Chemistry High School

For the following reaction, K > 1. Classify each of the reactants and products based on their strength as Bronsted-Lowry acids or bases.
C9H7N + HNO2Doublearrow.GIFC9H7NH+ + NO2-
a) HNO2 1) stronger acid
b) NO2- 2) weaker acid
c) C9H7NH+ 3) stronger base
d) C9H7N 4) weaker base

Answers

Answer 1

For the given reaction with K > 1, we can classify the reactants and products based on their strength as Bronsted-Lowry acids or bases:
a) 1, b) 4, c) 2, d) 3.

C9H7N + HNO2 ⇄ C9H7NH+ + NO2-

a) HNO2 is a stronger acid (1) because it donates a proton to C9H7N.
b) NO2- is a weaker base (4) because it accepts a proton less readily compared to C9H7N.
c) C9H7NH+ is a weaker acid (2) because it donates a proton less readily compared to HNO2.
d) C9H7N is a stronger base (3) because it accepts a proton from HNO2.

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Related Questions

Drag each tile to the correct location. Physical property. Chemical property. Tiles: acetic acid can react with another substance and change color. The melting point of tin is 231.9 degrees C. Sodium can react with water to form sodium hydroxide and hydrogen. Iron does not burn when exposed to flame. The density of solid silver is 10.49 grams/centimeter3. Pure water is odorless.

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The melting point of tin is 231.9 degrees C, Iron does not burn when exposed to flame, The density of solid silver is 10.49 grams/centimeter³ and Pure water is odorless are Physical property.

Although a physical change happens when substance alters forms without changing its chemical identity, a chemical change is the result of a chemical reaction. If enough energy is provided, many physical changes can be reversed. A different chemical reaction is the only way to undo a chemical change.

The melting point of tin is 231.9 degrees C, Iron does not burn when exposed to flame, The density of solid silver is 10.49 grams/centimeter³ and Pure water is odorless are Physical property. Sodium can react with water to form sodium hydroxide and hydrogen is Chemical property.

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what is the next stage after the body plan is established chapter 4 embryological similarities

Answers

The next stage after the body plan is established is the process of differentiation into organs and organ systems.

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What product(s) would you expect to obtain from reaction of 1,3-cyclohexadiene with each of the following?

(a) 1 mol Br2 in CH2Cl2

(b) O3 followed by Zn

(c) 1 mol HCl in ether

(d) 1 mol DCl in ether

(e) 3-Buten-2-one (H2C ═ CHCOCH3)

(f) Excess OsO4, followed by NaHSO3

Answers

(a) 1,3-cyclohexadiene would react with 1 mol Br2 in CH₂Cl₂ to give 1,2-dibromo-1,3-cyclohexadiene.

(b) 1,3-cyclohexadiene would react with O₃ followed by Zn to give adipic acid.

(c) 1,3-cyclohexadiene would react with 1 mol HCl in ether to give chlorocyclohexene.

(d) 1,3-cyclohexadiene would react with 1 mol DCl in ether to give deuterated cyclohexene.

(e) 1,3-cyclohexadiene would react with 3-buten-2-one in the presence of an acid catalyst to give a Diels-Alder adduct.

(f) 1,3-cyclohexadiene would react with excess OSO₄, followed by NaHSO₃ to give a vicinal diol.

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