Given: The angle
[tex]123^0[/tex]To Determine: The supplement of the given angle
Solution
Please note that two angle are supplement if they are add up to 180⁰
So if the supplement is x. Therefore
[tex]\begin{gathered} x+123^0=180^0 \\ x=180^0-123^0 \\ x=57^0 \end{gathered}[/tex]Hence, the supplement of 123⁰ is 57⁰, OPTION C
A restaurant uses four pounds of potatoes for a party of 12 people They are cooking potatoes for a party of 60 people what should I do
3. Arrange the like terms in columns and add them. - a) 2x³ - 7x⁴ + 7x⁵ and 11x³ - 4x⁴ – x b) -2p - 3p² and 1 - 5p + 8p²
The required solution of the expressions is (a) 7x⁵ + 13³ - 11x⁴ - x, (b) 5p² - 7p + 1.
Given that,
To arrange the like terms in columns and add them. - a) 2x³ - 7x⁴ + 7x⁵ and 11x³ - 4x⁴ – x b) -2p - 3p² and 1 - 5p + 8p².
The algebraic expression consists of constant and variable. eg x, y, z, etc.
Here,
(a)
= 2x³ - 7x⁴ + 7x⁵ + 11x³ - 4x⁴ – x
= 7x⁵ - 7x⁴ - 4x⁴+ 2x³ + 11x³– x
= 7x⁵ + 13³ - 11x⁴ - x,
(b)
= -2p - 3p² + 1 - 5p + 8p²
= 1 -2p - 5p -3p² + 8p²
= 1 - 5p + 8p²
Thus, the required solution of the expressions is (a) 7x⁵ + 13³ - 11x⁴ - x, (b) 5p² - 7p + 1.
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The required solutions to the given polynomials are 13x³- 11x⁴+ 7x⁵ – x and - 7p + 5p²+ 1.
What is a polynomial?A polynomial is defined as a mathematical expression that has a minimum of two terms containing variables or numbers.
The polynomials are given in the question :
2x³ - 7x⁴ + 7x⁵, and 11x³ - 4x⁴ – x
-2p - 3p² and,1 - 5p + 8p²
According to the question,
⇒ 2x³ - 7x⁴ + 7x⁵ + 11x³ - 4x⁴ – x
Rearrange the terms and apply the arithmetic operation,
⇒ 2x³ + 11x³- 7x⁴- 4x⁴ + 7x⁵ – x
⇒ 13x³- 11x⁴+ 7x⁵ – x
⇒ -2p - 3p² + 1 - 5p + 8p²
Rearrange the terms and apply the arithmetic operation,
⇒ -2p - 5p - 3p² + 8p²+ 1
⇒ - 7p + 5p²+ 1
Thus, the required solutions to the given polynomials are 13x³- 11x⁴+ 7x⁵ – x and - 7p + 5p²+ 1.
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a bike that goes from 6m/s to 16m/s in 20 seconds.
The initial velocity = vi = 6m/s
The final velocity = vf = 16 m/s
The total time = t = 20 seconds
The rate of change in velocity is called acceleration (a) that can be written as:
[tex]a\text{ = }\frac{Change\text{ in velocity}}{time}[/tex]
or
[tex]a\text{ = }\frac{vf-vi}{t}[/tex]Put the values in the equation to get the value of 'a'.
[tex]a\text{ = }\frac{16\text{ - 6}}{20}[/tex][tex]a\text{ = }\frac{10}{20}[/tex]or
[tex]a\text{ = }\frac{1}{2}[/tex]hence, the value of a is 1/2.
What’s the answer plsss
Answer:
8.5 cm
Step-by-step explanation:
See attached worksheet.
Opposite 63 is ML (we are not after that)
Adjacent is MN
Hypotenuse is 18.8
Choose adjacent + Hypotenuse to find MN
AH - CAH, cos
Cos63 = A/18.8
x18. 8
18.8 x Cos63 = A
8.535.... = A
So, MN = 8.5cm
Ans: C
Hope this helps!
how many bit strings of length five either start with two zeros or end with two zeros? how many bit strings of length six either do not start with two zeros or do not end with two zeros? how many bit strings of length seven either start with four ones or end with four ones? how many bit strings of length eight do not start with a one or do not end with a one?
16 bit strings of length five either start with two zeros or end with two zeros are there; 32 bit strings of length six either do not start with two zeros or do not end with two zeros are there; 16 bit strings of length seven either start with four ones or end with four ones are there and 256
bit strings of length eight do not start with a one or do not end with a one are there.
A string is a combination which is made up of only two characters, either 1 or 0.
So, the combinations of the string can be found,
If the length of the bit string is 5, it means it will have 5 characters.
If this string either start with two zeroes or end with two zeroes. It mean there are only three positions are remaining which have two choices available for each place.
So, the total bit strings possible are,
= 2×(1×1×2×2×2)
= 16
16 such bit strings are possible.
If the length of the bit string is 6, it means it will have 6 characters.
If this string either do not start with two zeroes or do not end with two zeroes. It mean there are only four positions are remaining which have two choices available for each place.
So, the total bit strings possible are,
= 2×(1×1×2×2×2×2)
= 32
So, 32 such strings are possible.
Now, If the length of the bit string is 7, it means it will have 7 characters.
If this string either start with four ones or end with four ones. It mean there are only three positions are remaining which have two choices available for each place.
So, the total bit strings possible are,
= 2×(1×1×1×1×2×2×2)
= 16
So, 16 such strings are possible.
If the length of the bit string is 8, it means it will have 8 characters.
If this string either do not start with one and do not end with one. It mean there are only seven positions are remaining which have two choices available for each place.
So, the total bit strings possible are,
= 2×(1×2×2×2×2×2×2×2)
= 256
So, 256 such strings are possible.
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The width of a classroom is 4m less than the length.its area is 45m raised to power of two .find the dimensions of the class room
Length =9 , second-order polynomial equation in a single variable. a 0. It has at least one solution because it is a second-order polynomial equation, which is guaranteed by the algebraic fundamental theorem.
What is quadratic equation?x ax2 + bx + c = 0 is a quadratic equation, which is a second-order polynomial equation in a single variable. a 0. It has at least one solution because it is a second-order polynomial equation, which is guaranteed by the algebraic fundamental theorem. The answer could be simple or complicated.
L= 4 + W
Area is 45, so
L times W = 45
substituting the value of L, we get (4+W)*W=45, after simplifying this we get
4W+W2=45
W2+4W-45=0, this is a quadratic equation and after solving this we get the factors 9 and -5
( W+9) and (W-5) = 0
we get W=-9 or W=5, since width cannot be negative, so width = 5
substituting the value of W=5 in L = 4 +5, we get length = 9
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Second-order polynomial equation in one variable, length = 9. a 0. Since it is a second-order polynomial equation, which is ensured by the algebraic fundamental theorem, it must have at least one solution.
What is quadratic equation?A quadratic equation, or second-order polynomial equation with a single variable, is x ax2 + bx + c = 0. a 0. Since it is a second-order polynomial equation, which is ensured by the algebraic fundamental theorem, it must have at least one solution. The solution might be straightforward or difficult.
L= 4 + W
Since the area is 45, L times W = 45. Substituting the value of L, we get (4+W)*W=45. Simplifying this, we get 4W+W2=45. W2+4W-45. = 0. This is a quadratic equation, and after solving it, we get the factors 9 and -5. Since width cannot be negative, we get W=-9 or W=5. Substituting the value of W=5 in L = 4 + 5,
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(c) Which is more unusual - an actress who receives an Oscar at 22 or an actor who
receives an Oscar at 55? Explain you answer using the percentages you calculated in
parts (a) and (b).
(d) Which is more unusual an actress who receives an Oscar at 55 or an actor who
receives an Oscar at 55? Calculate the standard score for the 55 year old actress.
Calculate the standard score for the 55 year old actor. Then answer the question and
explain your answer.
Trenton’s scouting group made 100 T-shirts for a charity fundraiser. The circle graph below compares how many of each different-colored T-shirt they made.
If the angle measure of the section for purple is 54°, how many purple T-shirts did Trenton’s scouting group make?
(Get it right, I will give you brainliest, thanks and 5* rating)
Trenton’s scouting group make 15 purple T-shirts.
How to find how much percent 'a' is of 'b'?Suppose a number is 'a'. Suppose another number is 'b'. We want to know how much percent of 'b' is 'a'. Then, it is calculated as:
[tex]\dfrac{a}{b} \times 100[/tex]
We have been given that Trenton’s scouting group made 100 T-shirts for a charity fundraiser.
Also the angle measure of the section for purple is 54°, then;
54 / 360 = percent /100
percent = 15
Therefore, 15 percent of 100 T shirt would be;
15/100 x 100
15
Hence, Trenton’s scouting group make 15 purple T-shirts.
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PLEASE HELP! this is probably easy, THANK YOU!
Answer:
The percent change in attendance from the 2014 to 2015 school year is a 11.5385% decrease, or 12% when rounded.
Make sure to mark as Brainliest if this is correct so others know that this is the correct answer.
Answer:
r u cheating or just need "HELP"
Step-by-step explanation:
3. Your boss asks you to compare three phone plans. Identify the cheapest plan when an average of 190 text messages are sent each month. • Plan A costs a basic fee of $29.95 per month and 13 cents per text message • Plan B costs a basic fee of $53.00 per month and has unlimited text messages. • Plan C has no basic fee, but charges $0.28 per text message. 2021 Illuminate Education. Inc
Analyze each plan according to the given specifications.
Plan A:
The basic fee must be added to the product of 0.13 and the average messages sent.
[tex]29.95+190\cdot0.13=54.65[/tex]Plan B:
It already includes the cost for unlimited messages.
[tex]53.00[/tex]Plan C:
The plan costs the product of 0.28 and the average messages sent.
[tex]190\cdot0.28=53.2[/tex]When comparing these plans, the cheapest one is Plan B, which only costs $53.00.
complete the two-column proof.
pleasee
∠2 ≅ ∠4 and m∠2 = 110°, and proved m<3 = 70⁰.
The answers of the blank lines are:
A . Vertically opposite angle.
B . Linear angle .
C . Hence proved .
Solution:Given ,
∠2 ≅ ∠4 and m∠2 = 110°.
We have to prove
m<3 = 70⁰
Here ,
m<2 = m<4 => They are vertically opposite angles.
And here ,
m<3 and m<4 are supplementary angles.
m∠3 + m∠4 = 180° => linear angle .
m<4 = 110⁰ => since m<2 = m<4
By substituting m∠4 we get,
m∠3 + m∠4 = 180°
= m∠3 + 110 = 180
= 180 - 110
m∠3 = 70°
Hence proved.
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how to find n(A-B)
q no 9 ii
sure branliest
Answer: 11
Step-by-step explanation:
[tex]A-B=\{2\}[/tex].
Since there is 1 element in this set, the answer is 1.
Evaluate log2 10 using the change of base formula. Round your answer to the nearest thousandth.
Take into account the following property:
[tex]\log _ab=\frac{\log b}{\log a}[/tex]Then, for the given expression you have:
[tex]\log _210=\frac{\log10}{\log2}=\frac{1}{\log }\approx3.322[/tex]Hence, the answer is approximately 3.322
Draw and label a figure that shows line z intersecting plane R at point M.
A figure that shows line z intersecting plane R at point M could be like:
The plane is black, the line is red and the point is blue.
Solve the equation b over 27 equals negative 3 for b.
81
9
−9
−81
Solve the equation 42 = v + 35 for v.
−77
77
−7
7
Solve the equation −128 = 4x for x.
−124
132
−32
32
The solution of the equation is as follows;
b = -81v = 7x = -32How to solve equations?An equation is a mathematical statement that is made up of two expressions connected by an equal sign.
In other words, an equation is a formula that expresses the equality of two expressions, by connecting them with the equals sign =.
The expression can be solved as follows:
b / 27 = - 3
cross multiply
b = -3 × 27
b = - 81
42 = v + 35
subtract 35 from both sides of the equations.
42 - 35 = v + 35 - 35
v = 42 - 35
v = 7
- 128 = 4x
divide both sides of the equations by 4
4x / 4 = - 128 / 4
x = - 32
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Answer:
b = -81v = 7 x = -32Step-by-step explanation:
1) b/27 = -3, then b = ?
→ b/27 = -3
→ b = -3 × 27
→ [ b = -81 ]
Thus, value of b is -81.
2) 42 = v + 35, then v = ?
→ v + 35 = 42
→ v = 42 - 35
→ [ v = 7 ]
Thus, value of v is 7.
3) -128 = 4x, then x = ?
→ 4x = -128
→ x = -128/4
→ [ x = -32 ]
Thus, value of x is -32.
I need help with the question above. I took a pic.
Answer:
[tex]S=\frac{12}{5}[/tex]Step-by-step explanation:
The common ratio of the following sequence is:
[tex]\frac{\frac{9}{16}}{\frac{3}{2}}=\frac{3}{8}[/tex]If the common ratio is less than 1 or greater than -1 but not 0, we can use the following expression to determine the sum of the infinite geometric series:
[tex]S=\frac{a_1}{1-r}[/tex]Therefore, if we have a common ratio of 3/8 or 0.375 and the first term of the series is 3/2.
The sum would be:
[tex]\begin{gathered} S=\frac{\frac{3}{2}}{1-\frac{3}{8}} \\ S=\frac{\frac{3}{2}}{\frac{5}{8}} \\ S=\frac{24}{10}=\frac{12}{5} \end{gathered}[/tex]Which system of linear inequalities is represented by the graph? O y=x-2 and x-2y 4 O y=x + 2 and x + 2y = 4 O y=x-2 and x + 2y = 4 O y =x-2 and x + 2y =-4
The two inequalities are (option c) y > x - 2 and2y + x < 4
Given,
Let's start by locating the red-hued area.
If the shadow is visible to be over the line, then the situation will be as follows:
y > ax + b
Hence the equation for the line is ax + b.
The slope is a, and the y-intercept is b.
The line in the graph intersects the y-axis at y = -2, which results in:
b = -2
Two points on the line are required to determine the slope; these points are (0, -2), and (2, 0)
We are aware of the slope for a line passing through the points (x1, y1) and (x2, y2) as follows:
a = (y2 - y1)/(x2 - x1) (x2 - x1)
The slope for this line will then be:
a = (0 - (-2))/(2 - 0) = 2/2 = 1
Then this line's equation is:
1x - 2
And here's the inequality:
y > x - 2.
The shaded area of the blue one is below the line, thus we will have:
y < ax + b
The y-intercept in this situation is y = 2.
This line crosses through the points (0, 2) and, as can be seen (4, 0)
The slope is then:
a = (0 - 2)/(4 - 0) (4 - 0) = -2/4 = -1/2
This inequality is then:
y < (-1/2)x + 2
If we rewrite this using the choices, we get the following:
y < (-1/2)x + 2
2y < -x + 2 ×2
2y + x < 4
The two inequalities are (option c) y > x - 2 and2y + x < 4
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Answer: C
Step-by-step explanation:
Using the numbers 8, 6, 4, and 2, write an expression that equals 6.
Answer:
6+4,8-6, 4x2,8-2
Step-by-step explanation:
solve (2x-3)²= 4x using the quadratic formula
Answer:
[tex]x = 2 \pm \frac12\sqrt7[/tex]
Step-by-step explanation:
Hello!
Expand the left-hand side of the equation:
(2x - 3)²(2x-3)(2x-3)(2x-3)(2x) +(2x-3)(-3)4x² - 6x - 6x + 94x² - 12x + 9Create the Equation:
4x² - 12x + 9 = 4x4x² - 16x + 9 = 0Solve using the quadratic formula:[tex]x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}[/tex][tex]x = \frac{-(-16) \pm \sqrt{(-16)^2 - 4(4)(9)}}{2(4)}[/tex][tex]x = \frac{16 \pm \sqrt{256 - 144}}{8}[/tex][tex]x = \frac{16 \pm \sqrt{112}}{8}[/tex][tex]x = \frac{16 \pm 4\sqrt7}{8}[/tex][tex]x = 2 \pm \frac12\sqrt7[/tex]The roots of the equation are [tex]x = 2 \pm \frac12\sqrt7[/tex]
What number should be the exponent on the 10 so that the two numbers are equivalent? 75.6 - 10% = 0.00756 y = -3 C y = 3 c y y = 4 y = 4 =
Answer:
y = -4
Explanation:
Given the equation:
[tex]75.6\times10^y=0.00756[/tex][tex]\begin{gathered} 0.00756=7.56\times10^{-3} \\ =75.6\times10^{-4} \end{gathered}[/tex]Thus, the number is -4.
What is the equation, in slope-intercept form, of the line that is perpendicular to the given line and passes through the point (2, −1)? y = Negative one-thirdx − One-third y = Negative one-thirdx − Five-thirds y = 3x − 3 y = 3x − 7
1st , 3rd & 5th choices
Step-by-step explanation:
perpendicular line would have a slope that is a
negative reciprocal
so if the slope is 3 then a perpendicular line would have a slope of -1/3
y - 1 = 1/3 (x + 2)
make the line look like y = mx + b
y = 1/3 (x + 2) + 1
y = 1/3 (x + 2) + 3/3
y = 1/3x + 2/3 + 3/3
y = 1/3x + 5/3
m = 1/3
perpendicular line has a slope of
m = -3
Find the unit rate of gallon to mile:
1/4 of a gallon to 3/10 mile
The unit rate of gallon to mile is calculated as: 5/6 gallon per mile.
How to Find the Unit Rate Between Two Variables?The unit rate between two variables is simply the ratio of the quantity of one variable to the quantity of the other variable, such that the the denominator of the will be equal to exactly 1.
We are given the variables gallons and miles, where 1/4 of a gallon is to 3/10 mile.
The unit rate between these two variables would be an amount of gallons per mile.
Thus, find the unit rate by dividing 1/4 by 3/10:
1/4 ÷ 3/10
= 1/4 × 10/3
= 10/12
= 5/6
The unit rate is therefore, 5/6 gallon per mile.
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y
(1.3)
(5.b)
(a, 6)
(9.7)
All of the points in the graph are on the same line.
Find the slope of the line.
Submit and Explain
A wedding planner placed two orders with a flower shop. The first order was for 13 bunches of roses and 4 palms, totaling $487. The second was for 6 bunches of roses and 2 palms, totaling $232. The receipts do not list the item per price. What is the cost of one bunch of roses and one palm?
Let's call X the cost of one bunch of roses and Y the cost of one palm.
Then, the first order was for 13 bunches of roses and 4 palms, totaling $487, so:
13X + 4Y = 487
Additionally, the second order was for 6 bunches of roses and 2 palms, totaling $232, so:
6X + 2Y = 232
Then, solving for Y on the first equation, we get:
[tex]\begin{gathered} 13X+4Y=487 \\ 4Y=487-13X \\ Y=\frac{487-13X}{4} \\ Y=\frac{487}{4}-\frac{13}{4}X \\ Y=121.75-3.25X \end{gathered}[/tex]Replacing on the second and solving for X, we get:
[tex]\begin{gathered} 6X+2Y=232 \\ 6X+2(121.75-3.25X)=232 \\ 6X+2\cdot121.75-2\cdot3.25X=232 \\ 6X+243.5-6.5X=232 \\ -0.5X+243.5=232 \\ -0.5X=232-243.5 \\ -0.5X=-11.5 \\ X=\frac{-11.5}{-0.5} \\ X=23 \end{gathered}[/tex]Then, we can replace the value of X and calculated the value of Y as:
[tex]\begin{gathered} Y=121.75-3.25X \\ Y=121.75-3.25\cdot23 \\ Y=121.75-74.75 \\ Y=47 \end{gathered}[/tex]Answer: The cost of one bunch of roses is $23 and the cost of one palm is $47
How many students age 15 and above take a car to school? Show work
A. 18
B. 38
C. 87
im pretty sure its B or most likeley C
just tell me the slope of the line and where to plot the segments on the graph
Answer:
The slope is 2
Step-by-step explanation:
Take any two points on the line. I am going to use the points (0,-8) and (4,0) Points are in the form (x,y) The y values form the two points is 0 and -8. The x values are 4 and 0.
The slope is the change in y over the change in x.
[tex]\frac{0- -8}{4-0}[/tex] = [tex]\frac{8}{4}[/tex] = 2
please help solve the attatched question pleasee
Using complementary angles, the numerical value of the given expression is as follows:
2.
What are complementary angles?Complementary angles are angles whose sum of the measures is of 90º.
The relevance of complementary angles in the context of this problem is that if a and b are complementary angles, then the sine of one angle is the cosine of the other angle, as follows:
sin(a) = cos(b).
Considering the angles of 40º and 50º in this problem, we have that:
sin(40º) = cos(50º).sin(50º) = cos(40º).Hence these following simplifications are applied:
sin²(40º) + sin²(50º) = sin²(40º) + cos²(40º) = 1.cos²(40º) + cos²(50º) = sin²(50º) + cos²(50º) = 1.sin(40º)cos(50º) = sin(40º)sin(40º) = sin²(40º).cos(40º)sin(50º) = cos(40º)cos(40º) = cos²(40º).Then the numerical value of the expression is given as follows:
1/1 + sin²(40º) + cos²(40º) = 1 + 1 = 2.
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Convert 41°F to degrees Celsius.
if necessary, round your answer to the nearest tenth of a degree.
Here are the formulas.
C=5/9(F-32)
F=9/5C+32
Answer:
5°C
Step-by-step explanation:
hope this helps, i used your formula :D
Assume that each circle shown below represents one unit. Express the shaded amount as a single fraction and as a mixed number. One Fraction: Mixed Number: Submit Answer attempt
The shaded amount can be express as a single fraction and mixed fraction below
[tex]\begin{gathered} \text{each circle=1 unit} \\ 2\text{ circle= 2 unit} \\ \text{each circle was divided into 12 parts} \\ \text{the shaded parts in the 24 parts =14} \\ Therefore, \\ 1\frac{2}{12}=\frac{14}{12}=1\frac{1}{6} \end{gathered}[/tex]find the derivative:f(x)= -3/ x^4
Given the function f(x), we can write it like this:
[tex]\begin{gathered} f(x)=-\frac{3}{x^4} \\ \Rightarrow f(x)=-3x^{-4} \end{gathered}[/tex]Using the formula for polynomial derivatives, we get:
[tex]\begin{gathered} f(x)=-3x^{-4} \\ \Rightarrow f^{\prime}(x)=-3\cdot(-4)x^{-4-1}=12x^{-5} \\ f(x)=\frac{12}{x^5} \end{gathered}[/tex]Therefore, the derivative f'(x) is 12/x^5