Answer:
In physics, a state of matter is one of the distinct forms in which matter can exist. Four states of matter are observable in everyday life: solid, liquid, gas, and plasma.
...
To From Gas
Solid Deposition
Liquid Condensation
Plasma Ionization
plssssss look at the picture i need it right hurry pls
Answer:
it is B
Explanation:
Answer:
CO and H20
Explanation:
A 150 g sample of brass at 100 °C is placed in a Styrofoam cup of water containing 120 mL of water at 10 °C. No heat is lost to the cup or surroundings. What is the final temperature of the mixture? answer in celsius
Answer:
≈19.144°C.
Explanation:
all the details are in the attachment.
Note, that c₁, m₁, t₁ are the parameters of the sample of brass; c₂, m₂ and t₂ are the parameters of the sample of water.
P.S. change the provided design according Your requirements.
A moving coil meter has a resistance of 25 and indicate full scale deflection when a current of 4.0mA flows through it.How could this meter be converted to a millimeter having a full scale deflection for a current of 50 mA?
By adding an external resistor of 287.5 Ω in series with the meter, the conversion of the moving coil meter to have a full-scale deflection for a current of 50 mA.
Current sensitivity (S) is the ratio of full-scale deflection current to full-scale deflection voltage.
S = I(fsd) / V(fsd).
S = 4.0 / 25
S = 0.16 mA/Ω
Desired current sensitivity for 50 mA (S(new)) = 50 mA / V(fsd)
(S(new)) = 50 mA / V(fsd)
(S(new)) = 50 / 0.16
(S(new)) = 312.5 Ω
Add External Resistor:
Add an external resistor (R(ext)) in series with the meter. Calculate R(ext) as the difference between R(new) and the internal resistance of the meter
(R(internal) = 25 Ω:
R(ext) = R(new) - R(internal)
R(ext) = 312.5 Ω - 25 Ω
R(ext) = 287.5 Ω
By adding an external resistor of 287.5 Ω in series with the meter, the conversion of the moving coil meter to have a full-scale deflection for a current of 50 mA. This will achieve the desired result.
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Given that the mass of a liquid is 0.01kg and the volume of the liquid is 0.05m^3 . Calculate the density of the liquid
A) 2kg/m^3
B)0.2kg/m^3
C) 5kg/m^3
D) 0.5kg/m^3
Answer:
B.
Explanation:
Density = mass / volume
= 0.01/0.05
= 0.2 kg/m^3.
who made the first game
A William Shakespeare
B Horace Alexander
C Doris Twitchell Allen
D William higginbotham
what depth would a submarine have to submerge so that it would not be swayed by surface waves wwith a wavelength of 30 meters
Answer:
Explanation:
ello
Describe your acceleration if you ride your bike up a hill,then ride down the other side.
Answer:
first negative and then positve
Can someone please give me the (Answers) to this? ... please ...
Explanation:
1. By Newton's 3rd Law, both forces are equal and opposite. Hence both forces are of the same magnitude.
2. The reaction force is the force of arrow on bowstring.
3. Forward force of fish on water and vice versa?
4. The mass of the person is very small as compared to mass of earth. Hence the force exerted is very small amd hence the recoil is not noticed.
5. Reaction force is the force of ball against the bat. By Newton's Third Law, they form an action reaction pair. Hence, they are equal in magnitude and opposite in direction.
6. The reaction force will also decreases as both forces are equal in magnitude.
7 im nt sure sorry Ahahah
Help it multiple-choice 16 and 17 only
Answer:
16. c
17. d
Explanation:
16. Newton’s third law states that a force will always have an opposite but equal force as a reaction, so every force comes as a pair of action-reaction forces. For example, if you push on a book, the book also pushes on you.
17. If 1cm represents 15N, then 5cm must represent 15N*5=75N.
Two forces that act on very small distances (smaller than you can see ) are
A 2 kg wagon is being pulled by a kid with a force of 0.1 N to the right. Determine the acceleration of the wagon
Answer:
0.2 m/s^2
Explanation:
a = fm
a = 2 x .1
a = 0.2 m/s^2
what is the most likely reason for the difference between how the compass works on earth and on the moon?
Answer: A compass taken to Earth's moon does not point in a specific direction on the moon. The moon does not have a strong magnetic field.
The expression below was formed by combining different gas laws. V is proportional to StartFraction n T over P EndFraction. Which law was used to determine the relationship between the volume and the number of moles in this equation? Boyle’s law Charles’s law Avogadro’s law Gay-Lussac’s law.
The relationship between the number of moles and the volume of gas is determined by the Avogadro's law in this equation.
Avogadro's law:
It states that at constant temperature and pressure, gases with same volume has the same number of molecules.
For an ideal gas with with constant temperature and pressure, the volume of the gas is directly proportional to the amount or number of molecules.
Charle's law states that at constant pressure, volume (V) and temperature (T) are directly proportional.Boyle's law states that at constant temperature, the volume of gas is inversely proportional to the gas pressure.Gay-Lussac's law states that pressure (P) and absolute temperature (T) of the gas are directly proportional.Therefore, the relationship between the number of moles and the volume of gas is determined by the Avogadro's law in this equation.
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Answer:
Avogadro's law
Explanation:
can someone explain it please?
Answer:
The answer is 9.4 m/s
Explanation:
Because you add 5.0 + 4.5= 9.4
A truck moves 60 kilometers east from point A to point B. At point B, It turns back west and stops 15 kllometers away from point A. What are the
total distance and total displacement of the truck?
Answer:
a). The truck's distance covered for the trip is
(60) + (60 - 15) = 105 kilometers .
b). Its displacement for the whole trip is the distance
and direction from the start-point to the end-point.
15 kilometers east .
Explanation:
A number line goes from 0 to 30. Closed circles are at 6 and 25. A line is drawn from point 6 to point 25. Ari is swimming a 25-meter race. After swimming 6 meters, she catches up to Amanda in a ratio of 7:3 from the 6-meter mark. At what meter mark does Ari catch up to Amanda? Round to the nearest tenth, if necessary. Ari catches up to Amanda at meters.
The position on the meter mark where Ari catches up with Amanda is 19.3 m.
The given parameters:
Range of the number line, = 0 to 30Position of the closed circles, = 6 and 25The ratio between the initial position and final position of Ari = 7:3The distance between 6 m mark and 25 m mark is calculated as follows;
[tex]d = 25 \ m - \ 6 \ m\\\\\d = 19 \ m[/tex]
The distance traveled by Ari before catching up with Amanda is calculated as follows;
total ratio = 7 + 3 = 10
[tex]distance = \frac{7}{10} \times 19 \ m\\\\distance = 13.3 \ m[/tex]
The position of Ari from the 6 m mark is calculated as follows;
[tex]position = 6 \ m \ + \ 13.3 \ m\\\\position = 19.3 \ m[/tex]
Thus, the position on the meter mark where Ari catches up with Amanda is 19.3 m.
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Answer:
The above answer is correct! The answer is 19.3 meters :)
Explanation:
adding a ss for proof!
hope this helps :D
A horizontal force is applied to a box with a mass equal to 5.5 kg, The graph shows the net force acting on a box as a function of its horizontal position x.
Part A
Find the net work done on the box as it moves from x = 0 m to x = 8.0 m. .
Part B
Apply concepts of work and energy to solve for the speed of the box when it reaches position x = 8.0 m. Assume the box started from rest.
From the graph, net work done on the box and the speed of the box when it reaches position x = 8.0 m are 28 Nm and 3.2 m/s respectively
From the question, these are the given parameters;
Mass M = 5.5 KgPosition X = 0 to X = 8mPart A
The net work done will be the area under the graph.
From position X = 2m to X = 8m gives us the shape of a trapezium.
A = 1/2( a + b )h
A = 1/2( 2 + 6 ) x 8
A = 8 x 4
A = 32 Nm
From X = 0 to X = 2 gives us the shape of a triangle.
A = 1/2bh
A = 1/2 x 2 x (-4)
A = -4 x 1
A = -4 Nm
Net Work done = 32 - 4
Net work done = 28 Nm
Part B
Applying the concepts of work and energy to solve for the speed of the box when it reaches position x = 8.0 m
Net Work done = 1/2m[tex]V^{2}[/tex]
Substitute all the necessary parameters
28 = 1/2 x 5.5 x [tex]V^{2}[/tex]
5.5[tex]V^{2}[/tex] = 56
[tex]V^{2}[/tex] = 56/5.5
[tex]V^{2}[/tex] = 10.18
V = [tex]\sqrt{10.1818}[/tex]
V = 3.19 m/s
Therefore, net work done on the box and the speed of the box when it reaches position x = 8.0 m are 28 Nm and 3.2 m/s respectively
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What is number 10 for this?
Answer:
The wavelength of WFNX’s radio waves with the given speed and frequency is 2.95m.
Given data in the question;
Speed of wave;
Frequency of wave;
wavelength;
To determine the wavelength of the radio wave, we use the expression for the relations between wavelength, frequency and speed.
Where is wavelength, f is frequency and c is the speed.
We substitute our given values into the equation
Therefore, the wavelength of WFNX’s radio waves with the given speed and frequency is 2.95m.
Explanation:
Grass, trees, shrubs, worms, birds, and deer that live in a certain area is known as what?
Answer:they live in grass land also called forests hope the answer helps
Explanation:
Resolve the weight of the box to find the component of the weight acting parallel to the slope.
W = 50N
30
Answer:
here's your answer below
Explanation:
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.
why we use light-years in space verses other units of distance?
Answer:
The light year is used to measure distances in space because the distances are so big that a large unit of distance is required.
The density of gold is 19.3 g/cm3. What is the volume of a 13 g gold nugget? (Density: D = m/v)
Answer:
Formula = D = m/v
Given value of D = 19.3 and m = 13g
19.3 = 13/v
V × 19.3 = 13
v = 13/19.3
v = 0.67
Use this table of a school bus during morning pickups to calculate its average speed between 0 h and 2.340 h.
Position (km) Time (h)
0.0 0.000
1.2 0.024
2.8 0.051
4.2 0.084
16.3 2.340
The average speed between 0 h and 2.340 h is 6.97 Km/h
Average speed is defined as the total distance travelled divided by the total time taken to cover the distance.
[tex]Average \: speed = \frac{total \: distance}{total \: time} \\ \\ [/tex]
With the above formula, we can obtain the average speed between 0 h and 2.340 h as illustrated below:
Total time = 2.340 – 0 = 2.340 hTotal distance = 16.3 – 0 = 16.3 KmAverage speed =?[tex]Average \: speed = \frac{total \: distance}{total \: time} \\ \\Average \: speed = \frac{16.3}{2.340} \\ \\ Average \: speed = 6.97 \: Km/h \\ \\ [/tex]
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Answer:
6.983 km/hr
Explanation:
The average rate of change is (16.34 - 0.0)/(2.34 - 0.000) ≈ 6.983 km/hr
Mejor yo por favor
plssss helppppppppppp i need it
Answer:
D
Explanation:
I don't know how to explain it I just did it
By the way thxs for help on one of my problems
Physical data is often used in the court system. In fact, police officers use radar to determine your speed when you are driving and admit that record in court if you are ever given a ticket. In one such instance, the police officer submitted data that goes against the claim of the driver, who is contesting his ticket in court. The police officer (who was stationary when he made the measure) claims that the driver was speeding at 44.7 m/s, but the driver claims he was only going 26.8 m/s (according to his speedometer). The speed limit was 60 mph. The driver argues that the radar gun must have been set incorrectly to record relative velocity. Is it possible that they are both telling the truth?
The driver is telling the truth, the radar gun must have been set incorrectly to record relative velocity.
The given parameters:
Speed of the driver observed by the stationary police officer, Vo = 44.7 m/sSpeed of the driver, V = 26.8 m/s.Speed limit = 60 mphThe speed limit of the driver in meter per second is calculated as follows;
[tex]= 60 \ \times \frac{miles}{hour} \times \frac{1609.34 \ m}{1 \ mile} \times \frac{1 \ hr}{3600 \ s}\\\\= 26.82 \ m/s[/tex]
From the speed limit, it is obvious that the driver's speed is within the limit. Thus, we can conclude that the driver is telling the truth, the radar gun must have been set incorrectly to record relative velocity.
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If a spaceship travels at an average speed of 6x10^10 kilometers per year, how many years will it take the spaceship to travel 3x10^30 kilometers? Show work or explain your logic for full credit. a) 5x10^2 b) 5x10^19 c) 5x10^20 d) 5x10^21
First, you need to find out the speed of 6x10^10. Then find out the value of 3x10^30 after you do that, Make this visual,
3x10^30. 5x10 to the 19 power
_______.
6x10^10
The answer is c
If the spaceship travels a distance of 6 × 10¹⁰ kilometers with an average speed the time taken to travel 3 × 10³⁰ kilometers is 5 × 10¹⁹ years. Thus, option a is correct.
What is speed?Speed is a physical quantity associated with a moving body. It is the measure of distance travelled per unit time . Thus, mathematically it is the ratio of distance to the time.
If we have the time and speed known we can find the distance travelled and vice versa. As the speed increases, the distance covered per unit time will be higher.
Here the spaceship travels 6 × 10¹⁰ kilometers . Thus the time taken to travel 3 × 10³⁰ kilometers can be calculated as follows:
1 year - 6 × 10¹⁰ km
? - 3 × 10³⁰ km
Cross multiply them we get, 3 × 10³⁰ km/ 6 × 10¹⁰ km = 5 × 10¹⁹ years.Hence, option a is correct.
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bow long does it take earth to rotate once on its axis
Answer:
23 hours, 56 minutes
anything that has mass and occupies space is called
Answer:
Matter
Hope you could get an idea from here.
Doubt clarification - use comment section.
Which form can solutions come in?
liquid
gas
solid
all of the above
Answer:
liquid
Explanation:
leave a thanks if helped !
Depth perception is also known as ___________ vision.
Answer:
depth from optical expansion
Explanation: