Forproblems 5-10, determine what type of symmetry each figure has. If the figure has line symmetry, determine how many lines of symmetry the figure has. If the figure has rotational symmetry, determine the angle of rotational symmetry and if the figure also has point symmetry. (A figure can have both line and rotational symmetries or neither of these symmetries)
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7. The figure has line and rotational symmetries. There are 2 lines of symmetry. The angle of symmetry is 180°
8. The figure has no symmetry
Related Questions
А.Translate the triangle.Then enter the new coordinates.A'([?], []).(4,-1) B'([ ], [])C'([],[ ](1,-3)(5,-4)<-2,3)B.
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Given the triangle shown in the picture, you know its vertices:
[tex]A\mleft(4,-1\mright);B\mleft(5,-4\mright);C\mleft(1,-3\mright)[/tex]You have the following translation vector:
[tex]\langle-2,3\rangle[/tex]Therefore, you can identify that to find the Image (the figure translated) of the Pre-Image (the original figure) ABC, you have to translate each vertex 2 units left and 3 units up. Then, you get:
[tex]\begin{gathered} A^{\prime}(4-2,-1+3)=A^{\prime}(2,2) \\ \\ B^{\prime}(5-2,-4+3)=B^{\prime}(3,-1) \\ \\ C^{\prime}(1-2,-3+3)=C^{\prime}(-1,0) \end{gathered}[/tex]Then, the answer is:
[tex]undefined[/tex]Which linear inequality is represented by the graph?1. y≤ 2x+42. y≤ x+33. y²x+34. y≥ 2x+3
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Given a graph represented a linear inequality.
First, we will find the equation of the shown line.
As shown, the line passes through the points (0, 3) and (2, 4)
the general equation of the line in the slope-intercept form will be:
[tex]y=mx+b[/tex]Where (m) is the slope and (b) is the y-intercept
b = y-intercept = 3
We will find the slope as follows:
[tex]m=\frac{y_2-y_1}{x_2-x_1}=\frac{4-3}{2-0}=\frac{1}{2}[/tex]So, the equation of the line will be:
[tex]y=\frac{1}{2}x+3[/tex]As shown, the point (0, 0) lying in the area of the solution
So, the linear inequality will be as follows:
[tex]y\leq\frac{1}{2}x+3[/tex]-2(k - 5) + 2K = 5k +5A)k=0B)k=4C)k1D)k=2
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The equation we have is:
[tex]-2(k-5)+2k=5k+5[/tex]Now we can simply the equation by multiply the -2 into the parenthesis
[tex]\begin{gathered} -2k+10+2k=5k+5 \\ 10=5k+5 \end{gathered}[/tex]now we can solve for k
[tex]\begin{gathered} 10-5=5k \\ 5=5k \\ \frac{5}{5}=k \\ 1=k \end{gathered}[/tex]Open the image attached belowProve that:sec n/(tan n + cot n) = sin n
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Given:
We are required to prove:
[tex]\frac{\sec\text{ }\theta\text{ }}{\tan\text{ }\theta\text{ + cot}\theta}\text{ = sin}\theta[/tex]From the left-hand side:
[tex]\begin{gathered} =\frac{\sec\text{ }\theta\text{ }}{\tan\text{ }\theta\text{ + cot}\theta}\text{ } \\ =\text{ }\frac{\frac{1}{\cos\theta}}{\frac{\sin\theta}{\cos\theta}\text{ + }\frac{\cos \theta}{\sin \theta}} \\ =\text{ }\frac{\frac{1}{\cos\theta}}{\frac{\sin ^2\theta+cos^2\theta}{\sin \theta\cos \theta}} \\ \end{gathered}[/tex]From standard trigonometric identity, we have:
[tex]\sin ^2\theta+cos^2\theta\text{ = 1}[/tex]Substituting we have:
[tex]\begin{gathered} =\text{ }\frac{\frac{1}{\cos\theta}}{\frac{1}{\sin \theta\cos \theta}} \\ =\text{ }\frac{\sin \theta\cos \theta}{\cos \theta} \\ =\text{ sin }\theta\text{ (Right-hand side)} \end{gathered}[/tex]Rabbit's run: distance (meters) time (minutes) way 800 1 900 5 1107.5 20 1524 32.5
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Answer:
Notice that:
[tex]\begin{gathered} \frac{800}{1}=800, \\ \frac{900}{5}=180, \\ \frac{1107.5}{20}=\frac{443}{8}, \\ \frac{1524}{32.5}=\frac{3048}{65}. \end{gathered}[/tex]Since all reduced fractions are different, the distance traveled by the rabbit and the time are not proportional.
the sign shown below is posted in front of a roller coaster ride at the Wadsworth country fairgrounds.if h represents the height of a rider in inches,what is the correct translation of the statement on this sign?h<48h>58h≤48h≥48
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Answer:
h≥48
Explanation:
If all riders must be at least 48 inches tall, it can mean the following.
0. The height of the riders can be ,exactly 48 inches, tall (h=48)
,1. The height of the riders can be, greater than 48 inches,, (h>48).
Combining the two, we have:
h≥48
Complete the square for each expression. Write the resulting expression as a binomial. x^2+14x+____
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To complete the square is take the second term in the expression, divided it by 2 and then squared it. This will be the number that we have to add to the original expression.
(14/2)^2=49
so, completing the expression:
x^2+14x+49
Then, the new expression can be factored into a single term squared:
x^2+14x+49= (x+7)^2
The post office offers flat-rate mailing of packages: $1.50 for a package weighing less than 4 oz, $2.50 for a package weighing 4 oz to less than 8 oz, and $3.50 for a package weighing 8 oz to 12 oz. write an equation that would represent the situation.
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To solve the problem, we will define a function that given the weight of the package, will determine the cost of the mailing. Let x be the weigth of the package in oz and let f(x) be the cost of mailing the package. We are told that if the weight is less than 4, then the rate is 1.50. So, in math notation that would be f(x) = 1.50 if x<4. Now, we are told that if the package weights between 4 and less than 8, then the rate is 2.50. So, that is f(x) = 2.50 if 4<=x<8. Finally, we are told that if the package weights between 8 and 12, the cost is 3.50. So f(x) = 3.50 if 8<=x<=12. So the final math expression for f(x) is
1.50 if x<4
f(x) = 2.50 if 4<=x<8
3.50 if 8<=x<=12.
Simplify 2+^3 ÷ 2- ^3
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We want to simplify the following expression:
[tex]\frac{2+\sqrt[]{3}}{2-\sqrt[]{3}}[/tex]This means that we want to "remove" the denominator".
STEP 1If we observe the denominator:
[tex](2-\sqrt[]{3})[/tex]If we multiply it by
2 + √3, then
[tex]\begin{gathered} (2-\sqrt[]{3})(2+\sqrt[]{3}) \\ =4-\sqrt[]{3}^2=4-3=1 \end{gathered}[/tex]STEP 2We know that if we multiply both sides of a fraction by the same number or expression, the fraction will remain the same, then we multiply both sides by 2 + √3:
[tex]\frac{2+\sqrt[]{3}}{2-\sqrt[]{3}}=\frac{(2+\sqrt[]{3})(2+\sqrt[]{3})}{(2-\sqrt[]{3})(2+\sqrt[]{3})}[/tex]For the denominator, as we analyzed before
[tex](2-\sqrt[]{3})(2+\sqrt[]{3})=1[/tex]For the denominator:
[tex](2+\sqrt[]{3})(2+\sqrt[]{3})=(2+\sqrt[]{3})^2[/tex]Then,
[tex]\frac{2+\sqrt[]{3}}{2-\sqrt[]{3}}=\frac{(2+\sqrt[]{3})(2+\sqrt[]{3})}{(2-\sqrt[]{3})(2+\sqrt[]{3})}=\frac{(2+\sqrt[]{3})^2}{1}=(2+\sqrt[]{3})^2[/tex]STEP 3Now, we can simplify the result:
[tex]\begin{gathered} (2+\sqrt[]{3})^2=(2+\sqrt[]{3})(2+\sqrt[]{3}) \\ =2^2+2\sqrt[]{3}+(\sqrt[]{3})^2+2\sqrt[]{3} \\ =4+4\sqrt[]{3}+3 \\ =7+4\sqrt[]{3} \end{gathered}[/tex]Answer: 7+4√3What is the equation of the line that is parallel to the graph of y = 2x - 5 and passes through the point (8, 10)?
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We know that the equation of a line is given by
[tex]y-y_1=m(x-x_1)[/tex]To find it we need the slope m and a point that the line passes thorugh. In this case we have the point (8,10) but we don't know the slope. What we know is that the line we are looking for is parallel to the line
[tex]y=2x-5[/tex]We also know that for two lines to be parallel they have the same slope. Then, if we fin the slope of the line y=2x-5, we have the slope of the line we are looking for. To find the slope of the line y=2x-5 we note that it is written in the slope-intercept form
[tex]y=mx+b[/tex]From this we know that the slope is multiplying the x variable when it is written in that form. Hence m=2.
Then the line we are looking for has an slope of 2 and passes through the point (8,10). Pluggin the values in the equation of a line we have.
[tex]y-10=2(x-8)[/tex]Writting it in the slope intercept form we have
[tex]\begin{gathered} y-10=2(x-8) \\ y-10=2x-16 \\ y=2x-16+10 \\ y=2x-6 \end{gathered}[/tex]Then the line parallel to y=2x-5 and passes through the point (8,10) is
[tex]y=2x-6[/tex]Rain equation for the line that is parallel to the given line and that passes through the given point
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From the properties of line
If two lines are parallel, then thier slope are equal.
The general equation of line with slope m is; y = mx + b
The given equation of line us y = -5x + 3, slope of the given line is (-5)
The line is passes through the point (-6,3) and slope (-5)
The general equation of line is;
[tex]y-y_1=m(x-x_1)[/tex]Substitute the coordinates as;
[tex]x_1=-6,y_1=3[/tex]Thus;
[tex]\begin{gathered} y-y_1=m(x-x_1) \\ y-3=-5(x+6) \\ y-3=-5x-30 \\ y+5x-3+30=0 \\ 5x+y+27=0 \\ y=-5x-27 \end{gathered}[/tex]Answer : y = -5x - 27
,,,
There is sales tax of $9.00 on an item t that costs $ 120.00 before tax. The sales tax on a different item is $ 19.05. How much does the second item cost before tax?
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SOLUTION:
Step 1:
In this question, we are given that:
There is sales tax of $9.00 on an item that costs $ 120.00 before tax.
The sales tax on a different item is $ 19.05.
We are meant to find how much the second item cost before tax.
Step 2:
Assuming that there is an equal percentage of tax,
and let the second item cost before tax be y,
then we have that:
[tex]\frac{9}{120}\text{ = }\frac{19.05}{y}[/tex]Cross-multiply, we have that:
[tex]\begin{gathered} 9\text{ x y = 19.05 x 120} \\ 9y\text{ = 2286} \\ \end{gathered}[/tex]Divide both sides by 9, we have that:
[tex]\begin{gathered} y\text{ = }\frac{2286}{9} \\ y\text{ = 254} \end{gathered}[/tex]CONCLUSION:
The cost of the second item before tax = $ 254
Given:• UZ | VW• UV ZUZ306Nw4511Which is closest to mZW?26.630°60°63.49
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From the image, given that UZ is parallel to VW, UV is congruent to UZ. We can redraw the image to include some extra details.
The image is below;
With the image above, we can the find the angle W, using tangent function of trigonometry.
This is seen below;
[tex]\begin{gathered} \tan w=\frac{opposite}{\text{Adjacent}} \\ \text{opposite =30ft} \\ \text{Adjacent}=15ft \\ \therefore\tan w=\frac{30}{15} \\ \tan w=2 \\ w=\tan ^{-1}2 \\ w=63.4^0 \end{gathered}[/tex]The angle closest to m
Answer: 63.4
Pls help with the question in the picture. 20 Points and brainliest.
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Answer:
∠ UTV = 66°
Step-by-step explanation:
the central angle USV is twice the angle on the circle ∠ UTV , subtended on the same arc UV , that is
10x + 82 = 2(10x + 16) ← divide both sides by 2
5x + 41 = 10x + 16 ( subtract 5x from both sides )
41 = 5x + 16 ( subtract 16 from both sides )
25 = 5x ( divide both sides by 5 )
5 = x
Then
∠ UTV = 10x + 16 = 10(5) + 16 = 50 + 16 = 66°
A $300,000 property appreciated in value by 3%. What is its new value?
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Answer:
The word "Appreciated" means "Increase" in value of something.
Here, The value of property is Appreciated by 3%
Therefore,
New price = Old price + 3% of Old price
New price = $300000 + 3% of $300000
New price = $300000 + $( 3/100 × 300000)
New price = $300000 + $9000
New price = $309000
I hope it's helpful
Answer:
$309 000.
Step-by-step explanation:
It is now worth 3% more than its original 100%
So 103% ( in decimal 1.03)
1.03 * 300 000 = 309 000 dollars
In a probability experiment, Craig rolled a six-sided die 62 times. The die landed on a number greater than three 36 times. What is the ratio of rolls greater than three to rolls less than or equal to three?
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Answer:
31/55
Step-by-step explanation:
Which set of ordered pairs does not show y as a function of x? A. {(3,-2); (5,-3); (7,-4); (9,-5)} B. O {(3,-2); (6,-2); (9,-2); (12,-2)} c.{(4, -2); (5,-3); (6,-4); (7,-5)} D.O{(4, -2); (5,-3); (4,-8); (5,-9)}
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To make banana berry smoothies, Just Juice mixes water and juice in a ratio of 5 to 3. How much water should Just Juice mix with 23 gallons of juice to make banana berry smoothies?
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Answer:
38 1/3 gallons.
Step-by-step explanation:
[tex]\frac{w}{j}[/tex] = [tex]\frac{w}{j}[/tex] set up a ratio of the ratio of water to juice to the actual amount of water in juice. Fill in the numbers that you know and solve for the actual amount of water.
[tex]\frac{5}{3}[/tex] = [tex]\frac{w}{23}[/tex] Cross multiply and solve
3w = 5(23)
3w = 115 Divide both side by 3
w = 38 1/3 Gallons
The question is which of these statements are true about radicals exponents and rational exponents
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We have the following:
I)
[tex]\sqrt[n]{a}=a^{\frac{1}{n}}[/tex]It´s true
II)
[tex]a^{\frac{1}{2}}=\sqrt[]{a}[/tex]It´s true
III)
[tex]\begin{gathered} a^{\frac{p}{q}}=\sqrt[p]{a^q}=(\sqrt[p]{a})^q \\ (\sqrt[p]{a})^q=(a^{\frac{1}{p}})^q=a^{\frac{q}{p}} \end{gathered}[/tex]It´s false
IV)
[tex]\sqrt[]{a}[/tex]It´s true
V)
[tex]\begin{gathered} a^{\frac{1}{n}}=\sqrt[]{a^n} \\ \sqrt[]{a^n}=a^{\frac{n}{2}} \end{gathered}[/tex]It´s false
Completely factor the expression by grouping if possible 2xy+3x+10y+15
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The required factor of the given expression is given as (2y + 3)(x + 3).
Given that,
The factor of the given expression 2xy+3x+10y+15 is to be determined.
The process in mathematics to operate and interpret the function to make the function or expression simple or more understandable is called simplifying and the process is called simplification.
Here
= 2xy+3x+10y+15
Simplifying through factorization,
= x(2y + 3) + 5(2y + 3)
= (2y + 3)(x + 3)
Thus, the required factor of the given expression is given as (2y + 3)(x + 3).
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I need help on question number 1 I have been stuck on it for a long time
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Explanation
Step 1
Vertical angles are formed when two lines intersect each other. Out of the 4 angles that are formed, the angles that are opposite to each other are vertical angles. vertical angles are congruent so
[tex]\begin{gathered} m\angle5=m\angle7\rightarrow reason\text{ vertical angles} \\ \end{gathered}[/tex]Step 1
replace the given values
[tex]\begin{gathered} m\angle5=m\angle7\rightarrow reason\text{ vertical angles} \\ -2(3x-4)=3(x-3)-1 \end{gathered}[/tex]now, we need to solve for x
a)
[tex]\begin{gathered} -2(3x-4)=3(x-3)-1 \\ \text{apply distributive property} \\ -6x+8=3x-9-1 \\ \text{add like terms} \\ -6x+8=3x-10\rightarrow reason\text{ distributive property} \end{gathered}[/tex]b)subtract 3x in both sides( additioin or subtraction property of equality)
[tex]\begin{gathered} -6x+8=3x-10 \\ subtract\text{ 3x in both sides} \\ -6x+8-3x=3x-10-3x \\ -9x+8=-10 \\ \text{subtract 8 in both sides} \\ -9x+8-8=-10-8 \\ -9x=-18 \\ -9x=-18\rightarrow reason\colon\text{ addition and subtraction property of equality} \end{gathered}[/tex]c) finally, divide both sides by (-9) division property of equality
[tex]\begin{gathered} -9x=-18 \\ \text{divide both side by -9} \\ \frac{-9x}{-9}=\frac{-18}{-9} \\ x=2\rightarrow\text{prove} \end{gathered}[/tex]i hope this helps you
I was getting helprd earlier but the last part didn't show up nor did the text messages. heres the question."Frieda Friendly works for a local car dealership. She noticed 3/4 of the cars are sedans and that half are white. What fraction of the dealership's car are white sedans?" *the picture is just the last question*
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3/4 of the cars are sedans
Half are white ( 1/2)
Multiply the fraction of cars that are sedans (3/4) by the fraction that are white (1/2)
[tex]\frac{3}{4}\times\frac{1}{2}=\frac{3}{8}[/tex]Just divide the fraction to obtain the decimal:
3/8 = 0.375
Multiply by 100 to obtain the percent:
0.375 x 100 = 37.5%
i have already graphed the problem, please help me fill in the following.
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ANSWER
There are 3 major points to prove that a quadrilateral is a rhombus
1. Indicate that the diagonals of the shape are bisectors that are perpendicular to each other
2. Indicate that the diagonal of the shape bisects both pair of opposite angles
3. Indicate that the shape is a parallelogram with sides of the same length
3. Suppose an investment of $5000 doubles every 12 years. How much is the investment worth after: 24 years?
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Money = $5000
time = 12 years
investment after 24 years
If the investment doubles every 12 years after 24 years the total amount of money will be $10000.0
What is the difference between the inverse function of quadratic and exponential
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Answer:
Quadratic functions are those where their rate of change changes at a constant rate. Exponential functions are those where their rate of change is proportional to itself.
Step-by-step explanation:
An example of a quadratic function would be the shape that a ball makes when you throw it. Gravity causes a constant acceleration, the ball slows down as it is moving up, and then it speeds up as it comes down.
An example of an exponential function would be the population of a bacterium as long as there is enough space and nutrients or how your money grows with compound interest in a bank.
the bearing from S to R is 160° what is the bearing of S from R
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.
The bearing of S from R is given as;
[tex]90+90+90+70=340\degree[/tex]the circle below has center E. Suppose that m
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Notice that the triangle △GEF is an isosceles triangle, since GE=EF (both sides are radii of the circle).
Since △GEF is an isosceles triangle with GE=EF, then the measure of the angles opposed to those sides is the same:
[tex]m\angle GFE=m\angle EGF[/tex]Since the line FH is tangent to the circle, the angle ∠HFE is a right angle.
Since ∠HFG and ∠GFE are adjacent angles, then:
[tex]m\angle\text{HFG}+m\angle\text{GFE}=m\angle\text{HFE}[/tex]Substitute m∠HFG=62 and m∠HFE=90 to find m∠GFE:
[tex]\begin{gathered} 62+m\angle\text{GFE}=90 \\ \Rightarrow m\angle GFE=28 \end{gathered}[/tex]Since the sum of the internal angles of any triangle is 180 degrees, then:
[tex]m\angle\text{GFE}+m\angle\text{EGF}+m\angle\text{FEG}=180[/tex]Substitute the values of m∠GFE and m∠EGF:
[tex]\begin{gathered} 28+28+m\angle\text{FEG}=180 \\ \Rightarrow\angle FEG=124 \end{gathered}[/tex]Therefore:
[tex]\begin{gathered} \text{m}\angle\text{FGE}=28 \\ m\angle FEG=124 \end{gathered}[/tex]15. Find m<1.
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Observing the given figure n< 1 can be found using the Vertical angel theorem to be 132.75 degrees
What is vertical angle theorem?The vertical angle theorem is used when two straight lines intersect, at their point of intersection four angles are formed. The angles opposite to each other are equal
How to find m< 1 using vertical angle theoremThe figure shows
(x² - 6x)⁰
(x/2 + 42)°
From vertical angle theorem
(x² - 6x)⁰ = (x/2 + 42)°
solving for x by multiplying out by 2
2x² - 12x = x + 84
2x² - 12x - x - 84 = 0
2x² - 13x - 84 = 0
factorizing the parabolic equation gives
(x + 4)(2x-21)
using the positive value of x
x = 21/2
substituting x = 21/2 into (x/2 + 42) gives
= 47.25
sum of angles at a point = 360 degrees
2 * 47.25 + 2 * m< 1 = 360
2 * m< 1 = 360 - 94.5
m< 1 = 265.5/2
m< 1 = 132.75
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mark has a bag containing a mixture of 30 green and white marbles.
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SOLUTION:
From the experiment performed;
Mark got 10 green marbles and 5 white marbles after 15 trials. Since the number of green marbles gotten in the experiment is more than the white, the conclusion best supported by the experiment is ;
The bag contains more green than white marbles.
The bank requires that customers select a PIN (personal identification number) so ATM’s can be accessed. The PIN must be 3 digits followed by one letter. How many different PIN numbers can be selected if the first digit cannot be zero?
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Answer:
A lot
Step-by-step explanation:
use random numbers from 1 to 9 and or 0, after the first natural number. And different letters, so there is no specific amount to say that can be used.