Answers
We have the function:
[tex]f\mleft(x\mright)=-0.4x-10[/tex]And we need to find its value when x = -12. So, replacing x with -12, we obtain:
[tex]f(-12)=-0.4(-12)-10=4.8-10=-5.2[/tex]Notice that the product of two negative numbers is a positive number.
Therefore, the answer is -5.2.
Related Questions
Given the median QR and trapezoid MNOP, what is the value of X?M3.8033Rکد 73PA. 6B. 19(C. 2D, 5E 7F. Cannot be determined
Answers
SOLUTION
Consider the diagram below
Applying the rule in the diagram above, we have
[tex]|QR|=\frac{1}{2}(|ON|+|PM|)[/tex]Recall from the questions
[tex]\begin{gathered} |QR|=33 \\ |ON|=3x-8 \\ |PM|=7x+4 \end{gathered}[/tex]Then we substitute the parameters above into the expression above
[tex]\begin{gathered} 33=\frac{1}{2}(3x-8+7x+4) \\ \text{ Multiply both sides by 2} \\ 66=3x-8+7x+4 \\ \text{rerrange the terms and simplify } \\ 66=10x-4 \\ \text{collect like terms } \\ 66+4=10x \end{gathered}[/tex]simplify further
[tex]\begin{gathered} 70=10x \\ \text{divide both sides by 10} \\ x=\frac{70}{10} \\ \text{then} \\ x=7 \end{gathered}[/tex]Therefore the value of x is 7
Therefore the right option is E
i need help please,solve and explain it's 4th grade math.. thank you.
Answers
What you can say about 12th, 18th and the 21st child, depends if these numbers are multiples of 4 (every 4th child is wearing spectacles), 3 (every 3rd child is a girl) and 2 (every 2nd child is wearing a white shirt).
If a numer is multiple of another one, then the quotient between them is an integer number.
for 12th:
12/4 = 3
12/3 = 4
12/2 = 6
12 is multiple of 3, 4 and 6.
Then, 12th child is wearing spectacles, a white shirt and is a girl.
for 18th:
18/4 = 4.5
18/3 = 6
18/2 = 9
18 is multiple of 3 and 2.
Then, 18th child is a girl and is weraing a white shirt
for 21th:
21/4 = 5.25
21/3 = 7
21/2 = 11.5
21 is multiple of 3.
THen, 21st child is a girl.
Given that the height of a trapezoid is 16 m and one base’s length is 25 m. Calculate the dimension of the other base of the trapezoid if its area is 352 m².
Answers
ANSWER:
19 m
STEP-BY-STEP EXPLANATION:
We have that the formula for the area of a trapezoid is the following:
[tex]A=\frac{B+b}{2}\cdot h[/tex]We substitute each value and calculate the length of the other base, like so:
[tex]\begin{gathered} 352=\frac{25+b}{2}\cdot16 \\ \\ 25+b=352\cdot\frac{2}{16}\frac{}{} \\ \\ b=44-25 \\ \\ b=19 \end{gathered}[/tex]The dimension of the other base of the trapezoid is 19 m
An arts academy requires there to be 6 teachers for every 96 students and 3 tutors for every 30 students. How many students does the academy have per teacher? Per tutor? How many tutors does the academy need if it has 100 students?
Answers
If the school requieres 6 teachers for every 96 students then
1 teacher will be required for every
= 96/6
= 16 students
If 3 tutors for every 30 students then 1 tutor is required for
= 30/3
= 10 students
If the academy has 100 students, the number of tutors required would be
= 100/10
= 10 tutors
Hence
The academy requires;
Tanvir applies the distributive property to the left-hand side of the equation 1/3(3q+15)=101 Which equation shows the correct application of the distributive property?
1: q+15=101
2:3q+5=101
3:3q+15=101
4:q+5=101
Answers
When Tanvir applies the distributive property to the left-hand side of the equation, 1/3(3q+15)=101, the equation that shows the correct application is equation 4: q+5=101.
What is distributive property?The distributive property applies basic mathematical operations, especially in equations.
This property is that when a value is multiplied or divided by a number to a set that will be added or subtracted, the result is the same, notwithstanding if the operation is done before the addition or subtraction.
1/3(3q+15) = 101
(3q/3+15/3) = 101
= q + 5 = 101
q = 96
Check of Distributive Property:
1/3(3q+15) = 101
1/3(3 x 96+15) = 101
= 1 x 96 + 5 = 101
= 96 + 5 = 101
= 101 = 101
Or: 1/3(3q+15) = 101
1/3(3 x 96+15) = 101
= 1/3(288 + 15) = 101
= 1/3(303) = 101
= 101 = 101
Thus, the equation that correctly applies the distributive property is equation 4: q+5=101.
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Cleo can paint a room in 8 hours, while Phil can paint the same room in 6 hours. If they paint theroom together, how long will it take them to paint the room?How many hours and how many minutes?
Answers
According to the given data we have the following:
Cleo can paint a room in 8 hours, so this is=1/8x
Phil can paint the same room in 6 hours=1/6x
In order to calculate how long it take them to paint the room we would solve the following equation:
(1/6)(x)+(1/8)(x)=1
To solve this equation we would first multiply both sides by 24
Hence:
24*(1/6)(x)+24*(1/8)(x)=24
4x+3x=24
7x=24
x=24/7
x= 3 3/7 hours
Therefore It will take them 3 and 3/7 hours to pain the room.
In minutes it will take to them 205 minutes.
I solved for Part A and the correct graph was answer A I just need Part B to be solved (at the bottom)
Answers
In Part (b) of this problem, we want to determine which function is the bes representation for the graph and table.
We are given:
To determine which function matches best, we can look at the parent function of a linear, logarithmic, and exponential function.
(see comparisons below):
Notice that our graph most closely resembles that of the exponential function. Therefore, the best model for the data would be an exponential function.
1 punto Two distinct coplanar lines that do not intersect are known as lines * A. parallel B. perpendicular C. skew D. Tangent
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Coplanar lines are lines that lies in the same plane.
By definition, two distince lines that lies in the same plane and that do not intersect are said to be parallel
Hence the correct choice is A
Is the prime factor of 121 11x11?
Answers
The prime factor of 121 is simply 11.
11x11 =121, since you can't take 11 two times.
write the slope-interference form of the equation of each line
Answers
The slope interference form of straight line is given by
[tex]y=mx+c[/tex]Here is the slope of the line and c is the y-intercept
Now, from the graph, it is seen that the line passes through the points (0,4) and (3,5)
So,
[tex]\begin{gathered} \frac{y-4}{5-4}=\frac{x-0}{3-0} \\ \frac{y-4}{1}=\frac{x}{3} \\ 3(y-4)=x \\ 3y=x+12 \\ y=\frac{x}{3}+4 \end{gathered}[/tex]So, the required equation is
[tex]y=\frac{x}{3}+4[/tex]
Give the sample space describing all the outcomes. Then give all of the out comes for the event that the number 3 chosen. Use the format H1 to mean that the coin toss is heads and the number chosen is 1. If there is more than one element in the set separate them with commas
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The sample space is composed of all the possible outcomes i.e. of all the possible combinations between the result of tossing the coin and picking the card. There are two possible outcomes for the coin and four for the cards so there will be 8 different combinations in the saple space. These are:
[tex]H1,H2,H3,H4,T1,T2,T3,T4[/tex]Then we must show all the outcomes where the card with the 3 is picked. This set is composed of all the elements with a 3 in the list above. There are two:
[tex]H3,T3[/tex]AnswersThen the answers are:
Sample space: {H1,H2,H3,H4,T1,T2,T3,T4}
Event that the number chosen is 3: {H3,T3}
1/b + 1/9 + = 1/tSolve for t
Answers
The given expression is
[tex]\frac{1}{b}+\frac{1}{9}=\frac{1}{t}[/tex]First, we multiply the equation by t
[tex]\begin{gathered} (\frac{1}{b}+\frac{1}{9})\cdot t=\frac{1}{t}\cdot t \\ (\frac{1}{b}+\frac{1}{9})\cdot t=1 \end{gathered}[/tex]Now, we divide the equation by 1/b + 1/9
[tex]\begin{gathered} \frac{(\frac{1}{b}+\frac{1}{9})\cdot t}{(\frac{1}{b}+\frac{1}{9})}=\frac{1}{(\frac{1}{b}+\frac{1}{9})} \\ t=\frac{1}{(\frac{1}{b}+\frac{1}{9})} \end{gathered}[/tex]Now, we sum fractions
[tex]t=\frac{1}{\frac{9+b}{9b}}[/tex]Then, we solve this combined fraction
[tex]t=\frac{9b\cdot1}{9+b}=\frac{9b}{9+b}[/tex]Therefore, the final expression is
[tex]t=\frac{9b}{9+b}[/tex]Given that figure ABCD is a dilation of figure KLMN, find the missing values:(note that values are slightly different because of a round-off error)
Answers
• Given the dimensions of ABCD:
m∠A = 71.68 degrees
m∠C = 47.68 degrees
m∠D = 141.87 degrees
CD = 4
AD = 6
BC = 8
• Dimensions of KLMN:
m∠K = 71.52 degrees
m∠L = 98.87 degrees
m∠M = 47.53 degrees
KL = 10
KN = 15
MN = 10
Let's find the missing values.
Given that figure ABCD is a dilation of KLMN, both figures are similar.
• Similar figures have proportional corresponding sides.
,• Similar figures have equal corresponding angles.
Therefore, we have the corresponding sides:
AB ⇔ KL
BC ⇔ LM
CD ⇔ MN
AD ⇔ KN
The corresponding angles are:
m∠A = m∠K
m∠B = m∠L
m∠C = m∠M
m∠D = m∠N
Thus, to find the missing values, we have:
• X = m∠B = m∠L = 98.87 degrees
X = 98.87 degrees.
• Y = m∠N = m∠D = 141.87 degrees.
Y = 141.87 degrees
• To find the value of ,a,, apply the proportionality equation:
[tex]\frac{AB}{AD}=\frac{KL}{KN}[/tex]Plug in values and solve for a:
[tex]\begin{gathered} \frac{a}{6}=\frac{10}{15} \\ \\ \text{Cross multiply:} \\ 15a=10\times6 \\ \\ 15a=60 \\ \\ a=\frac{60}{15} \\ \\ a=4 \end{gathered}[/tex]• To find the value of ,b,, apply the proportionality equation:
[tex]\begin{gathered} \frac{DC}{BC}=\frac{NM}{LM} \\ \\ \frac{4}{8}=\frac{10}{b} \\ \\ \text{Cross multiply:} \\ 4b=10\times8 \\ \\ 4b=80 \\ \\ b=\frac{80}{4} \\ \\ b=20 \end{gathered}[/tex]ANSWER:
• X = 98.87°
,• Y = 141.87°
,• a = 4
,• b = 20
Solve T=C(8+AB) for A
Answers
If the carrier transmits 12 kW, what is the modulated power if modulation index is (1/√2) ?
Answers
The modulated power is 15 kW.
The modulated power is given by the formula P_T= P_C (1+ (m_a^2)/2) and is connected to the total power of the carrier signal and the modulation index.
To obtain the modulated power, substitute the values in the given equation and simplify.
Given,
Power of carrier signal (P_C) = 12 kW
= 12000 W
Modulation index ( m_a) = 1/√2
Consequently, when we change the variables in the equation, we get
P_T= P_C (1+ (m_a^2)/2)
=12000 (1+ (1/√2)^2/2)
= 12000 (1+ 1/4)
= 12000 * 5/4
= 3000*5
= 15000 W
= 15 kW
Hence, modulated power is 15 kW.
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Describe the complement of the given event. 73% of nineteen year old males are at least 166 pounds
Answers
Solution
- The event is "73% of nineteen year old males are at least 166 pounds"
- The complement of this event is the set of all 19 year old males not in the event described above.
- These set of 19 year olds, must represent the remaining 27% of the population.
- Also, they would weigh less than 166 pounds.
- Thus, the complement of the event is:
"27% of nineteen year old males weigh less than 166 pounds"
Which is closest to the circumference of the earth if it's diameter is 7926.41 miles?
Answers
ANSWER
24901.55 miles
EXPLANATION
We have to find the circumference of the earth using the diameter given.
The formula for circumference is:
[tex]C=\pi\cdot D[/tex]where D = diameter
Therefore, the circumference is:
[tex]\begin{gathered} C=\pi\cdot7926.41 \\ C=24901.55\text{ miles} \end{gathered}[/tex]write in exponential form5x5x5
Answers
5 x 5 x 5 = 5^3
[tex]\begin{gathered} \\ 5x5x5=5^{3\text{ }}\text{ = 125} \end{gathered}[/tex][tex]=16^{5\text{ }}\text{ = 16 x 16 x 16 x 16 x 16 = 1,048,576}[/tex]f(x) = x^2 g(x) = x^2 - 8 g(x)= x^2 - 8 We can think of g as a translated (shifted) version of f. Complete the description of the transformation. Use nonnegative numbers. To get the function g, shift f [up/down/left/right] by [ ] units.
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We have that the parent function (the original function is x^2). If we add a number after it as:
[tex]f(x)=x^2_{}+b[/tex]We affect the function in the y-axis, that is, we move the original function upward or downward.
Therefore, to get the function g, we need to shift the f function down by 8 units, that is
[tex]g(x)=f(x)-8=x^2-8[/tex]18. The table below gives the population of a town (in thousands) from the year 2000 to the year 2008. Year '00 '01 '02 03 04 '05 06 '07 '08 Population 87 84 83 80 77 76 78 81 85 (thousands) What was the average rate of change of population: a. between 2002 and 2004? b. between 2002 and 2006?
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a . Average rate of change between 2002 and 2004 can be calculated below
[tex]\begin{gathered} average\text{ rate of change=}\frac{chang\text{e in y}}{\text{change in x}} \\ average\text{ rate of change = }\frac{77-83}{2004-2002} \\ average\text{ rate of change}=\frac{-6}{2}=-3(thousand) \end{gathered}[/tex]b. Average rate of change between 2002 and 2006 is
[tex]\begin{gathered} \text{average rate of change = }\frac{78-83}{2006-2002} \\ average\text{ rate of change}=\frac{-5}{4}=-\frac{5}{4}(thousand) \end{gathered}[/tex]I will give brainlist
The Busy Bee store bottles fresh jars of honey at a constant rate. In 2 hours, it bottles 18 jars, and in 6 hours, it bottles 54 jars of honey.
Determine the constant of proportionality.
9
18
0.11
4.5
Answers
The constant of proportionality is A. 9.
What is a constant of proportionality?The constant of proportionality is simply used to show that the numbers given have a constant value.
From the information, the Busy Bee store bottles fresh jars of honey at a constant rate. In 2 hours, it bottles 18 jars. The constant will be:
= Number of jars / Number of hours
= 18/2
= 9
In 6 hours, it bottles 54 jars of honey. The constant will be:
= 54 / 6
= 9
Therefore, the constant is 9.
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The graph shows the absolute value parent function. 6 Which statement is true? A. (0,1) is the x- and y-intercept of the function. B. (1,1) is the x- and y-intercept of the function. O C. (0,0) is the x- and y-intercept of the function. D. The function has no intercepts.
Answers
From the graph;
(0,0) is the (x, y) intercept of the graph
since the function passes through (0,0)
What was the initial population at time t=0?Find the size of the bacterial population after 4 hours.
Answers
Answer;
[tex]\begin{gathered} a)\text{ 195 bacteria} \\ b)\text{ 3,291,055,916 bacteria} \end{gathered}[/tex]Explanation;
a) We want to get the initial population of the bacteria
We start by writing a formula that links the initial bacteria population to a later bacteria population after time t
[tex]A(t)=I(1+r)^t[/tex]where A(t) is the bacteria population at time t
I is the initial bacteria population
r is the rate of increase in population
t is time
Now, let us find r
At t = 10; we know that A(t) = 2I
Thus, we have it that;
[tex]\begin{gathered} 2I=I(1+r)^{10} \\ (1+r)^{10}\text{ = 2} \\ 1+r\text{ = 1.0718} \\ r\text{ = 1.0718-1} \\ r\text{ = 0.0718} \end{gathered}[/tex]Now, let us find I, since we have r. But we have to make use of t= 80 and A(t) = 50,000
Thus, we have;
[tex]\begin{gathered} 50,000=I(1+0.0718)^{80} \\ I\text{ = }\frac{50,000}{(1+0.0718)^{80}} \\ I\text{ = 195} \end{gathered}[/tex]The initial population is 195 bacteria
b) For after 4 hours, we have to convert to minutes
We know that there are 60 minutes in an hour
So, in 4 hours, we have 4 * 60 = 240 minutes
Now, we proceed to use the formula above with I = 195 and t = 240
We have that as;
[tex]\begin{gathered} A(240)=195(1+0.0718)^{240} \\ A(240)\text{ = 3,291,055,916 bacteria} \end{gathered}[/tex]In the diagram below of triangle DEF, G is a midpoint of DE and H is a midpoint of EF. IfGH = 50 -- 87, and DF = 9x + 0, what is the measure of GH? E H D F
Answers
GH = 18
Explanations:From the diagram:
DF = 9x + 0
GH = 50 - 8x
Since G is a midpoint of DE and H is a midpoint of EF, using the midpoint theorem:
DF = 2GH
9x + 0 = 2 (50 - 8x)
9x = 100 - 16x
9x + 16x = 100
25x = 100
x = 100/25
x = 4
Substituting the value of x into GH = 50 - 8x
GH = 50 - 8(4)
GH = 50 - 32
GH = 18
g(x)=2x-2f(x)=4x-1Find (g*f) (-9)
Answers
Given:
[tex]\begin{gathered} g(x)=2x-2 \\ f(x)=4x-1 \end{gathered}[/tex]The expression for g(f(x)) is,
[tex]\begin{gathered} g(f(x))=2(f(x))-2 \\ =2(4x-1)-2 \\ =8x-2-2 \\ =8x \end{gathered}[/tex]Substitute x=-9 in the above expression.
[tex]\begin{gathered} g(f(-9))=8\times-9 \\ =-72 \end{gathered}[/tex]Thus, the final value of the expression is -72.
Determine the value of n that makes the polynomial a perfect square trinomial. Then factor as the square of a binomial. Express numbers as integers orsimplified fractions.u^2+20u+n
Answers
SOLUTION
The expression is given as
[tex]u^2+20u+n[/tex]The value of n makes the expression a perfect square trinomial.
To find the value of n, we have
Identify the coefficient of u and divide by 2
[tex]\begin{gathered} \text{the coefficient of u=20} \\ \text{divide by 2=}\frac{\text{20}}{2}=10 \end{gathered}[/tex]Then square the result, we have
[tex]\begin{gathered} 10^2=100 \\ \text{hence } \\ n=100 \end{gathered}[/tex]Then the complete trinomial of the polynomial becomes
[tex]u^2+20u+100[/tex]To factor as a square of a binomial we use the perfect square trinomial above
[tex]\begin{gathered} u^2+20u+100 \\ u^2+20u+10^2 \\ \text{Then} \\ (u+10)^2 \end{gathered}[/tex]Therefore
The vaue of n = 100
The factor as the square of a binomial is (u+ 10)²
Fill in the blank. In the triangle below, Z = 52° 35
Answers
Solution
Since the diagram given is a Triangle, therefore, the sum of it's interior angles is 180 degrees
However, the Triangle is a right angle Triangle since on of its angles is 90 degrees.
The sum of its Interior angles is given by;
[tex]\begin{gathered} z+52+90=180 \\ \\ \Rightarrow z+142=180 \end{gathered}[/tex]subtracting 142 from both sides,
[tex]\begin{gathered} \Rightarrow z+142-142=180-142=38 \\ \\ \Rightarrow z=38^0 \end{gathered}[/tex]Therefore, z = 38
Determine whether the lines are parallel, intersect, or coincideY = 4x - 53x + 4y = 7
Answers
Answer:
Explanation:
Given:
y=4x-5
3x+4y=7
We can check if the lines are parallel, intersect, or coincide by graphing. To graph, we plug in any values for x to determine the y values.
The graph of the lines is shown below:
So based on the graph, the lines intersect at a point.
Therefore, the lines intersect.
Hello I need help with the following question. 8. Use the given graph of the function f to find the domain and range(−6,6)8 The domain of f is(Type a compound inequality.)The range of f is(Type a compound inequality.)
Answers
We are to use the given graph in the question to find the domain and range
From the graph,
The lowest value of x plotted is x = -14
The highest value of x plotted is x = 12
The loowest value of y is y= -4
The highest value of y is y = 6
Hence, the domain is
[tex]-14\leq x\leq12[/tex]While the range is
[tex]-4\leq y\leq6[/tex]The function c = 100+.30m represents the cost c (in dollars) of renting a car afterdriving m miles.How many miles would a customer have to drive for the cost to be $149.50?
Answers
149.5 = 100 + .30m
149.5 - 100 = .30m
49.5 = .30m
Divide both sides by 0.30
m = 49.5/0.3
m =165
Option D