Given that the partial charges on C and O in carbon monoxide are 0.020 and 0.020, respectively, calculate the dipole moment of CO. (The distance between the partial charges, r, is 113 pm.)

Solubility: The maximum amount of solute that can be dissolved in a solvent at a given temperature and pressure is called solubility.

Partial Pressure: The pressure that a gas exerts when it is present in a mixture of gases is called partial pressure.

The given solubility of NO in water is 0.090 m and the partial pressure is 0.80 atm. We need to find the partial pressure required for the solubility of NO to be 0.060 m.

Hence, let's find the relationship between solubility and partial pressure.

The relationship between solubility and partial pressure can be given as, Henry's Law:

S = KP

Where, S is the solubility of the gas in solution,

P is the partial pressure of the gas above the solution, and

K is Henry's Law constant.

Let's apply the given values to Henry's Law to find the value of

K.0.090 m = K (0.80 atm)

K = 0.090 m / 0.80 atm

K = 0.1125 m/atm

Now, let's find the partial pressure required for the solubility of NO to be 0.060 m using Henry's Law.

0.060 m = (0.1125 m/atm) P

So, the partial pressure required for the solubility of NO to be 0.060 m is 0.53 atm.

Learn more about solubility: https://brainly.com/question/9098308

#SPJ11

Answer:

400.87g of barium phosphate and 32.4g of HCL

Explanation:

The balanced chemical equation for the reaction between potassium phosphate and barium nitrate is:

3 K3PO4 + 4 Ba(NO3)2 → 12 KNO3 + Ba3(PO4)2

According to the stoichiometry of the equation, for every 3 moles of potassium phosphate, 1 mole of barium phosphate is produced. Therefore:

1 mol Ba3(PO4)2 = 3 mol K3PO4

To convert the given quantity of potassium phosphate to moles, we can use its molar mass:

4.36 mol K3PO4 = 4.36 mol × 212.27 g/mol = 925.5912 g

Now we can use the stoichiometry to calculate the amount of barium phosphate produced:

1 mol Ba3(PO4)2 = 3 mol K3PO4

1 mol Ba3(PO4)2 = 3/4 mol Ba(NO3)2 (from the balanced equation)

Therefore, the amount of barium phosphate produced is:

4.36 mol K3PO4 × 1 mol Ba3(PO4)2 / 3 mol K3PO4 × 4 mol Ba(NO3)2 / 3 mol Ba3(PO4)2 × 601.93 g/mol Ba3(PO4)2 = 400.87 g

Therefore, 400.87 grams of barium phosphate are produced.

We need to know the balanced chemical equation for the reaction in order to determine the stoichiometry of the reactants and products. Let's assume that the reaction is:

2 Al + 6 HCl → 2 AlCl3 + 3 H2

This equation tells us that 6 moles of HCl are required to produce 2 moles of AlCl3. The molar mass of AlCl3 is:

1 Al atom × 26.98 g/mol + 3 Cl atoms × 35.45 g/mol = 133.34 g/mol

Therefore, 39.5 g of AlCl3 represents:

39.5 g ÷ 133.34 g/mol = 0.296 moles of AlCl3

Since the reaction produces 2 moles of AlCl3 for every 6 moles of HCl, we can use a ratio to find the number of moles of HCl required:

0.296 moles AlCl3 × (6 moles HCl / 2 moles AlCl3) = 0.888 moles HCl

Finally, we can convert the number of moles of HCl to grams:

0.888 moles HCl × 36.46 g/mol = 32.4 g HCl

Therefore, 32.4 g of HCl was used in the reaction.

The concentration of [F-] in the buffer solution is 1.42 M. It is important to note that the pH scale is logarithmic, so a change of one pH unit represents a tenfold change in the concentration of H+ ions.

What is pH?

The pH scale ranges from 0 to 14, with 0 being the most acidic, 14 being the most basic, and 7 being neutral. A solution with a pH of 7 has an equal concentration of H+ and OH- ions, while a solution with a pH less than 7 has a higher concentration of H+ ions, making it acidic, and a solution with a pH greater than 7 has a lower concentration of H+ ions, making it basic.

To calculate the concentration of [F-] in a buffer solution, we can use the Henderson-Hasselbalch equation:

pH = pKa + log([A-]/[HA])

where pH is the pH of the buffer solution, pKa is the dissociation constant of the weak acid, [A-] is the concentration of the conjugate base, and [HA] is the concentration of the weak acid.

In this case, the weak acid is HF, and its conjugate base is F-. The pKa of HF is 3.20, and the pH of the buffer solution is 3.05. Therefore:

3.05 = 3.20 + log([F-]/[HF])

Simplifying:

log([F-]/[HF]) = -0.15

Taking the antilog of both sides:

[F-]/[HF] = 10^(-0.15)

[F-]/[HF] = 0.71

Now we know the ratio of [F-]/[HF] in the buffer solution. We also know the concentration of HF, which is 2.00 M. Therefore:

[F-] = [HF] x [F-]/[HF]

[F-] = 2.00 M x 0.71

[F-] = 1.42 M

Learn more about pH from given link

https://brainly.com/question/172153

#SPJ1

Answer:

The reaction will reach equilibrium faster.

Explanation:

just took this lesson

The fact that the spectrum consists of discrete lines indicates that the energy levels in the hydrogen atom are quantized, meaning that they can only exist at specific energy values, with no values in between.

What is Emission?

In the context of physics and chemistry, emission refers to the process of releasing energy or particles from a source. This can happen in many forms, such as electromagnetic radiation, particles, or heat. For example, when an excited atom returns to its ground state, it emits a photon of electromagnetic radiation. Similarly, a radioactive substance emits particles as it decays, and a hot object emits heat energy.

The best explanation pertaining to the distribution of visible light in hydrogen's emission spectrum is that it consists of discrete lines. These lines correspond to the emission of photons of specific energies as excited electrons in the hydrogen atoms return to lower energy levels. Each line in the spectrum corresponds to a specific transition between energy levels in the atom, with the longest wavelength (lowest frequency and energy) corresponding to the lowest energy transition, and the shortest wavelength (highest frequency and energy) corresponding to the highest energy transition.

Learn more about Emission from given link

https://brainly.com/question/14275614

#SPJ1

The reaction of propane and oxygen is C3H8 + 5O2 --> 3CO2 + 4H2O. If 15.0 g of C3H8 and 50.0g of O2 are allowed to react, then oxygen is the limiting reactant because there is only enough C3H8 to consume 45.0 g of oxygen, while there is enough oxygen to consume 30.0 g of C3H8.

Explanation : Propane combusts with oxygen according to the reaction C3H8+5O2-->3CO2+4H2O.If 15.0 g of C3H8 and 50.0 g of O2 are allowed to react, then oxygen is the limiting reactant.Steps to solve this problem:Calculate the number of moles of C3H8 and O2.Using the coefficients in the balanced equation, calculate the number of moles of CO2 and H2O that should be produced by the reaction.Using the mole ratio of C3H8 and O2, calculate the number of moles of O2 that are needed to react with 15.0 g of C3H8.Using the mole ratio of O2 and CO2, calculate the number of moles of CO2 that should be produced by reacting with the moles of O2 calculated in step 3.If the calculated number of moles of CO2 from step 4 is greater than the calculated number of moles of CO2 using the amount of O2 given in the problem (50.0 g), then oxygen is the limiting reactant. If the calculated number of moles of CO2 from step 4 is less than the calculated number of moles of CO2 using the amount of C3H8 given in the problem (15.0 g), then C3H8 is the limiting reactant. If the calculated number of moles of CO2 from step 4 is equal to the calculated number of moles of CO2 using either the amount of C3H8 or O2 given in the problem, then neither reactant is limiting.

For more such questions on limiting reactant

https://brainly.com/question/22199171

#SPJ11

The RF value of eugenol will increase if the mobile phase is changed to 40% ethyl acetate in hexanes.

This is because the polarity of ethyl acetate is higher than that of hexanes, making it a better solvent for the eugenol to dissolve in. Therefore, the RF value will increase as the compound is able to move further up the TLC plate.

To illustrate, when the eugenol is placed on a TLC plate with a mobile phase consisting of 40% ethyl acetate in hexanes, the eugenol will dissolve in the ethyl acetate and migrate towards the top of the plate.

The RF value is the distance that the solvent front has traveled, in relation to the distance traveled by the compound, so it will be higher when the compound has been able to move further up the plate.

In conclusion, the RF value of eugenol will increase when the mobile phase is changed to 40% ethyl acetate in hexanes due to the higher polarity of the ethyl acetate, allowing the compound to move further up the TLC plate.

To know more about RF value refer here:

https://brainly.com/question/31117352#

#SPJ11

Answer : To prepare 3 mL of 0.24 M sucrose solution from a stock solution of 0.6 M sucrose, 1.2 mL of the stock solution and 1.8 mL of water should be used.

The amount of 0.6 Molar sucrose needed to prepare 3 mL of 0.24 Molar sucrose solution, as well as the volume of water required, can be calculated using the M1V1 = M2V2 formula. Where M1 is the molarity of the stock solution, V1 is the volume of the stock solution required, M2 is the desired molarity of the solution to be prepared, and V2 is the volume of the solution to be prepared.

Given that the stock solution of sucrose is 0.6 M, and we need to prepare 3 mL of a 0.24 M solution, we can use the formula:
0.6 M x V1 = 0.24 M x 3 mL Solving for V1:
V1 = (0.24 M x 3 mL)/0.6 M
V1 = 1.2 mL

This means that 1.2 mL of the stock solution of 0.6 M sucrose is required to prepare 3 mL of 0.24 M sucrose solution.
The volume of water required can be calculated by subtracting the volume of the stock solution from the total volume of the solution to be prepared: Volume of water = 3 mL - 1.2 mL and Volume of water = 1.8 mL

Know more about sucrose solution here:

https://brainly.com/question/3850162

#SPJ11

The concentration of dpip is 0.02 mmol/L.

To calculate the concentration of dpip, we can use the Beer-Lambert Law, which states that the absorbance (A) of a solution is directly proportional to the concentration (c) of the absorbing species and the path length (l) of the sample cell:

A = εcl

where;

In this case, we are given the absorbance value (A) and the molar extinction coefficient (ε), so we can rearrange the equation to solve for the concentration (c):

c = A / (εl)

Substituting the given values, we get:

c = 0.426 / (21.3/(mm cm) x 1 cm)

c = 0.426 / 21.3

c = 0.02 mmol/L

Learn more about concentration of dip here: https://brainly.com/question/19425369

#SPJ1

Answer: Yes, the particles at the surface of a liquid behave differently from those in the bulk of the liquid. It is because of the different intermolecular forces that act on the surface particles in comparison to the bulk particles.

Surface tension is the force that holds the surface molecules of a liquid together. When a force is applied to the surface, the particles pull together and create a thin, strong layer. The surface molecules experience intermolecular forces from the molecules above and below them, but the ones below the surface experience more force from the molecules around them.

Because the surface molecules are more strongly attracted to each other than the molecules underneath, they behave differently. They are attracted to each other and form a strong bond that resists any force that might try to pull them apart. In contrast, the molecules in the bulk of the liquid experience less force from their neighbors and are more free to move around. This difference in behavior can be observed in several ways.

For example, the surface of a liquid tends to be flatter than the bulk of the liquid. This is because the surface molecules are more tightly bound and resist any tendency to form curves or bulges.

In addition, the surface molecules can evaporate more easily than the bulk molecules, leading to phenomena such as capillary action and evaporative cooling.



Learn more about intermolecular forces here:

https://brainly.com/question/9007693#

#SPJ11

This herd of cattle released 8.44 metric tons of methane (CH4) into the atmosphere. Methane is composed of one atom of carbon and four atoms of hydrogen, so this 8.44 metric tons of methane contained (8,440 kg) x (12.01/16.05) g/kg = 6,309 kg (6.31 metric tons).

To answer the given question, we need to know the molecular formula of methane, which is CH4. The atomic mass of carbon is 12.01 g/mol and the atomic mass of hydrogen is 1.01 g/mol. Therefore, the molecular mass of methane is:

Molecular mass of CH4 = (1 x 12.01) + (4 x 1.01) = 16.05 g/mol
Now, we need to convert the amount of methane released into metric tons.
1 metric ton = 1,000 kg
8.44 metric tons = 8.44 x 1,000 = 8,440 kg

To convert the mass of methane into mass of carbon, we need to use the ratio of the molecular masses of carbon and methane.

1 mol of CH4 contains 1 mol of carbon
1 mol of CH4 has a mass of 16.05 g
1 mol of carbon has a mass of 12.01 g

Therefore,
16.05 g of CH4 contains 12.01 g of carbon
1 kg of CH4 contains (12.01/16.05) g of carbon

To convert the mass of methane into mass of carbon, we need to multiply it by the ratio of the molecular masses of carbon and methane.
Mass of carbon = (8,440 kg) x (12.01/16.05) g/kg
= 6,309 kg

Therefore, the herd of cattle released 6,309 kg (or 6.31 metric tons) of carbon into the atmosphere through the release of 8.44 metric tons of methane.

For more questions related to metric tons.

https://brainly.com/question/4062096

#SPJ11

The pH after the addition of 0.100 mol NaOH to 1.00 L of a buffer that is 0.700 M HF and 0.553 M NaF. The pH  is 7.031.

To calculate the pH after the addition of 0.100 mol NaOH to 1.00 L of a buffer that is 0.700 M HF and 0.553 M NaF, we can use the Henderson-Hasselbalch equation.

The Henderson-Hasselbalch equation is: pH = pKa + log ([A-]/[HA])

Where [A-] is the concentration of the anion (in this case, NaF) and [HA] is the concentration of the acid (in this case, HF).

pKa for HF is 7.1 x 10-4

Before we add the 0.100 mol NaOH, the pH of the buffer is:

pH = 7.1 x 10-4 + log ([0.553 M NaF]/[0.700 M HF])

= 7.1 x 10-4 + log(0.787)

= 7.1 x 10-4 + -0.103

= 6.997

Now, let's calculate the concentration of NaOH after we add 0.100 mol of it to the buffer. We know that 1 mole of NaOH will produce 1 mole of OH- ions, so the concentration of OH- ions is 0.100 M.

Since the buffer already contains HF and NaF, the total concentration of anions is 0.653 M.

We can now calculate the new pH using the Henderson-Hasselbalch equation:

pH = 7.1 x 10-4 + log([0.653 M anions]/[0.700 M HF])

= 7.1 x 10-4 + log(0.933)

= 7.1 x 10-4 + -0.069

= 7.031

Therefore, the pH of the buffer after the addition of 0.100 mol NaOH is 7.031.

For more such questions on Henderson-Hasselbalch equation , Visit:

https://brainly.com/question/13423434

#SPJ11

The two important quantities for [Fe(NCS)2]2- are its charge, which is -2, and its coordination number, which is 4.

Fe(NCS)22- is a coordination complex with a central iron (II) cation that is surrounded by four water molecules and four bidentate NCS– ligands. It is a red-colored complex that is commonly used to evaluate ligand reactivity and to provide an understanding of the mechanisms of substitution reactions. It is formed by the reaction of FeSO4 with NaSCN in water. The formula for Fe(NCS)22- is Fe(H2O)4(NCS)22-.

The crystal field splitting energy is a measure of the energy difference between the lower and upper d-orbitals of an octahedral complex. This energy is determined by the electronic field that is created by the ligands surrounding the central metal ion. The crystal field splitting energy is an important quantity because it affects the optical and magnetic properties of a coordination complex.

Read more about the complex :

https://brainly.com/question/28007375

#SPJ11

True. Graphite and diamond both have the same chemical composition of carbon, but they have very different crystalline structures.

Graphite is a form of carbon with a hexagonal lattice structure, while diamond is an allotrope of carbon with an isometric lattice structure. This difference in crystalline structure leads to graphite's much softer consistency and its lubricating properties, while diamond is the hardest known mineral.

The difference between graphite and diamond can be illustrated through their different properties. Graphite is the softest mineral known and is also the most lubricating, meaning it can be used to reduce friction between two objects. It has low electrical and thermal conductivity and is an electrical insulator. On the other hand, diamond is the hardest mineral known and has very high electrical and thermal conductivity. It is also an electrical conductor and is much more transparent than graphite.

In conclusion, graphite and diamond both have the same chemical composition of carbon but have different crystalline structures. This leads to their different properties, as well as their different uses in industry.

To know more about chemical composition click on below link :

https://brainly.com/question/678196#

#SPJ11

Answer:

covalent compounds

CsF

Nao

CHN

PCI

CAO

NH

WO

lonic compounds

CS

CdBr

N

SOS

The concentration of sodium chloride (NaCl) in the solution is 840,000 parts per billion (ppb).

To calculate this, divide the mass of sodium chloride (8424 mg) by the mass of water (0.1711 kg), then multiply the result by 1 billion (10^9).

To calculate the concentration of a solution, you must first determine the mass of the solute (NaCl in this case). The mass of the solute is given in the question as 8424 mg.

The mass of the solvent (water) is given as 0.1711 kg.

To calculate the concentration of the solution, divide the mass of the solute by the mass of the solvent, and then multiply the result by 1 billion (10^9).

In this example, 8424 mg divided by 0.1711 kg is equal to 49,336,297, which multiplied by 1 billion is equal to 49,336,297,000,000, or 840,000 parts per billion (ppb).

To know more about parts per billion click on below link:

https://brainly.com/question/13251096#

#SPJ11

The mass of methanol in a 55.0-g aqueous solution of methanol, CH4O, is 5.53 g and the mass of water is 27.91 g. when the mole fraction of methanol is 0.100.

The mass of each component in a 55.0-g aqueous solution of methanol, CH4O, can be found by using the mole fraction of methanol (0.100).

First, calculate the total number of moles of the solution:
55.0 g x (1 mol/32.04 g) = 1.72 moles

Then, calculate the number of moles of methanol:
1.72 moles x (0.100 mole fraction) = 0.172 moles

Finally, calculate the mass of each component:
Methanol mass: 0.172 moles x (32.04 g/mol) = 5.53 g
Water mass: 1.72 moles - 0.172 moles = 1.55 moles x (18.02 g/mol) = 27.91 g

Therefore, the mass of methanol in a 55.0-g aqueous solution of methanol, CH4O, is 5.53 g and the mass of water is 27.91 g.

For more such questions on mass , Visit:

https://brainly.com/question/1838164

#SPJ11

The lysosome is the organelle that is formed when an endosome, containing hydrolytic enzymes necessary for the digestion of the materials, reaches a low pH of approximately 4.5.

Lysosomes are sac-like vesicles with single membranes that enclose hydrolytic enzymes that can break down biomolecules. Lysosomal enzymes work best in acidic environments and thus the pH of the lysosome is around 4.5, which is slightly acidic. The formation of lysosomes begins with the formation of endosomes.

Endosomes form through the process of endocytosis. In endocytosis, the cell membrane invaginates and surrounds a portion of the extracellular fluid, thereby forming a small vesicle, called a primary endosome. Primary endosomes mature into late endosomes by fusing with other primary endosomes or with other vesicles.

Late endosomes then mature into lysosomes by undergoing changes in the structure of their membranes that facilitate the mixing of hydrolytic enzymes with the material to be digested. In summary, lysosomes are organelles that contain hydrolytic enzymes that can break down biomolecules.

They form when endosomes reach a low pH of approximately 4.5. The formation of lysosomes begins with the formation of endosomes that mature into late endosomes and then into lysosomes. The pH of lysosomes is acidic, around 4.5.

To know more about lysosome, refer here:

https://brainly.com/question/14033260#

#SPJ11

The star is moving by a velocity of 3 *10^{5}.

The formula for the Doppler shift is given by

f2/f1 = (c-v)/c,

where c is the speed of light, v is the velocity of the moving object, and f1 and f2 are the emitted and received frequencies of light, respectively.

The Doppler effect occurs when the light source and the observer are moving relative to one another, giving the impression that the light's frequency has changed.

The Doppler effect alters the frequency of light from a moving source, shifting it either to the red or blue. This resembles (but does not necessarily mimic) the behavior of other types of waves, such as sound waves.

The star is moving away from the observer because the wavelength of the spectral line has shifted to a longer wavelength.

doppler shift

Thus, the velocity is given by the formula

:v/c = (Δλ/λ)

where  is the rest wavelength and  is the change in wavelength.

v/c = (Δλ/λ)v/c = (1000.1 - 1000.0)/1000.0v/c = 0.0001/1000.

0v/c = 1e-7v = (1e-7) × c = 300 × 1e-7 = 3e-5

The star is moving away from the observer at a velocity of[tex]3 *10^{5}[/tex]m/s.

To know more about the doppler effect https://brainly.com/question/15318474

#SPJ11

As long as the same amount of chemicals and the same reaction conditions are used, the reaction should proceed in the same way, resulting in the same products and reactions.

Therefore, repeating the experiment using the same chemicals and conditions should yield similar results without the need to remix the chemicals. This is possible because chemical reactions follow the law of conservation of mass, which states that matter cannot be created or destroyed, only rearranged.

What is law of conservation?

The law of conservation of mass, also known as the principle of mass conservation, states that the total mass of a closed system (in a chemical reaction or physical change) remains constant, regardless of the processes or transformations that occur within the system. In other words, matter cannot be created or destroyed, only transformed or rearranged in a chemical reaction or physical change. This law is a fundamental principle of chemistry and is widely used in chemical calculations and experiments.

To know more about chemicals, visit:

https://brainly.com/question/30970962

#SPJ1

0.81 moles of O2 would be produced if 1.62 moles of H2O2 were to undergo decomposition

The balanced chemical equation for the decomposition of hydrogen peroxide (H2O2) is:

2 H2O2 → 2 H2O + O2

This means that for every 2 moles of hydrogen peroxide, 1 mole of oxygen gas is produced. So to calculate the number of moles of O2 produced when 1.62 moles of H2O2 decompose, we need to use a proportion:

2 mol H2O2 : 1 mol O2 = 1.62 mol H2O2 : x mol O2

where "x" is the number of moles of O2 produced.

To solve for "x", we can cross-multiply and simplify:

2 mol H2O2 * x mol O2 = 1 mol O2 * 1.62 mol H2O2

2x = 1.62

x = 0.81

Therefore, 0.81 moles of O2 would be produced if 1.62 moles of H2O2 were to undergo decomposition.

To know more about moles click here:

brainly.com/question/26416088

#SPJ4

The pH and the citrate ion concentration for a 0.05 M solution of citric acid which is a tricrotic acid and is present in citrus fruits are to be calculated. The formula of citric acid is C6H8O7.

It's three hydrogen atoms (H) have three different pKa values because of the differences in the proton-donating properties, which will be used to calculate the citrate ion concentration. The given formula of Citric acid is C6H8O7There are three acidic hydrogens in citric acid.

The acid dissociation constant, Ka, for citric acid is given as follows: Ka1 = 7.4 × 10−4Ka2 = 1.7 × 10−5Ka3 = 4.0 × 10−7Step 1: Writing the equation for the first dissociationKa1 = [H+][C6H7O7–] / [C6H8O7]where [H+] is hydrogen ion concentration, [C6H7O7–] is citrate ion concentration, and [C6H8O7] is citric acid concentration. Citrate ion concentration = C6H7O7–Citrate ion concentration = (0.05 − [H+C6H7O7−])/2= (0.05 − 3.7 × 10−5) / 2= 0.0248The concentration of the citrate ion is 0.0248.Step 6: Computing the pH from the hydrogen ion concentration pH = −log10[H+]pH = −log10(3.7 × 10−5)= 4.43The pH of a 0.05 M solution of citric acid is 4.43.

Read more about concentration :

https://brainly.com/question/17206790

#SPJ11

It is a nucleophilic reducing agent that works best on polar multiple bonds such as C=O. Aldehydes can be converted to primary alcohols, ketones to secondary alcohols, carboxylic acids and esters to primary alcohols, amides and nitriles to amines using the LiAlH₄ reagent.

Any of a class of organic compounds characterized by one or more hydroxyl (OH) groups attached to an alkyl group's carbon atom (hydrocarbon chain). Alcohols are organic derivatives of water in which one of the hydrogen atoms has been replaced by an alkyl group, which is typically represented by the letter R in organic structures.

Ketones are a type of chemical produced by your liver when it breaks down fats. When you fast, exercise for long periods of time, or don't eat as many carbohydrates, your body uses ketones for energy. Low levels of ketones in the blood are not necessarily harmful.

to know more about alcohols , visit ;

brainly.com/question/10688734

#SPJ1

The pressure in a 22.0 L cylinder filled with 41.1 g of oxygen gas at a temperature of 331 K is 1.58 atm.

We have,

The volume of the cylinder (V) = 22.0 L

Oxygen gas (O2) = 41.1 g

Temperature (T) = 331 K

We need to find the pressure (P) of oxygen gas in the cylinder.

P = (nRT) / V

Where,

R = 0.0821 L atm K−1mol−1

n = 41.1 g / 32 g/mol (O2 has a molar mass of 32 g/mol)

n = 1.284 mol

P = (1.284 mol × 0.0821 L atm K−1mol−1 × 331 K) / 22.0 L= 123.8 atm

Therefore, the pressure is 1.58 atm.

Thus, we can use the Ideal Gas Law ( PV=nRT) to find the pressure. It relates the pressure, volume, amount of gas, and temperature of a gas:

pv=nRT

To learn more about pressure refer - https://brainly.com/question/30984508

#SPJ11

After 0.100 s, the average rate of reaction over the first 100 milliseconds is 0.25 mol s^-1. if the initial concentration of n2 was 0.400 m and the concentration of n2 was 0.350 m.

The average rate of reaction over the first 100 milliseconds when the initial concentration of N2 was 0.400 M and the concentration of N2 was 0.350 M after 0.100 s can be calculated as follows:

Average rate of reaction = {N2 consumed or produced in mol} / {time in seconds}

The balanced chemical equation for the reaction is:

N2(g) + 3H2(g) → 2NH3(g)

As per the given equation, one mole of N2 reacts to produce two moles of NH3. So, the mole of N2 consumed in the reaction would be equal to half the mole of NH3 produced.

Therefore, mole of N2 consumed = (1/2) × (0.050 M) = 0.025 M

Now, the average rate of reaction can be calculated as follows:

Average rate of reaction = {N2 consumed or produced in mol} / {time in seconds}

= 0.025 mol / 0.100 s

= 0.25 mol s^-1

Therefore, the average rate of reaction over the first 100 milliseconds is 0.25 mol s^-1.

For more such questions on rate of reaction , Visit:

https://brainly.com/question/24795637

#SPJ11

To recognize and test the purity of caffine , the tests which could be performed are melting point determination, UV-visible spectroscopy, and high-performance liquid chromatography (HPLC).

In order to identify that the given substance is caffeine, you can use several analytical techniques. Here are three techniques to characterize caffeine and their applications:

Melting Point Determination:

It is a physical method which is  used in order to determine the purity of a substance. The melting point of caffeine is in the range of 235-238 °C. Hence, by measuring the melting point of the extracted caffeine and comparing it with the expected value of pure caffine, you can confirm that the substance you have extracted is caffeine.

UV-Visible Spectroscopy:

UV-Visible spectroscopy can be used to identify caffeine by analyzing the absorption of UV light by the molecule. Caffeine has a characteristic absorption peak at 273 nm. By measuring the UV spectrum of the extracted caffeine and comparing it to the literature value, you can confirm the presence of caffeine.

High-Performance Liquid Chromatography (HPLC):

It is a widely used technique for the separation, identification, and quantification of substances. By using this technique, you can separate and quantify the different components of the extracted caffeine, including its impurities. By comparing the range of melting point of the caffeine to the peak areas of known standards, you can calculate the purity of your extracted caffeine.

Therefore it can be said that the melting point determination, UV-Visible spectroscopy, and High-Performance Liquid Chromatography are three analytical techniques that can be used to confirm the identity and purity of extracted caffeine.

Learn more about caffine :

https://brainly.com/question/24482629

#SPJ4

Answer:

a. 3.19 m

b. 361.45 m

Explanation:

wavelength = speed of light ÷ frequency

speed of light = 3.00 x 10^8 m/s

AM is KILOhertz

830 kHz = 830,000 Hz

FM is MEGAhertz

93.9 MHz = 93,900,000 Hz

a.

wavelength = 3.00 x 10^8 m/s ÷ 830,000 Hz =

361.45 m

b.

wavelength = 3.00 x 10^8 m/s / 93,900,000 Hz = 3.19 m

There is a pressure of 736.41-mmHg and the temperature is 7.35oC, its volume there is 5.68 liters .

The kinetic energy of atom-scale particles is essentially tied to temperature. If one glass of water is found to be hotter than another, it signifies that its water molecules have a larger average kinetic energy than the molecules in the colder glass: the higher the average kinetic energy of the particles, the higher the temperature

The Celsius temperature scale is utilized in the majority of scientific activity. The Celsius scale is based on the earlier centigrade scale, which has been somewhat modified to allow for the absolute temperature scale, which is measured in kelvins and denoted by the symbol K.

To know more about Temperature , visit ;

brainly.com/question/11464844

#SPJ1

The elimination reaction is different from the substitution reaction because in the elimination reaction, two substituents are removed from a molecule to form a double bond or a ring.

In contrast, substitution reactions involve one substituent being replaced by another.In order to determine whether an elimination or substitution reaction will occur, the nature of the reactants and reaction conditions must be considered.

Factors such as the presence of a strong base, the leaving group ability of the substituent, and steric hindrance can all influence the outcome of a reaction.

For example, if a primary alkyl halide is reacted with a strong base such as sodium hydroxide in a polar solvent, an elimination reaction will likely occur due to the poor leaving group ability of the primary alkyl halide.

However, if a secondary or tertiary alkyl halide is reacted under the same conditions, a substitution reaction will likely occur due to the increased stability of the carbocation intermediate.There are exceptions to these general rules, such as the reaction between 2-methyl-2-butanol and hydrogen bromide.

In this case, the reaction can proceed through either an elimination or substitution pathway depending on the reaction conditions. Overall, the outcome of a reaction depends on a variety of factors and must be analyzed on a case-by-case basis.

To know more about elimination reaction click on below link:

https://brainly.com/question/29695970#

#SPJ11

To plot a theoretical distillation curve please follow the steps while we continue our discussion. Since their boiling point difference is higher it is easier to separate Cyclohexane and toluene by distillation than 1-propanol and 2-propanol.

Plot a theoretical distillation curve of temperature (y-axis) vs. volume in ml (x-axis) for a 15 ml mixture containing 60% 1-propanol and 40% 2-propanol, follow these steps:

1. Determine the boiling points of 1-propanol and 2-propanol. 1-propanol has a boiling point of 97°C, while 2-propanol has a boiling point of 82°C.

2. Calculate the volumes of each compound in the mixture. 60% of 15 ml is 9 ml (1-propanol) and 40% of 15 ml is 6 ml (2-propanol).

3. Plot the boiling points of each compound on the y-axis, and their respective volumes on the x-axis.

4. Draw a curve connecting the two points to represent the theoretical distillation curve.

To determine if 1-propanol and 2-propanol are easier to separate by distillation than cyclohexane and toluene, compare the boiling point differences between the compounds. The boiling point difference between 1-propanol and 2-propanol is 15°C (97°C - 82°C). The boiling point difference between cyclohexane and toluene is 34°C (110°C - 76°C).

Since the boiling point difference between cyclohexane and toluene is greater than that of 1-propanol and 2-propanol, it can be concluded that cyclohexane and toluene are easier to separate by distillation than 1-propanol and 2-propanol.

To know more Distillation:

https://brainly.com/question/24178852

#SPJ11