Given loga (m) = 10 and loga (n) = 25 , find loga (m * n ^ 2)

Answers

Answer 1

The result of the log function [tex]log_a (m * n ^ 2)[/tex]  is 60

According to the law of logarithm if [tex]log_ab=y[/tex] then [tex]b=a^y[/tex]

Given the following expressions

[tex]log_am=10\\log_an=25[/tex]

This can be expressed as

[tex]m =a^{10} \ and \ n = a^{25}[/tex]

Substitute the value of m and n into the expression [tex]log_a (m * n ^ 2)[/tex] to have:

[tex]log_a (m * n ^ 2) = log_a(a^{10}\times a^{50})\\=log_aa^{60}\\=60log_aa\\=60(1) \\= 60[/tex]

This shows that the result of the log function [tex]log_a (m * n ^ 2)[/tex]  is 60

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Answers

Answer:

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Answers

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Answers

Answer:

Answer y = -7x + 12

Step-by-step explanation:

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Describe and correct the error in finding the tenth term of the arithmetic sequence 4, 12, 20, 28.

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Answers

Answer: The tenth term is 76

=======================================================

Explanation:

We use this arithmetic sequence formula to get the nth term

[tex]a_n = a_1 + d(n-1)[/tex]

Plug in [tex]a_1 = 4, \ d = 8, \ n = 10[/tex] and you should get the following:

[tex]a_n = a_1 + d(n-1)\\\\a_{10} = 4 + 8(10-1)\\\\a_{10} = 4 + 8(9)\\\\a_{10} = \textbf{76}\\\\[/tex]

The tenth term is 76

---------

We can verify this by listing out the terms one by one. Start at 4, add on 8 each time, until you generate the 10th term. A table like the one shown below is a good way to keep track of all the terms.

[tex]\begin{array}{c|c}\boldsymbol{n} & \boldsymbol{a_n}\\1 & 4\\2 & 12\\3 & 20\\4 & 28\\5 & 36\\6 & 44\\7 & 52\\8 & 60\\9 & 68\\10 & \textbf{76}\\\end{array}[/tex]

---------

In short, the error is with the "10" in the expression 4+10(8). The student should have used 9 instead. This is because of the n-1 term in [tex]a_n = a_1 + d(n-1)[/tex] which shifts everything one spot to the left.

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