General nucleus and electron attraction explained

Answer:

Explanation:

Carbon is the only element listed. Carbon Dioxide consists of Carbon AND Oxygen x2 so this is a compound. As stated earlier, air is a mixture of compounds. Water is another compound consisting of Hydrogen x2 and Oxygen.

Ca(NO3)2 and H₂O. Option C is correct

The combination of acid and base to form salt and water at the product is known as a neutralization reaction.

Hence the products of the neutralization reaction between HNO3 and Ca(OH)2 must be salt and water

From the given option, the equivalent product that are salt and water is Ca(NO3)2 and H₂O which gives the required product.

The general molecular equation is; [tex]Ba(CH3COO)_{2} (aq) + Na_{3} PO_{4} ------ > Ba_{3} (PO_{4})_{2} (s)+ Na(CH3COO)_{2} (aq)[/tex] while the net ionic equation is; [tex]2PO_{4} }^{3-} (aq) + 3Ba^{2+ } (aq) ------- > Ba_{3} (PO_{4})_{2} (s)[/tex]

We can define the term reaction as the interaction that occurs between the reactants and helps us to be able to get a product as shown. Now we have a case in which we are asked to write the molecular, ionic and net ionic equation, with the phases of matter for the reaction between Barium acetate + Sodium phosphate --> Barium phosphate + Sodium acetate.

The task now is to make use of the ideas that we have from the question to be able to determine both the molecular reaction equation as well as the net ionic equation as required.

Let us no take the reaction individually. We can write the molecular reaction as;

[tex]Ba(CH3COO)_{2} (aq) + Na_{3} PO_{4} ------ > Ba_{3} (PO_{4})_{2} (s)+ Na(CH3COO)_{2} (aq)[/tex]

After we have written the molecular reaction equation, then we can identify the spectator ions as  acetate ion and the sodium ion as we can see from the balanced reaction equation.

The net ionic equation therefore is;

[tex]2PO_{4} }^{3-} (aq) + 3Ba^{2+ } (aq) ------- > Ba_{3} (PO_{4})_{2} (s)[/tex]

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The process of photosynthesis used by plant in which they produce sugar ( glucose ).

Photosynthesis is the process in which plants produced sugar by using sun - light , water and carbon dioxide. In the process of photosynthesis plants use carbon dioxide ( CO₂ ) and water H₂O from the air and the soil  then this carbon dioxide and water transforms to oxygen and sugar (glucose). the oxygen produced by plant back into the air and the sugar produces stores by the plant as the form of energy.

                                                sunlight

carbon dioxide  +   water       -------------->     glucose   +   oxygen

In the leaf cell a part called chloroplast in it energy in sunlight used to break oxygen and hydrogen. T he water required in the process of photosynthesis taken by the roots from soil and then it transport with the help of xylem cell to the different parts of plant. phloem takes sugar from leaves to different parts of plant. The stomata is for the transpiration exchange that means it takes carbon dioxide and the release oxygen back to air after the photosynthesis end.

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Answer:

586.846 lbs

Explanation:

the molar mass of HCl is 1 + 35.45 = 36.45

this means you can do 16.1 lbmol * 36.45 lb/lbmol = 586.845

1) Subatomic particles. Atoms are made up of smaller parts called subatomic particles. Proton, neutron, and electron are some of them.

Electron: 9.11*10^-31 kg.

Proton: 1.672 18*10^-27 kg.

Neutron: 1.674 93*10^27 kg.

The lightest subatomic particle is the electron, then comes the protons, and finally the electron.

Isotopes of certain __radioactive__ elements that spontaneously emit __radiation__ and _rays___ from the __nuclei____

Any of multiple species of the same chemical element with differing masses whose nuclei are unstable and spontaneously produce radiation in the form of alpha, beta, and gamma rays are known as radioactive isotopes, also known as radioisotopes, radionuclides, or radioactive nuclides.

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The moles of gas added could not be determined because of an apparent error in the data provided for the volume of the container.

The moles of gas in the container is calculated from the ideal gas equation as follows;

Data given:

P = 131,874 Pa or 131.874 kPa

V = 54.7 mL = 0.0547 L

T = 113.7 °C or (113.7 + 273) K

T = 386.7 K

R, molar gas constant  = 8.314 L⋅kPa.K/mol

n = (131.874 * 0.0547 L) / (8.314 * 386.7 )

n = 0.000224 moles

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The detailed steps to measure the volume of a piece of rock using a graduated cylinder and beaker are based on Archimedes' Principle, which states that an object that is displacing fluid has a weight equal to that of the object it is displacing.

The submersion or dunking method is another name for the displacement method.

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The molecular formula for the compound that contains 4.90 g N and 11.2 g O is N₂O₄

We'll begin by obtaining the empirical formula for the compound. This is illustrated below:

Divide by their molar mass

N = 4.9 / 14 = 0.35

O = 11.2 / 16 = 0.7

Divide by the smallest

N = 0.35 / 0.35 = 1

O = 0.7 / 0.35 = 2

Thus, the empirical formula of the compound is NO₂

Finally, we shall determine the molecula formula. Details below

Molecular formula = empirical × n = molar mass

[NO₂]ₙ = 92

[14 + (16×2)]ₙ = 92

46n = 92

Divide both side by 46

n = 92 / 46

n = 2

Molecular formula = [NO₂]ₙ

Molecular formula = [NO₂]₂

Molecular formula = N₂O₄

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Complete question:

Find the molecular formula for a compound that contains 4.90 g N and 11.2 g O. The molar mass of the compound is 92.0 g/mol.

Answer:

Explanation:

molar mass of 13c = 13 grams

number of moles = mass / molar mass

therefore,

number of moles = 7 / 13

To know the number of atoms in 7/13 moles, we simply multiply the number of moles by Avogadro's number as follows:

number of atoms = (7/13) x 6.022 x 10^23 = 3.2426 x 10^23 atoms

Answer

2NaCl + Cal₂ → 2Nal + CaCI₂

Explanation

Given unbalanced equation;

NaCl + _Cal₂ → Nal + CaCI₂

Step 1: Balance the Cl atom on both the reactant and product sides of the equation by putting 2 as the coefficient of NaCl in the reactant side.

2NaCl + _Cal₂ → Nal + CaCI₂

Step 2: Balance the Na atom on both the reactant and product sides of the equation by putting 2 as the coefficient of NaI in the product side.

2NaCl + Cal₂ → 2Nal + CaCI₂

Therefore, the balanced equation is: 2NaCl + Cal₂ → 2Nal + CaCI₂

The concertation of the HI that would be present in the new equilibrium position is 0.15 M.

We have to first obtain the equilibrium constant that we have under the initial conditions and then we have; H2 + I2 ------> 2HI

K = [HI]^2/[H2] [I2]

K = (0.490)^2/(0.080) (0.060)

K = 0.2401/(0.080) (0.060)

K = 50

Again;

                               H2      +      I2                     ------> 2HI

Initial                     0.080           0.060                        0.060

concentration         +x                   +x                            -2x

Equilibrium     0.080 + x      0.060 + x                 0.490 - 2x

50 = (0.490 - 2x)^2/( 0.080 + x) (0.060 + x)

Working through the quadratic we have;

46x^2 + 10.2 x - 0.38 = 0

x = 0.32 M

In each case we now have;

 H2 =  0.080 +  0.32  = 0.4 M

[I2] = 0.060  +  0.32  = 0.38 M

[HI] = 0.790 - 2( 0.32 ) = 0.15 M

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The stability of alkene can be determined by measuring the amount of energy that is associated with the hydrogenation of the molecule.

Because those branched alkanes are more stable than their linear isomers (Figure 1), the origins of this stability are unclear. For each branch in an alkane, the measured heat of formation is lower than expected by about 2 kcal mol−1 in comparison to the linear isomer. The fullness structures in which all atoms have complete valence shells are more stable. The structures with the least number of ritual charges are more stable. The structures with a negative charge on the further electronegative atom will be more stable. The three main factors determining the relative stability of alkenes are i) the number of substituents attached to the double-bond carbon atoms, ii) hyperconjugation, and iii) the stereochemistry of the double bond.

So we can conclude that the more electron-donating alkyl groups are the more stable the alkene

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The concentration of the 25ml of original HNO₃ solution that was neutralized with 31.4 mL of 0.250 M Ba(OH)₂ is 0.628 M HNO3

The neutralization reaction involved with HNO₃ and Ba(OH)2 is

Ba(OH)₂ + 2HNO₃---> Ba(NO₃) + 2H₂O.

From the balanced equation of the reaction, we can say that to neutralize barium hydroxide (Ba(OH)₂) we would require 2 moles of Nitric acid (HNO₃)

By multiplying concentration of barium hydroxide by volume its volume, and then multiplying by 2 as twice is required we would get the moles of HNO3 that is equivalent to 2 moles based on the values

Moles of HNO₃ = 2 (0.0314 * 0.250) = 0.0157 moles

Concentration of the original HNO₃ solution = 0.0157 moles / 0.025 L = 0.628 M HNO₃

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The number of blocks that can be lifted through this height is 11563 blocks.

We know that we define the term energy as the ability to do work, Now we have to consider the fact that we are told that one serving provides 185 kcal. Then we are told that  all of this energy is used to lift 1.0-kg blocks through a distance of  7.0 meters.

Given that the energy exerted in lifting each block is;

mgh

m = mass of the block

g = acceleration due to gravity

h = height lifted through

E = 1.0-kg * 9.8 m/s^2 * 7.0 meters = 68.6 J or 0.016 kcal

The number of blocks that can be lifted =  185 kcal/ 0.016 kcal

= 11563 blocks

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Taking into account the definition of pH and pOH, the concentration of OH⁻ is 1×10⁻² M.

pH is a measure of acidity or alkalinity that indicates the amount of hydrogen ions present in a solution or substance.

The pH is defined as the negative base 10 logarithm of the activity of hydrogen ions:

pH= - log [H⁺]

Similarly, pOH is a measure of hydroxyl ions in a solution and is expressed as the logarithm of the concentration of OH⁻ ions, with the sign changed:

pOH= - log [OH⁻]

The following relationship can be established between pH and pOH:

pOH + pH= 14

Being [H⁺]=1.0×10⁻¹² M, the pH is calculated as:

pH= - log (1.0×10⁻¹² M)

Solving:

pH= 12

Being pH= 4.85, and considering the relationship between pH and pOH, pOH is calculated as:

pOH + 12= 14

pOH= 14 - 12

pOH= 2

Replacing in the definition of pOH the concentration of OH⁻ ions is obtained:

- log [OH⁻]= 2

Solving

[OH⁻]= 10⁻²

[OH⁻]= 1×10⁻² M

In summary, the [OH⁻] is 1×10⁻² M.

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The International System of Units uses the mole (symbol: mol) as the unit of substance amount.

In 5.67 moles of CO2 there exists 249.48 grams of CO2.

Start by dividing the number of atoms by the atomic weight of each component of the compound to convert grams to moles. After that, tally up all of your responses to determine the compound's molar mass. The final step is to calculate the number of moles by dividing the number of grams of the compound by its molar mass.

The International System of Units uses the mole (symbol: mol) as the unit of substance amount. How many elementary entities of a particular substance are present in an object or sample is determined by the quantity of that substance.

Let the equation be

Mass = relative atomic mass × mole number

substitute the values in the above equation, we get

= 5.67 × (12 + 16 + 16)  

= 249.48 g

Therefore, there exists 249.48 grams of CO2 are in 5.67 moles of CO2.

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Answer:

Explanation:

Here, we want to get the percentage by mass of calcium carbonate in the limestone

We start by writing an equation of chemical reaction

The reaction involves calcium carbonate reacting with hydrochloric acid to give calcium chloride, carbon dioxide and water

We have the equation as follows:

Now, let us work with the extra information

16.89 g of calcium chloride are produced

Let us get the number of moles of calcium chloride produced

We can get that by dividing the mass by the molar mass of calcium chloride

The molar mass of calcium chloride is 111 g/mol

So, the number of moles will be:

From the equation,

1 mole of calcite gave 1 mole of calcium chloride, then 0.1522 mole of calcium chloride was produced by 0.1522 mole of calcite

To get the mass of calcite that produced this, we have to multipply the number of moles by the molar mass of calcite

The molar mass of calcite is 100 g/mol

That means the mass of calcite that produced the calcium chloride will be:

What this mean is that 15.22 g of calcite produced the given mass of calcium chloride

The percentage by mass of calcite in the limestone will be:

The volume of carbon dioxide (in L) that can be made from the 2.00 g of the antacid is 5.09 L

We'll beging by obtaining the mole of CO₂ produced. This can be obtained as follow:

CaCO₃ (s) + 2 HCl (aq) → CaCl₂ (aq) + H₂O (l) + CO₂ (g)

From the balanced equation above,

1 mole CaCO₃ reacted to produce 1 mole of CO₂.

Therefore,

0.02 mole CaCO₃ will also react to produce 0.02 mole of CO₂.

Finally, we shall determine the volume of the CO₂ produced. Details below.

PV = nRT

1 × V = 0.02 × 0.0821 × 310

V = 5.09 L

Thus, the volume obtained is 5.09 L

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Explanation:

First, let's write the formulas:

Potassium chlorate: KClO3

Oxygen: O2

Potassium chloride: KCl

So the reaction will be:

KClO3 -> O2 + KCl

Now let's balance it.

To balance the equation it is necessary to have the same number of atoms of each element on both sides of the equation (reactant side and product side). Let's count the number of atoms of each element for the unbalanced equation: KClO3 -> O2 + KCl

Reactant side:

K - 1

Cl - 1

O - 3

Product side:

O - 2

K - 1

Cl - 1

As you can see, oxygen number of atoms is not equal on both sides of the equation. Let's balance it by changing the stoichiometric coefficient.

2KClO3 → 2KCl + 3O2

Let's count the number of atoms of each element for the balanced equation.

Reactant side:

K - 2

Cl - 2

O - 6

Product side:

K - 2

Cl - 2

O - 6

Now the equation is balanced.

Answer: 2KClO3 → 2KCl + 3O2

Coefficients are: 2, 2 and 3.

Aluminum Oxide decomposes to Aluminum metal and Oxygen gas.

- First, write down each compound:

- Second, write the number of moles of each compound, so that we have the same amount of reactants as products. Here, it is important not to change the subscript of compound elements.

For example, let's start by adding a number 2 in front of the aluminum metal to balance:

So far, the amount of aluminum has been balanced but the amount of oxygen is unbalanced, so let's add a number 3 for the oxygen gas.

Now, to have the same amount of moles of oxygen on both sides, let's put a number 2 in the aluminum oxide:

Here, the amount of aluminum moles is unbalanced, so we add a number 4 for the aluminum metal to balance:

- This is the final balanced equation of decomposition of aluminum oxide:

Answer:

b d my good mannnnnnnnnnnn

Answer:

262

Explanation:

Light below the necessary critical frequency doesn't eject electrons from metal because no electrons will be emitted when the light shines on the metal.

This is a term in physics which is used to describe the number of occurrences of a repeating event per unit of time.

The amount of energy which is present in each photon in the beam is determined by and proportional to the frequency of the beam. This therefore means that if there is light which is below the threshold frequency, there will be no electrons emitted when light shines on the metal thereby making it the correct choice.

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The amount of heat energy that must be inputted into the reaction to make 58.9 grams of C₆H₁₂O₆ is 968.574 KJ

We'll begin by obtainig the number of mole of 58.9 grams of C₆H₁₂O₆. This can bbe obtained as follow:

Mole = mass/ molar mass

Mole of C₆H₁₂O₆ = 58.9 / 180

Mole of C₆H₁₂O₆ = 0.327 mole

Finally, we shall determine thhe heat energy needed.

The balanced equation for the reaction is given below:

6CO₂(g) + 6H₂O(g) → C₆H₁₂O₆(g) + 6O₂(g) ΔH = +2962 KJ/mol

From the balanced equation for above,

1 moles of C₆H₁₂O₆ was produced by 2962 KJ of heat energy.

Therefore,

0.327 mole of C₆H₁₂O₆ will be produce by = (0.327 × 2962) / 1 mole = 968.574 KJ of heat energy

Thus, 968.574 KJ of heat energy is needed for the reaction

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Answer:

Al 3+

Na+

Mg2+

F-

Explanation:

The element with the given electron that isn't an ion is Neon. It has 10 electrons in total.

Looking at the periodic table attached will help to see how the elements below are related to the one circled in red (Ne).

Al 3+ lacks 3 (because it has a 3+ charge) of its normal electrons so it has 10 and will have the same electron configuration as shown.

Na+ lacks one electron so it will also have 10 electrons instead of its normal 11.

Mg 2+ lacks two electrons so it will also have 10 total electrons.

F- has gained an extra electron so it now has 10 instead of 9.

Al3+, Na+, F-, and Mg2+ will have the given electronic configuration.

The electronic configuration given in the question is:

2p6, 2s2, 1s2

If it was a stable atom, the answer would have been Neon.

And if that would have been negative ion or anion (to be precise),

the answer would have been either F- or O2-.

But in the case of positive ions or we can say cations,

Al3+, Na+, and Mg2+ have the given electronic configurations.

Because the atom of Aluminum loses three electrons to achieve another state which is responsible for the formation of Al3+.

Similarly,

The atoms of Sodium and Magnesium also lose one and two electrons respectively to form Na+ and Mg2+.

So, we can conclude that Al3+, Na+, F- and Mg2+ will have the given electronic configuration.

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Answer:

Linear (180 degrees)

Explanation:

Whenever you have a triple bond between two atoms, their shape is linear. This is because the density of the triple bond between them is heavy, causing the other things attached to the atom to be as far away as possible, creating a linear structure.

To solve this question, we need to use the Clapeyron formula.

Clapeyron's formula is a mathematical expression that relates quantities such as pressure (P), volume (V), temperature (T) and the number of particles (n) that make up an ideal gas.

The formula is: PV = nRT

First, let's discover the number in moles of N2. We have:

P = 1.5 atm

V = 10 L

n = ???

R = 0.082 atm.L/mol.k

T = 273 K

1.5 x 10 = n x 0.082 x 273

15 = n x 22.386

n = 15/22.386

n = 0.67 moles

As we can see in the chemical reaction equation, the ratio between NaN3 and N2 is 2:3.

So:

2 mol of NaN3 --- 3 mol of N2

x mol of NaN2 --- 0.67 moles

3x = 2 x 0.67

x = 0.45 moles of NaN3

Now we transform this value into grams, using NaN3 formula mass, which is 65 g/mol:

65 g ---- 1 mol

x g ---- 0.45 mol

x = 29 g

Answer: 29 g of NaN3

The number of photons having a wavelength of 16.0 um required to produce 2.3KJ of energy is 1.85 x 10¹⁹

Photons are defined as a basic particle that is both the force carrier for the electromagnetic force and a quantum of the electromagnetic field, which includes electromagnetic radiation like light and radio waves.

It can also be defined as a discrete bundle of electromagnetic energy is what is known as a light particle.

Energy = 2.3 KJ

Wavelength = 16.0 x 10⁶ m

Energy = hc / ∧

            = 6.63 x 10²⁴ x 3 x 10³ / 16.0 x 10⁶

            = 1.24 x 10¹⁹ J

Number of photons used = 2.3 KJ / 1.24 x10¹⁹

                                          = 1.85 x 10¹⁹

Thus, the number of photons having a wavelength of 16.0 um required to produce 2.3KJ of energy is 1.85 x 10¹⁹

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