Five pulse rates are randomly selected from a set of measurements. The five pulso rates have a mean of 74 4 boats per minute. Four of the pulse rates are 84, 66, 79, and 57a. Find the missing valueb. Suppose that you need to create a list of n values that have a specific known mean. Some of thon values can be freely selected. How many of the n values can be froely assigned before the remaining valuesare determined? (The result is referred to as the number of degrees of freedom.)a. The missing value isbeats per minute

Answers

Answer 1

(a)

We have five pulse rates randomly selected with a mean of 74.4 beats per minute. We have four pulse rates given. We let x be the value of the fifth pulse rate. We have n equals 5 here since we have sample space of 5. We illustrate the mean of the pulse rates as

[tex]\begin{gathered} \operatorname{mean}=\frac{\sum x}{n} \\ \\ 74.4=\frac{84+66+79+57+x}{5} \end{gathered}[/tex]

Let's solve for the value of x. We have

[tex]\begin{gathered} 74.4=\frac{286+x}{5} \\ 286+x=(74.4)\cdot5 \\ 286+x=372 \\ x=372-286 \\ x=86 \end{gathered}[/tex]

Hence, the missing value is equal to 86.

Answer: 86

(b) The number of degrees of freedom is calculated using the equation

[tex]\text{Degrees of freedom}=n-1[/tex]

We already identified that the sample space n is equal to 5. Hence, the degrees of freedom is equal to

[tex]\text{Degrees of freedom}=5-1=4[/tex]

Answer: 4


Related Questions

What is the maximum volume of a rectangular prism (or box) if the prism has a square base and a total surface area of 100 cm^2?

A) First, let x = the side length of the base and h = the height of the prism. Write and solve the equation for h.

B) Write a function for the volume of the box, V, in terms of x.

Answers

Answer: A. 100/x^2 = h, B. v(x) = x^2*h

Step-by-step explanation:

A. Volume = b * h

100 cm^2 = x^2 * h

100/x^2 = h

B. v(x) = x^2*h

can someone please answer this step by step asap? im confused and dont know how to solve this

Answers

3 equations that can be used to solve the given scenario are:

10x + 15x + 20x = 500045x = 500010x + 15x + 20x = 300

What exactly are equations?In mathematical equations, the equals sign is used to show that two expressions are equal.An equation is a mathematical statement that uses the word "equal to" in between two expressions of the same value.As an illustration, 3x + 5 equals 15.There are many different types of equations, including linear, quadratic, cubic, and others.The three primary types of linear equations are slope-intercept, standard, and point-slope equations.

So, equations that can be used to solve the following scenario are:

Let, the number of students in each group is 'x'.

Then,

10x + 15x + 20x = 500045x = 500010x + 15x + 20x = 300

Therefore, 3 equations can be used to solve the given scenario are:

10x + 15x + 20x = 500045x = 500010x + 15x + 20x = 300

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In a sale, the normal price of a TV is reduced by 20%.
The sale price of the TV is £660
Work out the normal price of the TV.

Answers

The sale price is 80% of the normal price
p x 0.8 = 660
p = 660 / 0.8 = £825

Write the equation of the line that is perpendicular to the x-axis and contains point (0,
4).

Answers

The line of the equation which passes through the point (0, 4) and is parallel to the x-axis is 2y = 8.

What are equations?A mathematical statement that has an "equal to" symbol between two expressions with equal values is called an equation. As in 3x + 5 = 15, for instance. Equations come in a variety of forms, including linear, quadratic, cubic, and others. A mathematical equation is a formula that uses the equals sign to express the equality of two expressions.

So, the equation is as:

A line formed needs to be parallel to the x-axis which means x = 0.Should pass through points (0, 4)

Then, the equation can be:

2y = 8

(Refer to the graph attached below)

If you solve will become:

2y = 8y = 4

Therefore, the line of the equation which passes through the point (0, 4) and is parallel to the x-axis is 2y = 8.

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PLEASE HELP SOON!!!! Pre-calc, Trig, Calculus studentsss

Answers

Answer:

Step-by-step explanation:

31. a statistics class has 26 students. the instructor would like to select a random sample of 3 students to work together on a group project. a. how many different samples are possible? b. if 13 of the 26 students in class are freshmen, what is the probability that all 3 of the selected students are freshmen?

Answers

a. 2600 ways different samples are possible.

b. 0.11  is the probability that all 3 of the selected students are freshmen.

total student = 26

3 students are randomly selected  on group project

a.   the possible  different sample are

[tex]26 C_{3}[/tex] = [tex]\frac{26}{3 (26-3)}[/tex]

      =  [tex]\frac{26}{3 (23)}[/tex]

     = 2600 ways.

b.  13 students are freshmen  

Pr ( 3  selected students  is freshman)

[tex]\frac{13C_{3} }{26C_{3} }[/tex] = [tex]\frac{286}{2600}[/tex] = 0.11

What is probability?

Probability refers to potential. A random event's occurrence is the subject of this area of mathematics. The range of the value is 0 to 1. Mathematics has incorporated probability to forecast the likelihood of various events. The degree to which something is likely to happen is basically what probability means. You will understand the potential outcomes for a random experiment using this fundamental theory of probability, which is also applied to the probability distribution. Knowing the total number of outcomes is necessary before we can calculate the likelihood that a specific event will occur.

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ships a and b leave port together. for the next two hours, ship a travels at 20 mph in a direction 30o west of north while the ship b travels 20o east of north at 25 mph. a) what is the distance between the two ships two hours after they depart? b) what is the speed of ship a as seen by ship b?

Answers

Two hours after depart, the distance between two ships is 39.2 miles and the relative speed of ship A seen by ship B is 19.6 mph heading to 18.4⁰ South of East.

The situation can be depicted on the attached picture.

Let North - South be the y-axis and East - West ne the x-axis.

The velocities vector can be represented as:

Ship A, 20 mph 30⁰ west of north:

vA = - 20 . cos( 60⁰) i + 20 . sin( 60⁰) j

vA = -10 i + 10√3 j

Ship B, 25 mph 20⁰ east of north:

vB = 25 . cos( 70⁰) i + 25 . sin( 70⁰) j

vB = 8.55 i + 23.5 j

b) The speed of ship A relative to ship B is:

vAB = vA - vB

       = ( -10 i + 10√3 j) - (8.55 i + 23.5 j)

       = -18.55 i - 6.18 j

or vAB = sqrt (18.55² + 6.18²) = 19.6 mph with the angle tan⁻¹ (6.18/18.55) = 18.4⁰ South of East.

a) The distance between 2 ships after 2 hours:

d = vAB . 2 hours

d = 19.6 . 2 = 39.2 miles

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Please help me i dont the answer

Answers

[tex] \huge\underline\mathcal{Answer \: -} [/tex]

We know that ,

exterior angle equals sum of two interior opposite angles.

therefore ,

[tex]\bold{x + x + 14 = 136\degree} \\ \\ \longrightarrow \: 2x + 14 = 136\degree \\ \\ \longrightarrow \: 2x = 136\degree - 14 \\ \\ \longrightarrow \: 2x = 122\degree \\ \\ \longrightarrow \: x = \cancel\frac{122}{2} \\ \\ \longrightarrow\boxed{ \: x = 61\degree}[/tex]

hence , the first option is correct.

hope helpful ! ;-;

Answer:

First find the last angle of the triangle.

180 - 136 = 44° (sum of angles on a straight line=180)

Form an equation with the unknown angles with the knowledge that sum of angles in a triangle add up to 180°.

x + (x + 14) + 44 = 180

Simplify and solve for x.

2x + 58 = 180

2x = 122

x = 61

Rewrite in simplest terms: -4f-6(6f-10)

Answers

The given expression: -4f-6(6f-10) in simplified form
is: -40f + 60.

What is an algebraic expression and how is it simplified?
The concept of algebraic expressions is the use of letters or alphabets to represent numbers without providing their precise values. We learned how to express an unknown value using letters like x, y, and z in the fundamentals of algebra. Here, we refer to these letters as variables. Variables and constants can both be used in an algebraic expression. A coefficient is any value that is added before a variable and then multiplied by it. Simplifying the algebraic expressions is to carry out operations on the expressions and then clear it out.

Given, the expression for simplification is: y = -4f-6(6f-10)
Working on the expression above, we have:
y = -4f-6(6f-10) = -4f -36f + 60 = -40f + 60
Therefore the given expression: -4f-6(6f-10) in simplified form
is: -40f + 60.

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A car can be rented for $95 per week plus $0.95 per mile. How many miles can be driven if you have at most $380 to spend for weekly transportation? The car should be driven ....... miles a week?

Answers

We have the next inequality

[tex]95+0.95x\le380[/tex]

where x is the number of miles.

Then we solve the inequality

[tex]\begin{gathered} 0.95x<380-95 \\ \end{gathered}[/tex]

[tex]\begin{gathered} 0.95x\le285 \\ x\le\frac{285}{0.95} \\ x\le300 \end{gathered}[/tex]

The car should be driven 300 miles a week

What’s 4/6 - 1/3 simplified

Answers

Answer:

1/3

Step-by-step explanation:

(4/6) - (1/3)

The denominators need to be the same, so let's convert the second term to (2/6), which is the same as (1/3)

(1/3)*(2/2) = (2/6)

Now we can wite:

(4/6) - (2/6)

This is equal to 2/6 or 1/3

Hello!

The equation [tex]\frac{4}{6} - \frac{1}{3}[/tex] simplified is [tex]\frac{1}{3}[/tex].

Step-by-step explanation:

Begin by giving both equations common denominators in this case we will use 18.

For the first set of fractions we multiply 4 by 3 to get 12 and for the second set of fractions we multiply 1 by 6 to get 6.

Our new set of fractions will look like this [tex]\frac{12}{18}[/tex][tex]- \frac{6}{18}[/tex]

Now we can subtract the numerators since our denominators match.

[tex]12-6=6[/tex] so the new answer will be [tex]\frac{6}{18}[/tex]

It's time to simplify both sets of fractions before we can completely solve the equation. (divide by 2, then 3)

[tex]\frac{6}{18}[/tex] ÷ [tex]2=\frac{3}{9}[/tex] ÷ [tex]3=\frac{1}{3}[/tex]

Since 3 is larger than 1 we are done reducing, time to solve for the final answer.

[tex]\frac{4}{6} -\frac{1}{3} =\frac{1}{3}[/tex]

Hope this helps!

Determine whether each order pair is a solution of the equation

Answers

Answer:

Given equation is, x+3y=6

To determine whether each order pair is a solution of the equation

(3,1)

we have that, when x=3 we get y=1

Let us check this in the equation.

Put x=3, we get

[tex]3+3y=6[/tex][tex]\begin{gathered} 3y=6-3 \\ 3y=3 \end{gathered}[/tex][tex]y=1[/tex]

Hence (3,1) is the solution of the equation.

(6,0)

Put x=6, we get,

[tex]6+3y=6[/tex][tex]y=0[/tex]

Hence (6,0) is the solution of the equation.

(-2,2/3)

Put x=-2, we get,

[tex]-2+3y=6[/tex]

[tex]3y=6+2[/tex]

[tex]y=\frac{8}{3}[/tex]

Hence (-2,2/3) is not the solution of the equation.

Ivy is competing in a Read-A-Thon. Each day , she reads for 25 minutes before school and 45 minutes after school. Find the total number of minutes Ivy spends reading after 5 days. How can you find the total number of minutes Ivy spends reading?

A) Multiply 5 and 25. Then, add 45
B) Multiply 5 and 45. Then, add 25
C) Add 25 and 45. Then, Multiply by 5
D) Add 25 and 45. Then, add 5

Answers

C is the correct answer

Answer: C

Step-by-step explanation:

It the only one that includes both.

PLS HELP, IN A HURRY. Would Appreciate!!!!!

Answers

Answer:

y = w/(h - 5c^3)

Step-by-step explanation:

w = yh - 5yc^3

factorise out y:

w = y(h - 5c^3)

rearrange:

y = w/(h - 5c^3)

I think this is correct.

Question 2

help pls its hard i forgt how to do it

Answers

Answer: 52

Step-by-step explanation:

a^2+b^2=c^2

x is the hypotenuse (c). You can find the hypotenuse by finding the opposite of the right angle

48^2+20^2=2304+400=2704

√2704=52

x=52

Please help ASAP! Compare and contrast the formulas for P(A and B) for dependent and independent events. What is the relationship between P(B) and P(B|A) and can one equation be used for both independent and dependent events?

Answers

The equation P(A and B) = P(A) P(B|A) yields the likelihood that A and B will occur.If the events A and B are not mutually exclusive, the probability is: (A or B) = p(A) + p(B) – p(A and B).We cannot use  one equation  for both independent and dependent events.

Dependent events;

The probability of one event DOES effect the probability of a 2nd event.

Independent events;

The probability of one event DOES NOT effect the probability of a 2nd event

Give the equation for calculating the likelihood that events A and B will occur when A and B are dependent events. The equation P(A and B) = P(A) P(B|A) yields the likelihood that A and B will occur.If the events A and B are not mutually exclusive, the probability is: (A or B) = p(A) + p(B) – p(A and B).We cannot use  one equation  for both independent and dependent events.

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A blueprint for a rectangular warehouse has a length of 18 inches and a width of 10 inches. It uses a scale of 1 inch for every 20 feet. 1. What is the actual area of the warehouse in square feet? 2. How do you know?

Answers

Answer:

The actual area of the warehouse would be:

[tex]72000~\text{feet}^{2}[/tex]

Step-by-step explanation:

Step 1:  Convert all the blueprint lengths into real lengths:

Each inch in the blueprint represents 20 feet in the real world.

So, the real-life length (18 inches in blueprint) would be:

[tex]1~\text{inch}= 20~\text{feet}\\\\\text{Multiply by 18 on both sides}:\\1\times18~\text{inch}= 20\times18~\text{feet}\\18~\text{inch}= 360~\text{feet}\\[/tex]

Similarly, the real-life width would be:

[tex]1~\text{inch}= 20~\text{feet}\\\\\text{Multiply by 18 on both sides}:\\1\times10~\text{inch}= 20\times10~\text{feet}\\10~\text{inch}= 200~\text{feet}\\[/tex]

Step 2: Calculate the area

The area of the warehouse would be given by:

[tex]\text{Area}=\text{Length}\times \text{Width}[/tex]

The length is 360 feet, and the width is 200 feet, so the total area would be:

[tex]\text{Area}=\text{Length}\times \text{Width}\\\\\text{Substitute the values for the length and width}\\\text{Area}= 360\times 200\\\text{Area}=72000[/tex]

2 1/3 - 4/7
what is the answer to this question

Answers

The solution for the algebraic expression 2 1/3 - 4/7 is 37/21

Given,

The algebraic expression ; 2 1/3 - 4/7

We have to solve this expression;

First lets solve the mixed fraction 2 1/3

2 1/3 = (2 x 3) + 1 / 3 = 6 + 1 / 3 = 7/3

Mixed fraction;

A mixed fraction is one that is represented by both its quotient and remainder. A mixed fraction is, for instance, 2 1/3, where 2 is the quotient and 1 is the remainder. An amalgam of a whole number and a legal fraction is a mixed fraction.

Now,

7/3 - 4/7 = (7 x 7) / (3 x 7) - (4 x 3) / (7 x 3) = 49/21 - 12/21

That is,

49/21 - 12/21 = (49 - 12) / 21 = 37/21

That is,

The solution for the algebraic expression 2 1/3 - 4/7 is 37/21

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Which statement about the data in the table is true?
O The data represent a proportional relationship, and the constant of proportionality is $10.
The data do not represent a proportional relationship, but the rate of change of the data is $5 per shirt.
There is not a constant rate of change for these data.
The data represent a proportional relationship, and the constant of proportionality is $5.

Answers

B) The data does not represent a proportional relation, but it has constant rate of change of $5 per shirt.

A)

Take number of T-shirts up to 3 and calculate their proportions.

2/1 = 15/10 = 1.5 (3/2) = 20/15 = 1.33

Clearly the rate of T- shirts is not proportional.

B)

From option (A) we found the given data is not proportional but from the table given in question the rate of change of T- shirts is indeed $5.

C)

No, there is a constant rate of change of $5 as shown in the table below.

D)

No, the data does not represent a constant proportionality. The rate varies.

2/1 = 15/10 = 1.5 (3/2) = 20/15 = 1.33

What is rate of change ?

Rate of change is the rate that describes how one quantity changes relative to another quantity. If x is the independent variable and y is the dependent variable, then

rate of change change=change in y / change x  

Rate of change can be positive or negative. This corresponds to an increase or decrease in the y-value between two data points. If a quantity does not change over time, it is called zero rate of change.

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I just need the answer

Answers

[tex]f(x)=ax^2+bx+c[/tex]

At x=0

[tex]\begin{gathered} f(x)=14 \\ c=14 \end{gathered}[/tex]

at x=1

[tex]\begin{gathered} f(x)=10.5 \\ a+b=10.5-14 \\ a+b=-3.5 \end{gathered}[/tex]

at x=2

[tex]\begin{gathered} f(x)=8 \\ 4a+2b=8-14 \\ 4a+2b=-6 \end{gathered}[/tex]

a=1/2

So correct option is (c).

A company makes concrete bricks shaped like rectangular prisms. Each brick is 11 inches long, 8 inches wide, and 5 inches tall. If they used 11,000in3 of concrete, how many bricks did they make?

Answers

Answer:

25 bricks

Step-by-step explanation:

Calculate the volume of one brick:

Volume = (11')(8")(5") = 440 in^3

Divide the volume of a one brick into the volume of concrete that will be used:

(11000 in^3 concrete)/(440 in^3 concrete/brick) = 25 bricks

15:4y2 – 30:23 + 4554The quotient of517is7. When this quotient is divided bythe result is 3-35-5I3y – 25y2 + 3

Answers

We are given the following expression:

[tex]\frac{15x^4y^2-30x^2y^3+45xy}{5xy}[/tex]

To determine the quotient of the expression we will factor the numerator. To do that we take the Greatest Common Multiple of the denominator.

The denominator is the following expression:

[tex]15x^4y^2-30x^2y^3+45xy[/tex]

To get the greatest common multiple we need to determine the multiples of the coefficients first.

For 15 we have:

[tex]factors\text{ 15= 1, 3, 5, 15}[/tex]

For 30 we have:

[tex]\text{factors 30 = }1,2,3,5,6,10,15,30[/tex]

For 45 we have:

[tex]\text{factors 45 =}1,3,5,9,15,45[/tex]

We notice that the factors that are repeated for each of the numbers are:

[tex]\text{repeated = 1,3,5,15}[/tex]

The greatest of the repeated factors is 15, therefore, the greatest common factor is 15.

Now, we take the variables that are repeated in the expression and we take the ones with smaller exponents. The variables repeated are:

[tex]xy[/tex]

Of these, the ones with smaller exponents are:

[tex]xy[/tex]

Now, combining the two parts we get that the greatest common factor of the denominator is:

[tex]15xy[/tex]

We take out that factor and re arrange the expression, like this:

[tex]\frac{15x^4y^2-30x^2y^3+45xy}{5xy}=\frac{15xy(x^3y-2xy^2+3)}{5xy}[/tex]

Now, we cancel out the "xy" and simplify 15/5:

[tex]\frac{15xy(x^3y-2xy^2+3)}{5xy}=3(x^3y-2xy^2+3)[/tex]

And thus we get the quotient.

We notice that the quotient is multiplied by 3, therefore, if we divide by 3:

[tex]\frac{3(x^3y-2xy^2+3)}{3}[/tex]

We can cancel out the 3 and we get:

[tex]\frac{3(x^3y-2xy^2+3)}{3}=x^3y-2xy^2+3[/tex]

Therefore, the quotient is divided by 3.

Please helpppppp!!!!!!!!!!!!!!!!!!!!!!!!3|x_5|-|4y|/|x+y|when x=8 & y=4​

Answers

Answer:

29/49

Step-by-step explanation:

x:y = 3:4

let x = 3x , y = 5k

3x+4y/8x+5y

= 3(3k)+4(5k)/8(3k)+5(5k)

= 9k+20k/24k+25k

=29/49

A rental car company charges $37.50 per day to rent a car and $0.05 for every mile
driven. Alyssa wants to rent a car, knowing that:
. She plans to drive 100 miles.
. She has at most $200 to spend.
Write and solve on

Answers

Hello!

Knowing that Alyssa wants to rent a car where the company charges $37.50 per day to rent a car and $0.05 for each mile driven we have to find out how many days she is planning on renting a car for.

Step-by-step explanation:

Using the information we have we can see that it will be an additional $5 based on how many miles she is planning on driving.

If the base cost to rent a car is $37.50 you will have to add an additional $5  for the number of miles she plans to drive making the total $42.50.

Since she has at most $200 to spend on a car rental she can rent a car for a total of 5 days at a total cost of $192.50

[tex]37.50[/tex] × [tex]4=150[/tex] + [tex]42.50[/tex] = [tex]192.50[/tex]

Hope this helps!

The inequality will be 37.5x + (0.05 ×100) ≤ 200, and Alyssa can afford 5.2 days to rent while staying within her budget

How to write and solve an inequality to determine the number of days?

Given that the rental car company charges $37.50 per day to rent a car and $0.05 for every mile driven

She plans to drive 100 miles and has at most $200 to spend.

Let x is the number of days, Alyssa can afford to rent while staying within her budget

The inequality can be written as;

37.5x + (0.05 ×100) ≤ 200

Now solve for x:

37.5x + (0.05 ×100) ≤ 200

37.5x + 5 ≤ 200

37.5x  ≤ 200 - 5

37.5x  ≤ 195

x  ≤ 195/37.5

x ≤  5.2

Therefore, she can afford 5.2 days to rent while staying within her budget.

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A Ford F-150 truck is considered a half-ton truck because that is how much it can haul. How many pounds can the truck haul?

Answers

The truck can haul 1102 pounds.

According to the question,

We have the following information:

A Ford F-150 truck is considered a half-ton truck because that is how much it can haul.

(More to know: ton, pounds and kilograms are the most commonly used units for measuring weight.)

Now, we already have the knowledge that 1 ton is equal to 1000 kilograms.

So, half ton will make 500 kg.

Now, in order to convert this into pounds, we will multiply 500 kg by 2.205 because we know that 1 kg makes 2.205 pounds.

1 kg = 2.205 pounds

500 kg = (500*2.205) pounds

500 kg = 1102.5 pounds

Hence, the truck can haul 1102.5 pounds.

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O EQUATIONS AND INEQUALITIESSolving a word problem with two unknowns using a linear...

Answers

Given:

Total number of hamburgers and cheeseburgers sold = 439

There were 61 fewer cheeseburgers than hamburgers sold.

Let's determine the number of hamburgers sold.

Let C represent the number of cheeseburgers

Let H represent the number of hamburgers sold.

We have the system of equations:

• H + C = 439

,

• C = H - 61

Now, let's solve the equations simultaneously using the substitution method.

Substitute (H - 61) for C in the first equation.

We have:

H + (H - 61) = 439

H + H - 61 = 439

2H - 61 = 439

Add 61 to both sides:

2H - 61 + 61 = 439 + 61

2H = 500

Divide both sides by 2:

[tex]\begin{gathered} \frac{2H}{2}=\frac{500}{2} \\ \\ H=250 \end{gathered}[/tex]

Therefore, they sold 250 hamburgers on Friday.

ANSWER:

250 hamburgers

Rewrite one eighth times x cubed times y plus seven eighths times x times y squared using a common factor.

Answers

Equation y (1/8 x3 + 7) is rewritten by using a common factor. A literal equation is regarded as having at least two variables.

Given that,

Use a common factor to rewrite one eighth times x cubed times y plus seven eighths times x times y squared.

This is how the equation can be rewritten:

The first equation is written as 1/8 x3y + 7/8 xy2.

It is possible to rewrite the equation 1/8 xy(x2 + y) using the common factor.

Equation two:

1/4x.y.4x2 + 28y

1/4 .4 x³ .y + 28y

x3.y + 28y equation to be solved

Using the formula

y = (x3 + 28).

Third claim:

1/4. x. y. x2 + 7y

Fix the problem.

1/4 . x³ .y + 7y

Write y = (1/4x3 + 7) in a new way.

Fourth assertion:

1/8 x3y2.y + 7 x 1/8 x3y3 + 7 x

After removing the common element x(1/8 x2y3+ 7), rewrite the equation.

Fifth Declaration

1/8 x. y. x² + 7y

1/8 x³. y + 7y

Equation y (1/8 x3 + 7) is rewritten.

Thus, a literal equation is one that contains at least two variables. Solve for one variable in terms of the other variable to rephrase a literal equation.

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Y = 17x - 8, y = 24x +6 Parallel Perpendicular Neither

Answers

Two parallel lines in the coordinate system share the same slope, this means that if you have two parallel lines:

[tex]\begin{gathered} y_1=m_1x_1+b_1 \\ y_2=m_2x_2+b_2 \\ \text{Their slopes must be equal:} \\ m_1=m_2 \end{gathered}[/tex]

For the given equations, the slopes are:

[tex]\begin{gathered} y=17x-8 \\ m=17 \end{gathered}[/tex][tex]\begin{gathered} y=24x+6 \\ m=24 \end{gathered}[/tex]

The slopes are different, so this lines are not parallel.

Two lines are perpendicular, when the slope of one of them is the negative inverse of the first one, this is for the perpendicular lines:

[tex]\begin{gathered} y_1=m_1x_1+b_1 \\ y_2=m_2x_2+b_2 \\ m_2=-\frac{1}{m_1} \end{gathered}[/tex]

For the given equations, using y=17x-8 as reference, the slope of a line perpendicular to this one must be:

[tex]m_{}=-\frac{1}{17}[/tex]

The slope of a perpendicular line to y=17x-8 is different from the slope of the second given line, so you can conclude that these lines are not perpendicular.

The correct choice is Neither

the probability of observing a window given there is no window at its location is 0.2, and the probability of observing a window given there is a window is 0.9. after incorporating the observation of a window, what are the robot's new probabilities for being in

Answers

Updated Probabilities are: P(L1/W) = 0.341 & P(L1/w) = 0.949

Let W be the event that the robot's camera observes a window

It is given that the Probability of observing a window there is no window at its location is given 0.2

P(W/ L1) = 0.2 ( L1 which does not have a window)

Also, probability of observing a window is 0.9

P(W/ L2) = 0.9 ( L2 has window)

Now we have to find updated probabilities for the robot being in L1 i.e:- P(L1/W) & P(L1/w)

w means the camera does not observe a window.

By Bayes Rule,

P(L1/W) = P(L1)P(W/L1)/P(L1)P(W/L1)+P(L2)P(W/L2)

            = (0.7x 0.2)/ (0.7x0.2) + (0.3x0.9)

            = (0.14)/ 0.14+0.27

            ≈0.341 (rounded to 3. decimal places)

Thus  the probability of being in L1 if the camera observes a window is nearly 0.341.

P(L1/w) = P(L1)P(w/L1)/P(L1)P(w/L1)+P(L2)P(w/L2)

As P(W/L1) = 0.2;

P(w/L1) = 1 - P(w/L1) = 1-0.2 = 0.8

Also P(W/L2) = 0.1;

P(w/L2) = 1 - P(w/L2) = 1-0.9 = 0.1

P(L1/w) = (0.7 X 0.8)/ (0.7X0.8) + (0.3X0.1)

           =(0.56)/ (0.56+0.03) = (0.56/ 0.59)

           ≈ 0.949 (rounded to 3 decimal places).

Thus the probability of being in L1 if observe not the window is nearly 0.949.

Updated Probabilities are: P(L1/W) = 0.341 & P(L1/w) = 0.949

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Elijah put 2x+3
2
x
+
3
dollars in the bank the first week. The following week he doubled the first week’s savings and put that amount in the bank. The next week, he doubled what was in the bank and put that amount in the bank. He now has $477 in the bank. How much money did he put in the bank the first week?

Answers

Elijah put $53 in the Bank in the first week .

In the question ,

it is given that Elijah put (2x+3) in the first week .

In the second week Elijah put double the first week savings

that means second week deposit = 2*(2x+3) = 4x+6

in the third week he doubled the amount that was in the bank ,

which means third week deposit = 2*(first week + second week deposit)

= 2*(2x+3+4x+6)

Also given that total amount in the bank = $477

total amount = first week + second week + third week deposit

substituting the values we get

477 = (2x+3) + (4x+6) + 2*(2x+3+4x+6)

477 = 2x+3+4x+6+4x+6+8x+12

477 = 18x + 27

18x = 477-27

18x = 450

x = 450/18

x = 25

the amount deposited in the first week = 2x+3

                                                                  = 2(25)+3

                                                                  = 50+3 = $53

Therefore , Elijah put $53 in the Bank in the first week .

The given question is incomplete , the complete question is

Elijah put 2x+3 dollars in the bank the first week. The following week he doubled the first week’s savings and put that amount in the bank. The next week, he doubled what was in the bank and put that amount in the bank. He now has $477 in the bank. How much money did he put in the bank the first week?

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