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The probability that a dessert chosen at random contains nuts given that it contains chocolate is 34.9%.

The likelihood of any event A happening when another event B related to A has already happened is known as conditional probability. This implies that the likelihood of event A relies on event B.

The conditional probability symbol is P(A|B). Conditional probability P(A|B) is crucial for any exam that is part of a competition. The concept of conditional probability P(A|B), formula, and examples with solutions are all covered in this article. The Bayes theorem predicts the likelihood that an event connected to any condition would occur. For the situation of conditional probability, this theorem is taken into account.

Let A : a certain cafe contains chocolates

B: a dessert contains Nuts

P(A) = 86% = 0.86

P(AB) = 30% = 0.3

[tex]P(B|A) =\frac{P(AB)}{P(A)}[/tex]

= 0.3/0.86

= 34.9 %

So the answer is 34.9%

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The union and intersection of n sets that are all subsets of the universal set u can be found using bit strings.

Bit strings are a way of representing sets as strings of binary digits. To represent a set, each element is assigned a digit of 0 or 1. A 1 indicates that the element is in the set, while a 0 indicates that the element is not in the set.

The union of the sets is found by combining the bit strings and setting any digit that is 1 in any of the sets to a 1. The intersection is found by comparing the bit strings and setting any digit that is 1 in all of the sets to a 1.

By using bit strings, we can quickly and accurately find the union and intersection of n sets that are all subsets of the universal set u.

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The sum of all eight factors is 96

Let's express the integer as a product of its prime factors, in the form

n = p1^a1 × p2^a2 × ... × pn^an

where p1, p2, ..., pn are prime numbers and a1, a2, ..., an are positive integers.

We know that the integer has 8 factors, which means that its prime factorization must have the form:

n = p1^2 × p2^2 × p3^4

since (2+1) × (2+1) × (4+1) = 3 × 3 × 5 = 45, which is the total number of factors for this product.

We also know that 15 and 21 are factors of the integer, so they must be expressible in terms of the prime factors of n. We can write

15 = 3 × 5 = p1 × p2

21 = 3 × 7 = p1 × p3

From these expressions, we can see that p1 = 3, p2 = 5, and p3 = 7.

Therefore, the prime factorization of n is

n = 3^2 × 5^2 × 7^4

The eight factors of n are

1, 3, 5, 7, 9, 15, 21, and 35

Their sum is

1 + 3 + 5 + 7 + 9 + 15 + 21 + 35 = 96

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The simplified algebraic expression for the perimeter of the yard is 28m+10x, and if x=3m, then the perimeter is 58m.

The simplified algebraic expression for the perimeter of the yard is 28m+10x, and if x=3m, then the perimeter is 58m.

In the given figure, the yard is in the shape of a rectangle with dimensions (4x - 6) m and (2x + 3) m. The perimeter of a rectangle is the sum of the lengths of all four sides, which can be expressed as:

Perimeter = 2(Length + Width)

Perimeter = 2(4x - 6 + 2x + 3) m

Perimeter = 2(6x - 3) m

Perimeter = 12x - 6 m

So, a simplified algebraic expression for the perimeter of the yard is 12x - 6 m.

To find the perimeter in meters when x = 3 m, substitute x = 3 into the algebraic expression for perimeter:

Perimeter = 12(3) - 6 m

Perimeter = 30 m

Therefore, the perimeter of the yard when x = 3 m is 30 meters.

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Answer: 21, 32. 6, 12.

Step-by-step explanation:

10 + 3d = 43. 3d = 33. d = 11.

3 x [tex]r^{3}[/tex] = 24. [tex]r^{3}[/tex] = 8. r = 2.

Answer:1, -.66 repeating, 1.25

Step-by-step explanation  i turned them into decimals

24/8x-1/3= -1

-2/5x5/3= -.66 repeating

-5/6x-3/2= 1.25

The value of p from the given equation is 4.5.

In mathematics, an equation is a formula that expresses the equality of two expressions, by connecting them with the equals sign [tex]=\\[/tex].

The given equation is [tex]0.5p-3.45=-1.2[/tex]

The solution of an equation is the set of all values that, when substituted for unknowns, make an equation true.

The equation can be solved as follows

[tex]0.5p-3.45=-1.2[/tex]

[tex]0.5p= -1.2+3.45[/tex]

[tex]0.5p= 2.25[/tex]

[tex]p= 2.25\div0.5[/tex]

[tex]p= 4.5[/tex]

Therefore, the value of p is 4.5.

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The result is the t-statistic, which is used to compare the two samples.

The t-test is used to compare the means of two independent samples. The formula for the t-test is:

[tex]t = (x1 - x2) / √[s2/n1 + s2/n2][/tex],

where x1 is the mean of the first sample, x2 is the mean of the second sample, s2 is the variance of the two samples, and n1 and n2 are the sizes of each sample.

To calculate the t-test, first you need to calculate the mean for each sample. If the sample size is small (less than 30), then you should use the sample standard deviation.

Next, calculate the variance for each sample by taking the sum of the squared differences from the mean, and dividing by n-1 (where n is the sample size).

Finally, calculate the t-test statistic by substituting the means and variances into the formula above. The result is the t-statistic, which is used to compare the two samples.

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Answer:

They are congruent by AA- because the only thing they have in common is the 65 degree angles but the sides are all different

Step-by-step explanation:

Kendra cost $0.60 for each egg and $0.30 for each piece of toast.

Let's assume that the cost of one egg is x and the cost of one piece of toast is y.

From the given information, we can set up two equations:

2x + y = 1.5

x + y = 0.9

We can solve this system of equations by either substitution or elimination method.

Using the elimination method, we can multiply the second equation by -2 to eliminate y:

-2x - 2y = -1.8

2x + y = 1.5

Adding these two equations, we get:

-1y = -0.3

y = 0.3

Substituting y = 0.3 in either of the two equations, we get:

x = 0.6

Therefore, Kendra charges $0.60 for each egg and $0.30 for each piece of toast.

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The statement is true.

The coefficient of correlation, also known as the Pearson correlation coefficient, is a measure of the strength and direction of the linear relationship between two variables. It ranges from -1 to 1, with a value of -1 indicating a perfect negative correlation, a value of 0 indicating no correlation, and a value of 1 indicating a perfect positive correlation.

The coefficient of correlation is useful in many applications, including research, business, and finance. It allows us to quantify how closely related two variables are, which is important when analyzing data and making predictions.

For example, in finance, the correlation coefficient can be used to measure the degree of correlation between the returns of two assets, which is important when building diversified portfolios. It is important to note, however, that the coefficient of correlation only measures the strength and direction of the linear relationship between two variables.

It does not indicate causation, nor does it capture any non-linear relationships that may exist between the variables. Therefore, it should be used in conjunction with other analytical tools to fully understand the nature of the relationship between the variables.

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Answer: Proper fraction

Step-by-step explanation:

A proper fraction is a fraction that has its numerator value less than the denominator.

For example, ⅔, 6/7, 8/9, etc. are proper fractions.

Answer:

Since the decoration is in the shape of a triangle, we can use the formula for the area of a triangle to solve for its height. The area of a triangle is given by:

Area = (1/2) x base x height

Let's call the height of the decoration h. We know that the base after firing is 9 inches, so we can plug in the given values and solve for h:

Area = (1/2) x 9 x h

Area = 4.5h

We don't know the exact area of the decoration, but we do know that the decoration maintains its shape after firing. This means that the ratio of the areas before and after firing is the same, and so is the ratio of the heights and bases. Since the height and base are proportional, we can write:

h / 15 = 9 / 10

Simplifying the equation, we get:

h = (9/10) x 15

h = 13.5

Therefore, the height of the finished decoration is 13.5 inches.

To begin, we know that the median of the original collection of five positive integers is 4, which means that the middle number is 4. We also know that the unique mode is 3, which means that there is only one number in the collection that occurs more frequently than any other number.

Let's call the five positive integers in the original collection a, b, c, d, and e.

Since the mean of the original collection is 4.4, we can set up the equation:

(a+b+c+d+e)/5 = 4.4

Multiplying both sides by 5 gives:

a+b+c+d+e = 22

We also know that the mode is 3, which means that one of the numbers in the collection must be 3. Let's assume that a = 3, then we have:

3+b+c+d+e = 22

b+c+d+e = 19

Since the median is 4 and 3 is the unique mode, we can conclude that b, c, d, and e must be either 4 or 5. However, since there is only one unique mode, we know that there is only one number in the collection that is equal to 3. Therefore, we can conclude that the collection of five positive integers must be: 3, 4, 4, 4, 5.

If we add 8 to this collection, the new collection becomes: 3, 4, 4, 4, 5, 8. The new collection has six numbers, so the median is now the average of the two middle numbers. Since the middle two numbers are 4 and 5, the median is (4+5)/2 = 4.5.

Therefore, the new median is 4.5, expressed as a decimal to the nearest tenth.

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Option D : Matching a 3D shape to its net requires visual spatial reasoning and knowledge of geometry.

A net is a two-dimensional pattern that can be folded to form a three-dimensional shape. It shows how the faces of a 3D shape are connected and arranged in a flat layout. The process of making a net involves taking apart a 3D object and flattening it out without stretching or bending any of the faces.

A net must accurately represent the dimensions and features of the 3D shape it represents, such as the shape and size of each face, the number of edges and vertices, and the angles between the faces.

Some common 3D shapes that can be represented by nets include cubes, pyramids, prisms, cylinders, and cones. Nets can be created using various methods, such as drawing them by hand, using computer software, or printing them from online sources. When constructing a 3D object from a net, it is important to fold and join the edges carefully to ensure that the final shape is accurate and stable.

Therefore, the correct net that matches the 3D shape is option D.

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Answer:

Step-by-step explanation:lllllLet's start by using "R" to represent the number of apps that Rita started with, and "C" to represent the number of apps that Cora started with.

We know that Rita deleted 5 apps, so she would have (R-5) apps remaining. And we know that she still had twice the amount of Cora, which is 36.

So we can write the equation:

R-5 = 2C

And we also know that Cora had 36 apps, so we can substitute that value in for C:

R-5 = 2(36)

Simplifying the right side:

R-5 = 72

Finally, we can solve for R by adding 5 to both sides:

R = 77

So Rita started with 77 apps, and Cora started with 36 apps. We can check that Rita deleted 5 and had twice as many as Cora by plugging our values into the original equation:

77 - 5 = 72

2(36) = 72

Both sides are equal, so our solution is correct.

There is a .90 probability that the project will be completed before approximately day 118.

The given information can be solved by using the formula of z-score as follows:

Z = (X - μ)/σ

Where: Z = z-score

X = the time for project completion

μ = the mean time for the critical path

σ = standard deviation for the critical path

σ² = variance of the critical pathσ = √64

σ = 8

Given that the mean time for the critical path is μ = 108 days and σ = 8 days,

Therefore, the z-score of the completion of the project before 108 days is given by:

Z = (X - μ)/σ0.90

 = P(Z < z)

 = P(Z < (X - 108)/8)P(Z < (X - 108)/8)

 = 0.90

Using a z-table or calculator, we find the z-value to be 1.28.

Then,1.28 = (X - 108)/8

Multiplying both sides by 8, we get:10.24 = X - 108

Adding 108 to both sides, we get: X = 118.24

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Correct option is (c) 3174

The probability that a randomly selected case will have a score beyond either +1.00 or -1.00 standard deviation of the mean depends on the type of distribution and the area under the curve beyond these values.

Assuming a normal distribution, approximately 68% of the cases fall within one standard deviation from the mean, and approximately 32% of the cases fall beyond either +1.00 or -1.00 standard deviation of the mean.

To calculate the probability of a randomly selected case falling beyond either +1.00 or -1.00 standard deviation of the mean, we need to calculate the area under the curve beyond these values. Since the distribution is symmetric, we can calculate the area on one side of the mean and multiply it by 2.

Using a standard normal distribution table or calculator, we can find the area under the curve beyond +1.00 standard deviation from the mean as 0.1587 and the area under the curve beyond -1.00 standard deviation from the mean as 0.1587.

Therefore, the total probability of a randomly selected case falling beyond either +1.00 or -1.00 standard deviation of the mean is 0.1587 + 0.1587 = 0.3174, which is approximately 32%.

Hence, the correct option is (c) 3174.

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Therefore, the value of θ for the acute angle in a right triangle is 46°.We can use the fact that the sine and cosine of complementary angles are equal to find θ.

To find the value of θ for the acute angle in a right triangle, we need to use one of the trigonometric ratios. In this case, we are given the sine of θ and the cosine of 44°.  Recall that the sine of an angle θ is defined as the ratio of the opposite side to the hypotenuse in a right triangle:

sin(θ) = opposite / hypotenuse

And the cosine of an angle φ is defined as the ratio of the adjacent side to the hypotenuse:

cos(φ) = adjacent / hypotenuse

In a right triangle, the two acute angles are complementary, which means that their sum is 90°. That is,θ + 90° = 90°

θ = 90° - 44°.Now we can use the given equation sin(θ) = cos(44°) and substitute θ: sin(90° - 44°) = cos(44°) => sin(46°) = cos(44°)

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Option C, 12, is the correct answer. To spray the vegetables 5 times each hour, we need to determine how often the spray should occur.

Since there are 60 minutes in an hour, and we want the vegetables to be sprayed 5 times in that hour, we can divide 60 by 5 to get the interval between each spray:

60 ÷ 5 = 12

This means that the interval between each spray should be 12 minutes. Therefore, we should set the timer for 12 minutes in order to spray the vegetables 5 times each hour.

Option C, 12, is the correct answer.

It is important to note that this assumes the vegetable display is in operation for the entire hour without interruption. If the display is turned off or there are other factors that interrupt the timing, the frequency of sprays may be affected. Additionally, the optimal frequency of sprays may vary depending on the specific vegetables and the environment they are in.

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Answer:

negative linear association

Step-by-step explanation:

The best description of the association between life expectancy and infant mortality rate in the given graph is option B. Countries with higher infant mortality rates tended to have shorter life expectancies.

The negative linear association between life expectancy and infant mortality rate in the attached graph,

Life Expectancy,

Life expectancy refers to the average number of years a person is expected to live from birth.

In the graph, life expectancy is represented on the vertical axis (y-axis).

Infant Mortality Rate,

Infant mortality rate refers to the number of deaths of infants under one year of age per 1,000 live births.

In the graph, the infant mortality rate is represented on the horizontal axis (x-axis).

Negative Linear Association,

A negative linear association means that as one variable increases, the other variable tends to decrease at a consistent rate.

here, as the infant mortality rate increases (moving right on the x-axis), the life expectancy tends to decrease (moving down on the y-axis).

Interpretation,

Looking at the graph, we can see that countries with higher infant mortality rates are positioned towards the right side of the graph,

and they tend to have shorter life expectancies, which are positioned towards the bottom of the graph.

Conversely, countries with lower infant mortality rates are positioned towards the left side of the graph, and they tend to have longer life expectancies,

which are positioned towards the top of the graph.

Implication,

The negative linear association in the graph indicates that countries with higher rates of infant mortality are likely to have lower life expectancies.

This is because higher infant mortality rates often indicate poorer healthcare systems, lower living standards,

and other factors that can impact life expectancy negatively.

Therefore, based on the graph's trend, we can conclude that the statement B is the best description of the association between life expectancy and infant mortality rate.

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The above question is incomplete , the complete question is :

The Graph Below Shows The Relationship Between Life Expectancy And Infant Mortality Rate In A Random Sample Of Countries.

Which statement is the best description of the association between these variables? Choose all that apply.

A. Countries with higher infant mortality rates tended to have longer life expectancies.

B. Countries with higher infant mortality rates tended to have shorter life expectancies.

C. There is no clear relationship between infant mortality rates and life expectancy.

Attached graph.

The probability of P(more than 1 hour of TV | 6th period class) is option (D) 0.765

To find P(more than 1 hour of TV | 6th period class), we need to use conditional probability formula

P(more than 1 hour of TV | 6th period class) = P(more than 1 hour of TV and 6th period class) / P(6th period class)

The number of students who watched more than 1 hour of TV and were in the 6th period class is 13. Therefore, P(more than 1 hour of TV and 6th period class) = 13 / (13 + 10) = 13/23.

The total number of students in the 6th period class is 13 + 10 = 23. Therefore, P(6th period class) = 23 / (6 + 23) = 23/29.

Putting it all together

P(more than 1 hour of TV | 6th period class) = P(more than 1 hour of TV and 6th period class) / P(6th period class) = (13/23) / (23/29) = 0.765 (rounded to the nearest thousandth)

Therefore, the correct option is (D) 0.765

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The given question is incomplete, the complete question is:

The table shows the results of a survey of students in two math classes. Find P(more than 1 hour of TV | 6th period class). Round to the nearest thousandth. Did You Watch More Than One Hour of TV Last Night? Yes No 3rd period class 6 6th period class 13 10 A) 0.647 B) 0.565 C) 0.435 D) 0.765

The area of the walkway can be expressed as the sum of two terms is 9x + 7 and 10x + 4.

We are given that the area of the garden is 6(5.5x + 2.5). This means that the garden has a length of 5.5x + 2.5 units and a width of 6 units (since the problem doesn't specify which side is the length or width, we can assume either). We can use the formula for the area of a rectangle to find the area of the garden:

Area of the garden = length x width = (5.5x + 2.5) x 6 = 33x + 15

Next, we are given that the combined area of the garden and the walkway is 6.5(8x + 4). This means that the garden and the walkway together have a length of 8x + 4 units and a width of 6.5 units. We can again use the formula for the area of a rectangle to find the combined area:

Combined area = length x width = (8x + 4) x 6.5 = 52x + 26

To find the area of the walkway, we need to subtract the area of the garden from the combined area. This will give us the area of the walkway alone.

Area of the walkway = Combined area - Area of the garden

= (52x + 26) - (33x + 15)

= 19x + 11

Finally, we are asked to express the area of the walkway as the sum of two terms. This means we need to find two numbers that add up to 19 and two numbers that add up to 11. We can use trial and error to find these numbers. One possible solution is:

19x + 11 = (9x + 7) + (10x + 4)

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The standard form is 5x²-2x-4=0

A quadratic equation can be written in other forms.

Standard Form: ax²+bx+c=0

Vertex Form: a (x - h)2 + k = 0

Intercept Form: a (x - p)(x - q) = 0

This equation is called 'quadratic' as its degree is 2

The standard form of a quadratic equation is also known as its general form.

ax²+bx+c=0

with the conditions :  a ≠ 0, and a, b, and c are real numbers

'a' is the coefficient of x²

'b' is the coefficient of x

'c' is the constant

here a= 5 b= -2 c= -4

Shift all the terms to one side and write in standard quadratic equations

=> 5x²-2x+1-5=0

=> 5x²-2x-4=0

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The scale of proportionality is given as 8 from the table that you have presented

The table here was not properly arranged in the question. I have done so below

64 88 104

8 11 13

lets say that 8p = 64

then p = 64 / 8

p = 8

we would have to determine if the value 8 when multiplied with scaled factor  would be able to give us the original factor

8 * 11 = 88

8 * 13 = 104

Hence the scale of proportionality is given as 8

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Just ignore this answer, its incorrect

*edited*

For x = -2, g(-2) = 2(-2)^3 - 5(-2)^2 + 4(-2) - 1 = 0, so there is a value of x such that g(x) = 0 for -3 ≤ x ≤ 2.

The absolute minimum value of g on the interval -7 ≤ x ≤ 9 is -765, and the absolute maximum value of g on the interval is 1720.

a. To determine if there is a value of x such that g(x) = 0 for -3 ≤ x ≤ 2, we can plug in each value of x in the interval into the equation and see if we get 0.

g(x) = 2x^3 - 5x^2 + 4x - 1

For x = -3, g(-3) = 2(-3)^3 - 5(-3)^2 + 4(-3) - 1 = -55, which is not 0.

For x = -2, g(-2) = 2(-2)^3 - 5(-2)^2 + 4(-2) - 1 = 0, so there is a value of x such that g(x) = 0 for -3 ≤ x ≤ 2.

b. To find the absolute minimum and maximum values of g on the interval -7 ≤ x ≤ 9, we can use the Extreme Value Theorem, which states that a continuous function on a closed interval will have both an absolute minimum and maximum value on that interval.

To find these values, we can take the derivative of g(x) and set it equal to 0 to find critical points, and then evaluate g(x) at those critical points as well as at the endpoints of the interval.

g(x) = 2x^3 - 5x^2 + 4x - 1

g'(x) = 6x^2 - 10x + 4 = 2(3x-2)(x-1)

Setting g'(x) = 0, we get critical points x = 2/3 and x = 1.

g(-7) = -765, g(2/3) = -23/27, g(1) = 0, and g(9) = 1720.

Therefore, the absolute minimum value of g on the interval -7 ≤ x ≤ 9 is -765, and the absolute maximum value of g on the interval is 1720.

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There was this one person that said, 'hey how old are you?' of course I lied. then another asking me to change my profile to something inappropriate.

The value of the double integral is 128/27 - 32/9 + 8ln2/3. From triangular region with vertices (0, 1), (1, 2), (4, 1) d.

To evaluate the double integral, we first need to set up the limits of integration. Since the region D is a triangle, we can use the following limits:

0 ≤ x ≤ 1

1 + x ≤ y ≤ 4 - x

The integral then becomes:

∫0^1 ∫1+x^4-x 8y^2 dy dx

Evaluating the integral with respect to y first, we get:

∫0^1 ∫1+x^4-x 8y^2 dy dx = ∫0^1 [(8/3)(y^3)]1+x^4-x dx

= ∫0^1 [(8/3)(1+x^3)^3 - (8/3)(1+x^2)^3] dx

= 128/27 - 32/9 + 8ln2/3

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