue and profitability of investment real estate property. Let's say, for illustration purposes, that you own a duplex with a gross monthly income of $2,000 and monthly operating expenses of $400. You would start with your annual gross income ($24,000) and deduct your operating expenses ($4,800) to arrive at your net operating income.

So, the total net operating income:

The formula for net operating income: NOI = Gross Income - Operating Expenses

Now, substitute the values and get the NOI as follows:

NOI = Gross Income - Operating ExpensesNOI = (Sales+Sales) - [(variable expenses + variable expenses) + (fixed expenses + fixed expenses) + 137,200] NOI = (320,000+630,000) - [(158,100 + 343,800) + (72,300 + 135,100) + 137,200]NOI = 9,50,000 - (5,01,900 + 2,07,400 + 137,200)NOI = 9,50,000 - 8,46,500NOI = 1,03,500

Therefore, the total net operating income (NOI) of both divisions is $1,03,500.

Know more about net operating income here:

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