Find the sum of the first 39 terms of the following series, to the nearest integer.2,7, 12,...

Answers

Answer 1

The sequence 2,7,12,... given is an arithmetic progression. This is because it has a common difference.

Given:

first term, a = 2

common difference, d = second term - first term = 7 - 2 = 5

d = 5

n = 38

The sum of an arithmetic progression is given by;

[tex]\begin{gathered} S_n=\frac{n}{2}\lbrack2a+(n-1)d\rbrack \\ S_{38}=\frac{38}{2}\lbrack2(2)+(38-1)5\rbrack \\ S_{38}=19\lbrack4+37(5)\rbrack \\ S_{38}=19\lbrack4+185\rbrack \\ S_{38}=19(189) \\ S_{38}=3591 \end{gathered}[/tex]

Therefore, the sum of the first 39 terms of the series is 3,591


Related Questions

Use the remainder theorem to find P(-2) for P(x) = x³ + 3x² +9,Specifically, give the quotient and the remainder for the associated division and the value of P(-2).QuotientRemainder =P(-2)=

Answers

Answer:

Quotient:

[tex]x^2+x-2[/tex]

Remainder:

[tex]13[/tex]

P(-2):

[tex]13[/tex]

Step-by-step explanation:

Remember that the remainder theorem states that the remainder when a polynomial p(x) is divided by (x - a) is p(a).

To calculate the quotient, we'll do the synthetic division as following:

Step one:

Write down the first coefficient without changes

Step two:

Multiply the entry in the left part of the table by the last entry in the result row (under the horizontal line).

Add the obtained result to the next coefficient of the dividend, and write down the sum.

Step 3:

Multiply the entry in the left part of the table by the last entry in the result row (under the horizontal line).

Add the obtained result to the next coefficient of the dividend, and write down the sum.

Step 4:

Multiply the entry in the left part of the table by the last entry in the result row (under the horizontal line).

Add the obtained result to the next coefficient of the dividend, and write down the sum.

Now, we will have completed the division and have obtained the following resulting coefficients:

[tex]1,1,-2,13[/tex]

Thus, we can conlcude that the quotient is:

[tex]x^2+x-2[/tex]

And the remainder is 13, which is indeed P(-2)

Ariana is going to invest $62,000 and leave it in an account for 20 years. Assuming
the interest is compounded continuously, what interest rate, to the nearest tenth of a
percent, would be required in order for Ariana to end up with $233,000?

Answers

The rate of interest that Ariana should get in order to end up with a final amount of $233,000 is 0.07%.

What is compound interest and how is it calculated?
The interest that is calculated using both the principal and the interest that has accrued during the previous period is called compound interest. It differs from simple interest in that the principal is not taken into account when determining the interest for the subsequent period with simple interest.
Mathematically, A = P (1 + (R/f))ⁿ ;
where A = amount that the depositor will receive
P = initial amount that the depositor has invested
R = rate of interest offered to the depositor
f = frequency of compounding offered per year
n = number of years.

Given, Amount that Ariana wants to end up receiving = A = $233,00
Principal amount that Ariana can invest = P = $62,000
Frequency of compounding offered per year = f = 1
Number of years = 20
Let the rate of interest offered to the depositor be = R
Following the formula established in the literature, we have:
233000 = 62000(1 + R)²⁰ ⇒ 3.76 = (1 + R)²⁰ ⇒ 1.07 = 1 + R ⇒ R = 0.07%
Thus, the rate of interest that Ariana should get in order to end up with a final amount of $233,000 is 0.07%.

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Find the equation of the line parallel to the line y=-1, going through point (-5,4)

Answers

In this problem, want to find the equation of a line that will be parallel to a given function through a point.

Recall that parallel lines have the same slope.

We are given the line

[tex]y=-1[/tex]

and the point

[tex](-5,4)[/tex]

Notice that the equations is technically in slope-intercept form, by the value of the slope will be 0:

[tex]y=0x-1[/tex]

Therefore, the slope of the line through (-5,4) will also be zero. We can use that information to find the equation.

Using the form

[tex]y=mx+b[/tex]

we can substitute the point and the slope to solve for b:

[tex]\begin{gathered} 4=0(-5)+b \\ \\ 4=b \end{gathered}[/tex]

So, the equation of our line is:

[tex]y=0x+4\text{ or }\boxed{y=4}[/tex]

A circle has a circumference of 10 inches. Find its approximate radius, diameter and area

Answers

Answer:

Radius = 1.59 in

Diameter = 3.18 in

Area = 7.94 in²

Explanation:

The circumference of a circle can be calculated as:

[tex]C=2\pi r[/tex]

Where r is the radius of the circle and π is approximately 3.14. So, replacing C by 10 in and solving for r, we get:

[tex]\begin{gathered} 10\text{ in = 2}\pi r \\ \frac{10\text{ in}}{2\pi}=\frac{2\pi r}{2\pi} \\ 1.59\text{ in = r} \end{gathered}[/tex]

Then, the radius is 1.59 in.

Now, the diameter is twice the radius, so the diameter is equal to:

Diameter = 2 x r = 2 x 1.59 in = 3.18 in

On the other hand, the area can be calculated as:

[tex]A=\pi\cdot r^2[/tex]

So, replacing r = 1.59 in, we get:

[tex]\begin{gathered} A=3.14\times(1.59)^2 \\ A=3.14\times2.53 \\ A=7.94in^2 \end{gathered}[/tex]

Therefore, the answer are:

Radius = 1.59 in

Diameter = 3.18 in

Area = 7.94 in²

(x^2+9)(x^2-9) degree and number of terms

Answers

ANSWER

Degree: 4

Number of terms: 2

EXPLANATION

write the number 1,900 in scientific notation

Answers

[tex]1.9\cdot10^3[/tex]

Explanation

[tex]1900[/tex]

Calculating scientific notation for a positive integer is simple, as it always follows this notation:

[tex]a\cdot10^b[/tex]

Step 1

To find a, take the number and move a decimal place to the right one position.

so

[tex]1900\Rightarrow1.900\text{ }[/tex]

Step 2

Now, to find b, count how many places to the right of the decimal.

[tex]1900\Rightarrow1.900\text{ ( 3 places)}[/tex]

Step 3

finally,

Building upon what we know above,

a= 1.9

b=3 (Since we moved the decimal to the left the exponent b is positive)

replace

[tex]\begin{gathered} a\cdot10^b \\ a\cdot10^b=1.9\cdot10^3 \end{gathered}[/tex]

therefore, the answer i

[tex]1.9\cdot10^3[/tex]

I hope this helps you

What is the value of the expression below when z6?9z + 8

Answers

Hello!

Let's solve your expression:

[tex]9z+8[/tex]

Let's replace where's z by 6, look:

[tex]\begin{gathered} (9\cdot z)+18 \\ (9\cdot6)+18 \\ 54+18 \\ =72 \end{gathered}[/tex]

So the value of this expression when z=6 is 72.

help meeeeeeeeee pleaseee !!!!!

Answers

The composition of the function (g o f)(5) is evaluated as: (g o f)(5) = g(f(5)) = 6.

How to Determine the Composition of a Function?

To find the composition of a function, we have to first evaluate the inner function for the given value of x that is given as its input. After that, the output of the inner function would then be used as the input for the outer function, which would now be evaluated for the composition of the function.

Given the functions:

f(x) = x² - 6x + 2

g(x) = -2x

We need to find the composition of the function, (g o f)(5), where the inner function is f(x), and the outer function is g(x).

Therefore:

(g o f)(5) = g(f(5))

Find f(5):

f(5) = (5)² - 6(5) + 2

f(5) = -3

Substitute x = -3 into g(x) = -2x:

(g o f)(5) = -2(-3)

(g o f)(5) = 6

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How far apart, in inches, would the same two cities be on a map that has a scale of 1 inch to 40 miles?

Answers

Using scales, the distance of the two cities on the map would be of:

distance on the map = actual distance/40

What is the scale of a map?

A scale on the map represents the ratio between the actual length of a segment and the length of drawn segment, hence:

Scale = actual length/drawn length

In this problem, the scale is of 1 inch to 40 miles, meaning that:

Each inch drawn on the map represents 40 miles.

Then the distance of the two cities on the map, in inches, would be given as follows:

distance on the map = actual distance/40.

If the distance was of 200 miles, for example, the distance on the map would be of 5 inches.

The problem is incomplete, hence the answer was given in terms of the actual distance of the two cities. You just have to replace the actual distance into the equation to find the distance on the map.

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How to write slope intercept form

Answers

Answer:

See below

Step-by-step explanation:

If you are given slope (m) and intercept (b) , then write the line equation like this:

y = mx + b

Convert do you need to the specified equivalent unit round your answer to the nearest 1 decimal place, if necessary

Answers

Answer:

There are 59251.5 decigrams in 209 ounces.

Step-by-step explanation:

We'll solve this using the rule of three.

We know that there are 28.35 grams in an ounce. This way,

This way,

[tex]\begin{gathered} x=\frac{209\times28.35}{1} \\ \\ \Rightarrow x=5925.15 \end{gathered}[/tex]

And since we know there are 10 decigrams in a gram, we'll have that:

This way,

[tex]\begin{gathered} y=\frac{5925.15\times10}{1} \\ \\ \Rightarrow y=59251.5 \end{gathered}[/tex]

This way, we can conclude that there are 59251.5 decigrams in 209 ounces.

If your distance from the foot of the tower is 20 m and the angle of elevation is 40°, find the height of thetower.

Answers

We have to use the tangent of angle 40 to find the height of the tower.

[tex]\text{tan(angle) = }\frac{opposite\text{ side}}{\text{adjacent side}}[/tex]

The adjacent side is 20m, and the angle is 40 degrees, then

[tex]\tan (40)\text{ = }\frac{height\text{ of the tower}}{20m}[/tex][tex]\text{height = 20m }\cdot\text{ tan(40) = 20m }\cdot0.84\text{ = }16.8m[/tex]

Therefore, the height of the tower is 16.8m

Find the missing rational expression.382x + 6(x-3)(x + 1)X-332x + 6(x-3)(x + 1)(Simplify your answer.)X-3

Answers

[tex]\frac{3}{x-3}-\frac{2x+6}{(x-3)(x+1)}=\frac{3(x+1)-2x-6}{(x-3)(x+1)}=\frac{3x+3-2x-6}{(x-3)(x+1)}=\frac{x-3}{(x-3)(x+1)}=\frac{1}{x+1}[/tex]

which of the following equations represent a line that is perpendicular to y=-3x+6 and passes through the point (3,2)

Answers

Answer:

y = [tex]\frac{1}{3}[/tex] x + 1

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = - 3x + 6 ← is in slope- intercept form

with slope m = - 3

given a line with slope m then the slope of a line perpendicular to it is

[tex]m_{perpendicular}[/tex] = - [tex]\frac{1}{m}[/tex] = - [tex]\frac{1}{-3}[/tex] = [tex]\frac{1}{3}[/tex] , then

y = [tex]\frac{1}{3}[/tex] x + c ← is the partial equation

to find c substitute (3, 2 ) into the partial equation

2 = 1 + c ⇒ c = 2 - 1 = 1

y = [tex]\frac{1}{3}[/tex] x + 1 ← equation of perpendicular line

Help asp show your work you’ll get brainliest

Answers

The information given in the table on the Value of a Car and the Age of the Car, gives;

First Part;

The dependent variable is; The Value of Car

The independent variable is; The Age of Car

Second part;

The situation is a function given that each Age of Car maps to only one Value of Car.

What is a dependent and a independent variable?

A dependent variable is an output variable which is being observed, while an independent variable is the input variable which is known or controlled by the researcher.

First part;

The given information in the table is with regards to how the car's value decreases with time, therefore;

The dependent variable, which is the output variable, or the variable whose value is required is the current Value of the Car (Dollars)The independent variable, which is the input variable, or the variable that determines the value of the output or dependent variable, is the Age of Car (Years)

Second part;

A function is a relationship in which each input value has exactly one output.

Given that the Values of the cars are all different, and no two car of a particular age has two values, therefore;

The situation is a function

Given that the first difference varies depending on the age of the car, the function can be taken as a piecewise function

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There is a 50% chance of rain here and a 10% chance of rain on Mars. Therefore, there is a 45% chance that it will rain in neither place.

Answers

The given statement is true.

This is a question of probability.

It is given in the question that:-

Chance of raining here = 50 %

Chance of raining on Mars = 10 %

The given statement is :-

There is a 45 % chance that it will rain in neither place.

Chance of not raining here = 100 - 50 % = 50 % = 1/2

Chance of not raining on Mars = 100 - 10% = 90 % = 9/10

Hence, chance of raining in neither place = (1/2)*(9/10) = 9/20

9/20 = (9/20)*100 = 45 %.

Hence, the given statement "There is a 45% chance that it will rain in neither place" is true.

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If the number of college professors is P and the number of students S, and there are 20 times more students as professors, write an algebraic equation that shows the relationship

Answers

Answer

Algebraic equation that shows the relationship is

P = 20S

Explanation

Number of college professors = P

Number of students = S

There are 20 times as many students as professors.

P = (S) (20)

P = 20S

Hope this Helps!!!

I had $70 and my mother gave me $10 and my father gave me $30 and aunt and uncle gave me $150 and I had another $7 how much do I have

Answers

Initial money = 70

then add

10 + 30 + 150 + 7 = 197

Now add both results

70 + 197 = 267

Answer is

You have $267

Subtract. Write fractions in simplest form. 12/7 - (-2/9) =

Answers

You have to subtract the fractions:

[tex]\frac{12}{7}-(-\frac{2}{9})[/tex]

You have to subtract a negative number, as you can see in the expression, both negatives values are together. This situation is called a "double negative" when you subtract a negative value, both minus signs cancel each other and turn into a plus sign:

[tex]\frac{12}{7}+\frac{2}{9}[/tex]

Now to add both fractions you have to find a common denominator for both of them. The fractions have denominators 7 and 9, the least common dneominator between these two numbers is the product of their multiplication:

7*9=63

Using this value you have to convert both fractions so that they have the same denominator 63,

For the first fraction 12/7 multiply both values by 9:

[tex]\frac{12\cdot9}{7\cdot9}=\frac{108}{63}[/tex]

For the second fraction 2/9 multiply both values by 7:

[tex]\frac{2\cdot7}{9\cdot7}=\frac{14}{63}[/tex]

Now you can add both fractions:

[tex]\frac{108}{63}+\frac{14}{63}=\frac{108+14}{63}=\frac{122}{63}[/tex]

f(x)A6X-868Which of the given functions could this graph represent?OA. f(t) = (x - 1)(x - 2)(x + 1)(x + 2)O B. f(x) = x(x - 1)(1 + 1)Oc. /(x) = x(x - 1)(x - 2)(x + 1)(x + 2)OD. (r) = x(x - 1)(x - 2)

Answers

The Solution:

Given the graph below:

We are required to determine the function that best describes the above graph.

Step1:

Identify the roots of the function from the given graph.

[tex]\begin{gathered} x=-2 \\ x=-1 \\ x=1 \\ x=2 \end{gathered}[/tex]

This means that:

[tex]\begin{gathered} x+2=0 \\ x+1=0 \\ x-1=0 \\ x-2=0 \end{gathered}[/tex]

So, the required function becomes:

[tex]f(x)=(x-1)(x-2)(x+1)(x+2)[/tex]

Therefore, the correct answer is [option A]

Christian buys a $3500 computer using an installment plan that requires 17% down and a 3.7% interest rate. How much is the down payment?

Answers

1) Gathering the data

$3500 computer

17% down

3.7% interest rate.

2) Since we want to know how much is that down payment, we must turn that 17% into decimal form, then multiply it by the computer value:

17%=0.17

3500 x 0.17 = $595

3) So Christian must pay $595 as the down payment

1. Sketch the graph of y = x that is stretched vertically by a factor of 3. (Hint: Write the equation first, then graph) Sketch both y = x and the transformed graph.

Answers

ANSWER and EXPLANATION

We want to stretch the graph of:

y = x

A vertical stretch of a linear function is represented as:

y' = c * y

where c is the factor

The factor from the question is 3.

So, the new equation is:

y' = 3 * x

y' = 3x

Let us plot the functions:

3 /17% of a quantity is equal to what fraction of the quantity

Answers

Given:

The objective is to find the fraction of 3/17% of the quantity.

Consider the quantity as x. The fraction of 3/17% of the quantity can be calculated as,

[tex]\begin{gathered} =\frac{3}{17}\frac{1}{100}x \\ =\frac{3}{1700}x \end{gathered}[/tex]

Hence, the required fraction of quantity is 3/1700 of x.

the measure of angle is 15.1 what is measure of a supplementary angle

Answers

we get that measure of the supplemantary angle is:

[tex]180-15.1=164.9[/tex]

How long can you lease the car before the amount of the lease is more than the cost of the car

Answers

ANSWER:

48 months

STEP-BY-STEP EXPLANATION:

According to the statement we can propose the following equation, where the price of the car is more than or equal to the amount of the lease. Just like this:

Let x be the number of months

[tex]16920\ge600+340x[/tex]

We solve for x, just like this:

[tex]\begin{gathered} 600+340x-600\le16920-600 \\ \frac{340x}{340}\le\frac{16320}{340} \\ x\le48 \end{gathered}[/tex]

Therefore, for 48 months, the car rental will be lower

An actor invests some money at 7%, and $24000 more than three times the amount at 11%. The total annual interest earned from the investment is $27040. How much did he invest at each amount? Use the six-step method.

Answers

0.07x+0.11(3x+24000)=27040

we will solve for x

x=61,000 [ investment at 7%]

Investment at 11% = 3x + 24000

= 3(61000)+24000

= 207000 [ investment at 11%]

Consider the triangles ADB and EDC. Explain how they are similar.

Answers

Example: Triangles like ABC and EDC are similar by SAS similarity, because angle C is congruent in each triangle, and AC/EC = BC/DC = 2. By the definition of similarity, it follows that AB/DE = BC/EF = AC/DF = 2.

Factor.2n2 + 7n + 5

Answers

The first step to factor this expression is to find its roots (the values of 'n' that makes this expression equals zero)

To find the roots, we can use the quadratic formula:

(Using the coefficients a=2, b=7 and c=5)

[tex]\begin{gathered} n_1=\frac{-b-\sqrt{b^2-4ac}}{2a}=\frac{-7-\sqrt{49-40}}{4}=\frac{-7-3}{4}=\frac{-10}{4}=\frac{-5}{2} \\ n_2=\frac{-b+\sqrt{b^2-4ac}}{2a}=\frac{-7+3}{4}=\frac{-4}{4}=-1 \end{gathered}[/tex]

So the roots of the expression are -5/2 and -1. Now, we can write the expression in this factored form:

[tex]\begin{gathered} a(n-n_1)(n-n_2) \\ 2(n+\frac{5}{2})(n+1) \\ (2n+5)(n+1) \end{gathered}[/tex]

So the factored form is (2n+5)(n+1)

I need help to solve by using the information provided to write the equation of each circle! Thanks

Answers

Explanation

For the first question

We are asked to write the equation of the circle given that

[tex]\begin{gathered} center:(13,-13) \\ Radius:4 \end{gathered}[/tex]

The equation of a circle is of the form

[tex](x-a)^2+(y-b)^2=r^2[/tex]

In our case

[tex]\begin{gathered} a=13 \\ b=-13 \\ r=4 \end{gathered}[/tex]

Substituting the values

[tex](x-13)^2+(y+13)^2=4^2[/tex]

For the second question

Given that

[tex](18,-13)\text{ and \lparen4,-3\rparen}[/tex]

We will have to get the midpoints (center) first

[tex]\frac{18+4}{2},\frac{-13-3}{2}=\frac{22}{2},\frac{-16}{2}=(11,-8)[/tex]

Next, we will find the radius

Using the points (4,-3) and (11,-8)

[tex]undefined[/tex]

Find the absolute maximum and minimum values of the following function on the given interval. f(x)=3x−6cos(x), [−π,π]

Answers

Answer:

Absolute minimum: x = -π / 6

Absolute maximum: x = π

Explanation:

The candidates for the absolute maximum and minimum are the endpoints and the critical points of the function.

First, we evaluate the function at the endpoints.

At x = -π, we have

[tex]f(-\pi)=3(-\pi)-6\cos (-\pi)[/tex][tex]\Rightarrow\boxed{f(-\pi)\approx-3.425}[/tex]

At x = π, we have

[tex]f(\pi)=3(\pi)-6\cos (\pi)[/tex][tex]\Rightarrow\boxed{f(\pi)\approx15.425.}[/tex]

Next, we find the critical points and evaluate the function at them.

The critical points = are points where the first derivative of the function are zero.

Taking the first derivative of the function gives

[tex]\frac{df(x)}{dx}=\frac{d}{dx}\lbrack3x-6\cos (x)\rbrack[/tex]

[tex]\Rightarrow\frac{df(x)}{dx}=3+6\sin (x)[/tex]

Now the critical points are where df(x)/dx =0; therefore, we solve

[tex]3+6\sin (x)=0[/tex]

solving for x gives

[tex]\begin{gathered} \sin (x)=-\frac{1}{2} \\ x=\sin ^{-1}(-\frac{1}{2}) \end{gathered}[/tex]

[tex]x=-\frac{\pi}{6},\; x=-\frac{5\pi}{6}[/tex]

on the interval [−π,π].

Now, we evaluate the function at the critical points.

At x = -π/ 6, we have

[tex]f(-\frac{\pi}{6})=3(-\frac{\pi}{6})-6\cos (-\frac{\pi}{6})[/tex][tex]\boxed{f(-\frac{\pi}{6})\approx-6.77.}[/tex]

At x = -5π/6, we have

[tex]f(\frac{-5\pi}{6})=3(-\frac{5\pi}{6})-6\cos (-\frac{5\pi}{6})[/tex][tex]\Rightarrow\boxed{f(-\frac{5\pi}{6})\approx-2.66}[/tex]

Hence, our candidates for absolute extrema are

[tex]\begin{gathered} f(-\pi)\approx-3.425 \\ f(\pi)\approx15.425 \\ f(-\frac{\pi}{6})\approx-6.77 \\ f(-\frac{5\pi}{6})\approx-2.66 \end{gathered}[/tex]

Looking at the above we see that the absolute maximum occurs at x = π and the absolute minimum x = -π/6.

Hence,

Absolute maximum: x = π

Absolute minimum: x = -π / 6

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