HELP ME OUT PLEASE!!!

Determine which graph shows y as a function of x.​

Answer:

x = 18

Step-by-step explanation:

10 - x/3 = 4

=> - x/3 = -6

=> -x = -18

=> x = 18

Hoped this helped.

Answer: 18

Step-by-step explanation:

10 -1/3y = 4

1/3y = 10 - 4

1/3y = 6

y = 6 x 3 = 18

Answer:

2.4

Step-by-step explanation:

The constant of proportionality is y=kx which should 2.4

[tex]28+24=4(7)+4(6)=4(7+6)[=4(13)=52][/tex]

The answer: 4(7+6)

ok done. Thank to me :>

Answer:

The median goes up 0.5

Step-by-step explanation:

Before the number 10.

Mean x¯¯¯ 10.111111111111

Median x˜ 7

Mode 2

Range 22

Minimum 2

Maximum 24

Count n 9

Sum 91

Quartiles Quartiles:

Q1 --> 3

Q2 --> 7

Q3 --> 19

Interquartile

Range IQR 16

Outliers none

After 10 is added.

Mean x¯¯¯ 10.1

Median x˜ 7.5

Mode 2

Range 22

Minimum 2

Maximum 24

Count n 10

Sum 101

Quartiles Quartiles:

Q1 --> 4

Q2 --> 7.5

Q3 --> 18

Interquartile

Range IQR 14

Outliers none

It goes up .5.

Using the z-distribution, it is found that since the value of the test statistic is greater than the critical value for the right-tailed test, there is sufficient evidence to support the principal’s claim.

At the null hypothesis, it is tested if they are not above average, that is, their mean is of 500 or below, hence:

[tex]H_0: \mu \leq 500[/tex]

At the alternative hypothesis, it is tested if they are above average, that is, their mean is of more than 500, hence:

[tex]H_1: \mu > 500[/tex]

We have the standard deviation for the population, thus, the z-distribution is used. The test statistic is given by:

[tex]z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

The parameters are:

For this problem, the values of the parameters are: [tex]\overline{x} = 541, \mu = 500, \sigma = 100, n = 50[/tex]

Hence, the value of the test statistic is:

[tex]z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

[tex]z = \frac{541 - 500}{\frac{100}{\sqrt{50}}}[/tex]

[tex]z = 2.9[/tex]

The critical value for a right-tailed test, as we are testing if the mean is greater than a value, with the standard 0.05 significance level, is of [tex]z^{\ast} = 1.645[/tex].

Since the value of the test statistic is greater than the critical value for the right-tailed test, there is sufficient evidence to support the principal’s claim.

A similar problem is given at https://brainly.com/question/25728144

Answer:

[tex]The \: fraction \: \frac{15}{4} \: is \: equivalent \: to \: 3 \frac{3}{4 } .[/tex]

This fraction is a improper fraction once the absolute value of the top number or numerator (15) is greater than the absolute value of the bottom number or denomintor (4). So, the equivalent fraction is a mixed number which is made up of a whole number (3) and a proper fraction [tex]3 \frac{3}{4} [/tex]

The fraction [tex] \frac{15}{4} [/tex]

is also equal to 15÷4 and can also be expressed as a decimal as 3.75 and expressed as a percentage as 375%.

The fraction 15/4 is equivalent to 3 3/4.

Here, we have,

To simplify the fraction 15/4, you need to find the greatest common divisor (GCD) of the numerator (15) and the denominator (4) and divide both the numerator and denominator by the GCD.

The GCD of 15 and 4 is 1 since there are no common factors other than 1.

Dividing both the numerator and denominator by 1, we get:

(15 ÷ 1) / (4 ÷ 1) = 15/4

This fraction is a improper fraction once the absolute value of the top number or numerator (15) is greater than the absolute value of the bottom number or denominator (4).

So, the equivalent fraction is a mixed number which is made up of a whole number (3) and a proper fraction 3 3/4.

The fraction 15/4 is also equal to 15÷4 and can also be expressed as a decimal as 3.75 and expressed as a percentage as 375%.

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Answer:

1276.02

Step-by-step explanation:

25.02*51=(25*51)+(.02*51)=1275+1.02=1276.02

[tex] \: \: \: \: \: \: [/tex]

[tex] = 25x - 104[/tex]

Step-by-step explanation:

[tex] - x + x26 - 104[/tex]

[tex] - x + 26x - 104[/tex]

[tex] = 25x - 104[/tex]

Step-by-step explanation:

x³ + 3x² - 19  ÷ x - 2 = x² + 5x + 10 rem 1

x³ -  2x²

      5x² - 19

      5x² - 10x

               10x - 19

               10x - 20

                         1

Answer:

quickly:

x-2=0 x^3+3x^2-19

x=0+2 = 2^3+3(2)^2-19

x=2 = 8+6^2-19

=8+36-19

=42-19

=23

The remainder is 23

Answer:

{},{a},{b},{c},{d},{a,b},{a,c},{a,d},{b,c},{b,d},{c,d},{a,b,c},{a,b,d},{a,c,d},{b,c,d},{a,b,c,d}

Step-by-step explanation:

Answer:

34.700+98.42+98.775+132.435+132.980+133.128

Answer:

Step-by-step explanation:

I'll use y for quantity and x for price [love my x and y] and rewrite the demand and supply functions:

Demand:    y=1204−11x

Supply:       y = -3 + 6x

==

We want to know the equilibrium price and quantity.  The quantities purchased and sold would be equal to the quantities supplied:

  1204−11x = -3 + 6x

-17x = - 1207

 x = 71  The price of a widget is 71 units ($, €,£,¥, etc.) at equilibrium

A price of 71 would lead to a demand and supply of:

y = 1204−11x

y = 1204−11(71)

y = 423 Widgets

We can also plot this to find the point (71,423).  See the attachment.

At this point, I'm uncertain how to answer the "producer surplus" and "unmet demand" at equilibrium.  This is what I did, so please judge if it is correct.

The demand line, y=1204−11x, tells us that if the price were 0, the demand would be 1204, which I'll assume in the maximum, since it is stipulated that x > 0  (I imagine it may no longer be a straight line when the price goes into negative territory.  I'd be the first in line to accept a widget and $5 if they were priced at -$5).

At equilibrium, therefore, we would still have an unmet demand of (1204 - 423) or 781 widgets that customers wanted, but wouldn't pay the price.

It seems to me that this would also be the unmet demand:  Product that could have been sold, but wasn't, due to the price.  I'm unsure, however.

Answer:

a. 810

b. 27

c. 30

Step-by-step explanation:

Part a.

The volume is 9 * 9 * 10.

9 * 9 = 81, and 81 * 10 = 810.

Part b.

The volume of a cube is x^3, where x is the side length of the cube.

If x = 3, then 3^3 = 27.

Part c.

If each notebook has a volume of 27, then the maximum amount of notebooks that will fit in a box with volume 810 is 810/27 = 30 notebooks

a. The volume of the rectangular box is 810 inch³.

b. The volume of the notepad is 243 inch³.

c. The maximum number of notepads that will fit inside the box is 3.

A cuboid is a three-dimensional closed figure which has volume along with surface area.

The volume of a cuboid is the product of its length, width, and height.

The total surface area of a cuboid is 2(lw + wh + wl) and the lateral surface area is 2(l + w)×h.

Given, A paper company ships notepads in rectangular boxes that have dimensions measuring 9 inches long, 9 inches wide, and 10 inches tall.

Therefore, The volume of the box is, = (9×9×10) inch³.

= 810 inch³.

The dimensions of the notepad are 9 inches by 9 inches with an height of 3 inches.

Therefore, The volume of the notepad is = (9×9×3) = 243³ inches.

The maximum number of notepads that will fit inside thebox is,

= (810/243).

= 3.33 but it sholud only be 3 notepads.

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Answer:

True

Step-by-step explanation:

Eg. Republican party nominates a candidate to be considered by the people [hopefully voted] into office. If they win the election, they control a part of government in office.

1. Value=206

2. Value=205

3. Value= 208

4. Value=207

Answer:

-5/3

Step-by-step explanation:

lmk if you want an explanation

Answer:

( 6 , 8 )

Step-by-step explanation:

y = kx

k = [tex]\frac{y}{x}[/tex]

( 3 , 4 )

k = [tex]\frac{4}{3}[/tex]

[tex]\frac{4}{3}[/tex] = [tex]\frac{8}{6}[/tex] = [tex]\frac{12}{9}[/tex] = ....

( 6 , 8 )

Answer:

Step-by-step explanation:

Answer:

30 mm.

Step-by-step explanation:

The longest side = sqrt(5^2 + 12^2)

= sqrt169

= 13.     (Using Pythagoras).

So the perimeter = 5+12+13

= 30 mm.

Perimeter of the piece of jewelry = 30mm

Pythagoras theorem states that “In a right-angled triangle, the square of the hypotenuse side is equal to the sum of squares of the other two sides".

Given,

Shape of jewelry is right angle triangle ABC

length of shorter sides,

AB = 5mm

BC = 12mm

By Pythagoras theorem,

AC² = AB²+BC²

AC = √(5² + 12²)

AC = √169

AC = 13 mm

Perimeter of Triangle = AB + BC + AC

                                    = 5 + 12 + 13

Perimeter of Triangle = 30

Hence, 30 mm is the perimeter of jewelry.

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Answer:

16

Step-by-step explanation:

x+y=30  solve for x   x=30-y

substitute x with 30-y and solve

11.25x+22.4y=515.9

11.25(30-y)+22.4y=515.9

337.5+11.15y=515.9

11.15y=178.4

y=16

since we're solving for just large candles it's 16

if need small cangle number 30-16=14

Sets of 8pies

No if time for 8pies=3h

No of time for 37 sets of 8pies:-

Answer:

17

Step-by-step explanation:

-2 - 19 x -1

-2 + 19(because two negatives make a positive)

17

Answer:

17 is the answer.

Step-by-step explanation:

Given:

Let's substitute.

=> -2 - 19t

=> -2 - 19(-1)

=> -2 - (-19)

=> -2 + 19

=> 17

Therefore, 17 is the answer.

Hoped this helped.

Answer: y-(-2)=-2/3(x-5)

Step-by-step explanation:y-y1=m(x-x1)

Plug-in

Answer:

70⁰ + 30⁰ + x = 180 ( angle sum property (

100⁰ + x = 180

x = 80⁰

Answer:

The rat population in a major metropolitan city is given by the formula n(t)=67e^0.035t where t is measured in years since 1994 and n(t)is measured in millions.

Using the power and chain rules, the derivative of

y = sin²(x) - cos²(x)

is

dy/dx = 2 sin(x) cos(x) - 2 cos(x) (-sin(x))

dy/dx = 2 sin(x) cos(x) + 2 sin(x) cos(x)

dy/dx = 4 sin(x) cos(x)

and using the double angle identity for sine, this is equivalent to

dy/dx = 2 sin(2x)

Alternatively, we can first simplify y using the double angle identity for cosine:

cos(2x)= cos²(x) - sin²(x)

so that

y = -cos(2x)

and the derivative is

dy/dx = sin(2x) • 2

dy/dx = 2 sin(2x)

Answer:

1.  n=10

2. n=35

3. n=6

4. n=0 ? not sure for this one. two variables in the proportion

5. n=36

Step-by-step explanation:

set each set of proportion equal to each other and do cross multiplication

hope this helps !

how are you ?

Answer:

Step-by-step explanation:

Please take a look of the attached photo for the solution.

[tex]\begin{array}{|cc|ll} \cline{1-2} x&y\\ \cline{1-2} 0&-5\\ 1&-1\\ 2&3\\ 3&7\\ \cline{1-2} \end{array} \begin{array}{llll}\\[-0.5em] \leftarrow \textit{let's use this point}\\\\\\ \leftarrow \textit{and this point} \end{array}\qquad \qquad (\stackrel{x_1}{0}~,~\stackrel{y_1}{-5})\qquad (\stackrel{x_2}{3}~,~\stackrel{y_2}{7})[/tex]

[tex]\stackrel{slope}{m}\implies\cfrac{\stackrel{rise}{\stackrel{y_2}{7}-\stackrel{y1}{(-5)}}}{\underset{run}{\underset{x_2}{3}-\underset{x_1}{0}}}\implies \cfrac{7+5}{3}\implies \cfrac{12}{3}\implies 4[/tex]