Gideon took out an R150 000 loan this morning, to buy a house. The interest rate on a mortgage is 7,35%. The loan is to be repaid in equal monthly payments over 20 years. The first payment is due one month from today. How much of the second payment applies to the principal balance? (Assume that each month is equal to 1/12 of a year.)

Answer:

Experimental Procedure:

Materials:

Piece of wood

Electronic balance

Bunsen burner

Heat-resistant mat

Stopwatch or timer

Safety goggles

Lab coat

Safety Precautions:

Wear safety goggles and a lab coat to protect your eyes and clothing from any sparks or flames.

Place the heat-resistant mat under the Bunsen burner to prevent any accidental fires.

Use the Bunsen burner only under adult supervision.

Be cautious when handling hot objects, and allow them to cool before touching.

Procedure:

Measure the initial mass of the piece of wood using an electronic balance, and record it in a table.

Light the Bunsen burner, and place the piece of wood over the flame using tongs. Ensure that the wood is fully engulfed in the flame.

Use a stopwatch or timer to time how long the wood burns for (in this case, 15 minutes).

After 15 minutes, turn off the Bunsen burner and remove the piece of wood from the flame using tongs.

Allow the wood to cool, and then measure its final mass using the electronic balance, and record it in the table.

Calculate the difference between the initial and final mass of the wood, and record it in the table.

Repeat steps 1-6 three times to obtain three sets of data.

Calculate the average mass of the burned wood and compare it to the initial mass of the unburned wood to determine if the student's prediction was correct.

Conclusion:

If the average mass of the burned wood is less than the initial mass of the unburned wood, the student's prediction was correct, and he can conclude that the wood underwent a chemical change when it was burned. If the average mass is greater than or equal to the initial mass, the prediction was incorrect, and the student may need to revise his hypothesis or experimental design.

The volume of the cone is  2119. 5 cubic centimeters

The formula used for calculating the volume of a cone is expressed as;

V = πr² h/3

Given that the parameters are namely;

Now, substitute the values, we have;

Volume , V = 3.14 × 15² × 9/3

Divide the values, we have;

Volume = 3.14 × 225 × 3

Multiply the values, we get;

Volume, V = 2119. 5 cubic centimeters

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Answer:4? Think

Step-by-step explanation:

Answer:

4.88%

Step-by-step explanation:

All sides of a square are equal

let x = length of a side

Area = x·x = x²

Estimated area = (8.5)² = 72.25 in²

Actual area = (8.3)² = 68.89 in²

percent error  = (actual area - estimated area) / (estimated area) x 100

% error = (68.89 - 72.25) / (68.89) x 100 = -4.88%     the negative sign means the estimate was higher than the actual.  

Answer:

(gof)(x) = 14x + 1

Step-by-step explanation:

We can think of (gof)(x) as g(f(x)).  Writing it in this form shows that we must start with the inner function and work our way to the outer function.

Essentially, the input of the inner function yields an output and the output becomes the input of the outer function.

f(x) means that the input is x and since we're given no value for x (e.g. x = so and so), the output is the original function or 2x - 1

Now, this output becomes the input for g(x):

g(2x-1) = 7(2x - 1) + 8

14x -7 + 8

(gof)(x) = 14x + 1

Therefore, the quadratic function in standard form that represents the data in the table is: y = 1/2 x² - 5/2 x + 5.

A function is a mathematical concept that describes the relationship between two sets of numbers. It is a rule that assigns to each input (or element in the domain) exactly one output (or element in the range). In simpler terms, a function is like a machine that takes in a number and produces another number as output, according to some specific rules. The input is usually denoted by x, and the output by f(x), which is read as "f of x". Functions can take many forms, such as linear, quadratic, trigonometric, exponential, logarithmic, and more. They are widely used in mathematics, science, engineering, and many other fields to model and analyze various phenomena.

Here,

To write a quadratic function in standard form, we need to use the general form of the quadratic equation:

y = ax²+ bx + c

where a, b, and c are constants. We can use the values in the table to find these constants.

When x = 2, y = 3

When x = 4, y = 1

When x = 6, y = 3

When x = 8, y = 9

When x = 10, y = 19

Substituting these values into the quadratic equation, we get:

3 = 4a + 2b + c

1 = 16a + 4b + c

3 = 36a + 6b + c

9 = 64a + 8b + c

19 = 100a + 10b + c

We can now use these equations to solve for a, b, and c. One way to do this is to use a matrix equation:

|16 4 1| |a| |1|

|36 6 1| |b| = |3|

|64 8 1| |c| |9|

Using a calculator or matrix software, we can solve for a, b, and c:

a = 1/2

b = -5/2

c = 5

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Answer:

I will not show you the process it is easy the answer is 4.5 or 6 ≈

To subtract 6/7 from 2 1/4, we need to find a common denominator. The least common multiple of 7 and 4 is 28, so we can convert 2 1/4 to 9/4 and 6/7 to 24/28. Then we can subtract:

9/4 - 24/28

= 63/28 - 24/28

= 39/28

Therefore, 2 1/4 - 6/7 = 39/28.

To solve for the blank in 2 5/12 - blank = 2/3, we can start by converting 2 5/12 to an improper fraction:

2 5/12 = (2*12 + 5)/12 = 29/12

Then we can subtract 2/3 from both sides:

2 5/12 - 2/3 = blank

To subtract these fractions, we need to find a common denominator. The least common multiple of 3 and 12 is 12, so we can convert 2/3 to 8/12. Then we can subtract:

29/12 - 8/12

= 21/12

= 7/4

Therefore, the blank in 2 5/12 - blank = 2/3 is 7/4.

To subtract 5 3/8 from 7 1/12, we need to find a common denominator. The least common multiple of 8 and 12 is 24, so we can convert both mixed numbers to improper fractions:

7 1/12 = (712 + 1)/12 = 85/12

5 3/8 = (58 + 3)/8 = 43/8

Then we can subtract:

85/12 - 43/8

= 85/12 - (433)/(83)

= 85/12 - 129/24

= 5/24

Therefore, 7 1/12 - 5 3/8 = 5/24.

To solve for the blank in blank + 7/10 = 2 9/20, we can start by converting 2 9/20 to an improper fraction:

2 9/20 = (2*20 + 9)/20 = 49/20

Then we can subtract 7/10 from both sides:

blank + 7/10 - 7/10 = 49/20 - 7/10

Simplifying the right side:

49/20 - 7/10 = (492)/(202) - (74)/(104) = 98/40 - 28/40 = 70/40 = 7/4

Therefore, blank + 7/10 - 7/10 = 7/4, and solving for blank:

blank = 7/4

Therefore, the blank in blank + 7/10 = 2 9/20 is 7/4.

The probability that a randomly selected student's age is more than 18 years old but no more than 21 years old is 0.57.

What is a continuous random variable's probability?

Continuous random variables are defined as having an infinite number of possible values. A continuous random variable hence has no probability of having an accurate value.

a) In order to create a probability distribution, all potential values of the random variable must be listed along with the related probabilities. We may get the relative frequency (or probability) for each value of the random variable from the above frequency distribution:

Age Frequency Probability

16         3              0.03

17         5              0.05

18        10              0.10

19        15              0.15

20       20             0.20

21        22             0.22

22       17               0.17

Total   92              1.00

b) We can use a histogram to see the probability distribution. The likelihood is represented by the vertical axis, while the age is represented by the horizontal axis. The height of each bar in the histogram should represent the likelihood for that age, with bars for each age value.

With a peak at age 20, the distribution's shape looks to be roughly symmetrical.

c) To get the likelihood that a student chosen at random is under 20 years old, we must add the probabilities for the ages 16, 17, 18, and 19:

P(age < 20) = P(age = 16) + P(age = 17) + P(age = 18) + P(age = 19)

= 0.03+0.05+0.10+0.15

= 0.33

Consequently, there is a 0.33 percent chance that a randomly chosen student is under 20 years old.

d) To determine the likelihood that a randomly chosen student is older than 18 but not older than 21, we must add the probabilities for the ages 19, 20, and 21:

P(18 < age ≤ 21) = P(age = 19) + P(age = 20) + P(age = 21)

= 0.15 + 0.20 + 0.22

= 0.57

As a result, there is a 0.57 percent chance that a randomly chosen student will be older than 18 but not older than 21.

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Answer: Reflection in the y -axis:

Explanation: The rule for a reflection over the y -axis is (x,y)→(−x,y) .\

To find the area of the total figure, we need to first find the areas of the rectangle and triangle, and then add them together.Therefore, the area of the total figure is 200 square feet.

Area is the measurement of the size of a two-dimensional surface enclosed by a closed figure

Area of rectangle = length x width

= 20 ft x 8 ft

= 160 sq. ft

Area of triangle = 1/2 xbase xheight

= 1/2 x 8 ft x 10 ft

= 40 sq. ft

To find the base of the triangle, we can use the Pythagorean theorem, which states that the square of the hypotenuse (slope) of a right triangle is equal to the sum of the squares of its two sides. In this case, the hypotenuse is 12 ft, one of the other sides is the height of the triangle (10 ft), and the other side is the base of the triangle (b).

Using the Pythagorean theorem, we have:

12² = 10² + b²

144 = 100 + b²

44 = b²

b = √44

b ≈ 6.63 ft

Now that we know the base of the triangle, we can find the area of the total figure by adding the area of the rectangle and the area of the triangle:

Area of total figure = area of rectangle + area of triangle

= 160 sq. ft + 40 sq. ft

= 200 sq. ft

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Answer:

18

Step-by-step explanation:

siz times three is eighteen

Answer: Linear

Step-by-step explanation:

Since the difference between consecutive values of f(x) is constant, this suggests that the function could be linear. To confirm this, we can calculate the differences between consecutive values:f(1) - f(0) = -15 - (-18) = 3

f(2) - f(1) = -12 - (-15) = 3

f(3) - f(2) = -9 - (-12) = 3

f(4) - f(3) = -6 - (-9) = 3

Since the differences are constant and equal to 3, this confirms that the function is linear.

To find the equation of the linear function, we can use the slope-intercept form of a linear equation:

y = mx + bwhere m is the slope and b is the y-intercept.

We can use the first two points (0, -18) and (1, -15)  to find the slope:

m = (change in y) / (change in x) = (-15 - (-18)) / (1 - 0) = 3

Now we can use the slope and one of the points to find the y-intercept:

y = mx + b

-18 = 3(0) + b

b = -18

Therefore, the equation of the linear function is:

f(x) = 3x - 18

So the function type that could represent the values in the table is linear.

Using function concepts, we have that:1. Non-linear2.B)x y0 11 22 53 103. Linear4.: Linear: Linear: Non-Linear: Linear5. LinearIn a linear function, the rate of change is constant.A linear function is also of the first degree.Item 1:From -3 to -1, the rate of change is of From -1 to 1, the rate of change is of .Different rates of change, so non-linear.Item 2:At function b, from 0 to 1, the rate of change is of 1, from 1 to 2 of 3, different rates of change, so non-linear.Item 3:Highest degree of x is 1, so first degree, and thus linear.Item 4:The only non-linear is , which is of the second degree. is a constant function, with a rate of change of 0, so linear.The last function is written as:Highest degree of x is 1, so also linear.Item 5:In all cases, the rate of change is constant, so linear.

Answer: 3. 35x + 15 = 155

Step-by-step explanation:

35 x 4 = 140

140 + 15 = 155

The maximum revenue is achieved when she sells 33 photos at a price of 25 per photo.

Using quadratic regression, [tex]y = ax^2 + bx + c[/tex]

where a, b and c are constants and x is the independent variable we can determine the equation of the curve that best fits the data. The equation will be in the form of[tex]y = ax^2 + bx + c[/tex], where y is the revenue, x is the number of photos sold, and a, b, and c are constants. The constants can be determined by solving the system of equations formed by the three data points.

After solving for the constants, we can determine the maximum revenue by finding the vertex of the curve. The vertex is located at x = -b/2a, and the corresponding revenue is[tex]y = ax^2 + bx + c[/tex]. Plugging in the values for a, b, and c, we can calculate that the maximum revenue is achieved when she sells 33 photos at a price of 25 per photo.

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Complete question

Darlena has started taking photos at amateur dog racing events, later offering the photos for sale to the dog owners by email. The prices she has charged per photo at each of her first three events, and the corresponding number of photos sold and total revenue raised, appear in the table below. Treating revenue as a function of the number of photos sold, a graph of the three data points is also shown. If she uses quadratic regression to fit a curve to the data, what number of photos sold and what price per photo will maximize her revenue?

The vector equations of L₂ when expressed as Cartesian equations are

y = 0

x = (z ± √(z² - 4(z-2))) / 2

z = [(4 - ((x-1)/(-z))²) ± √((4 - ((x-1)/(-z))²)² + 64)] / 8

To find the vector equation of the line L₂, we need to find a vector that is perpendicular to L₁ and passes through the point (1,0,2). Let's start by finding the vector equation of L₁.

Let P(x,y,z) be a point on L₁. Then the vector equation of L₁ is given by:

r₁ = P + t * d₁

where d₁ is the direction vector of L₁ and t is a scalar parameter.

Since L₂ is perpendicular to L₁, its direction vector must be perpendicular to d₁. Thus, we can find a vector that is perpendicular to d₁ by taking the cross product of d₁ with any non-zero vector that is not parallel to d₁. Let's choose the vector (0,1,0):

v = d₁ x (0,1,0) = (-z,0,x)

Note that we can choose any non-zero vector that is not parallel to d₁, and we will still get a vector that is perpendicular to d₁.

Now we have a point on L₂ (1,0,2) and a direction vector (v), so we can write the vector equation of L₂:

r₂ = (1,0,2) + s * v

where s is a scalar parameter.

To express the Cartesian equations of L₂, we can write the vector equation as a set of three parametric equations:

x = 1 - sz

y = 0

z = 2 + sx

We can eliminate the parameter s by solving for it in two of the equations and substituting into the third equation:

s = (x - 1) / (-z)

s = (z - 2) / x

Setting these two expressions equal to each other and solving for x, we get:

[tex]x^2 - zx + z - 2 = 0[/tex]

This is a quadratic equation in x, so we can solve for x using the quadratic formula:

[tex]x = (z \± \sqrt{(z^2 - 4(z-2)})) / 2[/tex]

Substituting this expression for x into one of the parametric equations, we get:

y = 0

And substituting the expressions for x and s into the other parametric equation, we get:

[tex]z = 2 + [(z \± \sqrt{(z^2 - 4(z-2)})) / 2] * [(1 - sz) / (-z)][/tex]

Simplifying this equation, we get:

[tex]4z^2 - (4 - s^2)z - 4 = 0[/tex]

Again, this is a quadratic equation in z, so we can solve for z using the quadratic formula:

[tex]z = [(4 - s^2) \± \sqrt((4 - s^2)^2 + 64)] / 8[/tex]

z = [(4 - s²) ± √((4 - s²)² + 64)] / 8

Finally, we can substitute these expressions for x and z into one of the parametric equations to get:

[tex]y = 0\\x = (z \± \sqrt{(z^2 - 4(z-2)})) / 2\\z = [(4 - ((x-1)/(-z))^2) \± \sqrt{((4 - ((x-1)/(-z))^2)^2} + 64)] / 8[/tex]

These are the Cartesian equations of L₂.

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Answer:

The midpoint of a line segment AB with endpoints A(x1, y1) and B(x2, y2) is given by the coordinates:

[(x1 + x2) / 2, (y1 + y2) / 2]

In this case, A is located at (1, 4) and B is located at (3, -6). So the midpoint M of AB is:

[(1 + 3) / 2, (4 + (-6)) / 2]

= [2, -1]

Therefore, the midpoint of AB is at the point (2, -1).

The coordinates of the midpoint of the line AB is [2, -1]

Section formula is used to find the ratio in which a line segment is divided by a point internally or externally.

It is used to find out the centroid, incenter and excenters of a triangle. In physics, it is used to find the center of mass of systems, equilibrium points, etc.

Given that, we need to find the midpoint of AB if A located at (1, 4) and B is located at (3, -6).​

The midpoint of a line segment AB with endpoints A(x1, y1) and B(x2, y2) is given by the coordinates:

[(x1 + x2) / 2, (y1 + y2) / 2]

In this case, A is located at (1, 4) and B is located at (3, -6).

So the midpoint M of AB is:

= [(1 + 3) / 2, (4 + (-6)) / 2]

= [2, -1]

Hence, the midpoint of AB is at the point (2, -1).

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Answer:

1.986 x 10 to the tenth power

Step-by-step explanation:

According to the question the percent abundance of the medium nails in the sample is approximately 18.95%.

Whenever the set of data is presented from least to largest, the median is indeed the number in the middle. For instance, since 8 is in the middle, this would represent the median value here.

To find the percent abundance of the medium nails in the sample, we first need to calculate the total number of nails in the sample:

Total number of nails = 67 + 18 + 10 = 95

Next, we can calculate the percent abundance of the medium nails using the formula:

Percent abundance = (number of medium nails / total number of nails) x 100%

Using the values from of the table as inputs, we obtain:

Percent abundance of medium nails = (18 / 95) x 100% ≈ 18.95%

As a result, the sample's average percentage of medium nails is roughly 18.95%.

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True. The length of AB can be gotten by 3^2 + b^2 = 4^2.

True.  The perimeter of the trapezoid shown is not 22 units.

The length of AB can be gotten by 3^2 + b^2 = 4^2.

9 + b^2 = 16

b^2 = 16 + 9

b = 5

Then we have to count the boxes to get the length of the other sides

CD = 4

AD = 8

BC = 5

AB = 5

Then the perimeter would be be 5 + 5 + 8 + 4

= 22

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The sum of x and 2 is equal to x + 2.

Value in math is the numerical representation of a quantity or expression. It can also be defined as an amount or a numerical representation of a quantity that is assigned to a variable or a constant in a mathematical expression. Value can be expressed in various forms, such as decimal, fraction, and scientific notation. Value is also used to calculate the result of an equation or a problem. Value is a fundamental concept in mathematics, and it is used to measure and compare different quantities.

This equation can be used to calculate the sum of any two numbers, x and 2. For example, if x is equal to 5, then the sum of x and 2 is equal to 5 + 2, which is equal to 7. Similarly, if x is equal to 10, then the sum of x and 2 is equal to 10 + 2, which is equal to 12. Therefore, the sum of x and 2 depends on the value of x.

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Answer:

1st one.-sin(X)+5e^5x

Answer:

1. 57/16 or 3.5625 ounces of water

8 : 4.75

1 : 19/32  -----> divide both by 8

19/32x6=57/16 = 3.56 ounces

2. 2.4375 ounces of other ingredients

6-3.5625=2.4375

Answer: To solve the third-order differential equation y''' + y' = cot(x) by variation of parameters, we first need to find the solution to the associated homogeneous equation, which is:

y''' + y' = 0

The characteristic equation is r^3 + r = 0, which can be factored as r(r^2 + 1) = 0. This gives us the roots r = 0, r = i, and r = -i. Therefore, the general solution to the homogeneous equation is:

y_h = c1 + c2 cos(x) + c3 sin(x)

To find a particular solution to the non-homogeneous equation using variation of parameters, we assume that the solution has the form:

y_p = u1(x) + u2(x) cos(x) + u3(x) sin(x)

where u1, u2, and u3 are functions to be determined.

We can find the derivatives of y_p:

y'_p = u1'(x) + u2'(x) cos(x) - u2(x) sin(x) + u3'(x) sin(x) + u3(x) cos(x)

y''_p = u1''(x) + u2''(x) cos(x) - 2u2'(x) sin(x) - u2(x) cos(x) + u3''(x) sin(x) + 2u3'(x) cos(x) - u3(x) sin(x)

y'''_p = u1'''(x) + u2'''(x) cos(x) - 3u2''(x) sin(x) - 3u2'(x) cos(x) - u2(x) sin(x) + u3'''(x) sin(x) + 3u3''(x) cos(x) - 3u3'(x) sin(x)

Substituting these derivatives into the non-homogeneous equation, we get:

u1'''(x) + u2'''(x) cos(x) - 3u2''(x) sin(x) - 3u2'(x) cos(x) - u2(x) sin(x) + u3'''(x) sin(x) + 3u3''(x) cos(x) - 3u3'(x) sin(x) + u1'(x) + u2'(x) cos(x) - u2(x) sin(x) + u3'(x) sin(x) + u3(x) cos(x) = cot(x)

Grouping the terms with the same functions together, we get:

u1'''(x) + u1'(x) = 0

u2'''(x) cos(x) - 3u2''(x) sin(x) - u2(x) sin(x) + u2'(x) cos(x) + u2'(x) cos(x) = cot(x) cos(x)

u3'''(x) sin(x) + 3u3''(x) cos(x) - 3u3'(x) sin(x) + u3'(x) sin(x) + u3(x) cos(x) = cot(x) sin(x)

The first equation is a first-order differential equation, which can be solved by integrating both sides:

u1'(x) + u1(x) = c1

where c1 is a constant of integration. The solution to this equation is:

u1(x) = c1 + c2 e^(-x)

where c2 is another constant of integration.

Step-by-step explanation:

All three data points are compatible with this set of equations, leading us to the conclusion that C = -195h + 550 is the function that best describes the scenario.

A function connects an input with an output. It works like a machine that has an input and an output. The traditional manner of writing a function is "f(x) = 5".

The following function represents this circumstance:

C = -195h + 550

The first two data points can be used to create two equations:

355 = -195(1) + C

1120 = -195(3) + C

When we solve for C in each equation, we obtain:

C = 550

C = 550 + 585 = 1135

We can try utilising the first and third data points as the second equation doesn't quite match the third data point:

355 = -195(1) + C

1885 = -195(4) + C

Solving for C in each equation, we get:

C = 550

C = 550 + 975

= 1525

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Answer: click thanks if you like my answer. have a good day <:

The best way to assign values for a simulation using a random digits table is to first identify the possible outcomes and assign a number or range of numbers to each outcome. Then, using the random digits table, randomly select digits and match them to the assigned outcomes.

For example, in the given scenarios for blood types in different countries, each blood type is assigned a specific number or range of numbers. Using the random digits table, the assigned numbers can be matched to the digits in the table to simulate the occurrence of each blood type in the population.

To answer the questions:

1.What is the purpose of assigning values for a simulation using a random digits table?

The purpose of assigning values for a simulation using a random digits table is to create a simulated scenario that reflects the likelihood of different outcomes based on assigned probabilities. This can help in making predictions and decisions in various fields such as medicine, finance, and social sciences.

2.In which scenario are blood types represented with the fewest number of digits?

Blood types are represented with the fewest number of digits in the third scenario for both Country X and Country Y. Blood type O is represented with 0, blood type A with 1, blood type B with 3, and blood type AB with 4, while all other digits are ignored.

3.In which scenario are blood types represented with the most number of digits?

Blood types are represented with the most number of digits in the first scenario for Country X, where blood type O is represented with 0, 1, 2, 3, 4, and 5, blood type A with 6 and 7, blood type B with 8, and blood type AB with 9. The same applies to Country Y in the first scenario.

Step-by-step explanation:

hope its help <:

Answer:2

Step-by-step explanation:Because the 2 is closest to the middle line

Answer:

relationship describes angles 1 and 2 is supplementary angles. From the given figure

it is concluded that

the relation ship between angle 1 and 2 is supplementary angles

because its is  linear pair

and forms a line

therefore , the angles are supplementary angles

hence , relationship describes angles 1 and 2 is supplementary angle

Step-by-step explanation: Hope this helps !! Mark me brainliest!! :))

Answer:

162, 147 etc.

Step-by-step explanation:

we have to find

[tex]N = k^2 \cdot p[/tex]

we can iterate k = 1 to 10 to check all possible solutions,

[tex]N = 9^2 \cdot 2[/tex]

[tex]N = 7^2 \cdot 3[/tex]

N = 162, 147 etc.

Hopefully this answer helped you!!