Find the mean, median, mode, and range of the following list.
35, 16, 28, 4, 62, 15, 48, 22, 16, 28
Mean
Median
Mode
Range

Answer: D = 3c-5

Step-by-step explanation:

The first shape shows the input, C, the second one multiplies it by 3, next, it subtracts C by 5, leaving you with D equaling C times three, minus five.
You can simplify this equation into this:

D=3C (multiplied by 3)

Then subtract by 5
D=3C-5

The two triangles in the following diagram are congruent. The proofs are mentioned below.

SSS (Side-Side-Side)

If all the three sides of one triangle are equivalent to the corresponding three sides of the second triangle, then the two triangles are said to be congruent by SSS rule.

SAS (Side-Angle-Side)

If any two sides and the angle included between the sides of one triangle are equivalent to the corresponding two sides and the angle between the sides of the second triangle, then the two triangles are said to be congruent by SAS rule.

ASA (Angle-Side- Angle)

If any two angles and the side included between the angles of one triangle are equivalent to the corresponding two angles and side included between the angles of the second triangle, then the two triangles are said to be congruent by ASA rule.

AAS (Angle-Angle-Side) [Application of ASA]

AAS stands for Angle-Angle-Side. When two angles and a non-included side of a triangle are equal to the corresponding angles and sides of another triangle, then the triangles are said to be congruent.

AAS congruence can be proved in easy steps.

RHS (Right angle- Hypotenuse-Side)

If the hypotenuse and a side of a right- angled triangle is equivalent to the hypotenuse and a side of the second right- angled triangle, then the two right triangles are said to be congruent by RHS rule.

Hence, the two triangles in the following diagram are congruent.

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the interval where both F(x) and g(x) are increasing is x < 0, which can be represented on the number line as follows:

To find the interval where both functions F(x) and g(x) are increasing, we need to determine where the derivative of each function is positive. A function is increasing when its derivative is positive, which means that the function is becoming larger as x increases.

The derivative of F(x) can be found by applying the derivative rules for absolute value and addition, which gives us:

F'(x) = 3x/|x|

Now, we need to determine where F'(x) is positive. This occurs when either 3x is positive and |x| is positive, or when 3x is negative and |x| is negative. Therefore, F'(x) is positive for x > 0 and x < 0.

Next, we need to find the derivative of g(x) by applying the derivative rules for subtraction and multiplication, which gives us:

g'(x) = -1 + 8

Simplifying the expression, we get:

g'(x) = 7

Since g'(x) is a constant, it is always positive, which means that g(x) is increasing for all values of x.

To find the interval where both F(x) and g(x) are increasing, we need to identify where both F'(x) and g'(x) are positive. This occurs when x < 0, as this satisfies the condition for F'(x) being positive, and g'(x) is always positive.

Therefore, the interval where both F(x) and g(x) are increasing is x < 0, which can be represented on the number line as follows:

     <=====o------------------------>

         x<0                    x>0

In this interval, both functions are increasing as x becomes more negative.

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z = 110°

mEB = 90°

mCE = 74°
I’m not sure about x or y but I think these are right.

The Perimeter of the parallelogram whose vertices are given by the coordinates (3 ,6), (-5, 6), (6, -1), (-2, -1) is: 16 + 2√(58)

To find the perimeter of the parallelogram, we need to find the distance between each pair of adjacent vertices and add them up.

First, let's find the distance between (3, 6) and (-5, 6). This is simply the difference between their x-coordinates, which is 3 - (-5) = 8.

Next, let's find the distance between (-5, 6) and (-2, -1). To do this, we need to find the difference between their x-coordinates and their y-coordinates, and then use the Pythagorean theorem. The difference in x-coordinates is -5 - (-2) = -3, and the difference in y-coordinates is 6 - (-1) = 7. So the distance between these two points is √((-3)^2 + 7^2) = √(58).

We can use the same method to find the distance between (6, -1) and (3, 6), which is also √(58).

Finally, we need to find the distance between (6, -1) and (-2, -1), which is simply the difference between their x-coordinates, which is 6 - (-2) = 8.

Adding up all these distances, we get 8 + √(58) + √(58) + 8 = 16 + 2√(58).

So the exact perimeter of the parallelogram is 16 + 2√(58)

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If a research company claims that more than 55% of americans regularly watch public access television, the test statistic for the population proportion is 1.61.

To calculate the test statistic for the population proportion, we first need to set up the null and alternative hypotheses. Let p be the true proportion of Americans who regularly watch public access television.

H0: p ≤ 0.55 (null hypothesis)

Ha: p > 0.55 (alternative hypothesis)

We use a one-tailed test with α = 0.05 level of significance.

Next, we calculate the sample proportion:

p' = 255/425 = 0.60

Then, we calculate the standard error of the proportion:

SE = √(p'(1-p')/n) = √(0.60*0.40/425) ≈ 0.031

Finally, we calculate the test statistic:

z = (p' - p0)/SE = (0.60 - 0.55)/0.031 ≈ 1.61

where p0 is the value of the proportion under the null hypothesis.

The test statistic is approximately 1.61. To determine whether this value provides evidence to reject the null hypothesis, we compare it to the critical value of the z-distribution at α = 0.05 level of significance.

For a one-tailed test with a significance level of 0.05, the critical value is 1.645. Since our test statistic is less than the critical value, we fail to reject the null hypothesis.

Therefore, we do not have sufficient evidence to support the claim that more than 55% of Americans regularly watch public access television.

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Photosynthesis is maximum in red light because chlorophyll, the primary pigment responsible for capturing light energy in plants, absorbs red light most efficiently.

What is red light in Photosynthesis?

Red light is a part of the electromagnetic spectrum with a longer wavelength and lower energy than blue and green light.

Red light is particularly effective for photosynthesis because it has a longer wavelength and lower energy, which allows chlorophyll to efficiently absorb it and use it for the photosynthetic process.

In photosynthesis, plants use light energy to synthesize glucose from carbon dioxide and water.

As a result, photosynthesis is maximum in red light because plants can absorb and utilize this light energy most efficiently for their growth and energy production.

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[tex]\sqrt[n]{z}=\sqrt[n]{r}\left[ \cos\left( \cfrac{\theta+2\pi k}{n} \right) +i\sin\left( \cfrac{\theta+2\pi k}{n} \right)\right]\quad \begin{array}{llll} k\ roots\\ 0,1,2,3,... \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \boxed{k=0}\hspace{5em} \sqrt[ 3 ]{64} \left[ \cos\left( \cfrac{ 219^o + 360^o( 0 )}{3} \right) +i \sin\left( \cfrac{ 219^o + 360^o( 0 )}{3} \right)\right][/tex]

[tex]\sqrt[ 3 ]{64} \left[ \cos\left( \cfrac{ 219^o }{3} \right) +i \sin\left( \cfrac{ 219^o }{3} \right)\right]\implies \boxed{4[\cos(73^o)+i\sin(73^o)]} \\\\[-0.35em] ~\dotfill\\\\ \boxed{k=1}\hspace{5em} \sqrt[ 3 ]{64} \left[ \cos\left( \cfrac{ 219^o + 360^o( 1 )}{3} \right) +i \sin\left( \cfrac{ 219^o + 360^o( 1 )}{3} \right)\right][/tex]

[tex]\sqrt[ 3 ]{64} \left[ \cos\left( \cfrac{ 579^o }{3} \right) +i \sin\left( \cfrac{ 579^o }{3} \right)\right]\implies \boxed{4[\cos(193^o)+i\sin(193^o)]} \\\\[-0.35em] ~\dotfill\\\\ \boxed{k=2}\hspace{5em} \sqrt[ 3 ]{64} \left[ \cos\left( \cfrac{ 219^o + 360^o( 2 )}{3} \right) +i \sin\left( \cfrac{ 219^o + 360^o( 2 )}{3} \right)\right] \\\\\\ \sqrt[ 3 ]{64} \left[ \cos\left( \cfrac{ 939^o }{3} \right) +i \sin\left( \cfrac{ 939^o }{3} \right)\right]\implies \boxed{4[\cos(313^o)+i\sin(313^o)]}[/tex]

Yes, this relation is a function and here the domain and range are:

domain = {3,6,2,-7} and range ={0,-2,-1,0}

Domain and Range:

The domain and scope of a function are part of the function. The domain is the set of all input values ​​of a function, and the range is the possible outputs given by the function. Field → Function → Sequence. If there is a function f : A → B such that each element of set A corresponds to an element of set B, then A is the field and B is the codomain. The graph of an element "a" under a relation R is given by "b", where (a,b) ∈ R.

The scope of the function is the set of images. The domain and range of a function are usually expressed as:

Domain(f) = {x ∈ R: State} and range(f)={f(x): x ∈ domain(f)}

According to the Question:

The given function is:

{(3,0),(6,-2),(2,-1),(-7,0)}

It is a function as every input has a single output.

So, 3,6,2,-7 are the elements of the domain of the given relation.

Here domain = {3,6,2,-7} and range ={0,-2,-1,0}

Therefore, this relation is a function.

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the decay constant for this material is approximately 0.0445.when t = 8 years, the amount of the material remaining is 550 grams.

The formula for radioactive decay is given by:

a = [tex]e^(-kt)\\[/tex] * A

where a is the final amount,A is the initial amount, t is the time in years, and k is the decay constant.

We can use the given information to solve for k as follows:

When t = 0, a = A. So, we have:

A = [tex]e^(0 * k)[/tex] * A

Simplifying this gives:

1 = e^0

Therefore, we can see that k = 0 at the start of the decay process.

Now, when t = 8 years, the amount of the material remaining is 550 grams. Therefore, we have:

550 = [tex]e^(-8k)[/tex] * 700

Dividing both sides by 700 and taking the natural logarithm of both sides, we get:

ln(550/700) = -8k

Simplifying this gives:

k = ln(700/550)/8

Using a calculator, we can evaluate this expression to get:

k ≈ 0.0445

Therefore, the decay constant for this material is approximately 0.0445.

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Answer:

a. The triangular prism has 5 faces, 9 vertices, and 12 edges.

b. To find the volume of the packaging, we need to multiply the area of the base (an equilateral triangle) by the height of the prism.

The area of an equilateral triangle with side length 3.6 cm is given by:

$A = \frac{\sqrt{3}}{4} s^2 = \frac{\sqrt{3}}{4}(3.6\text{ cm})^2 \approx 5.270\text{ cm}^2$

So, the volume of the Toblerone packaging is:

$V = Ah = (5.270\text{ cm}^2)(21\text{ cm}) \approx 110.59\text{ cm}^3$

Therefore, the volume of the Toblerone packaging is approximately 110.59 cubic centimeters.

Answer:

Y = 4x

Step-by-step explanation:

In this equation, x represents the input value, and Y represents the output value. Coefficient 4 illustrates the rate of change or slope of the function, indicating that for every unit increase in x, the value of Y increases by four units. When x is 0, Y is also 0, consistent with the given data. Similarly, when x is 1, 2, and 3, Y is 4, 8, and 12, respectively, matching the provided output values.

Answer: the team amassed 88i points total, by shooting t two-point baskets and u 1-point free throws.

t+u = 53

total is:  2t + u = 88.

Step-by-step explanation:

hope i makes sense

The probability that the taxi at fault was blue given an eyewitness said it was is approximately 0.436.

To find the probability that the taxi at fault was blue given an eyewitness said it was, we can use Bayes' theorem. Bayes' theorem is expressed as: P(A|B) = (P(B|A) * P(A)) / P(B)

Where:
- P(A|B) is the probability of A given B (the probability the taxi is blue given the eyewitness said it was blue)
- P(B|A) is the probability of B given A (the probability the eyewitness said the taxi was blue given it was actually blue)
- P(A) is the probability of A (the probability the taxi is blue)
- P(B) is the probability of B (the probability the eyewitness said the taxi was blue)

First, let's define our events:
- A: The taxi is blue (Blue Cab), with a probability of 12% (0.12)
- B: The eyewitness said the taxi was blue

Now, we need to find P(B|A) and P(B).

1. P(B|A) = 0.85 (the probability the eyewitness correctly identifies the blue taxi)
2. P(B) can be found using the law of total probability: P(B) = P(B|A) * P(A) + P(B|A') * P(A')
  - A': The taxi is not blue (Green Cab), with a probability of 88% (0.88)
  - P(B|A') = 1 - 0.85 = 0.15 (the probability the eyewitness incorrectly identifies the green taxi as blue)

So, P(B) = 0.85 * 0.12 + 0.15 * 0.88 = 0.102 + 0.132 = 0.234

Now, we can apply Bayes' theorem:

P(A|B) = (P(B|A) * P(A)) / P(B)
P(A|B) = (0.85 * 0.12) / 0.234
P(A|B) ≈ 0.4359

Rounded to three decimal places, the probability that the taxi at fault was blue given an eyewitness said it was is approximately 0.436 or 436/1000 as a reduced fraction.

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When the polynomial p(x)=-x^5-2x^3+4x-3, then the value of p(-1) is 3

The Remainder Theorem is a fundamental concept in algebra that relates the value of a polynomial at a certain point to the remainder of the polynomial's division by a linear factor.

The remainder theorem states that when a polynomial p(x) is divided by (x - a), the remainder is equal to p(a).

In this case, we are asked to find p(-1) when p(x) = -x^5 - 2x^3 + 4x - 3.

To use the remainder theorem, we need to divide p(x) by (x - (-1)), which is the same as (x + 1).

We can perform polynomial long division to find the quotient and remainder

The remainder is -x + 2, which means that p(-1) = -(-1) + 2 = 3.

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To maintain an average of 79, Aldo must obtain a score of 82 in his upcoming exam.

To get the solution, let's calculate the total of the first five scores.

Total of the first five scores = 77 + 88 + 77 + 87 + 63 = 392

Now we know that there are a total of six scores, so to get the mean, we will divide the total by six.

Mean = Total/Number of ScoresTherefore, 79 = 392 + x/6

We need to find the value of x that will satisfy the above equation.

Now we will solve for x.79 = 392 + x/6

(Multiply both sides by 6) 6 * 79 = 6 * 392 + x6 * 79 = 2352 + xx = 6 * 79 - 392x = 474 - 392x = 82

Therefore, Aldo needs to score 82 on his next test to achieve an average of 79.


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To get an output of 5 from a function, the second point must be at a distance of 5 units above the x-axis.

The function represents the relationship between the inputs and the outputs. The function's domain is the set of all possible input values, while the range is the set of all possible output values. The function's graph is the set of all ordered pairs (x, y), where x is the input and y is the output.To get an output of 5 from the function, the second point must be at a distance of 5 units above the x-axis. This implies that the y-value of the second point is 5. The x-value of the second point is arbitrary, and it can be any value. The point (0,5) is an example of a point that is 5 units above the x-axis.

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a. The account balance is $1000 when opened.

b. $1,060 is the balance after 1 year.

c. 42.98 years as per compound interest.

Compound interest is a type of interest that is calculated not only on the principal amount of a loan or investment but also on the accumulated interest from previous periods. This means that interest is added to the principal amount, and the new total becomes the basis for calculating interest in the next period.

In the given question,

a. When the account is opened, t = 0. Therefore, the balance is:

1 × e(0.06 × 0) = 1 × e⁰ = 1

The account balance is $1,000 when it is opened.

b. After 1 year, t = 1. Therefore, the balance is:

1 × e(0.06 × 1) ≈ 1.06

The account balance is approximately $1,060 after 1 year.

c. After 2 years, t = 2. Therefore, the balance is:

1 × e(0.06 × 2) ≈ 1.123

The account balance is approximately $1,123 after 2 years.

Diego's statement is not accurate. The expression In 5 represents the natural logarithm of 5, which is approximately 1.609. It does not represent the time, in years, when the account will have 5 thousand dollars.

To find the time when the account will have a balance of $5,000, we need to solve the equation:

1 × e(0.06t) = 5

Dividing both sides by 1:

e(0.06t) = 5

Taking the natural logarithm of both sides:

ln(e(0.06t)) = ln(5)

0.06t = ln(5)

t = ln(5) / 0.06 ≈ 11.55

Therefore, the account will have a balance of $5,000 after approximately 11.55 years.

We can use the same equation as in part 2 to find out if the account balance will reach $1,000,000. We need to solve the equation:

1 × e(0.06t) = 1000

Dividing both sides by 1:

e(0.06t) = 1000

Taking the natural logarithm of both sides:

ln(e(0.06t)) = ln(1000)

0.06t = ln(1000)

t = ln(1000) / 0.06 ≈ 42.98

Therefore, the account balance will reach $1,000,000 after approximately 42.98 years.

Whether or not this will make you a millionaire by the time you reach retirement depends on when you plan to retire and how much money you need for retirement. If you plan to retire in less than 43 years or you need more than $1,000,000 for retirement, then this account alone will not make you a millionaire.

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Answer:

no

Step-by-step explanation:

using Pythagorean theorem:

[tex]26^{2} +42^{2}=50^{2}[/tex]

676+1764=2500

2440=2500

2440<2500

Answer:no

Answer: 32

Step-by-step explanation:

Answer:

Step-by-step explanation:

2 is the base and 5 is the exponent, so we have to multiply 2 5 times.

2*2*2*2*2=32

The equation that shows how the amount of money Dalton gets in a week, y, depends on the number of times he walks the dog, x is y = 5 + x

Given that

Weekly allowance = $5

Amount earned for walking the dog = $1

The above means that

Total money = Weekly allowance  + Amount earned for walking the dog  * Number of times

So, we have

y = 5 + 1 * x

Evaluate

y = 5 + x

Hence, the equation is y = 5 + x

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Answer:

The lowest common multiple 3 and 4 is 12.

Step-by-step explanation:

The total multiples of both 3 and 4 between 1 - 100 are 100/12 = 8 4/12 i.e. 8.

answer - y = -5x + 1

The point that partitions segment AB in a 1:4 ratio is [tex]P = \left(-1, -\frac{2}{5}\right)$[/tex].

To find the point that partitions segment AB in a 1:4 ratio, we can use the section formula.

Let P = (x, y) be the point that partitions segment AB in a 1:4 ratio, where AP:PB = 1:4. Then, we have:

[tex]$\frac{AP}{AB} = \frac{1}{1+4} = \frac{1}{5}$$[/tex]

and

[tex]$\frac{PB}{AB} = \frac{4}{1+4} = \frac{4}{5}$$[/tex]

Using the distance formula, we can find the lengths of AP, PB, and AB:

[tex]AP &= \sqrt{(x+3)^2 + (y-2)^2} \\PB &= \sqrt{(x-7)^2 + (y+10)^2} \\\ AB &= \sqrt{(7+3)^2 + (-10-2)^2} = \sqrt{244}[/tex]

Substituting these into the section formula, we have:

[tex]$\begin{aligned}x &= \frac{4\cdot(-3) + 1\cdot(7)}{1+4} = -1 \ y &= \frac{4\cdot2 + 1\cdot(-10)}{1+4} = -\frac{2}{5}\end{aligned}$$[/tex]

Therefore, the point that partitions segment AB in a 1:4 ratio is [tex]P = \left(-1, -\frac{2}{5}\right)$[/tex].

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To the nearest tenth, the length of each side of the equilateral triangle is roughly [tex]10(\sqrt{(3) - 1)[/tex].

An equilateral triangle has the following three characteristics: identical lengths on all three sides. The three angles are identical. Three symmetry lines may be seen in the figure.

All of the triangle's sides are equal in length since it is equilateral. Call this length "s" for short.

The distance from vertex A to side x, measured in altitude, is equal to the length of side x. Call the intersection of the altitude and side x "P" for short.

The length of AP is [tex](s/2) * \sqrt{}[/tex] because we know that the altitude from vertex A creates a triangle with sides of 30-60-90. (3).

Since side BP is half the length of side AB, we also know that its length is (s/2).

As a result, x's length equals the product of AP and BP:

x = AP + BP

= (s/2) * [tex]\sqrt{(3) + (s/2)[/tex]

= [tex](s/2)(\sqrt{(3) + 1)[/tex]

We are told that x equals 10. We may put the formula we discovered for x equal to 10 and do the following calculation to find s:

[tex](s/2)(\sqrt{(3) + 1)[/tex] = 10

The result of multiplying both sides by two is:

[tex]s(\sqrt{(3) + 1) = 20[/tex]

When you divide both sides by [tex](\sqrt{(3) + 1)[/tex], you get:

[tex]s = 20/(\sqrt{3) + 1)[/tex]

The result of multiplying the numerator and denominator by the conjugate of [tex](\sqrt{(3) + 1), (\sqrt{(3) - 1)[/tex], is as follows:

s = [tex]20(\sqrt{3) - 1)/(3 - 1)[/tex]

= [tex]10(\sqrt{(3) - 1[/tex]

As a result, to the nearest tenth, the length of each side of the equilateral triangle is about [tex]10(\sqrt{(3) - 1[/tex].

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The probability of drawing an ace and a queen from a pack of cards without replacement is 1/78. This can be explained as follows:

In a standard pack of 52 cards, there are 4 aces and 4 queens. When two cards are drawn without replacement, the probability of drawing an ace and then a queen is 4/52 x 3/51 = 12/2652. This can be simplified to 1/78.

Without replacement means that the card that is drawn is not replaced in the deck before the next card is drawn. In this case, when the first card is an ace, there are only 3 queens left in the deck so the probability of the second card being a queen is 3/51.

To put it another way, the chances of drawing an ace and a queen when the cards are drawn without replacement can be thought of as a ratio of the favorable outcomes to the total number of possible outcomes. There is only one favorable outcome (ace-queen) out of a total of 78 possible outcomes (4 aces and 4 queens combined with the remaining 44 cards). Thus, the probability of drawing an ace and a queen is 1/78.

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