f(x)=1-x when f(x)=2

Answers

Answer 1

By solving the equation, we know that f(x) = 1 - x is - 1 when f(x) =  2.

What are equations?In mathematical equations, the equals sign is used to show that two expressions are equal.An equation is a mathematical statement that uses the word "equal to" in between two expressions of the same value.As an illustration, 3x + 5 equals 15.There are many different types of equations, including linear, quadratic, cubic, and others.The three primary types of linear equations are slope-intercept, standard, and point-slope equations.

So, f(x) = 1 - x when f(x)=  2:

Solve for f(x) as follows:

f(x) = 1 - xf(x) = 1 - 2f(x) = - 1

Therefore, by solving the equation, we know that f(x) = 1 - x is - 1 when f(x) =  2.

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Related Questions

Gourmet Eatery has a policy of automatically adding a 18% tip to every restaurant Bill if a restaurant bill is $12 how much is it

Answers

Let:

B = Bill

C = Cost of the meal

T = Tip

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a cyclist rides her bike at a speed of 30 kilometers per hour. what is the speed in miles per hour? how many miles will the cyclist travel in 5 hours?

Answers

Answer:

the answer is 9.321 miles

A family of four went to an amusement park for their vacation. They started the vacation with $426.They spent a total of $198 the first three days.If they divided the remainder of the money evenly between the family members for souvenirs, how much did each person have to spend?

Answers

They started the vacation with $426

After spending $198 the first three days, the remainder is $426 - $198 = $228

Given that there are 4 family members, we have to divide this remainder by 4, that is, $228/4 = $57

Each person has $57 to spend

For each level of confidence o below, determine the corresponding normal confidence interval. Assume each confidence interval is constructed for the same sample statistics.Drag each normal confidence interval given above to the level of confidence

Answers

Note that the width of the confidence interval increases as the confidence level increases.

Since the confidence intervals constructed are for the same sample statistic, the higher confidence interval will have a higher width.

The confidence levels have the following widths:

Therefore, the confidence intervals are matched such that the lowest interval has the smallest confidence level and the highest has the largest confidence level. This is shown below:

For lunch, Kile can eat a sandwich with either ham or a bologna and with or without cheese. Kile also has the choice of drinking water or juice with his sandwich. The total number of lunches Kile can choose isA. 12B. 8C. 4D. 6

Answers

Okay, here we have this:

She can eat the following options:

Sandwich with ham with or without cheese. Two choices.

Sandwich with bologna with or without cheese. Other two choices

This mean that she can eat:

Sandwich with ham with cheese with water or juice. Two options.

Sandwich with ham without cheese with water or juice. Two options.

Sandwich with bologna with cheese with water or juice. Two options.

Sandwich with bologna without cheese with water or juice. Two options.

Finally we obtain a total of: 2+2+2+2=8 options of lunches.

Thw

For the data values 69, 54, 27, 43, 69, 56, the mean is 53.

Answers

From the table given,

To find the x - mean,

By the summation of all the x - mean

The value of x - mean is

[tex]x-\operatorname{mean}=16+1-26-10+16=-3[/tex]

Hence, the value of x - mean is -3

To find the (x - mean)²

By the summation of all the values of (x - mean)²

The value of (x - mean)² is

[tex](x-\operatorname{mean})^2=256+1+676+100+256=1289[/tex]

Hence, the value of (x - mean)² is 1289

The entire graph of the function h is shown in the figure below.
Write the domain and range of h using interval notation.
(a) domain=
(b) range =

Answers

The Domain is [-2, 5] and Range is [3, -4]

What is Domain and range ?

The domain and range are defined for a relation and they are the sets of all the x-coordinates and all the y-coordinates of ordered pairs respectively.

a.) Here in graph, see the x-axis for to find Domain

You'll notice that -2 is point where the point is marked as lowest after that there is no line or point is there and the highest it goes up to the blue line is reached is 5 in x-axis.

so, the Domain is [-2, 5]

b.) For the range you to look at y-axis, just observe the highest and lowest point in graph you'll be able to find range.

hence, the Range is [3, -4]

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how much would EZ Excavation charge to haul 40 cubic yards of dirt

Answers

Given the line on the graph, we have that it passes through the points (1,25) and (2,50), then we can find the relation function with the slope-point equation of the line:

[tex]\begin{gathered} \text{slope:} \\ m=\frac{y_2-y_1}{x_2-x_1} \\ \Rightarrow m=\frac{50-25}{2-1}=\frac{25}{1}=25 \\ y-y_1=m(x-x_1) \\ \Rightarrow y-25=25(x-1) \\ \Rightarrow y=25x-25+25=25x \\ y=25x \end{gathered}[/tex]

we have that the cost of the dirt is given by the equation y=25. To find how much would it be for 40 cubic yards of dirt, we make x=40 and we get the following:

[tex]\begin{gathered} x=40 \\ \Rightarrow y=25\cdot40=1000 \\ y=1000 \end{gathered}[/tex]

therefore, the cost to haul 40 cubic yards of dirt is $1000

what is the simplified ratio of 32:24

Answers

Answer:

4/3

Step-by-step explanation:

The simplest form of

32: 24

is 43

Steps to simplifying fractions

Find the GCD (or HCF) of numerator and denominator

GCD of 32 and 24 is 8

Divide both the numerator and denominator by the GCD

32 ÷ 8

24 ÷ 8

Reduced fraction:

4/3

Therefore, 32/24 simplified to lowest terms is 4/3.

=

A ball is thrown from a height of 156 feet with an initial downward velocity of 8 ft/s. The ball's height h (in feet) after t seconds is given by the following.
h=156-81-161²
How long after the ball is thrown does it hit the ground?
Round your answer(s) to the nearest hundredth.

Answers

The time taken by the ball to hit the ground is 2.88 sec.

What is termed as the distance?Distance is defined as an object's total movement without regard for direction. Distance can be defined as how much surface an object has covered regardless of its starting or closing point.

For the given question,

The total height from which the ball is thrown is 156 feet.

Let 'h' be the height after the time 't' sec.

The equation for the relation of the height and the times is;

h = 156 - 8t - 16t²

The initial velocity of the ball is 8 ft/s. .

When the ball hit the ground the height will become zero.

156 - 8t - 16t² = 0.

Divide the equation by -4.

4t² + 2t - 34 = 0

Solve the quadratic equation using the quadratic formula to find the time.

t = 2.88 sec.

Thus, the time taken by the ball to hit the ground is 2.88 sec.

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The correct question is-

A ball is thrown from a height of 156 feet with an initial downward velocity of 8 ft/s . The ball's height h (in feet) after t seconds is given by the following. h=156-8t-16t²

How long after the ball is thrown does it hit the ground?

Round your answer(s) to the nearest hundredth.

Convert 145 to base 4

Answers

Answer:

Converting 145 to base 4 will give;

[tex]2101_4[/tex]

Explanation:

We want to convert;

[tex]145_{ten}\text{ to base 4}[/tex]

Converting, we have;

[tex]\begin{gathered} 145\text{ }\div\text{ 4 } \\ 36\text{ }\div\text{ 4 R 1} \\ 9\text{ }\div\text{ 4 R 0} \\ 2\text{ }\div\text{ 4 R 1} \\ 0\text{ R 2} \end{gathered}[/tex]

Therefore, converting 145 to base 4 will give;

[tex]2101_4[/tex]

100 Points.
A rectangle has sides measuring (2x + 5) units and (3x + 7) units.
Part A: What is the expression that represents the area of the rectangle? Show your work.

Part B: What are the degrees and classifications of the expression obtained in Part A?

Part C: How does Part A demonstrate the closure property for the multiplication of polynomials?

Answers

The expression that represents the area of the rectangle is   [tex]6x^{2}[/tex]+29x + 35 square units , the degree of the obtained expression is 2.

According to the question,

We have the following information:

A rectangle has sides measuring (2x + 5) units and (3x + 7) units.

A) We know that following formula is used to find the area of rectangle:

Area = length*breadth

Area = (3x+7)(2x+5)

Area = [tex]6x^{2}[/tex] + 15x +14x + 35

Area =  [tex]6x^{2}[/tex] +29x + 35 square units

B) The degree of an expression is the highest power of the expression. In  this case, the highest power is 2. Hence, the degree of the expression obtained is 2.The expression can be classifies as a quadratic polynomial.

C) Part A demonstrates the closure property for the multiplication of polynomials because the expression within the brackets are polynomials and the result obtained is also a polynomial.

Hence, the area of the rectangle is [tex]6x^{2}[/tex] +29x + 35 square units and the degree of the obtained expression is 2.

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Solve for basic equation x2x+3=-3x-12

Answers

Solution

We have the following equation:

2x +3 = -3x-12

We can solve for x on this way:

5x = -12-3

5x = -15

Dividing both sides by 5 we got:

x= -3

StatusExam9 ft.15 ft.The volume ofthe figure iscubic feet.15 ft.15 ft.

Answers

Step 1:

The figure is a composite figure with a square base pyramid and a cube.

Step 1:

The volume of the composite shape is the sum of the volume of a square base pyramid and a cube.

[tex]\text{Volume = L}^3\text{ + }\frac{1}{2}\text{ base area }\times\text{ height}[/tex]

Step 3:

Given data

Cube

Length of its sides L = 15 ft

Square base pyramid

Height h = 9 ft

Length of the square base = 15 ft

Step 4:

Substitute in the formula.

[tex]\begin{gathered} \text{Volume = 15}^3\text{ + }\frac{1}{3}\text{ }\times15^2\text{ }\times\text{ 9} \\ \text{= 3375 + 675} \\ =4050ft^3 \end{gathered}[/tex]

Ms wash investdd $22000 in two accounts, one yielding 8% interest and the other yielding 11%. if she recieved a total of $1910 in interest at the end of the year, how much did she invest in each accouny

Answers

Take into account the following formula for the simple interest:

[tex]I=P\cdot r\cdot t[/tex]

where:

P: principal investment

r: interest rate

t: time

In order to determine the investments for both accounts, proceed as follow:

-Consider that both investments are represented by P1 and P2 respectively, then, you have:

[tex]\begin{gathered} P_1+P_2=22000 \\ P_2=22000-P_1 \end{gathered}[/tex]

- Next, use the given values for parameters r and t for each investment:

8% = 0.08

11% = 0.11

t = 1 year

[tex]\begin{gathered} I_1=P_1\cdot0.08\cdot1=0.08P_1 \\ I_2=P_2\cdot0.11\cdot1=0.11P_2 \end{gathered}[/tex]

- Next, consider that the sum of the total earnings is $1910, then:

[tex]I_1+I_2=1910[/tex]

- Replace I1 and I2 by the expressions in terms of P1 and P2 and write down the resultant expression in terms of P1, as follow:

[tex]\begin{gathered} 0.08P_1+0.11P_2=1910 \\ 0.08P_1+0.11(22000-P_1)=1910 \\ 0.08P_1+2420-0.11P_1=1910 \\ -0.03P_1=-510 \\ P_1=\frac{510}{0.03}=17000 \end{gathered}[/tex]

And for P2:

[tex]\begin{gathered} P_2=22000-P_1 \\ P_2=22000-17000=5000 \end{gathered}[/tex]

Hence, the amount of money invested in each account was $5000 and $17000

What’s the correct answer answer asap for brainlist

Answers

Answer:

Answer is B. Harding, Coolidge, and Hoover
:)

What is the standard form of the equation of a line passing through points (2,3) and (2,-5)?

Answers

Answer:

[tex]x\text{ = 2}[/tex]

Explanation:

Here, we want to find the standard form of the equation

We have the standard form as:

[tex]Ax\text{ + By = C}[/tex]

We can arrive at this using the two-points form:

This is:

[tex]\frac{y_2-y_1}{x_2-x_1}\text{ = }\frac{y-y_1}{x-x_1}[/tex]

(x1,y1) = (2,3)

(x2,y2) = (2,-5)

Now, as we can see, the line is a vertical line since the x-value is the same

Thus, we have it that:

[tex]x\text{ = c}[/tex]

where c will represent the x-intercept

Thus, we have the equation of the line as:

[tex]x\text{ = 2}[/tex]

Which inference about the man is best supported by the events in the text?

Answers

[tex]\begin{gathered} y=2x+2 \\ \text{its a straight line equation.} \\ \text{You can find the value of y, if you have a value for x} \end{gathered}[/tex]

The graph below shows the number of snowballs, y, needed to make x snowmen.
Number of Snowballs
15
10
S
(1,3)
(3,9)
(4, 12)
+
2
Number of Snowmen
3 4 5
How many snowballs are needed to make 2 snowmen?

Answers

The number of snowballs that  are needed to make 2 snowmen is equal to 6.

How to write a proportional equation?

Mathematically, a proportional relationship can be represented by the following equation:

y = kx

Where:

k is the constant of proportionality.y and x represent the variables in a proportional relationship.

Next, we would determine the constant of proportionality (k) for the data points on this graph as follows:

k = y/x

k = 3/1 = 9/3 = 12/4 = 3

When the number of snowmen, x = 2, the number of snowballs, y is given by:

y = kx

y = 3 × 2

y = 6.

Therefore, the ordered pair is equal to (2, 6).

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used to name a point

Answers

Answer:

It is represented by a dot and named by a capital letter

Step-by-step explanation:

Which vehicle has the smallest total volume?What is the volume?

Answers

The formula for the volume is,

[tex]V=\text{length}\cdot\text{ width}\cdot\text{ height}[/tex]

Determine the volume of Van.

[tex]\begin{gathered} V=10\cdot6\frac{1}{2}\cdot6 \\ =60\cdot\frac{13}{2} \\ =390 \end{gathered}[/tex]

Determine the volume of small truck.

[tex]\begin{gathered} V_1=11.3\cdot7.5\cdot6.75 \\ =572.0625 \end{gathered}[/tex]

Determine the volume of 2-bedroom moving truck.

[tex]\begin{gathered} V=14\frac{1}{2}\cdot\frac{77}{12}\cdot7\frac{1}{6} \\ =\frac{29}{2}\cdot\frac{77}{12}\cdot\frac{43}{6} \\ =666.798 \end{gathered}[/tex]

Determine the volume of 3 bedroom truck.

[tex]\begin{gathered} V=20.5\cdot7.7\cdot8.5 \\ =1341.725 \end{gathered}[/tex]

Determine the mega moving truck.

[tex]\begin{gathered} V=22\frac{1}{4}\cdot7\cdot9\frac{1}{3} \\ =1453.666 \end{gathered}[/tex]

The smallest volume is equal to

Given the zeros of the following polynomial 2 +2i, 3, - 4 select the corresponding factors AND the polynomia O (x + 2i) (2 - 2i) (2 - 3)(x+4) o f(c) = 24 - 23 822 - 42 - 48 0 (2 – 2i) (x + 2i) (2+3)(– 4) 24 – 13 + 82 40 - 48 0 (0 - 2) (+2)(x - 3)(x +4) 24 - 23 - 822 + 4x + 48 1 3 N

Answers

a)

d)

1) Since the zeros of that polynomial were given, then we can write it into the factored form. Note that there are 4 zeros, so we can write:

[tex]\begin{gathered} (x-x_1)(x-x_2)(x-x_3)(x-x_4)=0 \\ (x-(-2i))(x-2i)(x-3)(x-(-4))=0 \\ (x+2i))(x-2i)(x-3)(x+4))=0 \end{gathered}[/tex]

2) To find out the corresponding polynomial then we can expand it by rewriting "i" as -1

[tex]\begin{gathered} (x+2i))(x-2i)(x-3)(x+4) \\ (x+2i)(x-2i)=x^2+4 \\ (x-3)(x+4)=x^2+4x-3x-12 \\ (x^2+4)(x^2+x-12) \\ x^4+x^3-8x^2+4x-48 \end{gathered}[/tex]

3) Hence, the answers are

a)

d)

[tex]x^4+x^3-8x^2+4x-48[/tex]

The area of the unshaded region is 22.5cm2 . What is the area of the rectangle?A) 11.25cm2B) 22.5cm2C) 45cm2D) 90cm2

Answers

Let's use the variable b to represent the white triangle base (which is the width of the rectangle), and the variable h to represent the white triangle height (which is the length of the rectangle).

The white triangle area is given by:

[tex]A=\frac{b\cdot h}{2}=22.5\text{ cm}^2[/tex]

The area of the rectangle is given by the product of its length and its width, so we have:

[tex]A_2=b\cdot h=2\cdot(\frac{b\cdot h}{2})=2\cdot A=2\cdot22.5=45\text{ cm}^2[/tex]

Therefore the correct option is C.

A basketball player shooting from the foul line has a 40% chance of getting a basket. He takes five shots. Whether he scores on one shot is independent of what he does on another shot. What is the probability that he misses at most one basket (rounded off to three decimals)?

Answers

The probability that the basketball player misses at most one basket is 0.077 as it is a mutually exclusive event.

what are mutually exclusive events in probability?

Two events are said to be mutually exclusive if they cannot occur at the same time or simultaneously. This implies they are disjoint events and the probability of both events occurring at the same time will be zero.

Let us represent the probability of the player getting a basket to be p(y) and that of not getting a basket to be p(x)

then p(y)=40%=40/100=2/5

p(x)=1-(2/5)=3/5

The probability the player misses at most one basket implies his highest miss is one out of the five shots he took

So, the probability that he missed the:

1st shot= (3/5)×(2/5)×(2/5)×(2/5)×(2/5)=48/3125

2nd shot= (2/5)×(3/5)×(2/5)×(2/5)×(2/5)=48/3125

3rd shot= (2/5)×(2/5)×(3/5)×(2/5)×(2/5)=48/3125

4th shot= (2/5)×(2/5)×(2/5)×(3/5)×(2/5)=48/3125

5th shot= (2/5)×(2/5)×(2/5)×(2/5)×(3/5)=48/3125

The probability that he misses at most one basket= (48/3125)+(48/3125)+(48/3125)+(48/3125)+(48/3125)+(48/3125)= 249/3125=0.0768.

Finally, from the workings the probability that the player misses at most one basket is 0.077 rounded up to three decimals

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The table of values represents a quadratic function.What is the average rate of change for f(x) from x=−10 to x = 0?Please help me with this problem so that my son can understand better. Enter your answer in the box.xf(x)−10184−5390−654910204

Answers

We are given a quadratic function and the rather than the equation for this function we already have the outputs at each given input as shown in the table provided. This means, for example, for the function given, when the input is -10, the output is 184. Thus the table includes among other values;

[tex]x=-10|f(x)=184[/tex]

To calculate the average rate of change we shall apply the formula for the slope (which is also the average rate of change). This is given below;

[tex]\text{Aerage Rate of Change}=\frac{f(b)-f(a)}{b-a}[/tex]

Note that the variables are;

[tex]\begin{gathered} f(a)=\text{first input value} \\ f(b)=\text{second input value} \end{gathered}[/tex]

The first input value is -10 and the function at that value is 184

The second input value is 0 and the function at that value is -6

We now have;

[tex]\begin{gathered} a=-10,f(a)=184 \\ b=0,f(b)=-6 \end{gathered}[/tex]

We can now substitute these into the formula shown nearlier and we'll have;

[tex]\begin{gathered} \text{Ave Rate Of Change}=\frac{f(b)-f(a)}{b-a} \\ =\frac{-6-184}{0-\lbrack-10\rbrack} \end{gathered}[/tex][tex]\begin{gathered} =\frac{-190}{0+10} \\ \end{gathered}[/tex][tex]=\frac{-190}{10}[/tex][tex]\text{Average Rate of Change}=-19[/tex]

ANSWER:

The average rate of change over the given interval is -19

Crystal's favorite playlist has 80 rock songs, 40 jazz songs, 25 country songs, 30 hip hop songs, and 45 classical music songs. Which of thesestatements is true?

Answers

This problem tests the knowledge of the probability of a random event occuring: of playing a type of song from a variety of different song types

Thus, we have to compute the probability that each type of song is played.

To do this, we need to obtain the total number songs, as follows:

80 + 40 + 25 + 30 + 45 = 220

Thus, the probabilities are now easily computed as follows:

P(rock) = 80/220

P(jazz) = 40/220

P(country) = 25/220

P(hip hop) = 30/220

P(classical) = 45/220

Now:

Option 1 (the first statement in the options) claims that : P(rock) = 2 * P(hip hop)

However, 2 * P(hip hop)

a scientist need to 6000 calories per day. Based on the percentage of total daily calories and the number of calories needed, how many biscuits, packages of pemmican, butter and coco does a person need each day?

Answers

EXPLANATION:

Given;

We are told that a scientist needs 6000 calories per day.

We are also given a table showing the percentage of daily calories he can get from three types of food.

These are;

[tex]\begin{gathered} Biscuits---40\% \\ pemmican---45\% \\ Butter\text{ }and\text{ }cocoa---15\% \end{gathered}[/tex]

Required;

We are required to calculate how many of each type of food he would need to eat each day.

Step-by-step solution;

We shall solve this by first determining how many calories can be gotten from each type of food based on the percentage given. This is calculated below;

[tex]\begin{gathered} Biscuits: \\ 6000\times\frac{40}{100}=2400 \end{gathered}[/tex]

This means if he gets 75 calories from one biscuit, then to get 2,400 calories he would have to eat;

[tex]\begin{gathered} 75cal=1b \\ 2400cal=\frac{2400}{75} \\ 2400cal=32 \end{gathered}[/tex]

The scientist would have to eat 32 biscuits to get 2400 calories.

[tex]\begin{gathered} Pemmican: \\ 6000\times\frac{45}{100}=2700 \end{gathered}[/tex]

This means if he gets 135 calories from one pack of dried meat, then to get 2700 calories he would have to consume;

[tex]\begin{gathered} 135cal=1pack \\ 2700cal=\frac{2700}{135} \\ 2700cal=20 \end{gathered}[/tex]

Therefore, the scientist would have to eat 20 packs of pemmican to get 2700 calories

[tex]\begin{gathered} Butter\text{ }and\text{ }Cocoa: \\ 6000\times\frac{15}{100}=900 \end{gathered}[/tex]

This means if he eats 1 package of Butter and cocoa he gets 225 calories. To get 900 calories he would have to eat;

[tex]\begin{gathered} 225cal=1pack \\ 900cal=\frac{900}{225} \\ 900cal=4 \end{gathered}[/tex]

Therefore, the scientist would have to eat 4 packs of Butter and cocoa.

We now have the summary as follows;

ANSWER:

[tex]\begin{gathered} Biscuits=32 \\ Pemmican=20\text{ }packs \\ Butter\text{ }and\text{ }cocoa=4\text{ }packs \end{gathered}[/tex]

From 1999 to 2009, the number of dogs [tex]D[/tex] and the number of cats [tex]C[/tex] (in hundreds) adopted from animal shelters in the United States are modeled by the equations [tex]D = 2n+3[/tex] and [tex]C = n +4[/tex], where [tex]n[/tex] is the number of years since 1999.

a. Write a function that models the total number [tex]T[/tex] of adopted dogs and cats in hundreds for that time period.

b. If this trend continues, how many dogs and cats will be adopted in 2013?

Answers

The functions that models the number of adopted dogs and cat is T = 3n + 7.

If the trend continues, the number of cats and dog that will be adopted by 2013 is 4600.

How to find the function that models a problem?

From 1999 to 2009, the number of dogs  D and the number of cats  C (in hundreds) adopted from animal shelters in the United States are modelled by the equations D = 2n + 3 and C = n + 4, where n is the number of years since 1999.

Therefore, the functions that models the total number T of the adopted dogs and cats in hundreds for that time period can be represented as follows:

T = D + C

where

D = 2n + 3

C = n + 4

where

n = number of years

T = 2n + 3 + n + 4

T = 3n + 7

b. If the trends continues the number of cats and dogs that will be adopted in 2013 can be calculated as follows:

n =  2013 - 1999 = 13

Hence,

T = 3(13) + 7

T = 39 + 7

T = 46

Recall it's represented in hundred's

Therefore, 4600  dogs and cat will be adopted by 2013

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The following statements "If you are wearing a helmet, you are riding a bike." and "If you are not riding a bike, you are not wearing a helmet." are an example of a _____ statement.Select one:a.inverseb.conversec.contrapositive

Answers

Given:

The given statements are,

"If you are wearing a helmet, you are riding a bike."

"If you are not riding a bike, you are not wearing a helmet."

Required:

To identify the kind of statements.

Explanation:

We have the given statement:

"If you are wearing a helmet, you are riding a bike."

Here, p : you are wearing a helmet

q : you are riding a bike

Thus, taking negation of both the parts of the statement as follows:

If not q, then not p.

Hence, the statement formed is,

"If you are not riding a bike, you are not wearing a helmet."

This is the contrapositive statement.

Final Answer:

Given statements are an example of contrapositive.

Rewrite the following expression so it does not contain any radical term

Answers

Given:

The expression is given as,

[tex]\sqrt[]{36p^{10}m^6}[/tex]

The objective is to rewrite the expression without any radical form.

Explanation:

The given expression can be written as,

[tex]\sqrt[]{36p^{10}m^6}=\sqrt[]{6^2p^{10}m^6}\text{ . . . . .(1)}[/tex]

In general, the radical form of a square root can be written as,

[tex]\sqrt[]{x}=x^{\frac{1}{2}}[/tex]

Then, the equation (1) can be written as

[tex]\sqrt[]{36p^{10}m^6}=(6^2p^{10}m^6)^{\frac{1}{2}}[/tex]

On further solving the above expression,

[tex]\begin{gathered} \sqrt[]{36p^{10}m^6}=6^{2\times\frac{1}{2}}p^{10\times\frac{1}{2}}m^{6\times\frac{1}{2}} \\ =6p^5m^3 \end{gathered}[/tex]

Hence, the simplified expression of the given term is,

[tex]6p^5m^3[/tex]

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